Name: _______________________________________ UUID: ___________________________________ School: ______________________________________ Section: ________________________________ School ID: _____________ Date: _________________ Inv. Sign: _______________________________ Choose the correct option. [] 1) What is the sum of the given numbers? (A) 967 (B) 944 (C) 444 (D) 344 A. B 2) What is the difference of given numbers? [] (A) 754 (B) 236 (C) 547 (D) 631 A. D
3) 30 × 400 = ? [] (A) 12000 (C) 1020 (B) 120 (D) 7000 A. A Fill in the blanks. [] 4) Look at the symbol and ______________________ is the number (in figures). A. 42121 5) 18 ÷ 6 = ____________________________ [] A. 3 6) The numerator and denominator of the following fraction are __________ and 9. A. 7 [] Answer the following. [] 7) Fill the table using multiplication.
A. [] 8) Divide the following: 63 ÷ 9 A. [] 9) Write the place value of the underlined digit in the following number: 9,742 [] A. 700 [] 10) Write the number just after 3459. A. The number just after 3459 = 3460 11) Arrange vertically and add: 999 + 4000 A. [] 12) Solve: 13 × 400 [] A. 5200 13) Solve the following using dots.
A. [] 14) Arrange vertically and subtract: 465 – 179 [] A. [] 15) Write the place value of the underlined digit in the number. 9,002 A. 2 16) Write the fraction of the shaded parts of the shape.
A. Answer the following. 17) Rambhau had ₹ 15,000. He bought fodder worth ₹ 8,570 and the other animal feed worth ₹ 4,950. How much money did he have left? [] A. Total money = ₹ 15,000 Cost of fodder = ₹ 8,570 Cost of other feed = ₹ 4,950 Total money spent = Cost of fodder + Cost of other feed = ₹ 8570 + ₹ 4950 Rambhau spent ₹ 13,520 on fodder and other feed. Money left = Total money – Total money spent = ₹ 15,000 – ₹ 13,520 Therefore, Rambhau has ₹ 1,480 left with him.
18) Read the fraction and write them in words. [] [] a) b) A. a) Three quarters b) Three and one quarter [] 19) Multiply: 127 × 8 A. 20) Solve the following: A. 21) Write the following numbers in figures. [] [] a) Seven hundred and eighty b) Six hundred and sixty-one A. a) 780 b) 661 22) Write the numbers from their expanded form. a) 90,000 + 700 + 30 + 2 b) 8,000 + 50 + 6
A. a) 90,732 b) 8,056 23) Write the numbers in ascending and descending order. [] [] 4609, 5650, 2487 A. Ascending order: 2487 < 4609 < 5650 Descending order: 5650 > 4609 > 2487 Answer the following. 24) Complete the following. A. [] 25) Complete the following.
A. 26) Srinu has pieces of chocolate and Nishah as . Show these fractions in the form of pictures and tell who has more pieces of chocolate? [] A. Srinu has pieces of chocolate, Nisha has pieces of chocolate. The fraction of chocolate with Srinu =
The fraction of chocolate with Nisha = The shaded parts show the fractions. By comparing the shaded parts, we find that Srinu has more chocolates than Nisha. 27) Based on the information, make one addition and one subtraction problem each and solve the problems. Cost of a new motorcycle, ₹ 26,450; cost of an old motorcycle, ₹ 3,890. [] A. Addition problem: Costs of a new and an old motorcycle are ₹ 26,450 and ₹ 3,890 respectively. What will be the total cost of both the motorcycles? Total cost of both the motorcycles = ₹ 26,450 + ₹ 3,890 Therefore, both the motorcycles together cost ₹ 30,340. Subtraction problem: Costs of a new and an old motorcycle are ₹ 26,450 and ₹ 3,890 respectively. Find the difference in the costs of both the motorcycles. Which one is costlier? Difference in the costs = ₹ 26450 – ₹ 3890 Therefore, the new motorcycle is costlier by ₹ 22,560. 28) Mohith purchases 5 pens and gives ₹ 90 to the shopkeeper. Shopkeeper returns ₹ 5 to Mohith. What is the cost of one pen? []
A. Number of pens = 5 Cost of 5 pens = 90 − 5 = ₹ 85 Cost of 1 pen = 85 ÷ 5 Therefore, the cost of one pen is ₹ 17.
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