TUYỂN TẬP 50 ĐỀ THI HỌC KỲ 1 LỚP 2

["A. 10 B. 10 vi\u00ean bi C. 10 (vi\u00ean bi) D. 6 vi\u00ean bi 47 + 37 94 - 57 II\/ PH\u1ea6N T\u1ef0 LU\u1eacN (7 \u0110I\u1ec2M) B\u00e0i 1 (3 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 36 + 47 100 - 65 B\u00e0i 2 (1 \u0111i\u1ec3m): T\u00ecm a, bi\u1ebft: 63 - a = 25 37 + a = 81 B\u00e0i 3 (2 \u0111i\u1ec3m): M\u1ed9t khu v\u01b0\u1eddn c\u00f3 100 c\u00e2y \u0111\u00e0o, sau khi b\u00e1n \u0111i m\u1ed9t s\u1ed1 c\u00e2y \u0111\u00e0o th\u00ec khu v\u01b0\u1eddn c\u00f2n l\u1ea1i 37 c\u00e2y \u0111\u00e0o. H\u1ecfi \u0111\u00e3 b\u00e1n bao nhi\u00eau c\u00e2y \u0111\u00e0o? B\u00e0i gi\u1ea3i: ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. B\u00e0i 4 (1 \u0111i\u1ec3m): H\u00e3y v\u1ebd th\u00eam m\u1ed9t \u0111o\u1ea1n th\u1eb3ng v\u00e0o h\u00ecnh b\u00ean \u0111\u1ec3 c\u00f3 1 h\u00ecnh tam gi\u00e1c v\u00e0 2 h\u00ecnh t\u1ee9 gi\u00e1c. \u0110\u1ecdc t\u00ean c\u00e1c h\u00ecnh \u0111\u00f3? ................................................................. ................................................................. ................................................................ ................................................................. ................................................................ \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 23 I.TR\u1eaeC NGHI\u1ec6M 1.B 2.D 3.C 4.C 5.B 6.C II.T\u1ef0 LU\u1eacN 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,75\u0111 36+47=83 100 \u2013 65 =35 47 + 37 = 84 94 \u2013 57 = 37","2)T\u00ecm a , bi\u1ebft 37 \uf02b a \uf03d 81 63 \uf02d a \uf03d 25 a \uf03d 81\uf02d 37 a \uf03d 63 \uf02d 25 a \uf03d 44 a \uf03d 38 3)S\u1ed1 c\u00e2y \u0111\u00e0o \u0111\u00e3 b\u00e1n \u0111i l\u00e0: 100 \u2013 37 = 63 (c\u00e2y \u0111\u00e0o) \u0110\u00e1p s\u1ed1: 63 c\u00e2y \u0111\u00e0o 4) AE B Tam gi\u00e1c : ADE T\u1ee9 gi\u00e1c: ABCD, EBCD DC \u0110\u1ec0 24 1.(1 \u0111i\u1ec3m): Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m : a\/ 78 ; 79 ; 80 ; ..........................................................................................; 85 b\/ 76 ; 78 ; 80 ; ........................................................................................; 90 2.(1 \u0111i\u1ec3m): Vi\u1ebft s\u1ed1 li\u1ec1n tr\u01b0\u1edbc, li\u1ec1n sau v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau ......................... 25 ............................. .............................. 90 .............................. 3.(1 \u0111i\u1ec3m): \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: a\/ 9 + 7 = 17 b\/ 13 - 8 = 6 d\/ 8 + 9 = 17 c\/ 16 - 9 = 7 4.( 2 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : 31 + 15 53 - 28 36 + 26 100 - 36 5.(1 \u0111i\u1ec3m): T\u00ecm x:","89 \u2013 x = 36 x + 6 = 45 ............................................. .......................... .................. ............................................. .......................... .................. ........................... 6.(1\u0111i\u1ec3m): L\u1edbp 2A c\u00f3 26 h\u1ecdc sinh, l\u1edbp 2B c\u00f3 nhi\u1ec1u h\u01a1n l\u1edbp 2A 6 h\u1ecdc sinh. H\u1ecfi l\u1edbp 2B c\u00f3 bao nhi\u00eau h\u1ecdc sinh? Gi\u1ea3i: ........................................................................................................................................... ..... ........................................................................................................................................... ................ ........................................................................................................................................... ................ ........................................................................................................................................... ................ 7.(2\u0111i\u1ec3m): Xem t\u1edd l\u1ecbch th\u00e1ng 2 d\u01b0\u1edbi \u0111\u00e2y r\u1ed3i tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi : Th\u00e1ng Th\u1ee9 hai Th\u1ee9 ba Th\u1ee9 t\u01b0 Th\u1ee9 n\u0103m Th\u1ee9 s\u00e1u Th\u1ee9 b\u1ea3y Ch\u1ee7 nh\u1eadt 4 1 23 11 18 5 67 8 9 10 25 2 12 13 14 15 16 17 19 20 21 22 23 24 26 27 28 Trong th\u00e1ng 2: a. C\u00f3 ...... ng\u00e0y th\u1ee9 n\u0103m. b. C\u00e1c ng\u00e0y th\u1ee9 n\u0103m l\u00e0:......................................................................................................... c. Ng\u00e0y 17 th\u00e1ng hai l\u00e0 ng\u00e0y th\u1ee9 :......................................................................................... d. C\u00f3 t\u1ea5t c\u1ea3 ........................................ ng\u00e0y.","8.(1\u0111i\u1ec3m): Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: H\u00ecnh v\u1ebd b\u00ean : a. C\u00f3 .............. h\u00ecnh tam gi\u00e1c b. C\u00f3 .................. h\u00ecnh t\u1ee9 gi\u00e1c \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 24 1) .a) \u2026.;\u2026;\u2026;81;82;83;84;\u2026. b) \u2026;\u2026;\u2026;82;84;86;88;\u2026 2) S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau S\u1ed1 li\u1ec1n tr\u01b0\u1edbc 24 25 26 89 90 91 3) a) 9 + 7 = 17 . S b) 13 \u2013 8 = 6 . S c) 16 \u2013 9 = 7 . \u0110 d) 8 + 9 = 17 . \u0110 4) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 31 + 15 = 46 53 \u2013 28 = 25 36 + 26 = 62 100 \u2013 36 = 64 5)89 \uf02d x \uf03d 36 x \uf02b 6 \uf03d 45 x \uf03d 89 \uf02d 36 x \uf03d 45 \uf02d 6 x \uf03d 53 x \uf03d 39 6) S\u1ed1 h\u1ecdc sinh l\u1edbp 2B l\u00e0 : 26 + 6 = 32 (h\u1ecdc sinh) \u0110\u00e1p s\u1ed1 : 32 h\u1ecdc sinh 7) .a) C\u00f3 4 ng\u00e0y th\u1ee9 n\u0103m b) C\u00e1c ng\u00e0y th\u1ee9 n\u0103m l\u00e0 : 1; 8;15; 22 c) Ng\u00e0y 17 th\u00e1ng 2 l\u00e0 ng\u00e0y th\u1ee9 b\u1ea3y d) C\u00f3 t\u1ea5t c\u1ea3 28 ng\u00e0y 8) C\u00f3 2 tam gi\u00e1c, c\u00f3 4 t\u1ee9 gi\u00e1c.","\u0110\u1ec0 25 B\u00e0i 1: ? 36, 38, \u2026, 42, \u2026, \u2026, \u2026.., 50. B\u00e0i 2: N\u1ed1i ph\u00e9p t\u00ednh v\u1edbi k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh \u0111\u00f3 6+9 16 17 - 9 13 6+ 7 15 9+7 8 B\u00e0i 3: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng b )18 - 9= 13 a ) 9 + 7 = 16 c ) 18 \u2013 9 = 10 d ) 15 \u2013 4 = 11 B\u00e0i 4: Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang 28 + 4 = ? A . 68 B . 23 C. 32 D. 32m B\u00e0i 5: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 26 + 35 26 + 59 75 \u2013 17 60 \u2013 43 \u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026. B\u00e0i 6 : T\u00ecm x x + 17 = 24 45 \u2013 x = 19 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026................................ \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026................................ \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026................................ B\u00e0i 7 : M\u1ed9t c\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 74 kil\u00f4 gam \u0111\u01b0\u1eddng, bu\u1ed5i chi\u1ec1u b\u00e1n \u00edt h\u01a1n bu\u1ed5i s\u00e1ng 15 kil\u00f4 gam \u0111\u01b0\u1eddng. H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng \u0111\u00f3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau kil\u00f4 gam \u0111\u01b0\u1eddng?","B\u00e0i gi\u1ea3i : \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b . B\u00ecnh nh\u1ecf \u0111\u1ef1ng 14l\u00edt n\u01b0\u1edbc, b\u00ecnh l\u1edbn \u0111\u1ef1ng nhi\u1ec1u h\u01a1n b\u00ecnh nh\u1ecf 6l\u00edt n\u01b0\u1edbc. H\u1ecfi b\u00ecnh l\u1edbn \u0111\u1ef1ng bao nhi\u00eau l\u00edt n\u01b0\u1edbc ? B\u00e0i gi\u1ea3i : T\u00f3m t\u1eaft\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. . \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 8: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng H\u00ecnh v\u1ebd b\u00ean a . C\u00f3 \u2026.. tam gi\u00e1c. b . C\u00f3 \u2026.. t\u1ee9 gi\u00e1c \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 25 1) \u2026;\u2026.;40;\u2026.;44;46;48 2) 6+9=15 17 \u2013 9 = 8 6 + 7 =13 9 + 7 =16 3) .a)\u0110 b) S c) S d) \u0110 4) C 5) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 26+35=61 26+59=85 75 \u2013 17 =58 60 \u2013 43 = 17 6) x \uf02b17 \uf03d 24 45 \uf02d x \uf03d 19 x \uf03d 24 \uf02d17 x \uf03d 45 \uf02d19 x\uf03d7 x \uf03d 26 7)a) S\u1ed1 kilogam \u0111\u01b0\u1eddng, bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n l\u00e0: 74 \u2013 15 = 59 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1: 59 kg \u0111\u01b0\u1eddng b) S\u1ed1 l\u00edt n\u01b0\u1edbc b\u00ecnh l\u1edbn \u0111\u1ef1ng l\u00e0: 14 + 6 = 20 ( l n\u01b0\u1edbc) \u0110\u00e1p s\u1ed1: 20 l n\u01b0\u1edbc 8) a) c\u00f3 5 tam gi\u00e1c b) c\u00f3 4 t\u1ee9 gi\u00e1c .","\u0110\u1ec0 26 B\u00e0i 1: (1 \u0111i\u1ec3m) T\u00ednh nh\u1ea9m: 16 + 3 = \u2026.. 14 \u2013 8 = \u2026.. 15 \u2013 6 = \u2026.. 9 + 7 = \u2026.. B\u00e0i 2: (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : a) 35 + 44 b) 46 + 25 c) 80 \u2013 47 d) 39 \u2013 16 ............. ............. ............. ............. ............. .............. .............. .............. ............. .............. ............. .............. B\u00e0i 3: (1 \u0111i\u1ec3m) b) 24kg \u2013 13kg + 4kg = S\u1ed1 : ? a) 16l+ 5 l \u2013 10l = B\u00e0i 4: (2 \u0111i\u1ec3m) T\u00ecm X bi\u1ebft: a) X + 16 = 73 b) X \u2013 27 = 57 .......................................... ................................ ......................................... ................................ B\u00e0i 5: (1 \u0111i\u1ec3m) Nh\u1eadn d\u1ea1ng h\u00ecnh : Trong h\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y: c. C\u00f3 \u2026 h\u00ecnh tam gi\u00e1c. d. C\u00f3 \u2026 h\u00ecnh t\u1ee9 gi\u00e1c. B\u00e0i 6: (1 \u0111i\u1ec3m) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang : + = 100 -= 50 B\u00e0i 7: (2 \u0111i\u1ec3m) a) M\u1eb9 34 tu\u1ed5i, Cha h\u01a1n M\u1eb9 6 tu\u1ed5i. H\u1ecfi Cha bao nhi\u00eau tu\u1ed5i ? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 b)Anh T\u00f9ng h\u1ecdc l\u1edbp 5 c\u00e2n n\u1eb7ng 43 kg, b\u1ea1n Tu\u1ea5n h\u1ecdc l\u1edbp 2 nh\u1eb9 h\u01a1n anh T\u00f9ng 15 kg. H\u1ecfi b\u1ea1n Tu\u1ea5n c\u00e2n n\u1eb7ng bao nhi\u00eau kil\u00f4gam ? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 26 1) 16 + 3 = 19 14 \u2013 8 = 6 15 \u2013 6 = 9 9 + 7 = 16 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 .a) 35+44=79 b) 46+25=71 c) 80 \u2013 47 = 33 d) 39 \u2013 16 = 23 3) a) 16 l + 5 l \u2013 10 l = 21 l \u2013 10 l = 11 l b) 24 kg \u2013 13 kg + 4 kg = 11 kg + 4 kg = 15 kg 4)a) x \uf02b16 \uf03d 73 b) x \uf02d 27 \uf03d 57 x \uf03d 73 \uf02d16 x \uf03d 57 \uf02b 27 x \uf03d 57 x \uf03d 84 5) c) C\u00f3 5 tam gi\u00e1c 95 \u2013 45 = 50 d) c\u00f3 3 t\u1ee9 gi\u00e1c 6) 70 + 30 = 100 7) a) S\u1ed1 tu\u1ed5i c\u1ee7a cha l\u00e0 : 34 + 6 = 40 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 40 tu\u1ed5i b) S\u1ed1 kilogam b\u1ea1n Tu\u1ea5n n\u1eb7ng l\u00e0 : 43 \u2013 15 = 28 (kg) \u0110\u00e1p s\u1ed1: 28 kg","\u0110\u1ec0 27 PH\u1ea6N TR\u1eaeC NGHI\u1ec6M B\u00e0i 1 : Khoanh tr\u00f2n v\u00e0o c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 ho\u00e0n th\u00e0nh c\u00e1c b\u00e0i t\u1eadp sau: a) T\u00ecm x , bi\u1ebft 9 + x = 16 A. x = 9 B. x = 8 C. x = 7 b) Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 23 + 77 C. 69 + 30 c) K\u1ebft qu\u1ea3 t\u00ednh 12 - 2 - 6 b\u1eb1ng k\u1ebft qu\u1ea3 ph\u00e9p tr\u1eeb n\u00e0o d\u01b0\u1edbi \u0111\u00e2y? A. 12 - 8 B. 12 - 7 C. 12 - 6 d) \u0110i\u1ec1n d\u1ea5u >, < = ? 15 - 8 - 5 13 - 8 - 2 7+6+3 7+9+0 \u0111) \u0110\u00fang ghi \u0111, sai ghi s T\u1eeb 7 gi\u1edd \u0111\u1ebfn 8 gi\u1edd l\u00e0 60 ph\u00fat Th\u00e1ng 12 c\u00f3 30 ng\u00e0y e) H\u00ecnh sau c\u00f3 A. 3 t\u1ee9 gi\u00e1c B. 4 t\u1ee9 gi\u00e1c C. 5 t\u1ee9 gi\u00e1c PH\u1ea6N T\u1ef0 LU\u1eacN B\u00e0i 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 50 - 32 46 + 39 83 + 17 93 - 9 100 - 68 B\u00e0i 3 : T\u00ednh 76 - 29 + 8 36 + 18 - 45 = ............................... X - 24 = 56 =........................ ................................. .......................... B\u00e0i 4 : T\u00ecm X : 42 - X = 24","B\u00e0i 5 : N\u0103m nay b\u00e0 62 tu\u1ed5i, m\u1eb9 k\u00e9m b\u00e0 28 tu\u1ed5i. H\u1ecfi n\u0103m nay m\u1eb9 bao nhi\u00eau tu\u1ed5i? B\u00e0i gi\u1ea3i B\u00e0i 6: T\u00ednh hi\u1ec7u, bi\u1ebft s\u1ed1 b\u1ecb tr\u1eeb l\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 tr\u1eeb l\u00e0 90. B\u00e0i gi\u1ea3i \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 27 Ph\u1ea7n tr\u1eafc nghi\u1ec7m 1) a) C b)B c) A d) 7+6+3=7 + 9 + 0 15 \u2013 8 \u2013 5 = 13 \u2013 8 \u2013 2 \u0111) Th\u00e1ng 12 c\u00f3 30 ng\u00e0y: S T\u1eeb 7 gi\u1edd \u0111\u1ebfn 8 gi\u1edd l\u00e0 60 ph\u00fat : \u0110 e) A B\u00e0i 3. M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 50 \u2013 32 = 18 46 + 39 = 85 83 +17 = 100 93 \u2013 9 = 84 100 \u2013 68 = 32 4) 42 \uf02d x \uf03d 24 x \uf02d 24 \uf03d 56 x \uf03d 42 \uf02d 24 x \uf03d 56 \uf02b 24 x \uf03d 18 x \uf03d 80 5) S\u1ed1 tu\u1ed5i n\u0103m nay c\u1ee7a m\u1eb9 l\u00e0 : 62 \u2013 28 = 34 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 34 tu\u1ed5i 6) S\u1ed1 b\u1ecb tr\u1eeb l\u00e0 : 99 Hi\u1ec7u l\u00e0 : 99 \u2013 90 = 9 \u0110\u1ec0 28 C\u00e2u 1\/ Vi\u1ebft c\u00e1c s\u1ed1 63,59,71,89,23: a\/ Theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b\/ Theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 2: T\u00ednh: c\/ 37 + 24 =\u2026\u2026. a\/ 23 + 19 =\u2026\u2026. d\/ 36 + 23 =\u2026\u2026. b\/ 42 \u2013 17 = \u2026\u2026 C\u00e2u 3: T\u00ecm x:","a\/ x \u2013 37 = 22 b\/ x + 21 = 89 c\/ x + 19 = 43 d\/ x \u2013 27 = 16 C\u00e2u 4: Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a\/ Trong ph\u00e9p t\u00ednh 42 \u2013 18 = 24, s\u00f4 b\u1ecb tr\u1eeb l\u00e0: A\/ 42 B\/ 18 C\/ 24 b\/ Trong ph\u00e9p t\u00ednh x + 42 = 72, s\u1ed1 h\u1ea1ng x l\u00e0: A\/ 30 B\/ 32 C\/ 20 C\u00e2u 5: Bu\u1ed5i s\u00e1ng, c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 80l d\u1ea7u h\u1ecfa. Bu\u1ed5i chi\u1ec1u, c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c \u00edt h\u01a1n bu\u1ed5i s\u00e1ng 28l d\u1ea7u h\u1ecfa. H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng \u0111\u00f3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l d\u1ea7u h\u1ecfa? B\u00e0i gi\u1ea3i: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 C\u00e2u 6: Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang. H\u00ecnh b\u00ean c\u00f3: d\/ 5 h\u00ecnh t\u1ee9 gi\u00e1c a\/ 2 h\u00ecnh t\u1ee9 gi\u00e1c b\/ 3 h\u00ecnh t\u1ee9 gi\u00e1c c\/ 4 h\u00ecnh t\u1ee9 gi\u00e1c \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 28 1) .a) T\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn: 23; 59; 63; 71; 89 b) T\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9: 89; 71; 63; 59; 23 2) T\u00ednh .a) 23 + 19 = 42 c) 37 + 24 = 61 .b) 42 \u2013 17 = 25 d) 36 + 23 = 59 3) T\u00ecm x x \uf02b 21 \uf03d 89 x \uf02d 37 \uf03d 22 x \uf03d 22 \uf02b 37 x \uf03d 89 \uf02d 21 x \uf03d 59 x \uf03d 68 x \uf02b19 \uf03d 43 x \uf02d 27 \uf03d 16 x \uf03d 43 \uf02d19 x \uf03d 16 \uf02b 27 x \uf03d 24 x \uf03d 43 4) a) A b) A C\u00e2u 5. S\u1ed1 l\u00edt d\u1ea7u h\u1ecfa bu\u1ed5i chi\u1ec1u b\u00e1n l\u00e0: 80 \u2013 28 = 52 ( l d\u1ea7u h\u1ecfa) \u0110\u00e1p s\u1ed1 : 52 l d\u1ea7u h\u1ecfa","C\u00e2u 6. B \u0110\u1ec0 29 Ph\u1ea7n 1: Tr\u1eafc nghi\u1ec7m Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i A, B, C tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang. C\u00e2u 1: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 69 l\u00e0: A. 60 B. 68 C. 70 D. 80 C\u00e2u 2: S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 l\u00e0: A. 10 B. 90 C. 99 D. 100 C\u00e2u 3: 1 gi\u1edd chi\u1ec1u hay c\u00f2n g\u1ecdi l\u00e0 \u2026.. A. 12 gi\u1edd B. 13 gi\u1edd C. 14 gi\u1edd D. 15 gi\u1edd C\u00e2u 4: Th\u1ee9 3 tu\u1ea7n n\u00e0y l\u00e0 ng\u00e0y 21 th\u00e1ng 12. Th\u1ee9 3 tu\u1ea7n sau l\u00e0 ng\u00e0y n\u00e0o? A. 28 th\u00e1ng 12 B. 24 th\u00e1ng 12 C. 22 th\u00e1ng 12 D. 30 th\u00e1ng 12 Ph\u1ea7n 2: T\u1ef1 lu\u1eadn 1.a. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 37 + 54 65 - 29 79 + 13 80 \u2013 44 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b. Ghi k\u1ebft qu\u1ea3 c\u1ee7a t\u1eebng ph\u00e9p t\u00ednh: 27 kg - 7 kg + 3 kg = ..... 18l - 10 l + 2l = ..... 2. T\u00ecm x: a. x + 34 = 57 b. 56 \u2013 x = 38 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 3. \u0110\u1ecdc, vi\u1ebft c\u00e1c ng\u00e0y trong th\u00e1ng: \u0110\u1ecdc Vi\u1ebft Ng\u00e0y hai m\u01b0\u01a1i m\u1ed1t th\u00e1ng m\u1ed9t Ng\u00e0y 17 th\u00e1ng 9 4. a. Bao g\u1ea1o n\u1eb7ng 45 kg. Bao ng\u00f4 n\u1eb7ng h\u01a1n bao g\u1ea1o 25 kg. H\u1ecfi bao ng\u00f4 n\u1eb7ng bao nhi\u00eau kg?","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b. Quy\u1ec3n truy\u1ec7n c\u00f3 85 trang. T\u00e2m \u0111\u00e3 \u0111\u1ecdc 79 trang. H\u1ecfi T\u00e2m c\u00f2n ph\u1ea3i \u0111\u1ecdc m\u1ea5y trang n\u1eefa th\u00ec h\u1ebft quy\u1ec3n truy\u1ec7n? \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 5. Nh\u00e0 Ng\u00e2n nu\u00f4i 69 con v\u1eeba g\u00e0 v\u1eeba v\u1ecbt, trong \u0111\u00f3 c\u00f3 26 con g\u00e0. H\u1ecfi nh\u00e0 Ng\u00e2n nu\u00f4i bao nhi\u00eau con v\u1ecbt? \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026","\u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 29 Ph\u1ea7n 1: 2 \u0111i\u1ec3m \u0110\u00e1p \u00e1n \u0111\u00fang \u0110i\u1ec3m 0,5 \u0111i\u1ec3m C\u00e2u 1 B 0,5 \u0111i\u1ec3m 0,5 \u0111i\u1ec3m C\u00e2u 2 C 0,5 \u0111i\u1ec3m C\u00e2u 3 B - 80 44 C\u00e2u 4 A 36 Ph\u1ea7n 2: 1. 3 \u0111i\u1ec3m a. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: M\u1ed7i c\u00e2u \u0111\u00fang 0,5 \u0111 + 37 - 65 + 79 54 29 13 91 36 92 b. Ghi k\u1ebft qu\u1ea3 c\u1ee7a t\u1eebng ph\u00e9p t\u00ednh: M\u1ed7i c\u00e2u \u0111\u00fang 0,5 \u0111i\u1ec3m a. 27 kg - 7 kg + 3 kg = 23 kg b.18l - 10 l + 2l = 101 2. T\u00ecm x: 1 \u0111i\u1ec3m b. 56 \u2013 x = 38 a. x + 34 = 57 x = 56 - 38 x = 57 \u2013 34 x = 23 x = 18 3. \u0110\u1ecdc, vi\u1ebft c\u00e1c ng\u00e0y trong th\u00e1ng: 1 \u0111i\u1ec3m Vi\u1ebft \u0110\u1ecdc Ng\u00e0y hai m\u01b0\u01a1i m\u1ed1t th\u00e1ng m\u1ed9t Ng\u00e0y 21 th\u00e1ng 1 Ng\u00e0y m\u01b0\u1eddi b\u1ea3y th\u00e1ng ch\u00edn Ng\u00e0y 17 th\u00e1ng 9 4. 2 \u0111i\u1ec3m a. Bao g\u1ea1o n\u1eb7ng 45 kg. Bao ng\u00f4 n\u1eb7ng h\u01a1n bao g\u1ea1o 25. H\u1ecfi bao ng\u00f4 n\u1eb7ng bao nhi\u00eau kg? B\u00e0i gi\u1ea3i Bao ng\u00f4 n\u1eb7ng: 45 + 25 = 70 ( kg ) 0,75 \u0111 \u0110\u00e1p s\u1ed1: 70 kg 0,25 \u0111","b. Quy\u1ec3n truy\u1ec7n c\u00f3 85 trang. T\u00e2m \u0111\u00e3 \u0111\u1ecdc 79 trang. H\u1ecfi T\u00e2m c\u00f2n ph\u1ea3i \u0111\u1ecdc m\u1ea5y trang n\u1eefa th\u00ec h\u1ebft quy\u1ec3n truy\u1ec7n? B\u00e0i gi\u1ea3i S\u1ed1 trang T\u00e2m ph\u1ea3i \u0111\u1ecdc n\u1eefa: 85 \u2013 79 = 6 (trang) 0,75 \u0111 \u0110\u00e1p s\u1ed1: 6 trang 0,25 \u0111 5. 1 \u0111i\u1ec3m: Nh\u00e0 Ng\u00e2n nu\u00f4i 69 con v\u1eeba g\u00e0 v\u1eeba v\u1ecbt, trong \u0111\u00f3 c\u00f3 26 con g\u00e0. H\u1ecfi nh\u00e0 Ng\u00e2n nu\u00f4i bao nhi\u00eau con v\u1ecbt? B\u00e0i gi\u1ea3i S\u1ed1 v\u1ecbt c\u1ee7a nh\u00e0 Ng\u00e2n l\u00e0: 69 \u2013 26 = 43 (con v\u1ecbt) 0,75 \u0111 \u0110\u00e1p s\u1ed1: 43 con v\u1ecbt 0, 25 \u0111 \u0110\u1ec0 30 PH\u1ea6N TR\u1eaeC NGHI\u1ec6M B\u00e0i 1: Khoanh tr\u00f2n v\u00e0o c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 ho\u00e0n th\u00e0nh c\u00e1c b\u00e0i t\u1eadp sau: a) T\u00ecm x , bi\u1ebft 9 + x = 16 A. x = 9 B. x = 8 C. x = 7 b) Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 23 + 77 C. 69 + 30 c) K\u1ebft qu\u1ea3 t\u00ednh 12 - 2 - 6 b\u1eb1ng k\u1ebft qu\u1ea3 ph\u00e9p tr\u1eeb n\u00e0o d\u01b0\u1edbi \u0111\u00e2y? A. 12 - 8 B. 12 - 7 C. 12 - 6 d) \u0110i\u1ec1n d\u1ea5u >, < = ? 15 - 8 - 5 13 - 8 - 2 7+6+3 7+9+0 \u0111) \u0110\u00fang ghi \u0111, sai ghi s T\u1eeb 7 gi\u1edd \u0111\u1ebfn 8 gi\u1edd l\u00e0 60 ph\u00fat Th\u00e1ng 12 c\u00f3 30 ng\u00e0y e) H\u00ecnh sau c\u00f3 A. 3 t\u1ee9 gi\u00e1c B. 4 t\u1ee9 gi\u00e1c","C. 5 t\u1ee9 gi\u00e1c PH\u1ea6N T\u1ef0 LU\u1eacN B\u00e0i 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 50 - 32 46 + 39 83 + 17 93 - 9 100 - 68 B\u00e0i 3: T\u00ednh 76 - 29 + 8 = 36 + 18 - 45 = ............................... X - 24 = 56 .......................... ............................... .......................... B\u00e0i 4: T\u00ecm X: 42 - X = 24 B\u00e0i 5 : N\u0103m nay b\u00e0 62 tu\u1ed5i, m\u1eb9 k\u00e9m b\u00e0 28 tu\u1ed5i. H\u1ecfi n\u0103m nay m\u1eb9 bao nhi\u00eau tu\u1ed5i? B\u00e0i gi\u1ea3i","B\u00e0i 6: T\u00ednh hi\u1ec7u, bi\u1ebft s\u1ed1 b\u1ecb tr\u1eeb l\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 tr\u1eeb l\u00e0 90. B\u00e0i gi\u1ea3i","Ph\u1ea7n tr\u1eafc nghi\u1ec7m 2) a) C b)B c) A d) 7+6+3=7 + 9 + 0 15 \u2013 8 \u2013 5 = 13 \u2013 8 \u2013 2 \u0111) Th\u00e1ng 12 c\u00f3 30 ng\u00e0y: S T\u1eeb 7 gi\u1edd \u0111\u1ebfn 8 gi\u1edd l\u00e0 60 ph\u00fat : \u0110 e) A B\u00e0i 3. M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 50 \u2013 32 = 18 46 + 39 = 85 83 +17 = 100 93 \u2013 9 = 84 100 \u2013 68 = 32 4) 42 \uf02d x \uf03d 24 x \uf02d 24 \uf03d 56 x \uf03d 42 \uf02d 24 x \uf03d 56 \uf02b 24 x \uf03d 18 x \uf03d 80 5) S\u1ed1 tu\u1ed5i n\u0103m nay c\u1ee7a m\u1eb9 l\u00e0 : 62 \u2013 28 = 34 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 34 tu\u1ed5i 7) S\u1ed1 b\u1ecb tr\u1eeb l\u00e0 : 99 Hi\u1ec7u l\u00e0 : 99 \u2013 90 = 9 \u0110\u1ec0 31 I. Ph\u1ea7n tr\u1eafc nghi\u1ec7m: (7 \u0111i\u1ec3m C\u00e2u1. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: S\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1: 70; 39; 91; 48 l\u00e0 s\u1ed1 n\u00e0o? A. 39 B. 70 C. 48 D. 91 C\u00e2u 2. (0,5 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 47 + 35 = ? A. 82 B. 72 C. 12 D. 42 C\u00e2u 3. (0,5 \u0111i\u1ec3m ) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 51 \u2013 12 = ? A. 41 B.63 C. 39 D. 49 C\u00e2u 4. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: T\u00ecm x , bi\u1ebft x + 29 = 45 A. x = 74 B. x = 16 C. x = 26 D. x = 24 C\u00e2u 5 . (1 \u0111i\u1ec3m) \u0110\u1ed3ng h\u1ed3 b\u00ean ch\u1ec9 m\u1ea5y gi\u1edd? A. 3 gi\u1edd. B. 12 gi\u1edd C. 6 gi\u1edd D. 9 gi\u1edd C\u00e2u 6. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: 4 dm = \u2026\u2026cm A. 4 cm B. 44cm C. 40cm D. 14 cm C\u00e2u 7. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: H\u00ecnh v\u1ebd b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c? A. 1 B. 2 C. 3 D. 4 C\u00e2u 8. ( 1 \u0111i\u1ec3m) \u0110\u00fang th\u00ec ghi \u0110, sai th\u00ec ghi S v\u00e0o \u00f4 vu\u00f4ng: H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 s\u1ed1 h\u00ecnh t\u1ee9 gi\u00e1c l\u00e0: - C\u00f3 2 h\u00ecnh t\u1ee9 gi\u00e1c:","- C\u00f3 3 h\u00ecnh t\u1ee9 gi\u00e1c: II. Ph\u1ea7n t\u1ef1 lu\u1eadn: (3 \u0111i\u1ec3m) C\u00e2u 9. (1 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 39 + 14; 48 + 7; 72 - 34 100 - 25 \u2026\u2026\u2026.. . \u2026\u2026\u2026. \u2026\u2026\u2026.. \u2026\u2026\u2026. \u2026\u2026\u2026.. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026. .. \u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026. C\u00e2u 10. (2 \u0111i\u1ec3m) Th\u00f9ng to \u0111\u1ef1ng \u0111\u01b0\u1ee3c 62 l d\u1ea7u, th\u00f9ng nh\u1ecf \u0111\u1ef1ng \u0111\u01b0\u1ee3c \u00edt h\u01a1n th\u00f9ng to 15 l d\u1ea7u. H\u1ecfi th\u00f9ng nh\u1ecf \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 ....................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 31 C\u00e2u 1. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: S\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1: 70; 39; 91; 48 l\u00e0: A. 39 B. 70 C. 48 D. 91 Khoanh v\u00e0o ch\u1eef D. 91 C\u00e2u 2. (0,5 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 47 + 35 = ? A. 82 B. 72 C. 12 D. 42 Khoanh v\u00e0o ch\u1eef A. 82 C\u00e2u 3. (0,5 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 51 \u2013 12 = ? A. 41 B. 63 C. 39 D. 49 Khoanh v\u00e0o ch\u1eef C. 39 C\u00e2u 4. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: T\u00ecm x, bi\u1ebft x + 29 = 50 - 5 A. x = 74 B. x = 16 C. x = 26 D. 24 D. 9 gi\u1edd Khoanh v\u00e0o ch\u1eef B. x = 16 C\u00e2u 5 . (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: \u0110\u1ed3ng h\u1ed3 b\u00ean ch\u1ec9 m\u1ea5y gi\u1edd? A. 3 gi\u1edd B. 12 gi\u1edd C. 6 gi\u1edd Khoanh v\u00e0o ch\u1eef A. 3 gi\u1edd C\u00e2u 6. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: 4 dm = \u2026\u2026cm A. 4 cm B. 44cm C. 40cm D. 14 cm Khoanh v\u00e0o ch\u1eef C. 40 B\u00e0i 7. (1 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang: H\u00ecnh v\u1ebd b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c? A. 1 B.2 C. 3 D. 4 Khoanh v\u00e0o ch\u1eef C. 3 B\u00e0i 8. (1 \u0111i\u1ec3m) \u0110\u00fang th\u00ec ghi \u0110, sai th\u00ec ghi S v\u00e0o \u00f4 vu\u00f4ng:","H\u00ecnh v\u1ebd d\u01b0\u1edbi S - C\u00f3 2 h\u00ecnh t\u1ee9 gi\u00e1c: \u0110 - C\u00f3 3 h\u00ecnh t\u1ee9 gi\u00e1c: B\u00e0i 9 . (1 \u0111i\u1ec3m) M\u1ed7i ph\u00e9p t\u00ednh \u0111\u00fang 0, 25 \u0111i\u1ec3m. (N\u1ebfu h\u1ecdc sinh \u0111\u1eb7t t\u00ednh \u0111\u00fang nh\u01b0ng sai k\u1ebft qu\u1ea3 th\u00ec \u0111\u1ea1t m\u1ed9t n\u1eeda s\u1ed1 \u0111i\u1ec3m ) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 39 + 14; 48 + 7; 72 - 34 100 - 25 39 48 72 100 ++ - - 14 7 34 25 53 55 38 75 B\u00e0i 10. (2 \u0111i\u1ec3m) Th\u00f9ng to \u0111\u1ef1ng \u0111\u01b0\u1ee3c 62 l d\u1ea7u, th\u00f9ng nh\u1ecf \u0111\u1ef1ng \u0111\u01b0\u1ee3c \u00edt h\u01a1n th\u00f9ng to 15 l d\u1ea7u. H\u1ecfi th\u00f9ng nh\u1ecf \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u? B\u00e0i gi\u1ea3i S\u1ed1 l\u00edt d\u1ea7u th\u00f9ng nh\u1ecf \u0111\u1ef1ng \u0111\u01b0\u1ee3c l\u00e0:(0,5 \u0111i\u1ec3m) 62 \u2013 15 = 47 (l) (1,0 \u0111i\u1ec3m) \u0110\u00e1p s\u1ed1: 47 l d\u1ea7u (0,5 \u0111i\u1ec3m) - L\u1eddi gi\u1ea3i \u0111\u00fang cho 0,5 \u0111; ph\u00e9p t\u00ednh \u0111\u00fang cho 1\u0111; \u0111\u00e1p s\u1ed1 \u0111\u00fang cho 0,5\u0111. - \u1ede ph\u00e9p t\u00ednh, n\u1ebfu h\u1ecdc sinh ghi \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh 62 \u2013 15 = ... nh\u01b0ng t\u00ednh sai k\u1ebft qu\u1ea3 cho 0,5\u0111. \u0110\u1ec0 32 A. PH\u1ea6N TR\u1eaeC NGHI\u1ec6M (3 \u0111i\u1ec3m): Khoanh tr\u00f2n v\u00e0o c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 ho\u00e0n th\u00e0nh c\u00e1c b\u00e0i t\u1eadp sau: C\u00e2u 1: T\u00ecm x, bi\u1ebft 9 + x = 14 A. x = 5 B. x = 8 C. x = 6 C\u00e2u 2: Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 23 + 76 C. 69 + 31 C\u00e2u 3: K\u1ebft qu\u1ea3 t\u00ednh 13 - 3 - 4 b\u1eb1ng k\u1ebft qu\u1ea3 ph\u00e9p tr\u1eeb n\u00e0o d\u01b0\u1edbi \u0111\u00e2y? A. 12 - 8 B. 12 - 6 C. 12 - 7 C\u00e2u 4: \u0110i\u1ec1n d\u1ea5u >, < = ? 15 - 8 - 5 13 - 4 - 2 7+7+3 7+9+0 C\u00e2u 5: \u0110\u00fang ghi \u0111, sai ghi s T\u1eeb 7 gi\u1edd \u0111\u1ebfn 8 gi\u1edd l\u00e0 80 ph\u00fat Th\u00e1ng 12 c\u00f3 31 ng\u00e0y","B. PH\u1ea6N T\u1ef0 LU\u1eacN B\u00e0i 1 (2 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 60 - 32 26 + 39 73 + 17 100 - 58 .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... B\u00e0i 2 (1 \u0111i\u1ec3m): T\u00ednh 46 + 18 - 35 = ............................... 86 - 29 + 8 =........................ ....................................................... ..................................................... B\u00e0i 3 (1 \u0111i\u1ec3m): T\u00ecm X: a; 52 - X = 25 b; X - 34 = 46 .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... B\u00e0i 4 : (2 \u0111i\u1ec3m) N\u0103m nay m\u1eb9 32 tu\u1ed5i, m\u1eb9 k\u00e9m b\u00e0 28 tu\u1ed5i. H\u1ecfi n\u0103m nay b\u00e0 bao nhi\u00eau tu\u1ed5i? B\u00e0i gi\u1ea3i .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... B\u00e0i 5 (1 \u0111i\u1ec3m): T\u00ednh hi\u1ec7u, bi\u1ebft s\u1ed1 b\u1ecb tr\u1eeb l\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 tr\u1eeb l\u00e0 90. B\u00e0i gi\u1ea3i .................................................................................................................................... .................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 32 B\u00e0i 1 : (3 \u0111i\u1ec3m) Khoanh \u0111\u00fang m\u1ed7i ph\u1ea7n cho 0,5 \u0111i\u1ec3m C\u00e2u 1: A C\u00e2u 2: C C\u00e2u 3: B C\u00e2u 4: C","C\u00e2u 5: \u0110- S B\u00e0i 2 : (2 \u0111i\u1ec3m) T\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh cho 0,5 \u0111i\u1ec3m \u0110\/s: 28; 65; 90; 42 B\u00e0i 3 : (1 \u0111i\u1ec3m) T\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh cho 0,5 \u0111i\u1ec3m \u0110\/s: 29;65 B\u00e0i 4 : (1 \u0111i\u1ec3m) T\u00ecm \u0111\u00fang m\u1ed7i s\u1ed1 (0,5 \u0111i\u1ec3m) a; X= 27 b; X=80 B\u00e0i 5 : (2 \u0111i\u1ec3m) - Vi\u1ebft \u0111\u00fang c\u00e2u l\u1eddi gi\u1ea3i (0,5 \u0111i\u1ec3m) N\u0103m nay B\u00e0 c\u00f3 s\u1ed1 tu\u1ed5i l\u00e0: - Vi\u1ebft ph\u00e9p t\u00ednh \u0111\u00fang (1 \u0111i\u1ec3m) 32 + 29 + = 61 ( tu\u1ed5i) - Vi\u1ebft \u0111\u00e1p s\u1ed1 \u0111\u00fang (0,5 \u0111i\u1ec3m) \u0110\/s: 61 tu\u1ed5i B\u00e0i 6 : (1 \u0111i\u1ec3m) - T\u00ecm \u0111\u00fang s\u1ed1 b\u1ecb tr\u1eeb cho 0,25 \u0111i\u1ec3m S\u1ed1 b\u1ecb tr\u1eeb l\u00e0 99 - Vi\u1ebft \u0111\u00fang c\u00e2u l\u1eddi gi\u1ea3i (0,25 \u0111i\u1ec3m) Ta c\u00f3 ph\u00e9p t\u00ednh: - Vi\u1ebft ph\u00e9p t\u00ednh \u0111\u00fang (0,25 \u0111i\u1ec3m) 99 \u2013 90 = 9 - Vi\u1ebft \u0111\u00e1p s\u1ed1 \u0111\u00fang (0,5 \u0111i\u1ec3m) \u0110\/s : 9 \u0110\u1ec0 33 I. PH\u1ea6N TR\u1eaeC NGHI\u1ec6M (4 \u0111i\u1ec3m) Khoanh tr\u00f2n v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang: B\u00e0i 1: T\u00ednh 35 +9 A. 52 B. 44 C. 43 B\u00e0i 2: S\u1ed1 li\u1ec1n sau c\u1ee7a 68 l\u00e0: A. 67 B. 70 C. 69 B\u00e0i 3: K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p tr\u1eeb: 87 kg \u2013 8 kg l\u00e0: A. 79 B. 58 C. 86 B\u00e0i 4 : Trong h\u00ecnh v\u1ebd b\u00ean c\u00f3 s\u1ed1 h\u00ecnh tam gi\u00e1c: A. 1 h\u00ecnh B. 2 h\u00ecnh C. 3 h\u00ecnh B\u00e0i 5 : Em \u0111i ng\u1ee7 l\u00fac.............gi\u1edd t\u1ed1i A. 7 gi\u1edd B. 8 gi\u1edd C. 9 gi\u1edd B\u00e0i 6: T\u00ednh 4 \u00d7 7","A. 25 B.28 C. 26 II. PH\u1ea6N T\u1ef0 LU\u1eacN (6 \u0111i\u1ec3m) B\u00e0i 1: (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 46 + 28 62 +37 84 - 25 100 - 48 ...................................................................................................................................... ....................................................................................................................................................... ....................................................................................................................................................... .................................................................................................... B\u00e0i 2: (1\u0111i\u1ec3m) T\u00ecm X 15 + X = 24 X \u2013 16 = 34 ....................................................................................................................................................... ....................................................................................................................................................... ....................................................................................................................................................... ................................................................................. B\u00e0i 3: (2\u0111i\u1ec3m) N\u0103m nay b\u00e0 65 tu\u1ed5i, m\u1eb9 k\u00e9m b\u00e0 29 tu\u1ed5i. H\u1ecfi n\u0103m nay m\u1eb9 bao nhi\u00eau tu\u1ed5i? B\u00e0i gi\u1ea3i. ...................................................................................................................................... ....................................................................................................................................................... ....................................................................................................................................................... ....................................................................................................................................................... ................................................................................... B\u00e0i 4: (1\u0111i\u1ec3m) H\u00e3y v\u1ebd \u0111o\u1ea1n th\u1eb3ng AB d\u00e0i 5 cm: ....................................................................................................................................... I TR\u1eaeC NGHI\u1ec6M \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 33 C\u00e2u 1 234 5 6 \u0110\u00e1p \u00e1n B CAB C B \u0110i\u1ec3m 0,5 0,5 0,5 0,5 1 1 II PH\u1ea6N T\u1ef0 LU\u1eacN B\u00e0i 1 : T\u00ednh M\u1ed7i ph\u00e9p t\u00ednh \u0111\u00fang 0,5 \u0111i\u1ec3m ( N\u1ebfu \u0111\u1eb7t t\u00ednh sai, k\u1ebft qu\u1ea3 \u0111\u00fang ho\u1eb7c \u0111\u1eb7t t\u00ednh \u0111\u00fang k\u1ebft qu\u1ea3 sai 0,25 \u0111i\u1ec3m) 46 62 84 100 + 28 + 37 - 35 - 48 74 99 49 52 B\u00e0i 2 : T\u00ecm X 15 + X = 24 X - 16 = 34 X = 24 - 15 X = 34 + 16","X = 9 0,5 \u0111i\u1ec3m X = 50 0,5\u0111i\u1ec3m B\u00e0i 3 : B\u00e0i gi\u1ea3i: N\u0103m nay m\u1eb9 c\u00f3 s\u1ed1 tu\u1ed5i l\u00e0: 65 - 29 = 36 (tu\u1ed5i) (1 \u0111i\u1ec3m) \u0110\u00e1p s\u1ed1: 36 tu\u1ed5i (1 \u0111i\u1ec3m) B\u00e0i 4: V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB 1\u0111i\u1ec3m \u0110\u1ec0 34 A. PH\u1ea6N TR\u1eaeC NGHI\u1ec6M (6 \u0111i\u1ec3m): Khoanh tr\u00f2n v\u00e0o c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 ho\u00e0n th\u00e0nh c\u00e1c b\u00e0i t\u1eadp sau: C\u00e2u 1: T\u00ecm x , bi\u1ebft 9 + x = 14 A. x = 5 B. x = 8 C. x = 6 C\u00e2u 2: Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 23 + 76 C. 69 + 31 C. 12 \u2013 7 C\u00e2u 3: K\u1ebft qu\u1ea3 t\u00ednh 13 - 3 - 4 b\u1eb1ng k\u1ebft qu\u1ea3 ph\u00e9p tr\u1eeb n\u00e0o d\u01b0\u1edbi \u0111\u00e2y? A. 12 \u2013 8 B. 12 \u2013 6 C\u00e2u 4: 1 dm = .....cm A\/ 10 cm B\/ 1 cm B\/ 100cm C\/ 11 cm D\/ 90 C\u00e2u 5: S\u1ed1 li\u1ec1n sau s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 l\u00e0: A\/ 99 B\/ 98 C\/ 100 C\u00e2u 6: H\u00ecnh sau c\u00f3 A. 3 t\u1ee9 gi\u00e1c B. 4 t\u1ee9 gi\u00e1c C. 5 t\u1ee9 gi\u00e1c B. PH\u1ea6N T\u1ef0 LU\u1eacN ( 4 \u0111) B\u00e0i 1 (1 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 60 \u2013 32 26 + 39 73 + 17 100 \u2013 58 .................................................................................................................................... ....................................................................................................................................",".................................................................................................................................... .................................................................................................................................... B\u00e0i 2 (1 \u0111i\u1ec3m) : T\u00ecm X: a. X + 37 = 82 b. X - 34 = 46 .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... B\u00e0i 3: (1 \u0111i\u1ec3m) M\u1ea3nh v\u1ea3i m\u00e0u xanh d\u00e0i 35 dm, m\u1ea3nh v\u1ea3i m\u00e0u t\u00edm ng\u1eafn h\u01a1n m\u1ea3nh v\u1ea3i m\u00e0u xanh 17 dm. H\u1ecfi m\u1ea3nh v\u1ea3i m\u00e0u t\u00edm d\u00e0i bao nhi\u00eau \u0111\u1ec1 - xi \u2013 m\u00e9t? B\u00e0i gi\u1ea3i .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... B\u00e0i 4 (1 \u0111i\u1ec3m): T\u00ednh hi\u1ec7u, bi\u1ebft s\u1ed1 b\u1ecb tr\u1eeb l\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 tr\u1eeb l\u00e0 90. B\u00e0i gi\u1ea3i .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 34 A\/ PH\u1ea6N TR\u1eaeC NGHI\u1ec6M: (6 \u0111i\u1ec3m) Khoanh \u0111\u00fang m\u1ed7i ph\u1ea7n cho 1 \u0111i\u1ec3m C\u00e2u 1: A C\u00e2u 2: C C\u00e2u 3: B C\u00e2u 4: A C\u00e2u 5: C C\u00e2u 6: A B\/ PH\u1ea6N T\u1ef0 LU\u1eacN: B\u00e0i 1: (1 \u0111i\u1ec3m) T\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh cho 0,25 \u0111i\u1ec3m","\u0110\/s: 28; 65; 90; 42 B\u00e0i 2: (1 \u0111i\u1ec3m) T\u00ecm \u0111\u00fang m\u1ed7i s\u1ed1 (0,5 \u0111i\u1ec3m) a. X= 45 b;. X= 80 B\u00e0i 3: (1 \u0111i\u1ec3m) - Vi\u1ebft \u0111\u00fang c\u00e2u l\u1eddi gi\u1ea3i (0,25 \u0111i\u1ec3m) M\u1ea3nh v\u1ea3i t\u00edm d\u00e0i l\u00e0: - Vi\u1ebft ph\u00e9p t\u00ednh \u0111\u00fang ( 0,5 \u0111i\u1ec3m) 34 - 17 = 17 ( dm) - Vi\u1ebft \u0111\u00e1p s\u1ed1 \u0111\u00fang (0,25 \u0111i\u1ec3m) \u0110\/s: 17 dm B\u00e0i 4: (1 \u0111i\u1ec3m) - T\u00ecm \u0111\u00fang s\u1ed1 b\u1ecb tr\u1eeb cho 0,25 \u0111i\u1ec3m S\u1ed1 b\u1ecb tr\u1eeb l\u00e0 99 - Vi\u1ebft \u0111\u00fang c\u00e2u l\u1eddi gi\u1ea3i (0,25 \u0111i\u1ec3m) Ta c\u00f3 ph\u00e9p t\u00ednh: - Vi\u1ebft ph\u00e9p t\u00ednh \u0111\u00fang (0,25 \u0111i\u1ec3m) 99 \u2013 90 = 9 - Vi\u1ebft \u0111\u00e1p s\u1ed1 \u0111\u00fang (0, 25 \u0111i\u1ec3m) \u0110\/s : 9 \u0110\u1ec0 35 C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a) 45 + 32 39 + 48 c) 80 \u2013 23 d) 100 \u2013 58 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026.... \u2026\u2026\u2026.... \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. C\u00e2u 2: Vi\u1ebft v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) th\u00edch h\u1ee3p: a) 7 + 6 + 3 ................. 7 + 9 + 0 b) Th\u00e1ng 12 c\u00f3 ........ ng\u00e0y c) S\u1ed1 \u1edf gi\u1eefa 29 v\u00e0 31 l\u00e0:\u2026. d) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 50 l\u00e0 \u2026. C\u00e2u 3: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc \u00fd tr\u1ea3 l\u1eddi \u0111\u00fang: a) Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 69 + 30 C. 23 + 77 b) K\u1ebft qu\u1ea3 ph\u00e9t t\u00ednh 80 l\u00edt - 20 l\u00edt - 30 l\u00edt l\u00e0: A. 50 l\u00edt B. 40 l\u00edt C. 20 l\u00edt D. 30 l\u00edt D. 44 c) T\u00ecm x , bi\u1ebft : 19 + x = 40 A. 21 B. 22 C. 23 d) S\u1ed1 b\u1ecb tr\u1eeb v\u00e0 s\u1ed1 tr\u1eeb l\u1ea7n l\u01b0\u1ee3t l\u00e0 71 v\u00e0 26 th\u00ec hi\u1ec7u l\u00e0: A. 97 B. 45 C. 35 C\u00e2u 4: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) a) 14 cm + 26 cm = 4 dm b) T\u1eeb 11 gi\u1edd \u0111\u1ebfn 12 gi\u1edd l\u00e0 60 ph\u00fat C\u00e2u 5: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m:","H\u00ecnh v\u1ebd b\u00ean: a) C\u00f3 \u2026. h\u00ecnh t\u1ee9 gi\u00e1c b) C\u00f3 \u2026. h\u00ecnh tam gi\u00e1c C\u00e2u 6: Tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 m\u1ed9t c\u00f3 75 con, tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai \u00edt h\u01a1n tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 m\u1ed9t 17 con. H\u1ecfi tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai c\u00f3 bao nhi\u00eau con ? \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 35 C\u00e2u 1: (3.0 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh \u0111\u00fang, ghi 0.75 \u0111i\u1ec3m\/ ph\u00e9p t\u00ednh. T\u00ednh \u0111\u00fang nh\u01b0ng ch\u01b0a \u0111\u1eb7t t\u00ednh, ghi 0.5 \u0111i\u1ec3m\/ h\u00e9p t\u00ednh. C\u00e2u 2: (2 \u0111i\u1ec3m): Vi\u1ebft \u0111\u00fang m\u1ed7i s\u1ed1 theo y\u00eau c\u1ea7u, ghi 0.5 \u0111i\u1ec3m. Vi\u1ebft v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) th\u00edch h\u1ee3p: a) 7 + 6 + 3 = 7 + 9 + 0 b) Th\u00e1ng 12 c\u00f3 31 ng\u00e0y c) S\u1ed1 \u1edf gi\u1eefa 29 v\u00e0 31 l\u00e0: 30 d) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 50 l\u00e0 49 C\u00e2u 3: (2.0 \u0111i\u1ec3m): Khoanh v\u00e0o \u00fd \u0111\u00fang m\u1ed7i c\u00e2u, ghi 0.5 \u0111i\u1ec3m). a) C b) D c) A d) B C\u00e2u 4: (1.0 \u0111i\u1ec3m): \u0110i\u1ec1n \u0110 ho\u1eb7c S v\u00e0o ch\u1ed7 ch\u1ea5m th\u00edch h\u1ee3p \u1edf m\u1ed7i \u00fd, ghi 0.5 \u0111i\u1ec3m. a) \u0110 b) \u0110 C\u00e2u 5: (0.5 \u0111i\u1ec3m) Vi\u1ebft \u0111\u00fang m\u1ed7i s\u1ed1 theo y\u00eau c\u1ea7u , ghi 0.25 \u0111i\u1ec3m. a) 1 h\u00ecnh t\u1ee9 gi\u00e1c b) 4 h\u00ecnh tam gi\u00e1c C\u00e2u 6: (1.5 \u0111i\u1ec3m): C\u0103n c\u1ee9 v\u00e0o l\u1eddi gi\u1ea3i, ph\u00e9p t\u00ednh v\u00e0 c\u00e1ch ghi \u0111\u00e1p s\u1ed1 m\u00e0 ghi t\u1eeb 0 \u0111\u1ebfn 1.5 \u0111i\u1ec3m. Tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai c\u00f3 l\u00e0: 75 \u2013 17 = 58 (con) \u0110\u00e1p s\u1ed1: 58 con \u0110\u1ec0 36 1\/ \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : a\/ 73 + 27 b\/ 70 -16 c\/ 66 + 29 d\/ 44 - 8 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 2\/ Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc \u00fd tr\u1ea3 l\u1eddi \u0111\u00fang : a\/ Trong c\u00e1c s\u1ed1 sau, s\u1ed1 b\u00e9 nh\u1ea5t l\u00e0 : A. 45 B. 54 C. 44 b\/T\u00ecm x : 65 \u2013 x = 26 A. x = 91 B. x = 39 C. x = 49 c\/ K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 70 dm + 30dm - 20dm A. 60dm B. 70dm C. 80dm","d\/ Kim ng\u1eafn ch\u1ec9 s\u1ed1 8, kim d\u00e0i ch\u1ec9 s\u1ed1 12. \u0110\u1ed3ng h\u1ed3 ch\u1ec9 : A. 8 gi\u1edd B. 12 gi\u1edd C. 21 gi\u1edd 3\/ Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 ch\u1ea5m (...) cho th\u00edch h\u1ee3p : a\/ 57= 50 + .... b\/ S\u1ed1 li\u1ec1n sau c\u1ee7a 80 l\u00e0 .... . c\/ 9=18 - ..... d\/ S\u1ed1 \u1edf gi\u1eefa 79 v\u00e0 81 l\u00e0.... 4\/ Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc \u00fd tr\u1ea3 l\u1eddi \u0111\u00fang : H\u00ecnh v\u1ebd b\u00ean a) C\u00f3 m\u1ea5y h\u00ecnh tam gi\u00e1c ? A. 2 B. 3 C. 4 b) C\u00f3 m\u1ea5y h\u00ecnh t\u1ee9 gi\u00e1c ? A. 2 B. 3 C. 4 5\/ \u0110o\u1ea1n th\u1eb3ng AB d\u00e0i 36dm, \u0111o\u1ea1n th\u1eb3ng BC ng\u1eafn h\u01a1n \u0111o\u1ea1n th\u1eb3ng AB 18dm. H\u1ecfi \u0111o\u1ea1n th\u1eb3ng BC d\u00e0i bao nhi\u00eau dm? \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 36 B\u00e0i 1 : (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh \u0111\u00fang m\u1ed7i b\u00e0i ghi 0,5 \u0111i\u1ec3m B\u00e0i 2 ; (2 \u0111i\u1ec3m) Khoanh \u0111\u00fang m\u1ed7i c\u00e2u ghi 0,5 \u0111i\u1ec3m. B\u00e0i 3 : (2 \u0111i\u1ec3m) \u0110i\u1ec1n \u0111\u00fang m\u1ed7i ch\u1ed7 ch\u1ea5m ghi 0,5 \u0111i\u1ec3m. B\u00e0i 4: (1 \u0111i\u1ec3m) Khoanh \u0111\u00fang m\u1ed7i c\u00e2u ghi 0,5 \u0111i\u1ec3m. B\u00e0i 5 : (2 \u0111i\u1ec3m) - L\u1eddi gi\u1ea3i ghi 0,5 \u0111i\u1ec3m. - Ph\u00e9p t\u00ednh ghi 1 \u0111i\u1ec3m. - \u0110\u00e1p s\u1ed1 ghi 0,5 \u0111i\u1ec3m. (Sai \u0111\u01a1n v\u1ecb tr\u1eeb 0,5 \u0111i\u1ec3m cho to\u00e0n b\u00e0i.)","\u0110\u1ec0 37 C\u00e2u 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a) 45 + 32 39 + 48 c) 80 \u2013 23 d) 100 \u2013 58 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026.... \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026.... C\u00e2u 2: Vi\u1ebft v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) th\u00edch h\u1ee3p: a) 7 + 6 + 3 ................. 7 + 9 + 0 b) Th\u00e1ng 12 c\u00f3 ........ ng\u00e0y c) S\u1ed1 \u1edf gi\u1eefa 29 v\u00e0 31 l\u00e0:\u2026. d) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 50 l\u00e0 \u2026. C\u00e2u 3: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc \u00fd tr\u1ea3 l\u1eddi \u0111\u00fang: c) Ph\u00e9p t\u00ednh n\u00e0o d\u01b0\u1edbi d\u01b0\u1edbi \u0111\u00e2y c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 100? A. 55 + 35 B. 69 + 30 C. 23 + 77 d) K\u1ebft qu\u1ea3 ph\u00e9t t\u00ednh 80 l\u00edt - 20 l\u00edt - 30 l\u00edt l\u00e0: A. 50 l\u00edt B. 40 l\u00edt C. 20 l\u00edt D. 30 l\u00edt c) T\u00ecm x , bi\u1ebft : 19 + x = 40 A. 21 B. 22 C. 23 d) S\u1ed1 b\u1ecb tr\u1eeb v\u00e0 s\u1ed1 tr\u1eeb l\u1ea7n l\u01b0\u1ee3t l\u00e0 71 v\u00e0 26 th\u00ec hi\u1ec7u l\u00e0: A. 97 B. 45 C. 35 D. 44 C\u00e2u 4: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) a) 14 cm + 26 cm = 4 dm b) T\u1eeb 11 gi\u1edd \u0111\u1ebfn 12 gi\u1edd l\u00e0 60 ph\u00fat C\u00e2u 5: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: H\u00ecnh v\u1ebd b\u00ean: a) C\u00f3 \u2026. h\u00ecnh t\u1ee9 gi\u00e1c b) C\u00f3 \u2026. h\u00ecnh tam gi\u00e1c C\u00e2u 6: Tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 m\u1ed9t c\u00f3 75 con, tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai \u00edt h\u01a1n tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 m\u1ed9t 17 con. H\u1ecfi tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai c\u00f3 bao nhi\u00eau con ? \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 37 C\u00e2u 1: (3.0 \u0111i\u1ec3m): \u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh \u0111\u00fang, ghi 0.75 \u0111i\u1ec3m\/ ph\u00e9p t\u00ednh. T\u00ednh \u0111\u00fang nh\u01b0ng ch\u01b0a \u0111\u1eb7t t\u00ednh, ghi 0.5 \u0111i\u1ec3m\/ h\u00e9p t\u00ednh. C\u00e2u 2: (2 \u0111i\u1ec3m): Vi\u1ebft \u0111\u00fang m\u1ed7i s\u1ed1 theo y\u00eau c\u1ea7u, ghi 0.5 \u0111i\u1ec3m. Vi\u1ebft v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026) th\u00edch h\u1ee3p: a) 7 + 6 + 3 = 7 + 9 + 0 b) Th\u00e1ng 12 c\u00f3 31 ng\u00e0y c) S\u1ed1 \u1edf gi\u1eefa 29 v\u00e0 31 l\u00e0: 30 d) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 50 l\u00e0 49 C\u00e2u 3: (2.0 \u0111i\u1ec3m): Khoanh v\u00e0o \u00fd \u0111\u00fang m\u1ed7i c\u00e2u, ghi 0.5 \u0111i\u1ec3m). a) C b) D c) A d) B C\u00e2u 4: (1.0 \u0111i\u1ec3m): \u0110i\u1ec1n \u0110 ho\u1eb7c S v\u00e0o ch\u1ed7 ch\u1ea5m th\u00edch h\u1ee3p \u1edf m\u1ed7i \u00fd, ghi 0.5 \u0111i\u1ec3m. a) \u0110 b) \u0110 C\u00e2u 5: (0.5 \u0111i\u1ec3m) Vi\u1ebft \u0111\u00fang m\u1ed7i s\u1ed1 theo y\u00eau c\u1ea7u , ghi 0.25 \u0111i\u1ec3m. c) 1 h\u00ecnh t\u1ee9 gi\u00e1c d) 4 h\u00ecnh tam gi\u00e1c C\u00e2u 6: (1.5 \u0111i\u1ec3m): C\u0103n c\u1ee9 v\u00e0o l\u1eddi gi\u1ea3i, ph\u00e9p t\u00ednh v\u00e0 c\u00e1ch ghi \u0111\u00e1p s\u1ed1 m\u00e0 ghi t\u1eeb 0 \u0111\u1ebfn 1.5 \u0111i\u1ec3m. Tr\u1ea1i nu\u00f4i g\u00e0 s\u1ed1 hai c\u00f3 l\u00e0: 75 \u2013 17 = 58 (con) \u0110\u00e1p s\u1ed1: 58 con","\u0110\u1ec0 38 B\u00e0i 1: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: (1 \u0111i\u1ec3m) a. 87; 88; 89; \u2026\u2026\u2026.; \u2026\u2026\u2026.; \u2026\u2026\u2026..; \u2026\u2026\u2026\u2026; 94; 95 b. 82; 84; 86;\u2026\u2026\u2026..;\u2026\u2026\u2026..;\u2026\u2026\u2026\u2026;\u2026\u2026\u2026\u2026;96; 98 B\u00e0i 2: Vi\u1ebft s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: (1\u0111i\u1ec3m) \u0110\u1ecdc s\u1ed1 Vi\u1ebft s\u1ed1 Ch\u00edn m\u01b0\u01a1i s\u00e1u. \u2026\u2026\u2026\u2026................................. ..................................................... 84 B\u00e0i 3: T\u00ednh nh\u1ea9m: (1\u0111i\u1ec3m) a. 9 + 8 = \u2026.. c. 2 + 9 =\u2026\u2026 d. 17 \u2013 8 =\u2026\u2026 b. 14 \u2013 6 = \u2026. B\u00e0i 4: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: (1\u0111i\u1ec3m) d. 90 - 58 \u2026\u2026\u2026\u2026 a. 8 + 9 =16 \u2026\u2026\u2026\u2026. b. 5 + 7 = 12 \u2026\u2026\u2026\u2026. B\u00e0i 5: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2 \u0111i\u1ec3m) a. 57 + 26 b. 39 + 6 c. 81 \u2013 35 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026.. \u2026\u2026\u2026.. \u2026\u2026\u2026... \u2026\u2026\u2026. \u2026\u2026\u2026.. \u2026\u2026\u2026... \u2026\u2026\u2026. \u2026\u2026\u2026.. B\u00e0i 6: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: (1\u0111i\u1ec3m) a. 8 dm + 10 dm = \u2026\u2026.. dm A. 18 dm B. 28 dm C. 38 dm b. T\u00ecm x bi\u1ebft: X + 10=10 A. x = 10 B. x = 0 C. x = 20 B\u00e0i 7: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: ( 1 \u0111i\u1ec3m)","a) Trong h\u00ecnh c\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef b)Trong h\u00ecnh c\u00f3 bao nhi\u00eau h\u00ecnh tam nh\u1eadt gi\u00e1c A.1 A. 2 B.2 B. 3 C.3 C. 4 B\u00e0i 8: (2 \u0111i\u1ec3m ) a. Nh\u00e0 b\u1ea1n Mai nu\u00f4i 44 con g\u00e0. Nh\u00e0 b\u1ea1n H\u00e0 nu\u00f4i \u00edt h\u01a1n nh\u00e0 b\u1ea1n Mai 13 con g\u00e0. H\u1ecfi nh\u00e0 b\u1ea1n H\u00e0 nu\u00f4i bao nhi\u00eau con g\u00e0? (1\u0111i\u1ec3m) \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026 b.Em h\u00e1i \u0111\u01b0\u1ee3c 20 b\u00f4ng hoa ,ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n em 5 b\u00f4ng hoa .H\u1ecfi ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c m\u1ea5y b\u00f4ng hoa ? (1\u0111i\u1ec3m) \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 38 1)a) \u2026;\u2026;\u2026;90;91;92;93;\u2026.;\u2026.; b)\u2026;\u2026;\u2026;88;90;92;94;\u2026;\u2026. 2) a) Ch\u00edn m\u01b0\u01a1i s\u00e1u : 96 T\u00e1m m\u01b0\u01a1i t\u01b0: 84","3) .a) 9+8=17 c) 2 + 9 = 11 b)14 \u2013 6 = 8 d) 17 \u2013 8 = 9 4) .a) 8+9 = 16. S b) 5+7=12.\u0110 5) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 a) 57 \uf02b 26 \uf03d 83 b)39 \uf02b 6 \uf03d 45 c)81\uf02d 35 \uf03d 46 d)90 \uf02d 58 \uf03d 32 6) a)A b)A 7) a)A b)B 8) a) S\u1ed1 con g\u00e0 nh\u00e0 b\u1ea1n H\u00e0 nu\u00f4i l\u00e0 : 44 \u2013 13 = 31 (con) \u0110\u00e1p s\u1ed1: 31 con b) S\u1ed1 b\u00f4ng hoa ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c l\u00e0: 20 + 5 = 25 (b\u00f4ng hoa) \u0110\u00e1p s\u1ed1: 25 b\u00f4ng hoa","B\u00e0i 1) (2\u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: \u0110\u1ec0 39 54 + 36 27 + 63 54 - 38 88 - 49 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 2) (2\u0111) T\u00ecm X b) 92 - x = 45 a) x - 36 = 52 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 3) (2\u0111) Trong m\u1ed9t ng\u00e0y, c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 56 kg \u0111\u01b0\u1eddng, trong \u0111\u00f3 bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 27kg. H\u1ecfi bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau kg \u0111\u01b0\u1eddng? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 4) (2\u0111) Khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang a\/ 28 + 36 + 14=? b\/ 76 - 22 - 38 = ? A. 68 A. 26 B. 78 B. 15 C. 79 C. 16 B\u00e0i 5 (1\u0111) H\u00ecnh b\u00ean c\u00f3: \u2026\u2026..tam gi\u00e1c \u2026\u2026..t\u1ee9 gi\u00e1c B\u00e0i 6 (1\u0111) Vi\u1ebft ph\u00e9p t\u00ednh c\u00f3 hi\u1ec7u b\u1eb1ng s\u1ed1 b\u1ecb tr\u1eeb -=","\u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 39 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5d 54 \uf02b 36 \uf03d 90 54 \uf02d 38 \uf03d 16 27 \uf02b 63 \uf03d 90 88 \uf02d 49 \uf03d 39 2)a)x \uf02d 36 \uf03d 52 92 \uf02d x \uf03d 45 x \uf03d 52 \uf02b 36 x \uf03d 92 \uf02d 45 x \uf03d 88 x \uf03d 47 3)S\u1ed1 kilogam \u0111\u01b0\u1eddng bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c l\u00e0: 56 \u2013 27 = 29 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1 : 29 kg \u0111\u01b0\u1eddng B\u00e0i 4) a)B b) C B\u00e0i 5. C\u00f3 6 tam gi\u00e1c, c\u00f3 4 t\u1ee9 gi\u00e1c B\u00e0i 6. 20 \u2013 10 = 10 \u0110\u1ec0 40 M\u00f4n To\u00e1n l\u1edbp 2( Th\u1eddi gian l\u00e0m b\u00e0i 40 ph\u00fat) B\u00e0i 1: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang a\/ 85 \u2013 39 = ? A. 45 B. 46 C. 55 D. 56 C. 19 D. 9 b\/ 29 \u2013 5 + 15 = ? A. 49 B. 39 B\u00e0i 2: Vi\u1ebft c\u00e1c s\u1ed1 v\u00e0o \u00f4 tr\u1ed1ng Vi\u1ebft \u0110\u1ecdc 92 \u2013 75 T\u00e1m m\u01b0\u01a1i l\u0103m b\/ x + 14 = 40 Ch\u00edn m\u01b0\u01a1i ch\u00edn B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 43 + 57 B\u00e0i 4: T\u00ecm x a\/ x \u2013 22 = 38 B\u00e0i 5: M\u1ed9t c\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 45 kg \u0111\u01b0\u1eddng, bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c \u00edt h\u01a1n bu\u1ed5i s\u00e1ng 24 kg \u0111\u01b0\u1eddng. H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng \u0111\u00f3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ki l\u00f4 gam \u0111\u01b0\u1eddng? ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. B\u00e0i 6: H\u00ecnh v\u1ebd b\u00ean c\u00f3 m\u1ea5y h\u00ecnh tam gi\u00e1c? H\u00ecnh v\u1ebd tr\u00ean c\u00f3\u2026\u2026\u2026\u2026. h\u00ecnh tam gi\u00e1c.","\u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 40 1. .a)B b)B 2) T\u00e1m m\u01b0\u01a1i l\u0103m: 85 Ch\u00edn m\u01b0\u01a1i ch\u00edn: 99 3) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 43+57=100 92 \u2013 75 = 17 4)a)x \uf02d 22 \uf03d 38 b)x \uf02b14 \uf03d 40 x \uf03d 38 \uf02b 22 x \uf03d 40 \uf02d14 x \uf03d 60 x \uf03d 26 5) S\u1ed1 kilogam \u0111\u01b0\u1eddng bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c l\u00e0: 45 \u2013 24 = 21 (kg \u0111\u01b0\u1eddng) \u0110\u00e1p s\u1ed1: 21 kg \u0111\u01b0\u1eddng 6)H\u00ecnh v\u1ebd b\u00ean c\u00f3 8 tam gi\u00e1c \u0110\u1ec0 41 B\u00e0i 1: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng S\u1ed1 h\u1ea1ng 38 15 25 S\u1ed1 h\u1ea1ng 27 25 32 T\u1ed5ng 60 82 S\u1ed1 b\u1ecb tr\u1eeb 11 64 90 S\u1ed1 tr\u1eeb 4 34 38 Hi\u1ec7u 15 34 B\u00e0i 2: T\u00ednh : b) 36 + 24 - 18 a) 72 \u2013 36 + 24 = B\u00e0i 3: Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang S\u1ed1 h\u00ecnh t\u1ee9 gi\u00e1c trong h\u00ecnh v\u1ebd l\u00e0: A. 1 B. 2 C. 3 D. 4 B\u00e0i 4: B\u00ecnh c\u00e2n n\u1eb7ng 28 kg, An nh\u1eb9 h\u01a1n B\u00ecnh 4 kg . H\u1ecfi An n\u1eb7ng bao nhi\u00eau ki l\u00f4 gam? B\u00e0i gi\u1ea3i ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. B\u00e0i 5: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m","a) M\u1ed9t ng\u00e0y c\u00f3 \u2026\u2026\u2026. gi\u1edd b) 15 gi\u1edd hay \u2026\u2026\u2026.gi\u1edd chi\u1ec1u c) T\u1eeb 7 gi\u1edd s\u00e1ng \u0111\u1ebfn 10 gi\u1edd s\u00e1ng c\u00f9ng ng\u00e0y l\u00e0 \u2026. gi\u1edd. B\u00e0i 6: T\u00ednh nhanh 10 \u2013 9 + 8 \u2013 7 + 6 \u2013 5 + 4 \u2013 3 + 2 \u2013 1 B\u00e0i 1: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 41 S\u1ed1 h\u1ea1ng 38 15 25 50 45 25 32 S\u1ed1 h\u1ea1ng 27 60 50 82 T\u1ed5ng 65 S\u1ed1 b\u1ecb tr\u1eeb 11 49 64 90 S\u1ed1 tr\u1eeb 4 34 30 52 Hi\u1ec7u 7 15 34 38 B\u00e0i 2. T\u00ednh a) 72 \u2013 36 + 24=36+24=60 b) 36+24 \u2013 18 = 60 \u2013 18 = 42 B\u00e0i 3. D B\u00e0i 4. S\u1ed1 kilogam An c\u00e2n n\u1eb7ng l\u00e0: 28 \u2013 4 = 24 (kg) \u0110\u00e1p s\u1ed1: 24 kg. 5) a) M\u1ed9t ng\u00e0y c\u00f3 24 gi\u1edd b) 15 gi\u1edd hay 3 gi\u1edd chi\u1ec1u c) T\u1eeb 7 gi\u1edd s\u00e1ng \u0111\u1ebfn 10 gi\u1edd s\u00e1ng l\u00e0 3 gi\u1edd 6) 10 \u2013 9 + 8 \u2013 7 +6 \u2013 5 +4 \u2013 3 +2 \u2013 1 =1+1+1+1+1=5 \u0110\u1ec0 42 I . tr\u1eafc nghi\u1ec7m kh\u00e1ch quan: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: B\u00e0i 1. S\u1ed1 li\u1ec1n tr\u01b0\u1edbc 50 l\u00e0 A. 49 B. 51 C. 48 C. 90 B\u00e0i 2. S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 l\u00e0 : A. 88 B. 99 B\u00e0i 3. H\u00ecnh v\u1ebd b\u00ean c\u00f3 m\u1ea5y h\u00ecnh tam gi\u00e1c? A. 3 B. 4 C. 5","B\u00e0i 4. C\u00e2u n\u00e0o \u0111\u00fang? B. M\u1ed9t ng\u00e0y c\u00f3 12 gi\u1edd C. M\u1ed9t ng\u00e0y c\u00f3 20 gi\u1edd A.M\u1ed9t ng\u00e0y c\u00f3 24 gi\u1edd B\u00e0i 5. T\u00ednh t\u1ed5ng , bi\u1ebft c\u00e1c s\u1ed1 h\u1ea1ng l\u00e0 48 v\u00e0 17. C. 45 A.56 B. 65 B\u00e0i 6 .T\u00ecm x : x + 16 = 30 A.15 B. 16 C. 14 B\u00e0i 7 . T\u00ednh k\u1ebft qu\u1ea3 86 - 6 - 9 = ? A.71 B. 70 C. 81 B\u00e0i 8 . M\u1eb9 h\u00e1i \u0111\u01b0\u1ee3c 55 qu\u1ea3 cam , m\u1eb9 bi\u1ebfu b\u00e0 20 qu\u1ea3 cam . H\u1ecfi m\u1eb9 c\u00f2n l\u1ea1i bao nhi\u00eau qu\u1ea3 cam? A .30 qu\u1ea3 B. 35 qu\u1ea3 C.25 qu\u1ea3 II. T\u1ef1 lu\u1eadn : 80 - 43 45 + 39 B\u00e0i 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : 46 + 49 83 - 35 B\u00e0i 2. + 9kg - 18kg 26kg - 26 + 15 38 B\u00e0i 3. T\u00ednh 34 + 66 - 20 = 85 - 15 + 12 = == B\u00e0i 4 . M\u1ed9t c\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 83 l d\u1ea7u , bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c \u00edt h\u01a1n bu\u1ed5i s\u00e1ng 27l d\u1ea7u . H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng \u0111\u00f3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l d\u1ea7u? B\u00e0i gi\u1ea3i ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. .............................................................................................................................................................","............................................................................................................................................................. B\u00e0i 5 . \u0110i\u1ec1n s\u1ed1 c\u00f2n thi\u1ebfu v\u00e0o \u00f4 tr\u1ed1ng 4... .... \uf02d\uf02d 17 37 23 49 \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 42 I.Tr\u1eafc nghi\u1ec7m kh\u00e1ch quan 1.A 2.B 3.C 4.A 5.B 6.C 7.A 8.B II.T\u1ef0 LU\u1eacN 1)\u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 46+49=95 83 \u2013 35 = 48 80 \u2013 43 = 37 45 + 39 = 84 2)26 kg \uf02b 9 kg \uf03d 35kg \uf02d18 kg \uf03d 17 kg 64 \uf02d 26 \uf03d 38 \uf02b15 \uf03d 53 3)T\u00ednh 34 \uf02b 66 \uf02d 20 \uf03d 100 \uf02d 20 \uf03d 80 85 \uf02d15 \uf02b12 \uf03d 70 \uf02b12 \uf03d 82 4) S\u1ed1 l\u00edt d\u1ea7u bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c l\u00e0 : 83 \u2013 27 = 56 (l\u00edt d\u1ea7u) \u0110\u00e1p s\u1ed1: 56 l\u00edt d\u1ea7u 5) 40 \u2013 17 = 23 86 \u2013 37 = 49 \u0110\u1ec0 43 B\u00e0i 1:(2 \u0111i\u1ec3m) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1ee9ng tr\u01b0\u1edbc ph\u01b0\u01a1ng \u00e1n \u0111\u00fang. a\/ K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p c\u1ed9ng 76 + 16 l\u00e0 : A. 82 B. 72 C. 93 D. 92 C. 15 D. 16 b\/ Ph\u00e9p tr\u1eeb 100 - 75 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0: A. 35. B. 25 c\/ Hi\u1ec7u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y l\u1edbn h\u01a1n 56? A. 59 - 8 B. 69 - 10 C. 56 - 0 D. 58 - 3 d\/ S\u1ed1 h\u00ecnh tam gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 2 B. 3 C. 4 D. 5 B\u00e0i 2:(1 \u0111i\u1ec3m) \u0110i\u1ec1n s\u1ed1 ho\u1eb7c d\u1ea5u (>, <, =) th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m. a\/ 42 + 15 ...........75 b\/ 100 - 42 ......... 43 c\/ 10 gi\u1edd \u0111\u00eam c\u00f2n g\u1ecdi l\u00e0 ..... gi\u1edd. d\/ Ng\u00e0y 1 th\u00e1ng 1 n\u0103m 2011 l\u00e0 ng\u00e0y th\u1ee9 s\u00e1u. Th\u1ee9 s\u00e1u tu\u1ea7n sau \u0111\u00f3 l\u00e0 ng\u00e0y ..... th\u00e1ng ..... B\u00e0i 3: (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh: a\/ 36 + 38 b\/ 75 - 27 c\/ 100 - 37 d\/ 29 + 57 ........................................................................................................................................... ...........................................................................................................................................","........................................................................................................................................... .............................. B\u00e0i 4: (1 \u0111i\u1ec3m) T\u00ednh: a\/ 48 + 35 - 38 b\/ 100 - 28 + 15 ........................................................................................................................................... .......... B\u00e0i 5:(1 \u0111i\u1ec3m) T\u00ecm x, bi\u1ebft: a\/ x + 37 = 80 b\/ 42 - x = 22 ........................................................................................................................................... ........................................................................................................................................... .................... B\u00e0i 6: (2 \u0111i\u1ec3m) B\u00e0i gi\u1ea3i. Th\u00f9ng g\u1ea1o n\u1ebfp c\u00f3 53 kg, Th\u00f9ng g\u1ea1o t\u1ebb c\u00f3 \u00edt h\u01a1n th\u00f9ng g\u1ea1o n\u1ebfp 8 kg. H\u1ecfi th\u00f9ng g\u1ea1o t\u1ebb c\u00f3 bao nhi\u00eau ki - l\u00f4 - gam? B\u00e0i gi\u1ea3i ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. B\u00e0i 7. (1 \u0111i\u1ec3m) T\u00ednh nhanh: 24 + 65 - 4 - 5 ........................................................................................................................................... ........................................................................................................................................... ........................................................................................................................................... ........................................................................................................................................... ........................................ \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 43 1)a) D b)B c)B d)C 2) a) 42 \uf02b15 \uf03c 75 b)100 \uf02d 42 \uf03e 43 c) 10 gi\u1edd \u0111\u00eam c\u00f2n g\u1ecdi l\u00e0 22 gi\u1edd","d) Ng\u00e0y 1 th\u00e1ng 1 n\u0103m 2011 l\u00e0 ng\u00e0y th\u1ee9 s\u00e1u. Th\u1ee9 s\u00e1u tu\u1ea7n sau \u0111\u00f3 l\u00e0 ng\u00e0y 8 th\u00e1ng 1. 3) \u0110\u1eb7t t\u00ednh \u0111\u00fang m\u1ed7i c\u00e2u \u0111\u01b0\u1ee3c 0,5\u0111 a) 36+38=74 b)75 \u2013 27 = 48 c) 100 \u2013 37 = 63 d) 29 + 57 = 86 4) a) 48 \uf02b 35 \uf02d 38 \uf03d 83 \uf02d 38 \uf03d 45 b)100 \uf02d 28 \uf02b15 \uf03d 72 \uf02b15 \uf03d 87 5)a) x\uf02b 37 \uf03d 80 b) 42 \uf02d x \uf03d 22 x \uf03d 80 \uf02d 37 x \uf03d 42 \uf02d 22 x \uf03d 43 x \uf03d 20 B\u00e0i 6. S\u1ed1 kilogam th\u00f9ng g\u1ea1o t\u1ebb c\u00f3 l\u00e0 : 53 \u2013 8 = 45 (kg g\u1ea1o) \u0110\u00e1p s\u1ed1: 45 kg g\u1ea1o B\u00e0i 7. 24 \uf02b 65 \uf02d 4 \uf02d 5 \uf03d \uf02824 \uf02d 4\uf029 \uf02b \uf02865 \uf02d 5\uf029 \uf03d 20 \uf02b 60 \uf03d 80 \u0110\u1ec0 44 PH\u1ea6N TR\u1eaeC NGHI\u1ec6M 3 \u0111i\u1ec3m Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang C\u00e2u 1. S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 80 l\u00e0: A. 79 B. 80 C. 81 D. 82 C\u00e2u 2. S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m 60 cm = \u2026. dm l\u00e0: A. 6 dm B. 6 C. 60 D. 6 cm C\u00e2u 3. C\u00e1c s\u1ed1 28; 37; 46; 52 \u0111\u01b0\u1ee3c vi\u1ebft theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9 l\u00e0: A. 46; 37; 52; 28 B. 28; 37; 46; 52 C. 52; 46; 37; 28 D. 52; 37; 46; 28 C\u00e2u 4. S\u1ed1 l\u1edbn h\u01a1n 74 v\u00e0 nh\u1ecf h\u01a1n 76 l\u00e0: A. 73 B. 77 C. 75 D. 76 C\u00e2u 5. Hi\u1ec7u c\u1ee7a 64 v\u00e0 31 l\u00e0: A. 33 B. 77 C. 95 D. 34 C\u00e2u 6. Lan v\u00e0 H\u1ed3ng c\u00f3 22 quy\u1ec3n truy\u1ec7n tranh. N\u1ebfu l\u1ea5y b\u1edbt c\u1ee7a H\u1ed3ng 5 quy\u1ec3n th\u00ec hai b\u1ea1n c\u00f2n l\u1ea1i bao nhi\u00eau quy\u1ec3n truy\u1ec7n tranh? Hai b\u1ea1n c\u00f2n l\u1ea1i s\u1ed1 quy\u1ec3n truy\u1ec7n tranh l\u00e0: A. 27 B. 17 C. 22 D. 15 PH\u1ea6N T\u1ef0 LU\u1eacN 7 \u0111i\u1ec3m B\u00e0i 1. (2 \u0111i\u1ec3m) T\u00ecm x, bi\u1ebft: x + 15 = 41 x \u2013 23 = 39","B\u00e0i 2. (2 \u0111i\u1ec3m) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 44 + 37 95 \u2013 58 38 + 56 66 \u2013 8 B\u00e0i 3. (1,5 \u0111i\u1ec3m) H\u00ecnh v\u1ebd b\u00ean c\u00f3 bao nhi\u00eau t\u1ee9 gi\u00e1c? B\u00e0i 4. (1,5 \u0111i\u1ec3m). C\u00f3 hai th\u00f9ng d\u1ea7u. Th\u00f9ng th\u1ee9 nh\u1ea5t ch\u1ee9a nhi\u1ec1u h\u01a1n th\u00f9ng th\u1ee9 hai 8 l\u00edt d\u1ea7u, th\u00f9ng th\u1ee9 nh\u1ea5t ch\u1ee9a 33 l\u00edt d\u1ea7u. H\u1ecfi th\u00f9ng th\u1ee9 hai ch\u1ee9a bao nhi\u00eau l\u00edt d\u1ea7u? ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 44 I.PH\u1ea6N TR\u1eaeC NGHI\u1ec6M 1.A 2.A 3.C 4.C 5.A 6.B II.PH\u1ea6N T\u1ef0 LU\u1eacN 1) x \uf02b15 \uf03d 41 x \uf02d 23 \uf03d 39 x \uf03d 41\uf02d15 x \uf03d 39 \uf02b 23 x \uf03d 26 x \uf03d 62 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5\u0111 44 \uf02b 37 \uf03d 81 95\uf02d 58 \uf03d 37 38 \uf02b 56 \uf03d 94 66 \uf02d8 \uf03d 58 3) H\u00ecnh v\u1ebd c\u00f3 4 t\u1ee9 gi\u00e1c 4) S\u1ed1 l\u00edt d\u1ea7u th\u00f9ng hai ch\u1ee9a l\u00e0 : 33 + 8 = 41 ( l d\u1ea7u) \u0110\u00e1p s\u1ed1: 41 l d\u1ea7u.","\u0110\u1ec0 45 A- Ph\u1ea7n ki\u1ec3m tra tr\u1eafc nghi\u1ec7m. Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u0111\u00e1p \u00e1n \u0111\u00fang. (M\u1ed7i \u0111\u00e1p \u00e1n \u0111\u00fang cho 0,5 \u0111i\u1ec3m) 1) 5dm = ? cm A. 50 cm B. 5 cm C. 4 cm 2) S\u1ed1 b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1 : 100, 98, 89, 90 l\u00e0 A. 89 B. 90 C. 98 3) 47 + 35 = ? A. 72 B. 92 C. 82 4) S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 m\u00e0 t\u1ed5ng 2 ch\u1eef s\u1ed1 c\u1ee7a s\u1ed1 \u0111\u00f3 b\u1eb1ng 9 l\u00e0: A. 99 B. 90 C. 81 5) 11 \u2013 7 + 8 = ? A. 4 B. 12 C. 10 6) Con l\u1ee3n tr\u1eafng n\u1eb7ng 75 kg, con l\u1ee3n \u0111en nh\u1eb9 h\u01a1n con l\u1ee3n tr\u1eafng 18 kg. H\u1ecfi con l\u1ee3n \u0111en c\u00e2n n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam ? B. 57 C. 67 Con l\u1ee3n \u0111en c\u00e2n n\u1eb7ng : A. 93 7) S\u1ed1 ? 5 +7 -6 8) H\u00ecnh b\u00ean c\u00f3 m\u00e1y h\u00ecnh t\u1ee9 gi\u00e1c: A. 2 B. 3 C. 4 9) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: 5 > 58 A. 9 B. 8 C. 7 B. 51 C. 50 10 ) S\u1ed1 li\u1ec1n sau c\u1ee7a 49 l\u00e0: A. 48 B- Ph\u1ea7n ki\u1ec3m tra t\u1ef1 lu\u1eadn. B\u00e0i 1 (2 \u0111i\u1ec3m) : \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 38 + 62 ; 72 - 25 ; 64 + 27 ; 100 - 77 ; B\u00e0i 2: (1 \u0111i\u1ec3m) T\u00ecm x a. x + 28 = 41 b. 32 - x = 16 + 7","B\u00e0i 3: (2 \u0111i\u1ec3m) N\u0103m nay Lan 8 tu\u1ed5i, m\u1eb9 h\u01a1n Lan 27 tu\u1ed5i. H\u1ecfi n\u0103m nay m\u1eb9 bao nhi\u00eau tu\u1ed5i ? ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. ............................................................................................................................................................. \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 45 A.TR\u1eaeC NGHI\u1ec6M 1.A 2.A 3.C 4.B 5.B 6.B 7. 5 \uf02b 7 \uf03d 12 \uf02d 6 \uf03d 6 8.B 9.A 10.C 100 \uf02d 77 \uf03d 23 B.T\u1ef0 LU\u1eacN 1)M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5 \u0111 38 \uf02b 62 \uf03d 100 72 \uf02d 25 \uf03d 47 64 \uf02b 27 \uf03d 91 2)T\u00ecm x a) x \uf02b 28 \uf03d 41 b)32 \uf02d x \uf03d 16 \uf02b 7 x \uf03d 41\uf02d 28 32 \uf02d x \uf03d 23 x \uf03d 13 x \uf03d 32 \uf02d 23 x\uf03d9 3) S\u1ed1 tu\u1ed5i c\u1ee7a m\u1eb9 Lan n\u0103m nay l\u00e0: 8+27=35 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 35 tu\u1ed5i \u0110\u1ec0 46 B\u00e0i 1: S\u1ed1 ? 80 .\u2026. 82 \u2026.. 84 85 \u2026. \u2026. \u2026. 89 90 B\u00e0i 2: Vi\u1ebft s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p \u0111\u1ecdc s\u1ed1 Vi\u1ebft s\u1ed1 S\u00e1u m\u01b0\u01a1i l\u0103m \u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. 46 T\u00e1m m\u01b0\u01a1i t\u01b0 71 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. S\u1ed1","B\u00e0i 3: ? +7 a) 6 b) 7 +7 +5 c) 15 -\u2026.... 6 d) B\u00e0i 4: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng : 16 - 7 a) 8 + 4 = 13 b) 7 + 9 = 16 B\u00e0i 5: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : 47 + 25 64 - 28 100 -36 37 + 43 \u2026\u2026\u2026 \u2026\u2026\u2026. \u2026\u2026\u2026. \u2026\u2026\u2026.. \u2026\u2026.... \u2026\u2026\u2026. \u2026\u2026\u2026. \u2026\u2026\u2026.. \u2026\u2026\u2026 \u2026\u2026\u2026. \u2026\u2026\u2026. \u2026\u2026\u2026.. B\u00e0i 6: T\u00ecm x x +30 = 50 x \u2013 12 = 47 x =\u2026\u2026\u2026\u2026\u2026 x = \u2026\u2026\u2026\u2026\u2026\u2026. x =\u2026\u2026\u2026\u2026\u2026 x = \u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 7: Gi\u1ea3i to\u00e1n Quang c\u00e2n n\u1eb7ng 26 kg. Minh c\u00e2n n\u1eb7ng h\u01a1n Quang 8 kg. H\u1ecfi Minh c\u00e2n n\u1eb7ng bao nhi\u00eau kg ? B\u00e0i gi\u1ea3i: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. B\u00e0i 8: Khoanh v\u00e0o \u0111\u00e1p \u00e1n tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang a) S\u1ed1 t\u1ee9 gi\u00e1c trong h\u00ecnh v\u1ebd l\u00e0 : A. 1 C. 3 B. 2 D. 4 b) S\u1ed1 h\u00ecnh tam gi\u00e1c trong h\u00ecnh v\u1ebd l\u00e0: A. 4 C. 2 B. 3 D. 1 B\u00e0i 9 : Vi\u1ebft ti\u1ebfp v\u00e0o t\u1edd l\u1ecbch th\u00e1ng 12 d\u01b0\u1edbi \u0111\u00e2y r\u1ed3i tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi : Th\u1ee9 hai Th\u1ee9 ba Th\u1ee9 t\u01b0 Th\u1ee9 n\u0103m Th\u1ee9 s\u00e1u Th\u1ee9 b\u1ea3y Ch\u1ee7 nh\u1eadt 12 5 11 13 12 15 16 19 25 28 29 31","Trong th\u00e1ng 12 : a) C\u00f3 \u2026\u2026\u2026.ng\u00e0y th\u1ee9 hai. C\u00e1c ng\u00e0y th\u1ee9 hai \u0111\u00f3 l\u00e0 :\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) Ng\u00e0y 22 th\u00e1ng 12 l\u00e0 th\u1ee9 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. c) Th\u00e1ng 12 c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau ng\u00e0y :\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 d) Em \u0111\u01b0\u1ee3c ngh\u1ec9 th\u1ee9 b\u1ea3y v\u00e0 ch\u1ee7 nh\u1eadt.V\u1eady th\u00e1ng 12 em \u0111\u01b0\u1ee3c ngh\u1ec9 \u2026\u2026\u2026\u2026ng\u00e0y \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 46 1) \u2026.;81;\u2026;83;\u2026.;\u2026..;86;87;88;\u2026;\u2026.. 2) S\u00e1u m\u01b0\u01a1i l\u0103m: 65 B\u1ed1n m\u01b0\u01a1i s\u00e1u: 46 B\u1ea3y m\u01b0\u01a1i m\u1ed1t: 71 T\u00e1m m\u01b0\u01a1i t\u01b0: 84 3) a)6 \uf02b 7 \uf03d 13 b)7 \uf02b 7 \uf03d 14; 7 \uf02b 5 \uf03d 12 d)16 \uf02d 7 \uf03d 9 c)15\uf02d 9 \uf03d 6 4)a)8 \uf02b 4 \uf03d 13. S b)7 \uf02b 9 \uf03d 16. \u00a7 5) \u00a7\u00c6t t\u00ddnh \u00ae\u00f3ng m\u00e7i c\u00a9u \u00ae\u00ad\u00eec t\u00ddnh \u00aei\u00d3m t\u00e8i \u00aea 47+25=72 64 - 28 = 36 100-36=64 37+43=80 6) x+30=50 x=50 - 30 x=20 x-12=47 x=47+12=59 7)S\u00e8 kilogam Minh c\u00a9n n\u00c6ng l\u00b5: 26+8=34 (kg) \u00a7\u00b8p s\u00e8 :34 kg 8) a) C b)B 9) H\u00e4c sinh t\u00f9 vi\u00d5t ng\u00b5y Trong th\u00b8ng12 a) C\u00e3 5ng\u00b5y th\u00f8 hai,\u00ae\u00e3 l\u00b5 c\u00b8c ng\u00b5y :1;8;15;22;29 b)Ng\u00b5y 22 th\u00b8ng12 l\u00b5 th\u00f8 Hai c)Th\u00b8ng12 c\u00e3 31ng\u00b5y d) Th\u00b8ng12 em \u00ae\u00ad\u00eec ngh\u00d8 8 ng\u00b5y","\u0110\u1ec0 47 B\u00e0i 1: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m : 50 51 95 58 62 68 83 77 B\u00e0i 2: N\u1ed1i ph\u00e9p t\u00ednh v\u1edbi k\u1ebft qu\u1ea3 \u0111\u00fang: 99 9+7 9 16 - 7 16 9+6 8 17 - 9 15 B\u00e0i 3: \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng a) 7 + 8 = 15 c) 12 - 4 = 9 d) 11 - 4 = 7 b) 8 + 4 = 13 B\u00e0i 4: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 45 + 27 64 \u2013 38 33 + 47 80 - 36 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026. B\u00e0i 5: S\u1ed1? a) 16 + 5 - 10 = b) 24kg - 13kg + 4kg = kg","B\u00e0i 6: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: H\u00ecnh v\u1ebd b\u00ean c\u00f3: a) C\u00f3 \u2026\u2026\u2026\u2026h\u00ecnh tam gi\u00e1c. b) C\u00f3 \u2026\u2026\u2026\u2026h\u00ecnh t\u1ee9 gi\u00e1c. B\u00e0i 7: Gi\u1ea3i to\u00e1n: a) Anh Ho\u00e0 c\u00e2n n\u1eb7ng 45 kg, b\u1ea1n B\u00ecnh c\u00e2n nh\u1eb9 h\u01a1n anh Ho\u00e0 17 kg. H\u1ecfi b\u1ea1n B\u00ecnh c\u00e2n n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam? B\u00e0i gi\u1ea3i ........................................................................................................................ \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) B\u00ecnh nh\u1ecf \u0111\u1ef1ng 15 n\u01b0\u1edbc, b\u00ecnh to \u0111\u1ef1ng \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n b\u00ecnh nh\u1ecf 9 n\u01b0\u1edbc. H\u1ecfi b\u00ecnh to \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt n\u01b0\u1edbc? B\u00e0i gi\u1ea3i .......................................................................................................................... \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 8: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: += -=","\u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 47 1) H\u1ecdc sinh t\u1ef1 \u0111i\u1ec1n s\u1ed1 theo h\u01b0\u1edbng t\u0103ng d\u1ea7n 2) 9 + 7 = 16 16 \u2013 7 = 9 9 + 6 = 15 17 \u2013 9 = 8 3) .a) 7 + 8 = 15 .\u0110 c)12 \u2013 4 = 9. S b)8+4 = 13. S d) 11 \u2013 4 = 7 . \u0110 4) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c \u0111i\u1ec3m t\u1ed1i \u0111a 45+27=72 64 \u2013 38 = 26 35 + 47 = 82 80 \u2013 36 = 44 5) a) 16 l +5 l \u2013 10 l = 11 l b) 24 kg \u2013 13 kg + 4 kg = 15 kg 6) a) C\u00f3 4 h\u00ecnh tam gi\u00e1c, b) C\u00f3 2 h\u00ecnh t\u1ee9 gi\u00e1c. 7) a) S\u1ed1 kilogam c\u00e2n n\u1eb7ng c\u1ee7a b\u1ea1n B\u00ecnh l\u00e0: 45 \u2013 17 = 28 (kg) \u0110\u00e1p s\u1ed1: 28 kg b) S\u1ed1 l\u00edt n\u01b0\u1edbc b\u00ecnh to \u0111\u1ef1ng l\u00e0 : 15+9 = 24 (l n\u01b0\u1edbc) \u0110\u00e1p s\u1ed1 : 24 l n\u01b0\u1edbc 8) 10 \u2013 2 = 8 9\u20133=6 \u0110\u1ec0 48 1\/ Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng:: (2 \u0111i\u1ec3m) a\/ 62, 63, 64, \u2026..; \u2026..; ..\u2026; \u2026..; \u2026.., 70. b\/ 40, 42, 44, \u2026..;\u2026..;\u2026..;\u2026..;\u2026..., 56. 2\/ \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2 \u0111i\u1ec3m) 36 + 43 88 - 65 27 + 15 80 - 46 ................................ ................................ ................................ ................................ .. .. .. .. ................................ ................................ ................................ ................................ .. .. .. .. ................................ ................................ ................................ ................................ .. .. .. .. 3\/ T\u00ecm X. Bi\u1ebft: (2 \u0111i\u1ec3m) X + 19 = 72 X \u2013 37 = 28 100 \u2013 X = 45 ............................................ ............................................ ............................................ ..... ..... ..... ............................................ ............................................ ............................................ ..... ..... ..... ............................................ ............................................ ............................................ ..... ..... .....","4\/ Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: (1 \u0111i\u1ec3m) 2dm =\u2026\u2026\u2026 cm 9dm =\u2026\u2026\u2026 cm 70cm =\u2026\u2026\u2026 dm 5\/ B\u00ecnh c\u00e2n n\u1eb7ng 32 ki-l\u00f4-gam. Lan nh\u1eb9 h\u01a1n B\u00ecnh 9 ki-l\u00f4-gam. H\u1ecfi Lan c\u00e2n n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam? (2 \u0111i\u1ec3m) B\u00e0i l\u00e0m ........................................................................................................................................... ................ ........................................................................................................................................... ................ ........................................................................................................................................... ................ ........................................................................................................................................... ................ 6\/ (1 \u0111i\u1ec3m) H\u00ecnh b\u00ean c\u00f3 ....... h\u00ecnh tam gi\u00e1c H\u00ecnh b\u00ean c\u00f3 ....... h\u00ecnh t\u1ee9 gi\u00e1c \u0110\u00c1P \u00c1N \u0110\u1ec0 S\u1ed0 48 .1) a) \u2026;\u2026;\u2026.;65;66;67;68;69;\u2026. b) \u2026;\u2026;\u2026.;46;48;50;52;54;\u2026 2) M\u1ed7i c\u00e2u \u0111\u1eb7t t\u00ednh \u0111\u00fang \u0111\u01b0\u1ee3c 0,5 \u0111 36+43 = 79 88 \u2013 65 = 23 27+15=42 80 \u2013 46 = 34 3)T\u00ecm x x \uf02b19 \uf03d 72 x \uf02d 37 \uf03d 28 100 \uf02d x \uf03d 45 x \uf03d 72 \uf02d19 x \uf03d 28 \uf02b 37 x \uf03d 100 \uf02d 45 x \uf03d 53 x \uf03d 65 x \uf03d 55 4) 2 dm = 20 cm 9 dm = 90 cm 70 cm = 7 dm 5) S\u1ed1 kilogam Lan c\u00e2n n\u1eb7ng l\u00e0 : 32 \u2013 9 = 23 (kg) \u0110\u00e1p s\u1ed1: 23 kg 6) H\u00ecnh b\u00ean c\u00f3 3 tam gi\u00e1c, h\u00ecnh b\u00ean c\u00f3 3 t\u1ee9 gi\u00e1c \u0110\u1ec0 49 B\u00e0i 1: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u01a1 tr\u1ed1ng. (1 \u0111i\u1ec3m) 60 62 65 67 68 71 72 75 B\u00e0i 2: T\u00ednh. (5 \u0111i\u1ec3m) a) T\u00ednh nh\u1ea9m: (2 \u0111i\u1ec3m), HS t\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh\u0111\u01b0\u1ee3c 0,5 \u0111i\u1ec3m.","6+7= 17 \u2013 9 = 12 \u2013 4 = 8+5= b) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (3 \u0111i\u1ec3m), HS \u0111\u1eb7t t\u00ednh v\u00e0 t\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh \u0111\u01b0\u1ee3c 0,5 \u0111i\u1ec3m. 28 + 31 15 + 22 87 \u2013 47 26 + 36 54 \u2013 19 63 + 18 B\u00e0i 3: (1 \u0111i\u1ec3m) a) Lan \u0111i ng\u1ee7 l\u00fac 20 gi\u1edd , t\u1ee9c l\u00e0 Lan \u0111i ng\u1ee7 l\u00fac\u2026\u2026\u2026 gi\u1edd \u0111\u00eam. (0,5 \u0111i\u1ec3m). b) Ng\u00e0y 09 th\u00e1ng 01 n\u0103m 2008 l\u00e0 ng\u00e0y th\u1ee9 t\u01b0 . Ng\u00e0y 11 th\u00e1ng 01 n\u0103m 2008 l\u00e0 ng\u00e0y th\u1ee9 \u2026\u2026\u2026 (0,5 \u0111i\u1ec3m) B\u00e0i 4: Nh\u1eadn d\u1ea1ng h\u00ecnh. (1 \u0111i\u1ec3m) a) Trong h\u00ecnh v\u1ebd b\u00ean c\u00f3....... h\u00ecnh tam gi\u00e1c. (0,25 \u0111i\u1ec3m) Trong h\u00ecnh v\u1ebd b\u00ean c\u00f3 ....... h\u00ecnh t\u1ee9 gi\u00e1c. (0,25 \u0111i\u1ec3m) b) V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB d\u00e0i 6cm. (0,5 \u0111i\u1ec3m) B\u00e0i 5: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u01a1 tr\u1ed1ng \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang (1 \u0111i\u1ec3m) . + 2 = 39 28 \u2013 =3 B\u00e0i 6: Gi\u1ea3i to\u00e1n (1 \u0111i\u1ec3m) a) B\u1ea1n Lan c\u00e2n n\u1eb7ng 28kg. B\u1ea1n Mai c\u00e2n n\u1eb7ng h\u01a1n b\u1ea1n Lan 3kg. H\u1ecfi b\u1ea1n Mai c\u00e2n n\u1eb7ng bao nhi\u00eau kil\u01a1gam ? \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) M\u1eb9 h\u00e1i \u0111\u01b0\u1ee3c 38 qu\u1ea3 b\u01b0\u1edfi. Ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c 16 qu\u1ea3 b\u01b0\u1edfi. H\u1ecfi m\u1eb9 h\u00e1i nhi\u1ec1u h\u01a1n ch\u1ecb bao nhi\u00eau qu\u1ea3 b\u01b0\u1edfi ?"]