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PP You will be assessed on your ability to do the following: 2 PTS PP LVP HL · determine the vanishing points 1 48 HL · project from the station point 1 · project to the vanishing points 4 Arch · determine the arch construction 24 8 · draw the two point perspective view VPs 4 Con 4 Total 64 32 MARKS PTS =48 Arch Con = 8 VPS =4 CON =4 64/2 32 SP MEMO 53

ASSESSMENT CRITERIA 22 AUXILIARY VIEW & 4 1 PLACING 2 772 2 ISOMETRIC LINES 11½ 22 3 NON-ISOMETRIC LINES 2 3 777 32 2 7 4 ISOMETRIC CIRCLE 6 3 5 CIRCLE CONSTRUCTION 3 2 77 77 2 2 6 CENTRE LINES 1 2 62 26 2 24 7 7 SECTIONED SURFACES 14 4 7 8 HATCHING 2½ 2 7 7 7 TOTAL 44 2 4 2 7 73 27 4 2 7 7 7 5 7 4 22 4 5 7 7 5 1 1 8 8 1 1 7 1 1 77 1 7 X 1 CORRECT PLACEMENT ON POINT X 8 HATCHING CORRECTLY SHOWN MEMO P 62





ASSESSMENT CRITERIA 1 TOP VIEW DIVISIONS ½ D 2 TRUE LENGTHS x 5 7½ 33 3 DEVELOPMENT {7 + 14(½)} 21 E TOTAL 29 3 3 3 3 3 3 3 3 3 3 3 6 63 53 3 7C 3333 3 31 2 4 3 3333 3 3 5 F 3 3 33 4 32 3 31 3 B 3 0 A 0 A B 67 2 1 5 04 0 A B3 2 2 2 22EA 2 2 2 22F 1 0B 1 C/D 2 22 22F 3A3 C 44 1 21 0 55 66 22 7ED MEMO 67 P 94 54

2 POSITION OF THE 2 2 0° 360° UNIFORM ACCELERATION UNIFORM SIMPLE FOLLOWER ON 30° & RETARDATION MOTION HARMONIC DIRECTION INDICATION 30° 2 2 0° 345° 360° 330° 3 2 1 30° 60° 3 345° 60° 315° 1 90° 300° UNIFORM 390° ACCELERATION 330° 120° 285° 1 3 150° 270° 315° 1 3 DWELL 0° 1 3 285° 315° 345° 30° 60° 90° 120° 150° 180° 210° 240° 270° 300° 330° 360°120° 3 3 300° DISPLACEMENT GRAPH 150° SCALE 8 mm = 30° CMEMO 1. CONSTRUCTION: 1P 106 3 3 * CIRCLE DIVISION 1 4 3 * HORIZONTAL PROJECTION 1 3 * ARC PROJECTION 1 SIMPLE 285° * DIRECTION CORRECT = DWELL HARMONIC 3. CAM PROFILE: 2 3 UNIFORM 3 * ROLLERS 4 RETARDATION * CURVES =6 270° ASSESSMENT CRITERIA UNIFORM 1 GRAPH 5 MOTION 2 2 CONSTR + F/LOWER + DIRECTION 8 3 PLOTTING 7 180° 240° 4 CAM PROFILE 6 210° TOTAL 26

ASSESSMENT CRITERIA 1 CENTRE LINE & CIRC DIV 1 2 FRONT VIEW DIVISIONS 2 3 3 PLOTTING 15 2 4 4 CURVE & QUALITY 41 5 HATCHING 1 TOTAL 5 230 612 1 11 7 10 8 96 4 5 3 33 4 30 3 3 4 2 3 4 1 2 312 49 3 36 3 43 4 303 3 3 312 5 4 MEMO P 144





























INDEPENDENT SCHOOLS TRIAL EXAMINATION 2017: ENGINEERING GRAPHICS AND DESIGN: PAPER 2 MACHINING W ELDING AR AB MILLED 1 0,01 M10 0,1 8 Ø10 2 Ø18 2 C M10 K 55 3 Ø60 5 Ø6 40 6 Ø20 D M10 Ø10 30 E 10 Ø12 G Ø2Ø10 4 Ø100 JM FIGURE Z FIGURE Y Ø80 Ø6 Ø20 Ø430 20 15 15 L 25 F ABC M70 ?80 A Ø24 M16 A ABC 9 ANSW ER 20 HHP MOODLEY COPYRIGHT © 2017

RC PAGE 2 OF 7 TRIALS 2017 GRADE 12 P2 QUESTION 1 20 MARKS MECHANICAL ANALYTICAL REFER TO THE INFORMATION GIVEN AND ANSW ER THE FOLLOW ING QUESTIONS 1.1 W hat is the dimension A on Part 1? Ø10/M10 1.2 W hat is the dimension B on Part 1? Ø8 1.3 W hat is the dimension C on Part 2? 14 1.4 W hat is the dimension D on Part 3? 1 1.5 W hat is the dimension E on Part 4? 10 1.6 W hat is the dimension F on Part 4? Ø60 1.7 W hat type of welding is shown on the given welding symbol? V BUTT 1.8 W hat welding process is shown on the given welding symbol? ARC 1.9 W hat is the feature shown by G on Part 6? TAPER 1.10 W hat type of knurling is shown by H on Part 9? STRAIGHT 1.11 W hat type of sectioning is shown by J on Part 5? PART 1.12 W hat type of sectioning is shown by K on Part 3? REVOLVED 1.13 W hat type of sectioning is shown by L on Part 4? HALF 1.14 W hich is the correct representation of the bearing in Figure Y? A 1.15 W hat is the roughness value of the given machining symbol? 0,01 1.16 W hat is the machine allowance of the given machining symbol? 0,1 1.17 W hat is the direction of the lay of the given machining symbol? PARALLEL 1.18 W hat is the production method of the given machining symbol? MILLING/MILLED 1.19 W hich is the correct representation of the cut gear in Figure Z? B 1.20 W hat is the area of surface M (shaded surface) on Part 5? Area = πR² / Area M = Area (?10) - Area (?6) = (314) - (113.04) (write your answer in millimetres squared and to 1 decimal place) = 427 mm²CD NAMECD SHEET 1 PLEASE TURN OVER

INDEPENDENT SCHOOLS TRIAL EXAMINATION 2017: ENGINEERING GRAPHICS AND DESIGN: PAPER 2 GRAPH OF DISPLACEMENT 0° 360° Ω Ω 330° Ω 300° Ω ☺0° 60° 120° 180° 240° 300° 360° 30° 90° 150° 210° 270° 330° SCALE 6mm : 30° ☺ ☺ ☺ 270° 240° ANSW ERHP MOODLEY COPYRIGHT © 2017

PAGE 3 OF 7 TRIALS 2017 GRADE 12 P2 QUESTION 2.1 20 MARKS CAM PROFILE 30° The following details refer to a cam profile: ☺ 60° SPECIFICATIONS: ☺ - Roller-ended follower ☺ - Anti-clockwise direction 180° - Roller diameter = 12mm GRAPH OF DISPLACEMENT MOTION: 0° - 120° the follower rises 35mm with Uniform Acceleration and Retardation (given) 90° 120° - 180° the follower falls 70mm with ☺ Uniform Motion (given) ☺ 150° 180° - 360° the follower rises 35mm with Simple Harmonic Motion, back to its original position GIVEN: - Cam shaft diameter = 20mm - Minimum distance from the centre of the cam shaft to the profile = 14mm - Incomplete Graph of displacement - Roller-ended follower drawn 30° off centre 120° - Centre lines through the cam shaft ☺ REQUIREMENTS: 2.1.1. Complete the graph of displacement.☺ 2.1.2. Draw the cam profile. 2.1.3. Show all construction. 2.1.4. Show the direction of rotation. 2.1.5. Answer the questions shown below, in the given table, based on the graph of displacement: 2.1.5.1. What is the displacement at 150°? 2.1.5.2. What is the travel at 150°? ASSESSMENT CRITERIA 4 1 You will be assessed on your ability to do 11 210° the following:SHEET 2.1 2 complete the graph of displacement 1 plot the points for the cam profile 1 answer the questions correctly draw the direction arrow 0 draw a neat locus show all construction 70 2.1.5.1. What is the displacement at 150°? 2.1.5.2. What is the travel at 150°? NAME PLEASE TURN OVER