Nitrogen Oven Turbine Generator - Machinery and Measurements

Nitrogen Oven Turbine Generator Machinery and measurements

Project Machinery As the power of nitrogen turbine takes its strength from heat exchange dramatically, the machinery of the project has to obtain the relationship between cold slow layer of the air effected by the conducting of liquid nitrogen pass via the pipes on the top and the hot light fast separated layer of the air in the bottom. The molecules inside the isothermal system behaves as the physical rules commands, it acts in balance to keep the system stable by changing heat transfer in the whole process. And as a first rule of the thermodynamic says “energy can neither be created nor destroyed, only altered in form”.

Air as fluid Liquid Nitrogen Air is an object with a little thermal Hot Plate Cross sectional area conductivity equal to (26.24W/m-k) and when we mention the thermodynamic actions for the molecules we have to notice the air layers mobility inside the model. If we take a look on (layer A) – the first layer of the air combine the coldest and hottest layers in the right side of the system, we should obtain the major thermodynamic heat transfer between layers which guide us to the strength of the thermodynamics of molecules. In the second layer – (layer B)- the cold air is begin to shrink where the hot air takes place to get the command of the thermodynamic moves for molecules and is still good and strong. On the layer C – the last layer of the air -the hot air here is the commander and the thermodynamic move gone to be weaker than before

Heat Transfer As we mentioned in the previous brief the heat transfer on the one layer of the air should be measured as : Item Value Constant Note/Reference Thermal 26.24W/m-k yes no https://cutt.us/1tap1 conductivity 0.1561 cm2 Web calculator Cross sectional √ 250 ℃ https://cutt.us/X2Con area -190 ℃ √ Web calculator Temp. hot side 15 sec. Should be tested 0.025m √ Temp. cold side √ Should be tested √ Time taken √ predicted Thickness of Calculated material (layer of the air)

The Heat Transfer Calculation In Whole System The heat transfer for one layer in whole system is equal to 106272 Joules = 106.272KJ. If we divide the whole space on three layers , the whole system should produce an energy equal to : 106.272KJ * 3 layers = 318.816 KJ Scan Me

Liquid Nitrogen - Mobile Phase Movement Studying liquid nitrogen mobility through the pipes is very important in the model. The density of nitrogen is vary due to the effectiveness of heat transfer between the layers of air which affects the phase, density ,mobility , velocity in pipes ,volumetric flow and mass flow which is very essential to calculate the rate of flow. Source

Prototype Machinery and Measurements Stage 1 As shown in the prototype We are going to pour the liquid nitrogen and Being sure about the thermodynamic moves and heat transfer. Stage 2 we are going to Install the pump and Cryogenic cooler and nitrogen membrane to Close the circle.

The Complete Project Machinery and Measurements Stage 1 As shown in the prototype We are going to pour the liquid nitrogen and Being sure about the thermodynamic moves and heat transfer. Stage 2 we are going to Install the pump and Cryogenic cooler and nitrogen membrane to Close the circle.

Scan Me Watts Calculation As we mentioned previously the whole space on three layers should presents the whole system energy. The whole system should produce an energy equal to : 106.272KJ * 3 layers = 318.816 KJ Watts equal to Joules divided by time : The electrical ability of the machine should calculated: Watts= 318.816KJ/15sec = 21254.4W/s Which equal to 21.254.4 KW/s