100-de-thi-hoc-sinh-gioi-mon-toan-lop-5

["C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 L\u1ea5y A chia cho K: 72 : 9 = L\u1ea5y G chia cho C: 8 : 1 = L\u1ea5y B chia cho H: 16 : 2 = L\u1ea5y E chia cho D: 24 : 3 = \u0111\u1ec1u cho c\u00f9ng m\u1ed9t k\u1ebft qu\u1ea3 \u1edf \u00f4 \u0110. V\u1eady (?) l\u00e0 8. B\u00e0i 97: C\u00f4 gi\u00e1o y\u00eau c\u1ea7u: \u201cC\u00e1c con l\u1ea5y 6 \u0111i\u1ec3m tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng tr\u00f2n, n\u1ed1i c\u00e1c \u0111i\u1ec3m \u0111\u00f3 b\u1edfi c\u00e1c \u0111o\u1ea1n th\u1eb3ng t\u00f4 b\u1edfi m\u1ef1c xanh ho\u1eb7c m\u1ef1c \u0111\u1ecf\u201d. B\u1ea1n l\u1edbp tr\u01b0\u1edfng t\u1eadp h\u1ee3p c\u00e1c h\u00ecnh v\u1ebd l\u1ea1i v\u00e0 xem, b\u1ea1n th\u1ed1t l\u00ean: \u201cB\u1ea1n n\u00e0o c\u0169ng v\u1ebd \u0111\u01b0\u1ee3c 1 tam gi\u00e1c m\u00e0 3 c\u1ea1nh c\u00f9ng m\u00e0u m\u1ef1c\u201d! B\u1ea1n h\u00e3y th\u1eed l\u00e0m l\u1ea1i xem. Ai c\u00f3 th\u1ec3 l\u1eadp lu\u1eadn \u0111\u1ec3 l\u00e0m r\u00f5 t\u00ednh ch\u1ea5t n\u00e0y? B\u00e0i gi\u1ea3i: C\u00f3 nhi\u1ec1u c\u00e1ch gi\u1ea3i, \u0111\u00e2y l\u00e0 m\u1ed9t trong c\u00e1c c\u00e1ch gi\u1ea3i b\u00e0i n\u00e0y: Ta g\u1ecdi 6 \u0111i\u1ec3m n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n l\u00e0 A1, A2, A3, A4, A5, A6. B\u1eb1ng b\u00fat xanh v\u00e0 \u0111\u1ecf ta n\u1ed1i A1 v\u1edbi 5 \u0111i\u1ec3m c\u00f2n l\u1ea1i ta \u0111\u01b0\u1ee3c 5 \u0111o\u1ea1n th\u1eb3ng c\u00f3 hai m\u00e0u xanh ho\u1eb7c \u0111\u1ecf. Theo nguy\u00ean l\u00fd \u0110ir\u00edchl\u00ea c\u00f3 \u00edt nh\u1ea5t 3 \u0111o\u1ea1n th\u1eb3ng c\u00f9ng m\u00e0u. Kh\u00f4ng l\u00e0m m\u1ea5t t\u00ednh t\u1ed5ng qu\u00e1t, ta n\u1ed1i 3 \u0111o\u1ea1n A1A2, A1A3, A1A4 b\u1eb1ng b\u00fat m\u00e0u \u0111\u1ecf. Ta n\u1ed1i ti\u1ebfp A2A4 v\u00e0 A2A3. \u0110\u1ec3 tam gi\u00e1c A1A2A3 v\u00e0 tam gi\u00e1c A1A2A4 c\u00f3 3 c\u1ea1nh kh\u00f4ng c\u00f9ng m\u00e0u th\u00ec A2A4 v\u00e0 A2A3 ph\u1ea3i t\u00f4 m\u00e0u xanh. B\u00e2y gi\u1edd ta ti\u1ebfp t\u1ee5c n\u1ed1i A3A4, ta th\u1ea5y A3A4 \u0111\u01b0\u1ee3c t\u00f4 b\u1eb1ng b\u1ea5t k\u1ef3 m\u00e0u xanh ho\u1eb7c \u0111\u1ecf th\u00ec ta c\u0169ng \u0111\u01b0\u1ee3c \u00edt nh\u1ea5t m\u1ed9t tam gi\u00e1c c\u00f3 3 c\u1ea1nh c\u00f9ng m\u00e0u (ho\u1eb7c A1A3A4 c\u00f3 3 c\u1ea1nh \u0111\u1ecf ho\u1eb7c A2A3A4 c\u00f3 3 c\u1ea1nh m\u00e0u xanh). B\u00e0i 98: Thi b\u1eafn s\u00fang H\u00f4m nay D\u0169ng \u0111i thi b\u1eafn s\u00fang. D\u0169ng b\u1eafn gi\u1ecfi l\u1eafm, D\u0169ng \u0111\u00e3 b\u1eafn h\u01a1n 11 vi\u00ean, vi\u00ean n\u00e0o 101","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 c\u0169ng tr\u00fang bia v\u00e0 \u0111\u1ec1u tr\u00fang c\u00e1c v\u00f2ng 8;9;10 \u0111i\u1ec3m. K\u1ebft th\u00fac cu\u1ed9c thi, D\u0169ng \u0111\u01b0\u1ee3c 100 \u0111i\u1ec3m. D\u0169ng vui l\u1eafm. C\u00f2n c\u00e1c b\u1ea1n c\u00f3 bi\u1ebft D\u0169ng \u0111\u00e3 b\u1eafn bao nhi\u00eau vi\u00ean v\u00e0 k\u1ebft qu\u1ea3 b\u1eafn v\u00e0o c\u00e1c v\u00f2ng ra sao kh\u00f4ng? B\u00e0i gi\u1ea3i: S\u1ed1 vi\u00ean \u0111\u1ea1n D\u0169ng \u0111\u00e3 b\u1eafn ph\u1ea3i \u00edt h\u01a1n 13 vi\u00ean (v\u00ec n\u1ebfu D\u0169ng b\u1eafn 13 vi\u00ean th\u00ec D\u0169ng \u0111\u01b0\u1ee3c s\u1ed1 \u0111i\u1ec3m \u00edt nh\u1ea5t l\u00e0: 8 x 11 + 9 x 1 + 10 x 1 = 107 (\u0111i\u1ec3m) > 100 \u0111i\u1ec3m, \u0111i\u1ec1u n\u00e0y v\u00f4 l\u00fd). Theo \u0111\u1ec1 b\u00e0i D\u0169ng \u0111\u00e3 b\u1eafn h\u01a1n 11 vi\u00ean n\u00ean s\u1ed1 vi\u00ean \u0111\u1ea1n D\u0169ng \u0111\u00e3 b\u1eafn l\u00e0 12 vi\u00ean. M\u1eb7t kh\u00e1c 12 vi\u00ean \u0111\u1ec1u tr\u00fang v\u00e0o c\u00e1c v\u00f2ng 8, 9, 10 \u0111i\u1ec3m n\u00ean \u00edt nh\u1ea5t c\u00f3 10 vi\u00ean v\u00e0o v\u00f2ng 8 \u0111i\u1ec3m, 1 vi\u00ean v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m, 1 vi\u00ean v\u00e0o v\u00f2ng 10 \u0111i\u1ec3m. Do \u0111\u00f3 s\u1ed1 \u0111i\u1ec3m D\u0169ng b\u1eafn \u0111\u01b0\u1ee3c \u00edt nh\u1ea5t l\u00e0: 8 x 10 + 9 x 1 + 10 x 1 = 99 (\u0111i\u1ec3m) S\u1ed1 \u0111i\u1ec3m h\u1ee5t \u0111i so v\u1edbi th\u1ef1c t\u1ebf l\u00e0: 100 - 99 = 1 (\u0111i\u1ec3m) Nh\u01b0 v\u1eady s\u1ebd c\u00f3 1 vi\u00ean kh\u00f4ng b\u1eafn v\u00e0o v\u00f2ng 8 \u0111i\u1ec3m m\u00e0 b\u1eafn v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m; ho\u1eb7c c\u00f3 1 vi\u00ean kh\u00f4ng b\u1eafn v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m m\u00e0 b\u1eafn v\u00e0o v\u00f2ng 10 \u0111i\u1ec3m. N\u1ebfu c\u00f3 1 vi\u00ean D\u0169ng kh\u00f4ng b\u1eafn v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m m\u00e0 b\u1eafn v\u00e0o v\u00f2ng 10 \u0111i\u1ec3m th\u00ec t\u1ed5ng c\u1ed9ng s\u1ebd c\u00f3 10 vi\u00ean v\u00e0o v\u00f2ng 8 \u0111i\u1ec3m v\u00e0 2 vi\u00ean v\u00e0o v\u00f2ng 10 \u0111i\u1ec3m (lo\u1ea1i v\u00ec kh\u00f4ng c\u00f3 vi\u00ean n\u00e0o b\u1eafn v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m). V\u1eady s\u1ebd c\u00f3 1 vi\u00ean kh\u00f4ng b\u1eafn v\u00e0o v\u00f2ng 8 \u0111i\u1ec3m m\u00e0 b\u1eafn v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m, t\u1ee9c l\u00e0 c\u00f3 9 vi\u00ean v\u00e0o v\u00f2ng 8 \u0111i\u1ec3m, 2 vi\u00ean v\u00e0o v\u00f2ng 9 \u0111i\u1ec3m v\u00e0 1 vi\u00ean v\u00e0o v\u00f2ng 10 \u0111i\u1ec3m. B\u00e0i 99: Ai xem ca nh\u1ea1c? M\u1ed9t gia \u0111\u00ecnh c\u00f3 n\u0103m ng\u01b0\u1eddi: b\u00e0 n\u1ed9i, b\u1ed1, m\u1eb9 v\u00e0 hai b\u1ea1n Chi, B\u1ea3o. M\u1ed9t h\u00f4m gia \u0111\u00ecnh \u0111\u01b0\u1ee3c t\u1eb7ng 2 v\u00e9 m\u1eddi xem ca nh\u1ea1c. N\u0103m \u00fd ki\u1ebfn c\u1ee7a n\u0103m ng\u01b0\u1eddi nh\u01b0 sau: a) \u201cB\u00e0 n\u1ed9i v\u00e0 m\u1eb9 \u0111i\u201d b) \u201cB\u1ed1 v\u00e0 m\u1eb9 \u0111i\u201d c) \u201cB\u1ed1 v\u00e0 b\u00e0 n\u1ed9i \u0111i\u201d d) \u201cB\u00e0 n\u1ed9i v\u00e0 Chi \u0111i\u201d 102","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 e) \u201cB\u1ed1 v\u00e0 B\u1ea3o \u0111i\u201d Sau c\u00f9ng, m\u1ecdi ng\u01b0\u1eddi theo \u00fd ki\u1ebfn c\u1ee7a b\u00e0 n\u1ed9i v\u00e0 nh\u01b0 v\u1eady trong \u00fd ki\u1ebfn c\u1ee7a m\u1ecdi ng\u01b0\u1eddi kh\u00e1c \u0111\u1ec1u c\u00f3 m\u1ed9t ph\u1ea7n \u0111\u00fang. B\u00e0 n\u1ed9i \u0111\u00e3 n\u00f3i c\u00e2u n\u00e0o? B\u00e0i gi\u1ea3i: M\u1ed9t b\u00e0i to\u00e1n l\u00f4g\u00edc c\u01a1 b\u1ea3n v\u00e0 kh\u00f3, sau \u0111\u00e2y l\u00e0 l\u1eddi gi\u1ea3i. Ta k\u00fd hi\u1ec7u theo th\u1ee9 t\u1ef1 \u201c\u0111i xem\u201d ca nh\u1ea1c: n (B\u00e0 n\u1ed9i), m (m\u1eb9), b (B\u1ed1), C (Chi) v\u00e0 B (B\u1ea3o) v\u00e0 n\u0103m ng\u01b0\u1eddi tr\u00ean khi h\u1ecd \u201ckh\u00f4ng \u0111i\u201d l\u00e0 n, m, b, C v\u00e0 B. Nh\u01b0 v\u1eady theo \u00fd ki\u1ebfn c\u1ee7a n\u0103m ng\u01b0\u1eddi l\u00e0: a) n v\u00e0 m b) b v\u00e0 m c) b v\u00e0 n d) n v\u00e0 C e) b v\u00e0 B. C\u00f3 l\u1ebd c\u1ea7n ph\u1ea3i nh\u1ea5n m\u1ea1nh r\u1eb1ng: M\u1ed7i trong n\u0103m \u00fd tr\u00ean \u0111\u1ec1u c\u00f3 m\u1ed9t ph\u1ea7n \u0111\u00fang v\u00e0 m\u1ed9t ph\u1ea7n sai (tr\u1eeb \u00fd c\u1ee7a b\u00e0!). C\u00e2u m\u00e0 b\u00e0 n\u1ed9i n\u00f3i l\u00e0 \u0111\u00fang v\u1edbi c\u1ea3 n\u0103m \u00fd tr\u00ean. - N\u1ebfu ch\u1ecdn c\u00e2u a) th\u00ec kh\u00f4ng c\u00f3 e t\u1ee9c b v\u00e0 B. - N\u1ebfu ch\u1ecdn c\u00e2u b) th\u00ec kh\u00f4ng c\u00f3 d t\u1ee9c n v\u00e0 C. - N\u1ebfu ch\u1ecdn c\u00e2u c) th\u00ec c\u00e1c \u00fd ki\u1ebfn kh\u00e1c c\u00f3 m\u1ed9t ph\u1ea7n \u0111\u00fang. B\u00e0 n\u1ed9i \u0111\u00e3 n\u00f3i c\u00e2u c) N\u1ebfu h\u1ecdc sinh th\u00edch th\u00fa l\u00f4g\u00edc To\u00e1n th\u00ec c\u00f2n t\u00ecm th\u00eam \u0111\u01b0\u1ee3c nhi\u1ec1u c\u00e1ch gi\u1ea3i kh\u00e1c. B\u00e0i 100: Ch\u01a1i b\u1ed1c di\u00eam Tr\u00ean m\u1eb7t b\u00e0n c\u00f3 18 que di\u00eam. Hai ng\u01b0\u1eddi tham gia cu\u1ed9c ch\u01a1i: M\u1ed7i ng\u01b0\u1eddi l\u1ea7n l\u01b0\u1ee3t \u0111\u1ebfn phi\u00ean m\u00ecnh l\u1ea5y ra m\u1ed9t s\u1ed1 que di\u00eam. M\u1ed7i l\u1ea7n, m\u1ed7i ng\u01b0\u1eddi l\u1ea5y ra kh\u00f4ng qu\u00e1 4 que. Ng\u01b0\u1eddi n\u00e0o l\u1ea5y \u0111\u01b0\u1ee3c s\u1ed1 que cu\u1ed1i c\u00f9ng th\u00ec ng\u01b0\u1eddi \u0111\u00f3 th\u1eafng. N\u1ebfu b\u1ea1n \u0111\u01b0\u1ee3c b\u1ed1c tr\u01b0\u1edbc, b\u1ea1n c\u00f3 ch\u1eafc ch\u1eafn 103","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 th\u1eafng \u0111\u01b0\u1ee3c kh\u00f4ng? B\u00e0i gi\u1ea3i: Gi\u1ea3 s\u1eed r\u1eb1ng A v\u00e0 B tham gia cu\u1ed9c ch\u01a1i m\u00e0 A l\u1ea5y di\u00eam tr\u01b0\u1edbc. \u0110\u1ec3 ch\u1eafc th\u1eafng th\u00ec tr\u01b0\u1edbc l\u1ea7n cu\u1ed1i c\u00f9ng A ph\u1ea3i \u0111\u1ec3 l\u1ea1i 5 que di\u00eam, tr\u01b0\u1edbc \u0111\u00f3 A ph\u1ea3i \u0111\u1ec3 l\u1ea1i 10 que di\u00eam v\u00e0 l\u1ea7n b\u1ed1c \u0111\u1ea7u ti\u00ean A \u0111\u1ec3 l\u1ea1i 15 que di\u00eam, khi \u0111\u00f3 d\u00f9 B c\u00f3 b\u1ed1c bao nhi\u00eau que th\u00ec v\u1eabn c\u00f2n l\u1ea1i s\u1ed1 que \u0111\u1ec3 A ch\u1ec9 c\u1ea7n b\u1ed1c m\u1ed9t l\u1ea7n l\u00e0 h\u1ebft.Mu\u1ed1n v\u1eady th\u00ec l\u1ea7n tr\u01b0\u1edbc \u0111\u00f3 A ph\u1ea3i \u0111\u1ec3 l\u1ea1i 10 que di\u00eam , khi \u0111\u00f3 d\u00f9 B b\u1ed1c bao nhi\u00eau que v\u1eabn c\u00f2n l\u1ea1i s\u1ed1 que m\u00e0 A c\u00f3 th\u1ec3 b\u1ed1c \u0111\u1ec3 c\u00f2n l\u1ea1i 5 que . T\u01b0\u01a1ng t\u1ef1 nh\u01b0 th\u1ebf th\u00ec l\u1ea7n b\u1ed1c \u0111\u1ea7u ti\u00ean A ph\u1ea3i \u0111\u1ec3 l\u1ea1i 15 que di\u00eam . V\u1edbi \\\" chi\u1ebfn l\u01b0\u1ee3c\\\" n\u00e0y bao gi\u1edd A c\u0169ng l\u00e0 ng\u01b0\u1eddi th\u1eafng cu\u1ed9c. B\u00e0i 101: T\u00f4 m\u00e0u H\u00ecnh b\u00ean g\u1ed3m 6 \u0111\u1ec9nh A, B, C, D, E, F v\u00e0 c\u00e1c c\u1ea1nh n\u1ed1i m\u1ed9t s\u1ed1 \u0111\u1ec9nh v\u1edbi nhau. Ta t\u00f4 m\u00e0u c\u00e1c \u0111\u1ec9nh sao cho hai \u0111\u1ec9nh \u0111\u01b0\u1ee3c n\u1ed1i b\u1edfi m\u1ed9t c\u1ea1nh ph\u1ea3i \u0111\u01b0\u1ee3c t\u00f4 b\u1edfi hai m\u00e0u kh\u00e1c nhau. H\u1ecfi ph\u1ea3i c\u1ea7n \u00edt nh\u1ea5t l\u00e0 bao nhi\u00eau m\u00e0u \u0111\u1ec3 l\u00e0m vi\u1ec7c \u0111\u00f3? B\u00e0i gi\u1ea3i: T\u1ea5t c\u1ea3 c\u00e1c \u0111\u1ec9nh A, B, C, D, E \u0111\u1ec1u n\u1ed1i v\u1edbi \u0111\u1ec9nh F n\u00ean \u0111\u1ec9nh F ph\u1ea3i t\u00f4 m\u00e0u kh\u00e1c v\u1edbi c\u00e1c \u0111\u1ec9nh c\u00f2n l\u1ea1i. V\u1edbi 5 \u0111\u1ec9nh c\u00f2n l\u1ea1i th\u00ec A v\u00e0 C t\u00f4 c\u00f9ng m\u1ed9t m\u00e0u. B v\u00e0 D t\u00f4 c\u00f9ng m\u1ed9t m\u00e0u, E t\u00f4 ri\u00eang m\u1ed9t m\u00e0u, nh\u01b0 v\u1eady c\u1ea7n \u00edt nh\u1ea5t 3 m\u00e0u \u0111\u1ec3 t\u00f4 5 \u0111\u1ec9nh sao cho 2 \u0111\u1ec9nh \u0111\u01b0\u1ee3c n\u1ed1i b\u1edfi m\u1ed9t c\u1ea1nh \u0111\u01b0\u1ee3c t\u00f4 b\u1edfi 2 V\u1eady c\u1ea7n \u00edt nh\u1ea5t 4 m\u00e0u \u0111\u1ec3 t\u00f4 6 \u0111\u1ec9nh c\u1ee7a h\u00ecnh theo y\u00eau c\u1ea7u c\u1ee7a \u0111\u1ec1 b\u00e0i. m\u00e0u kh\u00e1c nhau. B\u00e0i 102: \u0110i\u1ec1n s\u1ed1 tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n \u0110i\u1ec1n 6 s\u1ed1 ch\u1eb5n t\u1eeb 2 \u0111\u1ebfn 12 v\u00e0o c\u00e1c ch\u1ea5m tr\u00ean 3 v\u00f2ng tr\u00f2n sao cho t\u1ed5ng 3 s\u1ed1 n\u1eb1m tr\u00ean m\u1ed7i v\u00f2ng tr\u00f2n \u0111\u1ec1u b\u1eb1ng 18. B\u00e0i gi\u1ea3i: S\u00e1u s\u1ed1 ch\u1eb5n \u0111\u00f3 l\u00e0: 2, 4, 6, 8, 10, 12. Ta c\u00f3: 18 = 2 + 4 + 12 18 = 2 + 6 + 10 18 = 4 + 6 + 8 104","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Tr\u00ean h\u00ecnh v\u1ebd ta th\u1ea5y c\u1ee9 hai \u0111\u01b0\u1eddng tr\u00f2n l\u1ea1i c\u00f3 m\u1ed9t \u0111i\u1ec3m chung. Nh\u01b0 v\u1eady s\u1ed1 n\u00e0o \u0111i\u1ec1n v\u00e0o \u0111i\u1ec3m chung \u0111\u00f3 s\u1ebd thu\u1ed9c hai t\u1ed5ng \u0111\u00e3 cho. Ta th\u1ea5y s\u1ed1 2, s\u1ed1 4, s\u1ed1 6 \u0111\u1ec1u l\u1eb7p l\u1ea1i hai l\u1ea7n n\u00ean ba s\u1ed1 \u0111\u00f3 \u0111\u01b0\u1ee3c \u0111i\u1ec1n v\u00e0o ba \u0111i\u1ec3m chung. C\u00e1c s\u1ed1 \u0111\u00e3 cho \u0111\u01b0\u1ee3c \u0111i\u1ec1n v\u00e0o h\u00ecnh v\u1ebd nh\u01b0 sau: B\u00e0i 103 : T\u00ecm hai s\u1ed1 bi\u1ebft r\u1eb1ng t\u1ed5ng c\u1ee7a ch\u00fang g\u1ea5p 5 l\u1ea7n hi\u1ec7u c\u1ee7a ch\u00fang v\u00e0 t\u00edch c\u1ee7a ch\u00fang g\u1ea5p 4008 l\u1ea7n hi\u1ec7u c\u1ee7a ch\u00fang. B\u00e0i gi\u1ea3i : Coi hi\u1ec7u c\u1ee7a hai s\u1ed1 l\u00e0 1 ph\u1ea7n th\u00ec t\u1ed5ng c\u1ee7a ch\u00fang l\u00e0 5 ph\u1ea7n. Do \u0111\u00f3 s\u1ed1 l\u1edbn l\u00e0 (5 + 1) : 2 = 3 (ph\u1ea7n). S\u1ed1 b\u00e9 l\u00e0 : 3 - 1 = 2 (ph\u1ea7n). T\u00edch c\u1ee7a hai s\u1ed1 l\u00e0 : 2 x 3 = 6 (ph\u1ea7n), m\u00e0 t\u00edch hai s\u1ed1 l\u00e0 4008 n\u00ean gi\u00e1 tr\u1ecb m\u1ed9t ph\u1ea7n l\u00e0 : 4008 : 6 = 668. S\u1ed1 b\u00e9 l\u00e0 : 668 x 2 = 1336 ; s\u1ed1 l\u1edbn l\u00e0 : 668 x 3 = 2004. B\u00e0i 104 : Trong kho c\u1ee7a m\u1ed9t \u0111\u01a1n v\u1ecb d\u00e2n c\u00f4ng c\u00f2n l\u1ea1i \u0111\u00fang m\u1ed9t bao g\u1ea1o ch\u1ee9a 39 kg g\u1ea1o. B\u00e1c c\u1ea5p d\u01b0\u1ee1ng c\u1ea7n l\u1ea5y ra 11\/13 s\u1ed1 g\u1ea1o \u0111\u00f3. H\u1ecfi ch\u1ec9 v\u1edbi m\u1ed9t chi\u1ebfc c\u00e2n lo\u1ea1i c\u00e2n \u0111\u0129a v\u00e0 m\u1ed9t qu\u1ea3 c\u00e2n 1 kg, b\u00e1c c\u1ea5p d\u01b0\u1ee1ng ph\u1ea3i l\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 ch\u1ec9 sau 3 l\u1ea7n c\u00e2n l\u1ea5y ra \u0111\u1ee7 s\u1ed1 g\u1ea1o c\u1ea7n d\u00f9ng. B\u00e0i gi\u1ea3i : S\u1ed1 g\u1ea1o b\u00e1c c\u1ea5p d\u01b0\u1ee1ng c\u1ea7n l\u1ea5y ra l\u00e0 : 39 x 11\/13 = 33 (kg) S\u1ed1 g\u1ea1o c\u00f2n l\u1ea1i sau khi b\u00e1c c\u1ea5p d\u01b0\u1ee1ng l\u1ea5y l\u00e0 : 39 - 33 = 6 (kg) C\u00e1ch th\u1ef1c hi\u1ec7n c\u00e2n nh\u01b0 sau : L\u1ea7n 1 : \u0110\u1eb7t qu\u1ea3 c\u00e2n l\u00ean m\u1ed9t \u0111\u0129a c\u00e2n, \u0111\u1ed5 g\u1ea1o v\u00e0o \u0111\u0129a c\u00e2n b\u00ean kia \u0111\u1ebfn khi c\u00e2n th\u0103ng b\u1eb1ng, \u0111\u01b0\u1ee3c 1 kg g\u1ea1o. L\u1ea7n 2 : \u0110\u1eb7t qu\u1ea3 c\u00e2n sang \u0111\u0129a c\u00f3 1 kg g\u1ea1o v\u1eeba c\u00e2n \u0111\u01b0\u1ee3c r\u1ed3i \u0111\u1ed5 g\u1ea1o v\u00e0o \u0111\u0129a c\u00e2n tr\u1ed1ng \u0111\u1ebfn khi c\u00e2n th\u0103ng b\u1eb1ng, \u0111\u01b0\u1ee3c 2 kg g\u1ea1o. L\u1ea7n 3 : \u0110\u1eb7t c\u1ea3 3 kg g\u1ea1o c\u00e2n \u0111\u01b0\u1ee3c \u1edf hai l\u1ea7n tr\u00ean v\u00e0o m\u1ed9t \u0111\u0129a c\u00e2n, \u0111\u0129a c\u00e2n kia \u0111\u1ed5 g\u1ea1o v\u00e0o cho \u0111\u1ebfn khi c\u00e2n th\u0103ng b\u1eb1ng, \u0111\u01b0\u1ee3c m\u1ed7i b\u00ean 3 kg g\u1ea1o. Nh\u01b0 v\u1eady s\u1ed1 g\u1ea1o c\u00f3 \u0111\u01b0\u1ee3c sau ba l\u1ea7n c\u00e2n l\u00e0 6 kg. S\u1ed1 g\u1ea1o c\u00f2n l\u1ea1i trong bao ch\u00ednh l\u00e0 s\u1ed1 g\u1ea1o m\u00e0 b\u00e1c c\u1ea5p d\u01b0\u1ee1ng c\u1ea7n d\u00f9ng. B\u00e0i 105 : Lan n\u00f3i m\u1ed9t s\u1ed1 c\u00f3 4 ch\u1eef s\u1ed1 b\u1ea5t k\u00ec s\u1ebd b\u1eb1ng 1\/5 s\u1ed1 vi\u1ebft theo th\u1ee9 t\u1ef1 ng\u01b0\u1ee3c l\u1ea1i. \u0110\u1ed1 b\u1ea1n bi\u1ebft Lan n\u00f3i \u0111\u00fang hay sai ? 105","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00e0i gi\u1ea3i : G\u1ecdi s\u1ed1 \u0111\u00f3 l\u00e0 (a > 0 ; a, b, c, d < 10). S\u1ed1 vi\u1ebft theo th\u1ee9 t\u1ef1 ng\u01b0\u1ee3c l\u1ea1i l\u00e0 Theo \u0111\u1ea7u b\u00e0i ta c\u00f3 : Nh\u01b0ng d x 5 c\u00f3 t\u1eadn c\u00f9ng l\u00e0 0 ho\u1eb7c 5 (kh\u00e1c 1) n\u00ean kh\u00f4ng t\u00ecm \u0111\u01b0\u1ee3c gi\u00e1 tr\u1ecb c\u1ee7a a ho\u1eb7c d. V\u1eady b\u1ea1n Lan n\u00f3i sai. B\u00e0i 106 : B\u00e1c Phong c\u00f3 m\u1ed9t m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt, chi\u1ec1u r\u1ed9ng m\u1ea3nh \u0111\u1ea5t d\u00e0i 8 m. B\u00e1c ng\u0103n m\u1ea3nh \u0111\u00f3 th\u00e0nh hai ph\u1ea7n, m\u1ed9t ph\u1ea7n \u0111\u1ec3 l\u00e0m nh\u00e0, ph\u1ea7n c\u00f2n l\u1ea1i \u0111\u1ec3 l\u00e0m v\u01b0\u1eddn. Di\u1ec7n t\u00edch ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 b\u1eb1ng 1\/2 di\u1ec7n t\u00edch m\u1ea3nh \u0111\u1ea5t c\u00f2n chu vi ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 b\u1eb1ng 2\/3 chu vi m\u1ea3nh \u0111\u1ea5t. T\u00ednh di\u1ec7n t\u00edch m\u1ea3nh \u0111\u1ea5t c\u1ee7a b\u00e1c. B\u00e0i gi\u1ea3i : C\u00f3 hai c\u00e1ch chia m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt th\u00e0nh hai ph\u1ea7n c\u00f3 di\u1ec7n t\u00edch b\u1eb1ng nhau. C\u00e1ch chia 1 : nh\u01b0 h\u00ecnh 1. H\u00ecnh 1 G\u1ecdi m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt l\u00e0 ABCD v\u00e0 ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 l\u00e0 AMND. V\u00ec di\u1ec7n t\u00edch ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 b\u1eb1ng n\u1eeda di\u1ec7n t\u00edch m\u1ea3nh \u0111\u1ea5t n\u00ean M, N l\u1ea7n l\u01b0\u1ee3t l\u00e0 \u0111i\u1ec3m ch\u00ednh gi\u1eefa c\u1ee7a AB v\u00e0 CD. Do \u0111\u00f3 AM = MB = CN = ND. Chu vi c\u1ee7a ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 l\u00e0 : (AM + AD) x 2 = (AM + 8) x 2 = = AM x 2 + 8 x 2 = AB + 16. Chu vi c\u1ee7a m\u1ea3nh \u0111\u1ea5t l\u00e0 : (AB + AD) 2 = (AB + 8) x 2 = = AB x 2 + 8 x 2 = AB x 2 + 16. Hi\u1ec7u chu vi m\u1ea3nh \u0111\u1ea5t v\u00e0 chu vi ph\u1ea7n \u0111\u1ea5t l\u00e0m nh\u00e0 l\u00e0 : (AB x 2 + 16) - (AB + 16) = AB. Hi\u1ec7u n\u00e0y so v\u1edbi chu vi m\u1ea3nh \u0111\u1ea5t th\u00ec chi\u1ebfm : 1 - 2\/3 = 1\/3 (chu vi m\u1ea3nh \u0111\u1ea5t) Do \u0111\u00f3 ta c\u00f3 : AB x 3 = AB x 2 + 16 106","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 AB x 3 - AB x 2 = 16 AB x (3 - 2) = 16 AB = 16 (m). V\u1eady di\u1ec7n t\u00edch m\u1ea3nh \u0111\u1ea5t l\u00e0 : 16 x 8 = 128 (m2) C\u00e1ch chia 2 : nh\u01b0 h\u00ecnh 2. H\u00ecnh 2 L\u1eadp lu\u1eadn t\u01b0\u01a1ng t\u1ef1 tr\u01b0\u1eddng h\u1ee3p tr\u00ean, ta t\u00ecm \u0111\u01b0\u1ee3c AB = 4 m. \u0110i\u1ec1u n\u00e0y v\u00f4 l\u00ed v\u00ec AB l\u00e0 chi\u1ec1u d\u00e0i c\u1ee7a m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt, \u0111\u01b0\u01a1ng nhi\u00ean ph\u1ea3i l\u1edbn h\u01a1n 8 m. Do \u0111\u00f3 tr\u01b0\u1eddng h\u1ee3p n\u00e0y b\u1ecb lo\u1ea1i. B\u00e0i 107 : Cho m\u1ed9t ph\u00e9p chia hai s\u1ed1 t\u1ef1 nhi\u00ean c\u00f3 d\u01b0. T\u1ed5ng c\u00e1c s\u1ed1 : s\u1ed1 b\u1ecb chia, s\u1ed1 chia, s\u1ed1 th\u01b0\u01a1ng v\u00e0 s\u1ed1 d\u01b0 l\u00e0 769. S\u1ed1 th\u01b0\u01a1ng l\u00e0 15 v\u00e0 s\u1ed1 d\u01b0 l\u00e0 s\u1ed1 d\u01b0 l\u1edbn nh\u1ea5t c\u00f3 th\u1ec3 c\u00f3 trong ph\u00e9p chia \u0111\u00f3. H\u00e3y t\u00ecm s\u1ed1 b\u1ecb chia v\u00e0 s\u1ed1 chia trong ph\u00e9p chia. B\u00e0i gi\u1ea3i : S\u1ed1 d\u01b0 trong ph\u00e9p chia l\u00e0 s\u1ed1 d\u01b0 l\u1edbn nh\u1ea5t n\u00ean k\u00e9m s\u1ed1 chia 1 \u0111\u01a1n v\u1ecb. Ta c\u00f3 s\u01a1 \u0111\u1ed3 sau : Theo s\u01a1 \u0111\u1ed3, n\u1ebfu g\u1ecdi s\u1ed1 chia l\u00e0 1 ph\u1ea7n, th\u00eam 1 \u0111\u01a1n v\u1ecb v\u00e0o s\u1ed1 d\u01b0 v\u00e0 s\u1ed1 b\u1ecb chia th\u00ec t\u1ed5ng s\u1ed1 ph\u1ea7n c\u1ee7a s\u1ed1 chia, s\u1ed1 b\u1ecb chia v\u00e0 s\u1ed1 d\u01b0 (m\u1edbi) g\u1ed3m : 15 + 1 + 1 + 1 = 18 (ph\u1ea7n) nh\u01b0 v\u1eady. Khi \u0111\u00f3 t\u1ed5ng c\u1ee7a s\u1ed1 chia, s\u1ed1 b\u1ecb chia v\u00e0 s\u1ed1 d\u01b0 (m\u1edbi) l\u00e0 : 769 - 15 + 1 + 1 = 756. S\u1ed1 chia l\u00e0 : 756 : 18 = 42 S\u1ed1 d\u01b0 l\u00e0 : 42 - 1 = 41 S\u1ed1 b\u1ecb chia l\u00e0 : 42 x 15 + 41 = 671 B\u00e0i 108 : S\u1ed1 t\u00e1o c\u1ee7a An, B\u00ecnh v\u00e0 Chi l\u00e0 nh\u01b0 nhau. An cho \u0111i 17 qu\u1ea3, B\u00ecnh cho \u0111i 19 qu\u1ea3 th\u00ec l\u00fac n\u00e0y s\u1ed1 t\u00e1o c\u1ee7a Chi g\u1ea5p 5 l\u1ea7n t\u1ed5ng s\u1ed1 t\u00e1o c\u00f2n l\u1ea1i c\u1ee7a An v\u00e0 B\u00ecnh. H\u1ecfi l\u00fac \u0111\u1ea7u m\u1ed7i 107","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 b\u1ea1n c\u00f3 bao nhi\u00eau qu\u1ea3 t\u00e1o ? B\u00e0i gi\u1ea3i : N\u1ebfu coi s\u1ed1 t\u00e1o c\u1ee7a Chi g\u1ed3m 5 ph\u1ea7n th\u00ec t\u1ed5ng s\u1ed1 t\u00e1o c\u1ee7a An v\u00e0 B\u00ecnh l\u00e0 10 ph\u1ea7n. S\u1ed1 t\u00e1o m\u00e0 An v\u00e0 B\u00ecnh \u0111\u00e3 cho \u0111i l\u00e0 : 17 + 19 = 36 (qu\u1ea3) V\u00ec s\u1ed1 t\u00e1o c\u1ee7a Chi g\u1ea5p 5 l\u1ea7n t\u1ed5ng s\u1ed1 t\u00e1o c\u00f2n l\u1ea1i c\u1ee7a An v\u00e0 B\u00ecnh n\u00ean s\u1ed1 t\u00e1o c\u00f2n l\u1ea1i c\u1ee7a hai b\u1ea1n g\u1ed3m 1 ph\u1ea7n. Nh\u01b0 v\u1eady An v\u00e0 B\u00ecnh \u0111\u00e3 cho \u0111i s\u1ed1 ph\u1ea7n l\u00e0 : 10 - 1 = 9 (ph\u1ea7n) V\u1eady s\u1ed1 t\u00e1o c\u1ee7a Chi l\u00e0 : (36 : 9) x 5 = 20 (qu\u1ea3) V\u00ec ba b\u1ea1n c\u00f3 s\u1ed1 t\u00e1o b\u1eb1ng nhau n\u00ean m\u1ed7i b\u1ea1n l\u00fac \u0111\u1ea7u c\u00f3 20 qu\u1ea3. B\u00e0i 109 : Con s\u1ed1 n\u00e0o trong c\u00e1c s\u1ed1 2, 3, 4, 5 c\u1ea7n thay v\u00e0o d\u1ea5u ch\u1ea5m h\u1ecfi (?) \u0111\u1ec3 h\u1ee3p l\u00f4gic ? B\u00e0i gi\u1ea3i : G\u1ecdi s\u1ed1 thay v\u00e0o h\u00ecnh tr\u00f2n l\u00e0 a, s\u1ed1 thay v\u00e0o tam gi\u00e1c l\u00e0 b v\u00e0 s\u1ed1 thay v\u00e0o h\u00ecnh vu\u00f4ng l\u00e0 c, ta c\u00f3 : a + 3 x b = 22. V\u00ec 3 x b chia h\u1ebft cho 3 ; 22 chia cho 3 d\u01b0 1 n\u00ean a chia cho 3 d\u01b0 1 (*). Ta l\u1ea1i c\u00f3 2 x a + 2 x c = 10, c nh\u1ecf nh\u1ea5t l\u00e0 2 n\u00ean a l\u1edbn nh\u1ea5t l\u00e0 (10 - 2 x 2) : 2 = 3 (**). T\u1eeb (*) v\u00e0 (**) ta c\u00f3 a = 1. Do \u0111\u00f3 1 + 3 x b = 22 ; b = (22 - 1) : 3 = 7 ; c = (10 - 2 x 1) : 2 = 4. V\u1eady s\u1ed1 c\u1ea7n thay v\u00e0o d\u1ea5u ch\u1ea5m h\u1ecfi \u0111\u1ec3 h\u1ee3p l\u00f4gic l\u00e0 s\u1ed1 4. B\u00e0i 110 : H\u00e3y d\u00f9ng t\u1ea5t c\u1ea3 c\u00e1c ch\u1eef s\u1ed1, m\u1ed7i ch\u1eef s\u1ed1 m\u1ed9t l\u1ea7n \u0111\u1ec3 vi\u1ebft n\u0103m s\u1ed1 t\u1ef1 nhi\u00ean, trong \u0111\u00f3 c\u00f3 m\u1ed9t s\u1ed1 l\u1ea7n l\u01b0\u1ee3t b\u1eb1ng 1\/2 ; 1\/3 ; 1\/4 v\u00e0 1\/5 c\u00e1c s\u1ed1 c\u00f2n l\u1ea1i. B\u00e0i gi\u1ea3i : G\u1ecdi 5 s\u1ed1 t\u1ef1 nhi\u00ean x\u1ebfp theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn l\u00e0 A ; B ; C ; D ; E. N\u1ebfu A c\u00f3 1 ch\u1eef s\u1ed1 th\u00ec E kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 9 x 5 = 45. Nh\u01b0 th\u1ebf c\u00f3 4 s\u1ed1 c\u00f3 kh\u00f4ng qu\u00e1 2 ch\u1eef s\u1ed1 n\u00ean m\u1edbi ch\u1ec9 d\u00f9ng kh\u00f4ng qu\u00e1 9 ch\u1eef s\u1ed1 (2 x 4 + 1 = 9). V\u1eady A c\u00f3 nhi\u1ec1u h\u01a1n 1 ch\u1eef s\u1ed1. N\u1ebfu E c\u00f3 3 ch\u1eef s\u1ed1 th\u00ec A c\u00f3 \u00edt nh\u1ea5t 2 ch\u1eef s\u1ed1 (v\u00ec 100 : 5 = 20). Nh\u01b0 v\u1eady c\u00f3 4 s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 v\u00e0 1 s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 n\u00ean ph\u1ea3i d\u00f9ng nhi\u1ec1u h\u01a1n 10 ch\u1eef s\u1ed1 (2 x 4 + 3 = 11). V\u1eady c\u1ea3 5 s\u1ed1 ph\u1ea3i l\u00e0 c\u00e1c s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 v\u00e0 E l\u1edbn h\u01a1n 45 chia h\u1ebft cho 5. V\u1eady E c\u00f3 th\u1ec3 l\u00e0 : 95 ; 90 ; 85 ; 80 ; 75 ; 70 ; 65 ; 60 ; 55 ; 50. Ta c\u00f3 108","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 b\u1ea3ng l\u1ef1a ch\u1ecdn sau : S\u1ed1 th\u1ee9 nh\u1ea5t l\u00e0 18, s\u1ed1 th\u1ee9 hai l\u00e0 36, s\u1ed1 th\u1ee9 ba l\u00e0 54, s\u1ed1 th\u1ee9 t\u01b0 l\u00e0 72 v\u00e0 s\u1ed1 th\u1ee9 5 l\u00e0 90. B\u00e0i 111 : B\u1ea1n h\u00e3y x\u00f3a nh\u1eefng ch\u1eef s\u1ed1 n\u00e0o \u0111\u00f3 \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang : 151 x 375 = 450. B\u00e0i gi\u1ea3i : Hai th\u1eeba s\u1ed1 \u1edf v\u1ebf tr\u00e1i \u0111\u1eb3ng th\u1ee9c ch\u1ec9 c\u00f3 c\u00e1c ch\u1eef s\u1ed1 l\u1ebb n\u00ean d\u00f9 x\u00f3a c\u00e1c ch\u1eef s\u1ed1 nh\u01b0 th\u1ebf n\u00e0o th\u00ec k\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n c\u0169ng l\u00e0 m\u1ed9t s\u1ed1 l\u1ebb. V\u1eady v\u1ebf ph\u1ea3i ch\u1ec9 c\u00f3 th\u1ec3 l\u00e0 45 ho\u1eb7c 5. Tr\u01b0\u1eddng h\u1ee3p 1 : K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n l\u00e0 45 ta c\u00f3 m\u1ed9t c\u00e1ch x\u00f3a : Tr\u01b0\u1eddng h\u1ee3p 2 : K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n l\u00e0 5 ta c\u00f3 hai c\u00e1ch x\u00f3a : B\u00e0i 112 : C\u00f3 hai t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng m\u00e0 s\u1ed1 \u0111o c\u00e1c c\u1ea1nh l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean chia h\u1ebft cho 3. \u0110\u1eb7t t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng nh\u1ecf l\u00ean t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng l\u1edbn th\u00ec di\u1ec7n t\u00edch ph\u1ea7n t\u1ea5m b\u00eca kh\u00f4ng b\u1ecb ch\u1ed3ng l\u00ean l\u00e0 63 cm2. T\u00ecm c\u1ea1nh c\u1ee7a m\u1ed7i t\u1ea5m b\u00eca \u0111\u00f3. B\u00e0i gi\u1ea3i : Ta \u0111\u1eb7t t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng nh\u1ecf l\u00ean t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng l\u1edbn sao cho c\u1ea1nh h\u00ecnh vu\u00f4ng nh\u1ecf tr\u00f9ng kh\u00edt v\u1edbi c\u1ea1nh h\u00ecnh vu\u00f4ng l\u1edbn. G\u1ecdi hai h\u00ecnh vu\u00f4ng l\u00e0 ABCD v\u00e0 AEGH. Di\u1ec7n t\u00edch ph\u1ea7n t\u1ea5m b\u00eca kh\u00f4ng b\u1ecb ch\u1ed3ng l\u00ean bao g\u1ed3m hai h\u00ecnh ch\u1eef nh\u1eadt BCKE v\u00e0 DKGH. Hai h\u00ecnh ch\u1eef nh\u1eadt n\u00e0y c\u00f3 BE 109","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 = DH (ch\u00ednh l\u00e0 hi\u1ec7u s\u1ed1 \u0111o c\u00e1c c\u1ea1nh c\u1ee7a hai h\u00ecnh vu\u00f4ng). Chuy\u1ec3n h\u00ecnh ch\u1eef nh\u1eadt BCKE xu\u1ed1ng b\u00ean c\u1ea1nh h\u00ecnh ch\u1eef nh\u1eadt DKGH ta \u0111\u01b0\u1ee3c h\u00ecnh ch\u1eef nh\u1eadt GKMN. Khi \u0111\u00f3 ta c\u00f3 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt HDMN l\u00e0 63 cm2. Ta th\u1ea5y h\u00ecnh ch\u1eef nh\u1eadt HDMN c\u00f3 chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng ch\u00ednh l\u00e0 t\u1ed5ng v\u00e0 hi\u1ec7u s\u1ed1 \u0111o hai c\u1ea1nh h\u00ecnh vu\u00f4ng. V\u00ec hai h\u00ecnh vu\u00f4ng \u0111\u1ec1u c\u00f3 s\u1ed1 \u0111o c\u00e1c c\u1ea1nh l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean chia h\u1ebft cho 3, n\u00ean t\u1ed5ng v\u00e0 hi\u1ec7u s\u1ed1 \u0111o hai c\u1ea1nh h\u00ecnh vu\u00f4ng c\u0169ng ph\u1ea3i l\u00e0 s\u1ed1 chia h\u1ebft cho 3. Do \u0111\u00f3 chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt HDMN \u0111\u1ec1u l\u00e0 s\u1ed1 chia h\u1ebft cho 3. V\u00ec 63 = 1 x 63 = 3 x 21 = 7 x 9 n\u00ean chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt HDMN ph\u1ea3i l\u00e0 21 cm v\u00e0 3 cm. V\u1eady \u0111\u1ed9 d\u00e0i c\u1ea1nh c\u1ee7a t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng nh\u1ecf l\u00e0 : (21 - 3) : 2 = 9 (cm) \u0110\u1ed9 d\u00e0i c\u1ea1nh c\u1ee7a t\u1ea5m b\u00eca h\u00ecnh vu\u00f4ng l\u1edbn l\u00e0 : 9 + 3 = 12 (cm) B\u00e0i 113 : So s\u00e1nh M v\u00e0 N bi\u1ebft : B\u00e0i gi\u1ea3i : B\u00e0i 114 : M\u1ed9t b\u1ea3ng \u00f4 vu\u00f4ng g\u1ed3m 3 d\u00f2ng v\u00e0 8 c\u1ed9t nh\u01b0 h\u00ecnh v\u1ebd. Tr\u00ean m\u1ed7i d\u00f2ng ta \u0111i\u1ec1n c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean li\u00ean ti\u1ebfp t\u1eeb 1 \u0111\u1ebfn 8 v\u00e0o m\u1ed7i \u00f4 theo th\u1ee9 t\u1ef1 t\u00f9y \u00fd (m\u1ed7i \u00f4 m\u1ed9t s\u1ed1 v\u00e0 m\u1ed7i s\u1ed1 ch\u1ec9 \u0111i\u1ec1n m\u1ed9t l\u1ea7n) sao cho t\u1ed5ng c\u00e1c s\u1ed1 \u1edf 8 c\u1ed9t \u0111\u1ec1u b\u1eb1ng nhau. B\u1ea1n Nhi cho r\u1eb1ng c\u00f3 th\u1ec3 l\u00e0m \u0111\u01b0\u1ee3c c\u00f2n b\u1ea1n T\u00edn kh\u1eb3ng \u0111\u1ecbnh kh\u00f4ng \u0111i\u1ec1n \u0111\u01b0\u1ee3c. H\u1ecfi ai \u0111\u00fang, ai sai ? B\u00e0i gi\u1ea3i : Gi\u1ea3 s\u1eed c\u00f3 th\u1ec3 \u0111i\u1ec1n \u0111\u01b0\u1ee3c theo y\u00eau c\u1ea7u b\u00e0i to\u00e1n (B\u1ea1n Nhi n\u00f3i \u0111\u00fang). T\u1ed5ng c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean li\u00ean ti\u1ebfp t\u1eeb 1 \u0111\u1ebfn 8 l\u00e0 : 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36. M\u1ed7i d\u00f2ng \u0111i\u1ec1n c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean li\u00ean ti\u1ebfp t\u1eeb 1 \u0111\u1ebfn 8 n\u00ean t\u1ed5ng c\u00e1c s\u1ed1 tr\u00ean 3 d\u00f2ng trong b\u1ea3ng \u00f4 110","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 vu\u00f4ng \u0111\u00f3 l\u00e0 : 36 x 3 = 108. V\u00ec t\u1ed5ng c\u00e1c s\u1ed1 \u1edf 8 c\u1ed9t \u0111\u1ec1u b\u1eb1ng nhau n\u00ean t\u1ed5ng t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 trong b\u1ea3ng \u00f4 vu\u00f4ng ph\u1ea3i l\u00e0 m\u1ed9t s\u1ed1 chia h\u1ebft cho 8. Nh\u01b0ng 108 kh\u00f4ng chia h\u1ebft cho 8 n\u00ean \u0111i\u1ec1u gi\u1ea3 s\u1eed \u1edf tr\u00ean l\u00e0 sai t\u1ee9c l\u00e0 b\u1ea1n Nhi n\u00f3i sai v\u00e0 b\u1ea1n T\u00edn n\u00f3i \u0111\u00fang. B\u00e0i 115 : N\u1ebfu \u0111\u1ebfm c\u00e1c ch\u1eef s\u1ed1 ghi t\u1ea5t c\u1ea3 c\u00e1c ng\u00e0y trong n\u0103m 2004 tr\u00ean t\u1edd l\u1ecbch treo t\u01b0\u1eddng th\u00ec s\u1ebd \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 bao nhi\u00eau ? B\u00e0i gi\u1ea3i : N\u0103m 2004 l\u00e0 n\u0103m nhu\u1eadn c\u00f3 366 ng\u00e0y. M\u1ed9t n\u0103m c\u00f3 12 th\u00e1ng, m\u1ed7i th\u00e1ng c\u00f3 9 ng\u00e0y t\u1eeb m\u00f9ng 1 \u0111\u1ebfn m\u00f9ng 9 l\u00e0 nh\u1eefng ng\u00e0y \u0111\u01b0\u1ee3c vi\u1ebft b\u1eb1ng c\u00e1c s\u1ed1 c\u00f3 1 ch\u1eef s\u1ed1. Nh\u01b0 v\u1eady s\u1ed1 ng\u00e0y \u0111\u01b0\u1ee3c vi\u1ebft b\u1eb1ng s\u1ed1 c\u00f3 1 ch\u1eef s\u1ed1 l\u00e0 : 9 x 12 = 108 (ng\u00e0y). S\u1ed1 ng\u00e0y c\u00f2n l\u1ea1i trong n\u0103m \u0111\u01b0\u1ee3c vi\u1ebft b\u1eb1ng s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 l\u00e0 : 366 - 108 = 258 (ng\u00e0y). V\u1eady \u0111\u1ebfm c\u00e1c ch\u1eef s\u1ed1 ghi t\u1ea5t c\u1ea3 c\u00e1c ng\u00e0y c\u1ee7a n\u0103m 2004 tr\u00ean t\u1edd l\u1ecbch th\u00ec ta \u0111\u01b0\u1ee3c : 1 x 108 + 2 x 258 = 624 (ch\u1eef s\u1ed1). B\u00e0i 116 : Cho : H\u00e3y so s\u00e1nh S v\u00e0 1\/2. B\u00e0i gi\u1ea3i : B\u00e0i 117 : Cho m\u1ed9t s\u1ed1 t\u1ef1 nhi\u00ean, n\u1ebfu vi\u1ebft th\u00eam m\u1ed9t ch\u1eef s\u1ed1 v\u00e0o b\u00ean ph\u1ea3i s\u1ed1 \u0111\u00f3 ta \u0111\u01b0\u1ee3c s\u1ed1 m\u1edbi h\u01a1n s\u1ed1 \u0111\u00e3 cho \u0111\u00fang 2004 \u0111\u01a1n v\u1ecb. T\u00ecm s\u1ed1 \u0111\u00e3 cho v\u00e0 ch\u1eef s\u1ed1 vi\u1ebft th\u00eam. B\u00e0i gi\u1ea3i : 111","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 C\u00e1ch 1 : Khi vi\u1ebft th\u00eam m\u1ed9t ch\u1eef s\u1ed1 n\u00e0o \u0111\u00f3 v\u00e0o b\u00ean ph\u1ea3i m\u1ed9t s\u1ed1 t\u1ef1 nhi\u00ean \u0111\u00e3 cho ta \u0111\u01b0\u1ee3c s\u1ed1 m\u1edbi b\u1eb1ng 10 l\u1ea7n s\u1ed1 t\u1ef1 nhi\u00ean \u0111\u00f3 c\u1ed9ng th\u00eam ch\u00ednh ch\u1eef s\u1ed1 vi\u1ebft th\u00eam. G\u1ecdi ch\u1eef s\u1ed1 vi\u1ebft th\u00eam l\u00e0 a, ta c\u00f3 s\u01a1 \u0111\u1ed3 : 9 l\u1ea7n s\u1ed1 \u0111\u00e3 cho l\u00e0 : 2004 - a. S\u1ed1 \u0111\u00e3 cho l\u00e0 : (2004 - a) : 9. V\u00ec s\u1ed1 \u0111\u00e3 cho l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean 2004 - a ph\u1ea3i chia h\u1ebft cho 9, s\u1ed1 2004 chia 9 d\u01b0 6 n\u00ean a chia cho 9 ph\u1ea3i d\u01b0 6, m\u00e0 a l\u00e0 ch\u1eef s\u1ed1 n\u00ean a = 6. S\u1ed1 t\u1ef1 nhi\u00ean \u0111\u00e3 cho l\u00e0 (2004 - 6) : 9 = 222. C\u00e1ch 2 : G\u1ecdi s\u1ed1 t\u1ef1 nhi\u00ean \u0111\u00e3 cho l\u00e0 A ch\u1eef s\u1ed1 vi\u1ebft th\u00eam l\u00e0 x th\u00ec s\u1ed1 m\u1edbi l\u00e0 . Ta c\u00f3 - A = 2004 A x 10 + x - A = 2004 (ph\u00e2n t\u00edch s\u1ed1) A x 10 - A + x = 2004 A x (10 - 1) + x = 2004 (m\u1ed9t s\u1ed1 nh\u00e2n v\u1edbi m\u1ed9t t\u1ed5ng) A x 9 + x = 2004 V\u00ec A x 9 chia h\u1ebft cho 9 ; 2004 chia 9 d\u01b0 6 n\u00ean x chia cho 9 ph\u1ea3i d\u01b0 6. V\u00ec x l\u00e0 ch\u1eef s\u1ed1 n\u00ean x = 6. Ta c\u00f3 : A x 9 + 6 = 2004 A x 9 = 2004 - 6 A x 9 = 1998 A = 1998 : 9 A = 222. V\u1eady s\u1ed1 t\u1ef1 nhi\u00ean \u0111\u00e3 cho l\u00e0 222 ; ch\u1eef s\u1ed1 vi\u1ebft th\u00eam l\u00e0 6. B\u00e0i 118 : M\u1ed9t t\u1edd gi\u1ea5y h\u00ecnh vu\u00f4ng c\u00f3 di\u1ec7n t\u00edch l\u00e0 72 cm2 th\u00ec \u0111\u01b0\u1eddng ch\u00e9o c\u1ee7a t\u1edd gi\u1ea5y \u0111\u00f3 112","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 d\u00e0i bao nhi\u00eau ? B\u00e0i gi\u1ea3i : G\u1ecdi t\u1edd gi\u1ea5y h\u00ecnh vu\u00f4ng l\u00e0 ABCD. N\u1ed1i hai \u0111\u01b0\u1eddng ch\u00e9o AC v\u00e0 BD c\u1eaft nhau t\u1ea1i O (h\u00ecnh v\u1ebd). H\u00ecnh vu\u00f4ng \u0111\u01b0\u1ee3c chia th\u00e0nh 4 tam gi\u00e1c vu\u00f4ng nh\u1ecf c\u00f3 di\u1ec7n t\u00edch b\u1eb1ng nhau. Di\u1ec7n t\u00edch tam gi\u00e1c AOB l\u00e0 : 72 : 4 = 18 (cm2). V\u00ec di\u1ec7n t\u00edch tam gi\u00e1c AOB b\u1eb1ng (OA x OB) : 2, do \u0111\u00f3 (OA x OB) : 2 = 18 (cm2). Suy ra OA x OB = 36 (cm2). V\u00ec OA = OB m\u00e0 36 = 6 x 6 n\u00ean OA = 6 (cm). V\u00ec AC = 2 x OA n\u00ean \u0111\u1ed9 d\u00e0i \u0111\u01b0\u1eddng ch\u00e9o c\u1ee7a t\u1edd gi\u1ea5y \u0111\u00f3 l\u00e0 : 6 x 2 = 12 (cm). B\u00e0i 119 : Trong \u0111\u1ee3t tr\u1ed3ng c\u00e2y \u0111\u1ea7u n\u0103m, l\u1edbp 5A c\u1eed m\u1ed9t s\u1ed1 b\u1ea1n \u0111i tr\u1ed3ng c\u00e2y v\u00e0 tr\u1ed3ng \u0111\u01b0\u1ee3c 180 c\u00e2y, m\u1ed7i h\u1ecdc sinh tr\u1ed3ng \u0111\u01b0\u1ee3c 8 ho\u1eb7c 9 c\u00e2y. T\u00ednh s\u1ed1 h\u1ecdc sinh tham gia tr\u1ed3ng c\u00e2y, bi\u1ebft s\u1ed1 h\u1ecdc sinh tham gia l\u00e0 m\u1ed9t s\u1ed1 chia h\u1ebft cho 3. B\u00e0i gi\u1ea3i : N\u1ebfu m\u1ed7i b\u1ea1n tr\u1ed3ng 9 c\u00e2y th\u00ec s\u1ed1 ng\u01b0\u1eddi tham gia s\u1ebd \u00edt nh\u1ea5t v\u00e0 ch\u00ednh l\u00e0 : 180 : 9 = 20 (ng\u01b0\u1eddi). V\u00ec 180 : 8 = 22 (d\u01b0 4) n\u00ean s\u1ed1 ng\u01b0\u1eddi tham gia nhi\u1ec1u nh\u1ea5t l\u00e0 22 ng\u01b0\u1eddi v\u00e0 khi \u0111\u00f3 c\u00f3 4 ng\u01b0\u1eddi tr\u1ed3ng 9 c\u00e2y, c\u00f2n l\u1ea1i m\u1ed7i ng\u01b0\u1eddi tr\u1ed3ng 8 c\u00e2y. Theo \u0111\u1ea7u b\u00e0i s\u1ed1 ng\u01b0\u1eddi tham gia l\u00e0 m\u1ed9t s\u1ed1 chia h\u1ebft cho 3 n\u00ean c\u00f3 21 b\u1ea1n tham gia. B\u00e0i 120 : Ch\u1ee9ng minh r\u1eb1ng kh\u00f4ng th\u1ec3 thay c\u00e1c ch\u1eef b\u1eb1ng c\u00e1c ch\u1eef s\u1ed1 \u0111\u1ec3 c\u00f3 ph\u00e9p t\u00ednh \u0111\u00fang : - = 2004 B\u00e0i gi\u1ea3i : C\u00e1ch 1 : \u0110\u1eb7t t\u00ednh : X\u00e9t ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb : C\u00f3 2 tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra : Tr\u01b0\u1eddng h\u1ee3p 1 : I > C. 113","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Khi \u0111\u00f3 ph\u00e9p tr\u1eeb \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb kh\u00f4ng c\u00f3 nh\u1edb sang h\u00e0ng ch\u1ee5c. \u1edf ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c : U - O = 0 hay U = O. \u1edf ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m : V - H = 0 hay V = H. Do \u0111\u00f3 (v\u00ec \u1edf ch\u1eef s\u1ed1 h\u00e0ng ngh\u00ecn C < I). Tr\u01b0\u1eddng h\u1ee3p 2 : I < C. Khi \u0111\u00f3 ph\u00e9p tr\u1eeb \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb c\u00f3 nh\u1edb 1 sang h\u00e0ng ch\u1ee5c. Do \u0111\u00f3 \u1edf h\u00e0ng ch\u1ee5c : U - O - 1 = 0 hay U - O = 1 n\u00ean O < U. Ph\u00e9p tr\u1eeb kh\u00f4ng c\u00f3 nh\u1edb sang h\u00e0ng tr\u0103m. \u1edf h\u00e0ng tr\u0103m : V - H = 0 hay V = H. V\u00ec th\u1ebf (v\u00ec \u1edf ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c ngh\u00ecn O < U). V\u1eady ta kh\u00f4ng th\u1ec3 thay th\u1ebf c\u00e1c ch\u1eef b\u1eb1ng c\u00e1c ch\u1eef s\u1ed1 \u0111\u1ec3 c\u00f3 ph\u00e9p t\u00ednh nh\u01b0 \u0111\u00e3 cho. C\u00e1ch 2 : D\u00f9ng t\u00ednh ch\u1ea5t chia h\u1ebft c\u1ee7a m\u1ed9t hi\u1ec7u : Ta th\u1ea5y 2 s\u1ed1 v\u00e0 c\u00f3 t\u1ed5ng c\u00e1c ch\u1eef s\u1ed1 b\u1eb1ng nhau n\u00ean c\u1ea3 2 s\u1ed1 s\u1ebd c\u00f3 c\u00f9ng s\u1ed1 d\u01b0 khi chia cho 9, do \u0111\u00f3 hi\u1ec7u c\u1ee7a hai s\u1ed1 ch\u1eafc ch\u1eafn s\u1ebd chia h\u1ebft cho 9. M\u00e0 2004 kh\u00f4ng chia h\u1ebft cho 9, do \u0111\u00f3 hi\u1ec7u c\u1ee7a hai s\u1ed1 kh\u00f4ng th\u1ec3 b\u1eb1ng 2004. N\u00f3i c\u00e1ch kh\u00e1c ta kh\u00f4ng th\u1ec3 thay c\u00e1c ch\u1eef b\u1eb1ng c\u00e1c ch\u1eef s\u1ed1 \u0111\u1ec3 c\u00f3 ph\u00e9p t\u00ednh \u0111\u00fang. B\u00e0i 121 : S\u1ed1 ch\u1eef s\u1ed1 d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang c\u1ee7a m\u1ed9t quy\u1ec3n s\u00e1ch l\u00e0 m\u1ed9t s\u1ed1 chia h\u1ebft cho s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch \u0111\u00f3. Bi\u1ebft r\u1eb1ng cu\u1ed1n s\u00e1ch \u0111\u00f3 tr\u00ean 100 trang v\u00e0 \u00edt h\u01a1n 500 trang. H\u1ecfi cu\u1ed1n s\u00e1ch \u0111\u00f3 c\u00f3 bao nhi\u00eau trang ? B\u00e0i gi\u1ea3i : V\u00ec cu\u1ed1n s\u00e1ch \u0111\u00f3 tr\u00ean 100 trang v\u00e0 \u00edt h\u01a1n 500 trang n\u00ean s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch \u0111\u00f3 l\u00e0 m\u1ed9t s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1. G\u1ecdi s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch \u0111\u00f3 l\u00e0 v\u1edbi a, b, c l\u00e0 c\u00e1c ch\u1eef s\u1ed1 v\u00e0 a kh\u00e1c 0. C\u00e1c s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch l\u00e0 c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean t\u1eeb 1 \u0111\u1ebfn . C\u00f3 9 trang c\u00f3 1 ch\u1eef s\u1ed1 n\u00ean c\u1ea7n 9 ch\u1eef s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang cho c\u00e1c trang n\u00e0y. C\u00f3 90 trang c\u00f3 2 ch\u1eef s\u1ed1 n\u00ean c\u1ea7n 2 x 90 = 180 (ch\u1eef s\u1ed1) \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang cho c\u00e1c trang n\u00e0y. S\u1ed1 trang c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 - 99 trang. S\u1ed1 ch\u1eef s\u1ed1 d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 : 3 x ( - 99) S\u1ed1 ch\u1eef s\u1ed1 d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch \u0111\u00f3 l\u00e0 : 9 + 180 + 3 x ( - 99) = 189 + 3 x 114","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 - 297 = 3 x - 180. V\u00ec s\u1ed1 ch\u1eef s\u1ed1 d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch l\u00e0 s\u1ed1 chia h\u1ebft cho s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch \u0111\u00f3 n\u00ean chia h\u1ebft cho hay 108 chia h\u1ebft cho . Suy ra ch\u00ednh b\u1eb1ng 108. V\u1eady cu\u1ed1n s\u00e1ch \u0111\u00f3 c\u00f3 108 trang. B\u00e0i 122 : Cha hi\u1ec7n nay 43 tu\u1ed5i. N\u1ebfu t\u00ednh sang n\u0103m th\u00ec tu\u1ed5i cha v\u1eeba g\u1ea5p 4 tu\u1ed5i con hi\u1ec7n nay. H\u1ecfi l\u00fac con m\u1ea5y tu\u1ed5i th\u00ec tu\u1ed5i cha g\u1ea5p 5 l\u1ea7n tu\u1ed5i con ? C\u00f3 bao gi\u1edd tu\u1ed5i cha g\u1ea5p 4 l\u1ea7n tu\u1ed5i con kh\u00f4ng ? V\u00ec sao ? B\u00e0i gi\u1ea3i : Tu\u1ed5i c\u1ee7a cha sang n\u0103m l\u00e0 : 43 + 1 = 44 (tu\u1ed5i) Tu\u1ed5i c\u1ee7a con hi\u1ec7n nay l\u00e0 : 44 : 4 = 11 (tu\u1ed5i) Tu\u1ed5i cha h\u01a1n tu\u1ed5i con l\u00e0 : 43 - 11 = 32 (tu\u1ed5i) Khi tu\u1ed5i cha g\u1ea5p 5 l\u1ea7n tu\u1ed5i con th\u00ec cha v\u1eabn h\u01a1n con 32 tu\u1ed5i. Ta c\u00f3 s\u01a1 \u0111\u1ed3 khi tu\u1ed5i cha g\u1ea5p 5 l\u1ea7n tu\u1ed5i con nh\u01b0 sau : Nh\u00ecn v\u00e0o s\u01a1 \u0111\u1ed3 ta th\u1ea5y : Tu\u1ed5i con khi \u0111\u00f3 l\u00e0 : 32 : (5 - 1) = 8 (tu\u1ed5i) N\u1ebfu tu\u1ed5i cha g\u1ea5p 4 l\u1ea7n tu\u1ed5i con, khi \u0111\u00f3 tu\u1ed5i con l\u00e0 1 ph\u1ea7n th\u00ec tu\u1ed5i cha l\u00e0 4 ph\u1ea7n nh\u01b0 th\u1ebf. Tu\u1ed5i cha h\u01a1n tu\u1ed5i con s\u1ed1 ph\u1ea7n l\u00e0 : 4 - 1 = 3 (ph\u1ea7n), khi \u0111\u00f3 cha c\u0169ng v\u1eabn h\u01a1n con 32 tu\u1ed5i ; 32 kh\u00f4ng chia h\u1ebft cho 3 n\u00ean kh\u00f4ng bao gi\u1edd tu\u1ed5i cha g\u1ea5p 4 l\u1ea7n tu\u1ed5i con (v\u00ec ta coi tu\u1ed5i con h\u00e0ng n\u0103m l\u00e0 m\u1ed9t s\u1ed1 t\u1ef1 nhi\u00ean). B\u00e0i 123 : C\u00f3 4 b\u00ecnh (\u0111\u00e1nh s\u1ed1 l\u00e0 1, 2, 3, 4) \u0111\u1ef1ng s\u1ed1 l\u01b0\u1ee3ng c\u00e1c h\u00f2n bi b\u1eb1ng nhau. L\u1ea5y ra t\u1eeb b\u00ecnh th\u1ee9 nh\u1ea5t m\u1ed9t s\u1ed1 vi\u00ean bi, l\u1ea5y g\u1ea5p \u0111\u00f4i s\u1ed1 \u0111\u00f3 t\u1eeb b\u00ecnh th\u1ee9 hai, l\u1ea5y g\u1ea5p ba s\u1ed1 \u0111\u00f3 t\u1eeb b\u00ecnh th\u1ee9 ba v\u00e0 cu\u1ed1i c\u00f9ng l\u1ea5y g\u1ea5p b\u1ed1n s\u1ed1 \u0111\u00f3 t\u1eeb b\u00ecnh th\u1ee9 t\u01b0. Khi \u0111\u00f3 t\u1ed5ng s\u1ed1 bi c\u00f2n l\u1ea1i trong c\u1ea3 b\u1ed1n b\u00ecnh l\u00e0 40 vi\u00ean v\u00e0 b\u00ecnh th\u1ee9 t\u01b0 c\u00f2n l\u1ea1i \u0111\u00fang 1 vi\u00ean bi. H\u1ecfi ban \u0111\u1ea7u s\u1ed1 l\u01b0\u1ee3ng bi trong b\u1ed1n b\u00ecnh 115","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 l\u00e0 bao nhi\u00eau ? B\u00e0i gi\u1ea3i : S\u1ed1 bi l\u1ea5y ra t\u1eeb b\u00ecnh 1 l\u00e0 : (40 - 1 x 4) : (3 + 2 + 1) = 6 (vi\u00ean). L\u00fac \u0111\u1ea7u s\u1ed1 l\u01b0\u1ee3ng bi trong b\u1ed1n b\u00ecnh l\u00e0 : (6 x 4 + 1) x 4 = 100 (vi\u00ean). B\u00e0i 124 : T\u1eeb m\u1ed9t t\u1edd gi\u1ea5y k\u1ebb \u00f4 vu\u00f4ng, b\u1ea1n Khang c\u1eaft ra m\u1ed9t h\u00ecnh sao b\u1ed1n c\u00e1nh nh\u01b0 h\u00ecnh b\u00ean. H\u00ecnh sao n\u00e0y c\u00f3 di\u1ec7n t\u00edch b\u1eb1ng m\u1ea5y \u00f4 vu\u00f4ng ? B\u00e0i gi\u1ea3i : C\u00f3 nhi\u1ec1u c\u00e1ch l\u00e0m, xin gi\u1edbi thi\u1ec7u 2 c\u00e1ch \u0111\u1ec3 c\u00e1c b\u1ea1n tham kh\u1ea3o. C\u00e1ch 1 : Di\u1ec7n t\u00edch h\u00ecnh sao \u0111\u00fang b\u1eb1ng di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng g\u1ed3m 16 \u00f4 vu\u00f4ng tr\u1eeb \u0111i di\u1ec7n t\u00edch b\u1ed1n h\u00ecnh tam gi\u00e1c b\u1eb1ng nhau. M\u1ed7i tam gi\u00e1c n\u00e0y c\u00f3 di\u1ec7n t\u00edch l\u00e0 2 \u00f4 vu\u00f4ng. Do \u0111\u00f3 di\u1ec7n t\u00edch h\u00ecnh sao l\u00e0 : 16 - 2 x 4 = 8 (\u00f4 vu\u00f4ng). C\u00e1ch 2 : C\u1eaft gh\u00e9p \u0111\u1ec3 t\u1eeb h\u00ecnh sao ta c\u00f3 h\u00ecnh m\u1edbi m\u00e0 h\u00ecnh n\u00e0y di\u1ec7n t\u00edch \u0111\u00fang b\u1eb1ng 8 \u00f4 vu\u00f4ng. B\u00e0i 125 : M\u1ed9t \u0111o\u00e0n t\u00e0u h\u1ecfa d\u00e0i 200 m l\u01b0\u1edbt qua m\u1ed9t ng\u01b0\u1eddi \u0111i xe \u0111\u1ea1p ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi t\u00e0u h\u1ebft 12 gi\u00e2y. T\u00ednh v\u1eadn t\u1ed1c c\u1ee7a t\u00e0u, bi\u1ebft v\u1eadn t\u1ed1c c\u1ee7a ng\u01b0\u1eddi \u0111i xe \u0111\u1ea1p l\u00e0 18 km\/gi\u1edd. B\u00e0i gi\u1ea3i : \u0110o\u00e0n t\u00e0u h\u1ecfa d\u00e0i 200 m l\u01b0\u1edbt qua ng\u01b0\u1eddi \u0111i xe \u0111\u1ea1p h\u1ebft 12 gi\u00e2y, c\u00f3 ngh\u0129a l\u00e0 sau 12 gi\u00e2y t\u1ed5ng qu\u00e3ng \u0111\u01b0\u1eddng t\u00e0u h\u1ecfa v\u00e0 xe \u0111\u1ea1p \u0111i l\u00e0 200 m. Nh\u01b0 v\u1eady t\u1ed5ng v\u1eadn t\u1ed1c c\u1ee7a t\u00e0u h\u1ecfa v\u00e0 xe \u0111\u1ea1p l\u00e0 : 116","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 200 : 12 = 50\/3(m\/gi\u00e2y), 50\/3 m\/gi\u00e2y = 60 km\/gi\u1edd. V\u1eadn t\u1ed1c c\u1ee7a xe \u0111\u1ea1p l\u00e0 18 km\/gi\u1edd, th\u00ec v\u1eadn t\u1ed1c c\u1ee7a t\u00e0u h\u1ecfa l\u00e0 : 60 - 18 = 42 (km\/gi\u1edd). B\u00e0i 126 : Cho s\u1ed1 g\u1ed3m b\u1ed1n ch\u1eef s\u1ed1 c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m l\u00e0 9 v\u00e0 ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c l\u00e0 7. T\u00ecm s\u1ed1 \u0111\u00e3 cho bi\u1ebft s\u1ed1 \u0111\u00f3 chia h\u1ebft cho 5 v\u00e0 27. B\u00e0i gi\u1ea3i : G\u1ecdi s\u1ed1 ph\u1ea3i t\u00ecm l\u00e0 (a kh\u00e1c 0 ; a ; b <10) V\u00ec chia h\u1ebft cho 5 n\u00ean b = 0 ho\u1eb7c b = 5. V\u00ec chia h\u1ebft cho 27 n\u00ean chia h\u1ebft cho 9. Thay b = 0 ta c\u00f3 chia h\u1ebft cho 9 n\u00ean a = 2. Th\u1eed 2970 : 27 = 110 (\u0111\u00fang). Thay b = 5 ta c\u00f3 chia h\u1ebft cho 9 n\u00ean a = 6. Th\u1eed 6975 : 27 = 258 (d\u01b0 9) tr\u00e1i v\u1edbi \u0111i\u1ec1u ki\u1ec7n b\u00e0i to\u00e1n. V\u1eady s\u1ed1 t\u00ecm \u0111\u01b0\u1ee3c l\u00e0 2970. B\u00e0i 127 : Ba l\u1edbp 5A, 5B v\u00e0 5C tr\u1ed3ng c\u00e2y nh\u00e2n d\u1ecbp \u0111\u1ea7u xu\u00e2n. Trong \u0111\u00f3 s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A v\u00e0 l\u1edbp 5B tr\u1ed3ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a 5B v\u00e0 5C l\u00e0 3 c\u00e2y. S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B v\u00e0 5C tr\u1ed3ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a 5A v\u00e0 5C l\u00e0 1 c\u00e2y. T\u00ednh s\u1ed1 c\u00e2y tr\u1ed3ng \u0111\u01b0\u1ee3c c\u1ee7a m\u1ed7i l\u1edbp. Bi\u1ebft r\u1eb1ng t\u1ed5ng s\u1ed1 c\u00e2y tr\u1ed3ng \u0111\u01b0\u1ee3c c\u1ee7a ba l\u1edbp l\u00e0 43 c\u00e2y. B\u00e0i gi\u1ea3i : C\u00e1ch 1 : V\u00ec s\u1ed1 c\u00e2y l\u1edbp 5A v\u00e0 l\u1edbp 5B tr\u1ed3ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B v\u00e0 5C l\u00e0 3 c\u00e2y n\u00ean s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5C l\u00e0 3 c\u00e2y. S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B v\u00e0 5C tr\u1ed3ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A v\u00e0 5C l\u00e0 1 c\u00e2y n\u00ean s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B tr\u1ed3ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A l\u00e0 1 c\u00e2y. Ta c\u00f3 s\u01a1 \u0111\u1ed3 : Ba l\u1ea7n s\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5C l\u00e0 : 43 - (3 + 3 + 1) = 36 (c\u00e2y) 117","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5C l\u00e0 : 36 : 3 = 12 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A l\u00e0 : 12 + 3 = 15 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B l\u00e0 : 15 + 1 = 16 (c\u00e2y). C\u00e1ch 2 : Hai l\u1ea7n t\u1ed5ng s\u1ed1 c\u00e2y c\u1ee7a 3 l\u1edbp l\u00e0 : 43 x 2 = 86 (c\u00e2y). Ta c\u00f3 s\u01a1 \u0111\u1ed3 : S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A v\u00e0 5C tr\u1ed3ng \u0111\u01b0\u1ee3c l\u00e0 : (86 - 3 - 1 - 1) : 3 = 27 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B l\u00e0 : 43 - 27 = 16 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5B v\u00e0 5C l\u00e0 : 27 + 1 = 28 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5C l\u00e0 : 28 - 16 = 12 (c\u00e2y). S\u1ed1 c\u00e2y c\u1ee7a l\u1edbp 5A l\u00e0 : 43 - 28 = 15 (c\u00e2y). B\u00e0i 128 : M\u1ed9t d\u00e3y c\u00f3 7 \u00f4 vu\u00f4ng g\u1ed3m 3 \u00f4 \u0111en v\u00e0 4 \u00f4 tr\u1eafng \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp nh\u01b0 h\u00ecnh v\u1ebd. 118","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Cho ph\u00e9p m\u1ed7i l\u1ea7n ch\u1ecdn hai \u00f4 t\u00f9y \u00fd v\u00e0 \u0111\u1ed5i m\u00e0u ch\u00fang (t\u1eeb \u0111en sang tr\u1eafng v\u00e0 t\u1eeb tr\u1eafng sang \u0111en). H\u1ecfi r\u1eb1ng n\u1ebfu l\u00e0m nh\u01b0 tr\u00ean nhi\u1ec1u l\u1ea7n th\u00ec c\u00f3 th\u1ec3 nh\u1eadn \u0111\u01b0\u1ee3c d\u00e3y \u00f4 vu\u00f4ng c\u00f3 m\u00e0u xen k\u1ebd nhau nh\u01b0 sau hay kh\u00f4ng ? B\u00e0i gi\u1ea3i : Nh\u00ecn v\u00e0o h\u00ecnh v\u1ebd ta th\u1ea5y \u1edf h\u00ecnh ban \u0111\u1ea7u c\u00f3 3 \u00f4 \u0111en v\u00e0 4 \u00f4 tr\u1eafng, c\u00f2n h\u00ecnh l\u00fac sau c\u00f3 4 \u00f4 \u0111en v\u00e0 3 \u00f4 tr\u1eafng. Khi ch\u1ecdn hai \u00f4 t\u00f9y \u00fd \u0111\u1ec3 \u0111\u1ed5i m\u00e0u c\u1ee7a ch\u00fang (t\u1eeb \u0111en sang tr\u1eafng v\u00e0 t\u1eeb tr\u1eafng sang \u0111en) th\u00ec c\u00f3 ba kh\u1ea3 n\u0103ng x\u1ea3y ra : - Ch\u1ecdn hai \u00f4 tr\u1eafng : Khi \u0111\u00f3 hai \u00f4 tr\u1eafng \u0111\u01b0\u1ee3c ch\u1ecdn s\u1ebd \u0111\u1ed5i th\u00e0nh hai \u00f4 \u0111en, do \u0111\u00f3 s\u1ed1 \u00f4 \u0111en t\u0103ng l\u00ean 2 \u00f4. - Ch\u1ecdn hai \u00f4 \u0111en : Khi \u0111\u00f3 hai \u00f4 \u0111en \u0111\u01b0\u1ee3c ch\u1ecdn s\u1ebd \u0111\u1ed5i th\u00e0nh hai \u00f4 tr\u1eafng, do \u0111\u00f3 s\u1ed1 \u00f4 \u0111en gi\u1ea3m \u0111i 2 \u00f4. - Ch\u1ecdn m\u1ed9t \u00f4 \u0111en v\u00e0 m\u1ed9t \u00f4 tr\u1eafng : Khi \u0111\u00f3 \u00f4 tr\u1eafng \u0111\u1ed5i th\u00e0nh \u00f4 \u0111en v\u00e0 \u00f4 \u0111en \u0111\u1ed5i th\u00e0nh \u00f4 tr\u1eafng, do \u0111\u00f3 s\u1ed1 \u00f4 \u0111en gi\u1eef nguy\u00ean. Do v\u1eady khi th\u1ef1c hi\u1ec7n vi\u1ec7c ch\u1ecdn hai \u00f4 \u0111\u1ec3 \u0111\u1ed5i m\u00e0u c\u1ee7a ch\u00fang th\u00ec s\u1ed1 l\u01b0\u1ee3ng \u00f4 \u0111en ho\u1eb7c t\u0103ng l\u00ean 2 \u00f4, ho\u1eb7c gi\u1ea3m \u0111i 2 \u00f4, ho\u1eb7c gi\u1eef nguy\u00ean. \u0110i\u1ec1u \u0111\u00f3 c\u00f3 ngh\u0129a l\u00e0 n\u1ebfu ch\u1ecdn hai \u00f4 t\u00f9y \u00fd v\u00e0 \u0111\u1ed5i m\u00e0u ch\u00fang nhi\u1ec1u l\u1ea7n th\u00ec s\u1ed1 \u00f4 \u0111en v\u1eabn lu\u00f4n lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 l\u1ebb. V\u00ec h\u00ecnh sau c\u00f3 4 \u00f4 \u0111en n\u00ean kh\u00f4ng th\u1ec3 th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c. B\u00e0i 129 : M\u1ed9t t\u1edd gi\u1ea5y h\u00ecnh ch\u1eef nh\u1eadt \u0111\u01b0\u1ee3c g\u1ea5p theo \u0111\u01b0\u1eddng ch\u00e9o nh\u01b0 h\u00ecnh v\u1ebd. Di\u1ec7n t\u00edch h\u00ecnh nh\u1eadn \u0111\u01b0\u1ee3c b\u1eb1ng 5\/8 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u. Bi\u1ebft di\u1ec7n t\u00edch ph\u1ea7n t\u00f4 m\u00e0u l\u00e0 18 cm2. T\u00ednh di\u1ec7n t\u00edch t\u1edd gi\u1ea5y ban \u0111\u1ea7u. 119","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00e0i gi\u1ea3i : Khi g\u1ea5p t\u1edd gi\u1ea5y h\u00ecnh ch\u1eef nh\u1eadt theo \u0111\u01b0\u1eddng ch\u00e9o (\u0111\u01b0\u1eddng n\u00e9t \u0111\u1ee9t) th\u00ec ph\u1ea7n h\u00ecnh tam gi\u00e1c \u0111\u01b0\u1ee3c t\u00f4 m\u00e0u b\u1ecb x\u1ebfp ch\u1ed3ng l\u00ean nhau. Do \u0111\u00f3 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u l\u1edbn h\u01a1n di\u1ec7n t\u00edch h\u00ecnh nh\u1eadn \u0111\u01b0\u1ee3c ch\u00ednh l\u00e0 di\u1ec7n t\u00edch tam gi\u00e1c \u0111\u01b0\u1ee3c t\u00f4 m\u00e0u. Di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u gi\u1ea3m \u0111i b\u1eb1ng 1 - 5\/8 = 3\/8 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u. Do v\u1eady di\u1ec7n t\u00edch tam gi\u00e1c t\u00f4 m\u00e0u b\u1eb1ng 3\/8 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u, hay 3\/8 di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u b\u1eb1ng 18 cm2. V\u1eady di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ban \u0111\u1ea7u l\u00e0 : 18 : 3\/8 = 48 (cm2) B\u00e0i 130. Ch\u1ee9ng t\u1ecf r\u1eb1ng k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n sau 3 x 3 x 3 x ... x 3 (2000 th\u1eeba s\u1ed1 3) l\u00e0 s\u1ed1 c\u00f3 \u00edt h\u01a1n 1001 ch\u1eef s\u1ed1. L\u1eddi gi\u1ea3i. Trong t\u00edch s\u1ed1 A = 3 x 3 x 3 x ... x 3 g\u1ed3m 2000 th\u1eeba s\u1ed1 3, k\u1ebft h\u1ee3p t\u1eebng c\u1eb7p s\u1ed1 3 \u0111\u01b0\u1ee3c A = (3 x 3) (3 x 3) ... (3 x 3) = 9 x 9 x ... x 9 g\u1ed3m 1000 th\u1eeba s\u1ed1 9. X\u00e9t s\u1ed1 B = 9 x 10 x ...x 10 th\u1eeba s\u1ed1 10 n\u00ean s\u1ed1 B = 90...0 c\u00f3 999 ch\u1eef s\u1ed1 0 v\u00e0 1 ch\u1eef s\u1ed1 9, ngh\u0129a l\u00e0 c\u00f3 1000 ch\u1eef s\u1ed1. V\u00ec 9 < 10 n\u00ean A = 9 x 9 x ... x 9 < B = 9 x10 x ... x 10 V\u1eady s\u1ed1 A c\u00f3 \u00edt h\u01a1n 1001 ch\u1eef s\u1ed1. B\u00e0i 131. T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ABCD. Bi\u1ebft r\u1eb1ng di\u1ec7n t\u00edch ph\u1ea7n m\u00e0u v\u00e0ng l\u00e0 20cm2 v\u00e0 I l\u00e0 \u0111i\u1ec3m chia AB th\u00e0nh 2 ph\u1ea7n b\u1eb1ng nhau. L\u1eddi gi\u1ea3i. K\u00ed hi\u1ec7u S l\u00e0 di\u1ec7n t\u00edch c\u1ee7a m\u1ed9t h\u00ecnh. N\u1ed1i D v\u1edbi I. Qua I v\u00e0 C v\u1ebd c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng IP v\u00e0 CQ vu\u00f4ng g\u00f3c v\u1edbi BD, IH vu\u00f4ng g\u00f3c v\u1edbi DC. 120","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Ta c\u00f3 SADB = SCDB = 1\/2 SABCD SDIB = 1\/2 SADB (v\u00ec c\u00f3 chung \u0111\u01b0\u1eddng cao DA, IB = 1\/2 AB), SDIB = 1\/2 SDBC. M\u00e0 2 tam gi\u00e1c n\u00e0y c\u00f3 chung \u0111\u00e1y DB N\u00ean IP = 1\/2 CQ. SIDK = 1\/2 SCDK (v\u00ec c\u00f3 chung \u0111\u00e1y DK v\u00e0 IP = 1\/2 CQ) SCDI = SIDK + SDKC = 3SDIK. Ta c\u00f3 : SADI = 1\/2 AD x AI, SDIC = 1\/2 IH x DC M\u00e0 IH = AD, AI = 1\/2 DC, SDIC = 2SADI n\u00ean SADI = 3\/2 SDIK V\u00ec AIKD l\u00e0 ph\u1ea7n \u0111\u01b0\u1ee3c t\u00f4 m\u00e0u v\u00e0ng n\u00ean SAIKD = 20(cm2) SDAI + SIDK = 20(cm2) SDAI + 2\/3 SADI = 20(cm2) SDAI = (3 x 20)\/5 = 12 (cm2) M\u1eb7t kh\u00e1c SDAI = 1\/2 SDAB (c\u00f9ng chung chi\u1ec1u cao DA, AI = 1\/2 AB) = 1\/4 SABCD suy ra SABCD = 4 x SDAI = 4 x 12 = 48 (cm2). B\u00e0i 132. N\u1ebfu trong m\u1ed9t th\u00e1ng n\u00e0o \u0111\u00f3 m\u00e0 c\u00f3 3 ng\u00e0y th\u1ee9 b\u1ea3y \u0111\u1ec1u l\u00e0 c\u00e1c ng\u00e0y ch\u1eb5n th\u00ec ng\u00e0y 25 c\u1ee7a th\u00e1ng \u0111\u00f3 s\u1ebd l\u00e0 ng\u00e0y th\u1ee9 m\u1ea5y ? L\u1eddi gi\u1ea3i. C\u00e1ch 1. Trong m\u1ed9t th\u00e1ng n\u00e0o \u0111\u00f3 c\u00f3 ba ng\u00e0y th\u1ee9 b\u1ea3y l\u00e0 ng\u00e0y ch\u1eb5n th\u00ec ch\u1eafc ch\u1eafn c\u00f2n c\u00f3 hai ng\u00e0y th\u1ee9 B\u1ea3y l\u00e0 ng\u00e0y l\u1ebb. N\u0103m ng\u00e0y th\u1ee9 B\u1ea3y \u0111\u00f3 s\u1eafp x\u1ebfp nh\u01b0 sau : Th\u1ee9 B\u1ea3y Th\u1ee9 B\u1ea3y (1) ch\u1eb5n (2) l\u1ebb Th\u1ee9 B\u1ea3y Th\u1ee9 B\u1ea3y Th\u1ee9 B\u1ea3y (3) ch\u1eafn (4) l\u1ebb (5) ch\u1eb5n 121","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 S\u1ed1 ng\u00e0y nhi\u1ec1u nh\u1ea5t trong m\u1ed9t th\u00e1ng l\u00e0 31 ng\u00e0y. Th\u00e1ng n\u00e0y c\u00f3 4 tu\u1ea7n v\u00e0 3 ng\u00e0y. N\u1ebfu th\u1ee9 b\u1ea3y \u0111\u1ea7u ti\u00ean l\u00e0 ng\u00e0y m\u00f9ng 4 th\u00ec th\u00e1ng \u0111\u00f3 s\u1ebd c\u00f3 s\u1ed1 ng\u00e0y l\u00e0: 4 + 7 x 4 = 32 (ng\u00e0y) ; tr\u00e1i v\u1edbi l\u1ecbch th\u00f4ng th\u01b0\u1eddng. V\u00ec th\u1ebf th\u1ee9 b\u1ea3y \u0111\u1ea7u ti\u00ean (1) ph\u1ea3i l\u00e0 ng\u00e0y m\u00f9ng 2 ; th\u1ee9 7 th\u1ee9 t\u01b0 s\u1ebd l\u00e0 ng\u00e0y: 2 + 7 x 3 = 23 V\u1eady ng\u00e0y 25 c\u1ee7a th\u00e1ng \u0111\u00f3 l\u00e0 ng\u00e0y th\u1ee9 hai. C\u00e1ch 2. L\u1eadp b\u1ea3ng theo tu\u1ea7n l\u1ec5 : 1234567 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 Trong 3 c\u1ed9t \u0111\u1ea7u ti\u00ean ch\u1ec9 c\u00f3 c\u1ed9t 2 th\u00edch h\u1ee3p v\u1edbi \u0111\u1ea7u b\u00e0i to\u00e1n. C\u1ed9t n\u00e0y c\u00f3 5 ng\u00e0y th\u1ee9 b\u1ea3y. V\u00ec ng\u00e0y 23 l\u00e0 th\u1ee9 b\u1ea3y, n\u00ean ng\u00e0y 25 l\u00e0 th\u1ee9 hai. B\u00e0i 133. B\u1ed1n b\u1ea1n Xu\u00e2n, H\u1ea1, Thu, \u0110\u00f4ng c\u00f3 t\u1ea5t c\u1ea3 61 vi\u00ean bi. Xu\u00e2n c\u00f3 s\u1ed1 bi \u00edt nh\u1ea5t, \u0110\u00f4ng c\u00f3 s\u1ed1 bi nhi\u1ec1u nh\u1ea5t v\u00e0 l\u00e0 s\u1ed1 l\u1ebb, Thu c\u00f3 s\u1ed1 bi g\u1ea5p 9 l\u1ea7n s\u1ed1 bi c\u1ee7a H\u1ea1. H\u00e3y cho bi\u1ebft m\u1ed7i b\u1ea1n c\u00f3 bao nhi\u00eau vi\u00ean bi ? L\u1eddi gi\u1ea3i. + S\u1ed1 bi c\u1ee7a Thu g\u1ea5p 9 l\u1ea7n s\u1ed1 bi c\u1ee7a H\u1ea1 n\u00ean t\u1ed5ng s\u1ed1 bi c\u1ee7a Thu v\u00e0 H\u1ea1 l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n. T\u1ed1ng s\u1ed1 bi c\u1ee7a b\u1ed1n b\u1ea1n l\u00e0 s\u1ed1 l\u1ebb, s\u1ed1 bi c\u1ee7a \u0110\u00f4ng l\u00e0 s\u1ed1 l\u1ebb, t\u1ed5ng s\u1ed1 bi c\u1ee7a H\u1ea1 v\u00e0 Thu l\u00e0 s\u1ed1 l\u1ebb ; do \u0111\u00f3 s\u1ed1 bi c\u1ee7a Xu\u00e2n ph\u1ea3i l\u00e0 s\u1ed1 ch\u1eb5n. + S\u1ed1 bi c\u1ee7a H\u1ea1 ph\u1ea3i l\u00e0 s\u1ed1 b\u00e9 h\u01a1n 4 v\u00ec n\u1ebfu s\u1ed1 \u0111\u00f3 l\u00e0 4 th\u00ec s\u1ed1 bi c\u1ee7a Thu l\u00e0 4 x 9 = 36. Khi \u0111\u00f3 \u00edt nh\u1ea5t \u0110\u00f4ng c\u00f3 s\u1ed1 bi l\u00e0 37 th\u00ec ch\u1ec9 ri\u00eang t\u1ed5ng s\u1ed1 bi c\u1ee7a Thu v\u00e0 \u0110\u00f4ng \u0111\u00e3 v\u01b0\u1ee3t qu\u00e1 t\u1ed5ng s\u1ed1 bi c\u1ee7a b\u1ed1n b\u1ea1n (36 + 37 = 73 > 61). + N\u1ebfu s\u1ed1 bi c\u1ee7a Xu\u00e2n l\u00e0 2 th\u00ec s\u1ed1 bi c\u1ee7a H\u1ea1 l\u00e0 3, s\u1ed1 bi c\u1ee7a Thu l\u00e0 27 (3 x 9 = 27) S\u1ed1 bi c\u1ee7a \u0110\u00f4ng l\u00e0 : 61 - (2 + 3 + 27) = 29 (vi\u00ean). 122","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00e0i 134. Thay c\u00e1c ch\u1eef c\u00e1i d\u01b0\u1edbi \u0111\u00e2y b\u1edfi c\u00e1c ch\u1eef s\u1ed1 (ch\u1eef c\u00e1i kh\u00e1c nhau th\u00ec thay b\u1edfi c\u00e1c ch\u1eef s\u1ed1 kh\u00e1c nhau) sao cho k\u1ebft qu\u1ea3 c\u00e1c ph\u00e9p t\u00ednh d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ea1t gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t. CHUC + MUNG + THAY + CO + NHAN + NGAY - 20 - 11 L\u1eddi gi\u1ea3i. V\u00ec N xu\u1ea5t hi\u1ec7n \u1edf nh\u1eefng h\u00e0ng cao nh\u1ea5t v\u00e0 nhi\u1ec1u l\u1ea7n nh\u1ea5t n\u00ean N ph\u1ea3i b\u1eb1ng 9 \u0111\u1ec3 k\u1ebft qu\u1ea3 l\u1edbn nh\u1ea5t. Ti\u1ebfp \u0111\u00f3 C xu\u1ea5t hi\u1ec7n \u1edf h\u00e0ng cao nh\u1ea5t c\u00f2n l\u1ea1i gi\u1ed1ng M v\u00e0 T nh\u01b0ng C c\u00f2n \u1edf hai h\u00e0ng kh\u00e1c n\u1eefa n\u00ean C b\u1eb1ng 8. N\u1ebfu M l\u00e0 7 th\u00ec T l\u00e0 6 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i, k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p to\u00e1n kh\u00f4ng thay \u0111\u1ed5i. V\u1edbi l\u1eadp lu\u1eadn nh\u01b0 tr\u00ean th\u00ec H b\u1eb1ng 5, U b\u1eb1ng 4 v\u00e0 G l\u00e0 3. T\u1eeb \u0111\u00f3 A b\u1eb1ng 2, Y b\u1eb1ng 1 v\u00e0 O l\u00e0 0. V\u1eady ta c\u00f3 2 \u0111\u00e1p s\u1ed1 : 8548 + 6493 + 7521 + 80 + 9529 + 9321 - 20 - 11 = 41461 v\u00e0 8548 + 7493 + 6521 + 80 + 9529 + 9321 - 20 - 11 = 41461 B\u00e0i 135 : Th\u0103ng \u0111\u1ed1 Long bi\u1ebft \u0111\u01b0\u1ee3c s\u1ed1 h\u1ecdc sinh c\u1ee7a tr\u01b0\u1eddng Th\u0103ng cu\u1ed1i n\u0103m h\u1ecdc v\u1eeba r\u1ed3i c\u00f3 bao nhi\u00eau h\u1ecdc sinh \u0111\u01b0\u1ee3c nh\u1eadn th\u01b0\u1edfng ? Bi\u1ebft r\u1eb1ng s\u1ed1 h\u1ecdc sinh \u0111\u01b0\u1ee3c nh\u1eadn th\u01b0\u1edfng l\u00e0 s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 v\u00e0 r\u1ea5t th\u00fa v\u1ecb l\u00e0 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m, ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb gi\u1ed1ng nhau. N\u1ebfu nh\u00e2n s\u1ed1 n\u00e0y v\u1edbi 6 th\u00ec \u0111\u01b0\u1ee3c t\u00edch l\u00e0 s\u1ed1 c\u0169ng c\u00f3 ba ch\u1eef s\u1ed1 v\u00e0 trong t\u00edch \u0111\u00f3 c\u00f3 m\u1ed9t ch\u1eef s\u1ed1 2. B\u00e0i gi\u1ea3i : G\u1ecdi s\u1ed1 phi t\u00ecm l\u00e0 aba(a kh\u00e1c b;a ; b nh\u1ecf ho\u1eb7c b\u1eb1ng 9). Theo \u0111\u1ea7u b\u00e0i ta c\u00f3: aba x 6 = deg (d kh\u00e1c 0 ; d; e; g nh\u1ecf h\u01a1n ho\u1eb7c b\u1eb1ng 9). N\u1ebfu a l\u1edbn h\u01a1n ho\u1eb7c b\u1eb1ng 2 th\u00ec t\u00edch nhi\u1ec1u h\u01a1n 3 ch\u1eef s\u1ed1.V\u1eady a = 1. Ta c\u00f3 1b1x 6 = deg ( deg c\u00f3 m\u1ed9t ch\u1eef s\u1ed1 2). Do \u0111\u00f3 : g = 1 x 6 = 6 v\u00e0 d l\u1edbn h\u01a1n ho\u1eb7c b\u1eb1ng 6. V\u00ec th\u1ebf : e = 2 V\u00ec b x 6 = n\u00ean b = 2 ho\u1eb7c b = 7. N\u1ebfu b = 2 th\u00ec 121 x 6 = 726 (\u0110\u00fang) N\u1ebfu b = 7 th\u00ec 171 x 6 = 1026 (Lo\u1ea1i) V\u1eady s\u1ed1 h\u1ecdc s\u1ecbnh nh\u1eadn th\u01b0\u1edfng l\u00e0 121 b\u1ea1n. B\u00e0i 136 : Em h\u00e3y di chuy\u1ec3n hai que di\u00eam l\u1ea1i \u0111\u00fang v\u1ecb tr\u00ed \u0111\u1ec3 k\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh l\u00e0 \u0111\u00fang : B\u00e0i gi\u1ea3i : C\u00e1ch 1 : Ta chuy\u1ec3n que di\u00eam \u1edf gi\u1eefa ch\u1eef s\u1ed1 8 \u0111\u1ec3 c\u00f3 ch\u1eef s\u1ed1 0. L\u1ea5y que di\u00eam \u0111\u00f3 gh\u00e9p v\u00e0o ch\u1eef s\u1ed1 5 c\u1ee7a s\u1ed1 502 \u0111\u1ec3 \u0111\u01b0\u1ee3c s\u1ed1 602. L\u1ea5y 1 que di\u00eam \u1edf ch\u1eef s\u1ed1 3 c\u1ee7a s\u1ed1 2003 v\u00e0 123","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \u0111\u1eb7t v\u00e0o v\u1ecb tr\u00ed kh\u00e1c c\u1ee7a ch\u1eef s\u1ed1 3 \u0111\u00f3 \u0111\u1ec3 chuy\u1ec3n s\u1ed1 2003 th\u00e0nh s\u1ed1 2002, ta c\u00f3 ph\u00e9p t\u00ednh \u0111\u00fang : C\u00e1ch 2 : Ta chuy\u1ec3n que di\u00eam \u1edf gi\u1eefa s\u1ed1 8 \u0111\u1ec3 c\u00f3 ch\u1eef s\u1ed1 0. l\u1ea5y que di\u00eam \u0111\u00f3 gh\u00e9p v\u00e0o ch\u1eef s\u1ed1 5 c\u1ee7a s\u1ed1 502 \u0111\u1ec3 \u0111\u01b0\u1ee3c s\u1ed1 602. L\u1ea5y 1 que di\u00eam \u1edf ch\u1eef s\u1ed1 2 c\u1ee7a s\u1ed1 602 v\u00e0 \u0111\u1eb7t v\u00e0o v\u1ecb tr\u00ed kh\u00e1c c\u1ee7a ch\u1eef s\u1ed1 2 \u0111\u00f3 \u0111\u1ec3 chuy\u1ec3n s\u1ed1 602 th\u00e0nh s\u1ed1 603, ta c\u00f3 ph\u00e9p t\u00ednh \u0111\u00fang : B\u00e0i 137 : M\u1ed9t b\u1ea1n ch\u1ecdn hai s\u1ed1 t\u1ef1 nhi\u00ean tu\u1ef3 \u00fd, t\u00ednh t\u1ed5ng c\u1ee7a ch\u00fang r\u1ed3i l\u1ea5y t\u1ed5ng \u0111\u00f3 nh\u00e2n v\u1edbi ch\u00ednh n\u00f3. B\u1ea1n \u1ea5y c\u0169ng l\u00e0m t\u01b0ng t\u1ef1 \u0111\u1ed1i v\u1edbi hi\u1ec7u c\u1ee7a hai s\u1ed1 m\u00e0 m\u00ecnh \u0111\u00e3 ch\u1ecdn \u0111\u00f3. Cu\u1ed1i c\u00f9ng c\u1ed9ng hai t\u00edch t\u00ecm \u0111\u01b0\u1ee3c v\u1edbi nhau. H\u1ecfi r\u1eb1ng t\u1ed5ng c\u1ee7a hai t\u00edch \u0111\u00f3 l\u00e0 s\u1ed1 ch\u1eb5n hay s\u1ed1 l\u1ebb ? V\u00ec sao ? B\u00e0i gi\u1ea3i : S\u1ebd x\u1ea3y ra m\u1ed9t trong hai tr\u01b0\u1eddng h\u1ee3p : C hai s\u1ed1 \u0111\u1ec1u ch\u1eb5n (ho\u1eb7c \u0111\u1ec1u l\u1ebb) ; m\u1ed9t s\u1ed1 ch\u1eb5n v\u00e0 m\u1ed9t s\u1ed1 l\u1ebb. a) Hai s\u1ed1 ch\u1eb5n (ho\u1eb7c hai s\u1ed1 l\u1ebb). T\u1ed5ng, hi\u1ec7u c\u1ee7a hai s\u1ed1 \u0111\u00f3 l\u00e0 s\u1ed1 ch\u1eb5n. S\u1ed1 ch\u1eb5n nh\u00e2n v\u1edbi ch\u00ednh n\u00f3 \u0111\u01b0\u1ee3c s\u1ed1 ch\u1eb5n. Do \u0111\u00f3 c\u1ed9ng hai t\u00edch (l\u00e0 hai s\u1ed1 ch\u1eb5n) ph\u1ea3i \u0111\u01b0\u1ee3c s\u1ed1 ch\u1eb5n. b) M\u1ed9t s\u1ed1 ch\u1eb5n v\u00e0 m\u1ed9t s\u1ed1 l\u1ebb. T\u1ed5ng, hi\u1ec7u c\u1ee7a ch\u00fang \u0111\u1ec1u l\u00e0 s\u1ed1 l\u1ebb. S\u1ed1 l\u1ebb nh\u00e2n v\u1edbi ch\u00ednh n\u00f3 \u0111\u01b0\u1ee3c s\u1ed1 l\u1ebb. Do \u0111\u00f3 c\u1ed9ng hai t\u00edch (l\u00e0 hai s\u1ed1 l\u1ebb) ph\u1ea3i \u0111\u01b0\u1ee3c s\u1ed1 ch\u1eb5n. V\u1eady theo \u0111i\u1ec1u ki\u1ec7n c\u1ee7a b\u00e0i to\u00e1n th\u00ec k\u1ebft qu\u1ea3 c\u1ee7a b\u00e0i to\u00e1n ph\u1ea3i l\u00e0 s\u1ed1 ch\u1eb5n. B\u00e0i 138 : a) H\u00e3y ph\u00e2n t\u00edch 20 th\u00e0nh t\u1ed5ng c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean sao cho t\u00edch c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean \u1ea5y c\u0169ng b\u1eb1ng 20. b) B\u1ea1n c\u00f3 th\u1ec3 l\u00e0m nh\u01b0 th\u1ebf v\u1edbi b\u1ea5t k\u00ec s\u1ed1 t\u1ef1 nhi\u00ean n\u00e0o \u0111\u01b0\u1ee3c kh\u00f4ng ? B\u00e0i gi\u1ea3i : Ph\u00e2n t\u00edch 20 th\u00e0nh t\u00edch c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean kh\u00e1c 1. 20 = 2 x 2 x 5 = 4 x 5 = 10 x 2 Tr\u01b0\u1eddng h\u1ee3p : 2 x 2 x 5 = 20 th\u00ec t\u1ed5ng c\u1ee7a ch\u00fang l\u00e0 : 2+ 2 + 5 = 9. V\u1eady \u0111\u1ec3 t\u1ed5ng b\u1eb1ng 20 th\u00ec ph\u1ea3i th\u00eam v\u00e0o : 20 - 9 = 11, ta thay 11 b\u1eb1ng t\u1ed5ng c\u1ee7a 11 s\u1ed1 1 khi \u0111\u00f3 t\u00edch s\u1ebd kh\u00f4ng thay \u0111\u1ed5i. L\u00ed lu\u1eadn t\u01b0\u01a1ng t\u1ef1 v\u1edbi c\u00e1c tr\u01b0\u1eddng h\u1ee3p : 20 = 4 x 5 v\u00e0 20 = 10 x 2. Ta c\u00f3 3 c\u00e1ch ph\u00e2n t\u00edch nh\u01b0 sau : C\u00e1ch 1 : 20 = 2 x 2 x 5 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1. 20 = 2 + 2 + 5 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1. C\u00e1ch 2 : 20 = 4 x 5 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1. 20 = 4 + 5 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1. C\u00e1ch 3 : 124","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 20 = 10 x 2 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1. 20 = 10 + 2 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1. b) M\u1ed9t s\u1ed1 chia h\u1ebft cho 1 v\u00e0 ch\u00ednh n\u00f3 s\u1ebd kh\u00f4ng l\u00e0m \u0111\u01b0\u1ee3c nh\u01b0 tr\u00ean v\u00ec t\u00edch c\u1ee7a 1v\u1edbi ch\u00ednh n\u00f3 lu\u00f4n nh\u1ecf h\u01a1n t\u1ed5ng c\u1ee7a 1 v\u1edbi ch\u00ednh n\u00f3. B\u00e0i 139 : T\u00ecm s\u1ed1 t\u1ef1 nhi\u00ean a nh\u1ecf nh\u1ea5t sao cho a chia cho 2 d\u01b0 1, chia cho 5 d\u01b0 1, chia cho 7 d\u01b0 3 v\u00e0 chia h\u1ebft cho 9. B\u00e0i gi\u1ea3i : V\u00ec a chia cho 2 d\u01b0 1 n\u00ean a l\u00e0 s\u1ed1 l\u1ebb. V\u00ec a chia cho 5 d\u01b0 1 n\u00ean a c\u00f3 t\u1eadn c\u00f9ng l\u00e0 1 ho\u1eb7c 6. Do \u0111\u00f3 a ph\u1ea3i c\u00f3 t\u1eadn c\u00f9ng l\u00e0 1. - N\u1ebfu a l\u00e0 s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 th\u00ec do a chia h\u1ebft cho 9 n\u00ean a = 81, lo\u1ea1i v\u00ec 81 : 7 = 11 d\u01b0 4 (tr\u00e1i v\u1edbi \u0111i\u1ec1u ki\u1ec7n c\u1ee7a \u0111\u1ec1 b\u00e0i). - N\u1ebfu a l\u00e0 s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 th\u00ec \u0111\u1ec3 a nh\u1ecf nh\u1ea5t th\u00ec ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m ph\u1ea3i l\u00e0 1. Khi \u0111\u00f3 \u0111\u1ec3 a chia h\u1ebft cho 9 th\u00ec theo d\u1ea5u hi\u1ec7u chia h\u1ebft cho 9 ta c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c phi l\u00e0 7 (\u0111\u1ec3 1 + 7 + 1 = 9 9). V\u00ec 171 : 7 = 24 d\u01b0 3 n\u00ean a = 171. V\u1eady s\u1ed1 ph\u1ea3i t\u00ecm nh\u1ecf nh\u1ea5t th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n c\u1ee7a \u0111\u1ec1 b\u00e0i l\u00e0 171. B\u00e0i 140 : S\u1ed1 n\u00e0y n\u1eb1m trong ph\u1ea1m vi c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean t\u1eeb 1 \u0111\u1ebfn 58. Khi vi\u1ebft \\\"n\u00f3\\\" kh\u00f4ng s\u1eed d\u1ee5ng c\u00e1c ch\u1eef s\u1ed1 1 ; 2 ; 3. Ngo\u00e0i ra \\\"n\u00f3\\\" l\u00e0 s\u1ed1 l\u1ebb v\u00e0 kh\u00f4ng chia h\u1ebft cho c\u00e1c s\u1ed1 3 ; 5 ; 7. V\u1eady \\\"n\u00f3\\\" l\u00e0 s\u1ed1 n\u00e0o ? B\u00e0i gi\u1ea3i : N\u00f3 l\u00e0 s\u1ed1 l\u1ebb n\u1eb1m trong ph\u1ea1m vi c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean t\u1eeb 1 \u0111\u1ebfn 58, khi vi\u1ebft n\u00f3 kh\u00f4ng s\u1eed d\u1ee5ng c\u00e1c ch\u1eef s\u1ed1 1 ; 2 ; 3 n\u00ean n\u00f3 c\u00f3 th\u1ec3 l\u00e0 : 5 ; 7 ; 9 ; 45 ; 47 ; 49 ; 55 ; 57 ; 59. Nh\u01b0ng n\u00f3 kh\u00f4ng chia h\u1ebft cho 3 ; 5 ; 7 n\u00ean trong c\u00e1c s\u1ed1 tr\u00ean ch\u1ec9 c\u00f3 s\u1ed1 47 l\u00e0 th\u1ecfa m\u00e3n. V\u1eady n\u00f3 l\u00e0 s\u1ed1 47. B\u00e0i 141 : B\u1ea1n T\u00e2n th\u1ef1c hi\u1ec7n ph\u00e9p chia m\u1ed9t s\u1ed1 cho 12 th\u00ec d\u01b0 1 v\u00e0 chia s\u1ed1 \u0111\u00f3 cho 14 th\u00ec d\u01b0 2. B\u1ea1n h\u00e3y ch\u1ee9ng t\u1ecf T\u00e2n \u0111\u00e3 l\u00e0m sai \u00edt nh\u1ea5t m\u1ed9t ph\u00e9p t\u00ednh. B\u00e0i gi\u1ea3i : A = 12 x p + 1 = 14 x q + 2 (v\u1edbi p ; q l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean) Ta th\u1ea5y : 12 x p l\u00e0 s\u1ed1 ch\u1eb5n n\u00ean A = 12 x p + 1 l\u00e0 s\u1ed1 l\u1ebb. 14 x q l\u00e0 s\u1ed1 ch\u1eb5n n\u00ean A = 14 x q + 2 l\u00e0 s\u1ed1 ch\u1eb5n. A kh\u00f4ng th\u1ec3 v\u1eeba l\u1ebb v\u1eeba ch\u1eb5n n\u00ean ch\u1eafc ch\u1eafn c\u00f3 \u00edt nh\u1ea5t m\u1ed9t ph\u00e9p t\u00ednh sai. B\u00e0i 142 : V\u01b0\u1eddn c\u00e2y b\u00e0 Th\u01b0\u1ee3c c\u00f3 s\u1ed1 c\u00e2y ch\u01b0a \u0111\u1ebfn 100 v\u00e0 c\u00f3 4 lo\u1ea1i c\u00e2y : xo\u00e0i, cam, m\u00edt, b\u01b0\u1edfi. Trong \u0111\u00f3 s\u1ed1 c\u00e2y xo\u00e0i chi\u1ebfm 1\/5 s\u1ed1 c\u00e2y, s\u1ed1 c\u00e2y cam chi\u1ebfm 1\/6 s\u1ed1 c\u00e2y, s\u1ed1 c\u00e2y b\u01b0\u1edfi chi\u1ebfm1\/4 s\u1ed1 c\u00e2y v\u00e0 c\u00f2n l\u1ea1i l\u00e0 m\u00edt. H\u00e3y t\u00ednh xem m\u1ed7i lo\u1ea1i c\u00f3 bao nhi\u00eau c\u00e2y ? B\u00e0i gi\u1ea3i : S\u1ed1 c\u00e2y xo\u00e0i chi\u1ebfm 1\/5 s\u1ed1 c\u00e2y, s\u1ed1 c\u00e2y cam chi\u1ebfm 1\/6 s\u1ed1 c\u00e2y, s\u1ed1 c\u00e2y b\u01b0\u1edfi chi\u1ebfm 1\/4 s\u1ed1 c\u00e2y n\u00ean s\u1ed1 c\u00e2y trong v\u01b0\u1eddn ph\u1ea3i chia h\u1ebft cho 4, 5, 6. M\u00e0 6 = 2 x 3 n\u00ean s\u1ed1 125","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 c\u00e2y trong v\u01b0\u1eddn ph\u1ea3i chia h\u1ebft cho 3, 4, 5. S\u1ed1 nh\u1ecf h\u01a1n 100 chia h\u1ebft cho 3, 4, 5 l\u00e0 60. V\u1eady s\u1ed1 c\u00e2y trong v\u01b0\u1eddn l\u00e0 60 c\u00e2y. S\u1ed1 c\u00e2y xo\u00e0i trong v\u01b0\u1eddn l\u00e0 : 60 : 5 = 12 (c\u00e2y) S\u1ed1 c\u00e2y cam trong v\u01b0\u1eddn l\u00e0 : 60 : 6 = 10 (c\u00e2y) S\u1ed1 c\u00e2y b\u01b0\u1edfi trong v\u01b0\u1eddn l\u00e0 : 60 : 4 = 15 (c\u00e2y) S\u1ed1 c\u00e2y m\u00edt trong V\u01b0\u1eddn l\u00e0 : 60 - (12 + 10 + 15) = 23 (c\u00e2y) \u0110\u00e1p s\u1ed1 : xo\u00e0i : 12 c\u00e2y ; cam : 10 c\u00e2y ; b\u01b0\u1edfi : 15 c\u00e2y ; m\u00edt : 23 c\u00e2y B\u00e0i 143 : B\u1ea1n h\u00e3y chia t\u1ea5m b\u00eca b\u00ean d\u01b0\u1edbi th\u00e0nh 6 ph\u1ea7n gi\u1ed1ng h\u1ec7t nhau v\u1ec1 h\u00ecnh d\u1ea1ng v\u00e0 m\u1ed7i ph\u1ea7n c\u00f3 m\u1ed9t b\u00f4ng hoa. B\u00e0i gi\u1ea3i : Ta chia t\u1ea5m b\u00eca th\u00e0nh c\u00e1c \u00f4 vu\u00f4ng nh\u1ecf b\u1eb1ng nhau nh\u01b0 trong h\u00ecnh v\u1ebd sau : Nh\u00ecn h\u00ecnh v\u1ebd ta th\u1ea5y t\u1ed5ng s\u1ed1 \u00f4 vu\u00f4ng nh\u1ecf l\u00e0 18 \u00f4. Do \u0111\u00f3 khi chia t\u1ea5m b\u00eca th\u00e0nh 6 ph\u1ea7n gi\u1ed1ng h\u1ec7t nhau v\u1ec1 h\u00ecnh d\u1ea1ng th\u00ec m\u1ed7i ph\u1ea7n s\u1ebd c\u00f3 s\u1ed1 \u00f4 l\u00e0 : 18 : 6 = 3 (\u00f4) v\u00e0 h\u00ecnh d\u1ea1ng m\u1ed7i ph\u1ea7n ph\u1ea3i c\u00f3 d\u1ea1ng h\u00ecnh ch\u1eef L. nh\u01b0 sau : (c\u1eaft theo \u0111\u01b0\u1eddng m\u00e0u) Ta c\u00f3 c\u00e1ch chia B\u00e0i 144 : Cho d\u00e3y c\u00e1c s\u1ed1 ch\u1eb5n li\u00ean ti\u1ebfp : 2 ; 4 ; 6 ; 8 ; ... ; 998 ; 1000. Sau khi \u0111i\u1ec1n th\u00eam c\u00e1c d\u1ea5u + ho\u1eb7c d\u1ea5u - v\u00e0o gi\u1eefa c\u00e1c s\u1ed1 theo \u00fd m\u00ecnh, b\u1ea1n B\u00ecnh th\u1ef1c hi\u1ec7n ph\u00e9p t\u00ednh \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 2002 ; b\u1ea1n Minh th\u1ef1c hi\u1ec7n ph\u00e9p t\u00ednh \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 2006. Ai t\u00ednh \u0111\u00fang ? B\u00e0i gi\u1ea3i : T\u1eeb 2 \u0111\u1ebfn 1000 c\u00f3 : (1000 - 2) : 2 + 1 = 500 (s\u1ed1 ch\u1eb5n) T\u1ed5ng c\u00e1c s\u1ed1 \u0111\u00f3 : N = (1000 + 2) x 500 : 2 = 250500. S\u1ed1 n\u00e0y chia h\u1ebft cho 4. Khi thay + a th\u00e0nh - a th\u00ec N b\u1ecb gi\u1ea3m \u0111i a x 2 c\u0169ng l\u00e0 s\u1ed1 chia h\u1ebft cho 4. Do \u0111\u00f3 k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng ph\u1ea3i l\u00e0 s\u1ed1 chia h\u1ebft cho 4. B\u00ecnh t\u00ednh \u0111\u01b0\u1ee3c 2002, Minh t\u00ednh \u0111\u01b0\u1ee3c 2006 \u0111\u1ec1u l\u00e0 s\u1ed1 kh\u00f4ng chia h\u1ebft cho 4. V\u1eady c\u1ea3 hai b\u1ea1n \u0111\u1ec1u t\u00ednh sai. B\u00e0i 145 : Tr\u01b0\u1eddng Ti\u1ec3u h\u1ecdc Xu\u00e2n \u0110\u1ec9nh tham gia h\u1ed9i kh\u1ecfe Ph\u00f9 \u0110\u1ed5ng, c\u00f3 11 h\u1ecdc sinh \u0111o\u1ea1t gi\u1ea3i, trong \u0111\u00f3 c\u00f3 6 em gi\u00e0nh \u00edt nh\u1ea5t 2 gi\u1ea3i, c\u00f3 4 em gi\u00e0nh \u00edt nh\u1ea5t 3 gi\u1ea3i v\u00e0 c\u00f3 2 em gi\u00e0nh m\u1ed7i ng\u01b0\u1eddi 4 gi\u1ea3i. H\u1ecfi tr\u01b0\u1eddng \u0111\u00f3 \u0111\u00e3 gi\u00e0nh \u0111\u01b0\u1ee3c bao nhi\u00eau gi\u1ea3i ? B\u00e0i gi\u1ea3i : C\u00f3 11 em \u0111o\u1ea1t gi\u1ea3i, trong \u0111\u00f3 c\u00f3 6 em gi\u00e0nh \u00edt nh\u1ea5t 2 gi\u1ea3i n\u00ean s\u1ed1 h\u1ecdc sinh gi\u00e0nh m\u1ed7i em 1 gi\u1ea3i l\u00e0 : 11 - 6 = 5 (em). C\u00f3 6 em gi\u00e0nh \u00edt nh\u1ea5t 2 gi\u1ea3i, trong \u0111\u00f3 c\u00f3 4 em gi\u00e0nh \u00edt nh\u1ea5t 3 126","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 gi\u1ea3i n\u00ean s\u1ed1 em gi\u00e0nh m\u1ed7i em 2 gi\u1ea3i l\u00e0 : 6 - 4 = 2 (em). C\u00f3 4 em gi\u00e0nh \u00edt nh\u1ea5t 3 gi\u1ea3i trong \u0111\u00f3 c\u00f3 c\u00f3 2 em gi\u00e0nh m\u1ed7i em 4 gi\u1ea3i n\u00ean s\u1ed1 em gi\u00e0nh m\u1ed7i em 3 gi\u1ea3i l\u00e0 : 4 - 2 = 2 (em). S\u1ed1 em gi\u00e0nh t\u1eeb 1 \u0111\u1ebfn 4 gi\u1ea3i l\u00e0 : 5 + 2 + 2 + 2 = 11 (em). Do \u0111\u00f3 kh\u00f4ng c\u00f3 em n\u00e0o gi\u00e0nh \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n 4 gi\u1ea3i. V\u1eady s\u1ed1 gi\u1ea3i m\u00e0 tr\u01b0\u1eddng \u0111\u00f3 gi\u00e0nh \u0111\u01b0\u1ee3c l\u00e0 : 1 x 5 + 2 x 2 + 3 x 2 + 4 x 2 = 23 (gi\u1ea3i). B\u00e0i 146 : T\u00ednh nhanh t\u1ed5ng sau : B\u00e0i gi\u1ea3i : \u0110\u1eb7t t\u1ed5ng tr\u00ean b\u1eb1ng A ta c\u00f3 : B B\u00e0i 147 : T\u00ecm s\u1ed1 t\u1ef1 nhi\u00ean a \u0111\u1ec3 bi\u1ec3u th\u1ee9c : A = 4010 - 2005 : (2006 - a) c\u00f3 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t. B\u00e0i gi\u1ea3i : \u0110\u1ec3 A c\u00f3 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t th\u00ec s\u1ed1 tr\u1eeb 2005 : (2006 - a) c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 4010. \u0110\u1ec3 2005 : (2006 - a) c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t th\u00ec s\u1ed1 chia (2006 - a) c\u00f3 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t l\u1edbn h\u01a1n 0. V\u1eady 2006 - a = 1 a = 2006 - 1 a = 2005. B\u00e0i 148 : M\u1ed9t l\u1edbp c\u00f3 29 h\u1ecdc sinh. Trong m\u1ed9t l\u1ea7n ki\u1ec3m tra ch\u00ednh t\u1ea3. b\u1ea1n Xu\u00e2n m\u1eafc 9 l\u1ed7i, c\u00f2n c\u00e1c b\u1ea1n trong l\u1edbp m\u1eafc \u00edt l\u1ed7i h\u01a1n. Ch\u1ee9ng minh r\u1eb1ng : Trong l\u1edbp c\u00f3 \u00edt nh\u1ea5t 4 b\u1ea1n c\u00f3 s\u1ed1 l\u1ed7i b\u1eb1ng nhau (k\u1ec3 c\u1ea3 tr\u01b0\u1eddng h\u1ee3p s\u1ed1 l\u1ed7i b\u1eb1ng 0). B\u00e0i gi\u1ea3i : V\u00ec c\u00e1c b\u1ea1n trong l\u1edbp \u0111\u1ec1u c\u00f3 \u00edt l\u1ed7i h\u01a1n Xu\u00e2n, n\u00ean c\u00e1c b\u1ea1n ch\u1ec9 c\u00f3 s\u1ed1 l\u1ed7i t\u1eeb 0 \u0111\u1ebfn 8. Tr\u1eeb Xu\u00e2n ra th\u00ec s\u1ed1 b\u1ea1n c\u00f2n l\u1ea1i l\u00e0 : 29 - 1 = 28 (b\u1ea1n). N\u1ebfu chia c\u00e1c b\u1ea1n c\u00f2n l\u1ea1i th\u00e0nh c\u00e1c nh\u00f3m theo 127","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 s\u1ed1 l\u1ed7i th\u00ec t\u1ed1i \u0111a c\u00f3 9 nh\u00f3m. N\u1ebfu m\u1ed7i nh\u00f3m c\u00f3 kh\u00f4ng qu\u00e1 3 b\u1ea1n th\u00ec 9 nh\u00f3m s\u1ebd c\u00f3 kh\u00f4ng qu\u00e1 3 x 9 = 27 (b\u1ea1n). \u0110i\u1ec1u n\u00e0y m\u00e2u thu\u1eabn v\u1edbi s\u1ed1 b\u1ea1n c\u00f2n l\u1ea1i l\u00e0 28 b\u1ea1n. Ch\u1ee9ng t\u1ecf \u00edt nh\u1ea5t ph\u1ea3i c\u00f3 m\u1ed9t nh\u00f3m c\u00f3 qu\u00e1 3 b\u1ea1n t\u1ee9c l\u00e0 trong l\u1edbp c\u00f3 \u00edt nh\u1ea5t c\u00f3 4 b\u1ea1n c\u00f3 s\u1ed1 l\u1ed7i b\u1eb1ng nhau. B\u00e0i 149 : H\u1ee3p t\u00e1c x\u00e3 H\u00f2a B\u00ecnh d\u1ef1 \u0111\u1ecbnh x\u00e2y d\u1ef1ng m\u1ed9t khu vui ch\u01a1i cho tr\u1ebb em trong x\u00e3. V\u00ec th\u1ebf h\u1ecd \u0111\u00e3 m\u1edf r\u1ed9ng m\u1ed9t m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt \u0111\u1ec3 di\u1ec7n t\u00edch g\u1ea5p ba l\u1ea7n di\u1ec7n t\u00edch ban \u0111\u1ea7u. Chi\u1ec1u r\u1ed9ng m\u1ea3nh \u0111\u1ea5t ch\u1ec9 c\u00f3 th\u1ec3 t\u0103ng l\u00ean g\u1ea5p \u0111\u00f4i n\u00ean ph\u1ea3i m\u1edf r\u1ed9ng th\u00eam chi\u1ec1u d\u00e0i. Khi \u0111\u00f3 m\u1ea3nh \u0111\u1ea5t tr\u1edf th\u00e0nh h\u00ecnh vu\u00f4ng. H\u00e3y t\u00ednh di\u1ec7n t\u00edch khu vui ch\u01a1i \u0111\u00f3. Bi\u1ebft r\u1eb1ng chu vi m\u1ea3nh \u0111\u1ea5t ban \u0111\u1ea7u l\u00e0 56 m. B\u00e0i gi\u1ea3i : G\u1ecdi m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt l\u00fac \u0111\u1ea7u l\u00e0 ABCD, khi m\u1edf r\u1ed9ng m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt \u0111\u1ec3 \u0111\u01b0\u1ee3c m\u1ea3nh \u0111\u1ea5t h\u00ecnh vu\u00f4ng APMN c\u00f3 c\u1ea1nh h\u00ecnh vu\u00f4ng g\u1ea5p 2 l\u1ea7n chi\u1ec1u r\u1ed9ng m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt ABCD v\u00e0 di\u1ec7n t\u00edch g\u1ea5p 3 l\u1ea7n di\u1ec7n t\u00edch m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt \u1ea5y. Khi \u0111\u00f3 di\u1ec7n t\u00edch c\u1ee7a c\u00e1c m\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt ABCD, DCHN, BPMH b\u1eb1ng nhau. M\u1ea3nh \u0111\u1ea5t h\u00ecnh ch\u1eef nh\u1eadt BPMH c\u00f3 \u0111\u1ed9 d\u00e0i c\u1ea1nh BH g\u1ea5p 2 l\u1ea7n \u0111\u1ed9 d\u00e0i c\u1ea1nh AD n\u00ean N\u1eeda chu vi m\u1ea3nh \u0111\u1ea5t ban \u0111\u1ea7u l\u00e0 56 m n\u00ean AD + AB = 56 : 2 = 28 (m). Ta c\u00f3 : Chi\u1ec1u r\u1ed9ng m\u1ea3nh \u0111\u1ea5t ban \u0111\u1ea7u (AD) l\u00e0 : 28 : (3 + 4) x 3 = 12 (m). C\u1ea1nh h\u00ecnh vu\u00f4ng APMN l\u00e0 : 12 x 2 = 24 (m). Di\u1ec7n t\u00edch khu vui ch\u01a1i l\u00e0 : 24 x 24 = 576 (m2). \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI M\u00d4N :TO\u00c1N L\u1edaP 5 Th\u1eddi gian: 90 ph\u00fat (kh\u00f4ng k\u1ec3 th\u1eddi gian giao \u0111\u1ec1) B\u00e0i 1(1,5 \u0111i\u1ec3m): T\u00ecm y bi\u1ebft: a) y \u2013 6 : 2 \u2013 ( 48 \u2013 24 x 2 : 6 \u2013 3) = 0 128","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 b) (7 x 13 + 8 x 13) : ( 9 2 \u2013 y) = 39 3 B\u00e0i 2 (2 \u0111i\u1ec3m):T\u00ednh nhanh: a) ( 1+3+5+7+\u2026+2003+2005) x (125 125 x 127 \u2013 127 127 x 125) 19,8 : 0,2x44,44x2x13,2 : 0,25 b) 3,3x88,88: 0,5x6,6 : 0,125x5 B\u00e0i 3 (2 \u0111i\u1ec3m): Ba xe \u00f4t\u00f4 ch\u1edf 147 h\u1ecdc sinh \u0111i tham quan. H\u1ecfi m\u1ed7i xe ch\u1edf bao nhi\u00eau h\u1ecdc sinh ? Bi\u1ebft r\u1eb1ng 2 s\u1ed1 h\u1ecdc sinh xe th\u1ee9 nh\u1ea5t b\u1eb1ng 3 s\u1ed1 h\u1ecdc sinh xe th\u1ee9 hai v\u00e0 b\u1eb1ng 4 s\u1ed1 h\u1ecdc sinh xe th\u1ee9 34 5 ba. B\u00e0i 4 (1 \u0111i\u1ec3m):T\u00ecm hai s\u1ed1 sao cho t\u1ed5ng c\u1ee7a ch\u00fang nh\u1ecf nh\u1ea5t , bi\u1ebft r\u1eb1ng m\u1ed7i s\u1ed1 c\u00f3 n\u0103m ch\u1eef s\u1ed1 v\u00e0 t\u1ed5ng c\u00e1c ch\u1eef s\u1ed1 c\u1ee7a hai s\u1ed1 \u0111\u00f3 l\u00e0 89. B\u00e0i 5 (1 \u0111i\u1ec3m):V\u1edbi ba m\u1ea3nh b\u00eca tr\u00ean \u0111\u00f3 vi\u1ebft c\u00e1c s\u1ed1 23, 79, v\u00e0 ab , ng\u01b0\u1eddi ta gh\u00e9p ch\u00fang th\u00e0nh c\u00e1c s\u1ed1 c\u00f3 s\u00e1u ch\u1eef s\u1ed1 kh\u00e1c nhau c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c. R\u1ed3i t\u00ednh t\u1ed5ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 n\u00e0y \u0111\u01b0\u1ee3c 2 989 896. T\u00ecm ab . B\u00e0i 6 (2,5 \u0111i\u1ec3m): H\u00ecnh vu\u00f4ng ABCD c\u00f3 c\u1ea1nh 6 cm. Tr\u00ean \u0111o\u1ea1n BD l\u1ea5y \u0111i\u1ec3m E v\u00e0 P sao cho BE = EP = PD. a) T\u00ednh di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng ABCD. b) T\u00ednh di\u1ec7n t\u00edch h\u00ecnh AECP. c) M l\u00e0 \u0111i\u1ec3m ch\u00ednh gi\u1eefa c\u1ea1nh PC, N l\u00e0 \u0111i\u1ec3m ch\u00ednh gi\u1eefa c\u1ea1nh DC. MD v\u00e0 NP c\u1eaft nhau t\u1ea1i I. So s\u00e1nh di\u1ec7n t\u00edch tam gi\u00e1c IPM v\u1edbi di\u1ec7n t\u00edch tam gi\u00e1c IDN. \u0110\u00c1P \u00c1N THI H\u1eccC SINH GI\u1eceI M\u00d4N :TO\u00c1N L\u1edaP 5 B\u00e0i 1(1,5 \u0111i\u1ec3m): (0,75\u0111i\u1ec3m) a) T\u00ednh \u0111\u00fang y = 40 (0,75\u0111i\u1ec3m) b) T\u00ednh \u0111\u00fang y = 4 2 3 B\u00e0i 2(2 \u0111i\u1ec3m): a) V\u00ec 125 125x127 \u2013 127 127x125 = 1001x125x127 \u2013 1001x127x125 = 0 n\u00ean : (1+3+5+...+2005)(125 125x127 \u2013 127 127x125) = 0 (1\u0111i\u1ec3m) 129","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 b)19,8 : 0,2x44,44x2x13,2 : 0,25 \uf03d 19,8x5x88,88x13,2x4 (1\u0111i\u1ec3m) 3,3x88,88: 0,5x6,6 : 0,125x5 3,3x88,88x2x6,6x8x5 \uf03d 19,8x5x88,88x13,2x4 \uf03d 19,8 \uf03d 3 3,3x88,88x13,2x4x2x5 3,3x2 B\u00e0i 3(2 \u0111i\u1ec3m): 2 \uf03d 12; 3 \uf03d 12; 4 \uf03d 12 (0,25\u0111i\u1ec3m) 3 18 4 16 5 15 - L\u1eadp lu\u1eadn \u0111\u00fang s\u1ed1 h\u1ecdc sinh xe I, II, III theo th\u1ee9 t\u1ef1 g\u1ed3m 18, 16, 15 ph\u1ea7n b\u1eb1ng nhau (ho\u1eb7c v\u1ebd s\u01a1 \u0111\u1ed3 \u0111o\u1ea1n th\u1eb3ng) (0,5\u0111i\u1ec3m) - T\u00ednh \u0111\u00fang s\u1ed1 h\u1ecdc sinh xe th\u1ee9 nh\u1ea5t (0,25\u0111i\u1ec3m) - T\u00ednh \u0111\u00fang s\u1ed1 h\u1ecdc sinh xe th\u1ee9 hai (0,25\u0111i\u1ec3m) - T\u00ednh \u0111\u00fang s\u1ed1 h\u1ecdc sinh xe th\u1ee9 ba (0,25\u0111i\u1ec3m) - K\u1ebft lu\u1eadn \u0111\u00fang (Xe I: 54 ; xe II: 48; xe III: 45 h\u1ecdc sinh) (0,25\u0111i\u1ec3m) B\u00e0i 4(1 \u0111i\u1ec3m): Hai s\u1ed1 \u0111\u00e3 cho c\u00f3: 5 x 2 = 10(ch\u1eef s\u1ed1) (0,25\u0111i\u1ec3m) Ch\u1eef s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0 9 n\u00ean t\u1ed5ng s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 th\u1ec3 c\u00f3 c\u1ee7a c\u00e1c ch\u1eef s\u1ed1 hai s\u1ed1 \u0111\u00f3 l\u00e0: 9 x 10 = 90 (0,25\u0111i\u1ec3m) V\u00ec 90 \u2013 89 = 1 n\u00ean trong 10 ch\u1eef s\u1ed1 c\u00f3 9 ch\u1eef s\u1ed1 9 v\u00e0 1 ch\u1eef s\u1ed1 8. (0,25\u0111i\u1ec3m) V\u1eady t\u1ed5ng nh\u1ecf nh\u1ea5t khi m\u1ed9t s\u1ed1 l\u00e0 99 999 v\u00e0 s\u1ed1 kia l\u00e0 89 999. (0,25\u0111i\u1ec3m) B\u00e0i 5(1 \u0111i\u1ec3m): -Ta l\u1eadp \u0111\u01b0\u1ee3c c\u00e1c s\u1ed1 2379ab;23ab79;79ab23;7923ab;ab2379;ab7923 n\u00ean s\u1ed1 v\u1ea1n c\u1ee7a t\u1ed5ng c\u0169ng nh\u01b0 s\u1ed1 ch\u1ee5c hay s\u1ed1 \u0111\u01a1n v\u1ecb \u0111\u1ec1u l\u00e0: ( 23 +79 + ab ) x 2 (0,25\u0111i\u1ec3m) - L\u1eadp lu\u1eadn \u0111\u01b0\u1ee3c t\u1ed5ng l\u00e0 : (23 + 79 + ab ) x 20 202 (0,25\u0111i\u1ec3m) - T\u00ecm \u0111\u01b0\u1ee3c : 23 + 79 + ab = 2 989 896 : 20 202 = 148 (0,25\u0111i\u1ec3m) - T\u00ednh \u0111\u01b0\u1ee3c ab = 148 \u2013 23 \u2013 79 = 46 (0,25\u0111i\u1ec3m) B\u00e0i 6(2,5 \u0111i\u1ec3m:) (0,25\u0111i\u1ec3m) V\u1ebd h\u00ecnh \u0111\u00fang a) T\u00ednh \u0111\u00fang di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng ABCD (0,25\u0111i\u1ec3m) b)-L\u1eadp lu\u1eadn \u0111\u00fang di\u1ec7n t\u00edch c\u00e1c tam gi\u00e1c ADP, APE, AEB, CPD, CPE, CEB b\u1eb1ng nhau v\u00e0 b\u1eb1ng 1 di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng ABCD. (0,5\u0111i\u1ec3m) 6 -L\u1eadp lu\u1eadn \u0111\u01b0\u1ee3c di\u1ec7n t\u00edch h\u00ecnh AECP b\u1eb1ng 1 di\u1ec7n t\u00edch h\u00ecnh (0,25\u0111i\u1ec3m) 3 vu\u00f4ng ABCD (0,25\u0111i\u1ec3m) -T\u00ednh \u0111\u00fang k\u1ebft qu\u1ea3 12cm2 (0,5\u0111i\u1ec3m) c)- L\u1eadp lu\u1eadn \u0111\u00fang di\u1ec7n t\u00edch tam gi\u00e1c DPM v\u00e0 DPN b\u1eb1ng nhau (0,5\u0111i\u1ec3m) - L\u1eadp lu\u1eadn \u0111\u00fang di\u1ec7n t\u00edch tam gi\u00e1c PMI v\u00e0 DNI b\u1eb1ng nhau 130","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 AB E P M C I N D *Ch\u00fa \u00fd :H\u1ecdc sinh c\u00f3 th\u1ec3 gi\u1ea3i c\u00e1ch kh\u00e1c, n\u1ebfu ch\u00ednh x\u00e1c b\u00b5i ki\u00d3m tra ch\u00e4n h\u00e4c sinh gi\u00e1i l\u00edp 5 \u00a7\u00d2 b\u00b5i C\u00a9u 1: (1\u00aei\u00d3m) \u00a7\u00e4c k\u00dc \u00aeo\u00b9n v\u00a8n sau v\u00b5 tr\u00b6 l\u00eai c\u00a9u h\u00e1i. \\\"Chi\u00d2u n\u00b5o c\u00f2ng v\u00cby, con chim ho\u00b9 mi \u00cay kh\u00abng bi\u00d5t t\u00f9 ph\u00acng n\u00b5o bay \u00ae\u00d5n \u00ae\u00cbu trong b\u00f4i t\u00c7m xu\u00a9n \u00eb v\u00ean nh\u00b5 t\u00abi m\u00b5 h\u00e3t. H\u00d7nh nh su\u00e8t m\u00e9t ng\u00b5y h\u00abm \u00ae\u00e3, n\u00e3 vui m\u00f5ng v\u00d7 \u00ae\u00b7 \u00ae\u00eec tha h\u00e5 rong ru\u00e6i bay ch\u00aci kh\u00bep tr\u00eai m\u00a9y gi\u00e3, u\u00e8ng bao nhi\u00aau n\u00edc su\u00e8i m\u00b8t trong khe n\u00f3i, n\u00d5m bao nhi\u00aau th\u00f8 qu\u00b6 ngon ng\u00e4t nh\u00cat \u00eb r\u00f5ng xanh. Cho n\u00aan nh\u00f7ng bu\u00e6i chi\u00d2u ti\u00d5ng h\u00e3t c\u00e3 khi \u00aam \u00ae\u00d2m, c\u00e3 khi r\u00e9n r\u00b7, nh m\u00e9t \u00aei\u00d6u \u00ae\u00b5n trong b\u00e3ng x\u00d5 m\u00b5 \u00a9m thanh vang m\u00b7i trong t\u00dcnh m\u00dech, t\u00ebng nh l\u00b5m rung \u00ae\u00e9ng l\u00edp s\u00acng l\u00b9nh m\u00ea m\u00ea r\u00f1 xu\u00e8ng c\u00e1 c\u00a9y.\\\" (Chim ho\u00b9 mi h\u00e3t - Theo Ng\u00e4c Giao) 1.\u00a7o\u00b9n v\u00a8n tr\u00aan c\u00e3 n\u00e9i dung ca ng\u00eei \u00aei\u00d2u g\u00d7? 2. \u00a7o\u00b9n v\u00a8n tr\u00aan c\u00e3 m\u00cay t\u00f5 l\u00b8y? C\u00a9u 2: T\u00d7m v\u00b5 ghi l\u00b9i c\u00b8c danh t\u00f5, \u00ae\u00e9ng t\u00f5 v\u00b5 t\u00ddnh t\u00f5 trong c\u00b8c c\u00a9u sau: \u00a7\u00d5n b\u00a9y gi\u00ea, Hoa v\u00c9n kh\u00abng qu\u00aan \u00ae\u00eec khu\u00abn m\u00c6t hi\u00d2n t\u00f5, m\u00b8i t\u00e3c b\u00b9c, \u00ae\u00abi m\u00bet \u00ae\u00c7y th\u00acng y\u00aau lo l\u00beng c\u00f1a \u00abng. C\u00a9u 3: X\u00b8c \u00ae\u00denh tr\u00b9ng ng\u00f7, ch\u00f1 ng\u00f7, v\u00de ng\u00f7 trong c\u00b8c c\u00a9u sau: 131","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 a. Ngo\u00b5i v\u00ean, ti\u00d5ng ma r\u00aci l\u00e9p \u00ae\u00e9p. b. Gi\u00f7a h\u00e5, n\u00e6i l\u00aan m\u00e9t h\u00dfn \u00ae\u00b6o nh\u00e1. c. V\u00d7 ch\u00a8m ch\u00d8 h\u00e4c t\u00cbp, b\u00b9n Lan c\u00f1a l\u00edp em \u00ae\u00b7 \u00ae\u00b9t h\u00e4c sinh gi\u00e1i. C\u00a9u 4: Cho m\u00e9t s\u00e8 t\u00f5 sau: Th\u00cbt th\u00b5, b\u00b9n b\u00cc, h h\u00e1ng, san s\u00ce, ch\u00a8m ch\u00d8, g\u00ben b\u00e3, b\u00b9n \u00ae\u00eang, ngoan ngo\u00b7n, gi\u00f3p \u00ae\u00ec, b\u00b9n \u00ae\u00e4c, kh\u00e3 kh\u00a8n. H\u00b7y s\u00bep x\u00d5p c\u00b8c t\u00f5 tr\u00aan \u00ae\u00a9y v\u00b5o 3 nh\u00e3m: a) T\u00f5 gh\u00d0p t\u00e6ng h\u00eep b) T\u00f5 gh\u00d0p ph\u00a9n lo\u00b9i c) T\u00f5 l\u00b8y. C\u00a9u 5. Em h\u00b7y vi\u00d5t l\u00aan nh\u00f7ng c\u00b6m ngh\u00dc c\u00f1a m\u00d7nh khi \u00ae\u00e4c xong \u00aeo\u00b9n th\u00ac: \\\"Nh\u00f7ng v\u00b9t n\u00acng m\u00b5u m\u00cbt L\u00f3a ch\u00ddn ng\u00cbp trong thung V\u00b5 ti\u00d5ng nh\u00b9c ng\u00f9a rung Su\u00e8t tri\u00d2n r\u00f5ng hoang d\u00b7\\\" (Ph\u00dda tr\u00edc c\u00e6ng tr\u00eai- Nguy\u00d4n \u00a7\u00d7nh \u00b6nh) C\u00a9u 6: Em h\u00b7y t\u00b6 l\u00b9i m\u00e9t k\u00fb v\u00cbt y\u00aau th\u00ddch nh\u00cat m\u00b5 em \u00ae\u00b7 \u00ae\u00eec t\u00c6ng trong m\u00e9t d\u00dep sinh nh\u00cbt m\u00d7nh. \u00a7\u00b8p \u00b8n b\u00b5i ki\u00d3m tra ch\u00e4n h\u00e4c sinh gi\u00e1i l\u00edp 5 N\u00a8m h\u00e4c 2008- 2009 m\u00abn: ti\u00d5ng vi\u00d6t C\u00a9u 1:(0,5\u00aei\u00d3m) - Ca ng\u00eei ti\u00d5ng h\u00e3t v\u00b5 \u00ae\u00eai s\u00e8ng t\u00f9 do ph\u00e3ng kho\u00b8ng c\u00f1a chim ho\u00b9 mi.(0,25\u00ae) - B\u00e8n t\u00f5 l\u00b8y.(0,25\u00ae) C\u00a9u 2.(1\u00aei\u00d3m) Danh t\u00f5: B\u00a9y gi\u00ea, Hoa, khu\u00abn m\u00c6t, m\u00b8i t\u00e3c, \u00ae\u00abi m\u00bet, \u00abng (0,5\u00ae) \u00a7\u00e9ng t\u00f5: Qu\u00aan, th\u00acng y\u00aau, lo l\u00beng (0.25\u00ae) T\u00ddnh t\u00f5: Hi\u00d2n t\u00f5, b\u00b9c, \u00ae\u00c7y (0.25\u00ae) C\u00a9u 3(1,5\u00aei\u00d3m) L\u00b5m \u00ae\u00f3ng m\u00e7i c\u00a9u cho 0,5 \u00aei\u00d3m. a. Ngo\u00b5i v\u00ean,\/ ti\u00d5ng ma r\u00aci\/ l\u00e9p \u00ae\u00e9p. 132","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 TN CN VN b. Gi\u00f7a h\u00e5,\/ n\u00e6i l\u00aan\/ m\u00e9t h\u00dfn \u00ae\u00b6o nh\u00e1. TN VN CN c. V\u00d7 ch\u00a8m ch\u00d8 h\u00e4c t\u00cbp, b\u00b9n Lan c\u00f1a l\u00edp em \u00ae\u00b7 \u00ae\u00b9t h\u00e4c sinh gi\u00e1i TN CN VN C\u00a9u 4.(1\u00aei\u00d3m) a) T\u00f5 gh\u00d0p c\u00e3 ngh\u00dca t\u00e6ng h\u00eep: h h\u00e1ng, san s\u00ce, g\u00ben b\u00e3, gi\u00f3p \u00ae\u00ec(0,5\u00ae) b) T\u00f5 gh\u00d0p c\u00e3 ngh\u00dca ph\u00a9n lo\u00b9i: b\u00b9n \u00ae\u00eang, b\u00b9n \u00ae\u00e4c(0,25\u00ae) c) T\u00f5 l\u00b8y: th\u00cbt th\u00b5, ch\u00a8m ch\u00d8, ngoan ngo\u00b7n, kh\u00e3 kh\u00a8n(0,25\u00ae) C\u00a9u 5:(1 \u00aei\u00d3m) \\\"Nh\u00f7ng v\u00b9t n\u00acng m\u00b5u m\u00cbt L\u00f3a ch\u00ddn ng\u00cbp trong thung V\u00b5 ti\u00d5ng nh\u00b9c ng\u00f9a rung Su\u00e8t tri\u00d2n r\u00f5ng hoang d\u00b7\\\" (Ph\u00dda tr\u00edc c\u00e6ng tr\u00eai- Nguy\u00d4n \u00a7\u00d7nh \u00b6nh) HS n\u00aau \u00ae\u00eec: Ch\u00d8 b\u00bbng b\u00e8n c\u00a9u th\u00ac nhng t\u00b8c gi\u00b6 \u00ae\u00b7 mi\u00aau t\u00b6 \u00ae\u00eec m\u00e9t b\u00f8c tranh t\u00acng \u00ae\u00e8i ho\u00b5n ch\u00d8nh v\u00d2 v\u00ce \u00ae\u00d1p c\u00f1a ph\u00dda tr\u00edc c\u00e6ng tr\u00eai v\u00edi kh\u00abng gian tr\u00b6i r\u00e9ng( c\u00f1a tri\u00d2n r\u00f5ng, c\u00f1a v\u00b9t n\u00acng, c\u00f1a thung l\u00f3a), v\u00edi m\u00b5u s\u00bec \u00cap \u00f1 l\u00aan h\u00acng( m\u00b5u m\u00cbt, m\u00b5u l\u00f3a ch\u00ddn) v\u00b5 vang vang trong \u00ae\u00e3 l\u00b5 m\u00e9t kh\u00abng gian r\u00cat \u00ae\u00c6c trng v\u00b5 quen thu\u00e9c c\u00f1a v\u00efng n\u00f3i r\u00f5ng( ti\u00d5ng nh\u00b9c ng\u00f9a rung). B\u00f8c tranh t\u00dcnh l\u00c6ng nhng \u00c8n ch\u00f8a m\u00e9t s\u00f8c s\u00e8ng n\u00e9i l\u00f9c, m\u00e9t v\u00ce \u00ae\u00d1p l\u00beng s\u00a9u, tinh t\u00d5\u2026.. C\u00a9u 6. H\u00e4c sinh vi\u00d5t b\u00b5i v\u00a8n( kho\u00b6ng 20-25 d\u00dfng) t\u00b6 m\u00e9t k\u00fb v\u00cbt m\u00b5 m\u00d7nh y\u00aau th\u00ddch vi\u00d5t \u00ae\u00f3ng ki\u00d3u b\u00b5i v\u00a8n t\u00b6 \u00ae\u00e5 v\u00cbt, di\u00d4n t\u00b6 lu lo\u00b8t r\u00e2 r\u00b5ng. a, M\u00eb b\u00b5i(1\u00aei\u00d3m): gi\u00edi thi\u00d6u \u00ae\u00eec k\u00fb v\u00cbt m\u00d7nh y\u00aau th\u00ddch. V\u00cbt k\u00fb ni\u00d6m \u00cay do ai t\u00c6ng, t\u00c6ng khi n\u00b5o? b, Th\u00a9n b\u00b5i(3\u00aei\u00d3m) - T\u00b6 theo th\u00f8 t\u00f9 ch\u00c6t ch\u00cf, h\u00eep l\u00fd( t\u00b6 bao qu\u00b8t, t\u00b6 chi ti\u00d5t) 1\u00aei\u00d3m - Bi\u00d5t ch\u00e4n t\u00b6 nh\u00f7ng n\u00d0t c\u00f4 th\u00d3, n\u00e6i b\u00cbt nh\u00bbm\\\" V\u00cf\u201d l\u00b9i \u00ae\u00e5 v\u00cbt \u00ae\u00e3 th\u00cbt sinh \u00ae\u00e9ng, h\u00cap d\u00c9n. - T\u00b6 c\u00e3 t\u00a9m tr\u00b9ng. - B\u00e9c l\u00e9 c\u00b6m x\u00f3c, th\u00b8i \u00ae\u00e9, t\u00d7nh c\u00b6m c\u00f1a b\u00b6n th\u00a9n, c\u00e8 g\u00beng truy\u00d2n \u00ae\u00d5n ng\u00eai \u00ae\u00e4c c\u00b6m x\u00f3c, \u00can t\u00eeng \u00ae\u00d1p v\u00d2 v\u00cbt k\u00fb ni\u00d6m \u00ae\u00e3( 1\u00aei\u00d3m) c, K\u00d5t b\u00b5i(1\u00aei\u00d3m): Th\u00d3 hi\u00d6n \u00ae\u00f9\u00acc t\u00d7nh c\u00b6m y\u00aau qu\u00fd, tr\u00a9n tr\u00e4ng v\u00cbt k\u00fb ni\u00d6m v\u00edi nh\u00f7ng vi\u00d6c l\u00b5m v\u00b5 h\u00b5nh \u00ae\u00e9ng c\u00f4 th\u00d3\u2026. * Khuy\u00d5n kh\u00ddch nh\u00f7ng HS c\u00e3 m\u00eb b\u00b5i gi\u00b8n ti\u00d5p v\u00b5 k\u00d5t b\u00b5i m\u00eb r\u00e9ng + \u00a7i\u00d3m to\u00b5n b\u00b5i ti\u00d5ng vi\u00d6t ch\u00cam \u00aei\u00d3m 10 l\u00b5m tr\u00dfn \u00ae\u00d5n 0.5. 133","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 + \u00a7i\u00d3m to\u00b5n b\u00b5i ti\u00d5ng vi\u00d6t b\u00de tr\u00f5 \u00aei\u00d3m v\u00d2 ch\u00f7 x\u00cau v\u00b5 l\u00e7i ch\u00ddnh t\u00b6 nh sau: - Ch\u00f7 x\u00cau, tr\u00d7nh b\u00b5y b\u00c8n tr\u00f5 1 \u00aei\u00d3m (GV ch\u00cam linh \u00ae\u00e9ng) \u0110\u1ec1 thi v\u00e0 \u0110A HS gi\u1ecfi c\u1ea5p huy\u1ec7n M\u00d4N: Ti\u00d5ng vi\u00d6t Th\u1eddi gian l\u00e0m b\u00e0i: 90 ph\u00fat ( Kh\u00abng k\u00d3 th\u00eai gian giao \u00ae\u00d2) ..................................................... B\u00e0i 1 (2,5 \u0111i\u1ec3m): a)T\u00ecm nh\u1eefng t\u1eeb \u0111\u1ed3ng ngh\u0129a v\u00e0 tr\u00e1i ngh\u0129a v\u1edbi t\u1eeb\u201d C\u1ed1 \u00fd\u201d? b) Ch\u1ecdn c\u00e1c t\u1eeb sau \u0111\u1ec3 x\u1ebfp th\u00e0nh c\u00e1c nh\u00f3m t\u1eeb \u0111\u1ed3ng ngh\u0129a: ch\u1eb1m b\u1eb7p, lung lay, v\u1ed7 v\u1ec1, \u1ec9 eo, ch\u1ee9a chan, thi\u1ebft tha, ng\u1eadp tr\u00e0n, ca th\u00e1n, l\u1ea5p l\u00e1nh, l\u1ea1nh lung, \u00ea a, l\u1ea5p lo\u00e1, \u0111\u1ea7y \u1eafp, d\u1ed7 d\u00e0nh, da di\u1ebft, n\u1ed3ng n\u00e0n, long l\u00e1nh. B\u00e0i 2 (3,5 \u0111i\u1ec3m): a) C\u00e1c t\u1eeb \u0111\u01b0\u1ee3c g\u1ea1ch d\u01b0\u1edbi trong \u0111o\u1ea1n v\u0103n sau thu\u1ed9c t\u1eeb lo\u1ea1i g\u00ec? ( DT, \u0110T, TT, \u0110\u1ea1i t\u1eeb, QHT) Th\u1eddi gian tr\u00f4i \u0111i nhanh qu\u00e1. T\u00f4i \u0111\u00e3 tr\u01b0\u1edfng th\u00e0nh, \u0111\u00e3 l\u00e0 m\u1ed9t thanh ni\u00ean, \u0111\u00e3 c\u00f3 c\u00f4ng \u0103n vi\u1ec7c l\u00e0m, \u0111\u00e3 c\u00f3 xe m\u00e1y, \u0111\u00e3 ph\u00f3ng v\u00f9 v\u00f9 qua kh\u1eafp ph\u1ed1 ph\u01b0\u1eddng, th\u00ec t\u00f4i v\u1eabn c\u1ee9 nh\u1edb m\u00e3i nh\u1eefng k\u1ec9 ni\u1ec7m th\u1eddi \u1ea5u th\u01a1. T\u00f4i c\u1ee9 nh\u1edb m\u00e3i v\u1ec1 b\u00e0, v\u1ec1 s\u1ef1 th\u01b0\u01a1ng y\u00eau c\u1ee7a b\u00e0, v\u00e0 l\u00f2ng t\u00f4i c\u1ee9 b\u00f9i ng\u00f9i th\u01b0\u01a1ng nh\u1edb\u2026 b) Chia c\u00e1c t\u1eeb sau th\u00e0nh ba nh\u00f3m: DT; \u0110T; TT bi\u1ebft \u01a1n, \u00fd ngh\u0129a, v\u1eadt ch\u1ea5t, gi\u1ea3i lao, long bi\u1ebft \u01a1n, h\u1ecfi, \u0111i\u1ec1u, trao t\u1eb7ng, c\u00e2u h\u1ecfi, ng\u00e2y ng\u00f4, s\u1ef1 trao t\u1eb7ng, nh\u1ecf nhoi, ch\u1eafc, s\u1ed1ng \u0111\u1ed9ng. B\u00e0i 3 (3,5 \u0111i\u1ec3m): a) X\u00e1c \u0111\u1ecbnh ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef , tr\u1ea1ng ng\u1eef trong c\u00e2u sau: T\u1ed1i h\u00f4m \u1ea5y, v\u1eeba \u0103n c\u01a1m xong, m\u1ed9t thanh ni\u00ean to, cao, kho\u00e1c tr\u00ean m\u00ecnh chi\u1ebfc \u00e1o cho\u00e0ng \u0111en b\u01b0\u1edbc v\u1ed9i \u0111\u1ebfn \u0111\u1ecba \u0111i\u1ec3m \u0111\u00e3 h\u1eb9n. b) M\u1ed7i d\u1ea5u ph\u1ea9y trong c\u00e2u sau c\u00f3 t\u00e1c d\u1ee5ng g\u00ec? Tr\u01b0a, \u0103n c\u01a1m xong, t\u00f4i \u0111\u1ed9i chi\u1ebfc m\u0169 v\u1ea3i, h\u0103m h\u1edf b\u01b0\u1edbc ra kh\u1ecfi nh\u00e0. c) Ch\u1ec9 ra quan h\u1ec7 t\u1eeb dung sai trong c\u00e1c c\u00e2u sau v\u00e0 s\u1eeda l\u1ea1i cho \u0111\u00fang: - V\u00f9ng \u0111\u1ea5t n\u00e0y kh\u00f3 tr\u1ed3ng tr\u1ecdt n\u00ean c\u00f3 nhi\u1ec1u s\u1ecfi \u0111\u00e1 . - Tuy kh\u00f4ng h\u1ecdc b\u00e0i th\u00ec em b\u1ecb \u0111i\u1ec3m k\u00e9m. - V\u00ec c\u00f4ng vi\u1ec7c kh\u00f3 nh\u1ecdc nh\u01b0ng b\u1ed1 v\u1eabn ki\u00ean tr\u00ec theo \u0111u\u1ed5i. B\u00e0i 4 ( 4,5 \u00aei\u00d3m ) Cho kh\u1ed5 th\u01a1 sau: Ng\u00e0y mai 134","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Chi\u1ebfc \u0111\u1eadp l\u1edbn n\u1ed1i li\u1ec1n hai kh\u1ed1i n\u00fai Bi\u1ec3n s\u1ebd n\u1eb1m b\u1ee1 ng\u1ee1 gi\u1eefa cao nguy\u00ean S\u00f4ng \u0110\u00e0 chia \u00e1nh sang \u0111i mu\u00f4n ng\u1ea3 T\u1eeb c\u00f4ng tr\u00ecnh thu\u1ef7 \u0111i\u1ec7n l\u1edbn \u0111\u1ea7u ti\u00ean. \u01af\u1edbc m\u01a1 c\u1ee7a nh\u00e0 th\u01a1 Quang Huy c\u00f3 nh\u00e0 m\u00e1y thu\u1ef7 \u0111i\u1ec7n tr\u00ean song \u0110\u00e0 \u0111\u00e3 th\u00e0nh hi\u1ec7n th\u1ef1c. Em c\u1ea3m nh\u1eadn \u0111\u01b0\u1ee3c nh\u1eefng h\u00ecnh \u1ea3nh g\u00ec \u1edf hai d\u00f2ng th\u01a1 \u0111\u1ea7u c\u1ee7a kh\u1ed5 th\u01a1 tr\u00ean? T\u1eeb \u201c b\u1ee1 ng\u1ee1 \u201c c\u00f3 g\u00ec hay? B\u00e0i 5 ( 5 \u0111i\u1ec3m): Em \u0111\u00e3 t\u1eebng ch\u1ee9ng ki\u1ebfn c\u1ea3nh th\u00f4n qu\u00ea \u1ed3n \u00e0o, nh\u00f4n nh\u1ecbp, h\u1ed1i h\u1ea3 trong l\u00fac tr\u1eddi v\u1ea7n v\u0169 chu\u1ef7en m\u01b0a, r\u1ed3i c\u01a1n going \u1eadp \u0111\u1ebfn. H\u1ef9a t\u1ea3 l\u1ea1i c\u1ea3nh \u0111\u00f3. (\u0110i\u1ec3m ch\u1eef vi\u1ebft v\u00e0 tr\u00ecnh b\u00e0y 1 \u0111i\u1ec3m) \u0110\u00e1p \u00e1n \u0111\u1ec1 thi HS gi\u1ecfi m\u00f4n ti\u1ebfng Vi\u1ec7t C\u00e2u 1: a) \u0110\u1ed3ng ngh\u0129a: c\u1ed1 t\u00ecnh, c\u1ed1 \u00fd Tr\u00e1i ngh\u0129a: v\u00f4 \u00fd, s\u01a1 \u00fd,\u2026 b) Nh\u00f3m1: ch\u1eb1m b\u1eb7p, v\u1ed7 v\u1ec1, d\u1ed7 d\u00e0nh Nh\u00f3m 2: \u1ec9 eo, ca than, k\u00eau ca. Nh\u00f3m 3: ch\u1ee9a chan, ng\u1eadp tr\u00e0n, \u0111\u1ea7y \u1eafp Nh\u00f3m 4: l\u1ea5p l\u00e1nh, l\u1ea5p lo\u00e1, long l\u00e1nh Nh\u00f3m 5: da di\u1ebft, thi\u1ebft tha, n\u1ed3ng n\u00e0n C\u00e2u 2: a) DT: th\u1eddi gian, thanh ni\u00ean, xe m\u00e1y, ph\u1ed1 ph\u01b0\u1eddng, b\u00e0, k\u1ec9 ni\u1ec7m, s\u1ef1 th\u01b0\u01a1ng y\u00eau, long \u0110t: tr\u00f4i \u0111i, tr\u01b0\u1edfng th\u00e0nh, ph\u00f3ng, nh\u1edb, ng\u1eadm ng\u00f9i, th\u01b0\u01a1ng nh\u1edb TT: nhanh, v\u00f9 v\u00f9, th\u01a1 \u1ea5u \u0110\u1ea1i t\u1eeb: t\u00f4i, t\u00f4i QHT: qua, th\u00ec, v\u1ec1, v\u00e0, c\u1ee7a b)DT: long bi\u1ebft \u01a1n, \u00fd ngh\u0129a, v\u1eadt ch\u1ea5t, c\u00e2u h\u1ecfi, s\u1ef1 trao t\u1eb7ng, \u0111i\u1ec1u \u0110t: bi\u1ebft \u01a1n, h\u1ecfi, trao t\u1eb7ng, gi\u1ea3i lao, x\u1ed1n xang TT: ng\u00e2y ng\u00f4, nh\u1ecf nhoi, ch\u1eafc, s\u1ed1ng \u0111\u1ed9ng C\u00e2u 3: a) D\u1ea5u ph\u1ea9y th\u1ee9 nh\u1ea5t: T\u00e1ch hai tr\u1ea1ng ng\u1eef D\u1ea5u ph\u1ea9y th\u1ee9 hai: T\u00e1ch tr \u1ea1ng ng \u1eef v \u1edbi v \u1ebf c \u00e2u D\u1ea5u ph\u1ea9y th\u1ee9 ba: T\u00e1ch hai v\u1ecb ng \u1eef b) Tr\u1ea1ng ng\u1eef: T\u1ed1i h\u00f4m \u1ea5y Ch \u1ee7 ng \u1eef: m \u1ed9t thanh ni\u00ean cao, to, kho\u00e1c tr\u00ean m \u00ecnh chi\u1ebfc \u00e1o cho\u00e0ng \u0111en V\u1ecb ng\u1eef: b\u01b0\u1edbc v\u1ed9i \u0111\u1ebfn \u0111\u1ecba \u0111i\u1ec3m \u0111\u00e3 h\u1eb9n c) n\u00ean thay b\u1eb1ng v\u00ec - tuy thay b\u1eb1ng n\u1ebfu - v\u00ec thayb\u1eb1ng tuy C\u00e2u 4: - Chi\u1ebfc \u0111\u1eadp l\u1edbn n\u1ed1i li\u1ec1n hai kh\u1ed1i n\u00fai: C\u00e2u th\u01a1 n\u00f3i l\u00ean s\u1ef1 g\u1eafn b\u00f3 c\u1ee7a con ng\u01b0\u1eddi v\u1edbi thi\u00ean nhi\u00ean- con ng\u01b0\u1eddi l\u00e0m ch\u1ee7 thi\u00ean nhi\u00ean( chi\u1ebfc \u0111\u1eadp l\u1edbn l\u00e0 th\u00e0nh qu\u1ea3 lao \u0111\u1ed9ng c\u1ee7a con ng\u01b0\u1eddi, hai kh\u1ed1i n\u00fai l\u00e0 thi\u00ean nhi\u00ean hung v\u0129\u2026) - H\u00ecnh \u1ea3nh\u201d Bi\u1ec3n s\u1ebd n\u1eb1m\u2026\u201d n\u00f3i l\u00ean s\u1ee9c m\u1ea1nh c\u1ee7a con ng\u01b0\u1eddi \u0111\u00e3 l\u00e0m ch\u1ee7 khoa h\u1ecdc hi\u1ec7n \u0111\u1ea1i , \u0111\u00e3 \u0111\u1eafp \u0111\u1eadp ng\u0103n s\u00f4ng x\u00e2y d\u1ef1ng \u0111\u01b0\u1ee3c nh\u00e0 m\u00e1y thu\u1ef7 \u0111i\u1ec7n tr\u00ean cao nguy\u00ean. - B\u1eb1ng c\u00e1ch s\u1eed d\u1ee5ng ph\u00e9p nh\u00e2n ho\u00e1, t\u00e1c gi\u1ea3 \u0111\u00e3 g\u1eafn cho bi\u1ec3n t\u00e2m tr\u1ea1ng nh\u01b0 ng\u01b0\u1eddi. - Ng\u1ea1c nhi\u00ean v\u00ec s\u1ef1 xu\u1ea5t hi\u1ec7n l\u1ea1 lung c\u1ee7a m\u00ecnh gi\u1eefa gi\u1eefu v\u00f9ng \u0111\u1ea5t cao( \u201c b\u1ee1 ng\u1ee1\u201d ngh\u0129a l\u00e0 l\u1ea1 135","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 lung, ng\u01a1 ng\u00e1c, ch\u01b0a quen thu\u1ed9c. Gi\u1eefa cao nguy\u00ean song \u0110\u00e0 xu\u1ea5t hi\u1ec7n m\u1ed9t b\u1ec3 n\u01b0\u1edbc m\u00eanh m\u00f4ng d\u00e2ng cao, \u0111\u1ea7y \u1eafp sao kh\u00f4ng b\u1ee1 ng\u1ee1) - T\u1eeb\u201d b\u1ee1 ng\u1ee1\u201d trong b\u00e0i th\u01a1 c\u00f2n bi\u1ec3u l\u1ed9 ni\u1ec1m t\u1ef1 h\u00e0o, ng\u1ea1c nhi\u00ean \u0110\u1ec0 THI KSHSG L\u1edaP 5 - L\u1ea6N 4- N\u0102M H\u1eccC 2010- 2011 M\u00d4N: TI\u1ebeNG VI\u1ec6T Th\u1eddi gian l\u00e0m b\u00e0i: 60 ph\u00fat ( Kh\u00f4ng k\u1ec3 th\u1eddi gian ch\u00e9p \u0111\u1ec1) B\u00e0i 1: Ch\u1ec9 ra quan h\u1ec7 t\u1eeb d\u00f9ng sai trong c\u00e1c c\u00e2u sau v\u00e0 ch\u1eefa l\u1ea1i cho \u0111\u00fang. a) N\u1ebfu R\u00f9a bi\u1ebft m\u00ecnh ch\u1eadm ch\u1ea1p n\u00ean n\u00f3 c\u1ed1 g\u1eafng ch\u1ea1y th\u1eadt nhanh. b) Tuy Th\u1ecf c\u1eafm c\u1ed5 ch\u1ea1y mi\u1ebft n\u00ean n\u00f3 v\u1eabn kh\u00f4ng ch\u1ea1y \u0111u\u1ed5i k\u1ecbp R\u00f9a. c) C\u00e2u chuy\u1ec7n n\u00e0y kh\u00f4ng ch\u1ec9 h\u1ea5p d\u1eabn, th\u00fa v\u1ecb n\u00ean n\u00f3 c\u00f2n c\u00f3 \u00fd ngh\u0129a gi\u00e1o d\u1ee5c r\u1ea5t s\u00e2u s\u1eafc. B\u00e0i 2: Chia c\u00e1c t\u1eeb sau th\u00e0nh 3 nh\u00f3m: Danh t\u1eeb, \u0111\u1ed9ng t\u1eeb, t\u00ednh t\u1eeb. Bi\u1ebft \u01a1n, long bi\u1ebft \u01a1n, \u00fd ngh\u0129a, v\u1eadt ch\u1ea5t, gi\u1ea3i lao, h\u1ecfi, c\u00e2u h\u1ecfi, \u0111i\u1ec1u, trao t\u1eb7ng, s\u1ef1 trao t\u1eb7ng, ng\u00e2y ng\u00f4, nh\u1ecf nhoi. B\u00e0i 3: T\u00ecm \u0111\u1ea1i t\u1eeb trong \u0111o\u1ea1n h\u1ed9i tho\u1ea1i sau, n\u00f3i r\u00f5 t\u1eebng \u0111\u1ea1i t\u1eeb thay th\u1ebf cho t\u1eeb ng\u1eef n\u00e0o? Trong gi\u1edd ra ch\u01a1i, Nam h\u1ecfi B\u1eafc: - B\u1eafc \u01a1i, h\u00f4m qua b\u1ea1n \u0111\u01b0\u1ee3c m\u1ea5y \u0111i\u1ec3m m\u00f4n Ti\u1ebfng Anh? - T\u1edb \u0111\u01b0\u1ee3c m\u01b0\u1eddi, c\u00f2n c\u1eadu \u0111\u01b0\u1ee3c m\u1ea5y \u0111i\u1ec3m? B\u1eafc n\u00f3i. - T\u1edb c\u0169ng th\u1ebf. B\u00e0i 4: T\u00ecm ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef, tr\u1ea1ng ng\u1eef trong c\u00e1c c\u00e2u sau: a) T\u00f4i th\u1eadt di\u1ec5m ph\u00fac v\u00ec \u0111\u01b0\u1ee3c cu\u1ed9c s\u1ed1ng ban t\u1eb7ng m\u1ed9t c\u01a1 th\u1ec3 l\u00e0nh l\u1eb7n v\u00e0 kh\u1ecfe m\u1ea1nh. b) V\u1edbi \u0111\u00f4i m\u1eaft trong s\u00e1ng, t\u00f4i c\u00f3 th\u1ec3 ng\u1eafm nh\u00ecn nh\u1eefng ng\u01b0\u1eddi th\u00e2n y\u00eau v\u00e0 cu\u1ed9c s\u1ed1ng t\u01b0\u01a1i \u0111\u1eb9p xung quanh. B\u00e0i 5: Trong b\u00e0i H\u1ea1t g\u1ea1o l\u00e0ng ta, nh\u00e0 th\u01a1 Tr\u1ea7n \u0110\u0103ng Khoa c\u00f3 vi\u1ebft: H\u1ea1t g\u1ea1o l\u00e0ng ta C\u00f3 b\u00e3o th\u00e1ng b\u1ea3y C\u00f3 m\u01b0a th\u00e1ng ba Gi\u1ecdt m\u1ed3 h\u00f4i sa C\u00f3 m\u01b0a th\u00e1ng s\u00e1u N\u01b0\u1edbc nh\u01b0 ai n\u1ea5u Ch\u1ebft c\u1ea3 c\u00e1 c\u1edd Cua ngoi l\u00ean b\u1edd M\u1eb9 em xu\u1ed1ng c\u1ea5y\u2026 Em hi\u1ec3u \u0111o\u1ea1n th\u01a1 tr\u00ean nh\u01b0 th\u1ebf n\u00e0o? H\u00ecnh \u1ea3nh \u0111\u1ed1i l\u1eadp trong \u0111o\u1ea1n th\u01a1 g\u1ee3i cho em nh\u1eefng suy ngh\u0129 g\u00ec? ng\u01b0\u1eddi m\u1eb9 \u0111\u1ec3 l\u00e0m ra h\u1ea1t g\u1ea1o v\u00e0 ch\u00fang ta l\u1ea1i c\u00e0ng th\u00eam y\u00eau th\u01b0\u01a1ng m\u1eb9 bi\u1ebft bao nhi\u00eau! B\u00e0i 6: B\u00a9y gi\u00ea thong th\u00b6 \u201cM\u00d1 dang \u00ae\u00abi c\u00b8nh Con bi\u00d5n v\u00b5o trong M\u00d1 \u00aei l\u00aan \u00ae\u00c7u M\u00d1 ng\u00c8ng \u00ae\u00c7u tr\u00abng \u00a7\u00b5n con b\u00d0 t\u00dd 136","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00e4n di\u00d2u b\u00e4n qu\u00b9 L\u00ddu r\u00ddu theo sau\u201d (Ph\u00b9m H\u00e6) D\u00f9a v\u00b5o \u00aeo\u00b9n th\u00ac tr\u00aan, em h\u00b7y t\u00b6 \u00ae\u00b5n g\u00b5 con \u00aeang theo m\u00d1 \u00aei ki\u00d5m m\u00e5i. \u0110\u00c1P \u00c1N: B\u00e0i 1: (1\u0111) C\u00e2u a: T\u1eeb n\u1ebfu thay t\u1eeb v\u00ec C\u00e2u b: T\u1eeb n\u00ean thay t\u1eeb nh\u01b0ng C\u00e2u c: T\u1eeb n\u00ean thay t\u1eeb m\u00e0 B\u00e0i 2: (1,5\u0111) Danh t\u1eeb: long bi\u1ebft \u01a1n, \u00fd ngh\u0129a, v\u1eadt ch\u1ea5t, c\u00e2u h\u1ecfi, \u0111i\u1ec1u, s\u1ef1 trao t\u1eb7ng. \u0110\u1ed9ng t\u1eeb: Bi\u1ebft \u01a1n, gi\u1ea3i lao, h\u1ecfi, trao t\u1eb7ng T\u00ednh t\u1eeb: ng\u00e2y ng\u00f4, nh\u1ecf nhoi B\u00e0i 3: (1\u0111) - C\u00e2u \u201cB\u1eafc \u01a1i\u2026\u201d: t\u1eeb b\u1ea1n (danh t\u1eeb l\u00e2m th\u1eddi l\u00e0m \u0111\u1ea1i t\u1eeb) thay th\u1ebf cho t\u1eeb B\u1eafc. - C\u00e2u \u201cT\u1edb \u0111\u01b0\u1ee3c m\u01b0\u1eddi\u2026\u201d: T\u1edb thay th\u1ebf B\u1eafc; c\u1eadu thay th\u1ebf Nam. - C\u00e2u \u201cT\u1edb c\u0169ng th\u1ebf\u201d: T\u1edb thay th\u1ebf Nam; Th\u1ebf thay th\u1ebf c\u1ee5m t\u1eeb \u201c\u0111\u01b0\u1ee3c \u0111i\u1ec3m 10\u201d. B\u00e0i 4: (1,5) c) T\u00f4i th\u1eadt di\u1ec5m ph\u00fac v\u00ec \u0111\u01b0\u1ee3c cu\u1ed9c s\u1ed1ng ban t\u1eb7ng m\u1ed9t c\u01a1 th\u1ec3 l\u00e0nh l\u1eb7n v\u00e0 kh\u1ecfe CN VN TN m\u1ea1nh. d) V\u1edbi \u0111\u00f4i m\u1eaft trong s\u00e1ng, t\u00f4i c\u00f3 th\u1ec3 ng\u1eafm nh\u00ecn nh\u1eefng ng\u01b0\u1eddi th\u00e2n y\u00eau v\u00e0 cu\u1ed9c TN CN VN CN s\u1ed1ng t\u01b0\u01a1i \u0111\u1eb9p xung quanh. VN B\u00e0i5: (2\u0111) H\u1ea1t g\u1ea1o c\u1ee7a l\u00e0ng qu\u00ea ta \u0111\u00e3 t\u1eebng ph\u1ea3i tr\u1ea3i qua bi\u1ebft bao kh\u00f3 kh\u0103n th\u1eed th\u00e1ch to l\u1edbn c\u1ee7a thi\u00ean nhi\u00ean: n\u00e0o l\u00e0 b\u00e3o th\u00e0ng b\u1ea3y, n\u00e0o l\u00e0 m\u01b0a th\u00e1ng ba\u2026 H\u1ea1t g\u1ea1o c\u00f2n \u0111\u01b0\u1ee3c l\u00e0m ra t\u1eeb nh\u1eefng gi\u1ecdt m\u1ed3 h\u00f4i c\u1ee7a ng\u01b0\u1eddi m\u1eb9 hi\u1ec1n tr\u00ean c\u00e1nh \u0111\u1ed3ng n\u1eafng l\u1eeda: \u201cGi\u1ecdt m\u1ed3 h\u00f4i sa\/ C\u00f3 m\u01b0a th\u00e1ng s\u00e1u\/ N\u01b0\u1edbc nh\u01b0 ai n\u1ea5u\/ Ch\u1ebft c\u1ea3 c\u00e1 c\u1edd\/ Cua ngoi l\u00ean b\u1edd\/ M\u1eb9 em xu\u1ed1ng c\u1ea5y\u2026\u201d . H\u00ecnh \u1ea3nh \u0111\u1ed1i l\u1eadp \u1edf hai d\u00f2ng th\u01a1 cu\u1ed1i (\u201cCua ngoi l\u00ean b\u1edd\/M\u1eb9 em xu\u1ed1ng c\u1ea5y\u201d g\u1ee3i cho ta ngh\u0129 \u0111\u1ebfn s\u1ef1 v\u1ea5t v\u1ea3, gian tru\u00e2n c\u1ee7a ng\u01b0\u1eddi m\u1eb9 kh\u00f3 c\u00f3 g\u00ec so s\u00e1nh n\u1ed5i. Qua \u0111\u00f3 ch\u00fang ta c\u00e0ng c\u1ea3m nh\u1eadn s\u00e2u s\u1eafc \u0111\u01b0\u1ee3c n\u1ed7i v\u1ea5t v\u1ea3 c\u1ee7a B\u00e0i 6: (3\u0111) HS bi\u1ebft d\u1ef1a v\u00e0o \u00fd th\u01a1 l\u00e0m \u0111\u01b0\u1ee3c m\u1ed9t b\u00e0i v\u0103n mi\u00eau t\u1ea3 c\u00f3 \u0111\u1ee7 3 ph\u1ea7n \u0111\u1ea3m b\u1ea3o y\/ c kho\u1ea3ng 25 d\u00f2ng) ( GV linh \u0111\u1ed9ng cho \u0111i\u1ec3m ch\u00fa \u00fd h\u00e0nh v\u0103n v\u00e0 c\u00e1ch d\u00f9ng t\u1eeb ng\u1eef mi\u00eau t\u1ea3 c\u1ee7a h\u1ecdc sinh\u2026) 137","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \u00ae\u00d2 thi h\u00e4c sinh gi\u00e1i - kh\u00e8i 5 n\u00a8m h\u00e4c: 2005 \u2013 2006 M\u00abn: Ti\u00d5ng Vi\u00d6t Th\u00eai gian: 90\u2019 (kh\u00abng k\u00d3 th\u00eai gian ch\u00d0p \u00ae\u00d2) C\u00a9u1: (1 \u00aei\u00d3m) X\u00b8c \u00ae\u00denh t\u00f5 lo\u00b9i c\u00f1a nh\u00f7ng t\u00f5 \u00ae\u00eec g\u00b9ch ch\u00a9n: a, M\u00cay h\u00abm nay b\u00b9n \u00cay suy ngh\u00dc d\u00f7 l\u00bem. b, T\u00abi r\u00cat tr\u00a9n tr\u00e4ng nh\u00f7ng suy ngh\u00dc c\u00f1a b\u00b9n. c, Trong tr\u00cbn b\u00e3ng \u00ae\u00b8 chi\u00d2u nay, \u00ae\u00e9i l\u00edp 5A \u00ae\u00b7 chi\u00d5n th\u00beng gi\u00dfn gi\u00b7. d, S\u00f9 chi\u00d5n th\u00beng c\u00f1a \u00ae\u00e9i l\u00edp 5A, c\u00e3 c\u00abng \u00ae\u00e3ng g\u00e3p c\u00f1a c\u00b6 tr- \u00eang. C\u00a9u2: (2 \u00aei\u00d3m) Em h\u00b7y gi\u00b6i th\u00ddch \u00fd ngh\u00dca c\u00f1a c\u00b8c th\u00b5nh ng\u00f7 sau: a, M\u00e9t n\u00beng hai s\u00acng. b, \u00eb hi\u00d2n g\u00c6p l\u00b5nh. C\u00a9u3: (2 \u00aei\u00d3m) X\u00b8c \u00ae\u00denh tr\u00b9ng ng\u00f7, ch\u00f1 ng\u00f7, v\u00de ng\u00f7 trong c\u00b8c c\u00a9u sau v\u00b5 cho bi\u00d5t m\u00e7i c\u00a9u thu\u00e9c lo\u00b9i c\u00a9u g\u00d7 ? (C\u00a9u \u00ae\u00acn hay c\u00a9u gh\u00d0p \u00ae\u00bcng l\u00cbp, c\u00a9u gh\u00d0p ch\u00ddnh ph\u00f4 ) a, Tra, n\u00edc bi\u00d3n xanh l\u00ac v\u00b5 khi chi\u00d2u t\u00b5, bi\u00d3n \u00ae\u00e6i sang m\u00b5u xanh l\u00f4c. b, Tr\u00aan n\u00d2n c\u00b8t tr\u00beng tinh, n\u00aci ng\u00f9c c\u00ab Mai t\u00d7 xu\u00e8ng \u00ae\u00e3n \u00ae\u00eang bay c\u00f1a gi\u00c6c, m\u00e4c l\u00aan nh\u00f7ng b\u00abng hoa t\u00ddm. C\u00a9u4: (2 \u00aei\u00d3m) \u201c N\u00dfi tre \u00ae\u00a9u ch\u00deu m\u00e4c cong Tra n\u00aan \u00ae\u00b7 nh\u00e4n nh tr\u00abng l\u00b9 th\u00eang Lng tr\u00c7n ph\u00aci n\u00beng ph\u00aci s\u00acng C\u00e3 manh \u00b8o c\u00e9c tre nh\u00eang cho con \u201d < Tr\u00ddch \u201c Tre Vi\u00d6t Nam \u201d\u2013 Nguy\u00d4n Duy > Em th\u00cay \u00aeo\u00b9n th\u00ac tr\u00aan c\u00e3 nh\u00f7ng h\u00d7nh \u00b6nh n\u00b5o \u00ae\u00d1p ? H\u00b7y n\u00aau \u00fd ngh\u00dca \u00ae\u00d1p \u00ae\u00cf v\u00b5 s\u00a9u s\u00bec c\u00f1a nh\u00f7ng h\u00d7nh \u00b6nh \u00ae\u00e3? C\u00a9u 5: (3 \u00aei\u00d3m) M\u00efa xu\u00a9n, qu\u00aa h\u00acng em c\u00e3 r\u00cat nhi\u00d2u c\u00b6nh \u00ae\u00d1p. H\u00b7y t\u00b6 l\u00b9i m\u00e9t c\u00b6nh \u00ae\u00d1p m\u00b5 em y\u00aau th\u00ddch nh\u00cat ( b\u00b5i vi\u00d5t kho\u00b6ng 20 \u2013 25 d\u00dfng ). \u00ae\u00b8p \u00b8n m\u00abn: Ti\u00d5ng Vi\u00d6t \u2013 Kh\u00e8i 5 C\u00a9u1: a, \u00a7\u00e9ng t\u00f5 b, Danh t\u00f5 c, \u00a7\u00e9ng t\u00f5 d, Danh t\u00f5 C\u00a9u2: Gi\u00b6i th\u00ddch th\u00b5nh ng\u00f7. 138","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 a, \u201c M\u00e9t n\u00beng hai s\u00acng \u201d: Ch\u00d8 s\u00f9 lao \u00ae\u00e9ng v\u00cat v\u00b6, c\u00f9c nh\u00e4c c\u00f1a ng\u00eai n\u00abng d\u00a9n. b, \u201c \u00eb hi\u00d2n g\u00c6p l\u00b5nh\u201d: \u00fd n\u00e3i: \u00a8n \u00eb hi\u00d2n l\u00b5nh t\u00e8t b\u00f4ng s\u00cf g\u00c6p \u00ae\u00acc may m\u00ben, \u00ae\u00eec nhi\u00d2u ng\u00eai gi\u00f3p \u00ae\u00ec. C\u00a9u3: a, Tr\u00b9ng ng\u00f7 : Tra, khi chi\u00d2u t\u00b5. Ch\u00f1 ng\u00f7: N\u00edc bi\u00d3n, bi\u00d3n. V\u00de ng\u00f7: Xanh l\u00ac, \u00ae\u00e6i sang m\u00b5u xanh l\u00f4c. b, Tr\u00b9ng ng\u00f7: Tr\u00aan n\u00d2n c\u00b8t tr\u00beng tinh \u2013 n\u00aci ng\u00f9c c\u00ab Mai \u2026 gi\u00c6c. Ch\u00f1 ng\u00f7: Nh\u00f7ng b\u00abng hoa t\u00ddm V\u00de ng\u00f7: M\u00e4c l\u00aan C\u00a9u4: * Nh\u00f7ng h\u00d7nh \u00b6nh \u00ae\u00d1p: - \u00a7\u00a9u ch\u00deu m\u00e4c cong. - \u00a7\u00b7 nh\u00e4n nh ch\u00abng. - Lng tr\u00c7n ph\u00aci n\u00beng ph\u00aci s\u00acng - Manh \u00b8o c\u00e9c, nh\u00eang cho con. * N\u00aau b\u00cbt \u00ae\u00eec 2 \u00fd: - Tinh th\u00c7n b\u00cat khu\u00cat, kh\u00abng ch\u00deu khu\u00cat ph\u00f4c tr\u00edc k\u00ce th\u00ef c\u00f1a d\u00a9n t\u00e9c ta. - L\u00dfng y\u00aau th\u00acng \u00ae\u00efm b\u00e4c gi\u00e8ng n\u00dfi c\u00f1a d\u00a9n t\u00e9c ta. C\u00a9u5: a, M\u00eb b\u00b5i: - Gi\u00edi thi\u00d6u \u00ae\u00eec : C\u00b6nh qu\u00aa h\u00acng em r\u00cat \u00ae\u00d1p, nh\u00cat l\u00b5 v\u00b5o m\u00efa xu\u00a9n c\u00b6nh \u00ae\u00d1p m\u00b5 em th\u00ddch nh\u00cat \u00ae\u00e3 l\u00b5 c\u00b6nh g\u00d7 b, Th\u00a9n b\u00b5i: - N\u00aau \u00ae\u00eec c\u00b6nh \u00ae\u00d1p: Theo th\u00f8 t\u00f9 th\u00eai gian ho\u00c6c theo th\u00f8 t\u00f9 kh\u00abng gian. - Xem c\u00b6m x\u00f3c trong qu\u00b8 tr\u00d7nh mi\u00aau t\u00b6. c, K\u00d5t lu\u00cbn: - N\u00aau \u00ae\u00eec c\u00b6m ngh\u00dc ho\u00c6c t\u00d7nh c\u00b6m c\u00f1a b\u00b6n th\u00a9n ho\u00c6c c\u00f1a m\u00e4i ng\u00eai \u00ae\u00e8i v\u00edi c\u00b6nh \u00ae\u00d1p qu\u00aa em. \u00ae\u00d2 thi h\u00e4c sinh gi\u00e1i kh\u00e8i 5 M\u00abn thi: Ti\u00d5ng vi\u00d6t Th\u00eai gian: \\\"90' \\\" kh\u00abng k\u00d3 th\u00eai gian ch\u00d0p \u00ae\u00d2. B\u00b5i 1: (1 \u00aei\u00d3m). H\u00b7y t\u00d7m 4 t\u00f5 gh\u00d0p n\u00e3i v\u00d2 ph\u00c8m ch\u00cat c\u00f1a anh b\u00e9 \u00ae\u00e9i C\u00f4 H\u00e5? 139","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00b5i 2: (1 \u00aei\u00d3m). T\u00d7m tr\u00b9ng ng\u00f7, ch\u00f1 ng\u00f7, v\u00de ng\u00f7 trong c\u00a9u sau: M\u00e7i l\u00c7n T\u00d5t \u00ae\u00d5n, \u00ae\u00f8ng tr\u00edc nh\u00f7ng c\u00b8i chi\u00d5u b\u00b5y tranh l\u00b5ng H\u00e5 gi\u00b6i tr\u00aan c\u00b8c l\u00d2 ph\u00e8 H\u00b5 N\u00e9i, l\u00dfng t\u00abi th\u00cam th\u00dda m\u00e9t n\u00e7i bi\u00d5t \u00acn \u00ae\u00e8i v\u00edi nh\u00f7ng ng\u00eai ngh\u00d6 s\u00dc t\u00b9o h\u00d7nh c\u00f1a nh\u00a9n d\u00a9n. B\u00b5i 3: (2 \u00aei\u00d3m). Trong c\u00b8c c\u00a9u sau \u00ae\u00a9y c\u00a9u n\u00b5o l\u00b5 c\u00a9u gh\u00d0p ch\u00ddnh ph\u00f4, c\u00a9u n\u00b5o l\u00b5 c\u00a9u gh\u00d0p \u00ae\u00bcng l\u00cbp? Trong c\u00a9u \u00ae\u00e3, c\u00a9u n\u00b5o c\u00e3 th\u00d3 t\u00b8ch th\u00b5nh c\u00a9u \u00ae\u00acn \u00ae\u00acc? V\u00d7 sao? a\/ N\u00d5u em l\u00b5 di\u00d4n vi\u00aan th\u00d7 em s\u00cf \u00ae\u00e3ng vai c\u00ab gi\u00b8o. b\/ Kh\u00abng nh\u00f7ng Lan h\u00e4c gi\u00e1i m\u00b5 Lan c\u00dfn h\u00b8t r\u00cat hay. c\/ Vi\u00d6t \u00ae\u00e4c b\u00b8o, Nam xem ti vi. d\/ B\u00e8 em l\u00b5 k\u00dc s c\u00dfn m\u00d1 em l\u00b5 B\u00b8c s\u00dc. B\u00b5i 4: (2 \u00aei\u00d3m). \\\" V\u00d2 th\u00a8m l\u00b5ng B\u00b8c, l\u00b5ng Sen C\u00e3 h\u00b5ng r\u00a9m b\u00f4t th\u00bep l\u00aan l\u00f6a h\u00e5ng C\u00e3 con b\u00edm tr\u00beng l\u00een v\u00dfng C\u00e3 ch\u00efm \u00e6i ch\u00ddn v\u00b5ng ong s\u00bec tr\u00eai...\\\" Nguy\u00d4n \u00a7\u00f8c M\u00cbu. Tr\u00ddch \\\" V\u00d2 th\u00a8m nh\u00b5 B\u00b8c \\\". \u00a7o\u00b9n th\u00ac tr\u00aan cho em bi\u00d5t \u00ae\u00eec nh\u00f7ng g\u00d7? Em hi\u00d3u nh th\u00d5 n\u00b5o v\u00d2 c\u00f4m t\u00f5 \\\" th\u00bep l\u00aan l\u00f6a h\u00e5ng\\\". B\u00b5i 5: (4 \u00aei\u00d3m). Em \u00ae\u00b7 \u00ae\u00eec \u00aei th\u00a8m nhi\u00d2u c\u00b6nh \u00ae\u00d1p tr\u00aan \u00ae\u00cat n\u00edc ta. Em h\u00b7y t\u00b6 l\u00b9i m\u00e9t n\u00aci m\u00b5 em y\u00aau th\u00ddch nh\u00cat?. * Ghi ch\u00f3: B\u00b5i ch\u00f7 x\u00cau, b\u00c8n tr\u00f5 \u00aei 1 \u00aei\u00d3m \u0110\u1ec0 KH\u1ea2O S\u00c1T HSG L\u1edaP 5 (L\u1ea7n 2) - N\u0102M H\u1eccC 2010-2011 M\u00d4N: TI\u1ebeNG VI\u1ec6T (Th\u1eddi gian 60 ph\u00fat) C\u00e2u 1. X\u00e1c \u0111\u1ecbnh b\u1ed9 ph\u1eadn tr\u1ea1ng ng\u1eef, ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef c\u1ee7a m\u1ed7i c\u00e2u sau: \u0110\u00eam \u1ea5y, b\u00ean b\u1ebfp l\u1eeda h\u1ed3ng, c\u1ea3 gia \u0111\u00ecnh c\u00f9ng ng\u1ed3i n\u1ea5u b\u00e1nh ch\u01b0ng, tr\u00f2 chuy\u1ec7n r\u00f4m r\u1ea3 m\u00e3i \u0111\u1ebfn khuya. C\u00e2u 2. D\u1ef1a v\u00e0o th\u00e0nh ph\u1ea7n c\u1ea5u t\u1ea1o \u0111\u1ec3 ph\u00e2n lo\u1ea1i c\u00e1c c\u00e2u d\u01b0\u1edbi \u0111\u00e2y: 140","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 a. Tr\u00ean tr\u1eddi, m\u00e2y tr\u1eafng nh\u01b0 b\u00f4ng. b. V\u00ec nh\u1eefng \u0111i\u1ec1u mong \u01b0\u1edbc c\u1ee7a n\u00f3 \u0111\u00e3 th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c n\u00ean n\u00f3 r\u1ea5t vui. c. V\u00ec nh\u1eefng \u0111i\u1ec1u n\u00f3 \u0111\u00e3 h\u1ee9a v\u1edbi c\u00f4 gi\u00e1o, n\u00f3 quy\u1ebft t\u00e2m h\u1ecdc gi\u1ecfi. C\u00e2u 3. T\u00ecm, v\u00e0 n\u00eau r\u00f5 ch\u1ee9c n\u0103ng ng\u1eef ph\u00e1p c\u1ee7a m\u1ed7i danh t\u1eeb trong c\u00e2u sau: \u0110\u1ee9ng tr\u00ean \u0111\u00f3, B\u00e9 tr\u00f4ng th\u1ea5y con \u0111\u00f2, x\u00f3m ch\u1ee3, r\u1eb7ng tr\u00e2m b\u1ea7u v\u00e0 c\u1ea3 nh\u1eefng n\u01a1i ba m\u00e1 B\u00e9 \u0111ang \u0111\u00e1nh gi\u1eb7c. 3 \u201c B\u00b8t c\u00acm m\u00efa g\u00c6t Th\u00acm h\u00b5o giao th\u00abng\u201d Tr\u00c7n \u00a7\u00a8ng Khoa (H\u00b9t g\u00b9o l\u00b5ng ta- TV5- T\u00cbp 1 ). Em hi\u00d3u c\u00a9u th\u00ac tr\u00aan nh th\u00d5 n\u00b5o? C\u00e2u 5. M\u1eb9 l\u00e0 h\u00ecnh \u1ea3nh \u0111\u1eb9p nh\u1ea5t tr\u00ean \u0111\u1eddi. B\u1eb1ng t\u00ecnh y\u00eau v\u00e0 l\u00f2ng k\u00ednh tr\u1ecdng c\u1ee7a m\u00ecnh, em h\u00e3y vi\u1ebft m\u1ed9t b\u00e0i v\u0103n t\u1ea3 v\u1ec1 m\u1eb9 c\u1ee7a m\u00ecnh cho c\u00e1c b\u1ea1n trong l\u1edbp c\u00f9ng bi\u1ebft. \u0110\u00c1P \u00c1N TI\u1ebeNG VI\u1ec6T C\u00e2u 1. 1 \u0111i\u1ec3m \u0110\u00eam \u1ea5y, b\u00ean b\u1ebfp l\u1eeda h\u1ed3ng, c\u1ea3 gia \u0111\u00ecnh c\u00f9ng ng\u1ed3i n\u1ea5u b\u00e1nh ch\u01b0ng, tr\u00f2 chuy\u1ec7n r\u00f4m r\u1ea3 TN TN CN VN VN m\u00e3i \u0111\u1ebfn khuya. C\u00e2u 2. 1 \u0111i\u1ec3m a. Tr\u00ean tr\u1eddi, m\u00e2y tr\u1eafng nh\u01b0 b\u00f4ng. C\u00e2u \u0111\u01a1n b.V\u00ec nh\u1eefng \u0111i\u1ec1u mong \u01b0\u1edbc c\u1ee7a n\u00f3 \u0111\u00e3 th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c n\u00ean n\u00f3 r\u1ea5t vui. C\u00e2u gh\u00e9p a. V\u00ec nh\u1eefng \u0111i\u1ec1u n\u00f3 \u0111\u00e3 h\u1ee9a v\u1edbi c\u00f4 gi\u00e1o, n\u00f3 quy\u1ebft t\u00e2m h\u1ecdc gi\u1ecfi. C\u00e2u \u0111\u01a1n C\u00e2u 3. 2 \u0111i\u1ec3m \u0110\u1ee9ng tr\u00ean \u0111\u00f3, B\u00e9 tr\u00f4ng th\u1ea5y con \u0111\u00f2, x\u00f3m ch\u1ee3, r\u1eb7ng tr\u00e2m b\u1ea7u v\u00e0 c\u1ea3 nh\u1eefng n\u01a1i ba m\u00e1 B\u00e9 CN VN VN VN VN \u0111ang \u0111\u00e1nh gi\u1eb7c. VN C\u00a9u 4. ( 2 \u00aei\u00d3m). C\u00a9u th\u00ac di\u00d4n t\u00b6 v\u00edi t\u00cat c\u00b6 ni\u00d2m t\u00f9 h\u00b5o h\u00b9t g\u00b9o l\u00b5ng ta c\u00dfn th\u00cam c\u00b6 x\u00acng m\u00b8u c\u00f1a ng\u00eai n\u00abng d\u00a9n v\u00f5a s\u00b6n xu\u00cat v\u00f5a chi\u00d5n \u00ae\u00cau.Ng\u00eai n\u00abng d\u00a9n Vi\u00d6t Nam kh\u00abng ch\u00d8 c\u00c7n c\u00ef trong s\u00b6n xu\u00cat m\u00b5 c\u00dfn anh h\u00efng trong chi\u00d5n \u00ae\u00cau. C\u00e2u 5. 4 \u0111i\u1ec3m Vi\u1ebft \u0111\u00fang th\u1ec3 lo\u1ea1i v\u0103n t\u1ea3 ng\u01b0\u1eddi (t\u1ea3 m\u1eb9). T\u1ea3 cho c\u00e1c b\u1ea1n trong l\u1edbp bi\u1ebft 141","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 B\u00c0I THI TI\u1ebeNG VI\u1ec6T H\u1eccC SINH GI\u1eceIC\u1ea4P T\u1ec8NH L\u1edaP 5 c\u1ee5m 1 nam 2011 (Th\u1eddi gian 120\u2019 ) \u0110\u1ec1 thi 1 \u2013 T\u1eeb \u201cb\u00e0n t\u00ednh\u201d trong 2 c\u00e2u sau thu\u1ed9c t\u1eeb lo\u1ea1i ? a) Tr\u01b0\u1edbc \u0111\u00e2y, ng\u01b0\u1eddi ta d\u00f9ng b\u00e0n t\u00ednh, \u0111\u1ec3 t\u00ednh to\u00e1n b) C\u1ea7n ph\u1ea3i b\u00e0n t\u00ednh c\u1ea9n th\u1eadn tr\u01b0\u1edbc khi l\u00ean \u0111\u01b0\u1eddng 2 \u2013 Cho c\u00e2u , T\u00ecm ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef a) Nh\u1edd ch\u0103m h\u1ecdc, H\u01b0\u1edfng \u0111\u00e3 tr\u1edf th\u00e0nh h\u1ecdc sinh gi\u1ecfi b) L\u00fac \u1edf nh\u00e0,m\u1eb9 c\u0169ng l\u00e0 c\u00f4 gi\u00e1o c) Ng\u00e0y mai, l\u1edbp em c\u00f3 ti\u1ebft ch\u00ednh t\u1ea3 d) V\u1edbi \u0111\u1ea7u \u00f3c quan s\u00e1t tinh t\u1ebf v\u00e0 b\u00e0n tay kh\u00e9o l\u00e9o, ng\u01b0\u1eddi h\u1ecda s\u0129 \u0111\u00e3 v\u1ebd l\u00ean nh\u1eefng b\u1ee9c tranh tuy\u1ec7t \u0111\u1eb9p. 3 - T\u00ecm ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef, n\u00f3i r\u00f5 s\u1ef1 kh\u00e1c nhau v\u1ec1 ngh\u0129a c\u1ee7a 2 c\u00e2u d\u01b0\u1edbi. a) Chu\u1ed9t ch\u00e0o m\u1eb9 ch\u1ea1y ra kh\u1ecfi hang b) Chu\u1ed9t ch\u00e0o m\u1eb9, ch\u1ea1y ra kh\u1ecfi hang 4 - X\u00e1c \u0111\u1ecbnh ngh\u0129a c\u1ee7a t\u1eeb \u201cch\u1ea1y\u201d trong c\u00e2u sau a) B\u00e9 ch\u1ea1y lon ton b) T\u00e0u ch\u1ea1y b\u0103ng b\u0103ng tr\u00ean \u0111\u01b0\u1eddng ray c) \u0110\u1ed3ng h\u1ed3 ch\u1ea1y \u0111\u00fang gi\u1edd d) D\u00e2n l\u00e0ng kh\u1ea9n tr\u01b0\u01a1ng ch\u1ea1y l\u0169 5 - T\u00ecm ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef a) N\u1eafng, tr\u01b0a \u0111\u00e3 r\u01a1i xu\u1ed1ng \u0111\u1ec9nh \u0111\u1ea7u m\u00e0 r\u1eebng s\u00e2u v\u1eabn \u1ea9m l\u1ea1nh, \u00e1nh n\u1eafng l\u1ecdt qua l\u00e1 xanh. b) T\u00e2y Nguy\u00ean c\u00f2n l\u00e0 mi\u1ec1n \u0111\u1ea5t c\u1ee7a nh\u1eefng d\u00f2ng s\u00f4ng cu\u1ed3n cu\u1ed9n, nh\u01b0ng d\u00f2ng su\u1ed1i n\u00ean th\u01a1. 6 - Trong \u0111o\u1ea1n th\u01a1 sau: Th\u00e2n d\u1eeba b\u1ea1c ph\u1ebfch th\u00e1ng n\u0103m Qu\u1ea3 d\u1eeba \u2013 \u0111\u00e0n l\u1ee3n con n\u1eb1m tr\u00ean cao \u0110\u00eam h\u00e8 hoa n\u1edf c\u00f9ng sao T\u00e0u d\u1eeba \u2013 Chi\u1ebfc l\u01b0\u1ee3c ch\u1ea3i v\u00e0o m\u00e2y xanh. T\u00e1c gi\u1ea3 \u0111\u00e3 so s\u00e1nh v\u1edbi s\u1ef1 v\u1eadt n\u00e0o v\u1edbi s\u1ef1 v\u1eadt n\u00e0o? C\u00e1ch so s\u00e1nh c\u1ea3m nh\u1eadn \u0111\u01b0\u1ee3c \u0111i\u1ec1u g\u00ec t\u1eeb s\u1ef1 v\u1eadt, c\u00f3 th\u1ec3 thay d\u1ea5u (\u2013 ) b\u1eb1ng t\u1eeb n\u00e0o? 7 \u2013 K\u1ec3 l\u1ea1i m\u1ed9t k\u1ef7 ni\u1ec7m v\u1ec1 t\u00ecnh b\u1ea1n b\u00e8? \u0110\u00e1p \u00e1n ( V\u00ec th\u1eddi gian, NG ch\u1ec9 n\u00eau \u0110\u00e1p \u00e1n v\u0103n t\u1eaft) *C\u00e2u 1: a\/ \u201cb\u00e0n t\u00ednh\u201d l\u00e0 danh t\u1eeb ; b\/\u201cb\u00e0n t\u00ednh\u201d l\u00e0 \u0111\u1ed9ng t\u1eeb. *C\u00e2u 2: 142","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \uf0b7 a\/ CN= H\u01b0\u1edfng ; VN = tr\u1edf th\u00e0nh \uf0b7 b\/ CN = M\u1eb9 ; VN = c\u0169ng l\u00e0 \uf0b7 c\/ CN= l\u1edbp em; VN = c\u00f3 \uf0b7 d\/ CN= Ng\u01b0\u1eddi ho\u1ea1 s\u0129; VN=\u0111\u00e3 v\u1ebd l\u00ean *C\u00e2u 3: \u00dd ngh\u0129a kh\u00e1c nhau c\u1ee7a 2 c\u00e2u do c\u00f3 d\u1ea5u Ph\u1ea9y \u201d,\u201d \u1edf c\u00e2u b\/ \uf0b7 a\/ Chu\u1ed9t ch\u00e0o m\u1eb9 v\u00e0 m\u1eb9 s\u1ebd \u201cch\u1ea1y ra kh\u1ecfi hang\u201d \uf0b7 b\/ Chu\u1ed9t ch\u00e0o m\u1eb9 r\u1ed3i ch\u00ednh chu\u1ed9t \u201cch\u1ea1y ra kh\u1ecfi hang\u201d *C\u00e2u 4: Ngh\u0129a c\u1ee7a t\u1eeb \u201cch\u1ea1y\u201d trong c\u00e1c c\u00e2u; \uf0b7 a\/ B\u00e9 ch\u1ea1y lon ton. T\u1eeb ch\u1ea1y v\u1edbi ngh\u0129a \u0111en, ngh\u0129a c\u1ee5 th\u1ec3 c\u1ee7a \u0111\u1ed9ng t\u00e1c \u0111i nhanh b\u0103ng ch\u00e2n \uf0b7 b\/ T\u00e0u ch\u1ea1y... T\u1eeb ch\u1ea1y v\u1edbi ngh\u0129a c\u1ee5 th\u1ec3 nh\u01b0ng nh\u00e2n ho\u00e1 coi con t\u00e0u nh\u01b0 ng\u01b0\u1eddi, m\u1eafc d\u00f9 kh\u00f4ng c\u00f3 ch\u00e2n v\u00e0 \u0111ang trong tr\u1ea1ng th\u00e1i chuy\u1ec3n \u0111\u1ed9ng, kh\u00e1c v\u01a1i d\u1eebng\/\u0111\u1ed7 \uf0b7 c\/ \u0110\u1ed3ng h\u1ed3 ch\u1ea1y.... T\u1eeb ch\u1ea1y c\u0169ng v\u1edbi ngh\u0129a c\u1ee5 th\u1ec3 ch\u1ec9 tr\u1ea1ng th\u00e1i \u0111\u1ed3ng h\u1ed3 \u0111ang ho\u1ea1t \u0111\u1ed9ng; kh\u00e1c v\u1edbi \u0110\u1ed3ng h\u1ed3 ch\u1ebft \uf0b7 d\/ D\u00e2n l\u00e0ng..... ch\u1ea1y l\u0169. T\u1eeb ch\u1ea1y v\u1edbi ngh\u0129a m\u1edf r\u1ed9ng h\u01a1n, kh\u00f4ng ch\u1ec9 g\u1ed3m ri\u00eang 1 \u0111\u1ed9ng t\u00e1c ch\u1ea1y m\u00e0 l\u00e0 nhi\u1ec1u c\u00f4ng vi\u1ec7c v\u1ed9i v\u00e3, kh\u1ea9n tr\u01b0\u01a1ng. *C\u00e2u 5: \uf0b7 a\/ CN= N\u1eafng tr\u01b0a; VN= \u0111\u00e3 d\u1ecd xu\u1ed1ng \uf0b7 b\/ CN= T\u00e2y Nguy\u00ean; VN = c\u00f2n l\u00e0. *C\u00e2u 6: \uf0b7 Trong \u0111o\u1ea1n th\u01a1 \u0111\u00f3 t\u00e1c gi\u1ea3 so s\u00e1nh: Qu\u1ea3 d\u1eeba v\u1edbi \u0111\u00e0n l\u1ee3n con T\u00e0u d\u01b0\u00e0 v\u1edbi chi\u1ebfc l\u01b0\u1ee3c \uf0b7 C\u00e1ch so s\u00e1nh tr\u00ean gi\u00fap ta c\u1ea3m nh\u1eadn s\u1ef1 s\u1ed1ng \u0111\u1ed9ng c\u1ee7a nh\u1eefng qu\u1ea3 d\u1eeba v\u00e0 s\u1ef1 g\u1ea7n g\u0169i th\u00e2n thi\u1ebft v\u1edbi con ng\u01b0\u1eddi khi ng\u1eafm h\u00ecnh \u1ea3nh t\u00e0u d\u1eeba soi l\u00ean m\u00e2y xanh, \u0111\u1ed3ng th\u1eddi li\u00ean t\u01b0\u1edfng nh\u01b0 b\u1ee9c tranh : C\u00f4 g\u00e1i= \u0111\u00e1m m\u00e2y xanh \u0111ang ch\u1ea3i t\u00f3c v\u1edbi chi\u1ebfc l\u01b0\u1ee3c l\u00e0 t\u00e0u d\u1eeba. B\u1ea3n th\u00e2n t\u00e0u d\u1eeba c\u0169ng gi\u1ed3ng h\u00ecnh chi\u1ebfc l\u01b0\u1ee3c, do \u0111\u00f3 \u0111\u00e2y l\u00e0 s\u1ef1 so s\u00e1nh r\u1ea5t s\u00e1t, r\u1ea5t hay. (M\u1ed9t l\u00e3o huynh y\u00eau tr\u1ebb) \u0110\u1ec1 thi h\u1ecdc sinh gi\u1ecfi M\u00f4n : Ti\u1ebfng Vi\u1ec7t C\u00e2u 1: (1\u0111 )H\u00e3y x\u1ebfp c\u00e1c t\u1eeb d\u01b0\u1edbi \u0111\u00e2y th\u00e0nh 3 nh\u00f3m t\u1eeb \u0111\u1ed3ng ngh\u0129a v\u00e0 cho bi\u1ebft ngh\u0129a c\u1ee7a m\u1ed7i nh\u00f3m: bao la, v\u1eafng v\u1ebb, m\u00eanh m\u00f4ng, l\u1ea1nh ng\u1eaft, hiu qu\u1ea1nh, b\u00e1t ng\u00e1t, v\u1eafng teo, l\u1ea1nh l\u1ebdo, th\u00eanh thang, c\u00f3ng, v\u1eafng ng\u1eaft, l\u1ea1nh bu\u1ed1t, th\u00f9ng th\u00ecnh. C\u00e2u 2(2\u0111) Ghi 3 c\u00e2u th\u00e0nh ng\u1eef n\u00f3i v\u1ec1 v\u1ebb \u0111\u1eb9p c\u1ee7a \u0111\u1ea5t n\u01b0\u1edbc, \u0111\u1eb7t 2 c\u00e2u ( m\u1ed7i c\u00e2u c\u00f3 s\u1eed d\u1ee5ng th\u00e0nh ng\u1eef v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c) C\u00e2u 3 : (3\u0111) Cho \u0111o\u1ea1n v\u0103n sau: 143","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \u201cM\u01b0a m\u00f9a xu\u00e2n x\u00f4n xao ph\u1edbi ph\u1edbi... Nh\u1eefng h\u1ea1t m\u01b0a b\u00e9 nh\u1ecf m\u1ec1m m\u1ea1i r\u01a1i m\u00e0 nh\u01b0 nh\u1ea3y nh\u00f3t. H\u00e3y x\u00e1c \u0111\u1ecbnh nh\u1eefng t\u1eeb gh\u00e9p, t\u1eeb l\u00e1y trong \u0111o\u1ea1n v\u0103n tr\u00ean. C\u00e2u 4: (3\u0111) X\u00e1c \u0111\u1ecbnh b\u1ed9 ph\u1eadn tr\u1ea1ng ng\u1eef, ch\u1ee7 ng\u1eef, v\u1ecb ng\u1eef c\u00f3 trong c\u00e1c c\u00e2u sau: ( G\u1ea1ch ch\u00e2n : tr\u1ea1ng ng\u1eef ghi : TN ; ch\u1ee7 ng\u1eef ghi : CN ; v\u1ecb ng\u1eef ghi : VN ) a. Nh\u00ecn t\u1eeb xa, tr\u1eafng tr\u1eddi, tr\u1eafng \u0111\u1ea5t c\u1ea3 m\u1ed9t r\u1eebng ban. b. C\u00e1i h\u00ecnh \u1ea3nh trong t\u00f4i v\u1ec1 c\u00f4, \u0111\u1ebfn b\u00e2y gi\u1edd, v\u1eabn c\u00f2n r\u00f5 n\u00e9t. c. D\u01b0\u1edbi \u00e1nh tr\u0103ng d\u00f2ng s\u00f4ng s\u00e1ng r\u1ef1c l\u00ean, nh\u1eefng con s\u00f3ng v\u1ed7 nh\u1eb9 v\u00e0o hai b\u00ean b\u1edd c\u00e1t C\u00e2u 5: (3\u0111) T\u00ecm danh t\u1eeb, \u0111\u1ed9ng t\u1eeb, t\u00ednh t\u1eeb trong \u0111o\u1ea1n v\u0103n sau: (G\u1ea1ch ch\u00e2n : danh t\u1eeb ghi :DT; \u0111\u1ed9ng t\u1eeb ghi : \u0110T; t\u00ednh t\u1eeb ghi : TT) Ch\u00fa chu\u1ed3n chu\u1ed3n n\u01b0\u1edbc tung c\u00e1nh bay v\u1ecdt l\u00ean. C\u00e1i b\u00f3ng ch\u00fa nh\u1ecf x\u00edu l\u01b0\u1edbt nhanh tr\u00ean m\u1eb7t h\u1ed3. M\u1eb7t h\u1ed3 tr\u1ea3i r\u1ed9ng m\u00eanh m\u00f4ng v\u00e0 l\u1eb7ng s\u00f3ng. C\u00e2u 6 : (3\u0111) Trong b\u00e0i Con c\u00f2, nh\u00e0 th\u01a1 Ch\u1ebf Lan Vi\u00ean c\u00f3 vi\u1ebft: Con d\u00f9 l\u1edbn v\u1eabn l\u00e0 con c\u1ee7a m\u1eb9, \u0110i h\u1ebft \u0111\u1eddi, l\u00f2ng m\u1eb9 v\u1eabn theo con. Hai d\u00f2ng th\u01a1 tr\u00ean \u0111\u00e3 gi\u00fap em c\u1ea3m nh\u1eadn \u0111\u01b0\u1ee3c \u0111i\u1ec1u g\u00ec \u0111\u1eb9p \u0111\u1ebd v\u00e0 s\u00e2u s\u1eafc? C\u00e2u 7 : (3\u0111) T\u1eadp l\u00e0m v\u0103n : Em h\u00e3y t\u1ea3 h\u00ecnh d\u00e1ng v\u00e0 t\u00ednh n\u1ebft m\u1ed9t ng\u01b0\u1eddi b\u1ea1n m\u00e0 em qu\u00fd m\u1ebfn ( Kho\u1ea3ng 25d\u00f2ng ) \u0110\u00c1P \u00c1N C\u00e2u 1: (1\u0111) *Nh\u00f3m 1: bao la, m\u00eanh m\u00f4ng, b\u00e1t ng\u00e1t, r\u1ed9ng, th\u00eanh thang, th\u00f9ng th\u00ecnh Ngh\u0129a chung: R\u1ed9ng *Nh\u00f3m 2: V\u1eafng v\u1ebb, hiu qu\u1ea1nh, v\u1eafng ng\u1eaft, v\u1eafng teo. Ngh\u0129a chung: V\u1eafng * Nh\u00f3m 3: l\u1ea1nh l\u1ebdo, l\u1ea1nh ng\u1eaft, l\u1ea1nh bu\u1ed1t, c\u00f3ng Ngh\u0129a chung: l\u1ea1nh C\u00e2u 2 : (2\u0111)V\u00ed d\u1ee5 : non xanh n\u01b0\u1edbc bi\u1ebfc, giang s\u01a1n g\u1ea5m v\u00f3c, non n\u01b0\u1edbc h\u1eefu t\u00ecnh, n\u00fai s\u00f4ng h\u00f9ng v\u0129, non cao bi\u1ec3n r\u1ed9ng. 144","V\u00ed d\u1ee5 \u0110\u1eb7t c\u00e2u : C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 Qu\u00ea h\u01b0\u01a1ng t\u00f4i non n\u01b0\u1edbc h\u1eefu t\u00ecnh. C\u00e2u 3 : (3\u0111) T\u1eeb l\u00e1y: x\u00f4n xao, ph\u01a1i ph\u1edbi, m\u1ec1m m\u1ea1i, nh\u1ea3y nh\u00f3t T\u1eeb gh\u00e9p: m\u00f9a xu\u00e2n, h\u1ea1t m\u01b0a, b\u00e9 nh\u1ecf. C\u00e2u 4 : (3\u0111) a. Nh\u00ecn t\u1eeb xa, tr\u1eafng tr\u1eddi, tr\u1eafng \u0111\u1ea5t c\u1ea3 m\u1ed9t r\u1eebng ban TN VN CN b. C\u00e1i h\u00ecnh \u1ea3nh trong t\u00f4i v\u1ec1 c\u00f4, \u0111\u1ebfn b\u00e2y gi\u1edd, v\u1eabn c\u00f2n r\u00f5 n\u00e9t. CN TN VN c. D\u01b0\u1edbi \u00e1nh tr\u0103ng, d\u00f2ng s\u00f4ng s\u00e1ng r\u1ef1c l\u00ean, nh\u1eefng con s\u00f3ng v\u1ed7 nh\u1eb9 v\u00e0 hai b\u00ean b\u1edd c\u00e1t TN CN VN CN VN C\u00e2u 5: (3\u0111) - Danh t\u1eeb: ch\u00fa, chu\u1ed3n chu\u1ed3n n\u01b0\u1edbc, c\u00e1i b\u00f3ng,ch\u00fa , m\u1eb7t h\u1ed3, m\u1eb7t h\u1ed3. - \u0110\u1ed9ng t\u1eeb: tung c\u00e1nh, bay, v\u1ecdt l\u00ean, l\u01b0\u1edbt nhanh, tr\u1ea3i r\u1ed9ng. - T\u00ednh t\u1eeb: nh\u1ecf x\u00edu, m\u00eanh m\u00f4ng, l\u1eb7ng s\u00f3ng C\u00e2u 6 ; (3\u0111) - Trong m\u1eaft m\u1eb9, con bao gi\u1edd c\u0169ng b\u00e9 nh\u1ecf, ng\u00e2y th\u01a1 c\u1ea7n \u0111\u01b0\u1ee3c s\u1ef1 n\u00e2ng niu d\u1ea1y d\u1ed7, ch\u0103m s\u00f3c v\u00e0 che ch\u1edf c\u1ee7a m\u1eb9. - T\u1ea5m l\u00f2ng m\u1eb9 bao la, r\u1ed9ng l\u1edbn, d\u00f9 \u1edf \u0111\u00e2u, l\u00fac n\u00e0o m\u1eb9 c\u0169ng quan t\u00e2m \u0111\u1ebfn con, h\u01b0\u1edbng v\u1ec1 con, d\u00ecu d\u1eaft con tr\u00ean b\u01b0\u1edbc \u0111\u01b0\u1eddng \u0111\u1eddi. - \u0110\u00f3 ch\u00ednh l\u00e0 th\u1ee9 t\u00ecnh c\u1ea3m thi\u00eang li\u00eang kh\u00f4ng ai c\u00f3 th\u1ec3 thay th\u1ebf \u0111\u01b0\u1ee3c. C\u00e2u 7 : (3\u0111) T\u1ea3 h\u00ecnh d\u00e1ng t\u00ednh n\u1ebft m\u1ed9t ng\u01b0\u1eddi b\u1ea1n m\u00e0 em qu\u00fd m\u1ebfn. B\u00e0i vi\u1ebft \u0111\u1ed9 kho\u1ea3ng 25 d\u00f2ng ; vi\u1ebft \u0111\u00fang th\u1ec3 lo\u1ea1i v\u0103n mi\u00eau t\u1ea3 ( ki\u1ec3u b\u00e0i t\u1ea3 ng\u01b0\u1eddi ). C\u1ea7n n\u00eau \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 \u00fd c\u01a1 b\u1ea3n sau : - N\u00eau t\u00ean ng\u01b0\u1eddi b\u1ea1n \u0111\u01b0\u1ee3c em ch\u1ecdn t\u1ea3 ; n\u00f3i r\u00f5 m\u1ed1i quan h\u1ec7, s\u1ef1 g\u1eafn b\u00f3 gi\u1eefa em v\u00e0 b\u1ea1n \u1ea5y. - nh\u1ea5n m\u1ea1nh nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m c\u1ee7a b\u1ea1n v\u1ec1 h\u00ecnh d\u00e1ng v\u00e0 t\u00ednh t\u00ecnh ( ch\u00fa \u00fd nh\u1eefng n\u00e9t g\u00e2y \u1ea5n t\u01b0\u1ee3ng s\u00e2u s\u1eafc \u0111\u1ed1i v\u1edbi em, th\u1ec3 hi\u1ec7n quan h\u1ec7 th\u00e2n thi\u1ebft \u0111\u1ed1i v\u1edbi em ). - B\u1ed1 c\u1ee5c b\u00e0i v\u0103n r\u00f5 r\u00e0ng, h\u1ee3p l\u00ed ; d\u00f9ng t\u1eeb \u0111\u00fang ; \u0111\u1eb7t c\u00e2u kh\u00f4ng sai ng\u1eef ph\u00e1p ; di\u1ec5n \u0111\u1ea1t r\u00f5 \u00fd, m\u1ea1ch l\u1ea1c ; vi\u1ebft \u0111\u00fang ch\u00ednh t\u1ea3 ; tr\u00ecnh b\u00e0y \u0111\u1eb9p m\u1eaft. ( Tr\u00ecnh b\u00e0y s\u1ea1ch \u0111\u1eb9p \u0111\u01b0\u1ee3c 2 \u0111i\u1ec3m ) 145","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \u00d1O\u00cfC THA\u00c0M VA\u00d8 LA\u00d8M BA\u00d8I TA\u00c4P : ( 30 phu\u00f9t ) \u2026\u2026\/ 5 Ho\u00efc sinh \u00f1o\u00efc tha\u00e0m ba\u00f8i: \u201c Cha se\u00f5 luo\u00e2n \u00f4\u00fb be\u00e2n con \u201d ro\u00e0i la\u00f8m ca\u00f9c \u00f1 ba\u00f8i ta\u00e4p sau: A. \u00d1o\u00efc hie\u00e5u : Khoanh tro\u00f8n va\u00f8o ch\u00f6\u00f5 ca\u00f9i \u00f1a\u00e0u ca\u00e2u ch\u00e6 y\u00f9 \u00f1u\u00f9ng ....\/ 0,5 nha\u00e1t: \u00f1 1. Ng\u00f6\u00f4\u00f8i cha \u00f1a\u00f5 la\u00f8m g\u00ec tr\u00f6\u00f4\u00f9c ca\u00fbnh ngo\u00e2i nha\u00f8 \u00f1o\u00e5 na\u00f9t ? a. Nh\u00f4\u00f9 la\u00efi v\u00f2 tr\u00ed l\u00f4\u00f9p ho\u00efc cu\u00fba con, cha\u00efy \u00f1e\u00e1n t\u00f6\u00ef \u00f1a\u00f8o b\u00f4\u00f9i. b. Ke\u00e2u than, th\u00f6\u00f4ng kho\u00f9c con. c. Nh\u00f4\u00f9 la\u00efi v\u00f2 tr\u00ed l\u00f4\u00f9p ho\u00efc cu\u00fba con, go\u00efi mo\u00efi ng\u00f6\u00f4\u00f8i \u00f1e\u00e1n \u00f1a\u00f8o b\u00f4\u00f9i. d. \u00d1\u00f6\u00f9ng ch\u00f4\u00f8 ca\u00fbnh sa\u00f9t va\u00f8 \u00f1o\u00e4i c\u00f6\u00f9u ho\u00e4 \u00f1a\u00f8o b\u00f4\u00f9i. ....\/ 0,5 2. Ca\u00e2u ng\u00f6\u00f4\u00f8i cha ho\u00fbi nh\u00f6\u00f5ng ng\u00f6\u00f4\u00f8i thuye\u00e1t phu\u00efc o\u00e2ng r\u00f4\u00f8i kho\u00fbi \u00f1 \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t : Anh\/ O\u00c2ng\/ Ca\u00f9c o\u00e2ng\/ co\u00f9 giu\u00f9p to\u00e2i kho\u00e2ng?\u201d cho tha\u00e1y \u00f1ie\u00e0u g\u00ec? a. Ng\u00f6\u00f4\u00f8i cha ca\u00e0n mo\u00efi ng\u00f6\u00f4\u00f8i giu\u00f9p \u00f1\u00f4\u00f5. b. Ng\u00f6\u00f4\u00f8i cha hi vo\u00efng mo\u00efi ng\u00f6\u00f4\u00f8i giu\u00f9p \u00f1\u00f4\u00f5. c. Ng\u00f6\u00f4\u00f8i cha quye\u00e1t ta\u00e2m t\u00f6\u00ef kie\u00e1m con m\u00ecnh. d. Ng\u00f6\u00f4\u00f8i cha tha\u00e1t vo\u00efng v\u00ec kho\u00e2ng ai giu\u00f9p. ....\/ 0,5 3. Nh\u00f6\u00f5ng ng\u00f6\u00f4\u00f8i kha\u00f9c la\u00f8m g\u00ec ? \u00f1 a. Ke\u00e2u than kho\u00f9c lo\u00f9c. b. Cho ra\u00e8ng \u00f1a\u00f5 qua\u00f9 muo\u00e4n, kho\u00e2ng the\u00e5 c\u00f6\u00f9u \u00f1\u00f6\u00f4\u00efc nh\u00f6\u00f5ng \u00f1\u00f6\u00f9a tre\u00fb. c. Thuye\u00e1t phu\u00efc va\u00f8 ke\u00f9o ng\u00f6\u00f4\u00f8i cha \u00f1ang \u00f1a\u00f8o b\u00f4\u00f9i ra kho\u00fbi \u00f1o\u00e1ng ga\u00efch. d. Cho ra\u00e8ng ng\u00f6\u00f4\u00f8i cha \u00f1a\u00f8o b\u00f4\u00f9i ch\u00e6 la\u00f8m cho vie\u00e4c t\u00ecm kie\u00e1m kho\u00f9 kha\u00ean h\u00f4n. ....\/ 0,5 4. Ke\u00e1t thu\u00f9c ca\u00e2u chuye\u00e4n co\u00f9 g\u00ec tha\u00e4t ca\u00fbm \u00f1o\u00e4ng ? \u00f1 a. Nh\u00f4\u00f8 t\u00ecnh ye\u00e2u cu\u00fba cha, ca\u00e4u be\u00f9 \u00f1a\u00f5 \u00f1\u00f6\u00f4\u00efc c\u00f6\u00f9u so\u00e1ng. b. Ca\u00e4u be\u00f9 va\u00f8 13 ng\u00f6\u00f4\u00f8i ba\u00efn cu\u00fba ca\u00e4u \u00f1\u00f6\u00f4\u00efc c\u00f6\u00f9u so\u00e1ng. c. Ca\u00e4u be\u00f9 nh\u00f6\u00f4\u00f8ng ca\u00f9c ba\u00efn ra kho\u00fbi \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t tr\u00f6\u00f4\u00f9c, ca\u00e4u la\u00f8 ng\u00f6\u00f4\u00f8i cuo\u00e1i cu\u00f8ng v\u00ec bie\u00e1t ra\u00e8ng cha kho\u00e2ng bao gi\u00f4\u00f8 bo\u00fb r\u00f4i ca\u00e4u. d. Ca\u00e4u va\u00f8 ca\u00f9c ba\u00efn \u00f1\u00f6\u00f4\u00efc \u00f1o\u00e4i c\u00f6\u00f9u hoa\u00fb c\u00f6\u00f9u so\u00e1ng tr\u00f6\u00f4\u00f9c nie\u00e0m vui m\u00f6\u00f8ng cu\u00fba mo\u00efi ng\u00f6\u00f4\u00f8i. ....\/ 0,5 5. Y\u00d9 ngh\u00f3a ca\u00e2u chuye\u00e4n la\u00f8 g\u00ec ? \u00f1 a. Cha me\u00ef luo\u00e2n \u00f1a\u00f9p \u00f6\u00f9ng mo\u00efi nhu ca\u00e0u cu\u00fba con ca\u00f9i. b. Cha me\u00ef la\u00f8 nh\u00f6\u00f5ng ng\u00f6\u00f4\u00f8i tha\u00e2n ga\u00e0n gu\u00f5i nha\u00e1t \u00f1o\u00e1i v\u00f4\u00f9i con ca\u00f9i. c. Cha me\u00ef luo\u00e2n ba\u00fbo ve\u00e4 con ca\u00f9i khi ca\u00e0n. d. Cha me\u00ef kho\u00e2ng qua\u00fbn gian nan, nguy hie\u00e5m, sa\u00fcn sa\u00f8ng hi sinh ta\u00e1t ca\u00fb v\u00ec con ca\u00f9i. 146","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 ....\/ 0,5 B. Luye\u00e4n t\u00f6\u00f8 va\u00f8 ca\u00e2u : \u00f1 6. Ca\u00f9c ve\u00e1 trong ca\u00e2u ghe\u00f9p: \u201cDu\u00f8 chuye\u00e4n g\u00ec xa\u00fby ra , cha cu\u00f5ng se\u00f5 luo\u00e2n \u00f4\u00fb be\u00e2n con.\u201d \u00f1\u00f6\u00f4\u00efc no\u00e1i v\u00f4\u00f9i nhau ba\u00e8ng ca\u00f9ch na\u00f8o? a. No\u00e1i tr\u00f6\u00efc tie\u00e1p ( kho\u00e2ng du\u00f8ng t\u00f6\u00f8 no\u00e1i ). b. No\u00e1i ba\u00e8ng 1 quan he\u00e4 t\u00f6\u00f8. \u00d1o\u00f9 la\u00f8 t\u00f6\u00f8 : \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 c. No\u00e1i ba\u00e8ng mo\u00e4t ca\u00ebp quan he\u00e4 t\u00f6\u00f8. \u00d1o\u00f9 la\u00f8 ca\u00ebp quan he\u00e4 t\u00f6\u00f8 : \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026... d. No\u00e1i ba\u00e8ng mo\u00e4t ca\u00ebp t\u00f6\u00f8 ho\u00e2 \u00f6\u00f9ng. \u00d1o\u00f9 la\u00f8 ca\u00ebp t\u00f6\u00f8 : \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. ....\/ 0,5 7. \u00d1oa\u00efn va\u00ean : \u201c O\u00c2ng co\u00e1 nh\u00f4\u00f9 la\u00efi c\u00f6\u00fba ha\u00f8nh lang ma\u00f8 o\u00e2ng va\u00e3n da\u00e3n \u00f1 con \u00f1e\u00e1n l\u00f4\u00f9p ho\u00efc mo\u00e3i nga\u00f8y. O\u00c2ng nh\u00f4\u00f9 pho\u00f8ng ho\u00efc cu\u00fba con trai m\u00ecnh \u00f4\u00fb .....\/ 0,5 ph\u00eda sau, be\u00e2n pha\u00fbi tr\u00f6\u00f4\u00f8ng. O\u00c2ng vo\u00e4i cha\u00efy \u00f1e\u00e1n \u00f1o\u00f9 va\u00f8 \u00f1a\u00f8o b\u00f4\u00f9i.\u201d co\u00f9 \u00f1 ca\u00f9c ca\u00e2u \u00f1\u00f6\u00f4\u00efc lie\u00e2n ke\u00e1t v\u00f4\u00f9i nhau ba\u00e8ng ca\u00f9ch na\u00f8o ? a. Ba\u00e8ng ca\u00f9ch s\u00f6\u00fb du\u00efng ca\u00f9c ca\u00ebp t\u00f6\u00f8 ho\u00e2 \u00f6\u00f9ng. Ca\u00ebp t\u00f6\u00f8 \u00f1o\u00f9 la\u00f8 : \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. b. Ba\u00e8ng ca\u00f9ch la\u00ebp t\u00f6\u00f8 ng\u00f6\u00f5. T\u00f6\u00f8 \u00f1o\u00f9 la\u00f8: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. c. Ba\u00e8ng ca\u00f9ch thay the\u00e1 t\u00f6\u00f8 ng\u00f6\u00f5. T\u00f6\u00f8 \u00f1o\u00f9 la\u00f8:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. d. Ba\u00e8ng t\u00f6\u00f8 ng\u00f6\u00f5 no\u00e1i. \u00d1o\u00f9 la\u00f8 t\u00f6\u00f8 no\u00e1i: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. .....\/ 0,5 8. Quan he\u00e4 y\u00f9 ngh\u00f3a gi\u00f6\u00f5a hai ve\u00e1 trong ca\u00e2u ghe\u00f9p : \u00ab Nha\u00e2n vie\u00e2n \u00f1 ca\u00fbnh sa\u00f9t cu\u00f5ng ra s\u00f6\u00f9c thuye\u00e1t phu\u00efc o\u00e2ng ve\u00e0 nha\u00f8 v\u00ec o\u00e2ng \u00f1ang \u00f4\u00fb trong ....\/ 1 \u00f1 vu\u00f8ng nguy hie\u00e5m. \u00bb thuo\u00e4c kie\u00e5u na\u00f8o d\u00f6\u00f4\u00f9i \u00f1a\u00e2y ? a. Quan he\u00e4 ke\u00e1t qua\u00fb \u2013 nguye\u00e2n nha\u00e2n. b. Quan he\u00e4 \u00f1ie\u00e0u kie\u00e4n (gia\u00fb thie\u00e1t) \u2013 ke\u00e1t qua\u00fb c. Quan he\u00e4 ta\u00eang tie\u00e1n. d. Quan he\u00e4 t\u00f6\u00f4ng pha\u00fbn. 9. \u00d1a\u00ebt ca\u00e2u : a. Mo\u00e4t ca\u00e2u ghe\u00f9p co\u00f9 s\u00f6\u00fb du\u00efng ca\u00ebp t\u00f6\u00f8 ho\u00e2 \u00f6\u00f9ng em \u00f1a\u00f5 \u00f1\u00f6\u00f4\u00efc ho\u00efc. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b. Mo\u00e4t ca\u00e2u co\u00f9 no\u00e4i dung ca ng\u00f4\u00efi truye\u00e0n tho\u00e1ng to\u00e1t \u00f1e\u00efp cu\u00fba da\u00e2n to\u00e4c ta. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 147","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u20261\u20264\u20268\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 BA\u00d8I \u00d1O\u00cfC THA\u00c0M : Cha se\u00f5 luo\u00e2n \u00f4\u00fb be\u00e2n con Na\u00eam 1989, ta\u00efi A\u00d9c-me\u00e2-ni-a, mo\u00e4t tra\u00e4n \u00f1o\u00e4ng \u00f1a\u00e1t 8,2 \u00f1o\u00e4 r\u00edch-t\u00f4 \u00f1a\u00f5 san ba\u00e8ng nhie\u00e0u la\u00f8ng ma\u00efc, tha\u00f8nh pho\u00e1, gie\u00e1t ha\u00efi h\u00f4n 30 000 ng\u00f6\u00f4\u00f8i trong vo\u00f8ng ch\u00f6a \u00f1a\u00e0y 149","C\u00c1C \u0110\u1ec0 THI H\u1eccC SINH GI\u1eceI L\u1edaP 5 bo\u00e1n phu\u00f9t. Gi\u00f6\u00f5a khung ca\u00fbnh ho\u00e3n loa\u00efn \u00f1o\u00f9, mo\u00e4t ng\u00f6\u00f4\u00f8i cha cha\u00efy vo\u00e4i \u00f1e\u00e1n tr\u00f6\u00f4\u00f8ng ho\u00efc cu\u00fba con trai. Toa\u00f8 nha\u00f8 tr\u00f6\u00f4\u00f9c tr\u00f6\u00f4\u00f8ng ho\u00efc nay ch\u00e6 co\u00f8n la\u00f8 mo\u00e4t \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t. Sau c\u00f4n so\u00e1c, ng\u00f6\u00f4\u00f8i cha nh\u00f4\u00f9 la\u00efi l\u00f4\u00f8i h\u00f6\u00f9a v\u00f4\u00f9i con m\u00ecnh : \u201c Du\u00f8 chuye\u00e4n g\u00ec xa\u00fby ra, cha cu\u00f5ng se\u00f5 luo\u00e2n \u00f4\u00fb be\u00e2n con! \u201d. Nh\u00ecn \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t ma\u00f8 tr\u00f6\u00f4\u00f9c kia la\u00f8 tr\u00f6\u00f4\u00f8ng ho\u00efc th\u00ec kho\u00f9 co\u00f8n co\u00f9 hi vo\u00efng g\u00ec. Nh\u00f6ng o\u00e2ng kho\u00e2ng the\u00e5 que\u00e2n l\u00f4\u00f8i h\u00f6\u00f9a \u00f1o\u00f9. O\u00c2ng co\u00e1 nh\u00f4\u00f9 la\u00efi c\u00f6\u00fba ha\u00f8nh lang ma\u00f8 o\u00e2ng va\u00e3n da\u00e3n con \u00f1e\u00e1n l\u00f4\u00f9p ho\u00efc mo\u00e3i nga\u00f8y. O\u00c2ng nh\u00f4\u00f9 pho\u00f8ng ho\u00efc cu\u00fba con trai m\u00ecnh \u00f4\u00fb ph\u00eda sau, be\u00e2n pha\u00fbi tr\u00f6\u00f4\u00f8ng. O\u00c2ng vo\u00e4i cha\u00efy \u00f1e\u00e1n \u00f1o\u00f9 va\u00f8 \u00f1a\u00f8o b\u00f4\u00f9i. Nh\u00f6\u00f5ng ng\u00f6\u00f4\u00f8i cha, ng\u00f6\u00f4\u00f8i me\u00ef kha\u00f9c cu\u00f5ng cha\u00efy \u00f1e\u00e1n \u00f1o\u00f9. T\u00f6\u00f8 kha\u00e9p n\u00f4i vang le\u00e2n nh\u00f6\u00f5ng tie\u00e1ng ke\u00e2u than: \u201c O\u00c2i con trai to\u00e2i! \u201d, \u201cO\u00c2i con ga\u00f9i to\u00e2i! \u201d. Mo\u00e4t so\u00e1 ng\u00f6\u00f4\u00f8i kha\u00f9c co\u00e1 ke\u00f9o o\u00e2ng ra kho\u00fbi \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t va\u00f8 no\u00f9i \u00f1i no\u00f9i la\u00efi: - \u00d1a\u00f5 muo\u00e4n qua\u00f9 ro\u00e0i! - Bo\u00efn nho\u00fb \u00f1a\u00f5 che\u00e1t ro\u00e0i! - O\u00c2ng kho\u00e2ng giu\u00f9p \u00f1\u00f6\u00f4\u00efc g\u00ec cho chu\u00f9ng n\u00f6\u00f5a \u00f1a\u00e2u! - O\u00c2ng ch\u00e6 la\u00f8m cho mo\u00efi vie\u00e4c kho\u00f9 kha\u00ean the\u00e2m ma\u00f8 tho\u00e2i! V\u00f4\u00f9i mo\u00e3i ng\u00f6\u00f4\u00f8i, o\u00e2ng ch\u00e6 la\u00ebp la\u00efi ca\u00e2u ho\u00fbi: \u201c Anh co\u00f9 giu\u00f9p to\u00e2i kho\u00e2ng ?\u201d. Sau \u00f1o\u00f9, o\u00e2ng la\u00efi tie\u00e1p tu\u00efc \u00f1a\u00f8o b\u00f4\u00f9i t\u00f6\u00f8ng vie\u00e2n ga\u00efch \u00f1e\u00e5 t\u00ecm con. Ch\u00e6 huy \u00f1o\u00e4i c\u00f6\u00f9u hoa\u00fb co\u00e1 s\u00f6\u00f9c khuye\u00e2n o\u00e2ng ra kho\u00fbi \u00f1o\u00e1ng \u00f1o\u00e5 na\u00f9t v\u00ec mo\u00efi va\u00e4t xung quanh \u00f1ang bo\u00e1c cha\u00f9y, ca\u00f9c toa\u00f8 nha\u00f8 \u00f1ang su\u00efp \u00f1o\u00e5. Nh\u00f6ng ng\u00f6\u00f4\u00f8i cha va\u00e3n ch\u00e6 ho\u00fbi: \u201c O\u00c2ng co\u00f9 giu\u00f9p to\u00e2i kho\u00e2ng?\u201d. Nha\u00e2n vie\u00e2n ca\u00fbnh sa\u00f9t cu\u00f5ng ra s\u00f6\u00f9c thuye\u00e1t phu\u00efc o\u00e2ng ve\u00e0 nha\u00f8 v\u00ec o\u00e2ng \u00f1ang \u00f4\u00fb trong vu\u00f8ng nguy hie\u00e5m. V\u00f4\u00f9i ho\u00ef, o\u00e2ng cu\u00f5ng ch\u00e6 ho\u00fbi: \u201cCa\u00f9c o\u00e2ng co\u00f9 giu\u00f9p to\u00e2i kho\u00e2ng? \u201d. Kho\u00e2ng \u00f1\u00f6\u00f4\u00efc ai giu\u00f9p \u00f1\u00f4\u00f5, o\u00e2ng tie\u00e1p tu\u00efc mo\u00e4t m\u00ecnh \u00f1a\u00f8o b\u00f4\u00f9i v\u00ec o\u00e2ng muo\u00e1n t\u00f6\u00ef t\u00ecm ra ca\u00e2u tra\u00fb l\u00f4\u00f8i: Con trai o\u00e2ng co\u00f8n so\u00e1ng hay \u00f1a\u00f5 che\u00e1t? O\u00c2ng \u00f1a\u00f8o tie\u00e1p\u202612 gi\u00f4\u00f8\u202624 gi\u00f4\u00f8\u2026.Sau \u00f1o\u00f9, khi la\u00e4t ng\u00f6\u00f5a mo\u00e4t ma\u00fbng t\u00f6\u00f4\u00f8ng l\u00f4\u00f9n, o\u00e2ng ch\u00f4\u00eft ca\u00fbm tha\u00e1y nh\u00f6 co\u00f9 tie\u00e1ng con trai. O\u00c2ng m\u00f6\u00f8ng r\u00f4\u00f5 ke\u00e2u te\u00e2n con: \u201c A\u00f9c-man! A\u00f9c-man!\u201d. Co\u00f9 tie\u00e1ng go\u00efi vo\u00efng ra: \u201c Cha \u00f4i! Con \u00f1a\u00e2y! Con \u00f1a\u00e2y!\u201d. Th\u00ec ra toa\u00f8 nha\u00f8 \u00f1o\u00e5 \u00f1a\u00f5 ta\u00efo ra mo\u00e4t khoa\u00fbng tro\u00e1ng nho\u00fb ne\u00e2n bo\u00efn tre\u00fb co\u00f8n so\u00e1ng so\u00f9t. Ca\u00e4u be\u00f9 no\u00f9i tie\u00e1p: - Cha \u00f4i! Con \u00f1a\u00f5 ba\u00fbo ca\u00f9c ba\u00efn la\u00f8 ne\u00e1u cha co\u00f8n so\u00e1ng, nha\u00e1t \u00f1\u00f2nh cha se\u00f5 c\u00f6\u00f9u con va\u00f8 ca\u00f9c ba\u00efn. - \u00d4\u00db \u00f1o\u00f9 the\u00e1 na\u00f8o ha\u00fb con? \u2013 Ng\u00f6\u00f4\u00f8i cha vo\u00e4i va\u00f5 ho\u00fbi. - Tu\u00efi con co\u00f9 14 ng\u00f6\u00f4\u00f8i. Chu\u00f9ng con \u00f1o\u00f9i va\u00f8 kha\u00f9t la\u00e9m. - Ca\u00f9c con chui ra \u00f1i! - \u00d1e\u00e5 ca\u00f9c ba\u00efn ra tr\u00f6\u00f4\u00f9c. Con bie\u00e1t cha kho\u00e2ng bao gi\u00f4\u00f8 bo\u00fb r\u00f4i con ma\u00f8. (Theo Truye\u00e4n A\u00d9c-me\u00e2-ni-a) H\u00d6\u00d4\u00d9NG DA\u00c3N CHA\u00c1M BA\u00d8I KT\u00d1K CUO\u00c1I HKI 150"]