TUYỂN TẬP 50 ĐỀ THI HỌC KỲ 1 LỚP 3

["51 \u0110\u1ec0 17 B\u00e0i ki\u1ec3m tra h\u1ecdc k\u00ec I M\u00f4n thi: To\u00e1n - kh\u1ed1i 3 Th\u1eddi gian: 40 ph\u00fat (kh\u00f4ng k\u1ec3 th\u1eddi gian giao \u0111\u1ec1) I\/ Ph\u1ea7n tr\u1eafc nghi\u1ec7m: (4 \u0111i\u1ec3m) Khoanh tr\u00f2n v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang 1. Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: 789 \u2013 45 + 55 l\u00e0: A.100 B.799 C.744 D. 689 2. Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: 930 \u2013 18 : 3 l\u00e0: A.924 B. 304 C.6 D. 912 3. 7m 3 cm = ....... cm: A. 73 B. 703 C. 10 D. 4 4. C\u00f3 750 quy\u1ec3n s\u00e1ch s\u00e1ch x\u1ebfp \u0111\u1ec1u v\u00e0o 5 t\u1ee7, m\u1ed7i t\u1ee7 c\u00f3 2 ng\u0103n. H\u1ecfi m\u1ed7i ng\u0103n c\u00f3 bao nhi\u00eau quy\u1ec3n s\u00e1ch, bi\u1ebft r\u1eb1ng m\u1ed7i ng\u0103n c\u00f3 s\u1ed1 s\u00e1ch nh\u01b0 nhau? A. 75 quy\u1ec3n B. 30 quy\u1ec3n C. 6 0 quy\u1ec3n D. 125 quy\u1ec3n 5. C\u00f3 7 con v\u1ecbt, s\u1ed1 g\u00e0 nhi\u1ec1u h\u01a1n s\u1ed1 v\u1ecbt 56 con. H\u1ecfi s\u1ed1 v\u1ecbt b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 g\u00e0? A. 1 B. 1 C. 1 D. 1 6 78 9 6. M\u1ed9t chi\u1ebfc b\u00eca h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 25 cm, chi\u1ec1u r\u1ed9ng 1dm. Chu vi mi\u1ebfng b\u00eca \u0111\u00f3 l\u00e0 bao nhi\u00eau \u0111\u1ec1 \u2013 xi \u2013 m\u00e9t? A. 52dm B.70cm C.7dm D. 70 dm 7. H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 m\u1ea5y g\u00f3c vu\u00f4ng? A. 1 B. 2 C.3 D. 4 8. 8 x 7 < \u25a1 x 8","A. 7 B. 5 52 C. 8 D. 6 II\/ Ph\u1ea7n t\u1ef1 lu\u1eadn (6 \u0111i\u1ec3m) B\u00e0i1: (2 \u0111i\u1ec3m) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 267 + 125 \u2013 278 538 \u2013 38 x 3 .................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... .................................................................................................................................... B\u00e0i 2. T\u00ecm X: (2 \u0111i\u1ec3m) X : 7 = 100 + 8 X x 7 = 357 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... B\u00e0i 3: (2 \u0111i\u1ec3m) M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 453 kg g\u1ea1o, \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c 1\/3 s\u1ed1 g\u1ea1o \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau ki- l\u00f4- gam g\u1ea1o? ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... \u2026\u2026................................................................................................... .........................","53 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 17 I.TR\u1eaeC NGHI\u1ec6M 1. B 2.A 3.B 4.A 5.C 6.C 7.B 8.C II. T\u1ef0 LU\u1eacN C\u00e2u 1 a)267 \uf02b125 \uf02d 278 \uf03d 392 \uf02d 278 \uf03d 114 b) 538 \uf02d 38\uf0b43 \uf03d 538 \uf02d114 \uf03d 424 C\u00e2u 2. x \uf0b4 7 \uf03d 357 x \uf03d 357 : 7 x : 7 \uf03d 100 \uf02b 8 x \uf03d 51 x : 7 \uf03d 108 x \uf03d 108\uf0b4 7 x \uf03d 756 C\u00e2u 3. T\u00f3m t\u1eaft C\u00f3: 453 kg g\u1ea1o \u0110\u00e3 b\u00e1n: 1\/3 s\u1ed1 g\u1ea1o C\u00f2n l\u1ea1i : ? kg g\u1ea1o Gi\u1ea3i S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n l\u00e0 453 : 3 = 151 (kg g\u1ea1o) S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i l\u00e0: 453 \u2013 151 = 302 (kg g\u1ea1o) \u0110\u00e1p s\u1ed1: 302 kg g\u1ea1o","54 \u0110\u1ec0 18 \u0110\u1ec1 ki\u1ec3m tra cu\u1ed1i h\u1ecdc k\u1ef3 I- N\u0103m h\u1ecdc: 2015-2016 M\u00f4n: To\u00e1n, l\u1edbp 3 (th\u1eddi gian l\u00e0m b\u00e0i 40 ph\u00fat) I\/ Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang (2 \u0111i\u1ec3m). 1 . K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n: 117 x 8 l\u00e0: A. 936 ; B. 639; C. 963; D. 886. 2. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p chia : 84 : 4 l\u00e0; A. 14; B. 21; C. 8; D. 12 3. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 765 \u2013 84 l\u00e0: A. 781; B. 681; C. 921; D. 671. 4. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 81 : 9 + 10 l\u00e0: A. 39; B. 19; C. 91; D. 20; II\/ T\u1ef1 lu\u1eadn: 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh; (2 \u0111i\u1ec3m). 486 + 303; 670 \u2013 261 ; 106 x 9 872 : 4. .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... 2. T\u00ecm y: (2 \u0111i\u1ec3m). 72 : y = 8; y + 158 = 261; 5 x y = 375; y : 5 = 141. .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... 3. (1,5 \u0111i\u1ec3m). N\u0103m nay \u00f4ng 72 tu\u1ed5i, ch\u00e1u 9 tu\u1ed5i. H\u1ecfi tu\u1ed5i ch\u00e1u b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y tu\u1ed5i \u00f4ng? .......................................................................................................................................... ..........................................................................................................................................","55 .......................................................................................................................................... .......................................................................................................................................... 4. (2,5 \u0111i\u1ec3m). T\u1ed5 m\u1ed9t tr\u1ed3ng \u0111\u01b0\u1ee3c 25 c\u00e2y, t\u1ed5 hai tr\u1ed3ng \u0111\u01b0\u1ee3c g\u1ea5p 3 l\u1ea7n t\u1ed5 m\u1ed9t. H\u1ecfi c\u1ea3 hai t\u1ed5 tr\u1ed3ng \u0111\u01b0\u1ee3c bao nhi\u00eau c\u00e2y? .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 18 I.Tr\u1eafc nghi\u1ec7m 1.A 2.B 3.B 4.B II. T\u1ef0 LU\u1eacN C\u00e2u 1. 670 \uf02d 261 \uf03d 409 486 \uf02b 303 \uf03d 789 106\uf0b49 \uf03d 954 872 : 4 \uf03d 218 y \uf02b158 \uf03d 261 C\u00e2u 2. 72 : y \uf03d 8 y \uf03d 72 : 8 y \uf03d 261\uf02d158 y\uf03d9 y \uf03d 103 5\uf0b4 y \uf03d 375 y : 5 \uf03d 141 y \uf03d 375 : 5 y \uf03d 141\uf0b4 5 y \uf03d 75 y \uf03d 705 C\u00e2u 3. S\u1ed1 ph\u1ea7n tu\u1ed5i ch\u00e1u b\u1eb1ng tu\u1ed5i \u00f4ng l\u00e0: 72:9=8 (ph\u1ea7n) \u0110\u00e1p s\u1ed1: 8 ph\u1ea7n C\u00e2u 4. S\u1ed1 c\u00e2y t\u1ed5 hai tr\u1ed3ng \u0111\u01b0\u1ee3c l\u00e0:25 x 3 = 75 (c\u00e2y) S\u1ed1 c\u00e2y c\u1ea3 hai t\u1ed5 tr\u1ed3ng \u0111\u01b0\u1ee3c l\u00e0: 25 + 75 = 100 (c\u00e2y) \u0110\u00e1p s\u1ed1: 100 c\u00e2y.","56 1.T\u00ednh nh\u1ea9m (1\u0111) \u0110\u1ec0 S\u1ed0 19 81 : 9 = \u2026. 7 x 8 = \u2026.. 6 x 9 = \u2026.. 63 : 7 = \u2026.. 2. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111): 271 x 2 372 x 4 847 : 7 836 : 2 D . 4015 3. \u0110\u00fang ghi \u0110 ; Sai ghi S v\u00e0o \u00f4 tr\u1ed1ng (1,5\u0111): a\/ Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c 12 x 4 : 2 l\u00e0 24 . b\/ Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c 35 + 15 : 5 l\u00e0 10. c\/ Chu vi h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 6cm l\u00e0 24cm. 4. Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang(1,5\u0111). a\/ S\u1ed1 b\u1ed1n tr\u0103m m\u01b0\u1eddi l\u0103m \u0111\u01b0\u1ee3c vi\u1ebft l\u00e0: A . 4105 B . 400105 C . 415 b\/ S\u1ed1 l\u1edbn 64 ; s\u1ed1 b\u00e9 l\u00e0 8 . * S\u1ed1 b\u00e9 b\u1eb1ng 1 ph\u1ea7n m\u1ea5y s\u1ed1 l\u1edbn : A. 1 B. 1 C. 1 D. 1 57 8 9 *S\u1ed1 l\u1edbn g\u1ea5p m\u1ea5y l\u1ea7n s\u1ed1 b\u00e9: A.6 B.8 C.9 D.7 5. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u1ea7u ch\u1ea5m (1\u0111). 28 ; 35 ; 42 ; \u2026.. ; \u2026\u2026 ; \u2026\u2026 ; \u2026\u2026. 6 . T\u00ecm X (1\u0111) : a\/ X + 1243 = 2662 b\/ X \uf0b4 4 = 864 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. 7. (2\u0111) M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 87 xe \u0111\u1ea1p, \u0111\u00e3 b\u00e1n 1 s\u1ed1 xe \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i 3 bao nhi\u00eau xe \u0111\u1ea1p? B\u00e0i gi\u1ea3i: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 19 1). 7 x 8 = 56 6 x 9 = 54 81 : 9 = 9 63 : 7 = 9 2) \u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 217 x 2 = 354 372 x 4 = 1488 847 : 7 = 121 836 : 2 = 418 3) a)\u0110 b)S c)\u0110 4) a) C b) C c) B 5) 28;35;42;49;56;63;70 x \uf0b4 4 \uf03d 864 6)x \uf02b1243 \uf03d 2662 x \uf03d 2662 \uf02d1243 x \uf03d 864 : 4 x \uf03d 1419 x \uf03d 216","57 7)S\u1ed1 xe \u0111\u1ea1p \u0111\u00e3 b\u00e1n \u0111i l\u00e0 : 87 : 3 = 29 (xe \u0111\u1ea1p ) S\u1ed1 xe \u0111\u1ea1p c\u00f2n l\u1ea1i l\u00e0 : 87 \u2013 29 = 58 (xe \u0111\u1ea1p) \u0110\u00e1p s\u1ed1: 58 xe \u0111\u1ea1p \u0110\u1ec0 S\u1ed0 20 Ph\u1ea7n I: (3 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef \u0111\u1ee9ng tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang. C\u00e2u 1: 1kg b\u1eb1ng: A . 1000g B. 100g C. 10000g D. 10g C\u00e2u 2: 1 c\u1ee7a 1 gi\u1edd b\u1eb1ng bao nhi\u00eau ph\u00fat? 6 A. 6 ph\u00fat B. 10 ph\u00fat C. 15 ph\u00fat D. 20 ph\u00fat C\u00e2u 3: S\u1ed1 b\u00e9 l\u00e0 6, s\u1ed1 l\u1edbn l\u00e0 36. S\u1ed1 b\u00e9 b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 l\u1edbn: A. 1 B. 1 C. 1 D. 1 3 4 5 6 C\u00e2u 4: Chu vi h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 5 cm l\u00e0: A. 5 cm B. 10 cm C. 20 cm D. 15 cm Ph\u1ea7n II. (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. 54 x 3 309 x 2 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.... 75 : 5 845 : 7 .............................................................................................................................................. .............................................................................................................................................. .............................................................................................................................................. .............................................................................................................................................. ..............................................................................................................................................","58 .............................................................................................................................................. ...... C\u00e2u 2: T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c. 42 + 24 : 8 71 \u2013 13 x 4 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 28 x 3 : 7 139 \u2013 ( 45 + 25) \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. . C\u00e2u 3: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng 8m v\u00e0 chi\u1ec1u d\u00e0i g\u1ea5p 3 l\u1ea7n chi\u1ec1u r\u1ed9ng . T\u00ednh chu vi c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 4: H\u00ecnh b\u00ean c\u00f3 bao nh\u00eau tam gi\u00e1c, bao nhi\u00eau t\u1ee9 gi\u00e1c? - C\u00f3 \u2026\u2026\u2026tam gi\u00e1c. - C\u00f3 \u2026\u2026\u2026 t\u1ee9 gi\u00e1c. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 20 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 20 I.TR\u1eaeC NGHI\u1ec6M 1.A 2.B 3.D 4.C II. T\u1ef0 LU\u1eacN 1)H\u1ecdc sinh \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 54 x 3 = 162 309 x 2 = 618 75 : 5 = 15 845 : 7 = 120 (d\u01b0 5)","59 2) 42 + 24 : 8 = 42 + 3 = 45 71 \u2013 13 x 4 = 71 \u2013 52 = 19 28 x 3 : 7 = 84 : 7 = 21 139 \u2013 ( 45 + 25 ) = 139 \u2013 70 = 69 3) Chi\u1ec1u d\u00e0i h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 : 8 x 3 = 24 (m ) Chu vi h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 : (24 + 8 ) x 2 = 64 (m) \u0110\u00e1p s\u1ed1 : 64 m 4) C\u00f3 12 tam gi\u00e1c, c\u00f3 5 t\u1ee9 gi\u00e1c \u0110\u1ec0 S\u1ed0 21 PH\u1ea6N I: H\u00e3y khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang 1) ph\u00e9p t\u00ednh 32 x 6 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: (0.5 \u0111i\u1ec3m) A. 182 B. 192 C. 129 D. 198 d\/ 450 : 6 2) S\u1ed1 d\u01b0 trong ph\u00e9p chia 46 : 6 l\u00e0 : ( 0,5 \u0111i\u1ec3m) A. 1 B. 2 C. 3 D. 4 3) M\u1ed7i gi\u1edd c\u00f3 60 ph\u00fat v\u1eady 1 gi\u1edd c\u00f3 : (0,5 \u0111i\u1ec3m) 3 A. 15 ph\u00fat B. 25 ph\u00fat C. 20 ph\u00fat D. 30 ph\u00fat 4) Bi\u1ec3u th\u1ee9c 36 : 4 x 3 c\u00f3 gi\u00e1 tr\u1ecb l\u00e0 : (0,5 \u0111i\u1ec3m) A. 27 B. 28 C.32 D. 34 5) H\u00ecnh b\u00ean c\u00f3: (1 \u0111i\u1ec3m) A. 3 g\u00f3c vu\u00f4ng B. 4 g\u00f3c vu\u00f4ng C. 5 g\u00f3c vu\u00f4ng D. 6 g\u00f3c vu\u00f4ng PH\u1ea6N II: L\u00e0m c\u00e1c b\u00e0i t\u1eadp sau: 1\/ \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2 \u0111i\u1ec3m) a\/ 214 x 4 b\/ 319 x 3 c\/ 905 : 5 2\/ \u0110\u1ed5i \u0111\u01a1n v\u1ecb \u0111o: (1 \u0111i\u1ec3m) a\/ 25 dm 7 cm = \u2026\u2026\u2026\u2026\u2026.. cm b\/ 8 m 32 cm = \u2026\u2026\u2026\u2026\u2026\u2026 cm 3\/ T\u00ecm x: (2 \u0111i\u1ec3m) b\/ x : 6 = 108 a\/ 876 : x = 4","60 ...................................................... ..................................................... ....................................................... ...................................................... 4\/ M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 56kg \u0111\u01b0\u1eddng, \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c 1 s\u1ed1 \u0111\u01b0\u1eddng \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i 8 bao nhi\u00eau ki-l\u00f4 gam \u0111\u01b0\u1eddng ? (2 \u0111i\u1ec3m) B\u00e0i gi\u1ea3i: ........................................................................................... ........................................................................................... ........................................................................................... .......................................................................................... .......................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 21 I.TR\u1eaeC NGHI\u1ec6M 1.B 2.D 3.C 4.A 5.C II. 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 a) 214x4=856 b)319 x 3 = 957 b) 905:5=181 d) 450:6=75 2) \u0110\u1ed5i \u0111\u01a1n v\u1ecb \u0111o a) 25 dm 7 cm = 257 cm b) 8m 32 cm = 832 cm 3) T\u00d7m x x : 6 \uf03d 108 a)876 : x \uf03d 4 x \uf03d 108\uf0b4 6 x \uf03d 876 : 4 x \uf03d 648 x \uf03d 219 4) S\u1ed1 kilogam \u0111\u01b0\u1eddng \u0111\u00e3 b\u00e1n l\u00e0 : 56:8=7 (kg \u0111\u01b0\u1eddng) S\u1ed1 kilogam \u0111\u01b0\u1eddng c\u00f2n l\u1ea1i l\u00e0: 56 \u2013 7 = 49 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1: 49 kg \u0111\u01b0\u1eddng. \u0110\u1ec0 S\u1ed0 22 1. T\u00ednh nh\u1ea9m: 6 x 4 = \u2026\u2026.; 9 x 3 = \u2026\u2026.; 72 : 8 = \u2026\u2026.; 42 : 6 = \u2026\u2026\u2026; 2. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a) 71 x 4 b) 84 x 3 c) 96 : 6 d) 84 : 7 3. \u0110i\u1ec1n d\u1ea5u < ; = ; > a) 4m 3dm \u2026\u2026 43dm b) 8m 7cm \u2026\u2026 870cm","61 4.\u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: a) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 56 + 24 : 6 l\u00e0 60 b) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 21 x 4 : 7 l\u00e0 12 5. Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a) S\u1ed1 b\u00e9 l\u00e0 8, s\u1ed1 l\u1edbn l\u00e0 32. S\u1ed1 l\u1edbn g\u1ea5p s\u1ed1 b\u00e9 s\u1ed1 l\u1ea7n l\u00e0: A. 24; B. 4; C. 8; b) Cho 1 gi\u1edd = \u2026\u2026.. ph\u00fat. A. 20; B. 24; C. 30; 3 S\u1ed1 th\u00edch h\u1ee3p \u0111\u1ec3 vi\u1ebft v\u00e0o ch\u1ed5 ch\u1ea5m l\u00e0: 6. M\u1ed9t quy\u1ec3n truy\u1ec7n d\u00e0y 129 trang. Nam \u0111\u00e3 \u0111\u1ecdc \u0111\u01b0\u1ee3c 1 s\u1ed1 trang \u0111\u00f3. H\u1ecfi: 3 a) Nam \u0111\u00e3 \u0111\u1ecdc \u0111\u01b0\u1ee3c bao nhi\u00eau trang? b) C\u00f2n bao nhi\u00eau trang n\u1eefa Nam ch\u01b0a \u0111\u1ecdc? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 7. M\u1ed9t s\u00e2n t\u1eadp th\u1ec3 d\u1ee5c h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 42m, chi\u1ec1u r\u1ed9ng 20m. T\u00ednh chu vi c\u1ee7a s\u00e2n t\u1eadp th\u1ec3 d\u1ee5c \u0111\u00f3. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026","62 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 22 1). 6 x 4 = 24 ; 9 x 3 = 27 ; 72 : 8 = 9 42 : 6 = 7 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5 \u0111 a) 71 x 4 = 284 b) 84 x 3 = 252 c) 96 : 6 = 16 d) 84 : 7 = 12 3) 4m 3 dm = 43 dm b) 8m 7 cm < 870 cm. 4) a) \u0110 b) \u0110 5) a) B b) A 6) a) S\u1ed1 trang s\u00e1ch Nam \u0111\u00e3 \u0111\u1ecdc l\u00e0 : 129 : 3 = 43 (trang) b) S\u1ed1 trang s\u00e1ch Nam ch\u01b0a \u0111\u1ecdc l\u00e0: 129 \u2013 43 = 86 (trang) \u0110\u00e1p s\u1ed1: a) 43 trang; b) 86 trang. \u0110\u1ec0 S\u1ed0 23 B\u00e0i 1: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: b) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 160 l\u00e0: A. 161 B. 150 C. 159 D. 170 b)M\u1ed9t c\u00e1i ao h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 6 m.Chu vi c\u1ee7a h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0: A.24m B.36 m C. 10 m D. 12 cm c ) 9m 8cm = \u2026. cm . S\u1ed1 th\u00edch h\u1ee3p c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. 98 B. 908 C. 980 D .9080 d )G\u1ea5p 7 l\u00edt l\u00ean 8 l\u1ea7n th\u00ec \u0111\u01b0\u1ee3c: A. 15 l\u00edt B. 49 l\u00edt C. 56 l\u00edt D. 65 l\u00edt B\u00e0i 2: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng : *Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c c) 2 + 8 x 5 = 50 d) 32 : 4 + 4 = 12 B\u00e0i 3: T\u00ednh nh\u1ea9m 8 x 7 = \u2026..... 7 x 6 = \u2026\u2026. 64 : 8 =\u2026\u2026. 63 : 9=\u2026\u2026. 660 \u2013 251 124 x 3 845 : 7 B\u00e0i 4: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 487 + 302 B\u00e0i 5: T\u00ecm x: b) 5 x X = 375 a) X : 6 = 144 B\u00e0i 6 : M\u1ed9t quy\u1ec3n truy\u1ec7n d\u00e0y 128 trang. An \u0111\u00e3 \u0111\u1ecdc \u0111\u01b0\u1ee3c 1 s\u1ed1 trang \u0111\u00f3. H\u1ecfi c\u00f2n 4 bao nhi\u00eau trang truy\u1ec7n n\u1eefa m\u00e0 An ch\u01b0a \u0111\u1ecdc?","63 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 23 .1) a) C b) A c) B d) C 2) a)S b)\u0110 3) 7x6 = 42; 63 : 9 = 7 8 x 7 = 56 64 : 8 = 8 4) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 487 + 302 = 789 660 \u2013 251 = 409 124 x 3 = 372 845 : 7 =120 (d\u01b0 5) 5) x : 6 \uf03d 144 5\uf0b4 x \uf03d 375 x \uf03d 144 \uf0b4 6 x \uf03d 375 : 5 x \uf03d 864 x \uf03d 75 6) S\u1ed1 trang s\u00e1ch An \u0111\u00e3 \u0111\u1ecdc l\u00e0: 128 : 4 = 32 (trang) S\u1ed1 trang s\u00e1ch An c\u00f2n ph\u1ea3i \u0111\u1ecdc l\u00e0: 128 \u2013 96 = 96 (trang) \u0110\u00e1p s\u1ed1 : 96 trang \u0110\u1ec0 S\u1ed0 24 C\u00e2u 1: S\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1 812; 799; 809; 789 l\u00e0......... A. 812 C. 799 B. 809 D. 789 C\u00e2u 2: S\u1ed1 l\u1edbn l\u00e0 42, s\u1ed1 b\u00e9 l\u00e0 6. V\u1eady s\u1ed1 l\u1edbn g\u1ea5p s\u1ed1 b\u00e9 s\u1ed1 l\u1ea7n l\u00e0: A. 24 l\u1ea7n C. 8 l\u1ea7n B. 7 l\u1ea7n D. 6 l\u1ea7n C\u00e2u 3: S\u1ed1 b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1 145; 120; 99; 110 l\u00e0........ A. 145 C. 120 B. 99 D. 110 C\u00e2u 4: Trong ph\u00e9p chia c\u00f3 s\u1ed1 chia l\u00e0 6, s\u1ed1 d\u01b0 l\u1edbn nh\u1ea5t l\u00e0: A. 7 C.6 B. 5 D. 4 C\u00e2u 5: \u0110\u1ebfm th\u00eam r\u1ed3i vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 27; 36; 45; .........; ...........; ............. C\u00e2u 6: 1 gi\u1edd c\u00f3 60 ph\u00fat th\u00ec 1\/2 gi\u1edd c\u00f3 ........... ph\u00fat S\u1ed1 th\u00edch h\u1ee3p \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng l\u00e0: A. 20 C. 30 B. 25 D. 40 Ph\u1ea7n II: (7\u0111) 40 : 5 = .............. C\u00e2u 1: T\u00ednh nh\u1ea9m: (1\u0111) 8 X 4 = ............","63 : 7 = ............ 64 8 X 8 = .............. C\u00e2u 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (1\u0111) b) 396 : 3 a) 170 X 5 C\u00e2u 3: T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: (2\u0111) a) 927 - 10 X 2 b) 100 - (60 + 10) C\u00e2u 4: (1\u0111) M\u1ed9t h\u1ed3 n\u01b0\u1edbc h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 30m. T\u00ednh chu vi h\u1ed3 n\u01b0\u1edbc \u0111\u00f3 ? Gi\u1ea3i: C\u00e2u 5: (2\u0111) C\u00f3 88 b\u1ea1n \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 2 \u0111\u1ed9i, M\u1ed7i \u0111\u1ed9i x\u1ebfp \u0111\u1ec1u th\u00e0nh 4 h\u00e0ng. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 bao nhi\u00eau b\u1ea1n ? Gi\u1ea3i: \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 24 I.TR\u1eaeC NGHI\u1ec6M 1.A 2.B 3,B 4.B 5) 27; 36; 45; 54; 63; 72 II.T\u1ef0 LU\u1eacN 1) 8 x 4 = 32 40 : 5 = 8 63 : 7 = 9 8 x 8 = 64 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a a) 170 x 5 = 850 b) 396 : 3 = 132 3) .a) 927 \u2013 10 x 2 = 927 \u2013 20 = 907 b) 100 \u2013 (60 +10) = 100 \u2013 70 = 30 4) Chu vi h\u1ed3 n\u01b0\u1edbc l\u00e0: 30 x 4 = 120 (m) \u0110\u00e1p s\u1ed1 : 120 m 5) S\u1ed1 b\u1ea1n \u1edf m\u1ed7i \u0111\u1ed9i l\u00e0 : 88 : 2 = 44 (b\u1ea1n) S\u1ed1 b\u1ea1n \u1edf m\u1ed7i h\u00e0ng l\u00e0 : 44 : 4 = 11 (b\u1ea1n) \u0110\u00e1p s\u1ed1: 11 b\u1ea1n \u0110\u1ec0 S\u1ed0 25 Ph\u1ea7n I: Tr\u1eafc nghi\u1ec7m ( 3 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t C\u00e2u 1. (0,5 \u0111i\u1ec3m). 1 kg = \u2026\u2026\u2026g A. 10 B. 100 C. 1 D. 1000 C\u00e2u 2. (0,5 \u0111i\u1ec3m). 5m 6cm = \u2026\u2026.cm A. 56 B. 560 C. 506 D. 5006 C\u00e2u 3. (0,5 \u0111i\u1ec3m). 1 gi\u1edd c\u00f3 bao nhi\u00eau ph\u00fat 5","65 A. 10 ph\u00fat B. 20 ph\u00fat C. 12 ph\u00fat D. 16 ph\u00fat C\u00e2u 4. (0,5 \u0111i\u1ec3m). 54 gi\u1ea3m 9 l\u1ea7n th\u00eam 8 S\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o h\u00ecnh tr\u00f2n l\u00e0: A. 6 B. 14 C. 15 D. 45 C\u00e2u 5. (0,5 \u0111i\u1ec3m). N\u0103m nay con 8 tu\u1ed5i, m\u1eb9 48 tu\u1ed5i. H\u1ecfi tu\u1ed5i m\u1eb9 g\u1ea5p m\u1ea5y l\u1ea7n tu\u1ed5i con ? A. 4 l\u1ea7n B. 3 l\u1ea7n C. 5 l\u1ea7n D. 6 l\u1ea7n C\u00e2u 6. (0,5 \u0111i\u1ec3m). H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 m\u1ea5y g\u00f3c vu\u00f4ng A. 6 g\u00f3c B. 9 g\u00f3c C. 8 g\u00f3c D. 7 g\u00f3c Ph\u1ea7n II: T\u1ef1 lu\u1eadn ( 7 \u0111i\u1ec3m) C\u00e2u 1. ( 2 \u0111i\u1ec3m ) \u0110\u1eb7t t\u00ednh r\u1ed1i t\u00ednh 425 + 231 506 \u2013 213 103 x 8 917 : 7 C\u00e2u 2. ( 1 \u0111i\u1ec3m ) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 50 + 50 x 2 96 : ( 48 : 8) C\u00e2u 3. ( 1 \u0111i\u1ec3m ) Cu\u1ed9n d\u00e2y th\u1ee9 nh\u1ea5t d\u00e0i 120m. Cu\u1ed9n d\u00e2y th\u1ee9 hai d\u00e0i g\u1ea5p 3 l\u1ea7n cu\u1ed9n d\u00e2y th\u1ee9 nh\u1ea5t. H\u1ecfi cu\u1ed9n d\u00e2y th\u1ee9 hai d\u00e0i bao nhi\u00eau m\u00e9t ? C\u00e2u 4. ( 2,5 \u0111i\u1ec3m ) M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 132kg \u0111\u01b0\u1eddng, \u0111\u00e3 b\u00e1n 1 s\u1ed1 ki-l\u00f4-gam \u0111\u01b0\u1eddng \u0111\u00f3. H\u1ecfi c\u1eeda 4 h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau ki-l\u00f4-gam \u0111\u01b0\u1eddng ? C\u00e2u 5. ( 1 \u0111i\u1ec3m ) An ngh\u0129 ra m\u1ed9t s\u1ed1. An l\u1ea5y s\u1ed1 \u0111\u00f3 nh\u00e2n v\u1edbi 4 r\u1ed3i c\u1ed9ng th\u00eam 539 th\u00ec \u0111\u01b0\u1ee3c s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1. H\u00e3y t\u00ecm s\u1ed1 An ngh\u0129. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 25 I.TR\u1eaeC NGHI\u1ec6M 1.D 2.C 3.C 4.B 5.D 6.B II.T\u1ef0 LU\u1eacN 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 425 + 231 = 656 506 \u2013 213 = 293 103 x 8 = 824 917 : 7 = 131 2) a) 50 + 50 x 2 = 50 + 100 = 150 b) 96 : (48 : 8) = 96 : 6 = 16","66 3) S\u1ed1 m\u00e9t cu\u1ed9n d\u00e2y th\u1ee9 hai d\u00e0i l\u00e0: 120 x 3 = 360 (m) \u0110\u00e1p s\u1ed1: 360 m 4) S\u1ed1 kilogam \u0111\u01b0\u1eddng \u0111\u00e3 b\u00e1n l\u00e0 : 132 : 4 = 33 (kg \u0111\u01b0\u1eddng) S\u1ed1 kilogam \u0111\u01b0\u1eddng c\u00f2n l\u1ea1i l\u00e0: 132 \u2013 33 = 99 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1: 99 kg \u0111\u01b0\u1eddng 5) S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0: 999 S\u1ed1 An ngh\u0129 l\u00e0: (999 \u2013 539) : 4 = 115 \u0110\u00e1p s\u1ed1 : 115 \u0110\u1ec0 S\u1ed0 26 I. Ph\u1ea7n tr\u1eafc nghi\u1ec7m : Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang : C\u00e2u 1. S\u1ed1 907 \u0111\u1ecdc l\u00e0: A. Ch\u00edn tr\u0103m b\u1ea3y m\u01b0\u01a1i B. Ch\u00edn tr\u0103m linh b\u1ea3y C. Ch\u00edn b\u1ea3y m\u01b0\u01a1i C\u00e2u 2. 16 g\u1ea5p 4 l\u1ea7n b\u1eb1ng m\u1ea5y? A. 64 B. 20 C. 4 C\u00e2u 3. . 6m 8cm = ? cm A. 68cm B. 608cm C. 520cm C\u00e2u 4. H\u00ecnh vu\u00f4ng l\u00e0 h\u00ecnh : A. H\u00ecnh c\u00f3 b\u1ed1n c\u1ea1nh b\u1eb1ng nhau. B. H\u00ecnh c\u00f3 b\u1ed1n g\u00f3c vu\u00f4ng v\u00e0 b\u1ed1n c\u1ea1nh. C. H\u00ecnh c\u00f3 b\u1ed1n g\u00f3c vu\u00f4ng v\u00e0 b\u1ed1n c\u1ea1nh b\u1eb1ng nhau. C\u00e2u 5.Chu vi h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 7 m, chi\u1ec1u r\u1ed9ng 5 m l\u00e0 : A. 12m B. 24cm C. 35cm C\u00e2u 6. 1 gi\u1edd =......ph\u00fat ? B. 12 ph\u00fat C. 20 ph\u00fat 3 A. 30 ph\u00fat II. T\u1ef1 lu\u1eadn : b) 659 \u2013 92 C\u00e2u 7. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh d) 285 : 7 a) 709 + 195 c) 165 x 4 C\u00e2u 8. T\u00ednh gi\u00e1 th\u1ecb bi\u1ec3u th\u1ee9c: a) (23 + 46) x 7 b) 90 + 172 : 2 C\u00e2u 9. M\u1ed9t th\u00f9ng d\u1ea7u \u0111\u1ef1ng 219 l d\u1ea7u. Ng\u01b0\u1eddi ta \u0111\u00e3 r\u00f3t ra 1 s\u1ed1 d\u1ea7u \u1edf trong th\u00f9ng ra 3 b\u00e1n. H\u1ecfi trong th\u00f9ng c\u00f2n l\u1ea1i bao nhi\u00eau l d\u1ea7u? C\u00e2u 10. a)H\u00e3y vi\u1ebft m\u1ed9t ph\u00e9p t\u00ednh c\u00f3 th\u01b0\u01a1ng b\u1eb1ng 0 b)H\u00e3y vi\u1ebft m\u1ed9t ph\u00e9p t\u00ednh c\u00f3 t\u00edch b\u1eb1ng th\u1eeba s\u1ed1 th\u1ee9 nh\u1ea5t.","67 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 26 I.TR\u1eaeC NGHI\u1ec6M 1.B 2.A 3.B 4.C 5.B 6.C II.T\u1ef0 LU\u1eacN 7) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a a) 709 + 195 = 904 b) 659 \u2013 92 = 567 c) 165 x 4 = 660 d) 285 : 7 = 40 (d\u01b0 5) 8) a) (23 + 46) x 7 = 69 x 7 = 483 b) 90 + 172 : 2 = 90 + 86 = 176 9) S\u1ed1 l\u00edt d\u1ea7u r\u00f3t ra l\u00e0 : 219 : 3 = 73 (l\u00edt d\u1ea7u) S\u1ed1 l\u00edt d\u1ea7u c\u00f2n l\u1ea1i l\u00e0 : 219 \u2013 73 = 146 (l\u00edt d\u1ea7u) \u0110\u00e1p s\u1ed1: 146 l\u00edt d\u1ea7u 10) a) 0 : 9 = 0 8x1=8 \u0110\u1ec0 S\u1ed0 27 B\u00e0i 1 : c. \u0110\u1ebfm th\u00eam r\u1ed3i vi\u1ebft ti\u1ebfp s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m : 30; 36; 42; . . .; . . .; . . .; 14; 21; 28; . . .; . . .; . . . 16; 24; 32; . . .; . . .; . . .; 36; 45; 54; . . .; . . .; . . . b. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng : 6 \uf0b4 6= 24 : 6 = 7 \uf0b4 8= 72 : 9 = 8 \uf0b4 5= 56 : 7 = 6 \uf0b4 9= 48 : 8 = 7 \uf0b4 4= 63 : 9 = 9 \uf0b4 9= 49 : 7 = 6 \uf0b4 7= 81 : 9 = 5 \uf0b4 7= 36 : 6 = B\u00e0i 2 : T\u00ednh \uf0b4 217 976 4 823 5 65 \u2026.. \u2026\u2026\u2026. \u2026.. \u2026\u2026\u2026 \u2026.. \uf0b4 3 \u2026.. 4 \u2026. \u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. B\u00e0i 3 : T\u00ecm x b) 80 - x = 30 a) x + 12 = 36 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026..","68 c) x \uf0b4 9 = 54 d) 42 : x = 7 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. B\u00e0i 4 : H\u00ecnh t\u1ee9 gi\u00e1c ABCD, g\u00f3c n\u00e0o l\u00e0 g\u00f3c vu\u00f4ng ? G\u00f3c n\u00e0o l\u00e0 g\u00f3c kh\u00f4ng vu\u00f4ng ? AB DC B\u00e0i 5 : Gi\u1ea3i to\u00e1n : M\u1ed9t bao g\u1ea1o c\u00e2n n\u1eb7ng 25 kg. M\u1ed9t bao ng\u00f4 c\u00e2n n\u1eb7ng g\u1ea5p \u0111\u00f4i bao g\u1ea1o. H\u1ecfi bao g\u1ea1o v\u00e0 bao ng\u00f4 c\u00e2n n\u1eb7ng bao nhi\u00eau ki l\u00f4 gam ? \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 27 1) a) 30;36;42;48;54;60 14; 21; 28; 35; 42; 49 16; 24; 32; 40; 48; 56 36; 45; 54; 63; 72; 81. b) 6 x 6 = 36 24 : 6 = 4 7 x 8 = 56 72 : 9 = 8 8 x 5 = 40 56 : 7 = 8 6 x 9 = 64 48 : 8 = 6 7 x 4 = 28 63 : 9 = 7 9 x 9 = 81 49 : 7 = 7 6 x 7 = 42 81 : 9 = 9 5 x 7 = 35 36 : 6 = 6 2)\u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 65 x 4 = 260 217 x 3 = 651 976 : 4 = 244 823 : 5 = 164 (d\u01b0 3) 3) T\u00ecm x b)80 \uf02d x \uf03d 30 a) x \uf02b12 \uf03d 36 x \uf03d 36 \uf02d12 x \uf03d 80 \uf02d 30 x \uf03d 24 x \uf03d 50 c) x \uf0b4 9 \uf03d 54 d) 42 : x \uf03d 7 x \uf03d 54 : 9 x \uf03d 42 : 7 x\uf03d6 x\uf03d6 4) G\u00f3c vu\u00f4ng: g\u00f3c A, g\u00f3c D G\u00f3c kh\u00f4ng vu\u00f4ng: G\u00f3c B, g\u00f3c C","69 5) S\u1ed1 kilogam c\u00e2n n\u1eb7ng c\u1ee7a bao ng\u00f4 l\u00e0: 25 x 2 = 50 (kg) S\u1ed1 kilogam bao g\u1ea1o v\u00e0 bao ng\u00f4 c\u00e2n n\u1eb7ng l\u00e0 : 50 + 25 = 75 (kg) \u0110\u00e1p s\u1ed1: 75 kg. \u0110\u1ec0 S\u1ed0 28 B\u00e0i 1: (2\u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 319 x 3 205 x 4 99 : 4 630 : 9 B\u00e0i 2: (2\u0111) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 15 +7 x 8 ; 81 : 9 + 10 ; 56 x (17 - 12) ; 46 : (6 : 3) B\u00e0i 3: (1,5\u0111) C\u00f3 35m v\u1ea3i, may m\u1ed7i b\u1ed9 qu\u1ea7n \u00e1o h\u1ebft 3m. H\u1ecfi c\u00f3 th\u1ec3 may \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t l\u00e0 m\u1ea5y b\u1ed9 qu\u1ea7n \u00e1o v\u00e0 c\u00f2n th\u1eeba m\u1ea5y m\u00e9t v\u1ea3i? B\u00e0i 4: (1\u0111) 5m 6cm ..... 5m; 5m 6cm ... 6m > 6m 3cm ...... 7m; 450g ....500g - 40g; < = 400g + 8g ..... 480g; B\u00e0i 5: (1,5\u0111) T\u00ednh chu vi m\u1ed9t s\u00e2n b\u00f3ng \u0111\u00e1 mini c\u00f3 chi\u1ec1u d\u00e0i 42 m v\u00e0 chi\u1ec1u r\u1ed9ng l\u00e0 25m. B\u00e0i 6: (1\u0111) Vi\u1ebft v\u00e0o \u00f4 tr\u1ed1ng: S\u1ed1 l\u1edbn S\u1ed1 b\u00e9 S\u1ed1 l\u1edbn g\u1ea5p m\u1ea5y l\u1ea7n s\u1ed1 b\u00e9? S\u1ed1 b\u00e9 b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 l\u1edbn? 93 .............................. ............................................ 16 4 ............................... ...................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 28 .1) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 319 x 3 = 957 205 x 4 = 820 99 : 4 = 24 (d\u01b0 3) 630 : 9 = 70 2) 15 + 7 x 8 = 15 + 56 = 71 81 : 9 + 10 = 9 +10 =19 56 x (17 \u2013 12 ) = 56 x 5 = 280 46 : (6 : 3) = 46 : 2 =23 3) Ta c\u00f3 35 : 3 = 11 (d\u01b0 2) V\u1eady c\u00f3 th\u1ec3 may \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t 11 b\u1ed9 qu\u1ea7n \u00e1o , th\u1eeba 2m v\u1ea3i 4) 6m 3 cm < 7 m 5 m 6 cm > 5 m 400 g + 8 g < 480g 5 m 6cm < 6 m 450 g < 500 g \u2013 40 g","70 5) Chu vi s\u00e2n b\u00f3ng mini l\u00e0: (42 + 25) x 2 = 134 (m) \u0110\u00e1p s\u1ed1: 134 m B\u00e0i 6. S\u1ed1 l\u1edbn S\u1ed1 b\u00e9 S\u1ed1 l\u1edbn g\u1ea5p m\u1ea5y l\u1ea7n s\u1ed1 S\u1ed1 b\u00e9 b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 l\u1edbn? b\u00e9? 93 3 1 3 16 4 4 1 4 1\/ T\u00ednh nh\u1ea9m (1\u0111): \u0110\u1ec0 S\u1ed0 29 a) 5 x 6 = ....................... 7 x 8 = ...................... b) 48 : 6 = ...................... 35 : 7 = ..................... 2\/ \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111): a) 124 x 4 b) 684 : 6 ............................. ............................... ............................. ............................... ............................. ............................... ............................. ............................... 3\/ \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng (1\u0111) : a) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 150: 5 x 3 l\u00e0 90 b) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 15 + 7 x 8 l\u00e0 70 4\/ T\u00ecm X (2\u0111): a) X : 3 = 213 b) X + 236 = 442 ............................. ............................... ............................. ............................... ............................. ............................... 5\/ Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang (1\u0111): a) 4 kg b\u1eb1ng: A. 40 g B. 400 g C. 4000 g b) \u0110\u1ed3ng h\u1ed3 ch\u1ec9: 11 12 1 10 2 93 84 76 5 A. 9 gi\u1edd 6 ph\u00fat B. 9 gi\u1edd 25 ph\u00fat C. 9 gi\u1edd 15 ph\u00fat D. 9 gi\u1edd 30 ph\u00fat 6\/ M\u1ea3nh v\u1ea3i \u0111\u1ecf d\u00e0i 14m, m\u1ea3nh v\u1ea3i xanh d\u00e0i h\u01a1n m\u1ea3nh v\u1ea3i \u0111\u1ecf 5m. H\u1ecfi c\u1ea3 hai m\u1ea3nh v\u1ea3i \u0111\u00f3 d\u00e0i bao nhi\u00eau m\u00e9t ? (2\u0111) B\u00e0i l\u00e0m","71 ................................................................................... ................................................................................... ................................................................................... ................................................................................... ................................................................................... ................................................................................... 7\/ H\u00ecnh v\u1ebd b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh vu\u00f4ng?(1\u0111) ................................................................................ ............................................................................... ............................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 29 1)T\u00ednh nh\u1ea9m: a) 5 x 6 = 30 7 x 8 = 56 b) 48 : 6 = 8 35: 7 = 5 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 1\u0111 a) 124 x 4 = 496 b) 684 : 6 = 114 3) a) \u0110 b) S 4)a) x : 3 \uf03d 213 x \uf02b 236 \uf03d 442 x \uf03d 213\uf0b43 x \uf03d 442 \uf02d 236 x \uf03d 639 x \uf03d 206 5) a) C b) D 6) S\u1ed1 m\u00e9t m\u1ea3nh v\u1ea3i xanh d\u00e0i l\u00e0: 14 + 5 = 19 (m) S\u1ed1 m\u00e9t hai m\u1ea3nh v\u1ea3i d\u00e0i l\u00e0: 14 + 19 = 33 (m) \u0110\u00e1p s\u1ed1: 33 m 7)H\u00ecnh v\u1ebd b\u00ean c\u00f3 14 h\u00ecnh vu\u00f4ng \u0110\u1ec0 S\u1ed0 30 PH\u1ea6N I : Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u. 1.G\u1ea5p 7 l\u00edt l\u00ean 8 l\u1ea7n th\u00ec \u0111\u01b0\u1ee3c: a. 15 l\u00edt b. 49 l\u00edt c. 56 l\u00edt d. 65 l\u00edt 2. 7m 4cm = \u2026\u2026.. cm. S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng l\u00e0: a. 74cm b. 740cm c. 407cm d. 704cm 3. T\u1ed5ng c\u1ee7a 16 v\u00e0 14 r\u1ed3i nh\u00e2n v\u1edbi 4 l\u00e0: a. 30 b. 34 c. 72 d. 120","72 4. M\u1ed9t c\u00e1i ao h\u00ecnh vu\u00f4ng c\u00f3 chu vi l\u00e0 24 m th\u00ec c\u1ea1nh c\u1ee7a h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0: a. 4m b. 6m c. 8m d. 12cm 5. S\u1ed1 th\u00edch h\u1ee3p vi\u1ebft v\u00e0o ch\u1ed7 tr\u1ed1ng trong ph\u00e9p t\u00ednh x6 :8 4 l\u00e0: a. 24 v\u00e0 3 b. 24 v\u00e0 4 c. 24 v\u00e0 6 d. 24 v\u00e0 8 1 6. 3 c\u1ee7a 24 kg l\u00e0: a. 1kg b. 3 kg c. 8 kg d. 12 kg c. 3 d. C\u1ea3 a, b, c \u0111\u1ec1u 7. Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 3 trong s\u1ed1 132 l\u00e0: a. 300 b. 30 sai 8. H\u00ecnh b\u00ean c\u00f3 g\u00f3c : a. Vu\u00f4ng. b. Kh\u00f4ng vu\u00f4ng. 9. S\u1ed1 d\u01b0 trong ph\u00e9p chia 27 : 5 l\u00e0 : c. 3 d. 4 a. 1 b. 2 PH\u1ea6N II : T\u00cdNH 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. (2 \u0111i\u1ec3m) 576 + 185 720 \u2013 342 75 x 7 783 : 6 2. T\u00ecm x: (1 \u0111i\u1ec3m) x + 23 = 81 100 : x = 4 1 3. M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 104kg g\u1ea1o, c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111i 4 kg g\u1ea1o \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau kg g\u1ea1o? (2 \u0111i\u1ec3m) Gi\u1ea3i \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 30 I.TR\u1eaeC NGHI\u1ec6M 1.C 2.D 3.D 4.B 5.A 6.C 7.B 8.A 9.B II.T\u00ednh 1)\u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u01b0\u1ee3c 0,5\u0111 576+185 = 761 720 \u2013 342 = 378","73 75 x 7 = 525 783 : 6 = 130 (d\u01b0 3) 2) x\uf02b 23 \uf03d 81 100 : x \uf03d 4 x \uf03d 81\uf02d 23 x \uf03d 100 : 4 x \uf03d 58 x \uf03d 25 3)S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111i l\u00e0: 104 : 4 = 26 (kg g\u1ea1o) S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i l\u00e0: 104 \u2013 26 = 78 (kg g\u1ea1o) \u0110\u00e1p s\u1ed1: 78 kg g\u1ea1o \u0110\u1ec0 S\u1ed0 31 PH\u1ea6N 1 : L\u00fd thuy\u1ebft ( \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.\/ 2 \u0111 ) M\u1ed7i b\u00e0i t\u1eadp d\u01b0\u1edbi \u0111\u00e2y c\u00f3 n\u00eau k\u00e8m theo m\u1ed9t c\u00e2u tr\u1ea3 l\u1eddi A, B, C, D ( l\u00e0 \u0111\u00e1p s\u1ed1 , k\u1ebft qu\u1ea3 t\u00ednh,\u2026). H\u00e3y khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u k\u1ebft qu\u1ea3 \u0111\u00fang. C\u00e2u 1: K\u1ebft qu\u1ea3 c\u1ee7a bi\u1ec3u th\u1ee9c 48 : (4 X 2) l\u00e0: A. 6 B. 8 C. 10 D. 12 D. 24 ph\u00fat C\u00e2u 2: M\u1ed9t gi\u1edd c\u00f3 60 ph\u00fat. V\u1eady 1 gi\u1edd b\u1eb1ng: 4 A. 10 ph\u00fat B. 15 ph\u00fat C. 20 ph\u00fat C\u00e2u 3: M\u1ed9t qu\u1ea3 l\u00ea n\u1eb7ng: A. 400g B. 400kg C. 4kg D. 4g C\u00e2u 4: H\u00ecnh ch\u1eef nh\u1eadt l\u00e0 h\u00ecnh : A. c\u00f3 4 g\u00f3c vu\u00f4ng v\u00e0 4 c\u1ea1nh b\u1eb1ng nhau. B. c\u00f3 4 g\u00f3c vu\u00f4ng, c\u00f3 2 c\u1ea1nh d\u00e0i b\u1eb1ng nhau v\u00e0 2 c\u1ea1nh ng\u1eafn b\u1eb1ng nhau. C. C\u1ea3 A, B \u0111\u00fang. D. C\u1ea3 A, B sai. PH\u1ea6N 2: T\u1ef1 lu\u1eadn ( \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.\/ 8 \u0111 ) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. 765 \u2013 374 305 X 3 845 : 7 175 + 453 C\u00e2u 2: a. T\u00ecm X, bi\u1ebft: X : 7 = 113 b. T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c 107 X (54 \u2013 48) = C\u00e2u 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026\u2026)","74 1m = \u2026\u2026..dm = \u2026\u2026.. cm 4m 5dm =\u2026\u2026\u2026.dm 2dm 7cm =\u2026\u2026\u2026\u2026\u2026.cm 6dam =\u2026\u2026\u2026\u2026\u2026m C\u00e2u 4: M\u00f9a xo\u00e0i n\u0103m nay, \u0111\u1ee3t \u0111\u1ea7u b\u00e1c ba h\u00e1i \u0111\u01b0\u1ee3c 60kg xo\u00e0i, \u0111\u1ee3t 2 b\u00e1c ba h\u00e1i \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n \u0111\u1ee3t \u0111\u1ea7u 25kg xo\u00e0i. H\u1ecfi c\u1ea3 hai \u0111\u1ee3t b\u00e1c ba thu ho\u1ea1ch \u0111\u01b0\u1ee3c bao nhi\u00eau kil\u00f4gam xo\u00e0i. Gi\u1ea3i \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 31 I.L\u00dd THUY\u1ebeT 1.A 2.B 3.A 4.B II.T\u1ef0 LU\u1eacN 1)\u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 175+453 = 628 765 \u2013 374 = 391 305 x 3 = 915 845 : 7 = 120 (d\u01b0 5) 2)a) x : 7 \uf03d 113 x \uf03d 113\uf0b4 7 x \uf03d 791 b)107\uf0b4 \uf02854 \uf02d 48\uf029 \uf03d 107\uf0b46 \uf03d 642 3)1m \uf03d 10 dm \uf03d 100 cm 4m5dm \uf03d 45dm 2 dm 7 cm \uf03d 27 cm 6 dam \uf03d 60m 4)S\u1ed1 kilogam xo\u00e0i \u0111\u1ee3t 2 h\u00e1i l\u00e0: 60 + 25=85 (kg xo\u00e0i) S\u1ed1 kilogam xo\u00e0i c\u1ea3 2 \u0111\u1ee3t h\u00e1i l\u00e0 : 60 + 85 = 145 (kg xo\u00e0i) \u0110\u00e1p s\u1ed1: 145 kg xo\u00e0i \u0110\u1ec0 S\u1ed0 32 I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m): Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. S\u1ed1 355 \u0111\u1ecdc l\u00e0: B. Ba tr\u0103m n\u0103m l\u0103m. A. Ba n\u0103m n\u0103m. C. Ba tr\u0103m n\u0103m m\u01b0\u01a1i n\u0103m. B. Ba tr\u0103m n\u0103m m\u01b0\u01a1i l\u0103m. 2. S\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ....l\u00e0: A. 60 B. 30 1 ph\u00fat = .....gi\u00e2y. D. 12 5 C. 15 3. Con l\u1ee3n n\u1eb7ng 100 kg, con ng\u1ed7ng n\u1eb7ng 5 kg. H\u1ecfi con l\u1ee3n n\u1eb7ng g\u1ea5p bao nhi\u00eau l\u1ea7n con ng\u1ed7ng? A. 50 l\u1ea7n B. 20 l\u1ea7n C. 10 l\u1ea7n D. 5 l\u1ea7n","75 4. M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng l\u00e0 4 cm, chi\u1ec1u d\u00e0i 12 cm. M\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 chu vi b\u1eb1ng chu vi c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3. V\u1eady c\u1ea1nh c\u1ee7a h\u00ecnh vu\u00f4ng l\u00e0: A. 32 cm B. 16 cm C. 8 cm D. 7 cm 5. D\u1ea5u c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ....l\u00e0: D. Kh\u00f4ng \u0111i\u1ec1n \u0111\u01b0\u1ee3c 2 kg 3 m.......32 m A. < B. > C. = 6. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c 65 - 12 x 3 l\u00e0 A. 159 B. 39 C. 29 Ii. t\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m): C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2 \u0111i\u1ec3m): 128 + 321 942 \u2013 58 105 x 7 852 : 6 .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... C\u00e2u 2. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c (1,5 \u0111i\u1ec3m): 456 - 34 + 56 84 + 645 : 5 175 - (104 : 8) .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... C\u00e2u 3. (2 \u0111i\u1ec3m) C\u00f3 57 ng\u01b0\u1eddi c\u1ea7n qua s\u00f4ng. M\u1ed7i chi\u1ebfc thuy\u1ec1n ch\u1ec9 ch\u1edf \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t l\u00e0 7 ng\u01b0\u1eddi (kh\u00f4ng k\u1ec3 l\u00e1i thuy\u1ec1n). H\u1ecfi c\u1ea7n \u00edt nh\u1ea5t bao nhi\u00eau thuy\u1ec1n \u0111\u1ec3 ch\u1edf m\u1ed9t l\u01b0\u1ee3t h\u1ebft s\u1ed1 ng\u01b0\u1eddi \u0111\u00f3? .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... C\u00e2u 4. (1 \u0111i\u1ec3m) C\u00f3 432 c\u00e2y ng\u00f4 \u0111\u01b0\u1ee3c tr\u1ed3ng \u0111\u1ec1u tr\u00ean 4 lu\u1ed1ng, m\u1ed7i lu\u1ed1ng c\u00f3 2 h\u00e0ng. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 bao nhi\u00eau c\u00e2y ng\u00f4? .......................................................................................................................................... ..........................................................................................................................................","76 .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... C\u00e2u 5. (0,5 \u0111i\u1ec3m) T\u00ednh nhanh: (8 x 7 - 16 - 5 x 8) x (1 + 2 + 3 + 4 + 6 + 7 + 8 + 9) .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 32 I.TR\u1eaeC NGHI\u1ec6M 1.C 2.D 3.B 4.C 5.D 6.C II.T\u1ef0 LU\u1eacN 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 128+321=449 942 \u2013 58 = 884 105 x 7 = 735 852 : 6 =142 2)T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c 456 \u2013 34 + 56 = 422 + 56 = 478 84 + 645 : 5 = 84 + 129 = 213 175 \u2013 (104:8) = 175 \u2013 13 =162 3) Ta c\u00f3 57 : 7 = 8 (d\u01b0 1) V\u1eady s\u1ed1 thuy\u1ec1n \u00edt nh\u1ea5t c\u1ea7n c\u00f3 l\u00e0: 8 + 1 = 9 (thuy\u1ec1n) \u0110\u00e1p s\u1ed1: 9 thuy\u1ec1n 4) S\u1ed1 c\u00e2y ng\u00f4 m\u1ed7i lu\u1ed1ng c\u00f3 l\u00e0: 432 : 4 = 108 (c\u00e2y ng\u00f4) S\u1ed1 c\u00e2y ng\u00f4 m\u1ed7i h\u00e0ng c\u00f3 l\u00e0 : 108 : 2 = 54 (c\u00e2y ng\u00f4) \u0110\u00e1p s\u1ed1: 54 c\u00e2y ng\u00f4 5)(8\uf0b4 7 \uf02d16 \uf02d 5\uf0b48)\uf0b4 \uf0281\uf02b 2 \uf02b 3 \uf02b 4 \uf02b 5 \uf02b 6 \uf02b 7 \uf02b 8 \uf02b 9\uf029 \uf03d (56 \uf02d16 \uf02d 40)\uf0b4 \uf0281\uf02b 2 \uf02b 3 \uf02b 4 \uf02b 5 \uf02b 6 \uf02b 7 \uf02b 8 \uf02b 9\uf029 \uf03d 0\uf0b4\uf0281\uf02b 2 \uf02b 3 \uf02b 4 \uf02b 5 \uf02b 6 \uf02b 7 \uf02b 8 \uf02b 9\uf029 \uf03d 0 \u0110\u1ec0 S\u1ed0 33 Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. S\u1ed1 g\u1ed3m b\u1ea3y tr\u0103m, n\u0103m \u0111\u01a1n v\u1ecb v\u00e0 hai ch\u1ee5c l\u00e0: A. 752 B. 725 C. 700520 D. 7520 C. = 2. D\u1ea5u c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ....l\u00e0: 4m 3 cm......430 cm A. < B. > 3. S\u1ed1 b\u00e9 l\u00e0 9, s\u1ed1 l\u1edbn l\u00e0 81. S\u1ed1 b\u00e9 b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 l\u1edbn? A. 9 l\u1ea7n B. 1 C. 1 D. 81 l\u1ea7n 81 9","77 4. 1 gi\u1edd = ......ph\u00fat. S\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ....l\u00e0: 4 A. 60 B. 30 C. 20 D. 15 5. M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 12 cm, chi\u1ec1u r\u1ed9ng b\u1eb1ng 1 chi\u1ec1u d\u00e0i. Chu vi 3 c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 l\u00e0: A. 32 B. 24 cm C. 32 cm D. 30 6. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c 56 + 24 : 4 l\u00e0 A. 20 B. 60 C. 62 II. t\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m): C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2 \u0111i\u1ec3m): 321 + 83 634 - 307 102 x 6 764 : 4 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ............................................ C\u00e2u 2. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c (1,5 \u0111i\u1ec3m): 450 - 45 : 9 34 x (56 : 8) 471 + 83 - 71 ..................................................................................................................................... ..................................................................................................................................... ...................... C\u00e2u 3. (2 \u0111i\u1ec3m) Th\u00f9ng th\u1ee9 nh\u1ea5t \u0111\u1ef1ng 123 l\u00edt d\u1ea7u, th\u00f9ng th\u1ee9 hai \u0111\u1ef1ng b\u1eb1ng 1 3 th\u00f9ng th\u1ee9 nh\u1ea5t. H\u1ecfi c\u1ea3 hai th\u00f9ng \u0111\u1ef1ng bao nhi\u00eau l\u00edt d\u1ea7u? ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ............................................ ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ................................. C\u00e2u 4. ( 1 \u0111i\u1ec3m) Kh\u1ed1i 3 c\u1ee7a m\u1ed9t tr\u01b0\u1eddng Ti\u1ec3u h\u1ecdc c\u00f3 72 h\u1ecdc sinh \u0111\u01b0\u1ee3c ph\u00e2n \u0111\u1ec1u th\u00e0nh 3 l\u1edbp. M\u1ed7i l\u1edbp \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 3 t\u1ed5. H\u1ecfi m\u1ed7i t\u1ed5 c\u00f3 bao nhi\u00eau h\u1ecdc sinh?","78 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ............................................ ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ................................. C\u00e2u 5. (0,5 \u0111i\u1ec3m) T\u00ednh nhanh: 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ............................................ ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 33 1.B 2.A 3.C 4.D 5.C 6.C II.T\u1ef0 LU\u1eacN 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 321+83 = 404 634 \u2013 307 = 327 102 x 6 = 612 764 : 4 = 191 2) 450 \u2013 45 : 9 =450 \u2013 5 = 445 34 x (56 : 8) =34 x 7 = 238 471 + 83 \u2013 71 = 554 \u2013 71 = 483 3) S\u1ed1 l\u00edt d\u1ea7u th\u00f9ng th\u1ee9 hai \u0111\u1ef1ng l\u00e0 : 123 : 3 = 41 (l d\u1ea7u) S\u1ed1 l\u00edt d\u1ea7u c\u1ea3 hai th\u00f9ng \u0111\u1ef1ng l\u00e0 : 123 + 41 = 164 ( l d\u1ea7u) \u0110\u00e1p s\u1ed1: 164 l d\u1ea7u 4)S\u1ed1 h\u1ecdc sinh m\u1ed7i l\u1edbp c\u00f3 l\u00e0: 72 :3 = 24 (h\u1ecdc sinh) S\u1ed1 h\u1ecdc sinh m\u1ed7i t\u1ed5 c\u00f3 l\u00e0: 24:3 = 8 (h\u1ecdc sinh) \u0110\u00e1p s\u1ed1 : 8 h\u1ecdc sinh 5)1\uf02b 3 \uf02b 5 \uf02b 7 \uf02b 9 \uf02b11\uf02b13 \uf02b15 \uf02b17 \uf02b19 \uf03d (19 \uf02b1) \uf02b (3 \uf02b17) \uf02b (5 \uf02b15) \uf02b (7 \uf02b13) \uf02b (9 \uf02b11) \uf03d 20 \uf02b 20 \uf02b 20 \uf02b 20 \uf02b 20 \uf03d 100 \u0110\u1ec0 S\u1ed0 34 B\u00e0i 1. ( 1.0 \u0111i\u1ec3m)Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m (.... ) a, 72; 64; 56; ...; ....; .... ; ..... b, 26; 35 ; 44; .... ; .... ;....; ....... C\u00e2u 2: ( 0.5 \u0111i\u1ec3m) Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m:","79 a, 60 ph\u00fat =.... gi\u1edd b, 1 gi\u1edd = ....ph\u00fat 4 C\u00e2u 3: ( 0.5 \u0111i\u1ec3m) ( Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang) M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 7m\u00e9t, chi\u1ec1u r\u1ed9ng 5 m\u00e9t. Chu vi l\u00e0: A. 12 m ; B. 24 m ; C. 35 m C\u00e2u 4: ( 1.0 \u0111i\u1ec3m) T\u00edch c\u1ee7a hai s\u1ed1 l\u00e0 54. Bi\u1ebft r\u1eb1ng th\u1eeba s\u1ed1 th\u1ee9 nh\u1ea5t l\u00e0 6 .T\u00ecm th\u1eeba s\u1ed1 th\u1eeba s\u1ed1 th\u1ee9 hai? ............................................................................................................................... ............................................................................................................................... C\u00e2u 5: ( 3.0 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, 709 + 195 b, 659 \u2013 92 c, 165 x 4 d, 285 : 7 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... .................................... C\u00e2u 6 : ( 2.0 \u0111i\u1ec3m) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c : a, ( 23 + 46) x 7 b, 90 + 172 : 2 ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... .................................................................... C\u00e2u 7: ( 2.0 \u0111i\u1ec3m) M\u1ed9t l\u1edbp h\u1ecdc c\u00f3 35 h\u1ecdc sinh, ph\u00f2ng h\u1ecdc c\u1ee7a l\u1edbp \u0111\u00f3 \u0111\u01b0\u1ee3c trang b\u1ecb lo\u1ea1i b\u00e0n gh\u1ebf 2 ch\u1ed7 ng\u1ed3i. H\u1ecfi c\u1ea7n \u00edt nh\u1ea5t bao nhi\u00eau b\u00e0n gh\u1ebf nh\u01b0 th\u1ebf? ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 34 1) a) 72;64;56;48;40;32;24 b)26;35;44;53;62;71;80. b) \u00bc gi\u1edd = 15 ph\u00fat 2) a) 60 ph\u00fat = 1 gi\u1edd 3)B 4) Th\u1eeba s\u1ed1 th\u1ee9 hai l\u00e0 :54 : 6 = 9 \u0110\u00e1p s\u1ed1: 9","80 5) M\u00e7i c\u00a9u \u00ae\u00c6t t\u00ddnh \u00ae\u00f3ng \u00ae\u00ad\u00eec0,75\u00ae a) 709+195=904 b)659 - 92 =567 c) 165 \uf0b4 4 \uf03d 660 d)285 : 7 \uf03d 40(d\u00ad 5) 6)a)(23 \uf02b 46)\uf0b4 7 \uf03d 69\uf0b4 7 \uf03d 483 b) 90 \uf02b172 : 2 \uf03d 90 \uf02b 86 \uf03d 176 7) Ta c\u00e3 :35 : 2 \uf03d 17(d\u00ad1) V\u00cby s\u00e8 b\u00b5n gh\u00d5 c\u00c7n c\u00e3 l\u00b5 :17 \uf02b1 \uf03d 18(b\u00b5n gh\u00d5) \u00a7\u00b8p s\u00e8 :18 b\u00b5n gh\u00d5 \u0110\u1ec0 S\u1ed0 35 B\u00e0i 1: M\u1ed7i b\u00e0i t\u1eadp d\u01b0\u1edbi \u0111\u00e2y c\u00f3 c\u00e1c c\u00e2u tr\u1ea3 l\u1eddi A, B, C, D. H\u00e3y khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang. (2 \u0111i\u1ec3m ) 1. D\u1ea5u ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng \u1edf ph\u00e9p so s\u00e1nh sau \u0111\u00e2y 6m 4 cm \uf063 7 m l\u00e0: A. > B. < C. = D. Kh\u00f4ng \u0111i\u1ec1n \u0111\u01b0\u1ee3c d\u1ea5u n\u00e0o. 2. 1 gi\u1edd \u2013 20 ph\u00fat = A. 40 ph\u00fat B. 40 gi\u1edd C. 80 ph\u00fat D. Kh\u00f4ng tr\u1eeb \u0111\u01b0\u1ee3c. 3. Ph\u00e9p t\u00ednh nh\u00e2n n\u00e0o d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 24 ? A. 6 x 9 B. 7 x 5 C. 6 x 4 D. 7 x 6 4. Ph\u00e9p t\u00ednh chia n\u00e0o d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 7 ? A. 28 : 7 B. 48 : 6 C. 81 : 9 D. 56 : 8 B\u00e0i 2: N\u1ed1i bi\u1ec3u th\u1ee9c \u1ee9ng v\u1edbi gi\u00e1 tr\u1ecb \u0111\u00e3 cho? ( 2 \u0111i\u1ec3m ) (100 + 11) x 6 100 + 11 x 6 201 + 39 : 3 375 \u2013 10 x 3 214 666 452 345 166 B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: ( 2 \u0111i\u1ec3m ) 26 x 7 213 x 4 246 : 6 343 : 3","81 B\u00e0i 4: Vi\u1ebft v\u00e0o \u00f4 tr\u1ed1ng theo m\u1eabu: (1 \u0111i\u1ec3m ) C\u1ea1nh h\u00ecnh vu\u00f4ng 7cm 21cm 35dm Chu vi h\u00ecnh vu\u00f4ng 7 x 4 = 28cm B\u00e0i 5: ( 2 \u0111i\u1ec3m ) M\u1ed9t kho th\u00f3c c\u00f3 180 bao th\u00f3c. Ng\u01b0\u1eddi ta \u0111\u00e3 b\u00e1n h\u1ebft 1 s\u1ed1 bao th\u00f3c trong 3 kho. H\u1ecfi trong kho c\u00f2n l\u1ea1i bao nhi\u00eau bao th\u00f3c ? T\u00f3m t\u1eaft Gi\u1ea3i: B\u00e0i 6: \u0110\u1ed3ng h\u1ed3 h\u00ecnh b\u00ean ch\u1ec9 m\u1ea5y gi\u1edd ? (1 \u0111i\u1ec3m ) .............................................................. ................. .............................................................. ................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 35 B\u00b5i1. 1)B 2)A 3)C 4)D B\u00b5i 2.(100 \uf02b11)\uf0b4 6 \uf03d 666 100 \uf02b11\uf0b4 6 \uf03d 166 201\uf02b 39 : 3 \uf03d 214 375 \uf02d10\uf0b43 \uf03d 345 b\u00b5i 3.M\u00e7i b\u00b5i \u00ae\u00c6t t\u00ddnh \u00ae\u00f3ng \u00ae\u00ad\u00eec0,5\u00ae 26 \uf0b4 7 \uf03d 182 213\uf0b4 4 \uf03d 852 246 : 6 \uf03d 41 343 : 3 \uf03d 114 (d\u00ad 1)","82 B\u00b5i 4.C\u00b9nh 21cm,chu vi : 21\uf0b4 4 \uf03d 84 (cm) C\u00b9nh 35dm,chu vi :35\uf0b4 4 \uf03d 140(dm) B\u00b5i 5.S\u00e8 bao th \u00e3c \u00ae\u00b7 b\u00b8n h\u00d5t l\u00b5 :180 : 3 \uf03d 60(bao th\u00e3c) S\u00e8 bao th\u00e3c c\u00dfn l\u00b9i l\u00b5 :180 \uf02d 60 \uf03d 120(bao th\u00e3c) \u00a7\u00b8p s\u00e8 :120 bao th\u00e3c B\u00b5i 6. \u00a7\u00e5ng h\u00e5 ch\u00d810 gi\u00ea10 ph\u00f3t \u0110\u1ec0 S\u1ed0 36 B\u00e0i 1: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 160 l\u00e0: A. 161 B. 150 C. 159 D. 170 b)M\u1ed9t c\u00e1i ao h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 6 m.Chu vi c\u1ee7a h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0: A.24m B.36 m C. 10 m D. 12 cm c ) 9m 8cm = \u2026. cm . S\u1ed1 th\u00edch h\u1ee3p c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. 98 B. 908 C. 980 D .9080 d )G\u1ea5p 7 l\u00edt l\u00ean 8 l\u1ea7n th\u00ec \u0111\u01b0\u1ee3c: A. 15 l\u00edt B. 49 l\u00edt C. 56 l\u00edt D. 65 l\u00edt B\u00e0i 2: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng : *Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c b) 2 + 8 x 5 = 50 c) 32 : 4 + 4 = 12 B\u00e0i 3: T\u00ednh nh\u1ea9m 8 x 7 = \u2026..... 7 x 6 = \u2026\u2026. 64 : 8 =\u2026\u2026. 63 : 9=\u2026\u2026. 660 \u2013 251 124 x 3 845 : 7 B\u00e0i 4: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh \u2026.\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 487 + 302 \u2026.\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026 B\u00e0i 5: T\u00ecm x: b) 5 x X = 375 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) X : 6 = 144 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 6 : M\u1ed9t quy\u1ec3n truy\u1ec7n d\u00e0y 128 trang. An \u0111\u00e3 \u0111\u1ecdc \u0111\u01b0\u1ee3c 1 s\u1ed1 trang \u0111\u00f3. H\u1ecfi c\u00f2n 4 bao nhi\u00eau trang truy\u1ec7n n\u1eefa m\u00e0 An ch\u01b0a \u0111\u1ecdc? .......................................................................................................................................... .......................................................................................................................................... ..........................................................................................................................................","83 .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 36 .1) a) C b) A c) B d) C 2) a)S b)\u0110 3) 7x6 = 42; 63 : 9 = 7 8 x 7 = 56 64 : 8 = 8 4) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 487 + 302 = 789 660 \u2013 251 = 409 124 x 3 = 372 845 : 7 =120 (d\u01b0 5) 5) x : 6 \uf03d 144 5\uf0b4 x \uf03d 375 x \uf03d 144 \uf0b4 6 x \uf03d 375 : 5 x \uf03d 864 x \uf03d 75 6) S\u1ed1 trang s\u00e1ch An \u0111\u00e3 \u0111\u1ecdc l\u00e0: 128 : 4 = 32 (trang) S\u1ed1 trang s\u00e1ch An c\u00f2n ph\u1ea3i \u0111\u1ecdc l\u00e0: 128 \u2013 96 = 96 (trang) \u0110\u00e1p s\u1ed1 : 96 trang \u0110\u1ec0 S\u1ed0 37 C\u00e2u 1: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m (1\u0111i\u1ec3m). 63 : 7 = \u2026\u2026 35 : 5 = \u2026\u2026\u2026. 42 : 6 = \u2026\u2026.. 56 : 7 = C\u00e2u 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111i\u1ec3m): a) 235 \uf0b4 2 = b) 630 : 7 = \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 3: Th\u1ef1c hi\u1ec7n t\u00ednh (2 \u0111i\u1ec3m). a) 205 + 60 +3 = \u2026\u2026\u2026.. b) 462 + 7 \u2013 40 = \u2026\u2026\u2026\u2026\u2026. C\u00e2u 4: (3 \u0111i\u1ec3m) S\u1ed1 b\u00f2 nhi\u1ec1u h\u01a1n s\u1ed1 tr\u00e2u l\u00e0 28 con. Bi\u1ebft r\u1eb1ng s\u1ed1 tr\u00e2u l\u00e0 7 con. H\u1ecfi s\u1ed1 tr\u00e2u b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 b\u00f2 ?","84 B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 5: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 60m, chi\u1ec1u r\u1ed9ng l\u00e0 20m. T\u00ednh chu vi h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 37 1)63 : 7 \uf03d 9 35 : 5 \uf03d 7 42 : 6 \uf03d 7 56 : 7 \uf03d 8 2) M\u00e7i c\u00a9u \u00ae\u00c6t t\u00ddnh \u00ae\u00f3ng \u00ae\u00ad\u00eec1\u00ae a) 235\uf0b4 2 \uf03d 470 b)630 : 7 \uf03d 90 3) Th\u00f9c hi\u00d6n t\u00ddnh a) 205 \uf02b 60 \uf02b 3 \uf03d 265 \uf02b 3 \uf03d 268 b)462 \uf02b 7 \uf02d 40 \uf03d 469 \uf02d 40 \uf03d 429 4)S\u00e8 con b\u00df l\u00b5 : 7 \uf02b 28 \uf03d 35(con) S\u00e8 l\u00c7n s\u00e8 b\u00df g\u00cap s\u00e8 tr\u00a9u l\u00b5 :35 : 7 \uf03d 5(l\u00c7n) V\u00cby s\u00e8 tr\u00a9u b\u00bbng 1 s\u00e8 b\u00df 5 \u00a7\u00b8p s\u00e8 :s\u00e8 tr\u00a9u b\u00bbng 1 s\u00e8 b\u00df 5 C\u00a9u 5.Chu vi h\u00d7nh ch\u00f7 nh\u00cbt l\u00b5:(60+20)\u00d72=160(m) \u00a7\u00b8p s\u00e8:160 m","85 \u0110\u1ec0 S\u00d4 38 I\/ Ph\u1ea7n tr\u1eafc nghi\u1ec7m: ( 4 \u0111) Khoanh tr\u00f2n v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang 1. Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: 789 \u2013 45 + 55 l\u00e0: A.100 B.799 C.744 D. 689 2. Gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: 930 \u2013 18 : 3 l\u00e0: A.924 B. 304 C.6 D. 912 3. 7m 3 cm = ....... cm: A. 73 B. 703 C. 10 D. 4 4. C\u00f3 750 quy\u1ec3n s\u00e1ch s\u00e1ch x\u1ebfp \u0111\u1ec1u v\u00e0o 5 t\u1ee7, m\u1ed7i t\u1ee7 c\u00f3 2 ng\u0103n. H\u1ecfi m\u1ed7i ng\u0103n c\u00f3 bao nhi\u00eau quy\u1ec3n s\u00e1ch, bi\u1ebft r\u1eb1ng m\u1ed7i ng\u0103n c\u00f3 s\u1ed1 s\u00e1ch nh\u01b0 nhau? A. 75 quy\u1ec3n B. 30 quy\u1ec3n C. 6 0 quy\u1ec3n D. 125 quy\u1ec3n 5. C\u00f3 7 con v\u1ecbt, s\u1ed1 g\u00e0 nhi\u1ec1u h\u01a1n s\u1ed1 v\u1ecbt 56 con. H\u1ecfi s\u1ed1 v\u1ecbt b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 g\u00e0? 1 1 1 1 A. B. C. D. 6 7 8 9 6. M\u1ed9t chi\u1ebfc b\u00eca h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 25 cm, chi\u1ec1u r\u1ed9ng 1dm. chu vi mi\u1ebfng b\u00eca \u0111\u00f3 l\u00e0 bao nhi\u00eau \u0111\u1ec1 \u2013 xi \u2013 m\u00e9t? A. 52dm B.70cm C.7dm D. 70 dm 7. H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 m\u1ea5y g\u00f3c vu\u00f4ng? A. 1 B. 2 C.3 D. 4 8. 8 x 7 < \uf035 x 8 C. 8 D. 6 A. 7 B. 5","86 II\/ Ph\u1ea7n t\u1ef1 lu\u1eadn( 6 \u0111) B\u00e0i1: ( 2 \u0111) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 267 + 125 \u2013 278 538 \u2013 38 x 3 B\u00e0i 2. T\u00ecm x: (2.\u0111) x : 7 = 100 + 8 X x 7 = 357 B\u00e0i 3: ( 2 \u0111) M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 453 kg g\u1ea1o, \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c 1\/3 s\u1ed1 g\u1ea1o \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau ki- l\u00f4- gam g\u1ea1o? \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 38 I. tr\u00bec nghi\u00d6m 1.B 2.A 3.B 4. A 5. D 6.C 7.B 8.B II. T\u00f9 lu\u00cbn 1) 267 \uf02b125 \uf02d 278 \uf03d 392 \uf02d 278 \uf03d 114 538 \uf02d 38\uf0b4 3 \uf03d 538 \uf02d114 \uf03d 424 2)x : 7 \uf03d 100 \uf02b 8 x : 7 \uf03d 108 x \uf03d 108\uf0b4 7 x \uf03d 756 x \uf0b4 7 \uf03d 357 x \uf03d 357 : 7 x \uf03d 51 3)S\u00e8 ki log am g\u00b9o c\u00f6a h\u00b5ng \u00ae\u00b7 b\u00b8n l\u00b5:453 : 3 \uf03d 151(kg g\u00b9o) S\u00e8 kilogam g\u00b9o c\u00f6a h\u00b5ng c\u00dfn l\u00b9i l\u00b5 :453 \uf02d151 \uf03d 302 (kg g\u00b9o) \u00a7\u00b8p s\u00e8 :302 kg g\u00b9o \u0110\u1ec0 S\u1ed0 39 Ph\u1ea7n 1: (4,0 \u0111) Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang. 1) 856: 4 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: A. 214 B. 241 C. 225 2) 64 x 5 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: C. 415 A. 203 B. 320","87 3) 75+ 15 x 2 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: A. 180 B. 187 C. 105. 4) 7 g\u1ea5p l\u00ean 8 l\u1ea7n \u0111\u01b0\u1ee3c : A. 64 B. 56 C. 49 5) M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i l\u00e0 15 m, chi\u1ec1u r\u1ed9ng l\u00e0 9 m. Chu vi h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 l\u00e0: A. 24 m B. 48 m C. 135 m 6) M\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh l\u00e0 60cm. Chu vi h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0: A. 200 B.140 C.240. 7) T\u00ecm x: X : 3 = 9 V\u1eady X = ? A. X = 3 B. X = 27 C. X = 18 8) M\u1ed9t \u0111\u00e0n g\u00e0 c\u00f3 14 con, ng\u01b0\u1eddi ta nh\u1ed1t m\u1ed7i l\u1ed3ng 4 con. H\u1ecfi c\u1ea7n c\u00f3 \u00edt nh\u1ea5t bao nhi\u00eau c\u00e1i l\u1ed3ng \u0111\u1ec3 nh\u1ed1t g\u00e0? A.4 B. 3 C.2 B\u00e0i 2) ( 2,0 \u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. a) 526 + 147 b) 627- 459 c) 419 x 2 d) 475 : 5 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026....................................................................................................................................... ..................................................................................................................................................... B\u00e0i 4) ( 1,5 \u0111) T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: a) 55: 5 x 3 b) ( 12+ 11) x 3 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026........................................................................... ..................................................................................................................................................... B\u00e0i 3) ( 2,5 \u0111): M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 96 kg \u0111\u01b0\u1eddng, \u0111\u00e3 b\u00e1n 1 s\u1ed1 ki-l\u00f4 gam \u0111\u01b0\u1eddng \u0111\u00f3. 4 H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau ki-l\u00f4-gam \u0111\u01b0\u1eddng? T\u00f3m t\u1eaft Gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026....................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 39","88 Ph\u00c7n1. 1. A 2.B 3.C 4.B 5.B 6.C 7.B 8. A b\u00b5i 2.M\u00e7i c\u00a9u \u00ae\u00c6t t\u00ddnh \u00ae\u00f3ng \u00ae\u00ad\u00eec 0,5\u00ae a) 526 \uf02b147 \uf03d 673 b)627 \uf02d 459 \uf03d 168 c)419\uf0b4 2 \uf03d 838 d)475 : 5 \uf03d 95 B\u00b5i 4.a) 55 : 5\uf0b43 \uf03d 11\uf0b43 \uf03d 33 b)\uf02812 \uf02b11\uf029\uf0b4 3 \uf03d 23\uf0b4 3 \uf03d 69 B\u00b5i 3. t\u00e3m t\u00bet:C\u00f6a h\u00b5ng c\u00e3:96 kg \u00ae\u00ad\u00eang,\u00a7\u00b7 b\u00b8n: 1 s\u00e8 \u00ae\u00ad\u00eang 4 C\u00dfn l\u00b9i: ? kg \u00ae\u00ad\u00eang Gi \u00b6 i : S\u00e8 ki lo gam \u00ae\u00ad\u00eang c\u00f6a h\u00b5ng \u00ae\u00b7 b\u00b8n l\u00b5 :96:4=24 (kg \u00ae\u00ad\u00eang) S\u00e8 kilogam \u00ae\u00ad\u00eang c\u00f6a h\u00b5ng c\u00dfn l\u00b9i l\u00b5:96-24=72 (kg \u00ae\u00ad\u00eang) \u00a7\u00b8p s\u00e8:72 kg \u00ae\u00ad\u00eang \u0110\u1ec0 S\u1ed0 40 I\/ Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang ( 2 \u0111i\u1ec3m). 1 . K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n: 117 x 8 l\u00e0: A. 936 ; B. 639; C. 963; D. 886. 2. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p chia : 84 : 4 l\u00e0; A. 14; B. 21; C. 8; D. 12 D. 671. 3. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 765 \u2013 84 l\u00e0: A. 781; B. 681; C. 921; 4. Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 81 : 9 + 10 l\u00e0: A. 39; B. 19; C. 91; D. 20; II\/ T\u1ef1 lu\u1eadn: 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh; ( 2 \u0111i\u1ec3m). 486 + 303; 670 \u2013 261 ; 106 x 9 872 : 4. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. 2. T\u00ecm y: ( 2 \u0111i\u1ec3m). 72 : y = 8; y + 158 = 261; 5 x y = 375; y : 5 = 141. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. .................................................................................................................................................................","89 3. (1,5 \u0111i\u1ec3m). N\u0103m nay \u00f4ng 72 tu\u1ed5i, ch\u00e1u 9 tu\u1ed5i. H\u1ecfi tu\u1ed5i ch\u00e1u b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y tu\u1ed5i \u00f4ng? ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. 4. ( 2,5 \u0111i\u1ec3m). T\u1ed5 m\u1ed9t tr\u1ed3ng \u0111\u01b0\u1ee3c 25 c\u00e2y, t\u1ed5 hai tr\u1ed3ng \u0111\u01b0\u1ee3c g\u1ea5p 3 l\u1ea7n t\u1ed5 m\u1ed9t. H\u1ecfi c\u1ea3 hai t\u1ed5 tr\u1ed3ng \u0111\u01b0\u1ee3c bao nhi\u00eau c\u00e2y? ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 40 I. Khoanh v\u00b5o \u00ae\u00b8p \u00b8n \u00ae\u00f3ng 1.A 2.B 3.B 4.B II.T\u00f9 lu\u00cbn 1) M\u00e7i c\u00a9u \u00ae\u00c6t t\u00ddnh \u00ae\u00f3ng \u00ae\u00ad\u00eec 0,5\u00ae 486+303=789 670-261=409 106 \uf0b4 9 \uf03d 954 872 : 4 \uf03d 218 5\uf0b4 y \uf03d 375 y : 5 \uf03d 141 2) 72 : y \uf03d 8 y \uf02b158 \uf03d 261 y \uf03d 72 : 8 y \uf03d 261\uf02d158 y \uf03d 375 : 5 y \uf03d 141\uf0b4 5 y\uf03d9 y \uf03d 103 y \uf03d 75 y \uf03d 705 3)S\u00e8 l\u00c7n tu\u00e6i \u00abng g\u00cap tu\u00e6i ch\u00b8u l\u00b5 :72 : 9 \uf03d 8(l\u00c7n) v\u00cby t u\u00e6i ch\u00b8u b\u00bbng 1 tu\u00e6i \u00abng 8 \u00a7\u00b8p s\u00e8:Tu\u00e6i ch\u00b8u b\u00bbng 1 tu\u00e6i \u00abng 8 4)S\u00e8 c\u00a9y t\u00e6 Hai tr\u00e5ng \u00ae\u00ad\u00eec l\u00b5:25\uf0b43=75(c\u00a9y) S\u00e8 c\u00a9y c\u00b6 hai t\u00e6 tr\u00e5ng \u00ae\u00ad\u00eec l\u00b5 :25+75=100(c\u00a9y) \u00a7\u00b8p s\u00e8:100 c\u00a9y","90 \u0110\u1ec0 S\u1ed0 41 PH\u1ea6N I : Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u. 1.G\u1ea5p 7 l\u00edt l\u00ean 8 l\u1ea7n th\u00ec \u0111\u01b0\u1ee3c: a. 15 l\u00edt b. 49 l\u00edt c. 56 l\u00edt d. 65 l\u00edt 2. 7m 4cm = \u2026\u2026.. cm. S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng l\u00e0: a. 74cm b. 740cm c. 407cm d. 704cm 3. T\u1ed5ng c\u1ee7a 16 v\u00e0 14 r\u1ed3i nh\u00e2n v\u1edbi 4 l\u00e0: a. 30 b. 34 c. 72 d. 120 4. M\u1ed9t c\u00e1i ao h\u00ecnh vu\u00f4ng c\u00f3 chu vi l\u00e0 24 m th\u00ec c\u1ea1nh c\u1ee7a h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0: a. 4m b. 6m c. 8m d. 12cm 5. S\u1ed1 th\u00edch h\u1ee3p vi\u1ebft v\u00e0o ch\u1ed7 tr\u1ed1ng trong ph\u00e9p t\u00ednh x6 :8 4 l\u00e0: a. 24 v\u00e0 3 b. 24 v\u00e0 4 c. 24 v\u00e0 6 d. 24 v\u00e0 8 1 6. 3 c\u1ee7a 24 kg l\u00e0: a. 1kg b. 3 kg c. 6 kg d. 8 kg c. 3 d. C\u1ea3 a, b, c \u0111\u1ec1u sai 7. Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 3 trong s\u1ed1 132 l\u00e0: a. 300 b. 30 8. H\u00ecnh b\u00ean c\u00f3 g\u00f3c : a. Vu\u00f4ng. b. Kh\u00f4ng vu\u00f4ng. 9. S\u1ed1 d\u01b0 trong ph\u00e9p chia 27 : 5 l\u00e0 : c. 3 d. 4 a. 1 b. 2 PH\u1ea6N II : T\u00cdNH 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. (2 \u0111i\u1ec3m) 576 + 185 720 \u2013 342 75 x 7 786 : 6 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 .\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.","91 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 .\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026 .\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026 .\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026. 100 : x = 4 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026. 2. T\u00ecm x: (1 \u0111i\u1ec3m) x + 23 = 81 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026... 1 3. M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 104kg g\u1ea1o, c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111i 4 kg g\u1ea1o \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau kg g\u1ea1o? (2 \u0111i\u1ec3m) Gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 41 PH\u1ea6N I. 1.C 2.D 3.D 4.B 5.A 6.D 7.B 8.A 9.B PH\u1ea6N II. 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5 \u0111i\u1ec3m 576 + 185 = 761 720 \u2013 342 = 378 75 x 7 = 525 786 : 6 = 131 2) T\u00ecm x 100 : x \uf03d 4 x \uf02b 23 \uf03d 81 x \uf03d 81\uf02d 23 x \uf03d 100 : 4 x \uf03d 58 x \uf03d 25 3) S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111i l\u00e0: 104 : 4 = 26 (kg g\u1ea1o) S\u1ed1 kilogam g\u1ea1o c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i l\u00e0: 104 \u2013 26 = 78 (kg g\u1ea1o) \u0110\u00e1p s\u1ed1: 78 kg g\u1ea1o","92 \u0110\u1ec0 S\u1ed0 42 B\u00e0i 1. T\u00ednh nh\u1ea9m: 4 x 5 = ............; 7 x8 = ...........; 45 : 9 = ...............; 64 : 8 = ................; B\u00e0i 2. T\u00ecm s\u1ed1 l\u1edbn nh\u1ea5t, b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1 sau: 375, 421, 573, 241, 735, 142 a) S\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 s\u1ed1: .............................. b) S\u1ed1 b\u00e9 nh\u1ea5t l\u00e0 s\u1ed1 : ........................................ B\u00e0i 3. Vi\u1ebft v\u00e0o \u00f4 tr\u1ed1ng (theo m\u1eabu) : C\u1ea1nh h\u00ecnh vu\u00f4ng 8cm 12cm 31cm Chu vi h\u00ecnh vu\u00f4ng 8 x 4 = 32 (cm) B\u00e0i 4. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: a) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c 288 + 24 : 6 l\u00e0 294 ; b) Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c 138 x (174 \u2013 168) l\u00e0 826 B\u00e0i 5. ? 6m 3cm ....... 7m 5m 6cm ....... 5m 6m 3cm ....... 630cm 5m 6cm ........ 506cm > < = B\u00e0i 6. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 213 x 3 208 x 4 684 : 6 630 : 9 B\u00e0i 7. T\u00ednh : b) 96g : 3 = ............; a) 163g + 28g = ............. ;. B\u00e0i 8. M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 36 m\u00e1y b\u01a1m, ng\u01b0\u1eddi ta \u0111\u00e3 b\u00e1n 1 s\u1ed1 m\u00e1y b\u01a1m \u0111\u00f3. H\u1ecfi c\u1eeda 6 h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau m\u00e1y b\u01a1m? Gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026","93 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 B\u00e0i 9. T\u00ednh chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt, bi\u1ebft n\u1eeda chu vi h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 l\u00e0 60m v\u00e0 chi\u1ec1u d\u00e0i l\u00e0 40m.. Gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026... 1) 4x5=20 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 42 31cm 7x8 = 56 31 x 4 = 124 (cm) 45 : 9 = 5 64 : 8 = 8 2) S\u1ed1 l\u1edbn nh\u1ea5t: 735 S\u1ed1 b\u00e9 nh\u1ea5t: 142 8cm 12cm 3) C\u1ea1nh h\u00ecnh vu\u00f4ng Chu vi h\u00ecnh vu\u00f4ng 8 x 4 = 32 (cm) 12 x 4 = 48 (cm) 4) a)S b) S 5) > < = 6 m 3 cm < 7 m 5 m 6 cm > 5 m 6 m 3 cm < 630 cm 5m 6 cm = 506 cm 6) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 213 x 3 = 639 208 x 4 = 832 684 : 6 = 114 630 : 9 = 70 7) T\u00ednh a) 163 g + 28 g = 191 g b) 96 g : 3 = 32 g 8) S\u1ed1 m\u00e1y b\u01a1m c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n l\u00e0: 36 : 6 =6 (m\u00e1y b\u01a1m) S\u1ed1 m\u00e1y b\u01a1m c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i l\u00e0: 36 \u2013 6 = 30 (m\u00e1y b\u01a1m) \u0110\u00e1p s\u1ed1: 30 m\u00e1y b\u01a1m 9) Chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt l\u00e0: 60 \u2013 40 = 20 (m) \u0110\u00e1p s\u1ed1: 20m","94 \u0110\u1ec0 S\u1ed0 43 I. PH\u1ea6N TR\u1eaeC NGHI\u1ec6M (3 \u0111i\u1ec3m) C\u00e2u 1(2 \u0111i\u1ec3m). N\u1ed1i ph\u00e9p t\u00ednh v\u00e0 bi\u1ec3u th\u1ee9c v\u1edbi gi\u00e1 tr\u1ecb c\u1ee7a n\u00f3: 45 + 29 59 79 - 20 74 30 x 3 : 3 21 (97 \u2013 13) : 4 30 C\u00e2u 2(1 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a) C\u1ea1nh c\u1ee7a h\u00ecnh vu\u00f4ng l\u00e0 6 cm. V\u1eady chu vi h\u00ecnh vu\u00f4ng l\u00e0\u2026\u2026\u2026 cm A. 10 B. 12 C. 24 b) S\u1ed1 th\u00edch h\u1ee3p c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m \u0111\u1ec3 3m 2cm = \u2026\u2026 cm l\u00e0: A. 32 B. 302 C. 320 II. PH\u1ea6N T\u1ef0 LU\u1eacN (7 \u0111i\u1ec3m) C\u00e2u 1(2 \u0111i\u1ec3m). T\u00ednh + 271 x 206 246 3 - 692 444 2 235 ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. C\u00e2u 2(1 \u0111i\u1ec3m). T\u00f4 m\u00e0u v\u00e0o 1 s\u1ed1 \u00f4 vu\u00f4ng 8","95 C\u00e2u 3(1 \u0111i\u1ec3m). T\u00ecm x: b) 7 x x = 847 \u2013 77 a) x : 6 = 121 ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. C\u00e2u 4(2 \u0111i\u1ec3m). M\u1ed9t t\u1ea5m v\u1ea3i d\u00e0i 68m, ng\u01b0\u1eddi ta c\u1eaft l\u1ea5y 4 kh\u00fac, m\u1ed7i kh\u00fac d\u00e0i 6m. H\u1ecfi t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i d\u00e0i bao nhi\u00eau m\u00e9t? B\u00e0i gi\u1ea3i ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. C\u00e2u 5(1 \u0111i\u1ec3m).T\u00ecm s\u1ed1 b\u1ecb chia trong ph\u00e9p chia cho 8, bi\u1ebft th\u01b0\u01a1ng l\u00e0 4 v\u00e0 s\u1ed1 d\u01b0 l\u00e0 s\u1ed1 d\u01b0 l\u1edbn nh\u1ea5t c\u00f3 th\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. ................................................................................................................................................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 43 I.TR\u1eaeC NGHI\u1ec6M 1) 45 + 29 = 74 79 \u2013 20 = 59 30x 3:3=30 (97 \u2013 13 ) :4=21 2) Khoanh v\u00e0o c\u00e2u \u0111\u00fang a) C b) B II. T\u1ef1 lu\u1eadn 1) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 271+444 = 715 246 : 3 = 82 206 x 2 = 412 692 \u2013 235 = 457 2)H\u1ecdc sinh t\u00f4 \u0111\u00fang 2 \u00f4 3) a) x : 6 \uf03d 121 7\uf0b4 x \uf03d 847 \uf02d 77 x \uf03d 121x6 7\uf0b4 x \uf03d 770 x \uf03d 726 x \uf03d 770 : 7 x \uf03d 110","96 4) S\u1ed1 m\u00e9t v\u1ea3i c\u1ee7a 4 kh\u00fac d\u00e0i l\u00e0: 6 x 4 = 24 (m) S\u1ed1 m\u00e9t v\u1ea3i t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i l\u00e0: 68 \u2013 24 = 44 (m) \u0110\u00e1p s\u1ed1: 44 m 5) S\u1ed1 d\u01b0 l\u1edbn nh\u1ea5t n\u00ean s\u1ed1 d\u01b0 l\u00e0 7 S\u1ed1 b\u1ecb chia c\u1ea7n t\u00ecm l\u00e0: 4 x 8 + 7 = 39 \u0110\u00e1p s\u1ed1 : 39 \u0110\u1ec0 S\u1ed0 44 PH\u1ea6N I: H\u00e3y khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang 1) ph\u00e9p t\u00ednh 32 x 6 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: (0.5 \u0111i\u1ec3m) B. 182 B. 192 C. 129 D. 198 d\/ 450 : 6 2) S\u1ed1 d\u01b0 trong ph\u00e9p chia 46 : 6 l\u00e0 : ( 0,5 \u0111i\u1ec3m) B. 1 B. 2 C. 3 D. 4 3) M\u1ed7i gi\u1edd c\u00f3 60 ph\u00fat v\u1eady 1 gi\u1edd c\u00f3 : (0,5 \u0111i\u1ec3m) 3 A. 15 ph\u00fat B. 25 ph\u00fat C. 20 ph\u00fat D. 30 ph\u00fat 4) Bi\u1ec3u th\u1ee9c 36 : 4 x 3 c\u00f3 gi\u00e1 tr\u1ecb l\u00e0 : (0,5 \u0111i\u1ec3m) A. 27 B. 28 C.32 D. 34 5) H\u00ecnh b\u00ean c\u00f3: (1 \u0111i\u1ec3m) A. 3 g\u00f3c vu\u00f4ng B. 4 g\u00f3c vu\u00f4ng C. 5 g\u00f3c vu\u00f4ng D. 6 g\u00f3c vu\u00f4ng PH\u1ea6N II: L\u00e0m c\u00e1c b\u00e0i t\u1eadp sau: 1\/ \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2 \u0111i\u1ec3m) a\/ 214 x 4 b\/ 319 x 3 c\/ 905 : 5 2\/ \u0110\u1ed5i \u0111\u01a1n v\u1ecb \u0111o: (1 \u0111i\u1ec3m) a\/ 25 dm 7 cm = \u2026\u2026\u2026\u2026\u2026.. cm b\/ 8 m 32 cm = \u2026\u2026\u2026\u2026\u2026\u2026 cm 3\/ T\u00ecm x: (2 \u0111i\u1ec3m) b\/ x : 6 = 108 a\/ 876 : x = 4 ...................................................... ..................................................... ....................................................... ......................................................","97 4\/ M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 56kg \u0111\u01b0\u1eddng, \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c 1 s\u1ed1 \u0111\u01b0\u1eddng \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i 8 bao nhi\u00eau ki-l\u00f4 gam \u0111\u01b0\u1eddng ? (2 \u0111i\u1ec3m) B\u00e0i gi\u1ea3i: ........................................................................................... ........................................................................................... ........................................................................................... .......................................................................................... .......................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 44 Ph\u1ea7n I. 1.B 2.D 3.C 4.A 5.C Ph\u1ea7n II. 1) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 a) 214 x 4 = 856 b) 319 x 3 = 957 c) 905 : 5 = 181 d) 450 : 6 = 75 2) \u0110\u1ed5i \u0111\u01a1n v\u1ecb a) 25 dm 7 cm = 257 cm b) 8 m 32 cm = 832 cm 3) T\u00ecm x x : 6 \uf03d 108 a)876 : x \uf03d 4 x \uf03d 876 : 4 x \uf03d 108\uf0b4 6 x \uf03d 219 x \uf03d 648 4) S\u1ed1 kilogam \u0111\u01b0\u1eddng \u0111\u00e3 b\u00e1n l\u00e0: 56 : 8 = 7 (kg \u0111\u01b0\u1eddng) S\u1ed1 kilogam \u0111\u01b0\u1eddng c\u00f2n l\u1ea1i l\u00e0: 56 \u2013 7 = 49 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1: 49 kg \u0111\u01b0\u1eddng \u0110\u1ec0 S\u1ed0 45 I>PH\u1ea6N TR\u1eaeC NGHI\u1ec6M: (3 \u0110I\u1ec2M) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: B\u00e0i 1: (1 \u0111i\u1ec3m) 1kg = ...........gam: A, 1000 gam B, 100 gam C, 10 gam B\u00e0i 2 : (1 \u0111i\u1ec3m) S\u1ed1 g\u00f3c vu\u00f4ng \u1edf h\u00ecnh b\u00ean l\u00e0 A, 3 g\u00f3c vu\u00f4ng B, 4 g\u00f3c vu\u00f4ng C, 5 g\u00f3c vu\u00f4ng B\u00e0i 3: (1 \u0111i\u1ec3m) 1 c\u1ee7a 24 ph\u00fat l\u00e0 ? 6 A, 4 ph\u00fat B, 9 ph\u00fat C, 10 ph\u00fat II> PH\u1ea6N T\u1ef0 LU\u1eacN: (7 \u0110I\u1ec2M) B\u00e0i 1: (1 \u0111i\u1ec3m) Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 9; 18; 27;.........;...............;.............;.............; ...........; .........;........... B\u00e0i 2: (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh:","98 168 + 105 652 \u2013 318 319 x 3 648 : 3 ......................... ........................... ....................... ........................... ......................... ........................... ....................... ........................... ......................... ........................... ....................... ........................... ......................... ........................... ....................... ........................... ......................... ........................... ....................... ........................... B\u00e0i 3: (1 \u0111i\u1ec3m) T\u00ecm X : a. 54 : X = 9 b, 45 \u2013 X = 20 ...................................................... ................................................................ ...................................................... ................................................................ ...................................................... ................................................................ ...................................................... ................................................................ B\u00e0i 4: (2 \u0111i\u1ec3m) M\u1ed9t c\u1eeda h\u00e0ng ng\u00e0y th\u1ee9 nh\u1ea5t b\u00e1n \u0111\u01b0\u1ee3c 6 kg g\u1ea1o. Ng\u00e0y th\u1ee9 hai b\u00e1n \u0111\u01b0\u1ee3c g\u1ea5p \u0111\u00f4i s\u1ed1 g\u1ea1o ng\u00e0y th\u1ee9 nh\u1ea5t. H\u1ecfi c\u1ea3 hai ng\u00e0y c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau kg g\u1ea1o? T\u00f3m t\u1eaft: B\u00e0i gi\u1ea3i: ........................................................... ....................................................................... ........................................................... ....................................................................... ........................................................... ....................................................................... ........................................................... ....................................................................... ........................................................... ....................................................................... B\u00e0i 5: (1 \u0111i\u1ec3m) T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: a, 21 x 3 : 9 = b, 526 + 20 x 4 = ........................................................... ....................................................................... ........................................................... ....................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 45 I.TR\u1eaeC NGHI\u1ec6M 1.A 2.B 3.A II. T\u1ef0 LU\u1eacN 1). 9;18;27;36;45;54;63;72;81;90 2) \u0110\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 168 + 105 = 273 319 x 3 = 957 652 \u2013 318 = 334 648 : 3 = 216 3) T\u00ecm x 45 \uf02d x \uf03d 20 a) 54 : x \uf03d 9 x \uf03d 54 : 9 x \uf03d 45 \uf02d 20 x\uf03d6 x \uf03d 25 4) T\u00f3m t\u1eaft: Ng\u00e0y th\u1ee9 nh\u1ea5t b\u00e1n: 6 kg g\u1ea1o Ng\u00e0y th\u1ee9 hai b\u00e1n: g\u1ea5p \u0111\u00f4i ng\u00e0y th\u1ee9 nh\u1ea5t C\u1ea3 hai ng\u00e0y b\u00e1n: ? kg g\u1ea1o Gi\u1ea3i S\u1ed1 kilogam g\u1ea1o ng\u00e0y th\u1ee9 hai b\u00e1n l\u00e0: 6 x 2 = 12 (kg g\u1ea1o) S\u1ed1 kilogam g\u1ea1o c\u1ea3 hai ng\u00e0y b\u00e1n l\u00e0 : 6 + 12 = 18 (kg g\u1ea1o) \u0110\u00e1p s\u1ed1: 18 kg g\u1ea1o","99 5) a) 21 x 3 : 9 = 63 : 9 = 7 b) 526 + 20 x 4 = 526 + 80 = 606 \u0110\u1ec0 S\u1ed0 46 B\u00e0i 1: ( 2 \u0111i\u1ec3m) a) \u0110\u1ebfm th\u00eam r\u1ed3i vi\u1ebft ti\u1ebfp 12 s\u1ed1 th\u00edch h\u01a1p v\u00e0o ch\u1ed7 ch\u1ea5m: 23 ; 29 ; 35 ; \u2026\u2026;\u2026\u2026.;\u2026\u2026\u2026; 13 ; 17 ; 21 ;\u2026..;\u2026\u2026;\u2026\u2026.; 13 ; 20 ; 27 ;\u2026\u2026.;\u2026\u2026.;\u2026\u2026\u2026; 26 ; 35 ; 44 ;\u2026..;\u2026\u2026;\u2026\u2026.; b) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: g\u1ea5p 4 l\u1ea7n gi\u1ea3m 3 l\u1ea7n 5 36 B\u00e0i 2: T\u00ednh: ( 2 \u0111i\u1ec3m) 7 x 6 = \u2026\u2026. 54 : 6 = \u2026\u2026.. 7x 8 = \u2026\u2026 64 : 8 = \u2026\u2026 6 x 4 = \u2026\u2026 48 : 8 = \u2026\u2026. 9 x 6= \u2026\u2026 81 : 9 = \u2026\u2026 B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: ( 2 \u0111i\u1ec3m) 52 x 6 105 x 5 96 : 3 852 : 4 \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 4: Trong h\u00ecnh t\u1ee9 gi\u00e1c ABCD c\u00f3 hai g\u00f3c vu\u00f4ng v\u00e0 hai g\u00f3c kh\u00f4ng vu\u00f4ng. (1 \u0111i\u1ec3m) a) T\u00ean c\u1ea1nh c\u00e1c g\u00f3c vu\u00f4ng l\u00e0:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) T\u00ean c\u1ea1nh c\u00e1c g\u00f3c kh\u00f4ng vu\u00f4ng l\u00e0:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. AB D C B\u00e0i 5: T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: ( 1 \u0111i\u1ec3m) a) 123 x 2 : 3 = b) 80 + 38 : 2 = \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. B\u00e0i 6: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang : ( 1 \u0111i\u1ec3m) a) 1 c\u1ee7a 12 gi\u1edd l\u00e0 : C. 8 gi\u1edd 4 A. 3 gi\u1edd B. 6 gi\u1edd b) Chu vi c\u1ee7a h\u00ecnh vu\u00f4ng ABCD c\u00f3 canh AB = 3 cm l\u00e0 : A. 6cm B. 9cm","100 C. 12cm c) \u0110\u1ed3ng h\u1ed3 ch\u1ec9: A. 1 gi\u1edd 50 ph\u00fat B. 2 gi\u1edd 50 ph\u00fat C. 10 gi\u1edd 10 ph\u00fat d). \u0110\u1ed5i \u0111\u01a1n v\u1ecb \u0111o 2 dam = ? m A. 2 m B. 20 m C. 200 m .B\u00e0i 7: Gi\u1ea3i to\u00e1n : (1 \u0111i\u1ec3m) a) Hu\u1ec7 c\u1eaft \u0111\u01b0\u1ee3c 8 b\u00f4ng hoa, H\u1ed3ng c\u1eaft \u0111\u01b0\u1ee3c g\u1ea5p 4 l\u1ea7n s\u1ed1 b\u00f4ng hoa c\u1ee7a Hu\u1ec7 . H\u1ecfi H\u1ed3ng c\u1eaft \u0111\u01b0\u1ee3c bao nhi\u00eau b\u00f4ng hoa ? Gi\u1ea3i .............................................................................................................................................................. b) M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 186 m\u00e1y b\u01a1m, ng\u01b0\u1eddi ta \u0111\u00e3 b\u00e1n 1 s\u1ed1 m\u00e1y b\u01a1m \u0111\u00f3. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i 6 bao nhi\u00eau m\u00e1y b\u01a1m ? Gi\u1ea3i .............................................................................................................................................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 46 1). a) 23;29;35;41;47;53 13;17;21;25;29;33 13;20;27;34;41;48 26; 35; 44; 53; 62; 71. 36 gi\u1ea3m 3 l\u1ea7n : 12 b) 5 g\u1ea5p 4 l\u1ea7n: 20 2)7\uf0b46 \uf03d 42 54 : 6 = 9 7 x 8 =56 64 : 8 = 8 81 : 9 = 9 6 \uf0b4 4 \uf03d 24 48 : 8 = 6 9 x 6=54 3) M\u1ed7i cau \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5 \u0111 52 x 6 = 312 105 x 5 = 525 96 : 3 = 32 852 : 4 =213 4) a) C\u1ea1nh g\u00f3c vu\u00f4ng : AB, AD, DC. b) T\u00ean c\u1ea1nh c\u00e1c g\u00f3c kh\u00f4ng vu\u00f4ng l\u00e0:AB, BC, CD 5) a) 123 x 2 : 3= 246 : 3 = 82 b) 80 + 38 : 2 = 80 + 19 = 99 6) a)A b) C c) A d) B 7) S\u1ed1 b\u00f4ng hoa H\u1ed3ng c\u1eaft l\u00e0: 8 x 4 = 32 (b\u00f4ng hoa) \u0110\u00e1p s\u1ed1: 32 b\u00f4ng hoa b) S\u1ed1 m\u00e1y b\u01a1m c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n l\u00e0 : 186 : 6 = 31 (m\u00e1y b\u01a1m) S\u1ed1 m\u00e1y b\u01a1m c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i l\u00e0 : 186 \u2013 31 = 155 (m\u00e1y b\u01a1m) \u0110\u00e1p s\u1ed1: 155 m\u00e1y b\u01a1m \u0110\u1ec0 S\u1ed0 47 Ph\u1ea7n I : Tr\u1eafc nghi\u1ec7m: Khoanh tr\u00f2n tr\u01b0\u1edbc ph\u01b0\u01a1ng \u00e1n tr\u1ea3 l\u1eddi \u0111\u00fang: C\u00e2u 2: 52 hm : 2 = ? A. 24 hm B. 26 hm C. 26 dm D. 24 dam C\u00e2u 3: T\u00ecm x , bi\u1ebft: x \u2013 10 = 218 x 4"]