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Home Explore 51 đề kiểm tra học kỳ I môn toán lớp 3

51 đề kiểm tra học kỳ I môn toán lớp 3

Published by TIỂU HỌC NGHĨA AN - NINH GIANG - HẢI DƯƠNG, 2023-07-04 12:57:39

Description: 51 đề kiểm tra học kỳ I môn toán lớp 3

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["\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 15. \u0110\u1ec0 2 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: C\u00f3 7 qu\u1ea3 chu\u1ed1i v\u00e0 1 qu\u1ea3 d\u00e2u. H\u1ecfi s\u1ed1 qu\u1ea3 d\u00e2u b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y qu\u1ea3 chu\u1ed1i? A. B. C. D. C\u00e2u 2: T\u00ednh: B. 2 d\u01b0 7 C. 2 d\u01b0 8 D. 2 d\u01b0 5 A. 2 d\u01b0 6 C\u00e2u 3: Trong c\u00e1c ph\u00e9p chia cho 9, s\u1ed1 d\u01b0 nh\u1ecf nh\u1ea5t c\u00f3 th\u1ec3 l\u00e0: A. 1 B. 0 C. 8 D. 2 C\u00e2u 4: S\u1ed1 n\u00e0o gi\u1ea3m \u0111i 3 l\u1ea7n r\u1ed3i c\u1ed9ng th\u00eam 2 \u0111\u01a1n v\u1ecb th\u00ec b\u1eb1ng 120? A. 360 B. 323 C. 364 D. 354 C\u00e2u 5: C\u00f3 234 h\u1ecdc sinh x\u1ebfp h\u00e0ng. M\u1ed7i h\u00e0ng c\u00f3 9 h\u1ecdc sinh. H\u1ecfi c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau h\u00e0ng? A. 26 h\u00e0ng B. 27 h\u00e0ng C. 25 h\u00e0ng D. 27 h\u00e0ng C\u00e2u 6: T\u00ecm x: ( ) A. x = 4 B. x = 5 C. x = 6 D. x = 7 Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, b, c, d, C\u00e2u 2: M\u1ed9t t\u1ed1p c\u00f4ng nh\u00e2n c\u00f3 240 ng\u01b0\u1eddi. Trong \u0111\u00f3 s\u1ed1 c\u00f4ng nh\u00e2n l\u00e0 c\u00f4ng nh\u00e2n n\u1eef. H\u1ecfi c\u00f3 bao nhi\u00eau c\u00f4ng nh\u00e2n n\u1eef? C\u00e2u 3: M\u1eb9 Minh n\u0103m nay 28 tu\u1ed5i. H\u1ecfi Minh bao nhi\u00eau tu\u1ed5i? Bi\u1ebft t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a 2 m\u1eb9 con hi\u1ec7n t\u1ea1i l\u00e0 7 tu\u1ed5i.","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 15. \u0110\u1ec0 3 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: C\u00f3 7 qu\u1ea3 cam v\u00e0 1 qu\u1ea3 d\u00e2u. H\u1ecfi s\u1ed1 qu\u1ea3 d\u00e2u b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y t\u1ed5ng s\u1ed1 qu\u1ea3? A. B. C. D. C\u00e2u 2: S\u1ed1 d\u01b0 c\u1ee7a ph\u00e9p chia l\u00e0: A. 7 B. 8 C. 9 D. 6 C\u00e2u 3: T\u00ednh: A. 65 B. 60 C. 63 D. 75 C\u00e2u 4: T\u00ecm x: d\u01b0 1 A. x = 775 B. x = 774 C. x = 777 D. x = 778 C\u00e2u 5: M\u1ed9t l\u1edbp h\u1ecdc c\u00f3 33 h\u1ecdc sinh \u0111\u01b0\u1ee3c x\u1ebfp v\u00e0o ph\u00f2ng h\u1ecdc lo\u1ea1i b\u00e0n 2 ch\u1ed7 ng\u1ed3i. H\u1ecfi c\u1ea7n \u00edt nh\u1ea5t bao nhi\u00eau b\u00e0n \u0111\u1ec3 ai c\u0169ng c\u00f3 ch\u1ed7 ng\u1ed3i? A. 15 B. 16 C. 17 D. 18 C\u00e2u 6: M\u1ed9t s\u00e2n v\u1eadn \u0111\u1ed9ng d\u00e0i 364m \u0111\u01b0\u1ee3c chia th\u00e0nh 7 \u0111o\u1ea1n b\u1eb1ng nhau. H\u1ecfi m\u1ed7i \u0111o\u1ea1n d\u00e0i bao nhi\u00eau m\u00e9t? A. 53 B. 52 C. 55 D. 54 Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ecm x bi\u1ebft: a, ( ) b, ( ) c, ( ) d, ( ) C\u00e2u 2: M\u1ed9t h\u1ed9p b\u00e1nh c\u00f3 3 chi\u1ebfc b\u00e1nh. H\u1ecfi v\u1edbi 561 chi\u1ebfc b\u00e1nh th\u00ec x\u1ebfp \u0111\u01b0\u1ee3c v\u00e0o bao nhi\u00eau h\u1ed9p?","C\u00e2u 3: Minh c\u00f3 m\u1ed9t cu\u1ed1n truy\u1ec7n tranh d\u00e0y 320 trang. Minh \u0111\u00e3 \u0111\u1ecdc \u0111\u01b0\u1ee3c s\u1ed1 trang. H\u1ecfi Minh c\u00f2n ph\u1ea3i \u0111\u1ecdc bao nhi\u00eau trang n\u1eefa th\u00ec h\u1ebft truy\u1ec7n? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 16. \u0110\u1ec0 1 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: A. 94 B. 49 C. 79 D. 50 C\u00e2u 2: Gi\u1edd n\u00e0o sau \u0111\u00e2y c\u00f3 kim gi\u1edd v\u00e0 kim ph\u00fat t\u1ea1o th\u00e0nh 1 g\u00f3c : A. 3 gi\u1edd 10 ph\u00fat B. 3 gi\u1edd C. 3 gi\u1edd 20 ph\u00fat D. 3 gi\u1edd 5 ph\u00fat C\u00e2u 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u00e3y s\u1ed1: 1, 3, 4, 7, 11, ...... A. 12 B. 13 C. 14 D. 18 C\u00e2u 4: So s\u00e1nh: A. > B. < C. = D. Kh\u00f4ng th\u1ec3 so s\u00e1nh C\u00e2u 5: T\u00ecm x: A. 81 B. 19 C. 9 D. 90 C\u00e2u 6: T\u00ednh: A. 140 B. 120 C. 34 D. 134 Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m)","C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, b, c, d, C\u00e2u 2: Qu\u00e3ng \u0111\u01b0\u1eddng AB d\u00e0i 218m, qu\u00e3ng \u0111\u01b0\u1eddng BC d\u00e0i g\u1ea5p 3 l\u1ea7n qu\u00e3ng \u0111\u01b0\u1eddng AB (H\u00ecnh v\u1ebd). H\u1ecfi qu\u00e3ng \u0111\u01b0\u1eddng AC d\u00e0i bao nhi\u00eau m\u00e9t? AB C C\u00e2u 3: T\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft r\u1eb1ng s\u1ed1 \u0111\u00f3 nh\u00e2n v\u1edbi 7 r\u1ed3i c\u1ed9ng v\u1edbi 41 th\u00ec \u0111\u01b0\u1ee3c m\u1ed9t bi\u1ec3u th\u1ee9c c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng 300. \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 16. \u0110\u1ec0 2 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: () A. 980 B. 908 C. 890 D. 809 C\u00e2u 2: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u00e3y s\u1ed1: 2, 4, 6, 10, 16, ...... A. 17 B. 18 C. 26 D. 22 C\u00e2u 3: So s\u00e1nh: A. > B. < C. = D. Kh\u00f4ng th\u1ec3 so s\u00e1nh C\u00e2u 4: T\u00ecm x: A. 1 B. 2 C. 3 D. 4 C\u00e2u 5: T\u00ednh: A. 44 B. 200 C. 48 D. 40 C\u00e2u 6: T\u00ecm x: A. 168 B. 108 C. 118 D. 178 Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m)","C\u00e2u 1: T\u00ecm x bi\u1ebft: a, ( ) b, ( ) C\u00e2u 2: M\u1ed9t g\u00f3i k\u1eb9o n\u1eb7ng 20g, m\u1ed9t g\u00f3i b\u00e1nh n\u1eb7ng 40g. M\u1eb9 mua 2 g\u00f3i k\u1eb9o v\u00e0 5 g\u00f3i b\u00e1nh. H\u1ecfi s\u1ed1 b\u00e1nh k\u1eb9o m\u1eb9 mua n\u1eb7ng bao nhi\u00eau gam? C\u00e2u 3: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 183kg g\u1ea1o. Ng\u01b0\u1eddi ta b\u00e1n \u0111i 78 kg g\u1ea1o. S\u1ed1 c\u00f2n l\u1ea1i chia \u0111\u1ec1u v\u00e0o 7 t\u00fai. H\u1ecfi m\u1ed7i t\u00fai c\u00f3 bao nhi\u00eau kg g\u1ea1o? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 16. \u0110\u1ec0 3 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: A. 130 B. 4 C. 140 D. 14 C\u00e2u 2: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u00e3y s\u1ed1: 1, 4, 7, 10, 13, ...... A. 14 B. 15 C. 16 D. 17 C\u00e2u 3: So s\u00e1nh: ...... A. > B. < C. = D. Kh\u00f4ng th\u1ec3 so s\u00e1nh C\u00e2u 4: T\u00ecm x bi\u1ebft: x=? A. x = 8 B. x = 9 C. x = 10 D. x = 11 C\u00e2u 5: S\u1ed1 n\u00e0o gi\u1ea3m \u0111i 25 \u0111\u01a1n v\u1ecb r\u1ed3i gi\u1ea3m ti\u1ebfp 2 l\u1ea7n th\u00ec b\u1eb1ng 10? A. 45 B. 40 C. 25 D. 50 C\u00e2u 6: M\u1ed7i b\u00f4ng hoa h\u1ed3ng c\u00f3 gi\u00e1 9 xu, m\u1ed7i b\u00f4ng hoa c\u1ea9m ch\u01b0\u1edbng c\u00f3 gi\u00e1 7 xu. M\u1eb9 mua 5 b\u00f4ng hoa h\u1ed3ng v\u00e0 5 b\u00f4ng hoa c\u1ea9m ch\u01b0\u1edbng h\u1ebft bao nhi\u00eau ti\u1ec1n? A. 35 xu B. 70 xu C. 45 xu D. 80 xu","Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh: a, b, c, d, C\u00e2u 2: M\u1eb9 h\u00e1i \u0111\u01b0\u1ee3c 70 qu\u1ea3 \u0111\u00e0o, ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c 35 qu\u1ea3 \u0111\u00e0o. S\u1ed1 \u0111\u00e0o \u0111\u00f3 \u0111\u01b0\u1ee3c x\u1ebfp \u0111\u1ec1u v\u00e0o 7 th\u00f9ng. H\u1ecfi m\u1ed7i th\u00f9ng c\u00f3 bao nhi\u00eau qu\u1ea3 \u0111\u00e0o? C\u00e2u 3: Cho bi\u1ec3u th\u1ee9c a, 90 . H\u00e3y \u0111\u1eb7t c\u00e1c d\u1ea5u ngo\u1eb7c \u0111\u01a1n v\u00e0o bi\u1ec3u th\u1ee9c tr\u00ean \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e1c k\u1ebft qu\u1ea3 sau: b, 26 \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 17. \u0110\u1ec0 1 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: () C. 218 D. 228 A. 148 B. 184 C\u00e2u 2: T\u00ecm x: B. x = 1 x=? D. x = 3 A. x = 0 C. x = 2 C\u00e2u 3: Cho h\u00ecnh v\u1ebd: H\u1ecfi h\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef nh\u1eadt? A. 1 B. 2 C. 3 D. 4","C\u00e2u 4: H\u00ecnh v\u1ebd tr\u00ean (C\u00e2u 3) c\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c? A. 2 B. 3 C. 5 D. 4 C\u00e2u 5: C\u00f3 25 chi\u1ebfc b\u00e1nh. N\u1ebfu th\u00eam 5 chi\u1ebfc b\u00e1nh th\u00ec x\u1ebfp \u0111\u1ec1u \u0111\u01b0\u1ee3c v\u00e0o 3 th\u00f9ng. H\u1ecfi m\u1ed7i th\u00f9ng c\u00f3 bao nhi\u00eau chi\u1ebfc b\u00e1nh? A. 10 chi\u1ebfc b\u00e1nh B. 8 chi\u1ebfc b\u00e1nh C. 6 chi\u1ebfc b\u00e1nh D. 5 chi\u1ebfc b\u00e1nh C\u00e2u 6: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 2dm, chi\u1ec1u r\u1ed9ng 2cm. H\u1ecfi chi\u1ec1u d\u00e0i h\u01a1n chi\u1ec1u r\u1ed9ng bao nhi\u00eau cm? A. 20cm B. 2cm C. 18cm D. 10cm Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh: a, ( ) b, ( ) C\u00e2u 2: C\u00f3 120 h\u1ed9p s\u1eefa x\u1ebfp \u0111\u1ec1u v\u00e0o 2 k\u1ec7. M\u1ed7i k\u1ec7 \u0111\u1ec3 \u0111\u01b0\u1ee3c 3 th\u00f9ng. H\u1ecfi m\u1ed7i th\u00f9ng c\u00f3 bao nhi\u00eau h\u1ed9p s\u1eefa? C\u00e2u 3: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i l\u00e0 24m. Chi\u1ec1u r\u1ed9ng b\u1eb1ng chi\u1ec1u d\u00e0i. H\u1ecfi chi\u1ec1u r\u1ed9ng d\u00e0i bao nhi\u00eau m\u00e9t? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 17. \u0110\u1ec0 2 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: () A. 10 B. 11 C. 42 D. 24","C\u00e2u 2: T\u00ecm x: () A. 0 B. 1 C. 2 D. 3 C\u00e2u 3: Cho h\u00ecnh v\u1ebd: H\u00ecnh ch\u1eef nh\u1eadt ABDC c\u00f3 chi\u1ec1u r\u1ed9ng b\u1eb1ng bao nhi\u00eau cm? A. 1cm B. 4cm C. 5cm D. 6cm C\u00e2u 4: Chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt ABDC l\u1edbn h\u01a1n chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt ABMN l\u00e0 bao nhi\u00eau cm? (h\u00ecnh v\u1ebd c\u00e2u 3) A. 3cm B. 1cm C. 4cm D. 2cm C\u00e2u 5: H\u00ecnh v\u1ebd tr\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef nh\u1eadt? A. 4 B. 3 C. 2 D. 1 C\u00e2u 6: H\u00ecnh ch\u1eef nh\u1eadt c\u00f3 t\u1ed5ng chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng l\u00e0 75cm. Chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt b\u1eb1ng t\u1ed5ng chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng. H\u1ecfi chi\u1ec1u d\u00e0i h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 bao nhi\u00eau cm? A. 60 B. 13 C. 15 D. 40 b, Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh: a, ( ) C\u00e2u 2: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 36 chi\u1ebfc qu\u1ea1t. Ng\u00e0y th\u1ee9 nh\u1ea5t b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 qu\u1ea1t. Ng\u00e0y th\u1ee9 hai b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 qu\u1ea1t c\u00f2n l\u1ea1i. H\u1ecfi c\u1eeda h\u00e0ng ng\u00e0y th\u1ee9 hai b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau chi\u1ebfc qu\u1ea1t? C\u00e2u 3: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng b\u1eb1ng chi\u1ec1u d\u00e0i. N\u1ebfu m\u1edf r\u1ed9ng chi\u1ec1u d\u00e0i th\u00eam 12m ta \u0111\u01b0\u1ee3c 27m. H\u1ecfi chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng ban \u0111\u1ea7u h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 bao nhi\u00eau?","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 17. \u0110\u1ec0 3 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: T\u00ednh: () A. 165 B. 145 C. 125 D. 135 C\u00e2u 2: T\u00ecm x: () A. 1 B. 2 C. 3 D. 4 C\u00e2u 3: Cho h\u00ecnh v\u1ebd: H\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef nh\u1eadt? A. 6 B. 9 C. 8 D. 7 C\u00e2u 4: T\u00ednh: A. 28 B. 72 C. 100 D. 68 C\u00e2u 5: Hai \u0111\u1ed9i c\u00f4ng nh\u00e2n c\u00f9ng l\u00e0m chung m\u1ed9t \u0111o\u1ea1n \u0111\u01b0\u1eddng d\u00e0i 585m. \u0110\u1ed9i A c\u00f3 5 ng\u01b0\u1eddi, \u0111\u1ed9i B c\u00f3 4 ng\u01b0\u1eddi. H\u1ecfi m\u1ed7i c\u00f4ng nh\u00e2n ph\u1ea3i l\u00e0m bao nhi\u00eau m\u00e9t \u0111\u01b0\u1eddng? (c\u00e1c c\u00f4ng nh\u00e2n l\u00e0m nh\u01b0 nhau) A. 66m B. 64m C. 60m D. 65m C\u00e2u 6: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 24m, chi\u1ec1u r\u1ed9ng b\u1eb1ng chi\u1ec1u d\u00e0i. H\u1ecfi chi\u1ec1u d\u00e0i h\u01a1n chi\u1ec1u r\u1ed9ng bao nhi\u00eau m\u00e9t? A. 8m B. 16m C. 24m D. 12m Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m)","C\u00e2u 1: T\u00ednh: b, ( ) ( ) a, C\u00e2u 2: Theo k\u1ebf ho\u1ea1ch, m\u1ed9t t\u1ed5 s\u1ea3n xu\u1ea5t ph\u1ea3i d\u1ec7t 450 chi\u1ebfc \u00e1o len. T\u1ed5 \u0111\u00f3 \u0111\u00e3 l\u00e0m \u0111\u01b0\u1ee3c s\u1ed1 chi\u1ebfc \u00e1o len theo k\u1ebf ho\u1ea1ch . H\u1ecfi t\u1ed5 \u0111\u00f3 c\u00f2n ph\u1ea3i d\u1ec7t bao nhi\u00eau chi\u1ebfc \u00e1o len n\u1eefa? C\u00e2u 3: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i h\u01a1n chi\u1ec1u r\u1ed9ng 16m. Chi\u1ec1u d\u00e0i g\u1ea5p 3 l\u1ea7n chi\u1ec1u r\u1ed9ng. H\u1ecfi chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 b\u1eb1ng bao nhi\u00eau m\u00e9t? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 18. \u0110\u1ec0 1 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 ch\u00edn tr\u0103m m\u01b0\u1eddi hai vi\u1ebft l\u00e0: A. 92 B. 902 C. 912 D. 921 C\u00e2u 2: T\u00ednh: () A. 210 B. 220 C. 202 D. 120 C\u00e2u 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 7m 3cm = ........ cm A. 73 B. 703 C. 730 D. 713 C\u00e2u 4: M\u1ed9t chi\u1ebfc b\u00eca h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i l\u00e0 25dm, chi\u1ec1u r\u1ed9ng 1dm. Chu vi mi\u1ebfng b\u00eca \u0111\u00f3 l\u00e0 bao nhi\u00eau dm? A. 52dm B. 70dm C. 26dm D. 60dm C\u00e2u 5: H\u00ecnh vu\u00f4ng c\u00f3 m\u1ea5y g\u00f3c vu\u00f4ng?","A. 1 B. 2 C. 3 D. 4 C\u00e2u 6: M\u1ed9t c\u00e1i ao h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 6m. Chu vi c\u00e1i ao \u0111\u00f3 l\u00e0: A. 24m B. 30m C. 12m D. 18m Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, b, c, d, C\u00e2u 2: Ng\u01b0\u1eddi ta x\u1ebfp 100 c\u00e1i b\u00e1nh v\u00e0o c\u00e1c h\u1ed9p, m\u1ed7i h\u1ed9p c\u00f3 4 c\u00e1i b\u00e1nh. Sau \u0111\u00f3, ng\u01b0\u1eddi ta x\u1ebfp c\u00e1c h\u1ed9p v\u00e0o c\u00e1c th\u00f9ng, m\u1ed7i th\u00f9ng 5 h\u1ed9p. H\u1ecfi c\u00f3 bao nhi\u00eau th\u00f9ng b\u00e1nh? C\u00e2u 3: C\u00f3 5 th\u00f9ng s\u00e1ch, m\u1ed7i th\u00f9ng \u0111\u1ef1ng \u0111\u01b0\u1ee3c 117 quy\u1ec3n s\u00e1ch. S\u1ed1 s\u00e1ch \u0111\u00f3 chia \u0111\u1ec1u cho 9 th\u01b0 vi\u1ec7n tr\u01b0\u1eddng h\u1ecdc. H\u1ecfi m\u1ed7i th\u01b0 vi\u1ec7n \u0111\u01b0\u1ee3c chia bao nhi\u00eau quy\u1ec3n s\u00e1ch? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 18. \u0110\u1ec0 2 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Cho s\u1ed1 b\u00e9 l\u00e0 5, s\u1ed1 l\u1edbn l\u00e0 35. H\u1ecfi s\u1ed1 l\u1edbn g\u1ea5p m\u1ea5y l\u1ea7n s\u1ed1 b\u00e9? A. 8 l\u1ea7n B. 7 l\u1ea7n C. 6 l\u1ea7n D. 5 l\u1ea7n C\u00e2u 2: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u1ea5u \u201c?\u201d: A. 108 B. 99 C. 76 D. 100 D. 912 C\u00e2u 3: T\u00ednh: D. 4 A. 924 B. 304 C. 612 C\u00e2u 4: H\u00ecnh ch\u1eef nh\u1eadt c\u00f3 bao nhi\u00eau g\u00f3c vu\u00f4ng? A. 1 B. 2 C. 3","C\u00e2u 5: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 9m 8cm = ........ cm A. 98 B. 908 C. 980 D. 9080 C\u00e2u 6: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng 6cm. Chi\u1ec1u d\u00e0i h\u01a1n chi\u1ec1u r\u1ed9ng 7cm. H\u1ecfi chu vi h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 bao nhi\u00eau cm? A. 38cm B. 19cm C. 13cm D. 42cm Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ecm x bi\u1ebft: a, ( ) b, ( ) C\u00e2u 2: C\u00f3 750 quy\u1ec3n s\u00e1ch x\u1ebfp \u0111\u1ec1u v\u00e0o 5 t\u1ee7, m\u1ed7i t\u1ee7 c\u00f3 2 ng\u0103n. H\u1ecfi m\u1ed7i ng\u0103n c\u00f3 bao nhi\u00eau quy\u1ec3n s\u00e1ch? Bi\u1ebft m\u1ed7i ng\u0103n c\u00f3 s\u1ed1 s\u00e1ch l\u00e0 nh\u01b0 nhau. C\u00e2u 3: M\u1ed9t c\u1eeda h\u00e0ng nh\u1eadp v\u1ec1 168 t\u1ea5n g\u1ea1o, chia \u0111\u1ec1u v\u00e0o 3 kho. Sau \u0111\u00f3, c\u1eeda h\u00e0ng nh\u1eadp th\u00eam v\u00e0o m\u1ed7i kho 16 t\u1ea5n g\u1ea1o v\u00e0 b\u00e1n h\u1ebft s\u1ed1 g\u1ea1o trong 2 kho. H\u1ecfi c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau t\u1ea5n g\u1ea1o? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 18. \u0110\u1ec0 3 M\u00d4N: TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 kh\u00e1c nhau l\u00e0: A. 102 B. 101 C. 100 D. 120 C\u00e2u 2: T\u00ednh: A. 100 B. 799 C. 744 D. 689 C\u00e2u 3: C\u00f3 7 con v\u1ecbt, s\u1ed1 g\u00e0 nhi\u1ec1u h\u01a1n s\u1ed1 v\u1ecbt 56 con. H\u1ecfi s\u1ed1 v\u1ecbt b\u1eb1ng m\u1ed9t ph\u1ea7n m\u1ea5y s\u1ed1 g\u00e0?","A. B. C. D. C\u00e2u 4: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: A. 7 B. 5 C. 8 D. 6 C. 70 l\u00edt D. 17 l\u00edt C\u00e2u 5: G\u1ea5p 7 l\u1ea7n c\u1ee7a 10 l\u00edt l\u00e0: C. 1012 D. 1000 A. 15 l\u00edt B. 49 l\u00edt b, C\u00e2u 6: S\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 4 ch\u1eef s\u1ed1 l\u00e0: A. 1023 B. 1001 Ph\u1ea7n II. T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh: a, C\u00e2u 2: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 453kg g\u1ea1o, c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 g\u1ea1o. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau kg g\u1ea1o? C\u00e2u 3: Lan c\u00f3 6 h\u1ed9p k\u1eb9o. Sau khi Lan cho b\u1ea1n 24 vi\u00ean k\u1eb9o th\u00ec Lan c\u00f2n l\u1ea1i 4 h\u1ed9p k\u1eb9o. H\u1ecfi Lan c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau vi\u00ean k\u1eb9o?",""]


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