460 bai toan vui luyen tri thong minh

["Li\u1ec1n tr\u01b0\u1edbc 20 \u0110\u1ed1 vui v\u1eeba h\u1ecdc v\u1eeba c\u01b0\u1eddi T\u00ednh t\u1ed5ng 2 s\u1ed1, ai ng\u01b0\u1eddi gi\u1ecfi nhanh? C\u00e2u 7. Ng\u01b0\u1eddi ta tr\u1ed3ng 42 c\u00e2y d\u1eeba \u1edf xung quanh m\u1ed9t h\u1ed3 sen h\u00ecnh tr\u00f2n. Bi\u1ebft r\u1eb1ng hai c\u00e2y li\u1ec1n nhau lu\u00f4n c\u00e1ch \u0111\u1ec1u nhau 15m. H\u00e3y t\u00ednh b\u00e1n k\u00ednh h\u1ed3 sen. C\u00e2u 8. S\u1ed1 n\u00e0o thay cho d\u1ea5u (?). 1,5 | 4,5 | 13,5 | 16,5 | ?","B\u00e0i 18 C\u00e2u 1. S\u1ed1 n\u00e0o thay cho d\u1ea5u (?). C\u00e2u 2. T\u00ecm s\u1ed1 \u0111i\u1ec1n v\u00e0o d\u1ea5u (?). 4 9 20 8 5 14 10 3 ? C\u00e2u 3. Trong hai ng\u00e0y v\u1edbi 8 ng\u01b0\u1eddi th\u00ec s\u1eeda \u0111\u01b0\u1ee3c 64m \u0111\u01b0\u1eddng. V\u1eady trong 5 ng\u00e0y v\u1edbi 9 ng\u01b0\u1eddi th\u00ec s\u1eeda \u0111\u01b0\u1ee3c bao nhi\u00eau m\u00e9t \u0111\u01b0\u1eddng? (N\u0103ng su\u1ea5t m\u1ed7i ng\u01b0\u1eddi nh\u01b0 nhau). C\u00e2u 4. C\u1ed9ng s\u1ed1 tu\u1ed5i c\u1ee7a: A + B = 43 A + C = 55","B + C = 66 H\u1ecfi tu\u1ed5i c\u1ee7a m\u1ed7i ng\u01b0\u1eddi l\u00e0 nh\u01b0 th\u1ebf n\u00e0o? C\u00e2u 5. Hai h\u00ecnh tr\u00ean gh\u00e9p l\u1ea1i s\u1ebd t\u1ea1o th\u00e0nh h\u00ecnh n\u00e0o ph\u00eda d\u01b0\u1edbi? C\u00e2u 6. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u1ea5u (?). 7 9 5 11 5 14 12 7 13 8 11 ? C\u00e2u 7. C\u00f3 bao nhi\u00eau s\u1ed1 b\u00ecnh ph\u01b0\u01a1ng tr\u00ean b\u00e0n c\u1edd 8 x 8 \u00f4 v\u00e0 t\u1ed5ng c\u1ee7a ch\u00fang b\u1eb1ng bao nhi\u00eau? C\u00e2u 8. T\u00ecm s\u1ed1 \u0111i\u1ec1n v\u00e0o d\u1ea5u (?). 96 16 12","88 ? 11 C\u00e2u 9. M\u1ed9t xe kh\u00e1ch kh\u1edfi h\u00e0nh t\u1eeb A \u0111\u1ec3 v\u1ec1 B v\u1edbi v\u1eadn t\u1ed1c 42km\/h. Sau \u0111\u00f3 10 ph\u00fat m\u1ed9t xe du l\u1ecbch c\u0169ng b\u1eaft \u0111\u1ea7u \u0111i t\u1eeb A \u0111u\u1ed5i theo v\u1edbi v\u1eadn t\u1ed1c 58km\/h. Bi\u1ebft c\u1ea3 hai xe \u0111\u1ebfn B c\u00f9ng m\u1ed9t l\u00fac, h\u00e3y t\u00ecm qu\u00e3ng \u0111\u01b0\u1eddng t\u1eeb A \u0111\u1ebfn B?","C\u00e2u 1. N\u1ebfu kh\u00f4ng c\u00f3 tr\u01b0\u1eddng h\u1ee3p n\u00e0o d\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0111\u00fang th\u00ec ch\u00fang ta c\u00f3 th\u1ec3 k\u1ebft lu\u1eadn ai l\u00e0 ng\u01b0\u1eddi l\u00e0m v\u1ee1 l\u1ecd hoa? a. Mike: Sally l\u00e0m v\u1ee1 l\u1ecd hoa. b. Tom: Mike s\u1ebd n\u00f3i cho b\u1ea1n bi\u1ebft ai l\u00e0 ng\u01b0\u1eddi l\u00e0m v\u1ee1 l\u1ecd hoa. c. April: Tom, Mike v\u00e0 t\u00f4i kh\u00f4ng th\u1ec3 l\u00e0m v\u1ee1 l\u1ecd hoa. d. Chris: T\u00f4i kh\u00f4ng l\u00e0m v\u1ee1 l\u1ecd hoa. e. Erik: Mike l\u00e0m v\u1ee1 l\u1ecd hoa, v\u00ec v\u1eady Tom v\u00e0 April kh\u00f4ng th\u1ec3 l\u00e0m v\u1ee1 \u0111\u01b0\u1ee3c. f. Jim: T\u00f4i l\u00e0m v\u1ee1 l\u1ecd hoa n\u00ean Tom kh\u00f4ng l\u00e0m v\u1ee1 l\u1ecd hoa. C\u00e2u 2. C\u00f3 hai kho th\u00f3c. Kho th\u1ee9 nh\u1ea5t ch\u1ee9a 261 t\u1ea1 30kg. Kho th\u1ee9 hai ch\u1ee9a \u00edt h\u01a1n kho th\u1ee9 nh\u1ea5t 1560kg v\u00ec c\u00f3 \u00edt h\u01a1n 24 bao. Bi\u1ebft r\u1eb1ng c\u00e1c bao n\u1eb7ng nh\u01b0 nhau. H\u1ecfi m\u1ed7i kho c\u00f3 bao nhi\u00eau bao th\u00f3c? C\u00e2u 3. Nghe v\u1ebb nghe ve Nghe v\u00e8 vui \u0111\u1ed1 Nhanh t\u00ecm ba s\u1ed1 3 s\u1ed1 g\u00ec \u0111\u00e2y?","T\u1ed5ng 3 s\u1ed1 n\u00e0y B\u1eb1ng t\u00edch ch\u00fang ngay Ai bi\u1ebft, ai hay Xin nhanh, nhanh k\u1ec3 B\u1ea1n h\u1ecdc gi\u1ecfi th\u1ebf Kh\u00f4ng l\u1ebd ch\u1ecbu thua? V\u1eeba h\u1ecdc v\u1eeba \u0111\u00f9a Xem ai gi\u1ecfi nh\u1ea5t. C\u00e2u 4. S\u1ed1 n\u00e0o ti\u1ebfp theo d\u00e3y s\u1ed1 sau? 100, 99, 97, 93, 85, ? C\u00e2u 5. Trong m\u1ed9t b\u1ea3ng c\u1ee7a Cup b\u00f3ng \u0111\u00e1 th\u1ebf gi\u1edbi 1994, t\u1ed5ng s\u1ed1 \u0111i\u1ec3m c\u1ee7a 4 \u0111\u1ed9i c\u1ed9ng l\u1ea1i b\u1eb1ng 16. H\u1ecfi c\u00f3 m\u1ea5y tr\u1eadn th\u1eafng, m\u1ea5y tr\u1eadn h\u00f2a? (C\u00e1ch cho \u0111i\u1ec3m nh\u01b0 sau: \u0111\u1ed9i th\u1eafng \u0111\u01b0\u1ee3c 3 \u0111i\u1ec3m, \u0111\u1ed9i thua \u0111\u01b0\u1ee3c 0 \u0111i\u1ec3m, ho\u00e0 th\u00ec m\u1ed7i \u0111\u1ed9i \u0111\u01b0\u1ee3c 1 \u0111i\u1ec3m). C\u00e2u 6. M\u1ed9t c\u00e0nh c\u00e2y c\u00f3 th\u1ec3 \u0111\u1ee1 \u0111\u01b0\u1ee3c 3 ng\u01b0\u1eddi. John n\u1eb7ng g\u1ea5p 2 l\u1ea7n Adam, Rachel n\u1eb7ng b\u1eb1ng m\u1ed9t n\u1eeda Adam. V\u1eady John, Rachel v\u00e0 Adam \u0111\u1ec1u c\u00f3 th\u1ec3 c\u00f9ng ng\u1ed3i tr\u00ean c\u00e0nh c\u00e2y \u0111\u00f3. a. \u0110\u00fang b. Sai","C\u00e2u 7. Tr\u00ean m\u1ed9t qu\u00e3ng \u0111\u01b0\u1eddng d\u00e0i 3km, ng\u01b0\u1eddi ta tr\u1ed3ng c\u00e2y hai b\u00ean \u0111\u01b0\u1eddng theo th\u1ee9 t\u1ef1: 1 c\u00e2y d\u01b0\u01a1ng, 1 c\u00e2y d\u01b0\u01a1ng n\u1eefa, 1 c\u00e2y b\u1ea1ch \u0111\u00e0n r\u1ed3i \u0111\u1ebfn 1 c\u00e2y tr\u00e0m. Bi\u1ebft r\u1eb1ng c\u1ee9 c\u00e1ch 20m l\u1ea1i tr\u1ed3ng m\u1ed9t c\u00e2y v\u00e0 c\u00f3 tr\u1ed3ng c\u00e2y \u1edf hai \u0111\u1ea7u \u0111\u01b0\u1eddng, h\u1ecfi ph\u1ea3i d\u00f9ng bao nhi\u00eau c\u00e2y m\u1ed7i lo\u1ea1i? C\u00e2u 8. 3 c\u00e2y v\u1ea3i \u0111\u1ecf, xanh, v\u00e0ng Chi\u1ec1u d\u00e0i t\u1ed5ng c\u1ed9ng l\u00e0 ng\u00e0n m\u00e9t y V\u1ea3i \u0111\u1ecf 10 m\u00e9t c\u1eaft \u0111i May c\u1edd t\u1eb7ng \u0111\u1ed9i thi\u1ebfu nhi di\u1ec5u h\u00e0nh C\u1eaft 20 m\u00e9t v\u1ea3i xanh Th\u01b0\u1edfng cho c\u00e1c b\u1ea1n h\u1ecdc h\u00e0nh gi\u1ecfi ngoan C\u1eaft 25 m\u00e9t v\u1ea3i v\u00e0ng T\u1eb7ng \u0111\u1ed9i v\u0103n ngh\u1ec7 may m\u00e0n, k\u00e9o ph\u00f4ng N\u00e0y em, n\u00e0y b\u1ea1n bi\u1ebft kh\u00f4ng 3 c\u00e2y l\u00fac \u0111\u00f3 d\u00e0i \u0111\u1ed3ng nh\u01b0 nhau \u0110\u1ed1 ai, ai bi\u1ebft \u0111\u00e1p mau M\u1ed7i c\u00e2y v\u1ea3i l\u00fac ban \u0111\u1ea7u d\u00e0i nhi\u00eau?","B\u00e0i 20 C\u00e2u 1. S\u1ed1 n\u00e0o thay cho d\u1ea5u (?) 188 300 263 893 ? 915 C\u00e2u 2. M\u1ed9t ng\u01b0\u1eddi du l\u1ecbch r\u1eddi kh\u1ecfi th\u00e0nh ph\u1ed1, \u0111i b\u1ed9 h\u1ebft 6 gi\u1edd v\u00e0 \u0111i ng\u1ef1a h\u1ebft 5 gi\u1edd th\u00ec c\u00e1ch xa th\u00e0nh ph\u1ed1 80km. L\u1ea7n sau ng\u01b0\u1eddi \u0111\u00f3 r\u1eddi th\u00e0nh ph\u1ed1 \u0111i ng\u1ef1a h\u1ebft 11 gi\u1edd, r\u1ed3i \u0111i b\u1ed9 quay tr\u1edf l\u1ea1i th\u00e0nh ph\u1ed1 h\u1ebft 6 gi\u1edd th\u00ec l\u00fac \u0111\u00f3 c\u00f2n c\u00e1ch th\u00e0nh ph\u1ed1 64km. H\u00e3y t\u00ednh xem khi \u0111i ng\u1ef1a, ng\u01b0\u1eddi \u0111\u00f3 \u0111i \u0111\u01b0\u1ee3c bao nhi\u00eau kil\u00f4m\u00e9t trong 1 gi\u1edd? C\u00e2u 3. Gi\u00e1 c\u1ee7a m\u1ed9t \u0111\u00f4i t\u1ea5t l\u00e0 3.500\u0111. Gi\u00e1 m\u1ed9t h\u1ed9p g\u1ed3m 6 \u0111\u00f4i t\u1ea5t l\u00e0 19.500\u0111. H\u00e3y t\u00ednh bao nhi\u00eau ph\u1ea7n tr\u0103m r\u1ebb h\u01a1n khi b\u1ea1n mua m\u1ed9t h\u1ed9p g\u1ed3m 6 \u0111\u00f4i t\u1ea5t? C\u00e2u 4. S\u1ed1 n\u00e0o thay cho d\u1ea5u (?). 1 36 1 34?9 6 86","C\u00e2u 5. D\u00f9ng ch\u00eca kh\u00f3a (key) d\u01b0\u1edbi \u0111\u00e2y h\u00e3y l\u00e0m c\u00e1c ph\u00e9p t\u00ednh T, W, Z v\u00e0 c\u00e1c gi\u00e1 tr\u1ecb bao xung quanh ch\u00fang: % % \\\\$ ) T ) Z ) % \\\\$ ) % \\\\$ W % % \\\\$ ) ) Key: ) = 3, % = 7, \\\\$ = 5 T = ?, W = ?, Z = ? C\u00e2u 6. T\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a b\u1ed1, m\u1eb9 v\u00e0 hai con l\u00e0 87. B\u1ed1 h\u01a1n m\u1eb9 3 tu\u1ed5i. S\u1ed1 tu\u1ed5i c\u1ee7a ng\u01b0\u1eddi con th\u1ee9 nh\u1ea5t g\u1ea5p \u0111\u00f4i s\u1ed1 tu\u1ed5i c\u1ee7a ng\u01b0\u1eddi con th\u1ee9 hai. S\u1ed1 tu\u1ed5i ng\u01b0\u1eddi con th\u1ee9 hai nh\u00e2n v\u1edbi ch\u00ednh s\u1ed1 \u0111\u00f3 th\u00ec b\u1eb1ng s\u1ed1 tu\u1ed5i c\u1ee7a b\u1ed1. H\u00e3y t\u00ednh s\u1ed1 tu\u1ed5i c\u1ee7a m\u1ed7i ng\u01b0\u1eddi trong gia \u0111\u00ecnh n\u00e0y? C\u00e2u 7. C\u00f3 12 v\u1eadn \u0111\u1ed9ng vi\u00ean ch\u1ea1y marathon, h\u1ecd ch\u1ea1y th\u00e0nh hai h\u00e0ng v\u1edbi \u00e1o \u0111\u01b0\u1ee3c mang s\u1ed1 \u0111\u01b0\u1ee3c x\u1ebfp nh\u01b0 sau: H\u00e0ng 1: 8 5 4 46 52 61 H\u00e0ng 2: 7 6 9 94 63 ? V\u1eadn \u0111\u1ed9ng vi\u00ean cu\u1ed1i c\u00f9ng s\u1ebd m\u1eb7c \u00e1o s\u1ed1 bao nhi\u00eau? C\u00e2u 8. \u0110\u1ed1 em, \u0111\u1ed1 b\u1ea1n, \u0111\u1ed1 ai \u0110\u1ed5i c\u00e1c \u0111\u01a1n v\u1ecb chi\u1ec1u d\u00e0i ra mau","T\u1eeb t\u1eeb t\u00ednh tr\u01b0\u1edbc suy sau Ghi li\u1ec1n \u0111\u00e1p s\u1ed1, ch\u1ee9 \u0111\u00e2u kh\u00f3 g\u00ec! a. 14m 5dm = ?dm b. 1km 50m = ? m c. 2500m = ? km ?m d. 968mm = ? dm ?mm","C\u00e2u 1. H\u00ecnh \u1ea3nh n\u00e0o \u00edt gi\u1ed1ng v\u1edbi c\u00e1c h\u00ecnh c\u00f2n l\u1ea1i? C\u00e2u 2. D\u00f9ng 4 ch\u1eef s\u1ed1 1, 2, 3, 4 c\u00f3 th\u1ec3 vi\u1ebft \u0111\u01b0\u1ee3c bao nhi\u00eau s\u1ed1 c\u00f3 4 ch\u1eef s\u1ed1 kh\u00e1c nhau? C\u00e2u 3. S\u01a1n v\u1eeba \u0111\u1ee9ng th\u1ee9 10 t\u1eeb tr\u00ean xu\u1ed1ng v\u1eeba \u0111\u1ee9ng th\u1ee9 10 t\u1eeb d\u01b0\u1edbi l\u00ean trong cu\u1ed9c thi vi\u1ebft v\u1edf s\u1ea1ch ch\u1eef \u0111\u1eb9p. H\u1ecfi c\u00f3 bao nhi\u00eau b\u1ea1n tham gia cu\u1ed9c thi? C\u00e2u 4. 1000 v\u1edf th\u01b0\u1edfng cu\u1ed1i n\u0103m C\u00f3 50 b\u1ea1n gi\u1ecfi ch\u0103m nh\u1eadn qu\u00e0 Ph\u00e2n \u0111\u1ec1u s\u1ed1 v\u1edf tr\u00ean ra C\u00f3 12 b\u1ea1n kh\u1ed1i ba l\u00e3nh ph\u1ea7n \u0110\u1ed1 ai to\u00e1n gi\u1ecfi chia nh\u00e2n Kh\u1ed1i ba ri\u00eang t\u00ednh nh\u1eadn ph\u1ea7n bao nhi\u00eau?","C\u00e2u 5. L\u1edbp A c\u00f3 47 h\u1ecdc sinh, l\u1edbp B c\u00f3 43 h\u1ecdc sinh. C\u1ea3 hai l\u1edbp \u0111\u01b0\u1ee3c mua 450 quy\u1ec3n v\u1edf. M\u1ed7i h\u1ecdc sinh \u0111\u1ec1u \u0111\u01b0\u1ee3c mua m\u1ed9t s\u1ed1 v\u1edf nh\u01b0 nhau. H\u1ecfi m\u1ed7i l\u1edbp \u0111\u01b0\u1ee3c mua bao nhi\u00eau quy\u1ec3n v\u1edf? C\u00e2u 6. Mu\u1ed1n \u0111o chi\u1ec1u d\u00e0i c\u1ee7a m\u1ed9t c\u0103n ph\u00f2ng, ch\u00fang ta \u0111o b\u1eb1ng c\u00e1ch l\u1ea5y th\u01b0\u1edbc \u0111o hay \u0111o b\u1eb1ng c\u00e1ch \u0111\u1ebfm c\u00e1c vi\u00ean g\u1ea1ch l\u00e1t \u1edf n\u1ec1n s\u1ebd ch\u00ednh x\u00e1c h\u01a1n? C\u00e2u 7. Trong b\u1ea3ng d\u01b0\u1edbi \u0111\u00e2y, h\u00e3y t\u00ecm t\u1ed5ng c\u1ee7a ba s\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t, sau \u0111\u00f3 t\u00ecm t\u00edch c\u1ee7a hai s\u1ed1 l\u1ebb nh\u1ecf nh\u1ea5t. Cu\u1ed1i c\u00f9ng l\u1ea5y t\u1ed5ng tr\u1eeb \u0111i t\u00edch, k\u1ebft qu\u1ea3 l\u00e0 bao nhi\u00eau? 14 15 10 3 9 16 21 22 11 8 24 12 C\u00e2u 8. S\u1ed1 n\u00e0o thay cho d\u1ea5u (?). 754624178 1 6642278? 45271 2765 C\u00e2u 9. M\u1ed9t \u00f4t\u00f4 di chuy\u1ec3n 40km, trong c\u00f9ng th\u1eddi gian nh\u01b0 v\u1eady m\u1ed9t \u00f4t\u00f4 kh\u00e1c di chuy\u1ec3n nhanh h\u01a1n 20km\/h, v\u1edbi kho\u1ea3ng c\u00e1ch 60km. H\u00e0nh tr\u00ecnh c\u1ee7a \u00f4t\u00f4 th\u1ee9 nh\u1ea5t m\u1ea5t bao l\u00e2u?","B\u00e0i 22 C\u00e2u 1. T\u00ecm s\u1ed1 \u0111i\u1ec1n v\u00e0o d\u1ea5u h\u1ecfi ch\u1ea5m 36 | 30 | 24 | 18 | ? C\u00e2u 2. Trong gi\u1ea3i v\u00f4 \u0111\u1ecbch b\u00f3ng \u0111\u00e1 tr\u1ebb to\u00e0n qu\u1ed1c, b\u1ea3ng B c\u00f3 5 \u0111\u1ed9i thi \u0111\u1ea5u v\u00f2ng tr\u00f2n m\u1ed9t l\u01b0\u1ee3t, t\u00ednh \u0111i\u1ec3m. Trong m\u1ed7i tr\u1eadn \u0111\u1ea5u \u0111\u1ed9i th\u1eafng \u0111\u01b0\u1ee3c 3 \u0111i\u1ec3m, \u0111\u1ed9i thua \u0111\u01b0\u1ee3c 0 \u0111i\u1ec3m, n\u1ebfu h\u00f2a th\u00ec m\u1ed7i \u0111\u1ed9i \u0111\u01b0\u1ee3c 1 \u0111i\u1ec3m. H\u00e3y t\u00ednh xem m\u1ed7i \u0111\u1ed9i b\u00f3ng th\u1eafng m\u1ea5y tr\u1eadn, ho\u00e0 m\u1ea5y tr\u1eadn, thua m\u1ea5y tr\u1eadn, n\u1ebfu: a. \u0110\u1ed9i \u0111\u00f3 \u0111\u01b0\u1ee3c 7 \u0111i\u1ec3m b. \u0110\u1ed9i \u0111\u00f3 \u0111\u01b0\u1ee3c 8 \u0111i\u1ec3m c. \u0110\u1ed9i \u0111\u00f3 \u0111\u01b0\u1ee3c 11 \u0111i\u1ec3m. C\u00e2u 3. T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a A, B,C v\u00e0 D C C A D =22 C D D A =20 A A D D =32 C B B A =30 =24 =25 =23 =32","C\u00e2u 4. Ch\u1ecdn m\u1ed9t trong n\u0103m h\u00ecnh b\u00ean d\u01b0\u1edbi \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o d\u1ea5u (?): C\u00e2u 5. B\u00e0 c\u00f3 m\u1ed9t s\u1ed1 qu\u1ea3 na Chia 5 r\u1ed3i l\u1ea1i l\u1ea5y ra m\u1ed9t ph\u1ea7n G\u1ecdi Ti, T\u00e8o, T\u00ed \u0111\u1ebfn g\u1ea7n Xoa \u0111\u1ea7u, \u0111\u1ebfm qu\u1ea3 ph\u00e1t ph\u00e2n l\u00e0m qu\u00e0 Ti: 5, T\u00e8o: ch\u1ec9 \u0111\u01b0\u1ee3c 3 T\u00ed nh\u1ecf nh\u1ea5t nh\u00e0 \u0111\u01b0\u1ee3c 6 qu\u1ea3 xinh \u0110\u1ed1 h\u1ecdc tr\u00f2, \u0111\u1ed1 h\u1ecdc sinh S\u1ed1 na b\u00e0 c\u00f3 khai tr\u00ecnh bao nhi\u00eau? C\u00e2u 6. C\u1ed9ng s\u1ed1 tu\u1ed5i c\u1ee7a An v\u00e0 B\u00ecnh l\u00e0 88 C\u1ed9ng s\u1ed1 tu\u1ed5i c\u1ee7a B\u00ecnh v\u00e0 Chi l\u00e0 76","C\u1ed9ng s\u1ed1 tu\u1ed5i c\u1ee7a An v\u00e0 Chi l\u00e0 80 H\u00e3y t\u00ednh s\u1ed1 tu\u1ed5i c\u1ee7a m\u1ed7i ng\u01b0\u1eddi? C\u00e2u 7. \u0110\u01b0a s\u1ed1 v\u00e0o c\u00e1c \u00f4 tr\u1ed1ng sao cho t\u1ea5t c\u1ea3 c\u00e1c b\u00e0i to\u00e1n \u0111\u01b0\u1ee3c \u0111\u00fang theo h\u00e0ng ngang v\u00e0 h\u00e0ng d\u1ecdc, 6 v\u00e0 8 \u0111\u00e3 \u0111\u01b0\u1ee3c \u0111\u1eb7t s\u1eb5n. C\u00e2u 8. 7 m\u00e8o, 3 ng\u01b0\u1eddi, 5 g\u00e0 v\u00e0 6 ch\u00f3, h\u1ecfi c\u00f3 t\u1ed5ng s\u1ed1 bao nhi\u00eau ch\u00e2n? (Kh\u00f4ng c\u00f3 ng\u01b0\u1eddi v\u00e0 con v\u1eadt n\u00e0o kh\u00e1c th\u01b0\u1eddng).","C\u00e2u 1. C\u00f3 m\u1ed9t nh\u00e0 r\u1ea5t gi\u00e0u, s\u1ee3 bu\u1ed5i \u0111\u00eam b\u1ecb tr\u1ed9m vi\u1ebfng th\u0103m, h\u1ecd \u0111\u00e3 thu\u00ea 1 ng\u01b0\u1eddi canh nh\u00e0 ban \u0111\u00eam. M\u1ed9t s\u00e1ng n\u1ecd, ng\u01b0\u1eddi canh nh\u00e0 h\u1ed9c t\u1ed1c ch\u1ea1y v\u00e0o n\u00e0i n\u1ec9 \u00f4ng ch\u1ee7 \u0111\u1eebng \u0111i c\u00f4ng t\u00e1c b\u1eb1ng chuy\u1ebfn bay s\u1eafp t\u1edbi v\u00ec anh ta n\u1eb1m m\u01a1 th\u1ea5y chuy\u1ebfn bay \u0111\u00f3 b\u1ecb g\u1eb7p n\u1ea1n v\u00e0 t\u1ea5t c\u1ea3 m\u1ecdi ng\u01b0\u1eddi \u0111\u1ec1u ch\u1ebft. Y nh\u01b0 r\u1eb1ng chuy\u1ec7n \u0111\u00f3 \u0111\u00fang s\u1ef1 th\u1eadt. Gia \u0111\u00ecnh \u0111\u00f3 c\u00e1m \u01a1n anh ta, t\u1eb7ng th\u01b0\u1edfng r\u1ea5t nhi\u1ec1u th\u1ee9 nh\u01b0ng r\u1ed3i \u0111u\u1ed5i anh ta \u0111i. H\u00e0nh \u0111\u1ed9ng c\u1ee7a gia \u0111\u00ecnh \u0111\u00f3 c\u00f3 h\u1ee3p l\u00fd kh\u00f4ng? C\u00e2u 2. a. V\u1edbi b\u1ed1n ch\u1eef s\u1ed1 2, 0, 4, 7, c\u00f3 th\u1ec3 l\u1eadp \u0111\u01b0\u1ee3c bao nhi\u00eau s\u1ed1 c\u00f3 4 ch\u1eef s\u1ed1 m\u00e0 c\u00f3 m\u1eb7t c\u1ea3 4 ch\u1eef s\u1ed1 \u0111\u00f3. b. H\u00e3y vi\u1ebft c\u00e1c s\u1ed1 \u1ea5y d\u01b0\u1edbi d\u1ea1ng t\u1ed5ng c\u1ee7a c\u00e1c ng\u00e0n, c\u00e1c ch\u1ee5c, c\u00e1c tr\u0103m \u0111\u01a1n v\u1ecb. c. T\u00ednh t\u1ed5ng t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 \u0111\u00f3. C\u00e2u 3. T\u00ecm s\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng: 4 12 10 6 10 3 6 7 68? 5 C\u00e2u 4. M\u1ed9t th\u00f9ng \u0111em \u0111\u1ef1ng d\u1ea7u \u0111\u1ea7y","N\u1eb7ng 44 k\u00fd, ghi ngay nh\u1edb r\u1ed3i Th\u00f9ng \u0111\u00f3 \u0111\u1ef1ng n\u1eeda d\u1ea7u th\u00f4i N\u1eb7ng 24 k\u00fd, gi\u00fap t\u00f4i gi\u1ea3i li\u1ec1n Em ngoan th\u00ec t\u00e0i v\u1edbi b\u1ea1n hi\u1ec1n V\u1ecf th\u00f9ng n\u1eb7ng m\u1ea5y, mau nghi\u00ean c\u1ee9u gi\u00f9m. C\u00e2u 5. Tu\u1ed5i Mai g\u1ea5p hai l\u1ea7n tu\u1ed5i c\u1ee7a Nam. Tu\u1ed5i c\u1ee7a Nam b\u1eb1ng 1\/3 tu\u1ed5i c\u1ee7a Lan. H\u1ecfi ai nhi\u1ec1u tu\u1ed5i nh\u1ea5t? C\u00e2u 6. An mua 5 c\u00e2y b\u00fat m\u00e1y, B\u00ecnh mua 3 c\u00e2y b\u00fat bi, An tr\u1ea3 nhi\u1ec1u h\u01a1n B\u00ecnh 54.000\u0111. T\u00ecm gi\u00e1 ti\u1ec1n m\u1ed7i lo\u1ea1i b\u00fat bi\u1ebft r\u1eb1ng m\u1ed9t c\u00e2y b\u00fat m\u00e1y \u0111\u1eaft h\u01a1n c\u00e2y b\u00fat bi 10.000\u0111. C\u00e2u 7. S\u1ed1 n\u00e0o ti\u1ebfp theo d\u00e3y s\u1ed1 sau? 18 | 20 | 24 | 32 | ?","B\u00e0i 24 C\u00e2u 1. Chia 30 cho 1\/2 r\u1ed3i c\u1ed9ng th\u00eam 10. K\u1ebft qu\u1ea3 b\u1eb1ng? c. 35 b. 70 c. 35 C\u00e2u 2. M\u1ed9t ng\u01b0\u1eddi n\u00f4ng d\u00e2n c\u00f3 17 con c\u1eebu, 9 con v\u1eeba ch\u1ebft. H\u1ecfi ng\u01b0\u1eddi n\u00f4ng d\u00e2n \u0111\u00f3 c\u00f2n l\u1ea1i m\u1ea5y con? C\u00e2u 3. Hai \u0111o\u00e0n \u00f4t\u00f4 c\u00f9ng ch\u1edf m\u1ed9t s\u1ed1 xi m\u0103ng nh\u01b0 nhau. \u0110o\u00e0n th\u1ee9 nh\u1ea5t g\u1ed3m c\u00e1c \u00f4t\u00f4 lo\u1ea1i c\u00f3 tr\u1ecdng t\u1ea3i 5 t\u1ea5n, \u0111o\u00e0n th\u1ee9 hai g\u1ed3m c\u00e1c \u00f4t\u00f4 c\u00f3 tr\u1ecdng t\u1ea3i 3 t\u1ea5n. Bi\u1ebft t\u1ed5ng s\u1ed1 \u00f4t\u00f4 c\u1ee7a c\u1ea3 hai \u0111o\u00e0n l\u00e0 24 chi\u1ebfc. T\u00ecm s\u1ed1 \u00f4t\u00f4 m\u1ed7i \u0111o\u00e0n? C\u00e2u 4. C\u00f3 ba con kh\u1ec9 c\u00f9ng \u0111i qua m\u1ed9t chi\u1ebfc c\u1ea7u kh\u1ec9. M\u1ed9t con l\u00f4ng m\u00e0u n\u00e2u, m\u1ed9t con l\u00f4ng m\u00e0u v\u00e0ng, m\u1ed9t con l\u00f4ng m\u00e0u ng\u0169 s\u1eafc. B\u1ed7ng m\u1ed9t con b\u1ecb r\u01a1i xu\u1ed1ng n\u01b0\u1edbc, c\u00f2n hai con tr\u00ean c\u1ea7u. H\u1ecfi con kh\u1ec9 b\u1ecb r\u01a1i xu\u1ed1ng n\u01b0\u1edbc l\u00f4ng m\u00e0u g\u00ec? C\u00e2u 5. T\u1ed5ng 5 s\u1ed1 ch\u1eb5n \u0111\u1ea7u ti\u00ean T\u1ed5ng 5 s\u1ed1 l\u1ebb \u0111\u1ea7u ti\u00ean","\u0110\u1ed1 em ngoan, \u0111\u1ed1 b\u1ea1n hi\u1ec1n So s\u00e1nh hai t\u1ed5ng, \u0111\u00e1p li\u1ec1n ra sao? Thi t\u00e0i, th\u1eed s\u1ee9c th\u1ea5p cao Ai \u0111\u00e1p nhanh \u0111\u00fang, m\u1eebng ch\u00e0o ph\u00e1o tay. C\u00e2u 6. Ch\u1ecdn m\u1ed9t trong 5 h\u00ecnh b\u00ean d\u01b0\u1edbi \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o d\u1ea5u (?). C\u00e2u 7. M\u1ed9t \u0111\u1ed9i c\u00f4ng nh\u00e2n c\u00f3 38 ng\u01b0\u1eddi nh\u1eadn s\u1eeda m\u1ed9t qu\u00e3ng \u0111\u01b0\u1eddng d\u00e0i 1.330m trong 5 ng\u00e0y. H\u1ecfi mu\u1ed1n s\u1eeda m\u1ed9t qu\u00e3ng \u0111\u01b0\u1eddng d\u00e0i 1.470m trong 2 ng\u00e0y th\u00ec c\u1ea7n bao nhi\u00eau c\u00f4ng nh\u00e2n? (M\u1ee9c l\u00e0m c\u1ee7a m\u1ed7i ng\u01b0\u1eddi \u0111\u1ec1u nh\u01b0 nhau).","C\u00e2u 1. Ba ch\u1ecb c\u00f4ng nh\u00e2n \u0111\u01b0\u1ee3c chia m\u1ed9t s\u1ed1 ti\u1ec1n th\u01b0\u1edfng nh\u01b0 sau: s\u1ed1 ti\u1ec1n c\u1ee7a ch\u1ecb An v\u00e0 ch\u1ecb Ba l\u00e0 200.000 \u0111\u1ed3ng, s\u1ed1 ti\u1ec1n c\u1ee7a ch\u1ecb Ba v\u00e0 ch\u1ecb C\u00fac l\u00e0 150.000 \u0111\u1ed3ng, s\u1ed1 ti\u1ec1n c\u1ee7a ch\u1ecb C\u00fac v\u00e0 ch\u1ecb An l\u00e0 220.000 \u0111\u1ed3ng. H\u1ecfi m\u1ed7i ng\u01b0\u1eddi \u0111\u01b0\u1ee3c th\u01b0\u1edfng bao nhi\u00eau ti\u1ec1n? C\u00e2u 2. C\u00f3 bao nhi\u00eau vi\u00ean g\u1ea1ch c\u00f2n thi\u1ebfu? C\u00e2u 3. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng 1 45? 236? C\u00e2u 4. M\u1ed9t ng\u01b0\u1eddi b\u00e1n kem c\u00f3 6 lo\u1ea1i kem kh\u00e1c nhau. N\u1ebfu m\u1ed7i l\u1ea7n \u00f4ng ta","b\u00e1n hai que kem v\u1edbi hai h\u01b0\u01a1ng v\u1ecb kh\u00e1c nhau th\u00ec \u00f4ng c\u00f3 th\u1ec3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l\u1ea7n nh\u01b0 v\u1eady? C\u00e2u 5. S\u1eed d\u1ee5ng ch\u00eca kho\u00e1 (key) d\u01b0\u1edbi \u0111\u00e2y, l\u00e0m ph\u00e9p t\u00ednh X, Y, Z v\u1edbi c\u00e1c gi\u00e1 tr\u1ecb bao xung quanh n\u00f3 Key: | \\\\$=1 | @=2 | &=3 @$ & $ & & Y @@& @$ & $ X Z &@@$ X=? | Y=? | Z=? C\u00e2u 6. T\u1eeb 10 \u0111\u1ebfn 1.000 c\u00f3 bao nhi\u00eau s\u1ed1 t\u1ef1 nhi\u00ean m\u00e0 t\u1ed5ng c\u00e1c ch\u1eef s\u1ed1 c\u1ee7a s\u1ed1 \u0111\u00f3 b\u1eb1ng 9? C\u00e2u 7. An c\u1ea7n \u0111em 11 b\u00ecnh n\u01b0\u1edbc cho c\u1eeda h\u00e0ng. An ch\u1ec9 c\u00f3 th\u1ec3 mang 3 b\u00ecnh m\u1ed9t l\u00fac, v\u1eady s\u1ed1 l\u1ea7n t\u1ed1i thi\u1ec3u An ph\u1ea3i \u0111i l\u1ea1i l\u00e0 bao nhi\u00eau? a. 5 b. 4 1\/2 c. 1\/2 d. 5 1\/2 e. 4","C\u00e2u 8. T\u00ecm hai s\u1ed1 ti\u1ebfp theo c\u1ee7a d\u00e3y s\u1ed1 sau: 9 | 7 | 12 | 10 | ? | ?","B\u00e0i 26 C\u00e2u 1. B\u1ea1n \u0111\u1ee9ng trong nh\u00e0 c\u00f3 3 c\u00e1i c\u00f4ng t\u1eafc, trong \u0111\u00f3 ch\u1ec9 c\u00f3 1 c\u00e1i c\u00f4ng t\u1eafc n\u1ed1i v\u1edbi b\u00f3ng \u0111\u00e8n ngo\u00e0i s\u00e2n. Khi b\u00f3ng s\u00e1ng, b\u1ea1n \u1edf trong nh\u00e0 kh\u00f4ng nh\u00ecn th\u1ea5y v\u00e0 b\u1ea1n ch\u1ec9 \u0111\u01b0\u1ee3c ch\u1ea1y ra ngo\u00e0i s\u00e2n xem b\u00f3ng s\u00e1ng hay kh\u00f4ng duy nh\u1ea5t 1 l\u1ea7n. B\u1eb1ng c\u00e1ch n\u00e0o b\u1ea1n c\u00f3 th\u1ec3 bi\u1ebft c\u00f4ng t\u1eafc n\u00e0o l\u00e0 c\u00f4ng t\u1eafc n\u1ed1i v\u1edbi b\u00f3ng \u0111\u00e8n ngo\u00e0i s\u00e2n. C\u00e2u 2. S\u00e1ch 98 cu\u1ed1n, 2 ng\u0103n Nghe cho k\u1ef9 nh\u00e9, bi\u1ebft r\u1eb1ng: N\u1ebfu ng\u0103n nh\u1ea5t d\u1eddi 12 cu\u1ed1n Xu\u1ed1ng ng\u0103n hai, l\u00fac \u0111\u00f3 2 ng\u0103n 2 ng\u0103n s\u1ed1 s\u00e1ch c\u00e2n b\u1eb1ng \u0110\u1ed1 ai, ai c\u00f3 bi\u1ebft ch\u0103ng Bao nhi\u00eau cu\u1ed1n s\u00e1ch m\u1ed7i ng\u0103n ban \u0111\u1ea7u? C\u00e2u 3. M\u1ed9t \u0111\u1ed9i d\u00e2n c\u00f4ng \u0111\u1eafp \u0111\u00ea ph\u00f2ng l\u1ee5t, 4 ng\u00e0y \u0111\u1ea7u m\u1ed7i ng\u00e0y \u0111\u1eafp \u0111\u01b0\u1ee3c 115m3, 6 ng\u00e0y sau \u0111\u1eafp \u0111\u01b0\u1ee3c 140 m3. H\u1ecfi trung b\u00ecnh m\u1ed7i ng\u00e0y \u0111\u1ed9i d\u00e2n c\u00f4ng \u0111\u00f3 \u0111\u1eafp \u0111\u01b0\u1ee3c bao nhi\u00eau m3 \u0111\u1ea5t? C\u00e2u 4.","M\u1ed9t h\u1ed3 n\u01b0\u1edbc h\u00ecnh h\u1ed9p ch\u1eef nh\u1eadt d\u00e0i 1,2m; r\u1ed9ng 1m; cao 0,8m, h\u1ed3 kh\u00f4ng c\u00f3 n\u01b0\u1edbc. L\u00fac 6 gi\u1edd ng\u01b0\u1eddi ta m\u1edf n\u01b0\u1edbc v\u00e0o h\u1ed3, m\u1ed7i ph\u00fat ch\u1ea3y \u0111\u01b0\u1ee3c 32 l\u00edt. Tuy nhi\u00ean \u1edf \u0111\u00e2y h\u1ed3 l\u1ea1i c\u00f3 m\u1ed9t l\u1ed7 h\u1ed5ng, m\u1ed7i ph\u00fat ch\u1ea3y ra m\u1ea5t 20 l\u00edt. H\u1ecfi \u0111\u1ebfn m\u1ea5y gi\u1edd th\u00ec h\u1ed3 \u0111\u1ea7y n\u01b0\u1edbc? C\u00e2u 5. T\u00ecm s\u1ed1 ti\u1ebfp theo c\u1ee7a d\u00e3y s\u1ed1: 34 | 27 | 20 | 13 | ?","C\u00e2u 1. Ch\u1ecdn h\u00ecnh b\u00ean ph\u1ea3i \u0111\u1ec3 ti\u1ebfp v\u1edbi chu\u1ed7i h\u00ecnh b\u00ean tr\u00e1i: C\u00e2u 2. M\u1ed9t b\u1ea7y d\u00ea c\u00f3 35 con \u0111ang \u0111i trong r\u1eebng, \u0111\u1ed9t nhi\u00ean m\u1ed9t con b\u1ecb b\u1eafn ch\u1ebft, v\u1eady c\u00f2n t\u1ea5t c\u1ea3 bao nhi\u00eau con? C\u00e2u 3. Kim ng\u1eafn ch\u1ec9 s\u1ed1 12, kim d\u00e0i ch\u1ec9 gi\u1eefa s\u1ed1 1 v\u00e0 s\u1ed1 2, h\u1ecfi l\u00e0 m\u1ea5y gi\u1edd? C\u00e2u 4. Cho s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1, trong \u0111\u00f3 ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb g\u1ea5p \u0111\u00f4i ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c. N\u1ebfu l\u1ea5y s\u1ed1 \u0111\u00f3 tr\u1eeb \u0111i 4 th\u00ec s\u1ebd \u0111\u01b0\u1ee3c s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 gi\u1ed1ng nhau. H\u00e3y t\u00ecm s\u1ed1 \u0111\u00e3 cho? C\u00e2u 5. 4 con v\u1ecbt th\u00ec n\u1eb7ng h\u01a1n 6 con g\u00e0 1kg 3 con v\u1ecbt th\u00ec nh\u1eb9 h\u01a1n 10 con g\u00e0 7,5kg H\u1ecfi m\u1ed7i con v\u1ecbt n\u1eb7ng bao nhi\u00eau kil\u00f4gam?","C\u00e2u 6. Gi\u1ea3i ph\u00e9p t\u00ednh 40 | : | 2 | = | 5x ? a. 5 b. 20 c. 10 d. 4 e. 3 C\u00e2u 7. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: 18 6 11 3 12 3 7 2 2 27 18 ? C\u00e2u 8. \u0110i\u1ec1n s\u1ed1 v\u00e0o ch\u1ed7 tr\u1ed1ng: ? | 3 | 4 | 6 | 8 | 12 C\u00e2u 9. Trong ng\u00e0y H\u1ed9i Kh\u1ecfe Ph\u00f9 \u0110\u1ed5ng, tr\u00ean n\u00f3c kh\u00e1n \u0111\u00e0i s\u00e2n v\u1eadn \u0111\u1ed9ng t\u1ec9nh em c\u1eafm r\u1ea5t nhi\u1ec1u c\u1edd, c\u00e1ch \u0111\u1ec1u nhau 3m. Hai \u0111\u1ea7u kh\u00e1n \u0111\u00e0i \u0111\u1ec1u c\u00f3 c\u1edd. Cho chi\u1ec1u d\u00e0i kh\u00e1n \u0111\u00e0i l\u00e0 210m. H\u00e3y t\u00ednh s\u1ed1 c\u1edd c\u1ea7n d\u00f9ng v\u00e0 s\u1ed1 v\u1ea3i \u0111\u1ec3 may c\u1edd. Bi\u1ebft r\u1eb1ng m\u1ed7i l\u00e1 c\u1edd \u0111\u1ec1u c\u00f3 chi\u1ec1u r\u1ed9ng b\u1eb1ng kh\u1ed5 v\u1ea3i v\u00e0 chi\u1ec1u d\u00e0i l\u00e0 12dm.","C\u00e2u 10. Th\u01b0\u1edfng tr\u00f2 h\u1ecdc gi\u1ecfi, l\u00e0m ch\u0103m C\u00f4 \u0111em s\u1ed1 v\u1edf chia 5 ph\u1ea7n \u0111\u1ec1u M\u1ed9t b\u1ea1n g\u01b0\u01a1ng t\u1ed1t l\u00e0m theo T\u1eb7ng l\u1ea1i b\u1ea1n ngh\u00e8o 5 quy\u1ec3n c\u00f2n 3 \u0110\u1ed1 em, \u0111\u1ed1 b\u1ea1n g\u1ea7n xa S\u1ed1 v\u1edf c\u00f4 th\u01b0\u1edfng t\u1ed5ng l\u00e0 bao nhi\u00eau? \u0110\u1ed1 b\u1ea1n hi\u1ec1n, \u0111\u1ed1 em y\u00eau \u0110\u1ed1 ai, ai bi\u1ebft, mau \u0111i\u1ec1u tra xem.","B\u00e0i 28 C\u00e2u 1. Tr\u00ean \u0111\u01b0\u1eddng ph\u1ed1, c\u00f3 5 ng\u01b0\u1eddi \u0111\u00e0n \u00f4ng, tr\u00ean vai m\u1ed7i ng\u01b0\u1eddi \u0111\u00e0n \u00f4ng c\u00f3 1 c\u00e1i r\u1ed5. Trong m\u1ed7i c\u00e1i r\u1ed5 c\u00f3 m\u1ed9t con m\u00e8o m\u1eb9, m\u1ed7i con m\u00e8o m\u1eb9 c\u00f3 5 con m\u00e8o con. H\u1ecfi tr\u00ean \u0111\u01b0\u1eddng c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau c\u00e1i ch\u00e2n? (Kh\u00f4ng c\u00f3 ng\u01b0\u1eddi n\u00e0o hay con m\u00e8o n\u00e0o d\u1ecb t\u1eadt). C\u00e2u 2. Ch\u1ecdn m\u1ed9t trong 4 h\u00ecnh b\u00ean tr\u00e1i \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng: C\u00e2u 3. T\u00f3c h\u00fai, t\u00f3c d\u00e0i T\u1ed5ng c\u1ed9ng 42 T\u00ednh ri\u00eang phe n\u1eef t\u00f3c d\u00e0i 30 T\u00f3c h\u00fai chia t\u1ed5 6 ng\u01b0\u1eddi Th\u00e0nh ra m\u1ea5y t\u1ed5, m\u1ec9m c\u01b0\u1eddi \u0111\u00e1p nhanh?","C\u00e2u 4. C\u00f3 hai cha hai con c\u00f9ng \u0111i c\u00e2u c\u00e1 m\u1ed7i ng\u01b0\u1eddi c\u00e2u \u0111\u01b0\u1ee3c 1 con nh\u01b0ng khi v\u1ec1 t\u1edbi nh\u00e0 ch\u1ec9 c\u00f3 3 con. T\u1ea1i sao? C\u00e2u 5. Gi\u1ea3i ph\u00e9p t\u00ednh 6 x 0,5 = 0,25 x ? C\u00e2u 6. S\u1ed1 n\u00e0o ti\u1ebfp theo d\u00e3y s\u1ed1 sau? 156, 145, 123, 90, ? a. 46 b. 56 c. 69 d. 73 e. 79 C\u00e2u 7. T\u00e8o \u0111\u01b0\u1ee3c m\u1eb9 \u0111\u01b0a cho 10 qu\u1ea3 tr\u1ee9ng v\u1ecbt ra ch\u1ee3 b\u00e1n. D\u1ecdc \u0111\u01b0\u1eddng \u0111i, T\u00e8o g\u1eb7p ch\u00fa, ch\u00fa xin m\u1ed9t qu\u1ea3. Sau \u0111\u00f3 l\u1ea1i g\u1eb7p ch\u1ecb, T\u00e8o t\u1eb7ng ch\u1ecb 2 qu\u1ea3. C\u00f2n l\u1ea1i \u0111\u01b0a ra ch\u1ee3 b\u00e1n h\u1ebft. H\u1ecfi T\u00e8o b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ti\u1ec1n? (Bi\u1ebft m\u1ed7i qu\u1ea3 tr\u1ee9ng gi\u00e1 1.500\u0111). C\u00e2u 8. Cho h\u00ecnh v\u1ebd:","a. C\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef nh\u1eadt trong h\u00ecnh v\u1ebd? b. Bi\u1ebft c\u1ea1nh c\u1ee7a c\u00e1c \u00f4 vu\u00f4ng trong h\u00ecnh v\u1ebd \u0111\u1ec1u d\u00e0i 1cm. H\u00e3y t\u00ednh t\u1ed5ng di\u1ec7n t\u00edch c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c h\u00ecnh vu\u00f4ng c\u00f3 trong h\u00ecnh v\u1ebd. C\u00e2u 9. Tr\u1eddi kh\u00f4ng tr\u0103ng, kh\u00f4ng sao, kh\u00f4ng \u0111\u00e8n, m\u1ed9t \u00f4ng t\u00e2y \u0111en \u0111i gi\u1eefa l\u00f2ng \u0111\u01b0\u1eddng \u0111en. C\u00f3 m\u1ed9t \u00f4t\u00f4 \u0111i ng\u01b0\u1ee3c chi\u1ec1u nh\u01b0ng \u00f4ng t\u00e2y kh\u00f4ng b\u1ecb \u0111\u00e2m v\u00e0o \u00f4t\u00f4. H\u1ecfi t\u1ea1i sao? C\u00e2u 10. B\u00ed v\u00e0 B\u1ea7u c\u00f3 t\u1ea5t c\u1ea3 48 vi\u00ean bi. N\u1ebfu B\u00ed cho B\u1ea7u 3 vi\u00ean bi v\u00e0 B\u1ea7u cho l\u1ea1i B\u00ed 1 vi\u00ean bi th\u00ec hai b\u1ea1n c\u00f3 s\u1ed1 bi b\u1eb1ng nhau. H\u1ecfi tr\u01b0\u1edbc khi cho nhau, m\u1ed7i b\u1ea1n c\u00f3 bao nhi\u00eau vi\u00ean bi?","C\u00e2u 1. M\u1ed9t tr\u1ea1i ch\u0103n nu\u00f4i c\u00f3 100 con b\u00f2 v\u1eeba lo\u1ea1i m\u1ed9t, v\u1eeba lo\u1ea1i hai. B\u00f2 lo\u1ea1i m\u1ed9t c\u00f3 30 con, m\u1ed7i con m\u1ed9t n\u0103m cho 4.000 l\u00edt s\u1eefa. B\u00f2 lo\u1ea1i hai c\u00f3 70 con, m\u1ed7i con m\u1ed9t n\u0103m cho 3.600 l\u00edt s\u1eefa. H\u1ecfi: a. Trung b\u00ecnh m\u1ed7i n\u0103m con b\u00f2 cho bao nhi\u00eau l\u00edt s\u1eefa? b. Trung b\u00ecnh m\u1ed7i th\u00e1ng m\u1ed9t con b\u00f2 cho bao nhi\u00eau l\u00edt s\u1eefa? C\u00e2u 2. H\u00ecnh n\u00e0o \u0111i\u1ec1n v\u00e0o d\u1ea5u h\u1ecfi ch\u1ea5m? a, b, c, d hay e? C\u00e2u 3. M\u1ed9t c\u00f4ng nh\u00e2n k\u0129 thu\u1eadt t\u00ednh r\u1eb1ng mu\u1ed1n ti\u1ec7n 6 c\u00e1i b\u00e1nh xe ph\u1ea3i m\u1ea5t 4 gi\u1edd. H\u1ecfi mu\u1ed1n ti\u1ec7n 1260 c\u00e1i b\u00e1nh xe ki\u1ec3u \u1ea5y th\u00ec ph\u1ea3i m\u1ea5t bao nhi\u00eau ng\u00e0y c\u00f4ng lao \u0111\u1ed9ng, bi\u1ebft r\u1eb1ng m\u1ed7i ng\u00e0y c\u00f4ng lao \u0111\u1ed9ng l\u00e0 8 gi\u1edd?. C\u00e2u 4. Ba ch\u00e0ng trai v\u00e0o \u0103n ph\u1edf, m\u1ed7i ng\u01b0\u1eddi tr\u1ea3 10 ngh\u00ecn cho c\u00f4 b\u00e1n ph\u1edf, c\u00f4","ch\u1ee7 nh\u1edd ng\u01b0\u1eddi h\u1ea7u b\u00e0n tr\u1ea3 l\u1ea1i cho h\u1ecd 5 ngh\u00ecn. Nh\u01b0ng anh ch\u00e0ng n\u00e0y l\u1ea1i b\u1edbt 2 ngh\u00ecn v\u00e0 tr\u1ea3 cho m\u1ed7i ng\u01b0\u1eddi 1 ngh\u00ecn. V\u1eady t\u00ednh ra 3 ch\u00e0ng trai m\u1ea5t 9 x 3 = 27 ngh\u00ecn + v\u1edbi 2 ngh\u00ecn t\u1eeb ng\u01b0\u1eddi h\u1ea7u b\u00e0n l\u00e0 29 ngh\u00ecn. V\u1eady 1 ngh\u00ecn n\u1eefa \u1edf \u0111\u00e2u nh\u1ec9?. C\u00e2u 5. S\u1ed1 n\u00e0o \u0111i\u1ec1n v\u00e0o d\u1ea5u (?). 6 12 24 48 2 4 16 ? C\u00e2u 6. L\u1edbp em \u0111ang c\u00f3 8 b\u00e0n 6 b\u1ea1n 1 b\u00e0n, ng\u1ed3i ch\u1eadt nh\u01b0 n\u00eam M\u1ed7i b\u00e0n n\u1ebfu x\u1ebfp 4 em M\u1ea5y b\u00e0n c\u1ea7n ph\u1ea3i k\u00ea th\u00eam m\u1edbi v\u1eeba? Ai ng\u01b0\u1eddi ch\u0103m ch\u1ec9 s\u1edbm tr\u01b0a? \u0110\u1ed1 ai, ai bi\u1ebft, mau th\u01b0a r\u00f5 r\u00e0ng? C\u00e2u 7. S\u1ed1 n\u00e0o ti\u1ebfp theo d\u00e3y s\u1ed1 sau? 100, 70, 30, 100, 90, ? C\u00e2u 8. H\u00ecnh n\u00e0o b\u00ean ph\u1ea3i ti\u1ebfp theo chu\u1ed7i h\u00ecnh b\u00ean tr\u00e1i?","C\u00e2u 9. Ba anh ch\u00e0ng r\u00fat th\u0103m \u0111\u1ec3 ch\u1ecdn l\u00e0m con r\u1ec3. H\u1ecd l\u1ea7n l\u01b0\u1ee3t r\u00fat m\u1ed7i ng\u01b0\u1eddi 1 th\u0103m, trong 3 th\u0103m \u0111\u00f3 c\u00f3 1 th\u0103m chi\u1ebfn th\u1eafng. V\u1eady ng\u01b0\u1eddi n\u00e0o s\u1ebd c\u00f3 kh\u1ea3 n\u0103ng chi\u1ebfn th\u1eafng nh\u1ea5t? R\u00fat \u0111\u1ea7u hay r\u00fat sau?","B\u00e0i 30 C\u00e2u 1. Qu\u00e3ng \u0111\u01b0\u1eddng t\u1eeb A \u0111\u1ebfn B g\u1ed3m m\u1ed9t \u0111o\u1ea1n l\u00ean d\u1ed1c v\u00e0 m\u1ed9t \u0111o\u1ea1n xu\u1ed1ng d\u1ed1c. M\u1ed9t ng\u01b0\u1eddi \u0111i t\u1eeb A \u0111\u1ebfn B h\u1ebft 21 ph\u00fat r\u1ed3i tr\u1edf v\u1ec1 B \u0111\u1ebfn A m\u1ea5t 24 ph\u00fat. H\u00e3y t\u00ednh qu\u00e3ng \u0111\u01b0\u1eddng AB bi\u1ebft v\u1eadn t\u1ed1c khi l\u00ean d\u1ed1c l\u00e0 2,5km\/h v\u00e0 khi xu\u1ed1ng d\u1ed1c l\u00e0 5km\/h. C\u00e2u 2. D\u00f9ng ch\u00eca kho\u00e1 (key) d\u01b0\u1edbi \u0111\u00e2y l\u00e0m c\u00e1c ph\u00e9p t\u00ednh B, F, \u01af v\u1edbi nh\u1eefng gi\u00e1 tr\u1ecb bao xung quanh n\u00f3. Key: | %=6 | \\\\$=7 | @=8 W \\\\$ & \\\\$ @ @ % \\\\$ F % \\\\$ \\\\$ @ \\\\$ % @ B % @ \\\\$ B=? | F=? | W=? C\u00e2u 3. \u0110i\u1ec1n s\u1ed1 v\u00e0o \u00f4 tr\u1ed1ng: 4 7 21 20 42 14 8 100 252 64 C\u00e2u 4.","Trung b\u00ecnh c\u1ed9ng c\u1ee7a 3 s\u1ed1 l\u00e0 75. N\u1ebfu th\u00eam 0 v\u00e0o b\u00ean ph\u1ea3i s\u1ed1 th\u1ee9 hai th\u00ec \u0111\u01b0\u1ee3c s\u1ed1 th\u1ee9 nh\u1ea5t. N\u1ebfu g\u1ea5p 4 l\u1ea7n s\u1ed1 th\u1ee9 hai th\u00ec \u0111\u01b0\u1ee3c s\u1ed1 th\u1ee9 ba. T\u00ecm ba s\u1ed1 \u0111\u00f3? C\u00e2u 5. C\u00f3 bao nhi\u00eau h\u00ecnh ch\u1eef nh\u1eadt trong h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y? C\u00e2u 6. C\u00f4 gi\u00e1o chia v\u1edf cho m\u1ed9t s\u1ed1 b\u1ea1n. N\u1ebfu chia cho m\u1ed7i b\u1ea1n 5 quy\u1ec3n v\u1edf th\u00ec th\u1eeba 2 quy\u1ec3n, n\u1ebfu chia cho m\u1ed7i b\u1ea1n 6 quy\u1ec3n th\u00ec thi\u1ebfu 1 quy\u1ec3n. H\u1ecfi c\u00f3 m\u1ea5y b\u1ea1n \u0111\u01b0\u1ee3c chia v\u1edf? C\u00f4 gi\u00e1o c\u00f3 bao nhi\u00eau quy\u1ec3n v\u1edf? C\u00e2u 7. M\u1eb9 2 tu\u1ed5i nh\u1ecf h\u01a1n ba Tu\u1ed5i ba nh\u1edb nh\u00e9 \u0111\u1ea5y l\u00e0 33 Ai \u01a1i! Ai bi\u1ebft ch\u0103ng l\u00e0 Chia 2 tu\u1ed5i b\u00e0 b\u1eb1ng tu\u1ed5i m\u1eb9 \u0111\u00e2y Tu\u1ed5i b\u00e0 ai bi\u1ebft ai hay Bao nhi\u00eau nhanh h\u00e3y \u0111\u00e1p ngay, kh\u00f3 g\u00ec! C\u00e2u 8. Ch\u1eef n\u00e0o thay cho d\u1ea5u (?)","I 31 E O 17 Y ? 23 O C\u00e2u 9. Cho ba s\u1ed1, trong \u0111\u00f3 hi\u1ec7u s\u1ed1 c\u1ee7a s\u1ed1 l\u1edbn nh\u1ea5t v\u00e0 s\u1ed1 b\u00e9 nh\u1ea5t b\u1eb1ng 4,8. N\u1ebfu \u0111em m\u1ed9t s\u1ed1 nh\u00e2n v\u1edbi 12, m\u1ed9t s\u1ed1 nh\u00e2n v\u1edbi 15, m\u1ed9t s\u1ed1 nh\u00e2n v\u1edbi 10 th\u00ec \u0111\u01b0\u1ee3c ba t\u00edch b\u1eb1ng nhau. H\u00e3y t\u00ecm ba s\u1ed1 \u0111\u00e3 cho. C\u00e2u 10. M\u1ed7i t\u1ed5 c\u00f3 5 nam, 6 n\u1eef To\u00e1n ai hay, t\u00ednh th\u1eed gi\u00f9m xem L\u1edbp em s\u0129 s\u1ed1 m\u1ea5y em? Bi\u1ebft c\u00f3 b\u1ed1n t\u1ed5 ch\u1eb3ng th\u00eam b\u1edbt g\u00ec \u0110\u1ed1 em, \u0111\u1ed1 b\u1ea1n thi\u1ebfu nhi \u0110\u1ed1 ai, ai bi\u1ebft c\u00f9ng thi \u0111ua t\u00e0i?","C\u00e2u 1. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u1ea5u (?). 9 2 5 29 12 4 3 26 15 8 ? 15 C\u00e2u 2. M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 20 th\u00f9ng \u0111\u1ef1ng d\u1ea7u g\u1ed3m hai lo\u1ea1i: lo\u1ea1i th\u00f9ng 60 l\u00edt v\u00e0 lo\u1ea1i th\u00f9ng 40 l\u00edt. H\u1ecfi c\u00f3 bao nhi\u00eau th\u00f9ng m\u1ed7i lo\u1ea1i bi\u1ebft s\u1ed1 d\u1ea7u \u0111\u1ef1ng \u1edf m\u1ed7i lo\u1ea1i th\u00f9ng \u0111\u1ec1u b\u1eb1ng nhau? C\u00e2u 3. 3 s\u1ed1 trong m\u1ed9t ph\u00e9p chia \u0110em c\u1ed9ng ch\u00fang l\u1ea1i ra k\u00eca 95 S\u1ed1 chia cho bi\u1ebft b\u1eb1ng 5 H\u1ecfi th\u01b0\u01a1ng b\u1eb1ng m\u1ea5y, \u0111\u00e2y kh\u00e2m ph\u1ee5c t\u00e0i Ai \u0111\u00e1p nhanh \u0111\u00fang, \u0111\u1eebng sai Hoan h\u00f4 ai nh\u00e9, m\u1eddi ai nh\u1eadn qu\u00e0. C\u00e2u 4. S\u1eed d\u1ee5ng ch\u00eca kho\u00e1 (key) d\u01b0\u1edbi \u0111\u00e2y v\u00e0 l\u00e0 c\u00e1c ph\u00e9p t\u00ednh K, L, M v\u1edbi c\u00e1c gi\u00e1 tr\u1ecb xung quanh ch\u00fang.","Key: | \\\\$=7 | %=6 | !=5 $ %! ! $ %! K%! $ %$$ M L ! ! %$ K=? | L=? | M=? C\u00e2u 5. C\u00f3 bao nhi\u00eau h\u00ecnh vu\u00f4ng trong h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y? C\u00e2u 6. C\u00f3 m\u1ed9t \u0111\u00e0n chim v\u00e0 m\u1ed9t r\u1eebng c\u00e2y. L\u1ea7n \u0111\u1ea7u, ch\u00fang \u0111\u1eadu m\u1ed9t con xu\u1ed1ng m\u1ed9t c\u00e2y th\u00ec d\u01b0 ra m\u1ed9t con, khi \u0111\u00f3 \u0111\u00e0n chim bay l\u00ean r\u1ed3i \u0111\u00e1p xu\u1ed1ng \u0111\u1eadu l\u1ea7n hai, hai con m\u1ed9t c\u00e2y th\u00ec d\u01b0 ra m\u1ed9t c\u00e2y. H\u1ecfi c\u00f3 bao nhi\u00eau c\u00e2y v\u00e0 bao nhi\u00eau chim? C\u00e2u 7. Hai ng\u01b0\u1eddi mua chung 21m v\u1ea3i h\u1ebft 315.000\u0111. Ng\u01b0\u1eddi th\u1ee9 nh\u1ea5t tr\u1ea3 h\u01a1n ng\u01b0\u1eddi th\u1ee9 hai 52.500\u0111. H\u1ecfi m\u1ed7i ng\u01b0\u1eddi mua bao nhi\u00eau m\u00e9t v\u1ea3i? C\u00e2u 8.","S\u1ed1 n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng ph\u1ea3i s\u1ed1 nguy\u00ean t\u1ed1? a.73 | b.83 | c.79 | d.87 C\u00e2u 9. \u0110\u00e1p s\u1ed1 n\u00e0o \u0111\u00fang v\u1edbi bi\u1ec3u th\u1ee9c d\u01b0\u1edbi \u0111\u00e2y: (892) - (882) a. 176 b. 177 c. 178 d. 179 e. 180 C\u00e2u 10. \u0110\u1ed1 em, \u0111\u1ed1 b\u1ea1n g\u1ea7n xa Nhanh nhanh so s\u00e1nh A v\u00e0 B xem \u0110\u1ed1 ai, \u0111\u1ed1 b\u1ea1n, \u0111\u1ed1 em Ai \u0111\u00e1p nhanh \u0111\u00fang, th\u01b0\u1edfng k\u00e8m ph\u00e1o tay A = 155m + 50dm B = 1km - 840m","B\u00e0i 32 C\u00e2u 1. T\u1ed5ng c\u1ee7a 3 s\u1ed1 l\u1ebb li\u00ean ti\u1ebfp b\u1eb1ng 75. T\u00ecm 3 s\u1ed1 \u0111\u00f3. C\u00e2u 2. M\u1ed9t b\u1ebfp \u0103n chu\u1ea9n b\u1ecb g\u1ea1o cho 120 ng\u01b0\u1eddi \u0103n trong 50 ng\u00e0y. Nh\u01b0ng sau \u0111\u00f3 c\u00f3 m\u1ed9t s\u1ed1 ng\u01b0\u1eddi \u0111\u1ebfn th\u00eam n\u00ean s\u1ed1 g\u1ea1o ch\u1ec9 \u0111\u1ee7 \u0103n trong 30 ng\u00e0y. H\u1ecfi s\u1ed1 ng\u01b0\u1eddi \u0111\u1ebfn th\u00eam l\u00e0 bao nhi\u00eau? C\u00e2u 3. S\u1ed1 n\u00e0o \u0111i\u1ec1n v\u00e0o d\u1ea5u h\u1ecfi ch\u1ea5m? ?361 46 61 1 1 23 1 25023 C\u00e2u 4. C\u00f3 bao nhi\u00eau h\u00ecnh tam gi\u00e1c trong h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y? a.9 b.10","c.11 d.12 C\u00e2u 5. Th\u00e1ng v\u1eeba qua, b\u00e1c An v\u00e0 b\u00e1c Th\u1ecbnh \u0111\u00e3 l\u0129nh \u0111\u01b0\u1ee3c t\u1ea5t c\u1ea3 1.350.000\u0111 ti\u1ec1n l\u01b0\u01a1ng. B\u00e1c An \u0111\u00e3 l\u00e0m trong 24 ng\u00e0y, b\u00e1c Th\u1ecbnh l\u00e0m trong 21 ng\u00e0y. H\u1ecfi m\u1ed7i ng\u01b0\u1eddi chia \u0111\u01b0\u1ee3c bao nhi\u00eau ti\u1ec1n, bi\u1ebft r\u1eb1ng ti\u1ec1n c\u00f4ng m\u1ed7i ng\u00e0y c\u1ee7a hai b\u00e1c nh\u01b0 nhau. C\u00e2u 6. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o d\u1ea5u (?). 5, 6, 7, 8, 9, 10, 11, 12, ? C\u00e2u 7. Trong m\u1ed9t bu\u1ed5i lao \u0111\u1ed9ng, c\u00f4 gi\u00e1o ph\u00e2n c\u00f4ng m\u1ed9t n\u1eeda l\u1edbp l\u00e0m v\u01b0\u1eddn tr\u01b0\u1eddng, m\u1ed9t n\u1eeda l\u1edbp d\u1ecdn t\u1ee7 s\u00e1ch. Cu\u1ed1i bu\u1ed5i lao \u0111\u1ed9ng, s\u1ed1 h\u1ecdc sinh \u0111\u01b0\u1ee3c bi\u1ec3u d\u01b0\u01a1ng nhi\u1ec1u g\u1ea5p 6 l\u1ea7n s\u1ed1 h\u1ecdc sinh kh\u00f4ng \u0111\u01b0\u1ee3c bi\u1ec3u d\u01b0\u01a1ng. H\u1ecfi s\u1ed1 h\u1ecdc sinh \u0111\u01b0\u1ee3c bi\u1ec3u d\u01b0\u01a1ng c\u1ee7a l\u1edbp l\u00e0 bao nhi\u00eau, bi\u1ebft r\u1eb1ng l\u1edbp c\u00f3 t\u1eeb 40 \u0111\u1ebfn 50 h\u1ecdc sinh? C\u00e2u 8. L\u1edbp em chu\u1ea9n b\u1ecb di\u1ec5u h\u00e0nh 20 nam, 27 n\u1eef x\u1ebfp th\u00e0nh h\u00e0ng t\u01b0 X\u1ebfp xong, c\u00e1c b\u1ea1n c\u00f2n d\u01b0 C\u1ea7m c\u1edd \u0111i tr\u01b0\u1edbc oai nh\u01b0 anh h\u00f9ng Tr\u1ed1ng khua c\u1eafc c\u1eafc t\u00f9ng t\u00f9ng a. \u0110\u1ed1 ai, m\u1ea5y b\u1ea1n x\u1ebfp chung m\u1ed9t h\u00e0ng?","M\u1ed9t hai \u0111\u1ec1u b\u01b0\u1edbc nh\u1ecbp nh\u00e0ng b. C\u1ea7m c\u1edd m\u1ea5y b\u1ea1n hi\u00ean ngang d\u1eabn \u0111\u1ea7u?","C\u00e2u 1. T\u1eeb hai ch\u1eef s\u1ed1 t\u1ef1 nhi\u00ean trong c\u00e1c s\u1ed1: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 c\u00f3 bao nhi\u00eau c\u00e1ch vi\u1ebft th\u00e0nh m\u1ed9t s\u1ed1 nguy\u00ean d\u01b0\u01a1ng nh\u1ecf nh\u1ea5t? a. 1 c\u00e1ch b. 2 c\u00e1ch c. 3 c\u00e1ch d. Nhi\u1ec1u c\u00e1ch. C\u00e2u 2. Xe m\u1ed9t ch\u1edf 24 gh\u1ebf Xe hai ch\u1edf 36 gh\u1ebf Xe ba ch\u1edf m\u1ed9t s\u1ed1 b\u00e0n \u0110em \u0111\u1ebfn nh\u00e0 h\u00e0ng, b\u00e0n gh\u1ebf x\u1ebfp chung 1 b\u00e0n 4 gh\u1ebf k\u00ea c\u00f9ng Kh\u00f4ng d\u01b0, ch\u1eb3ng thi\u1ebfu, ung dung ra v\u1ec1 M\u1ed9t ng\u01b0\u1eddi ch\u1ea1y \u0111\u1ebfn: \\\"Khoan! \u00ca\\\" \\\"M\u1ea5y b\u00e0n, m\u1ea5y gh\u1ebf xin \u0111\u1ec1 gi\u1ea5y \u0111\u00e2y\\\"? \u0110\u1ed1 ai, ai bi\u1ebft, ai hay Ai hay, ai bi\u1ebft, ghi ngay kh\u00f3 g\u00ec.","C\u00e2u 3. M\u1ed9t ng\u01b0\u1eddi ch\u1ee7 \u0111\u00f3ng th\u00eam m\u1ed9t c\u1ed9t tr\u1ee5 \u1edf gi\u1eefa hai c\u1ed9t c\u1ee7a m\u1ed9t h\u00e0ng r\u00e0o th\u1eb3ng. N\u1ebfu \u00f4ng \u0111ang c\u00f3 10 c\u1ed9t \u1edf h\u00e0ng r\u00e0o th\u00ec \u00f4ng ph\u1ea3i \u0111\u00f3ng th\u00eam bao nhi\u00eau c\u1ed9t tr\u1ee5 n\u1eefa: a. 5 b. 9 c. 10 d. 20 C\u00e2u 4. C\u00f3 bao nhi\u00eau s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng b\u1eb1ng 5? C\u00e2u 5. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng: 6 | 9 | 12 | 15 | ? C\u00e2u 6. Trong k\u00ec thi tuy\u1ec3n v\u00e0o \u0111\u1ea1i h\u1ecdc, tr\u01b0\u1eddng \u0110\u1ea1i h\u1ecdc X tuy\u1ec3n 1.000 sinh vi\u00ean m\u1edbi. C\u00f3 t\u1ea5t c\u1ea3 24.000 th\u00ed sinh. B\u1ea1n Linh l\u00e0 m\u1ed9t trong 24.000 th\u00ed sinh \u0111\u00f3. H\u00e3y t\u00ednh gi\u00fap xem b\u1ea1n Linh ph\u1ea3i \u0111\u01b0\u01a1ng \u0111\u1ea7u v\u1edbi s\u1ed1 th\u00ed sinh theo t\u1ec9 l\u1ec7 bao nhi\u00eau \u0111\u1ec3 \u0111\u01b0\u1ee3c tr\u00fang tuy\u1ec3n? a. 1\/24 b. 1\/24.000 c. 1\/23.000 d. 1\/23","C\u00e2u 7. C\u00f3 10 ng\u01b0\u1eddi b\u01b0\u1edbc v\u00e0o ph\u00f2ng h\u1ecdp. T\u1ea5t c\u1ea3 \u0111\u1ec1u b\u1eaft tay l\u1eabn nhau. H\u1ecfi c\u00f3 bao nhi\u00eau c\u00e1i b\u1eaft tay?","B\u00e0i 34 C\u00e2u 1. H\u00ecnh n\u00e0o \u00edt gi\u1ed1ng v\u1edbi c\u00e1c h\u00ecnh c\u00f2n l\u1ea1i? C\u00e2u 2. N\u1ebfu (A - B) l\u1edbn h\u01a1n (A - C) th\u00ec C l\u1edbn h\u01a1n B \u0111\u00fang hay sai? C\u00e2u 3. C\u00f3 1 nh\u00f3m g\u1ed3m 10 nam v\u00e0 10 n\u1eef, h\u00e3y ch\u1ecdn 7 ng\u01b0\u1eddi sao cho trong s\u1ed1 \u0111\u00f3 c\u00f3 \u00edt nh\u1ea5t l\u00e0 3 nam v\u00e0 2 n\u1eef. C\u00e2u 4. D\u00f9ng 4 ch\u1eef s\u1ed1 0, 1, 2, 3 c\u00f3 th\u1ec3 vi\u1ebft \u0111\u01b0\u1ee3c bao nhi\u00eau s\u1ed1 c\u00f3 4 ch\u1eef s\u1ed1 kh\u00e1c nhau? C\u00e2u 5. T\u00ecm s\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng: 6248 4 4 5 11","736? C\u00e2u 6. D\u00f9ng ph\u00e9p t\u00ednh +, -, x, : t\u00f9y \u00fd v\u1edbi 8 con s\u1ed1 8 d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 1000: 88888888 C\u00e2u 7. H\u00ecnh n\u00e0o kh\u00f4ng theo quy lu\u1eadt so v\u1edbi c\u00e1c h\u00ecnh c\u00f2n l\u1ea1i? C\u00e2u 8. T\u00ecm ti\u1ebfp c\u00e1c ch\u1eef s\u1ed1 theo quy lu\u1eadt. XXOXXXXOOOXXXXXXXXOOOOOOOOXXXXXXXX XXXXXXXXOOOOOOOOOOOOOOOOOOOOXXXXXXX XXXXXXXXXXXXXXXXXXXXXXXXXOOOOOOOOOOOO","OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO O??????????","C\u00e2u 1. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 hai c\u00e1i l\u1ec1u \u0111\u01b0\u1ee3c d\u1ef1ng gi\u1eefa m\u1ed9t v\u00e0i c\u00e2y xanh \u1edf v\u00f9ng \u0111\u1ea5t c\u1ee7a ng\u01b0\u1eddi Anh \u0110i\u00eang (M\u1ef9). Trong b\u1ee9c tranh c\u00f2n thi\u1ebfu th\u1ee9 g\u00ec n\u1eefa? a. M\u1ed9t c\u00e2y to b. M\u1ed9t c\u00e2y nh\u1ecf c. M\u1ed9t c\u00e1i l\u1ec1u d. M\u1ed9t c\u00e1i l\u1ec1u h\u00ecnh n\u00f3n e. M\u1ed9t \u0111\u1ed1ng l\u1eeda f. Kh\u00f4ng c\u00f3 c\u00e1i g\u00ec c\u1ea3. C\u00e2u 2. S\u1ed1 n\u00e0o ti\u1ebfp theo chu\u1ed7i s\u1ed1 sau: 1, 3, 5, 7, 9, 11, 13, ? C\u00e2u 3. M\u1ed7i n\u1eef x\u1ebfp \u0111\u01b0\u1ee3c 10 sao Nam x\u1ebfp thua n\u1eef 3 sao m\u1ed7i ng\u01b0\u1eddi \u0110\u1ed1 vui v\u1eeba h\u1ecdc v\u1eeba c\u01b0\u1eddi Nam 19 ng\u01b0\u1eddi x\u1ebfp \u0111\u01b0\u1ee3c m\u1ea5y sao? Thi t\u00e0i th\u1eed s\u1ee9c th\u1ea5p cao","Ai \u0111\u00e1p nhanh ch\u00f3ng, m\u1eebng ch\u00e0o ph\u00e1o tay C\u00e2u 4. C\u00f3 bao nhi\u00eau h\u00ecnh vu\u00f4ng trong h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y: C\u00e2u 5. N\u1ebfu \u0111em s\u1ed1 k\u1eb9o c\u1ee7a m\u1eb9 chia \u0111\u1ec1u cho t\u1ea5t c\u1ea3 c\u00e1c con th\u00ec m\u1ed7i con \u0111\u01b0\u1ee3c 6 c\u00e1i. Nh\u01b0ng v\u00ec anh c\u1ea3 kh\u00f4ng \u0103n n\u00ean m\u1ed7i con \u0111\u01b0\u1ee3c 8 c\u00e1i. T\u00ednh s\u1ed1 con trong gia \u0111\u00ecnh v\u00e0 s\u1ed1 k\u1eb9o c\u1ee7a m\u1eb9? C\u00e2u 6. C\u00f3 3 c\u00f4 g\u00e1i: c\u00f4 \u0110en, c\u00f4 \u0110\u1ecf v\u00e0 c\u00f4 N\u00e2u g\u1eb7p nhau trong c\u1eeda hi\u1ec7u l\u00e0m t\u00f3c. M\u1ed9t ng\u01b0\u1eddi trong s\u1ed1 h\u1ecd n\u00f3i: \\\"T\u1edb c\u00f3 t\u00f3c \u0111en, hai c\u1eadu c\u00f3 t\u00f3c \u0111\u1ecf v\u00e0 n\u00e2u, nh\u01b0ng kh\u00f4ng ai trong ch\u00fang ta c\u00f3 m\u00e0u t\u00f3c tr\u00f9ng v\u1edbi t\u00ean c\u1ee7a m\u00ecnh\\\". C\u00f4 N\u00e2u \u0111\u00e1p: \\\"C\u1eadu ho\u00e0n to\u00e0n \u0111\u00fang\\\". V\u1eady, c\u00f4 \u0110\u1ecf t\u00f3c m\u00e0u g\u00ec? C\u00e2u 7. Trong m\u00f9a d\u01b0a h\u1ea5u, gia \u0111\u00ecnh \u00f4ng Hai L\u00faa thu ho\u1ea1ch \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 tr\u00e1i d\u01b0a h\u1ea5u. \u00d4ng Hai L\u00faa r\u1ea5t ng\u1ea1c nhi\u00ean khi th\u1ea5y t\u1ed5ng s\u1ed1 d\u01b0a h\u1ea5u chia"]