Regression Analysis                                                                            345          Illustration: 2: For a given distribution the value of correlation is 0.64 and its probable error  is 0.13274. Find the number of items in the series.                                         2    Solution: P.E. =0.6745 × 1           r  Given, PE = 0.13274 Correlation (r) = 0.64                                       n    n=?                                   2    PE =             1     (0.64)        0.6745 ×           n          0.13274 =        0.6745(1 0.4096)     n 0.13274 = 0.6745 x 0.5904                                     n            n = 0.3982  n = 2.999 ? n = 9 (Approx)                   0.13274    Illustration: 3: Compute Karl Pearson’s Co-efficient of Correlation from the following data    and calculate its probable error and interpret the result.    Marks in Accountancy 77 54 27 52 14 35 90 25 56 60    Marks in English                  35 58 60 40 50 40 35                              56 34      42                                                                                             xy  Solution:                           Calculation of Karl Pearson’s Co-efficient of Correlation    X X - 49                          x2 Y Y - 45                        y2                      x                                             y    77 + 28                        784 35 - 10 100                                      - 280    54 + 5                            25 58 + 13 169                                    + 65    27 - 22                        484 60 + 15 225                                      - 330    52 + 3                               9 40                   -5       25             - 15    14 - 35 1,225 50 + 5                                                 25             - 175    35 - 14                        196 40                       -5       25             + 70    90 + 41 1,681 35 - 10 100                                                           - 410    25 - 24                        576 56 + 11 121                                      - 264    56 + 7                            49 34 - 11 121                                    - 77    60 + 11                        121 42                       -3       9              - 33    ¦X = 490               ¦x2 = 5,150 ¦Y = 450                          ¦y2 = 920 ¦xy = - 1,449                                                                                                   r                                      CU IDOL SELF LEARNING MATERIAL (SLM)
346 Business Mathematics and Statistics               =               ¦ xy 1449                                    0.666                             2 2=                         ¦x u ¦ y           5150 u              920                                       2                         2                   0.3753                               1r             1 (0.666)               PE = 0.6745 N = 0.6745 10 = 3.162 0.119    Illustration 9: Calculate Karl Pearson’s coefficient of correlation between percentage of pass    and failures from the following data. Also obtain probable error:         No. of Students:                 80 60 90 70 50 40         No. of Students passed:          48  30                     45              56          45    30    Solution:    % of pass % of fail x = x - a x2 y = y - b                                               y2        xy    (x) (y) a = 50                                                   b = 50    60 40 10 100 -10 100 -100    50 50 0 0 0 0 0    50 50 0 0 0 0 0    80 20 30 900 -30 900 -900    90         10                 40 1,600                             -40               1,600       -1,600    75 25 25 625 -25 625 -625    405        195                105 3,225                          -105                3,225       -3,225            405 195  X = 6 = 67.5 = 6 = 32.5                          N.6 xy 6x. 6y       r= 2 2 2 2                 N6x 6x) N6y (6y)                    6( 3, 225) (105)( 105)         =2                                                       2               6(3, 225) (105) 6(3, 225) ( 105)                           19,350 11, 025                            8,325               8,325         =     19,350 11,025 19,350 11, 025 =                                     2  =   8,325   = -1                                                                     (8,325)                    1       2                                  2  0.6745 × 0                           r      0.6745 1 ( 1)  PE = 0.6745 n =                           6 = 6 =0                                  CU IDOL SELF LEARNING MATERIAL (SLM)
Regression Analysis                                        347    15.6 Summary          Regression: The term “regression” was used by Sir Francis Galton to describe a hereditary  phenomenon that he observed in his study of the heights of sons and fathers. His main observation  was that though tall fathers usually had tall sons, the average height of the sons of tall fathers was  less than the average height of the fathers. In short, the average height of the sons of tall fathers will  regress or go back to the general average height. Galton called this backward or downward tendency  in the average height as regression. At phenomena — whether economic business or social.          A line that is drawn as close as possible to the plotted points of the scatter diagram shows the  average tendency of the plotted points. This line is known as the regression line and its equation is  called the regression equation.          Unlike the coefficient of correlation, which indicates the extent of the relationship between  two sets of figures, a regression equation enables us to calculate the amount of change in one  variable corresponding to a change in the other.    15.7 Key Words/Abbreviations          Regression Equation, Regression Coefficients    15.8 Learning Activity             1. Form a frequency distribution of the following test scores of 50 individuals using a               class interval of 10:                    75 130 135 90 118 92 80 142 97 147                    98 94 115 109 154 109 111 117 120 91                    124 101 97 98 126 94 109 109 94 110                    82 96 119 92 99 114 104 169 107 93                    102 83 117 98 77 133 87 145 91                         CU IDOL SELF LEARNING MATERIAL (SLM)
348 Business Mathematics and Statistics    2. The following data represent weights, recorded to the nearest kilogram, of 30 students      selected from a school of 500 students:    21 30 40 25 26 22 39 31 29    36 38 35 34 33 30 23 27 27    29 31 33 22 21 36 40 31 33    30 37 36    In the above data, state what is the:    (i) Population (ii) Sample and (iii) Variate.    3. Draft a blank table to show:    (a) Sex.    (b) Three ranks — supervisors, assistants and clerks.    (c) Years 1998 and 2003.    (d) Age-groups: 18 years and under, over 18 but less than 55 years, over 55 years.    4. Draw up the proforma of suitable table (complete with title, rulings, columnar heading,      sub-headings, source, note etc.) showing the number of students in your university in      various classes, classified according to sex, residence, domicile and medium of      instruction.    5. Draw up a table to show the distribution of workers in a certain cloth mill according to:    (i) Salary:  Below ` 150, ` 150 to 300, ` 300 to 450, ` 450 and over,    (ii) Three years: 1967, 68, 69.    (iii) Age groups: Below 20, 20 and under 30, 30 and under 40, 40 and under 50,50                           and over.    (iv) Sex.    6. Present the following information in a suitable tabular form, filling the gaps if any.      “The total population of India is 3,566 lakhs, of which 2,948 lakhs belong to rural    areas. In rural areas, 2,404 lakhs belong to agricultural classes; while in urban areas 531  lakhs belong to the non-agricultural classes. Of the rural agricultural classes, 687 lakhs  are self-supporting persons, 1,414 lakhs are non-earning dependents and the remaining                 CU IDOL SELF LEARNING MATERIAL (SLM)
Regression Analysis                                        349                 are earning dependents. Of the rural non-agricultural population, 170 lakhs are self-               supporting, 326 lakhs are non-earning dependants and the remaining are earning               dependants. In the urban agricultural classes 23 lakhs are self-supporting, 56 lakhs are               non-earning dependants and the remaining are earning dependants. In the urban non-               agricultural population, 153 lakhs are self-supporting, 347 lakhs are non-earning               dependants and the remaining are earning dependants.”    15.9 Unit End Questions (MCQ and Descriptive)    A. Descriptive Type: Short Answer Type Questions           1. Explain the concept of ‘regression’ and comment on its utility.           2. Explain the terms (i) coefficient of regression and (ii) lines of regression.           3. Show that the correlation coefficient is the geometric mean between regression               coefficients.           4. Explain the concept of linear regression. Why are there two regression lines? Do they               cut each other?           5. Compare and contrast the roles of correlation and regression in studying the               interdependence of two variates.           6. Define ‘regression’. Why are there two regression lines? Under what conditions can               there be only one regression line?           7. Distinguish between coefficient of correlation and coefficient of regression and state               briefly why the latter is often more useful in statistics than the former.           8. Find the regression coefficients and the regression equations for the following data:               X : 76 50 61 45 27 49 32 54 70 36               Y : 58 60 72 78 56 40 43 65 22 36           9. From the undermentioned data, find out                (i) Karl Pearson’s coefficient of correlation,               (ii) the two regression equations,                         CU IDOL SELF LEARNING MATERIAL (SLM)
350 Business Mathematics and Statistics                (iii) the two regression coefficients,              (iv) the best mean value of X when Y is 50,               (v) the best mean value of Y when X is 45.               Y: 55 59 63 68 56 73 82 76 64 74               X : 60 62 55 54 63 72 78 79 65 82         10. Calculate the coefficient of correlation and obtain the lines of regression for the following               data:               X: 1 2 3 4 5 6 7 8 9               Y: 9 8 10 12 11 13 14 16 15               Obtain an estimate of y which should correspond on the average to x = 6.2         11. In a partially destroyed laboratory record of an analysis of correlation data, the following               results only are legible:               Variance of x = 9. Regression equations:               8x - 10y + 66 = 0, 40x - 18y = 214.               What were the mean values of x and y, the standard deviation of y and the coefficient of               correlation between x and y?         12. The following are marks in Statistics (x) and Mathematics (y) of ten students.               x : 56 55 58 58 57 56 60 54 59 57               y : 68 67 67 70 65 68 70 66 68 66               Calculate the coefficient of correlation and estimate marks in Mathematics of a student               who scores 62 marks in statistics.         13. The following data give the height in inches (X) and the weight in lb (Y) of random               sample of 10 students from a large group of students of age 17 years.               x : 61 68 68 64 65 70 63 62 64 67               y : 112 123 130 115 110 125 100 113 116 126               Estimate the weight of a student of height 69 inches.         14. From the following data calculate the coefficient of correlation and estimate x when y               is equal to 105.                                                           CU IDOL SELF LEARNING MATERIAL (SLM)
Regression Analysis                                                   351    x : 44 58 49 46 58 56 48 46 48 47  y : 88 114 102 113 91 89 102 93 114 94    15. For a bivariate data              the mean value of x = 53.2              the mean value of y = 27.9              the regression coefficient of x on y = - 0.2 and              the regression coefficient of y on x = - 1.5    Find (i) the most probable value of y when x = 60, (ii) r the coefficient of correlation.    16. You are given the following results for the heights (x) and weights (y) of 1000 workers    of a factory.    x = 68 inches,                 Vx = 2.5 inches    y = 150 lb,                    Vy = 20 lb                                   rxy = 0.6.    Estimate from the above data.    (i) The height fo a particular factory worker whose weight is 200 lb    (ii) The weight of a particular factory worker who is 5 feet tall.    17. Find the most likely price in Bombay (x) corresponding to the price of Rs.70 at Calcutta        (y) from the following data:    Average price at Calcutta = 55    Average prie at Bombay         = 67  S. D. at Calcutta              = 2.5  S. D. at Bombay                = 3.5                                 = + .8    18. The equation of two regerssion lines obtained in a correlation analysis are as follows:                4y = 9x + 15               25x = 6y + 7                         CU IDOL SELF LEARNING MATERIAL (SLM)
352 Business Mathematics and Statistics    Obtain the value of correlation coefficient, the ratio of the coefficient of variability of x  to that of y and also mean values of x and y.    19. Following is the information relating to per capita consumption of wheat per year and    the retail price of wheat:                                (Y)                   (X)                                               Retail Price  Year              Per Capita Consumption                                                  (Paise)                              (Kg)                   63                                                     65  1960                        35                     68                                                     64  1961                        34                     64                                                     68  1962                        32                     70                                                     75  1963                        36    1964                        37    1965                        34    1966                        33    1967                        30    Fit a straight line of per capita consumption (Y) on retail price (X).    20. From the data given below find:    (a) The two regression equations.    (b) The coefficient of correlation between marks in Economics and Statistics.    (c) The most likely marks in Statistics when the marks in Economics are 30.    Marks in Economics : 25 28 35 32 31 36 29 38 34 32    Marks in Statistics : 43 46 49 41 36 32 31 30 33 39    B. Multiple Choice/Objective Type Questions    1. Given the 2 Keynesian equation    3x - 2y + 1 = 0  62y - 5x + 3 = 0    (a) 0.45                                     (b) 0.53  (c) 0.63                                     (d) None of these                      CU IDOL SELF LEARNING MATERIAL (SLM)
Regression Analysis                                                              353    2. Given x = 1, y = 43, r = 0.62      Vx = 8.3, Vy = 6/4. like 2      Regression equations are x = 0.8y - 3.57 and y = 0.48 + 28.18    (a) Wrong                                        (b) Correct         (c) None of these  3. The term “regression” was used by Sir Francis Galton to describe the average        ____________ of father and son.    (a) Weight                                       (b) Complexion    (c) Height                                       (d) size    4. The equation of regression line is called as __________.    (a) Regression equation                          (b) Coefficient of correlation                  (c) Correlation                    (d) All the above  Answers:                 (1) (b); (2) (b); (3) (c); (4) (a)    15.10 References    References of this unit have been given at the end of the book.                                                                              CU IDOL SELF LEARNING MATERIAL (SLM)
UNIT 16 TIME SERIES ANALYSIS    Structure    16.0 Learning Objectives  16.1 Introduction  16.2 Time Series: Its meaning  16.3 Time Series: Analysis  16.4 Measurement of General Trend  16.5 Solved Problems  16.6 Summary  16.7 Key Words/Abbreviations  16.8 Learning Activity  16.9 Unit End Questions (MCQ and Descriptive)  16.10 References    16.0 Learning Objectives          After completing this unit, you would be able to:           1. Explain the meaning of a time series and the various types of influences that include,               General trend, Seasonal Changes, Cyclical fluctuations and irregular variations.           2. Elaborate the methods of measurement of the general trend that include: Geographical               method, Method of moving averages and the method of least squares.                                                           CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                        355             3. The procedure for finding 3 yearly, moving averages as explained in the solved problems           4. Differentiate the Merits and Demerits of Moving Averages.           5. Analyse the method of least-squares with reference to the solved problem.           6. Explain the histogram.           7. Elaborate the Parabolic Trend Equation with reference to the solved problem.           8. Explain the Exponentist Trend Method: and as well as various solved problems.    16.1 Introduction          A orderly set of number corresponding to time is a time series. Time series corresponding to  variables such as sales, projects, investment etc., show a number of changes done to the influence of  various factory. These details have been explained in 16.3.          For calculation of these changes Cartesian methods are used. These methods are explained in  the pages that follows.    16.2 Time Series: Its Meaning          In the world of business and economics we find variables of one kind or the other. For instance,  sales, profits, capital, investments, prices, costs, rates of interest, savings, demand for commodities  etc. These are said to be variables because they vary over a period of time. Managements are very  often concerned in closely examining these variables over different periods of time.          An orderly set of numbers written in the order corresponding to time is called a time series.  For instance, a series of terms showing the profits of a business concern over a number of years is a  time series because the terms of series representing profits are written in relation to time. A  careful scrutiny of a time series along with a detailed analysis of condition in the past enables one to  forecast future changes and estimates.          The following is a time series showing the production of cereals in India in million tonnes.                          CU IDOL SELF LEARNING MATERIAL (SLM)
356 Business Mathematics and Statistics    Net Production (Million Tonnes)* of Cereals in India    Year                        Production    1951                        40.01  1952                        40.59  1953                        45.36  1954                        53.44  1955                        51.59  1956                        50.33  1957                        52.67  1958                        49.35  1959                        57.29  1960                        56.76  1961                        60.66  1962                        62.08  1963*                       58.43    * Provisional.  Source: Ministry of Food & Agriculture. Published in the Quarterly Bulletin of the Eastern Economist. New              Delhi. Vol. 16, No. 2.    16.3 Time Series: Analysis          A detailed analysis of the above time series enables us to find the different types of movements  influencing its course. Usually in any given time series the different types of movements are  characterized by the following component:             1. General Trend           2. Seasonal changes           3. Cyclical Fluctuations           4. Irregular Variations    16.3.1 General Trend        The time series of the net productions of cereals in India shows that there is certainly a gradual    increase in the production of cereals even though the increase is not regular. This gradual increase  is called the “General Trend” or secular trend. This trend, which means here a gradual increase in  the production of cereals, is brought about by the proper use of modern agricultural machinery and    CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                        357    techniques, better manure and chemical fertilizers and also the farmer’s efforts. Maximum yields  can be expected when farmers know exactly the proper proportions of nutrients that are ideal for  crops. An hectare of agricultural land would need several hundred kilograms of nitrogen, phosphorous  and potash and a fair sparkling of secondary and micro elements like iron copper. In other words  this gradual increase can be attributed to the growing realization among farmers about the advantages  of profit-oriented farming, modern equipment, improved seeds, greater use of fertilizers, pesticides  and modern methods of farming.          The general trend is influenced by a group of factors which include seasonal fluctuations,  cyclical fluctuations and also unforeseen events. The trend can therefore be clearly studied when  these different influences are clearly eliminated.    16.3.2 Seasonal Fluctuations        Eliminating seasonal influences is no easy task. The occurrence of seasons is responsible for    these fluctuations. Natural phenomena are always unavoidable beyond any measure of control. For  instance, variations in food grain production over time depend on whether the season is favorable  or not. It is quite possible that production may be very high and beyond expectations in a certain  season and very low at other times. In short seasonal influences are more or less regularly present  in any time series.    16.3.3 Cyclical Fluctuations        These are due to the occurrence of business or trade cycles in the economic world. For instance;    there may be a period of depression followed by a boom after a few years. It is at such times that  there is considerable variability in the production of cereals. Trade cycles cause up and down  movements in any time series of economic data.    16.3.4 Irregular Variations        In many time series of economic data, we observe sudden upward or downward movements in    the trend. Such movements are irregular and are brought about by unforeseen events and sudden  changes in economic activities and business conditions. Further, political factors too contribute to  uncertain and significant changes. Other irregular and unforeseen events may be wars, earthquakes,  revolutions, fires and floods, which cause sudden and unexpected increase in prices in general.                          CU IDOL SELF LEARNING MATERIAL (SLM)
358 Business Mathematics and Statistics          Further technological progress may lead to an increase in industrial activities. Sometimes  agricultural prosperity might be ushered in by a bounty of nature - favorable rainfall etc. agricultural  prosperity in turn may bring about falling prices in foodgrains and other commodities. In short,  irregular movements are changes by ‘fits and starts’.    16.4 Measurement of General Trend          A general trend can be measured by the following methods:           1. Graphical method-freehand curve.           2. Method of moving averages.           3. Method of least squares.    16.4.1 Graphical Method        This method consists in drawing the curve of the time series on graph paper. First of all,    certain points representing the time series are plotted on the graph paper and these plotted points  are joined by a smooth curve. Such a curve gives a picture of the different up and down movements  in the time series. This curve, when it is drawn smoothly, fairly and regularly, shows the general  direction of the trend. This method gives a rough indication of the nature of the trend and is especially  useful to all those who do not know other techniques of measuring trends. The main drawback of  this graphical method of indicating a trend is that different curves may be drawn by different persons  for the same data and may provide a misleading picture.    16.4.2 Method of Moving Averages        Moving Averages are calculated on the basis of a given period, such as, 3-yearly or 4-yearly or    5-yearly. For instance, 3-yearly moving averages are calculated by taking the average of the values  of 3 years beginning from the first year. This method is especially useful in the case of a time series  with regular cyclical movements. If the periodicity of a time series is known, moving averages can  be calculated easily. The following examples make the method quite clear.    16.4.3 Solved Problems        Problem 1: Calculate the three yearly moving average of the net production (million tonnes)    of cereals.                                                           CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                 359    Year:         1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993    Production: 40.01 40.59 45.36 53.44 51.59 50.33 52.67 49.35 57.29 56.76 60.66 62.08 58.63           Year           Production     Three                             Three yearly                                    yearly Total                       Moving Average         1981                40.01         1982                40.59      —                                     —         1983                45.36     125.96                                 41.99         1984                53.44     139.39                                 46.46         1985                51.59     150.39                                 50.13         1986                50.33     155.36                                 51.79         1987                52.67     154.59                                 51.53         1988                49.35     152.35                                 50.78         1989                57.29     159.31                                 53.10         1990                56.76     163.40                                 54.47         1991                60.66     174.71                                 58.24         1992                62.08     179.50                                 59.83         1993                58.63     181.37                                 60.46                                                                              —                                        —          Problem 2: Calculate four-yearly moving averages and five yearly moving averages for the  following data:    Year:         1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994  Profits:      112 114 119 111 106 101 113 118 121 119 123 124 126           Year           Profits     Four-yearly  Total of                Four-yearly                                      Moving       Two                 Moving Average          1982           112            Total          1983           114                     4-yearly                  Centered          1984          1985           119        456                                113.25          1986           450                               906         110.87                         111                                           108.50                                                           887                         106        437                         431                                                           868                                   CU IDOL SELF LEARNING MATERIAL (SLM)
360 Business Mathematics and Statistics     1987   101                            869            108.62                  438                                   111.37   1988   113                                           115.50                                         891            119.00   1989   118     453                                   121.00                                                        122.37   1990   121                            924                  471   1991   119                                         952   1992   123     481     1993   124                            968   1994   126     487  Year   Profits                                         979   1982   112     492   1983   114   1984   119     Four-yearly  Total of                   Four-yearly   1985   111       Moving       Two                    Moving Average   1986   106         Total   1987   101                  4-yearly                     Centered   1988   113   1989   118     562 906                                       112.4   1990   121     551 887                                       110.2   1991   119     550 868                                       110   1992   123     549 869                                       1098   1991   124     559 891                                       111.8   1994   126     572 924                                       114.4                  594 952                                       118.8                  605 968                                       121                  613 979                                       122.6    16.4.4 Merits of the Moving Average Method           1. It is particularly useful in the case of a time series with regular cyclical movements.           2. Moving averages can be easily calculated and readily understood.           3. The trend either increasing or decreasing that may exist in a time series is clearly brought               out by this method.                    CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                        361             4. It is far better than the freehand curve method.           5. If the period of the moving averages and the duration of the cyclical variation happen to                 be the same, then the moving average method completely eliminates the variations.    16.4.5 Demerits of the Moving Averages Method           1. It is applicable to only such time series that show periodic fluctuations.           2. The trend values at the two extremities of a time series cannot be determined.           3. It is not useful in the case of a time series with regular variations.    16.4.6 Method of Least Squares        Instead of drawing an observation-trend-line for a time series freehand, it is better to fit a    straight line trend more accurately using the mathematical method of least squares. This straight  line so drawn is called the ‘Line of Best Fit’. It is a straight line drawn so that the sum of the squares  of the vertical deviations of the plotted points of the time series is the least. It is for this reason that  the method is called the method of least squares.          If the equation to the line of best fit is written as Y = a +bx, then the values of the constants a  and b are determined by using the following two normal equations:               6y = Na + b6x          6XY = a6X + b6x2        Where                   X represents the year (time).                 Y represents the actual values of the terms in the series.                 N is the number of terms in the time series.        This method can be best explained by the following example:          Problem 3: Fit a straight line trend using the method of least squares to the/scale^ of X, XZ  Industries as given below:                          CU IDOL SELF LEARNING MATERIAL (SLM)
362 Business Mathematics and Statistics                             Year          Sales in Thousands                                              of Rupees                           1988                           1989          204                           1990          1230                           1991          192                           1992          ?~n                                         274                                X               Year                Y XY                            X2                                1               1988             2  204 204                           1               1989             3  230 460                           4               1990             4  192 576                           9               1991             5  250 1000                        16               1992            15  274 1370                        25                                     1150                   3610     55    Substituting the values    N = 5, XY = 1150, 6X = 15, 6XY = 3610, 6X2 = 55 in the two.    Normal equations:               6Y = Na + b6x                                              … (1)          6XY = a6X + b6X2                                              … (2)                                                                        … (1)  We get 1150 = 5a + 15b           3610 = 15a + 55b     Now, 3450 = 15a + 45b    That is multiplying equation (1) by 3 and subtracting the resulting equation (1) from equation    (2) we get:    160 = 10b                  160      ? b = 10 = 16  Now 5a = 1150 - 240    ?a=          910                 5     = 1182    The equation to the line of best fit is: Y = 182 + 16x                               CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                       363          By putting X = 1, 2, 3, 4, 5 in the above equation, we obtain the trend values 198, 214, 230,  246 and 262 respectively.          X = 1, Y = 182 + 16 = 198        X = 2,Y = 182 + 32 = 214        X = 3, Y = 182 + 48 = 230        X = 4, Y = 182 + 64 = 246        X = 5, Y = 182 + 80 = 262    Short Cut Method          We can simplify above calculations by using a short cut method. This method consists of  numbering the years (time) under the column heading X in a different manner. We put zero at the  centre and write negative and positive values above and below it — that is, on either side of zero.  By doing so, we get X = 0 in the two normal equations we obtain the following simplified equations:              6Y = Na6XY = b6X2          ¦Y ¦ XY  a=                       b= 2                        N        ¦x    We now use the short cut method to fit a straight line trend (least squares) to the data given in    the previous example.    Let the equation to the line of best fit be: Y = a + bX    To find the values of the constants a & b we prepare the following table:    Year                     YX                              X2 XY    1988                     204 -2                          4 -408  1989                     230 -1                          1 -230  1990                     192 0                           00  1991                     250 +1                          1 250  1992                     274 +2                          4 548                             1150                            10 160    For the table we have N = 5, 6x2 = 10, 6X = 1150, 6XY = 1600.                                   CU IDOL SELF LEARNING MATERIAL (SLM)
364 Business Mathematics and Statistics    Substituting these values in the two simplified equations it follows that:         ¦Y 1150  a = N = 5 = 230    And,    b=  ¦ XY 160                 = 10  = 16              2          ¦x    Therefore the equation to the line of best fit is -          Y = 230 + 16X        By putting x = -2, -1, 0, 1 and 2 in this equation, at each stage, we get the values of the trend  ordinates 198, 214, 230, 246 and 262 respectively.          The following graph shows vividly actual sales trend, both in freehand and by the method of  least squares.                                             SALES OF X, Y, Z INDUSTRIES                   300                   250                   200                                                              ACTUAL SALES AND FORECAST SALES                                                              ACTUAL SALES                   150                                                              TREND (FREE·HAND)                                                              TREND (LEAST·SQUARES)                   100                    50                   0           1988  1989  1990          1991        1902                               CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                 365    16.5 Solved Problems          Problem 5: Fit an exponential trend Y = abx to the following data by the method of least    squares and find the trend values for the years 1994-98.          Year(X):        1994     1995          1996      1997     1998  1999     2000        Sales(Y) :       87       97           113       129      202   195      193          The exponential curve, is given by the equation Y = abx which can be written in the logarithmic    form          Log Y = log a + X log b                                                        … (1)          If the deviations (X) of the given years are calculated from the middle year 1945, then 6X =    0 and the values of log a and log b is given by:                   ¦log Y                ¦(XlogY)          log a =     N    and, log b =                 2                                                 ¦X          Year             Sales         X                 Log Y          XLogY    X2          1994              87 -3                           1.9395        -5.8185   9        1995              97 -2                           1.9868        -3.9736   4        1996             113 -1                           2.0531        -2.0531   1        1997             129 0                            2.1106                  0        1998             202 1                            2.3054         0        1        1999             195 2                            2.2900         2.3054   4        2000             193 3                            2.2856         4.58     9                                                                         6.8568                                            0            14.9710                 28                                                                         1.8970                          N = 7, 6logY = 14.9710, 6(X log Y) = 1.8970, 6X2 =28.                           ¦log Y 14.9710                    log a = N                  7 = 2.1387          And 6(X log Y) = log b (6X2)                           ¦(XlogY) 1.9870                      log b = ¦X2                28 = 0.0678          Substituting the values of log a and log b in equation (I), we obtain the equation for the  exponential trend in the logarithmic form                                   CU IDOL SELF LEARNING MATERIAL (SLM)
366 Business Mathematics and Statistics    log Y = 2.1387 + 0.0678X.    Further a = Antilog (2.1387) = 137.6           b = Antilog (0.0678) = 1.169.    Therefore the equation of the exponential curve is:    Y = 137.6(1.169)x          Substituting the relevant values of X (deviations from 1945 in the equation log Y = 2.1387 +  0.0678 X we get the logarithms of the trend values for the different years. By finding the anti-  logarithms of these we obtain the trend values.    The trend values for the years 1944 to 1948 are as follows:    Year  X            log Y    1994  -1           2.1387 + (0.0678) (-1) = 2.0709    1995  0            2.1387 + (0.0678) (0) = 2.1387    1996  1            2.1387 + (0.0678) (1) = 2.2065    1997  2            2.1387 + (0.0678) (2) = 2.2743    1998  3 2.1387 + (0.0678) (3) = 2.3421  Year  Trend values    1994  Antilog (2.0709) = 117.7    1995  Antilog (2.1387) = 137.6    1996  Antilog (2.2065) = 160.9    1997  Antilog (2.2743) = 188.0    1998  Antilog (2.3421) = 219.9    Problem 6: Use the method of moving averages (three yearly) to determine the trend in the    following series showing the index numbers for values of imports into India during 1914-1928.    87, 62, 47, 24, 45, 57, 96, 97, 84, 79, 77, 80, 92, 106, and 113.              CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                 367    Solution:           Year           Index                    Three-          Three-yearly                         No.                  yearly Total  Moving Total Average           1914            87                                                         i         1915            62                       196 65.33         1916            47                       133 44.33         1917            24                       116 38.67         1918            45                       126 42.00         1919            57                       198 66.00         1920            96                       250 83.33         1921            97                       277 92.33         1922            84                       260 86.67         1923            79                       240 80.00         1924            77                       236 78.67         1925            80                       249 83.00         1926            92                       278 92.67         1927           106                       311 103.67         1928           113    Problem 7: Calculate the five-yearly moving averages of students studying in a commerce    college as shown by the following figures.    Year:                 1991 92 93 94 95 96 97 98 99 2000    No. of students:      332 317 357 392 402 405 410 427 405 438    Draw a graph to represent the moving averages.  Solution:           Year            No. of               Five-yearly        Five-yearly                        Students                  Total       Moving Average           1991           332                       1800        360.00         1992           317                       1873        374.60         1993           357                       1966        393.20         1994           392                       2036        407.20         1995           402                       2049        409.80         1996           405                       2085        417.00         1997           410         1998           427         1999           405         2000           438                          CU IDOL SELF LEARNING MATERIAL (SLM)
368 Business Mathematics and Statistics          Problem 8: The following table shows the yearly available supplies of all cereals per adult  equivalent of population in India for a number of years. Draw a graph to represent the data:    Year:             1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992  Supplies in Kg.:  214 208 204 204 190 203 195 180 191 176 178 179          Calculate three-year moving averages and plot them on the same chart. What is the deviation  of the actual value from the moving average for the year 19867          Solutions:     Year             Supply  Three Yearly                    Three Yearly                                 Total                    Moving Average  1981               214  1982               208           626                          208.67  1983               204           616                          205.33  1984               204           598                          199.33  1985               190           597                          199.00  1986               203           588                          196.00  1987               195           578                          192.67  1988               180           566                          188.67  1989               191           547                          182.33  1990               176           545                          181.67  1991               178           533                          177.67  1992               179                      CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                    369    Problem 9: Calculate four-yearly moving averages for the following data:    Year                     Bank     Four Yearly     Two Yearly              Four Yearly                        Clearances       Total      Total of Four             Moving                                      Yearly Totals      Average    1986                  53                       0     00                                                    564 70.500  1987                  79 274                      595 74.375                                                    639 79.875  1988                  76 290                      689 86.125                                                    720 90.000  1989                  66 305    1990                  69 334    1991                  94 355    1992 105 365    1993                  87    1994                  79    Problem 10: Calculate five-yearly moving averages for the following time series:    Year:                 1           2345678                                                9  Annual figure:        78          67 107 142 152 155 160 177                            155          Year                        Annual Fig.     Five Yearly              Five Yearly                                                        Total             Moving Average           1                             78           2                             67         546 109.2           3                           107          623 124.6           4                           142          716 143.2           5                           152          786 157.2           6                           155          799 159.8           7                           160           8                           177           9                           155                                      CU IDOL SELF LEARNING MATERIAL (SLM)
370 Business Mathematics and Statistics          Problem 11: Calculate four-yearly centered moving averages for the production in million  tonnes for the following data.          Year  Production      Five-yearly    Fived-yearly                                  Total    Moving Average          1990              65               316 63.2        1991              62               319 63.8        1992              61               320 64        1993              63               326 65.2        1994              65               323 64.6        1995              68               317 63.4        1996              63        1997              67        1998              60        1999              59    Solution:    Year        Production      Four-yearly  Two-yearly total     Four-yearly                                  Total              of           Moving                                                                  Average                                           Four-yearly Total    1990        68                           505 63.125  1991        62 254                       508 63.500  1992        61 251                       651 64.500  1993        63 259                       621 65.250  1994        65 263                       521 65.250  1995        68 258                       507 63.375  1996        63 258  1997        67 249  1998  1999        60                59                            CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                   371    Problem 12: Fit a straight line trend by the method of least squares to the following data:    X (Years):            1991     1992  1993  1994               1995   1996        1997  (Production):          80,      90    92    83                 94     99          92    Years                       X        Y                 XY                  X2    1991                         1 80                         80                  1  1992                         2 90                       180                   4  1993                         3 92                       276                   9  1994                         4 83                       332                 16  1995                         5 94                       470                 25  1996                         6 99                       594                 36  1997                         7 92                       644                 49                                28 630                     2576                140    Substituting the values N = 7, 6Y = 630, 6X = 28 in the two normal equations:    we get 630 = 7a + 28b                                                                  (1)       i.e., 90 = a + 4b ...      2576 = 28a + 140b                                                                    (2)  i.e., 92 = a + 5b...  Subtracting (1) from (2) we get    b = 2 and a = 90 - 4b = 90 - 8 = 82  The equation to the line of the best fit: Y = 82 + 2x          By putting X= 1, 2, 3, 4, 5, 6, 7 in the equation we obtain trend values 84, 86, 88, 90, 92, 92,  94, 96 respectively.          x = 1, Y = 82 + 2 = 84        x = 12 Y = 82 + 4 = 86        x = 3, Y = 82 + 6 = 88        x = 4, Y = 82 + 8 = 90        x = 5, Y = 82 + 10 = 92        x = 6, Y = 82 + 12 = 94        x = 7, y = 82 + 14 = 9 6                                   CU IDOL SELF LEARNING MATERIAL (SLM)
372 Business Mathematics and Statistics    Problem 13: The following are the annual profits in thousands of rupees of a certain business.    Year:                           1991 1992 1993 1994 1995 1996 1997    Profit in thousands of rupees:  60 72 71 65 80 85 95          Use the method of least squares to fit a straight line to the above data. Plot the above figures  and draw the line. Also make an estimate of the profits ~ 1998.          Solution: Let the equation to the line of best fit be Y = a + sx, where Y represents profits in  thousands of rupees and X the years. To find the values of the constants a and b we prepare the  following table:    Year Y X XY X2    1991 60 -3 -180                                                       9                                                                        4  1992 72 -2 -144                                                       1                                                                        0  1993 75 -1 -75                                                        1                                                                        4  1994                 65               0             0                 9    1995                 80               1 80    1996                 85               2 170    1997                 95               3 285    Total           528                   0 136                           28    From the table, we have N = 5, 6X2 = 28, 6Y = 528, 6XY = 136.  Substituting these values in the two simplified equations we get:           ¦Y 532         a= N      = 76               7    And,                ¦XY 136          b = ¦X2 28 = 4.86    Therefore the equation to the line of best fit is:           = 76 + 4.86X    By putting, X = -3, -2, -1, 0, +1, +2, +3 in this equation, we get the trend values as follows:    61.42, 66.28, 71.14, 76.00, 80.86, 85.72, 90.58.    Putting X = -3, y = 76 + (4.86) (-3)           = 76 - 14.58           = 61.42                                    CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                          373          Putting X = -2, Y = 76 + (4.86) (-2)                       = 76 - 9.72                       = 66.28          Putting X = -1, y = 76 + (4.86) (-1)                       = 76 - 4.86                       = 71.14          Putting X = 0, y = 76 + (4.86) (0)                       = 76.00          Putting X = 1, y = 76 + (4.86) (1)                       = 80.86          Putting X = 2, y = 76 + (4.86) (2)                       = 76 + 9.7285.72          Putting X = 3, y = 76 + (4.86) (3)                       = 76 + 14.58                       = 90.58          By putting X = 4, we the profits for 1958 are:                       = 76 + (4.86) (4)                       = 76+19.44                       = 95.44          Profits for 1998 = ` 95.44 (in thousands)        Problem 14: Given below are the production figures (in thousand maunds) of a sugar factory.  Obtain the secular trend by fitting a straight line.    Year:                 1990  1991  1992  1993            1994      1995  1996  Production:            12    10    14    11              13        15    16    Also plot the trend values to indicate the trend line.                                CU IDOL SELF LEARNING MATERIAL (SLM)
374 Business Mathematics and Statistics    Solution: Let the equation to the line of best fit be Y = a + bX where Y represents the sugar    production in thousand maunds. To find the values of the constants a and b we prepare the following    table. In this table, X stands for the deviation of the years from 1993.    Year           Y    X XY                                                  X2    1990           12   -3 36                                                  9  1991           10   -2 -20                                                 4  1992           14   -1 -14                                                 1  1993           11                                                          0  1994           13    00                                                    1  1995           15   +1 +13                                                 4  1996           16   +2 +30                                                 9                      +3 +41                 91                                                         28                       0 21    From the table, we have N = 7, 6X2 = 28, 6Y = 91, 6XY = 21.    Substituting these values in the two simplified equation we get:         ¦Y 21  a = N 31 = 13    And,         ¦XY 21  b = ¦X 2 28 = 0.75    Therefore the equation to the line of best fit is:  Y = 13 + 0.75X  By putting X = -3, -2, -1, 0, +1, + 2, +3 in this equation, we get the following trend values:  10.75, 11.50, 12.25, 13.00, 13.75, 14.50, 15.25.  These trend values may be plotted on the graph and the line of best fit may be drawn.    16.6 Summary          An orderly set of numbers written in the order corresponding to time is called a time series.  For instance, a series of terms showing the profits of a business concern over a number of years is  a time series because the terms of series representing profits are written in relation to time. A                        CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                        375    careful scrutiny of a time series along with a detailed analysis of condition in the past enables one to  forecast future changes and estimates.    The following is a time series showing the production of cereals in India in million tonnes.                                  Net Production (million tonnes)* of Cereals in India                          Year  Production                          1951  40.01                        1952  40.59                        1953  45.36                        1954  53.44                        1955  51.59                        1956  50.33                        1957  52.67                        1958  49.35                        1959  57.29                        1960  56.76                        1961  60.66                        1962  62.08                        1963  58.43          A detailed analysis of the above time series enables us to find the different types of movements  influencing its course.             1. General Trend             2. Seasonal Changes             3. Cyclical Fluctuations             4. Irregular Variations           1. General Trend: The time series of the net productions of cereals in India shows that                 there is certainly a gradual increase in the production of cereals even though the increase               is not regular. This gradual increase is called the “General Trend” or secular trend.           2. Seasonal Fluctuations: Eliminating seasonal influences is no easy task. The occurrence               of seasons is responsible for these fluctuations. Natural phenomena are always               unavoidable beyond any measure of control.                          CU IDOL SELF LEARNING MATERIAL (SLM)
376 Business Mathematics and Statistics             3. Cyclical Fluctuations: These are due to the occurrence of business or trade cycles in               the economic world. For instance; there may be a period of depression followed by a               boom after a few years.             4. Irregular Variations: In many time series of economic data, we observe sudden upward               or downward movements in the trend. Such movements are irregular and are brought               about by unforeseen events and sudden changes in economic activities and business               conditions.          A general trend can be measured by the following methods:          A. Graphical method-freehand curve.          B. Method of moving averages.          C. Method of least squares.          Graphical Method: This method consists in drawing the curve of the time series on graph  paper.          Method of Moving Averages: Moving Averages are calculated on the basis of a given period,  such as, 3-yearly or 4-yearly or 5-yearly.          Method of Least Squares: Instead of drawing an observation-trend-line for a time series  freehand, it is better to fit a straight line trend more accurately using the mathematical method of  least squares. This straight line so drawn is called the ‘Line of Best Fit’.          If the equation to the line of best fit is written as Y = a + bx, then the values of the constants a  and b are determined by using the following two normal equations:              6Y = Na + b6x          6XY = a6X + b6x2  Where                   X represents the year (time).                 Y represents the actual values of the terms in the series.                 N is the number of terms in the time series.        The graph that represents a time series is called a ‘Historigram’. It is so called, simply because  it represents a historical series which is another name for a time series.                                                           CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                          377          Parabolic Trend Method: The straight line trend shows the increase or decrease in a time  series by a constant amount. However, in certain cases the straight line trend may not be adequate  and appropriate. In such a case the trend is indicated by a non linear curve and not by a straight line.          The equation of the parabola is given by              Y = a + bX + CX2          where the values of a, b, and c can be determined by solving the following normal equations:            6Y = Na + b6x + c6X2            6XY = b6x + b6x2 + c6X2         6X2Y = a6X2+ b6X3 + c6X4        When trends are plotted on a semi-logarithmic chart and arc represented by a non-linear  curve, then an upward curve would indicate the increase at different rates. The rate of ioncrease  depends on the slope-steeper the slope, higher the rate of increase. Using the logarithmic procedure  we can calculate the exponential trends.    16.7 Key Words/Abbreviations          General trend, Seasonal, Cyclical, Irregular, Variation, Fluctuation, Moving Averages, Least  Sequences Method.    16.8 Learning Activity    1. Calculate five-yearly moving averages of students in a commerce college as shown by    the following figures:                          Year  No. of Students                          1 1402                        2 1405                        3 1410                        4 1427                        s 1405                        6 1438                        7 1445                        8 1447                            CU IDOL SELF LEARNING MATERIAL (SLM)
378 Business Mathematics and Statistics    9 1480  10 1482  11 1482  12 1500    2. The following are the index numbers of annual production of a certain commodity.    Assuming a five-yearly cycle, find the trend values.    Year  Production    1991  325  1992  310  1993  301,  1994  315  1995  323  1996  345  1997  335  1998  325  1999  333  2000  349  2001  365    3. Draw a graph to represent the following data showing the number of students in a      college:    Year  No. of Students    1985  705  1986  685  1987  703  1988  687  1989  705  1990  689  1991  715  1992  685  1993  725  1994  751    Calculate the five-yearly moving averages of the above data and plot them on the same  chart.    CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                                    379    4. The following series relate to the profits of a commercial concern for eight years.                          Year   Profits (`)                          1995   15420                        1996   14470                        1997   15520                        1998   21020                        1999   26120                        2000   31950                        2001   35370                        2002   35670    Find the trend of profits. Assume a three year cycle and ignore decimals.    5. Find the trend of bank clearances by moving averages (assume a five-yearly cycle).                          Years  Bank Clearances                                  (` in crores)                          yI 53                        y2 79                        y3 76                        y4 66                        y5 69                        y6 94                        y7 105                        y8 87                        y9 79                        y10 104                        y11 97                        y12 92                        y13 101    16.9 Unit End Questions (MCQ and Descriptive)    A. Descriptive Type: Short Answer Type Questions           1. Explain clearly what is meant by time series analysis. Indicate fully the importance of               such analysis in business.                          CU IDOL SELF LEARNING MATERIAL (SLM)
380 Business Mathematics and Statistics    2. Describe the various types of fluctuations influencing a time series. Indicate fully the      procedure of estimating the secular trend.    3. Explain what is meant by long term trend of a time series. Use the method of moving      averages (three-yearly) to determine the trend in the following series showing index      numbers for values of imports into India during 1984-1998.    87, 62, 47, 24, 45, 57, 96, 97, 84, 79, 77, 80, 92, 106 and 113.    4. What are the components of a time series? Explain the importance of the moving average      method in the analysis of time series.    5. Distinguish between regular and irregular fluctuations in a time series.    6. Distinguish between seasonal variations and cyclical fluctuations.  7. Explain how a “growth factor”, a “decline factor”, a “seasonal factor II and a “cyclical        factor” affect a variable over a period of time.  8. Write a short essay on “Components of a Time Series”.    9. Explain the meaning and use of a moving average.    10. Discuss the different methods of determining secular trend in a time series with their        relative merits and demerits.    11. Write a note on Trend in a Time Series’.    12. Discuss any two methods of determining the secular trend in a time series with their        merits and demerits.    13. What is a “historical series”? What are its main components? Discuss briefly anyone        method of determining the general trend present in a given historical series.    14. Calculate the five-yearly moving averages of students in a commerce college as shown    by the following figures.    Year                       No. of Students    1 402  2 405  3 410  4 427  5 405          CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                        381                                   6 438                                 7 445                                 8 447                                 9 480                               10 482                                11 482                               12 500    15. Explain the “moving averages method II to find the secular trend in a time series. Mention          its uses and limitations.    16. (a) What is a time series? What is meant by the analysis of time series? Discuss the              practical utility of the analysis of a time series.    (b) The following are the index numbers of the annual production of a certain        commodity. Assuming a five-yearly cycle, find the trend values.                          Year  Index Num                          1991  225                        1992  210                        1993  201                        1994  215                        1995  223                        1996  245                        1997  235                        1998  225                        1999  233                        2000  249                        2001  265    17. Explain the method of moving averages in finding the trend in a time series data.  18. What is a “secular trend”? State the important method of finding the secular trend,          explaining in detail anyone of them.    19. (a) What is a time series? State the various components of a time series? What is the              purpose of such an analysis?         (b) Determine the trend component for the following time series using the five-yearly              moving averages.                          CU IDOL SELF LEARNING MATERIAL (SLM)
382 Business Mathematics and Statistics    Year  Index Number           (in lakh)  1988  1989         80  1990         79  1991         98  1992         77  1993         64  1994         51  1995         50  1996         54  1997         53  1998         61  1999         123  2000         119  2001         120               98    20. Calculate four-yearly centered moving averages production in million pounds for the        following data:    Year  Prod    1990  68  1991  62  1992  61  1993  63  1994  65  1995  68  1996  63  1997  67  1998  60  1999  59    CU IDOL SELF LEARNING MATERIAL (SLM)
Time Series Analysis                                                    383    B. Multiple Choice/Objective Type Questions:    1. A time series is also called __________.    (a) Value series                                 (b) Historical series    (c) biographical series                          (d) None of these.    2. General Trend in a time series is also called _____________.    (a) Secular Trend                                (b) Fine Trend    (c) Peculiar Trend                               (d) None of these    3. The graph that represent a time series is called a __________.    (a) Biographical                                 (b) Historical    (c) Historigram                                  (d) All the above    4. Parabolic Trend method is the straight line trend shows the increase or decrease in a      time series by __________ amount.    (a) Varying                                      (b) Constant                  (c) Recurring                      (d) All the above  Answers:                 (1) (b); (2) (a); (3) (c); (4) (b)    16.10 References    References of this unit have been given at the end of the book.                                                                               CU IDOL SELF LEARNING MATERIAL (SLM)
384 Business Mathematics and Statistics                                                REFERENCES     1. Dr. A.B. Rao, “Business Mathematics”, Himalaya Publishing House Pvt. Ltd.     2. Dr. A.B. Rao, “Business Statistics”, Himalaya Publishing House Pvt. Ltd.     3. Dr. A.B. Rao, “Decision-making”, Himalaya Publishing House Pvt. Ltd.     4. Dr. A.B. Rao, “Operation Research”, Jaico Publishing House Pvt. Ltd.     5. Dr. A.B. Rao, “Quantitative Techniques in Business”, Jaico Publishing House Pvt. Ltd.     6. Lenin Jothi, “Business Mathematics”, Himalaya Publishing House Pvt. Ltd., Mumbai.     7. http://data.conferenceworld.in/SGTB/P726-729.pdf     8. https://www.inc.com/encyclopedia/annuities.html     9. https://blog.myrank.co.in/combination-properties-of-%E2%81%BFcr/    10. https://blog.myrank.co.in/applications-of-permutation-and-combination/    11. https://www.hindawi.com/journals/mpe/2010/723402/                                                                                                      CU IDOL SELF LEARNING MATERIAL (SLM)
                                
                                
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