["A. 3cm B. 12cm C. 4cm D. 36cm C\u00e2u 6: \u0110o\u1ea1n th\u1eb3ng AB d\u00e0i 100 cm. M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB, c\u00f2n N l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AM. H\u1ecfi MN c\u00f3 \u0111\u1ed9 d\u00e0i l\u00e0? A. 25cm B. 75cm C. 48cm D. 50cm Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) b, (42017 + 39274) : 3 = C\u00e2u 1: T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: a, 45823 \u2013 25256 : 4 = c, (2368 + 12564 3) : 4 = d, (684 + 23687 5) : 7 = C\u00e2u 2: C\u00f3 19250m v\u1ea3i, may m\u1ed7i b\u1ed9 \u00e1o d\u00e0i m\u1ea5t 3m v\u1ea3i. H\u1ecfi c\u00f3 th\u1ec3 may \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t bao nhi\u00eau b\u1ed9 \u00e1o d\u00e0i v\u00e0 c\u00f2n th\u1eeba bao nhi\u00eau m\u00e9t v\u1ea3i? C\u00e2u 3: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 m\u1ed9t s\u1ed1 th\u00f9ng d\u1ea7u nh\u01b0 nhau ch\u1ee9a t\u1ed5ng c\u1ed9ng 72 l\u00edt, ng\u01b0\u1eddi ta th\u00eam v\u00e0o s\u1ed1 d\u1ea7u \u0111\u00f3 3 th\u00f9ng th\u00ec s\u1ed1 d\u1ea7u \u0111\u00f3 c\u00f3 t\u1ea5t c\u1ea3 l\u00e0 99 l\u00edt. H\u1ecfi l\u00fac \u0111\u1ea7u c\u1eeda h\u00e0ng c\u00f3 bao nhi\u00eau th\u00f9ng d\u1ea7u? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 31. \u0110\u1ec0 3 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t c\u00f3 n\u0103m ch\u1eef s\u1ed1 l\u00e0: A. 99998 B. 99990 C. 88888 D. 99999 C\u00e2u 2: Bi\u1ebft 7042 : x = 7. H\u1ecfi x = ? A. 1003 B. 1004 C. 1005 D. 1006 C\u00e2u 3: Bi\u1ebft A = 98987 : a, B = 99887 : a. H\u00e3y so s\u00e1nh A v\u00e0 B A. A = B B. A > B C. A < B D Kh\u00f4ng th\u1ec3 so s\u00e1nh \u0111\u01b0\u1ee3c","C\u00e2u 4: T\u00fa c\u00f3 56 ngh\u00ecn \u0111\u1ed3ng mua \u0111\u01b0\u1ee3c 8 quy\u1ec3n truy\u1ec7n. H\u00f9ng c\u00f3 \u00edt h\u01a1n T\u00fa 21 ngh\u00ecn \u0111\u1ed3ng. H\u1ecfi H\u00f9ng mua \u0111\u01b0\u1ee3c bao nhi\u00eau quy\u1ec3n truy\u1ec7n? A. 7 quy\u1ec3n B. 6 quy\u1ec3n C. 5 quy\u1ec3n D. 4 quy\u1ec3n C\u00e2u 5: Ch\u1eef s\u1ed1 5 \u1edf s\u1ed1 40503 thu\u1ed9c h\u00e0ng n\u00e0o? A. H\u00e0ng ngh\u00ecn B. H\u00e0ng ch\u1ee5c ngh\u00ecn C. H\u00e0ng ch\u1ee5c D. H\u00e0ng tr\u0103m C\u00e2u 6: S\u1ed1 g\u1ed3m 47 tr\u0103m, 5 ch\u1ee5c, 18 \u0111\u01a1n v\u1ecb vi\u1ebft l\u00e0: A. 4768 B. 6748 C. 47518 D. 4758 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ecm x: a, (x \u2013 3412) 3 = 45789 b, 51264 \u2013 x = 19992 : 7 c, (x + 3478) : 2 = 78632 d, 28694 \u2013 x 2 = 7658 C\u00e2u 2: M\u1ed9t nh\u00e0 m\u00e1y d\u1ef1 \u0111\u1ecbnh s\u1ea3n xu\u1ea5t 28680 chi\u1ebfc c\u1ed1c. Nh\u00e0 m\u00e1y \u0111\u00e3 s\u1ea3n xu\u1ea5t \u0111\u01b0\u1ee3c \u00bc l\u01b0\u1ee3ng \u0111\u00f3. H\u1ecfi nh\u00e0 m\u00e1y c\u00f2n ph\u1ea3i s\u1ea3n xu\u1ea5t bao nhi\u00eau chi\u1ebfc c\u1ed1c n\u1eefa? C\u00e2u 3: M\u1ed9t c\u1eeda h\u00e0ng nh\u1eadp v\u1ec1 168 bao \u0111\u01b0\u1eddng v\u00e0 chia \u0111\u1ec1u v\u00e0o 3 kho. Sau \u0111\u00f3 l\u1ea1i nh\u1eadp th\u00eam 16 bao \u0111\u01b0\u1eddng v\u00e0 b\u00e1n h\u1ebft s\u1ed1 \u0111\u01b0\u1eddng trong hai kho l\u00fac tr\u01b0\u1edbc. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau bao \u0111\u01b0\u1eddng? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 32. \u0110\u1ec0 1 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 n\u00e0o g\u1ed3m: Hai m\u01b0\u01a1i ch\u00edn ngh\u00ecn, kh\u00f4ng tr\u0103m, ba m\u01b0\u01a1i t\u01b0.","A. 29043 B. 29034 C. 29304 D. 29340 C\u00e2u 2: S\u1ed1 ch\u1eb5n li\u1ec1n tr\u01b0\u1edbc c\u1ee7a s\u1ed1 99000 l\u00e0: A. 99898 B. 98999 C. 98998 D. 98998 C\u00e2u 3: T\u00ecm s\u1ed1 nh\u1ecf nh\u1ea5t trong c\u00e1c s\u1ed1 sau: A. 27898 B. 27989 C. 27899 D. 27998 D. Kh\u00f4ng th\u1ec3 so s\u00e1nh \u0111\u01b0\u1ee3c C\u00e2u 4: Bi\u1ebft x > 21001 v\u00e0 y < 21002. H\u00e3y so s\u00e1nh x v\u00e0 y: A. x = y B. x < y C. x > y C\u00e2u 5: H\u00e3y so s\u00e1nh A = 8km 40cm, B = 8000m 4dm A. A > B B. A < B C. A = B D. Kh\u00f4ng th\u1ec3 so s\u00e1nh \u0111\u01b0\u1ee3c C\u00e2u 6: S\u1ed1 l\u1ebb l\u1edbn nh\u1ea5t c\u00f3 n\u0103m ch\u1eef s\u1ed1 kh\u00e1c nhau c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng ngh\u00ecn l\u00e0 3 l\u00e0: A. 98765 B. 93765 C. 93875 D. 93876 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u1eeb c\u00e1c ch\u1eef s\u1ed1 1, 3, 5, 8, 6. Ta l\u1eadp \u0111\u01b0\u1ee3c bao nhi\u00eau s\u1ed1 l\u1ebb c\u00f3 5 ch\u1eef s\u1ed1 kh\u00e1c nhau b\u1eaft \u0111\u1ea7u b\u1eb1ng ch\u1eef s\u1ed1 1? \u0110\u00f3 l\u00e0 nh\u1eefng s\u1ed1 n\u00e0o? C\u00e2u 2: Vi\u1ebft c\u00e1c t\u1ed5ng sau th\u00e0nh s\u1ed1 c\u00f3 n\u0103m ch\u1eef s\u1ed1: a) 20000 + 800 + 90 + 2 = b) 20000 + 6000 + 1 = c) 70000 + 90 + 4 = d) 50000 + 8000 + 700 + 90 + 3 = C\u00e2u 3: Cho A = 7a6c3 + 9b7d B = 79675 + abcd H\u00e3y so s\u00e1nh A v\u00e0 B \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 32. \u0110\u1ec0 2 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 38899 \u0111\u01b0\u1ee3c \u0111\u1ecdc l\u00e0:","A. Ba m\u01b0\u01a1i t\u00e1m ngh\u00ecn t\u00e1m tr\u0103m ch\u00edn m\u01b0\u01a1i ch\u00edn B. Ba m\u01b0\u01a1i ch\u00edn ngh\u00ecn t\u00e1m tr\u0103m ch\u00edn m\u01b0\u01a1i ch\u00edn C. Ba m\u01b0\u01a1i ch\u00edn ngh\u00ecn t\u00e1m tr\u0103m t\u00e1m m\u01b0\u01a1i t\u00e1m D. Ba m\u01b0\u01a1i t\u00e1m ngh\u00ecn ch\u00edn tr\u0103m ch\u00edn m\u01b0\u01a1i ch\u00edn C\u00e2u 2: S\u1ed1 l\u1ebb li\u1ec1n sau s\u1ed1 99879 l\u00e0: A. 99877 B. 99878 C. 99881 D. 98981 C\u00e2u 3: T\u00ecm s\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1 sau: A. 41590 B. 41800 C. 42360 D. 41785 V\u1eady a = ? C\u00e2u 4: Bi\u1ebft 26775 > 267a6. A. a = 8 B. a = 9 C. a = 7 D. a = 6 C\u00e2u 5: \u0110i\u1ec1n s\u1ed1 ti\u1ebfp theo v\u00e0o d\u00e3y s\u1ed1: 2005, 2010, 2015, 2020, \u2026 A. 20025 B. 2025 C. 20205 D. 2205 C\u00e2u 6: S\u1ed1 l\u1ebb nh\u1ecf nh\u1ea5t c\u00f3 n\u0103m ch\u1eef s\u1ed1 c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c l\u00e0 2 l\u00e0: A. 10021 B. 10020 C. 10201 D. 12001 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 tr\u1ed1ng: a) Vi\u1ebft s\u1ed1: \u2026\u2026.., \u0111\u1ecdc s\u1ed1: Ch\u00edn m\u01b0\u01a1i ba ngh\u00ecn s\u00e1u tr\u0103m t\u00e1m m\u01b0\u01a1i b) Vi\u1ebft s\u1ed1: 38008, \u0111\u1ecdc s\u1ed1:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 c) Vi\u1ebft s\u1ed1: 57080, \u0111\u1ecdc s\u1ed1:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.... d) Vi\u1ebft s\u1ed1: \u2026\u2026.., \u0111\u1ecdc s\u1ed1: T\u00e1m m\u01b0\u01a1i s\u00e1u ngh\u00ecn b\u1ea3y tr\u0103m ba m\u01b0\u01a1i hai C\u00e2u 2: T\u1eeb c\u00e1c ch\u1eef s\u1ed1 9, 6, 3, 5, 7. Ta c\u00f3 th\u1ec3 l\u1eadp \u0111\u01b0\u1ee3c t\u1ea5t c\u1ea3 bao nhi\u00eau s\u1ed1 ch\u1eb5n c\u00f3 n\u0103m ch\u1eef s\u1ed1 kh\u00e1c nhau v\u00e0 s\u1ed1 l\u1eadp \u0111\u01b0\u1ee3c nh\u1ecf h\u01a1n 50000. C\u00e2u 3: T\u00ecm s\u1ed1 c\u00f3 n\u0103m ch\u1eef s\u1ed1 bi\u1ebft r\u1eb1ng, s\u1ed1 \u0111\u00f3 l\u00e0 s\u1ed1 l\u1ebb v\u00e0 ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb g\u1ea5p 5 l\u1ea7n ch\u1eef s\u1ed1 h\u00e0ng ngh\u00ecn v\u00e0 t\u1ed5ng c\u1ee7a ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m v\u00e0 h\u00e0ng ch\u1ee5c b\u1eb1ng 6 v\u00e0 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m nh\u1ecf h\u01a1n ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c v\u00e0 s\u1ed1 \u0111\u00f3 nh\u1ecf h\u01a1n 20000.","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 32. \u0110\u1ec0 3 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 n\u00e0o sau \u0111\u00e2y \u0111\u01b0\u1ee3c \u0111\u1ecdc l\u00e0 ba m\u01b0\u01a1i ngh\u00ecn kh\u00f4ng tr\u0103m ba m\u01b0\u01a1i t\u01b0? A. 30304 B. 30030 C. 30034 D. 34300 C\u00e2u 2: S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 sau theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn: 28765, 27865, 26785, 28675 A. 28765, 27865, 26785, 28675 B. 26785, 27865, 28675, 28765 C. 26785, 28675, 27865, 28765 D. 26785, 27865, 28765, 28675 C\u00e2u 3: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a s\u1ed1 56970 l\u00e0 s\u1ed1: A. 56969 B. 56971 C. 7970 D. 56980 C\u00e2u 4: Bi\u1ebft A = 28694 + abcd v\u00e0 B = 2a6c4 + 8b8d. H\u00e3y so s\u00e1nh A v\u00e0 B: A. A = B B. A > B C. A < B D. Kh\u00f4ng th\u1ec3 so s\u00e1nh \u0111\u01b0\u1ee3c C\u00e2u 5: \u0110i\u1ec1n s\u1ed1 ti\u1ebfp theo v\u00e0o d\u00e3y s\u1ed1: 20831, 20834, 20837, 20840, \u2026 A. 20841 B. 20842 C. 20843 D. 20844 C\u00e2u 6: S\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t c\u00f3 n\u0103m ch\u1eef s\u1ed1 m\u00e0 c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m l\u00e0 1 l\u00e0: A. 91999 B. 91998 C. 99199 D. 99198 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: a) 16370, 16380, \u2026 , \u2026 , 16410 b) 31576, 31581, 31586, \u2026 , \u2026 c) 28670, \u2026 , 28676, 28679, \u2026 d) 51010, 52010, 53010, \u2026 , \u2026 C\u00e2u 2: T\u1eeb c\u00e1c ch\u1eef s\u1ed1 1,3,5,7, 9 ta c\u00f3 th\u1ec3 l\u1eadp \u0111\u01b0\u1ee3c bao nhi\u00eau s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 kh\u00e1c nhau c\u00f3 t\u1eadn c\u00f9ng b\u1eb1ng 3 v\u00e0 nh\u1ecf h\u01a1n 300 C\u00e2u 3: T\u00ecm s\u1ed1 c\u00f3 n\u0103m ch\u1eef s\u1ed1 kh\u00e1c nhau sao cho ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c ngh\u00ecn g\u1ea5p 5 l\u1ea7n ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u00e0 ch\u1eef s\u1ed1 h\u00e0ng ngh\u00ecn, h\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c \u0111\u1ec1u chia h\u1ebft cho 3.","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 33. \u0110\u1ec0 1 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c: 2342 + 403 6 l\u00e0: A. 4660 B. 4760 C. 4860 D. 4960 C\u00e2u 2: Mua 2kg g\u1ea1o h\u1ebft 18000 \u0111\u1ed3ng. H\u1ecfi mua 5kg g\u1ea1o th\u00ec h\u1ebft bao nhi\u00eau ti\u1ec1n? A. 35000 \u0111\u1ed3ng B. 40000 \u0111\u1ed3ng C. 45000 \u0111\u1ed3ng D. 50000 \u0111\u1ed3ng C\u00e2u 3: 12m7dm b\u1eb1ng bao nhi\u00eau dm? A. 1207dm B. 127dm C. 1270dm D. 1027dm C\u00e2u 4: Th\u00f9ng nh\u1ecf c\u00f3 24 l\u00edt d\u1ea7u. S\u1ed1 d\u1ea7u th\u00f9ng l\u1edbn g\u1ea5p 5 l\u1ea7n s\u1ed1 d\u1ea7u th\u00f9ng nh\u1ecf. Th\u00f9ng l\u1edbn c\u00f3 s\u1ed1 l\u00edt d\u1ea7u l\u00e0: A. 120 l\u00edt B. 29 l\u00edt C. 100 l\u00edt D. 1020 l\u00edt C\u00e2u 5: T\u00ecm x: x : 7 = 28645 A. 200551 B. 200155 C. 250015 D. 200515 C\u00e2u 6: M\u1eb9 mua cho Linh m\u1ed9t chi\u1ebfc m\u0169 gi\u00e1 10000 \u0111\u1ed3ng v\u00e0 m\u1ed9t chi\u1ebfc kh\u0103n gi\u00e1 25000 \u0111\u1ed3ng. M\u1eb9 \u0111\u01b0a cho c\u00f4 b\u00e1n h\u00e0ng 50000 \u0111\u1ed3ng. C\u00f4 b\u00e1n h\u00e0ng ph\u1ea3i tr\u1ea3 l\u1ea1i m\u1eb9 Linh bao nhi\u00eau ti\u1ec1n? A. 40000 \u0111\u1ed3ng B. 35000 \u0111\u1ed3ng C. 15000 \u0111\u1ed3ng D. 25000 \u0111\u1ed3ng Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, 28536 + 4237 b, 5036 4 c, 7361 \u2013 2504 d, 7854 : 6 C\u00e2u 2: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 10450kg g\u1ea1o, c\u1eeda h\u00e0ng \u0111\u00f3 \u0111\u00e3 b\u00e1n trong 4 tu\u1ea7n, m\u1ed7i tu\u1ea7n b\u00e1n 560kg g\u1ea1o. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau kg g\u1ea1o? C\u00e2u 3: Bao g\u1ea1o th\u1ee9 nh\u1ea5t n\u1eb7ng 25kg, bao th\u1ee9 hai n\u1eb7ng 38kg. H\u1ecfi ph\u1ea3i chuy\u1ec3n t\u1eeb bao th\u1ee9 hai sang bao th\u1ee9 nh\u1ea5t bao nhi\u00eau kg g\u1ea1o \u0111\u1ec3 bao g\u1ea1o th\u1ee9 hai ch\u1ec9 h\u01a1n bao g\u1ea1o th\u1ee9 nh\u1ea5t 3kg g\u1ea1o?","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 33. \u0110\u1ec0 2 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: M\u1ed9t \u00f4 t\u00f4 \u0111i trong 8 gi\u1edd \u0111\u01b0\u1ee3c 32624km. H\u1ecfi \u00f4 t\u00f4 \u0111\u00f3 \u0111i trong 3 gi\u1edd \u0111\u01b0\u1ee3c bao nhi\u00eau km? A. 4078 B. 12234 C. 12230 D. 4070 C\u00e2u 2: 9m 6dm = \u2026 cm A. 9600 B. 96 C. 906 D. 960 C\u00e2u 3: 1 gi\u1edd 15 ph\u00fat = \u2026 ph\u00fat A. 30 B. 45 C. 60 D. 75 C\u00e2u 4: T\u1ed5ng c\u1ee7a 47856 v\u00e0 35687 l\u00e0: A. 83433 B. 82443 C. 83543 D. 82543 C\u00e2u 5: T\u00ecm x bi\u1ebft: x \u2013 5732 = 1293 A. 6925 B. 4439 C. 4449 D. 7025 C\u00e2u 6: B\u00ecnh c\u00f3 hai t\u1edd gi\u1ea5y b\u1ea1c lo\u1ea1i 2000 \u0111\u1ed3ng. B\u00ecnh mua b\u00fat h\u1ebft 2700 \u0111\u1ed3ng. H\u1ecfi B\u00ecnh c\u00f2n l\u1ea1i bao nhi\u00eau ti\u1ec1n? A. 1300 \u0111\u1ed3ng B. 1500 \u0111\u1ed3ng C. 1800 \u0111\u1ed3ng D. 2100 \u0111\u1ed3ng Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1:T\u00ecm x: a, (x \u2013 284) 4 = 2864 b, (x : 7) + 286 = 3684 c, 78564 \u2013 x = 286 d, x + 2684 = 3895 C\u00e2u 2: C\u00f3 750 l\u00edt n\u01b0\u1edbc m\u1eafm \u0111\u1ef1ng \u0111\u1ec1u trong 5 th\u00f9ng. H\u1ecfi 7 th\u00f9ng nh\u01b0 th\u1ebf \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt n\u01b0\u1edbc m\u1eafm. C\u00e2u 3: S\u1ee3i d\u00e2y th\u1ee9 nh\u1ea5t d\u00e0i 480mm v\u00e0 s\u1ee3i d\u00e2y th\u1ee9 hai d\u00e0i b\u1eb1ng 1\/3 s\u1ee3i d\u00e2y th\u1ee9 nh\u1ea5t v\u00e0 s\u1ee3i d\u00e2y th\u1ee9 nh\u1ea5t b\u1eb1ng \u00bd s\u1ee3i d\u00e2y th\u1ee9 3. H\u1ecfi 3 s\u1ee3i d\u00e2y d\u00e0i bao nhi\u00eau mm?","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 33. \u0110\u1ec0 3 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c 700 : 5 4 l\u00e0: A. 35 B. 560 C. 7500 D. 150 C\u00e2u 2: Mua 9 b\u00fat ch\u00ec h\u1ebft 5400 \u0111\u1ed3ng. H\u1ecfi mua 6 b\u00fat ch\u00ec nh\u01b0 th\u1ebf h\u1ebft bao nhi\u00eau ti\u1ec1n? A. 36 \u0111\u1ed3ng B. 360 \u0111\u1ed3ng C. 3600 \u0111\u1ed3ng D. 36000 \u0111\u1ed3ng C\u00e2u 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: 8m 7cm = \u2026 cm l\u00e0: A. 87 B. 78 C. 870 D. 807 C\u00e2u 4: T\u00ecm x: 8462 \u2013 x = 762 A. 8700 B. 6700 C. 7600 D. 7700 C\u00e2u 5: M\u1ed7i gi\u1edd c\u00f3 60 ph\u00fat, v\u1eady \u00bc gi\u1edd l\u00e0: A. 25 ph\u00fat B. 40 ph\u00fat C. 4 ph\u00fat D. 15 ph\u00fat C\u00e2u 6: B\u00ecnh n\u1eb7ng 35 kg. An nh\u1eb9 h\u01a1n B\u00ecnh 6kg, Tu\u1ea5n n\u1eb7ng h\u01a1n B\u00ecnh 3kg. H\u1ecfi c\u1ea3 3 b\u1ea1n n\u1eb7ng bao nhi\u00eau kg? A. 102kg B. 105kg C. 108kg D. 111kg Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: a, 15840 + 7932 5 = b, 239 + 1267 3 = c, (15786 \u2013 13982) 3 = d, 2505 : (403 \u2013 398) = C\u00e2u 2: M\u1ed9t \u00f4 t\u00f4 \u0111i trong 8 ng\u00e0y \u0111\u01b0\u1ee3c 32624km. H\u1ecfi \u00f4 t\u00f4 \u0111\u00f3 \u0111i trong 3 ng\u00e0y \u0111\u01b0\u1ee3c bao nhi\u00eau km? Bi\u1ebft m\u1ed7i ng\u00e0y \u00f4 t\u00f4 \u0111i \u0111\u01b0\u1ee3c s\u1ed1 km l\u00e0 nh\u01b0 nhau C\u00e2u 3: An c\u01b0a m\u1ed9t kh\u00fac g\u1ed7 th\u00e0nh c\u00e1c kh\u00fac g\u1ed7 ng\u1eafn h\u01a1n, m\u1ed7i kh\u00fac d\u00e0i 5dm v\u00e0 An c\u01b0a 5 l\u1ea7n th\u00ec h\u1ebft kh\u00fac g\u1ed7. H\u1ecfi kh\u00fac g\u1ed7 ch\u01b0a c\u01b0a l\u00fac \u0111\u1ea7u c\u1ee7a An d\u00e0i bao nhi\u00eau m\u00e9t?","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 34. \u0110\u1ec0 1 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: Cho h\u00ecnh v\u1ebd: AM B O 1cm D 1cm N 1cm C C\u00e2u 1: H\u00ecnh v\u1ebd tr\u00ean c\u00f3 bao nhi\u00eau \u0111o\u1ea1n th\u1eb3ng c\u00f3 \u0111i\u1ec3m \u0111\u1ea7u l\u00e0 A? A. 6 \u0111o\u1ea1n B. 8 \u0111o\u1ea1n C. 9 \u0111o\u1ea1n D. 5 \u0111o\u1ea1n C\u00e2u 2: Bi\u1ebft O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a MN. H\u1ecfi MO = ? cm A. 1cm B. 2cm C. 3cm D. Kh\u00f4ng th\u1ec3 bi\u1ebft \u0111\u01b0\u1ee3c C\u00e2u 3: \u1ede h\u00ecnh v\u1ebd tr\u00ean c\u00e2u n\u00e0o sau \u0111\u00e2y \u0111\u00fang? A. 3 \u0111i\u1ec3m A, O, B th\u1eb3ng h\u00e0ng B. 3 \u0111i\u1ec3m A, O, C th\u1eb3ng h\u00e0ng C. 3 \u0111i\u1ec3m D, O, C th\u1eb3ng h\u00e0ng D. 3 \u0111i\u1ec3m A, B, C th\u1eb3ng h\u00e0ng C\u00e2u 4: Bi\u1ebft ABCD l\u00e0 h\u00ecnh vu\u00f4ng, chu vi h\u00ecnh vu\u00f4ng ABCD b\u1eb1ng: A. 4cm B. 6cm C. 8cm D. 8cm2 C\u00e2u 5: Di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng ABCD l\u00e0: A. 4cm2 B. 6cm C. 8cm2 D. 10cm Sai k\u00ed hi\u1ec7u cm2 C\u00e2u 6:M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i g\u1ea5p 3 l\u1ea7n c\u1ea1nh h\u00ecnh vu\u00f4ng ABCD v\u00e0 chi\u1ec1u r\u1ed9ng g\u1ea5p 2 l\u1ea7n c\u1ea1nh h\u00ecnh vu\u00f4ng ABCD. H\u1ecfi di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 b\u1eb1ng bao nhi\u00eau? A. 10cm B. 24cm C. 20cm2 D. 24cm2 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: Cho h\u00ecnh ch\u1eef nh\u1eadt ABCD v\u00e0 h\u00ecnh vu\u00f4ng MNPQ c\u00f3 k\u00edch th\u01b0\u1edbc nh\u01b0 h\u00ecnh v\u1ebd. So s\u00e1nh di\u1ec7n t\u00edch hai h\u00ecnh tr\u00ean?","A BM N 5cm 6cm D 6cm C QP C\u00e2u 2: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt v\u00e0 m\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 chu vi b\u1eb1ng nhau. Bi\u1ebft h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 60m, chi\u1ec1u r\u1ed9ng 40m. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ea1nh h\u00ecnh vu\u00f4ng. C\u00e2u 3: \u0110\u1ec3 chu\u1ea9n b\u1ecb cho m\u1ed9t h\u1ed9i ngh\u1ecb ng\u01b0\u1eddi ta k\u00ea 9 h\u00e0ng gh\u1ebf \u0111\u1ee7 ch\u1ed7 cho 81 ng\u01b0\u1eddi ng\u1ed3i. Tr\u00ean th\u1ef1c t\u1ebf c\u00f3 108 ng\u01b0\u1eddi \u0111\u1ebfn d\u1ef1 h\u1ecdp. H\u1ecfi ph\u1ea3i k\u00ea th\u00eam m\u1ea5y h\u00e0ng gh\u1ebf n\u1eefa m\u1edbi \u0111\u1ee7 ch\u1ed7 ng\u1ed3i. \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 34. \u0110\u1ec0 2 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: H\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 3cm. Di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng b\u1eb1ng: A. 6cm2 B. 6cm C. 9cm2 D. 12cm C\u00e2u 2: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 12cm, chi\u1ec1u r\u1ed9ng b\u1eb1ng 1\/3 chi\u1ec1u d\u00e0i. T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3. A. 36cm2 B. 48cm2 C. 16cm2 D. 32cm2 C\u00e2u 3: H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 bao nhi\u00eau g\u00f3c vu\u00f4ng?","A. 6 B. 8 C. 10 D.12 C\u00e2u 4: H\u00ecnh v\u1ebd c\u00e2u 3 c\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c: A. 2 B. 3 C. 4 D. 5 C\u00e2u 5: H\u00ecnh v\u1ebd c\u00e2u 3 c\u00f3 bao nhi\u00eau h\u00ecnh t\u1ee9 gi\u00e1c: A. 4 B. 5 C. 6 D. 7 C\u00e2u 6: M\u1ed9t ng\u01b0\u1eddi \u0111i b\u1ed9 trong 6 ph\u00fat \u0111\u01b0\u1ee3c qu\u00e3ng \u0111\u01b0\u1eddng 480m. H\u1ecfi trong 9 ph\u00fat ng\u01b0\u1eddi \u0111\u00f3 \u0111i \u0111\u01b0\u1ee3c qu\u00e3ng \u0111\u01b0\u1eddng bao nhi\u00eau, bi\u1ebft v\u1eadn t\u1ed1c c\u1ee7a ng\u01b0\u1eddi \u0111\u00f3 l\u00e0 nh\u01b0 nhau: A. 720m B. 640m C. 800m D. 900m Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0: 35cm, 26cm, 40cm C\u00e2u 2: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i g\u1ea5p \u0111\u00f4i chi\u1ec1u r\u1ed9ng. Bi\u1ebft chi\u1ec1u r\u1ed9ng c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt b\u1eb1ng c\u1ea1nh c\u1ee7a m\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 chu vi b\u1eb1ng 48cm. T\u00ednh chu vi v\u00e0 di\u1ec7n t\u00edch c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt. C\u00e2u 3: M\u1ed9t qu\u1ea7y t\u1ea1p ho\u00e1 c\u00f3 9 th\u00f9ng c\u1ed1c. Sau khi b\u00e1n \u0111i 450 c\u1ed1c th\u00ec qu\u1ea7y \u0111\u00f3 c\u00f2n l\u1ea1i 6 th\u00f9ng c\u1ed1c. H\u1ecfi tr\u01b0\u1edbc khi b\u00e1n qu\u1ea7y \u0111\u00f3 c\u00f3 bao nhi\u00eau c\u1ed1c? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 34. \u0110\u1ec0 3 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Chu vi h\u00ecnh vu\u00f4ng l\u00e0 96cm. C\u1ea1nh c\u1ee7a h\u00ecnh vu\u00f4ng l\u00e0:","A. 86cm B. 43cm C. 24cm D. 32cm C\u00e2u 2: Di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i 13m, chi\u1ec1u r\u1ed9ng 9m l\u00e0: A. 117m B. 117m2 C. 44m2 D. 44m C\u00e2u 3: M\u1ed9t th\u1eeda ru\u1ed9ng h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng 8cm, chi\u1ec1u d\u00e0i g\u1ea5p 3 l\u1ea7n chi\u1ec1u r\u1ed9ng. T\u00ednh di\u1ec7n t\u00edch th\u1eeda ru\u1ed9ng? A. 192cm2 B. 190cm2 C. 80cm2 D. 84cm2 C\u00e2u 4: H\u00ecnh ch\u1eef nh\u1eadt ABCD c\u00f3 AB = 5cm, AD = 13cm. Di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ABCD l\u00e0: A. 36cm B. 36cm2 C. 65cm2 D. 45cm2 C\u00e2u 5: \u0110o\u1ea1n th\u1eb3ng AB d\u00e0i 45cm. \u0110o\u1ea1n th\u1eb3ng CD d\u00e0i h\u01a1n 1\/3 \u0111o\u1ea1n th\u1eb3ng AB l\u00e0 5cm. H\u1ecfi c\u1ea3 hai \u0111o\u1ea1n d\u00e0i bao nhi\u00eau cm? A. 70cm B. 65cm C. 60cm D. 55cm C\u00e2u 6: M\u1ed9t h\u1ed9i ngh\u1ecb c\u00f3 36 c\u00e1i gh\u1ebf x\u1ebfp \u0111\u1ec1u v\u00e0o 4 h\u00e0ng. H\u1ecfi v\u1edbi 2304 gh\u1ebf th\u00ec x\u1ebfp v\u00e0o \u0111\u01b0\u1ee3c bao nhi\u00eau h\u00e0ng? Bi\u1ebft m\u1ed7i h\u00e0ng c\u00f3 s\u1ed1 gh\u1ebf nh\u01b0 nhau? A. 253 h\u00e0ng B.254 h\u00e0ng C. 255 h\u00e0ng D. 256 h\u00e0ng Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 2685 c\u00e1i \u00e1o. Bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 1\/5 s\u1ed1 \u00e1o. Bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c g\u1ea5p \u0111\u00f4i s\u1ed1 \u00e1o bu\u1ed5i s\u00e1ng. H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau chi\u1ebfc \u00e1o? C\u00e2u 2: C\u00f3 48 l\u00edt d\u1ea7u \u0111\u1ed5 \u0111\u1ec1u v\u00e0o 6 xe. H\u1ecfi v\u1edbi 2872 l\u00edt d\u1ea7u s\u1ebd \u0111\u1ed5 \u0111\u01b0\u1ee3c bao nhi\u00eau chi\u1ebfc xe? Bi\u1ebft m\u1ed7i xe \u0111\u1ed5 l\u01b0\u1ee3ng d\u1ea7u nh\u01b0 nhau C\u00e2u 3: Cho h\u00ecnh v\u1ebd H .T\u00ednh chu vi v\u00e0 di\u1ec7n t\u00edch h\u00ecnh H A 6cm B 2cm C 2cm D 6cm 4cm F 8cm E","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 35. \u0110\u1ec0 1 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Ng\u00e0y 25 th\u00e1ng 8 l\u00e0 th\u1ee9 b\u1ea3y. H\u1ecfi ng\u00e0y 2\/9 n\u0103m \u0111\u00f3 l\u00e0 th\u1ee9 m\u1ea5y? A. Th\u1ee9 s\u00e1u B. Th\u1ee9 b\u1ea3y C. Ch\u1ee7 nh\u1eadt D. Th\u1ee9 hai C\u00e2u 2: S\u1ed1 li\u1ec1n sau c\u1ee7a 78999 l\u00e0: A. 78901 B. 78991 C. 79000 D. 78100 C\u00e2u 3: Trong c\u00e1c s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y, s\u1ed1 n\u00e0o kh\u00f4ng thu\u1ed9c d\u00e3y: 1, 4, 7, 10, 13, \u2026 A. 100 B. 1234 C. 2017 D. 1001 C\u00e2u 4: S\u1ed1 12 \u0111\u01b0\u1ee3c vi\u1ebft theo s\u1ed1 La M\u00e3 l\u00e0: A. XI B.XII C. VVII D. IIX C\u00e2u 5: 7hm 3dam = \u2026 m \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p A. 73 B.730 C. 703 D. 370 C\u00e2u 6: T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c: 23864 : 4 + 2587 A. 8553 B. 8355 C. 8535 D. 8353 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, 14754 + 23680 b, 15840 \u2013 8795 c, 12936 3 d, 68325 : 8 C\u00e2u 2: An mua 3 b\u00fat ch\u00ec v\u00e0 5 quy\u1ec3n v\u1edf h\u1ebft 21 ngh\u00ecn \u0111\u1ed3ng, H\u1ed3ng mua 5 quy\u1ec3n v\u1edf v\u00e0 5 b\u00fat ch\u00ec h\u1ebft 25 ngh\u00ecn \u0111\u1ed3ng. T\u00ednh s\u1ed1 ti\u1ec1n 1 b\u00fat ch\u00ec v\u00e0 m\u1ed9t quy\u1ec3n v\u1edf. C\u00e2u 3: H\u00ecnh tam gi\u00e1c ABC c\u00f3 3 c\u1ea1nh b\u1eb1ng nhau, h\u00ecnh t\u1ee9 gi\u00e1c MNPQ c\u00f3 4 c\u1ea1nh b\u1eb1ng nhau. Bi\u1ebft c\u1ea1nh h\u00ecnh tam gi\u00e1c d\u00e0i h\u01a1n c\u1ea1nh h\u00ecnh t\u1ee9 gi\u00e1c l\u00e0 10cm v\u00e0 chu vi hai h\u00ecnh \u0111\u00f3 b\u1eb1ng nhau. T\u00ecm \u0111\u1ed9 d\u00e0i c\u1ea1nh c\u1ee7a h\u00ecnh tam gi\u00e1c ABC v\u00e0 h\u00ecnh t\u1ee9 gi\u00e1c MNPQ.","\u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 35. \u0110\u1ec0 2 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: Ng\u00e0y 28 th\u00e1ng 4 l\u00e0 th\u1ee9 s\u00e1u. H\u1ecfi ng\u00e0y 4\/5 n\u0103m \u0111\u00f3 l\u00e0 th\u1ee9 m\u1ea5y? A. Th\u1ee9 t\u01b0 B. Th\u1ee9 s\u00e1u C. Th\u1ee9 n\u0103m D. Ch\u1ee7 nh\u1eadt C\u00e2u 2: S\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1: 8576, 8756, 8765, 8675 l\u00e0: A. 8576 B. 8756 C. 8765 D. 8675 C\u00e2u 3: N\u0103m nay m\u1eb9 35 tu\u1ed5i, tu\u1ed5i con b\u1eb1ng 1\/5 tu\u1ed5i m\u1eb9. T\u00ednh t\u1ed5ng s\u1ed1 tu\u1ed5i hai m\u1eb9 con khi con b\u1eb1ng tu\u1ed5i m\u1eb9 hi\u1ec7n nay: A. 98 B. 175 C. 170 D. 100 C\u00e2u 4: S\u1ed1 li\u1ec1n sau c\u1ee7a s\u1ed1: 65939 l\u00e0: A. 65929 B. 65940 C. 65941 D. 65938 C\u00e2u 5: Cho h\u00ecnh v\u1ebd AM B H\u00ecnh v\u1ebd tr\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c: A. 8 B. 10 C. 12 D. 14 7cm D 2cm N 2cm C C\u00e2u 6: Bi\u1ebft ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u r\u1ed9ng 4cm, chi\u1ec1u d\u00e0i 10 cm. H\u1ecfi di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ABCD l\u00e0: A. 14cm2 B. 14cm C. 28cm D. 28cm2 Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a, 28764 : 4 b, 1563 7 c, 92835 + 1269 d, 65941 - 5929 C\u00e2u 2: Ng\u00e0y th\u1ee9 nh\u1ea5t b\u00e1n \u0111\u01b0\u1ee3c 2358kg g\u1ea1o, ng\u00e0y th\u1ee9 hai b\u00e1n \u0111\u01b0\u1ee3c g\u1ea5p 3 l\u1ea7n ng\u00e0y th\u1ee9 nh\u1ea5t. H\u1ecfi c\u1ea3 hai ng\u00e0y b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau kg g\u1ea1o?","C\u00e2u 3: Bi\u1ebft chu vi h\u00ecnh ch\u1eef nh\u1eadt g\u1ea5p 6 l\u1ea7n chi\u1ec1u r\u1ed9ng. H\u1ecfi chi\u1ec1u d\u00e0i h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3 g\u1ea5p m\u1ea5y l\u1ea7n chi\u1ec1u r\u1ed9ng? \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I TU\u1ea6N 35. \u0110\u1ec0 3 M\u00d4N:TO\u00c1N 3 Ph\u1ea7n I. Tr\u1eafc nghi\u1ec7m (3 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang nh\u1ea5t: C\u00e2u 1: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc s\u1ed1 42840 l\u00e0: A. 42841 B. 42830 C. 42839 D. 43850 C\u00e2u 2: \u0110i\u1ec1n d\u1ea5u >, <, = v\u00e0o ch\u1ed7 tr\u1ed1ng: 88568 \u2026 78858 l\u00e0: A. > B. < C. = D. Kh\u00f4ng c\u00f3 d\u1ea5u n\u00e0o C\u00e2u 3: S\u1ed1 g\u1ed3m b\u1ea3y ch\u1ee5c ngh\u00ecn, n\u0103m tr\u0103m, s\u00e1u \u0111\u01a1n v\u1ecb vi\u1ebft l\u00e0: A. 75600 B. 75060 C. 75006 D. 70506 C\u00e2u 4: H\u00f4m nay l\u00e0 th\u1ee9 n\u0103m. H\u1ecfi 100 ng\u00e0y sau l\u00e0 th\u1ee9 m\u1ea5y trong tu\u1ea7n? A. Th\u1ee9 t\u01b0 B. Th\u1ee9 n\u0103m C. Th\u1ee9 s\u00e1u D. Th\u1ee9 b\u1ea3y C\u00e2u 5: Trong c\u00e1c s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y s\u1ed1 n\u00e0o kh\u00f4ng thu\u1ed9c d\u00e3y: 2, 5, 8, 11, 14, \u2026 A. 23456 B. 2000 C. 2333 D. 21345 C\u00e2u 6: M\u1ed9t \u0111\u1ed9i c\u00f4ng nh\u00e2n 5 ng\u00e0y \u0111\u00e0o \u0111\u01b0\u1ee3c 1615m \u0111\u01b0\u1eddng. H\u1ecfi 7 ng\u00e0y \u0111\u00e0o \u0111\u01b0\u1ee3c bao nhi\u00eau m\u00e9t \u0111\u01b0\u1eddng? A. 323m B. 2261m C. 2621m D. 332m Ph\u1ea7n II: T\u1ef1 lu\u1eadn (7 \u0111i\u1ec3m) C\u00e2u 1: T\u00ecm x:","a, x : 8 = 3721 b, 24860 : x = 5 c, 49623 + x = 78578 d, 78026 \u2013 x = 69375 C\u00e2u 2: B\u1ea3y bao xi m\u0103ng n\u1eb7ng 350kg. M\u1ed7i v\u1ecf bao n\u1eb7ng 200g. H\u1ecfi n\u0103m bao xi m\u0103ng nh\u01b0 th\u1ebf c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng xi m\u0103ng l\u00e0 bao nhi\u00eau kg? C\u00e2u 3: M\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 chi\u1ec1u d\u00e0i g\u1ea5p ba l\u1ea7n chi\u1ec1u r\u1ed9ng v\u00e0 c\u00f3 di\u1ec7n t\u00edch b\u1eb1ng 48cm2. T\u00ednh chu vi h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3?"]
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