Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

["B\u00e0i 10\u00a0:C\u00f3 20 c\u00e1i b\u00e1nh chia \u0111\u1ec1u v\u00e0o 5 \u0111\u0129a. H\u1ecfi m\u1ed7i \u0111\u0129a c\u00f3 bao nhi\u00eau c\u00e1i b\u00e1nh? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 301","\u0110\u00c1P \u00c1N B. B\u00c0I T\u1eacP e Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u a b c d \u0110\u00e1p \u00e1n B C A C B\u00e0i 2: N\u1ed1i ( theo m\u1eabu ) : 21 32 27 30 18 10 B\u00e0i 3: . T\u00f4 m\u00e0u v\u00e0o s\u1ed1 \u00f4 vu\u00f4ng \u1edf m\u1ed7i h\u00ecnh : B\u00e0i 4: \u0110\u00fang ghi \u0110 ; sai ghi S : T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 21 dm ; 22 dm ; 23 dm v\u00e0 24 dm. a) 80 dm S b) 90 dm \u0110 To\u00e1n 2-1 Page 302","T\u00ecm x bi\u1ebft : b) \u0110 a) S d) \u0110 c) S Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : 4 \u00d7 5 : 2 = 20 : 2 B\u00e0i 1: T\u00ednh = 10 100 - 34 - 19 = 66 - 19 9 \u00d7 5 - 18 = 45 - 18 = 47 = 27 28cm + 45cm - 39cm = 73cm \u2013 39cm 50 : 5 + 70 = 10 + 70 = 34cm = 80 9l + 27l + 43l = 36l + 43l = 79l B\u00e0i 2: S\u1ed1? S\u1ed1 b\u1ecb chia 10 20 36 35 45 24 18 27 9 S\u1ed1 chia 2445533 3 Th\u01b0\u01a1ng 5597986 x : 4 = 28 : 4 x:4 =7 B\u00e0i 3: T\u00ecm x: x \u00d7 3 = 21 x:3 =8 x:4 =8: x = 21 : 3 x =8\u00d73 x2 x =7\u00d74 x + 3 = 21 + 9 x =7 x = 24 x =4 x = 28 x + 3 = 30 x =4\u00d7 4 x = 30 \u2013 3 = 16 x = 27 B\u00e0i 4: : \u0110i\u1ec1n d\u1ea5u \u00d7, +, - v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026.) (2 \u0111i\u1ec3m) 3\u00d73-4=5 7 + 2 + 9 = 18 9 \u00d7 3 + 8 = 35 6 \u00d7 5 - 15 = 15 B\u00e0i 5: \u00a0. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng : 15 12 : : 20 : 5 = 4 15 : 3 = 5 = = To\u00e1n 2-1 Page 303","34 B\u00e0i 6: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c bi\u1ebft \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 7 cm ; 8 cm v\u00e0 9 cm. B\u00e0i gi\u1ea3i Chu vi h\u00ecnh tam gi\u00e1c \u0111\u00f3 l\u00e0: 7 + 8 + 9 = 24 (cm) \u0110\u00e1p s\u1ed1: 24 cm B\u00e0i 7: B\u00e0i gi\u1ea3i Chu vi h\u00ecnh tam gi\u00e1c ABC l\u00e0: 3 + 5 + 7 = 15 (cm) \u0110\u00e1p s\u1ed1: 24 cm Chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3 l\u00e0: 3 + 5 + 5 + 6 = 19 (cm) \u0110\u00e1p s\u1ed1: 19 cm B\u00e0i 8: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 21 dm, 22 dm, 23 dm, 24 dm. Chu vi h\u00ecnh t\u1ee9 gi\u00e1c l\u00e0: 21 + 22 + 23 + 24 = 90 (dm) \u0110\u00e1p s\u1ed1: 90dm B\u00e0i 9: B\u00e1c An nu\u00f4i m\u1ed9t \u0111\u00e0n th\u1ecf .S\u1ed1 th\u1ecf n\u00e0y \u0111\u01b0\u1ee3c nh\u1ed1t v\u00e0o 8 chu\u1ed3ng , m\u1ed7i chu\u1ed3ng c\u00f3 4 con th\u1ecf . H\u1ecfi \u0111\u00e0n th\u1ecf \u0111\u00f3 bao nhi\u00eau con ? B\u00e0i gi\u1ea3i \u0110\u00e0n th\u1ecf \u0111\u00f3 c\u00f3 s\u1ed1 con l\u00e0: 8 \u00d7 4 = 32 (con) \u0110\u00e1p s\u1ed1: 32 con th\u1ecf B\u00e0i 10\u00a0:C\u00f3 20 c\u00e1i b\u00e1nh chia \u0111\u1ec1u v\u00e0o 5 \u0111\u0129a. H\u1ecfi m\u1ed7i \u0111\u0129a c\u00f3 bao nhi\u00eau c\u00e1i b\u00e1nh? B\u00e0i gi\u1ea3i M\u1ed7i \u0111\u0129a c\u00f3 s\u1ed1 c\u00e1i b\u00e1nh l\u00e0: 20 : 5 = 4 ( c\u00e1i) \u0110\u00e1p s\u1ed1: 4 c\u00e1i b\u00e1nh To\u00e1n 2-1 Page 304","To\u00e1n 2-1 Page 305","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N .1. S\u1ed1 1 trong ph\u00e9p nh\u00e2n, ph\u00e9p chia - S\u1ed1 1 nh\u00e2n v\u1edbi s\u1ed1 n\u00e0o c\u0169ng b\u1eb1ng ch\u00ednh s\u1ed1 \u0111\u00f3. V\u00ed d\u1ee5: 1 2 = 2 1 3=3 1 4=4 - S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 1 c\u0169ng b\u1eb1ng ch\u00ednh s\u1ed1 \u0111\u00f3. 2 1=2 4 1=4 3 1=3 5 1=5 2. S\u1ed1 0 trong ph\u00e9p nh\u00e2n, ph\u00e9p chia - S\u1ed1 0 nh\u00e2n v\u1edbi s\u1ed1 n\u00e0o c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5: 0 2 = 0 0 3=0 - S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5: 2 0 = 0 3 0=0 - S\u1ed1 0 chia cho s\u1ed1 n\u00e0o kh\u00e1c 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5: 0 : 2 = 0 0:3=0 L\u01b0u \u00fd: Kh\u00f4ng c\u00f3 ph\u00e9p chia cho 0. B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: a. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh 5 \u00d7 2 \u00d7 3 l\u00e0: A. 30 B. 40 C. 20 b. M\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0 MN = 6 cm, NP = 13 cm, PQ = 11 cm; QM = 10cm. Chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3 l\u00e0: A. 30cm B. 40cm C. 50cm c. T\u00ecm 1 s\u1ed1 m\u00e0 khi nh\u00e2n s\u1ed1 \u0111\u00f3 v\u1edbi b\u1ea5t k\u00ec s\u1ed1 t\u1ef1 nhi\u00ean n\u00e0o ta c\u0169ng nh\u1eadn \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 0. S\u1ed1 \u0111\u00f3 l\u00e0: A. 0 B. 1 C. 10 d. C\u00f3 12 qu\u1ea3 cam, m\u1eb9 \u0111\u1ec3 \u0111\u1ec1u v\u00e0o 4 \u0111\u0129a. H\u1ecfi m\u1ed7i \u0111\u0129a c\u00f3 bao nhi\u00eau qu\u1ea3 cam? A. 8 qu\u1ea3 cam B. 16 qu\u1ea3 cam C. 3 qu\u1ea3 cam To\u00e1n 2-1 Page 306","B\u00e0i 2: a. S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 1 c\u0169ng b\u1eb1ng 1. V\u00ed d\u1ee5: ......................................... b. S\u1ed1 n\u00e0o chia cho 1 c\u0169ng b\u1eb1ng ch\u00ednh s\u1ed1 \u0111\u00f3. V\u00ed d\u1ee5 ......................... c. S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5: ...................................... d. S\u00f3 n\u00e0o nh\u00e2n v\u1edbi 0 c\u0169ng b\u1eb1ng ch\u00ednh n\u00f3. V\u00ed d\u1ee5 ............................ e. S\u1ed1 0 chia cho s\u1ed1 n\u00e0o c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5 ................................ f. S\u1ed1 0 chia cho s\u1ed1 n\u00e0o kh\u00e1c 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5....................... B\u00e0i 3: S\u1ed1? ............ \u00d7 5 = 0 6 : ............ = 6 ................... : 1 = 1 .....: 10 \u00d7 5 = 0 10 \u00d7 .......\u00d7 5 = 0 15 : 5 \u00d7 5 \u00d7 ..... = 0 8 \u00d7 ...... : 5 = 0 6 \u00d7 3 \u00d7 ........= 0 B\u00e0i 4: N\u1ed1i ( theo m\u1eabu ) . T\u00ecm x : 8 20 10 6 12 15 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: T\u00ednh 3\u00d72:1 3:1\u00d72 8\u00d70:1 5 \u00d7 4: 1 6\u00d70:6 8:2\u00d71 ................... ................... ................... ................... ................... ................... ................... ................... ................... ................... ................... ................... B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng. S\u1ed1 b\u1ecb chia 12 24 15 35 40 S\u1ed1 chia 44 3 5 4 44 Th\u01b0\u01a1ng 98 To\u00e1n 2-1 Page 307","B\u00e0i 3: T\u00ecm x: x : 3 = 45 : 5 ............................... x:2=5\u00d72 ................................ ............................... ................................ x:5=3\u00d73 x:4=3\u00d72 ............................... ............................... ................................... ................................ B\u00e0i 4: : \u0110i\u1ec1n d\u1ea5u > , <, = v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026.) 19 cm + 50 cm \u2026. 6dm 10dm \u2026. 35cm + 53 cm 50 cm \u00d7 2 \u2026.. 10dm 20cm \u00d7 4 \u2026. 9 dm B\u00e0i 5: \u00a0\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng. a) 1ng\u00e0y =\u2026\u2026\u2026\u2026gi\u1edd b*) ng\u00e0y = ...... gi\u1edd 1gi\u1edd = \u2026\u2026\u2026..ph\u00fat ng\u00e0y = ...... gi\u1edd 1ph\u00fat =\u2026\u2026..gi\u00e2y 1tu\u1ea7n = \u2026.ng\u00e0y B\u00e0i 6: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c ABC bi\u1ebft \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0 : 15 cm , 27 cm , 28 cm. B\u00e0i gi\u1ea3i B\u00e0i 7: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c MNPQ bi\u1ebft \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0 : 18 dm, 23 dm, 25 dm, 34 dm. B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 308","B\u00e0i 8: C\u00f3 m\u1ed9t s\u1ed1 b\u00fat ch\u00ec chia v\u00e0o 10 h\u1ed9p , m\u1ed7i h\u1ed9p c\u00f3 5 b\u00fat ch\u00ec . H\u1ecfi c\u00f3 t\u1ea5t c\u1ea9 bao nhi\u00eau b\u00fat ch\u00ec ? B\u00e0i gi\u1ea3i B\u00e0i 9: M\u1ed9t thanh s\u1eaft \u0111\u01b0\u1ee3c u\u1ed1n th\u00e0nh h\u00ecnh vu\u00f4ng (nh\u01b0 h\u00ecnh v\u1ebd). H\u00e3y t\u00ednh \u0111\u1ed9 d\u00e0i thanh s\u1eaft \u0111\u00f3. B\u00e0i gi\u1ea3i: 20 cm \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026............. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 10\u00a0: C\u00f3 18 b\u00f4ng hoa, m\u1ed7i l\u1ecd c\u1eafm 6 b\u00f4ng hoa. H\u1ecfi c\u1ea7n bao nhi\u00eau l\u1ecd \u0111\u1ec3 c\u1eafm h\u1ebft s\u1ed1 hoa \u0111\u00f3? To\u00e1n 2-1 Page 309","B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 310","\u0110\u00c1P \u00c1N B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u s\u1ed1 abc d C \u0110\u00e1p \u00e1n ABA S cB\u00e0i 2: a. S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 1 c\u0169ng b\u1eb1ng 1. V\u00ed d\u1ee5: ......................................... b. S\u1ed1 n\u00e0o chia cho 1 c\u0169ng b\u1eb1ng ch\u00ednh s\u1ed1 \u0111\u00f3. V\u00ed d\u1ee5 5 : 1 = 5 \u0110 c. S\u1ed1 n\u00e0o nh\u00e2n v\u1edbi 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5: 0 \u00d7 3 = 0 \u0110 d. S\u00f3 n\u00e0o nh\u00e2n v\u1edbi 0 c\u0169ng b\u1eb1ng ch\u00ednh n\u00f3. V\u00ed d\u1ee5 ............................ S e. S\u1ed1 0 chia cho s\u1ed1 n\u00e0o c\u0169ng b\u1eb1ng 0. S f. S\u1ed1 0 chia cho s\u1ed1 n\u00e0o kh\u00e1c 0 c\u0169ng b\u1eb1ng 0. V\u00ed d\u1ee5 0 : 3 = 0 \u0110 B\u00e0i 3: S\u1ed1? 0\u00d75=0 6:1=6 1:1=1 0 : 10 \u00d7 5 = 0 8\u00d70:5=0 6\u00d73\u00d70=0 10 \u00d7 0 \u00d7 5 = 0 15 : 5 \u00d7 5 \u00d7 0 = 0 B\u00e0i 4: N\u1ed1i ( theo m\u1eabu ) . T\u00ecm x : 8 20 10 6 12 15 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: T\u00ednh 3\u00d72:1 3:1\u00d72 8\u00d70:1 5 \u00d7 4: 1 6\u00d70:6 8:2\u00d71 =6:1=6 = 20 : 1 = 20 =0:6=0 =4\u00d71=4 = 3 \u00d7 2 = 6 = 0 : 1= 0 To\u00e1n 2-1 Page 311","B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng. S\u1ed1 b\u1ecb chia 12 24 15 35 40 36 32 5 4 44 S\u1ed1 chia 44 3 7 10 9 8 Th\u01b0\u01a1ng 36 5 x : 3 = 45 : 5 x:3 =9 B\u00e0i 3: T\u00ecm x: x:2 =5\u00d72 x =9\u00d73 x : 2 =10 x = 27 x = 10 : 2 x =5 x:4 =3\u00d72 x:5 =3\u00d73 x:4 =6 x: 5 = 9 x =6\u00d74 x =9\u00d75 x = 24 x = 45 B\u00e0i 4: : \u0110i\u1ec1n d\u1ea5u > , <, = v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026.) 19 cm + 50 cm > 6dm 10dm > 35cm + 53 cm 50 cm \u00d7 2 = 10dm 20cm \u00d7 4 < 9 dm B\u00e0i 5: \u00a0\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng. a) 1ng\u00e0y = 24gi\u1edd b*) ng\u00e0y = 8 gi\u1edd 1gi\u1edd = 60ph\u00fat ng\u00e0y = 6 gi\u1edd 1ph\u00fat = 60gi\u00e2y 1tu\u1ea7n = 7 ng\u00e0y B\u00e0i 6: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c ABC bi\u1ebft \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0 : 15 cm , 27 cm , 28 cm. B\u00e0i gi\u1ea3i Chu vi h\u00ecnh tam gi\u00e1c ABC l\u00e0: 15 + 27 + 28 = 70 ( cm) To\u00e1n 2-1 Page 312","\u0110\u00e1p s\u1ed1: 70cm B\u00e0i 7: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c MNPQ bi\u1ebft \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0 : 18 dm, 23 dm, 25 dm, 34 dm. B\u00e0i gi\u1ea3i Chu vi h\u00ecnh t\u1ee9 gi\u00e1c MNPQ l\u00e0: 18 + 23 + 25 + 34 = 100 ( dm) \u0110\u00e1p s\u1ed1: 100dm B\u00e0i 8: C\u00f3 m\u1ed9t s\u1ed1 b\u00fat ch\u00ec chia v\u00e0o 10 h\u1ed9p , m\u1ed7i h\u1ed9p c\u00f3 5 b\u00fat ch\u00ec . H\u1ecfi c\u00f3 t\u1ea5t c\u1ea9 bao nhi\u00eau b\u00fat ch\u00ec ? B\u00e0i gi\u1ea3i C\u00f3 t\u1ea5t c\u1ea3 s\u1ed1 b\u00fat ch\u00ec l\u00e0: 10 \u00d7 5 = 50 ( b\u00fat) \u0110\u00e1p s\u1ed1: 50 b\u00fat ch\u00ec B\u00e0i 9: M\u1ed9t thanh s\u1eaft \u0111\u01b0\u1ee3c u\u1ed1n th\u00e0nh h\u00ecnh vu\u00f4ng (nh\u01b0 h\u00ecnh v\u1ebd).H\u00e3y t\u00ednh \u0111\u1ed9 d\u00e0i thanh s\u1eaft \u0111\u00f3. B\u00e0i gi\u1ea3i \u0110\u1ed9 d\u00e0i thanh s\u1eaft \u0111\u00f3 l\u00e0: 20 + 20 + 20+ 20 = 80 ( cm) \u0110\u00e1p s\u1ed1: 100cm B\u00e0i 10\u00a0: C\u00f3 18 b\u00f4ng hoa, m\u1ed7i l\u1ecd c\u1eafm 6 b\u00f4ng hoa. H\u1ecfi c\u1ea7n bao nhi\u00eau l\u1ecd \u0111\u1ec3 c\u1eafm h\u1ebft s\u1ed1 hoa \u0111\u00f3? B\u00e0i gi\u1ea3i C\u1ea7n s\u1ed1 l\u1ecd \u0111\u1ec3 \u0111\u1ec3 c\u1eafm h\u1ebft s\u1ed1 hoa \u0111\u00f3: 18 : 6= 3 ( l\u1ecd hoa) \u0110\u00e1p s\u1ed1: 3 l\u1ecd hoa To\u00e1n 2-1 Page 313","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp:\u2026\u2026. A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N .1. \u0110\u01a1n v\u1ecb, ch\u1ee5c, tr\u0103m, ngh\u00ecn + 1 ch\u1ee5c b\u1eb1ng 10 \u0111\u01a1n v\u1ecb. + 1 tr\u0103m b\u1eb1ng 10 ch\u1ee5c. 2 tr\u0103m b\u1eb1ng 20 ch\u1ee5c. \u0110\u1ec3 ch\u1ec9 s\u1ed1 l\u01b0\u1ee3ng l\u00e0 2 tr\u0103m, ng\u01b0\u1eddi ta d\u00f9ng s\u1ed1 2 tr\u0103m, vi\u1ebft l\u00e0 200. C\u00e1c s\u1ed1 100, 200, 300, \u2026 900 l\u00e0 c\u00e1c s\u1ed1 tr\u00f2n tr\u0103m. + 1 ngh\u00ecn b\u1eb1ng 10 tr\u0103m. \u0110\u1ec3 ch\u1ec9 s\u1ed1 l\u01b0\u1ee3ng l\u00e0 1 ngh\u00ecn, ng\u01b0\u1eddi ta d\u00f9ng s\u1ed1 1 ngh\u00ecn, vi\u1ebft l\u00e0 1000. 3. So s\u00e1nh c\u00e1c s\u1ed1 tr\u00f2n tr\u0103m Khi so s\u00e1nh c\u00e1c s\u1ed1 tr\u00f2n tr\u0103m ta ch\u1ec9 c\u1ea7n so s\u00e1nh ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m v\u1edbi nhau m\u00e0 kh\u00f4ng c\u1ea7n so s\u00e1nh c\u00e1c ch\u1eef s\u1ed1 \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb v\u00e0 h\u00e0ng ch\u1ee5c. S\u1ed1 n\u00e0o c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m l\u1edbn h\u01a1n th\u00ec s\u1ed1 \u0111\u00f3 l\u1edbn h\u01a1n, s\u1ed1 n\u00e0o c\u00f3 ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m b\u00e9 h\u01a1n th\u00ec s\u1ed1 \u0111\u00f3 b\u00e9 h\u01a1n. V\u00ed d\u1ee5: So s\u00e1nh 200 v\u00e0 300 + Ta so s\u00e1nh c\u00e1c ch\u1eef s\u1ed1 h\u00e0ng tr\u0103m, v\u00ec 2 < 3 n\u00ean 200 < 300 hay 300 > 200 - L\u01b0u \u00fd: So s\u00e1nh l\u1ea7n l\u01b0\u1ee3t c\u00e1c ch\u1eef s\u1ed1 t\u1eeb h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb. 4. C\u00e1c s\u1ed1 tr\u00f2n ch\u1ee5c t\u1eeb 110 \u0111\u1ebfn 200 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 11 0 110 M\u1ed9t tr\u0103m m\u01b0\u1eddi 12 0 120 M\u1ed9t tr\u0103m hai m\u01b0\u01a1i 13 0 130 M\u1ed9t tr\u0103m ba m\u01b0\u01a1i 14 0 140 M\u1ed9t tr\u0103m b\u1ed1n m\u01b0\u01a1i 15 0 150 M\u1ed9t tr\u0103m n\u0103m m\u01b0\u01a1i 16 0 160 M\u1ed9t tr\u0103m s\u00e1u m\u01b0\u01a1i 17 0 170 M\u1ed9t tr\u0103m b\u1ea3y m\u01b0\u01a1i 18 0 180 M\u1ed9t tr\u0103m t\u00e1m m\u01b0\u01a1i 19 0 190 M\u1ed9t tr\u0103m ch\u00edn m\u01b0\u01a1i 20 0 200 Hai tr\u0103m To\u00e1n 2-1 Page 314","4. C\u00e1c s\u1ed1 tr\u00f2n ch\u1ee5c t\u1eeb 101 \u0111\u1ebfn 110 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 10 1 101 M\u1ed9t tr\u0103m linh m\u1ed9t 10 2 102 M\u1ed9t tr\u0103m linh hai 10 3 103 M\u1ed9t tr\u0103m linh ba 10 4 104 M\u1ed9t tr\u0103m linh t\u01b0 10 5 105 M\u1ed9t tr\u0103m linh n\u0103m 10 6 106 M\u1ed9t tr\u0103m linh s\u00e1u 10 7 107 M\u1ed9t tr\u0103m linh b\u1ea3y 10 8 108 M\u1ed9t tr\u0103m linh t\u00e1m 10 9 109 M\u1ed9t tr\u0103m linh ch\u00edn 11 0 110 M\u1ed9t tr\u0103m m\u01b0\u1eddi B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: a. Khoanh tr\u00f2n v\u00e0o s\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1 \u0111\u00e3 cho? 128; 281; 182; 821; 218; 812 b. G\u1ea1ch ch\u00e2n d\u01b0\u1edbi s\u1ed1 b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1 \u0111\u00e3 cho 427; 494; 471; 426; 491 c. Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: 1. H\u00ecnh n\u00e0o \u0111\u00e3 t\u00f4 m\u00e0u m\u1ed9t ph\u1ea7n hai h\u00ecnh: A B C 2. S\u1ed1 105 \u0111\u1ecdc l\u00e0 B. M\u1ed9t tr\u0103m linh l\u0103m C. M\u1ed9t tr\u0103m A. M\u1ed9t linh n\u0103m linh n\u0103m To\u00e1n 2-1 Page 315","3. T\u00ecm a bi\u1ebft : a : 2 = 5 \u00d7 2. a l\u00e0: A. 5 B. 10 C. 20 B\u00e0i 2: : S\u1ed1? \u00d72=2 8\u00d71: =4 5: =5 :1x1=6 28 : = 7 3\u00d7 :2=9 B\u00e0i 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m 110 120 150 200 B\u00e0i 4: N\u1ed1i c\u00e1c s\u1ed1 \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u00e1ch \u0111\u1ecdc t\u01b0\u01a1ng \u1ee9ng \u1edf c\u1ed9t b\u00ean ph\u1ea3i 200 Ba tr\u0103m 300 M\u1ed9t tr\u0103m linh n\u0103m 160 Hai tr\u0103m 105 M\u1ed9t tr\u0103m s\u00e1u m\u01b0\u01a1i 140 M\u1ed9t tr\u0103m b\u1ed1n m\u01b0\u01a1i Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: a)\u0110\u1ecdc c\u00e1c s\u1ed1 sau: 100 : ...................................................................... 109: ......................................................................... 500: ....................................................................... 110: ......................................................................... 104: ....................................................................... 1000: ......................................................................... b) Vi\u1ebft c\u00e1c s\u1ed1 sau: - M\u1ed9t tr\u0103m n\u0103m m\u01b0\u01a1i:............................... - B\u1ed1n tr\u0103m:................................................ - S\u1ed1 g\u1ed3m 3 tr\u0103m, 2 ch\u1ee5c v\u00e0 0 \u0111\u01a1n v\u1ecb:............................................................ - S\u1ed1 g\u1ed3m 5 tr\u0103m, 0 ch\u1ee5c, 0 \u0111\u01a1n v\u1ecb:................................................................... - M\u1ed9t tr\u0103m linh hai:....................................................................... B\u00e0i 2: \u0110i\u1ec1n d\u1ea5u <, >, = v\u00e0o ch\u1ed7 ch\u1ea5m: a. 230 ......... 410 b. 200 .......... 300 To\u00e1n 2-1 Page 316","230 ......... 240 500 ........ 100 180 ......... 150 400 ........ 700 B\u00e0i 3: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: S\u1ed1 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb \u0110\u1ecdc s\u1ed1 105 11 0 150 200 M\u1ed9t tr\u0103m linh t\u00e1m B\u00e0i 4: : a) S\u1ed1 tr\u00f2n tr\u0103m nh\u1ecf nh\u1ea5t l\u00e0 : ..... b) S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t v\u00e0 nh\u1ecf h\u01a1n 1000 l\u00e0 : ........... c) S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn h\u01a1n 500 v\u00e0 nh\u1ecf h\u01a1n 1000 l\u00e0: ......................................................................... B\u00e0i 5: \u00a0X\u1ebfp c\u00e1c s\u1ed1 sau theo tr\u1eadt t\u1ef1 t\u1eeb nh\u1ecf \u0111\u1ebfn l\u1edbn: 1000; 300; 900; 100; 200; 400; 700; 500; 600; 800. B\u00e0i 6: Vi\u1ebft c\u00e1c s\u1ed1 t\u1eeb 101 \u0111\u1ebfn 110 theo th\u1ee9 t\u1ef1 gi\u1ea3m d\u1ea7n. B\u00e0i 7: T\u00ecm x: b) 3 \u00d7 x = 12 a) x \u00d7 2 = 12 \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. d) x : 7 = 3 c) x : 3 = 5 \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. Page 317 To\u00e1n 2-1","B\u00e0i 8: C\u00f3 30 quy\u1ec3n v\u1edf th\u01b0\u1edfng cho h\u1ecdc sinh, m\u1ed7i h\u1ecdc sinh \u0111\u01b0\u1ee3c th\u01b0\u1edfng 3 quy\u1ec3n. H\u1ecfi c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau h\u1ecdc sinh? B\u00e0i gi\u1ea3i B\u00e0i 9: T\u00ednh chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD bi\u1ebft s\u1ed1 \u0111o c\u00e1c c\u1ea1nh nh\u01b0 h\u00ecnh v\u1ebd: 9cm D A 5cm 8cm B C 1dm B\u00e0i gi\u1ea3i B\u00e0i 10\u00a0:Ng\u01b0\u1eddi b\u00e1n h\u00e0ng \u0111\u1ed5 l\u1ea1c v\u00e0o c\u00e1c t\u00fai ,m\u1ed7i t\u00fai 3 kg l\u1ea1c. H\u1ecfi c\u00f3 15 kg l\u1ea1c th\u00ec \u0111\u1ed5 \u0111\u01b0\u1ee3c v\u00e0o bao nhi\u00eau t\u00fai nh\u01b0 th\u1ebf? To\u00e1n 2-1 Page 318","B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 319","\u0110\u00c1P \u00c1N B\u00e0i 1: a. Khoanh tr\u00f2n v\u00e0o s\u1ed1 l\u1edbn nh\u1ea5t trong c\u00e1c s\u1ed1 \u0111\u00e3 cho? 128; 281; 182; ; 218; 812 b. G\u1ea1ch ch\u00e2n d\u01b0\u1edbi s\u1ed1 b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1 \u0111\u00e3 cho 427; 494; 471; 426; 491 c. Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 C \u0110\u00e1p \u00e1n B C B\u00e0i 2: : S\u1ed1? 1 \u00d72=2 8\u00d71:2=4 5: 1 =5 6:1x1=6 28 : 4 = 7 3\u00d76:2=9 B\u00e0i 3: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m 200 110 120 130 140 150 160 170 180 190 B\u00e0i 4: N\u1ed1i c\u00e1c s\u1ed1 \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u00e1ch \u0111\u1ecdc t\u01b0\u01a1ng \u1ee9ng \u1edf c\u1ed9t b\u00ean ph\u1ea3i 200 Ba tr\u0103m 300 M\u1ed9t tr\u0103m linh n\u0103m 160 Hai tr\u0103m 105 M\u1ed9t tr\u0103m s\u00e1u m\u01b0\u01a1i 140 M\u1ed9t tr\u0103m b\u1ed1n m\u01b0\u01a1i Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: a)\u0110\u1ecdc c\u00e1c s\u1ed1 sau: 100 : M\u1ed9t tr\u0103m 109: M\u1ed9t tr\u0103m linh ch\u00edn 500: N\u0103m tr\u0103m 110: M\u1ed9t tr\u0103m m\u01b0\u1eddi To\u00e1n 2-1 Page 320","104: M\u1ed9t tr\u0103m linh t\u01b0 1000: M\u1ed9t ngh\u00ecn b) Vi\u1ebft c\u00e1c s\u1ed1 sau: - M\u1ed9t tr\u0103m n\u0103m m\u01b0\u01a1i: 150 - B\u1ed1n tr\u0103m: 400 - S\u1ed1 g\u1ed3m 3 tr\u0103m, 2 ch\u1ee5c v\u00e0 0 \u0111\u01a1n v\u1ecb: 320 - S\u1ed1 g\u1ed3m 5 tr\u0103m, 0 ch\u1ee5c, 0 \u0111\u01a1n v\u1ecb: 500 - M\u1ed9t tr\u0103m linh hai: 102 B\u00e0i 2: \u0110i\u1ec1n d\u1ea5u <, >, = v\u00e0o ch\u1ed7 ch\u1ea5m: a. 230 < 410 b. 200 < 300 230 < 240 500 > 100 180 > 150 400 < 700 B\u00e0i 3: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: S\u1ed1 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb \u0110\u1ecdc s\u1ed1 105 05 M\u1ed9t tr\u0103m linh n\u0103m 1 110 1 1 0 M\u1ed9t tr\u0103m m\u01b0\u1eddi 150 1 5 0 M\u1ed9t tr\u0103m n\u0103m m\u01b0\u01a1i 200 2 0 0 Hai tr\u0103m 108 1 0 8 M\u1ed9t tr\u0103m linh t\u00e1m B\u00e0i 4: : a) S\u1ed1 tr\u00f2n tr\u0103m nh\u1ecf nh\u1ea5t l\u00e0 : 100 b) S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t v\u00e0 nh\u1ecf h\u01a1n 1000 l\u00e0 : 900 c) S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn h\u01a1n 500 v\u00e0 nh\u1ecf h\u01a1n 1000 l\u00e0: 600, 700, 800, 900 B\u00e0i 5: \u00a0X\u1ebfp c\u00e1c s\u1ed1 sau theo tr\u1eadt t\u1ef1 t\u1eeb nh\u1ecf \u0111\u1ebfn l\u1edbn: 1000; 300; 900; 100; 200; 400; 700; 500; 600; 800. 100, 200, 300, 400, 500, 600, 700 B\u00e0i 6: Vi\u1ebft c\u00e1c s\u1ed1 t\u1eeb 101 \u0111\u1ebfn 110 theo th\u1ee9 t\u1ef1 gi\u1ea3m d\u1ea7n. 110, 109, 108, 107, 106, 105, 104, 103, 102, 101 B\u00e0i 7: T\u00ecm x: a) x \u00d7 2 = 12 b) 3 \u00d7 x = 12 x = 12 : 2 x = 12 : 3 x =6 x =4 c) x : 3 = 5 d) x : 7 = 3 To\u00e1n 2-1 Page 321","x =5\u00d73 x =3\u00d77 x = 15 x = 21 B\u00e0i 8: C\u00f3 30 quy\u1ec3n v\u1edf th\u01b0\u1edfng cho h\u1ecdc sinh, m\u1ed7i h\u1ecdc sinh \u0111\u01b0\u1ee3c th\u01b0\u1edfng 3 quy\u1ec3n. H\u1ecfi c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau h\u1ecdc sinh? B\u00e0i gi\u1ea3i C\u00f3 s\u1ed1 h\u1ecdc sinh \u0111\u01b0\u1ee3c th\u01b0\u1edfng v\u1edf l\u00e0: 30 : 3 = 10 ( h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 10 h\u1ecdc sinh B\u00e0i 9: T\u00ednh chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD bi\u1ebft s\u1ed1 \u0111o c\u00e1c c\u1ea1nh nh\u01b0 h\u00ecnh v\u1ebd: 9cm D A 5cm 8cm BC 1dm B\u00e0i gi\u1ea3i \u0110\u1ed5i 1dm = 10 cm Chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0: 5 + 9 + 8 + 10 = 32 (cm) \u0110\u00e1p s\u1ed1: 32 cm B\u00e0i 10\u00a0:Ng\u01b0\u1eddi b\u00e1n h\u00e0ng \u0111\u1ed5 l\u1ea1c v\u00e0o c\u00e1c t\u00fai ,m\u1ed7i t\u00fai 3 kg l\u1ea1c. H\u1ecfi c\u00f3 15 kg l\u1ea1c th\u00ec \u0111\u1ed5 \u0111\u01b0\u1ee3c v\u00e0o bao nhi\u00eau t\u00fai nh\u01b0 th\u1ebf? B\u00e0i gi\u1ea3i C\u00f3 15kg l\u1ea1c th\u00ec \u0111\u1ed5 \u0111\u01b0\u1ee3c v\u00e0o s\u1ed1 t\u00fai nh\u01b0 th\u1ebf l\u00e0: 15 : 3 = 5 (t\u00fai) \u0110\u00e1p s\u1ed1: 5 t\u00fai To\u00e1n 2-1 Page 322","M\u1ed8T S\u1ed0 \u0110\u1ec0 TO\u00c1N \u00d4N T\u1eacP GI\u1eeeA K\u00cc II \u0110\u1ec0 S\u1ed0 1 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: 1. (0,5\u0111) H\u00ecnh n\u00e0o \u0111\u00e3 t\u00f4 m\u00e0u s\u1ed1 \u00f4 vu\u00f4ng trong nh\u1eefng h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y: A. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 2.\u00a0(0,5\u0111) S\u1ed1 ch\u1eb5n li\u1ec1n sau 96 l\u00e0: A. 98\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 94\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 100\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 96 3. (0,5\u0111) K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh:\u00a0\u00a0 86 \u2013 38 + 19 l\u00e0: A. 57\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 79\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 87\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 67 4.\u00a0(0,5\u0111) Ng\u00e0y 12 th\u00e1ng 1 n\u0103m 2020 l\u00e0 ch\u1ee7 nh\u1eadt tu\u1ea7n n\u00e0y. H\u1ecfi th\u1ee9 b\u1ea3y tu\u1ea7n sau l\u00e0 ng\u00e0y n\u00e0o? A. 20\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 19\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 18\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 17 5.\u00a0(1\u0111) Trong m\u1ed9t ph\u00e9p tr\u1eeb, khi ta c\u00f9ng th\u00eam 5 \u0111\u01a1n v\u1ecb v\u00e0o s\u1ed1 b\u1ecb tr\u1eeb v\u00e0 s\u1ed1 tr\u1eeb th\u00ec hi\u1ec7u s\u1ebd thay \u0111\u1ed5i nh\u01b0 th\u1ebf n\u00e0o? A.\u00a0Hi\u1ec7u gi\u1ea3m 5 \u0111\u01a1n v\u1ecb.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. Hi\u1ec7u t\u0103ng l\u00ean 5 \u0111\u01a1n v\u1ecb\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. Hi\u1ec7u kh\u00f4ng \u0111\u1ed5i. 6.\u00a0\u00a0(0,5\u0111) 3 \u0111\u01b0\u1ee3c l\u1ea5y 5 l\u1ea7n, ta \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh n\u00e0o \u0111\u00fang nh\u1ea5t\u00a0: A.\u00a05x 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 3+ 5\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3 x 5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 5 + 5 +\u00a05\u00a0\u00a0 7. (0,5\u0111)\u00a0 M\u1ed9t con ch\u00f3 c\u00f3 4 c\u00e1i ch\u00e2n, m\u1ed9t con g\u00e0 c\u00f3 2 c\u00e1i ch\u00e2n. V\u1eady hai con ch\u00f3 v\u00e0 ba con g\u00e0 c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau c\u00e1i ch\u00e2n\u00a0? A. 20\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 14\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 16\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 18 PH\u1ea6N II. T\u1ef0 LU\u1eacN B\u00e0i 1.\u00a0\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh (2\u0111) 36 + 45 73 \u2013 39 45 + 44 88 \u2013 79 \u2026......................\u2026 \u2026......................\u2026 \u2026......................\u2026 \u2026......................\u2026 ..\u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026... \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 2. T\u00ecm x: (1\u0111)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 a. x + 37 = 63 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b. 5 x 7 = x + 19 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 3.\u00a0\u00a0Gi\u1ea3i to\u00e1n: (2\u0111) uNg\u00e0y 8 th\u00e1ng 3, c\u00e1c b\u1ea1n nam trong t\u1ed5 \u0111\u00e3 chu\u1ea9n b\u1ecb m\u1ed9t s\u1ed1 hoa t\u1eb7ng cho 4 b\u1ea1n n\u1eef trong t\u1ed5, m\u1ed7i b\u1ea1n n\u1eef \u0111\u01b0\u1ee3c nh\u1eadn 3 b\u00f4ng hoa. H\u1ecfi c\u00e1c b\u1ea1n nam c\u1ea7n chu\u1ea9n b\u1ecb bao nhi\u00eau b\u00f4ng hoa? 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B\u00e0i 5.\u00a0\u00a0(1\u0111) \u0110\u01b0\u1eddng g\u1ea5p kh\u00fac MNPQ c\u00f3 MN d\u00e0i 3dm. \u0110o\u1ea1n MN d\u00e0i h\u01a1n \u0111o\u1ea1n NP l\u00e0 12cm v\u00e0 d\u00e0i h\u01a1n \u0111o\u1ea1n PQ l\u00e0 18cm. T\u00ednh: a. \u0110\u1ed9 d\u00e0i c\u00e1c \u0111o\u1ea1n th\u1eb3ng NP v\u00e0 PQ. b. \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac MNPQ. 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To\u00e1n 2-1 Page 324","\u0110\u1ec0 S\u1ed0 2 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u d\u01b0\u1edbi \u0111\u00e2y 1. (0,5 \u0111) S\u1ed1 65 \u0111\u1ecdc l\u00e0: A. S\u00e1u m\u01b0\u01a1i n\u0103m B. N\u0103m m\u01b0\u01a1i s\u00e1u C. S\u00e1u m\u01b0\u01a1i l\u0103m D. S\u00e1u n\u0103m 2. (1 \u0111) C\u00f3 15 c\u00e1i k\u1eb9o chia \u0111\u1ec1u cho 3 b\u1ea1n. H\u1ecfi m\u1ed7i b\u1ea1n c\u00f3 m\u1ea5y c\u00e1i k\u1eb9o? A. 5 c\u00e1i k\u1eb9o. B. 6 c\u00e1i k\u1eb9o . C. 7 c\u00e1i k\u1eb9o. D. 8 c\u00e1i k\u1eb9o. 3. (0,5 \u0111) Cho ph\u00e9p nh\u00e2n 2 x 4 = 8. Em h\u00e3y khoanh v\u00e0o ph\u00e9p chia th\u00edch h\u1ee3p d\u01b0\u1edbi \u0111\u00e2y: A. 2 : 4 = 8. B. 8 : 2 = 4. C. 8 : 4 = 4. D. 2 : 4 = 4. 4 : 2 = 8. 8 : 4 = 2. 4 : 8 = 4. 4 : 2 = 4. 4. (1 \u0111) Khoanh v\u00e0o t\u00ean g\u1ecdi \u0111\u00fang c\u1ee7a h\u00ecnh b\u00ean: CD A. \u0111o\u1ea1n th\u1eb3ng. B. \u0111\u01b0\u1eddng th\u1eb3ng. A B C. \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac. D. H\u00ecnh ch\u1eef nh\u1eadt. 5. (0,5\u0111) H\u00e3y khoanh v\u00e0o h\u00ecnh \u0111\u00e3 t\u00f4 m\u00e0u s\u1ed1 \u00f4 vu\u00f4ng trong nh\u1eefng h\u00ecnh d\u01b0\u1edbi \u0111\u00e2y: A. B. C. D. 6. (0,5\u0111) M\u1ed9t \u0111\u1ed9i l\u00e0m vi\u1ec7c c\u00f3 20 ng\u01b0\u1eddi \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 4 t\u1ed5. H\u1ecfi m\u1ed7i t\u1ed5 l\u00e0 m\u1ed9t ph\u1ea7n m\u1ea5y? A. . B. . C. . D. . 70 \u2013 26 PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111) 57 + 18 82- 37 13+ 67 ..................... ..................... ..................... .......................... .......................... ..... ..... ..... .......................... ..................... ..................... ..................... ..... ..... ..... To\u00e1n 2-1 Page 325","..................... ..................... ..................... ..... ..... ..... B\u00e0i 2: T\u00ecm X (1\u0111) a. X x 3 = 18 b. X x 2 = 5 x 4 .............................................................................................................................. .............................................................................................................................. .............................................................................................................................. B\u00e0i 3. Gi\u1ea3i to\u00e1n: (2\u0111) 8. (2 \u0111i\u1ec3m) L\u1edbp 2A c\u00f3 25 h\u1ecdc sinh \u0111\u01b0\u1ee3c x\u1ebfp \u0111\u1ec1u th\u00e0nh 5 t\u1ed5. H\u1ecfi m\u1ed7i t\u1ed5 c\u00f3 m\u1ea5y h\u1ecdc sinh ? 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B\u00e0i 4. (1\u0111) M\u1ed9t \u0111o\u1ea1n d\u00e2y \u0111\u1ed3ng \u0111\u01b0\u1ee3c u\u1ed1n th\u00e0nh h\u00ecnh tam gi\u00e1c nh\u01b0 h\u00ecnh v\u1ebd. T\u00ednh \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n d\u00e2y \u0111\u1ed3ng \u0111\u00f3 ? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026................... To\u00e1n 2-1 Page 326","\u0110\u1ec0 S\u1ed0 3 I. TR\u1eaeC NGHI\u1ec6M (4\u0111). Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u d\u01b0\u1edbi \u0111\u00e2y 1. (0,5\u0111) S\u1ed1 45 \u0111\u1ecdc l\u00e0: A. B\u1ed1n m\u01b0\u01a1i n\u0103m B. N\u0103m m\u01b0\u01a1i b\u1ed1n C. B\u1ed1n m\u01b0\u01a1i l\u0103m D. N\u0103m m\u01b0\u01a1i t\u01b0 2. (0,5 \u0111) S\u1ed1 li\u1ec1n sau c\u1ee7a s\u1ed1 99 l\u00e0: A. 98 B. 100 C. 90 D. 80 3. (0,5 \u0111) Cho c\u00e1c s\u1ed1 73, 9, 37, 45, 54. S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 \u0111\u00e3 cho theo th\u1ee9 t\u1ef1 gi\u1ea3m d\u1ea7n: A. 73, 9, 37, 45, 54 C. 73, 54, 45, 37, 9 B. 9, 37, 45, 54, 73. D. 9, 37, 54, 45, 73 4. (1 \u0111) N\u1ed1i \u00f4 tr\u1ed1ng v\u1edbi ph\u00e9p to\u00e1n th\u00edch h\u1ee3p 29 < < 42 5. (1\u0111) An c\u00f3 28 vi\u00ean bi. H\u00f9ng c\u00f3 nhi\u1ec1u h\u01a1n An 12 vi\u00ean bi. H\u1ecfi H\u00f9ng c\u00f3 bao nhi\u00eau vi\u00ean bi? A. 6 vi\u00ean bi B. 40 vi\u00ean bi C. 16 vi\u00ean bi D. 8 vi\u00ean bi 6. (1\u0111 H\u00ecnh M c\u00f3: A. 2 h\u00ecnh tam gi\u00e1c, 4 h\u00ecnh t\u1ee9 gi\u00e1c. B. 2 h\u00ecnh tam gi\u00e1c, 3 h\u00ecnh t\u1ee9 gi\u00e1c. C. 3 h\u00ecnh tam gi\u00e1c, 4 h\u00ecnh t\u1ee9 gi\u00e1c. D. 3 h\u00ecnh tam gi\u00e1c, 3 h\u00ecnh t\u1ee9 gi\u00e1c. II. T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 1. (2 \u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 34 + 29 46 - 27 28 + 72 100 \u2013 37 ..................... ..................... ..................... .......................... .......................... ..... ..... ..... .......................... To\u00e1n 2-1 Page 327","..................... ..................... ..................... ..... ..... ..... ..................... ..................... ..................... ..... ..... ..... B\u00e0i 2. (1 \u0111) T\u00ecm x b. 3 x x = 18 a. 29 + x = 45 .............................................................................................................................. .............................................................................................................................. .............................................................................................................................. B\u00e0i 3. (2 \u0111) Gi\u1ea3i to\u00e1n M\u1ed7i ng\u00e0y nh\u00e0 Mai \u0103n h\u1ebft 2kg g\u1ea1o. H\u1ecfi 1 tu\u1ea7n l\u1ec5 nh\u00e0 Mai \u0103n h\u1ebft bao nhi\u00eau ki-l\u00f4-gam g\u1ea1o? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026................... B\u00e0i 4. (1\u0111) C\u00f3 hai s\u1ed1, n\u1ebfu g\u1ea5p s\u1ed1 th\u1ee9 hai l\u00ean 3 l\u1ea7n th\u00ec t\u00edch hai s\u1ed1 l\u00e0 24. T\u00ecm t\u00edch ban \u0111\u1ea7u c\u1ee7a hai s\u1ed1. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026................... To\u00e1n 2-1 Page 328","\u0110\u1ec0 S\u1ed0 4 I. TR\u1eaeC NGHI\u1ec6M (4\u0111). Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u d\u01b0\u1edbi \u0111\u00e2y 1. (0,5\u0111) S\u1ed1 g\u1ed3m 7 ch\u1ee5c, 2 \u0111\u01a1n v\u1ecb vi\u1ebft l\u00e0: A. 72 B. 27 C. 70 D. 9 2. (0,5 \u0111) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a s\u1ed1 99 l\u00e0: A. 98 B. 100 C. 90 D. 80 3. (0,5 \u0111) Gi\u00e1 tr\u1ecb ch\u1eef s\u1ed1 7 h\u01a1n gi\u00e1 tr\u1ecb ch\u1eef s\u1ed1 5 trong s\u1ed1 75 l\u00e0: A. 2 C. 65 B. 5 D. 20 4. (1 \u0111) S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: 1; 2; 3; 5; 8; ... A. 10 B. 11 C. 12 D. 13 5. (1\u0111) C\u00f3 18 vi\u00ean bi chia \u0111\u1ec1u cho 3 b\u1ea1n. H\u1ecfi m\u1ed7i b\u1ea1n c\u00f3 bao nhi\u00eau vi\u00ean bi? A. 6 vi\u00ean bi B. 15 vi\u00ean bi C. 21 vi\u00ean bi D. 8 vi\u00ean bi 6. (1\u0111 H\u00ecnh M c\u00f3: a. ................. tam gi\u00e1c. b. ................. t\u1ee9 gi\u00e1c. II. T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 1. (2 \u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 18+ 42 92 - 37 27 + 73 100 \u2013 56 ..................... ..................... ..................... .......................... .......................... ..... ..... ..... .......................... ..................... ..................... ..................... ..... ..... ..... ..................... ..................... ..................... ..... ..... ..... B\u00e0i 2. (1 \u0111) T\u00ecm y b. y + 21 = 73 - 18 a. y x 2 = 16 .............................................................................................................................. To\u00e1n 2-1 Page 329",".............................................................................................................................. .............................................................................................................................. B\u00e0i 3. (2 \u0111) Gi\u1ea3i to\u00e1n M\u1ed9t c\u1eeda h\u00e0ng c\u00f3 51kg t\u00e1o, \u0111\u00e3 b\u00e1n 26kg. H\u1ecfi c\u1eeda h\u00e0ng \u0111\u00f3 c\u00f2n l\u1ea1i bao nhi\u00eau ki-l\u00f4-gam t\u00e1o? 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B\u00e0i 4. (1\u0111) T\u00edch hai s\u1ed1 l\u00e0 8. N\u1ebfu g\u1ea5p th\u1eeba s\u1ed1 th\u1ee9 nh\u1ea5t l\u00ean 3 l\u1ea7n th\u00ec t\u00edch m\u1edbi l\u00e0 bao nhi\u00eau? 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To\u00e1n 2-1 Page 330","\u0110\u1ec0 S\u1ed0 5 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u d\u01b0\u1edbi \u0111\u00e2y 1.\u00a0(0,5\u0111) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc 96 l\u00e0: A. 98\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 94\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 100\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 95 3. (0,5\u0111) Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 5 trong s\u1ed1 56 l\u00e0 A. 5 \u0111\u01a1n v\u1ecb\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 5 ch\u1ee5c\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 56\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 5 4.\u00a0(0,5\u0111) Ng\u00e0y 7 th\u00e1ng 1 n\u0103m 2020 l\u00e0 th\u1ee9 ba. H\u1ecfi th\u1ee9 b\u1ea3y tu\u1ea7n \u0111\u00f3 l\u00e0 ng\u00e0y n\u00e0o? A. 9\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 10\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 11\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 12 5.\u00a0(1\u0111) Trong m\u1ed9t ph\u00e9p tr\u1eeb, khi ta th\u00eam 5 \u0111\u01a1n v\u1ecb v\u00e0o s\u1ed1 b\u1ecb tr\u1eeb v\u00e0 b\u1edbt \u0111i 5 \u0111\u01a1n v\u1ecb \u1edf s\u1ed1 tr\u1eeb th\u00ec hi\u1ec7u s\u1ebd thay \u0111\u1ed5i nh\u01b0 th\u1ebf n\u00e0o? A.\u00a0Hi\u1ec7u gi\u1ea3m 5 \u0111\u01a1n v\u1ecb.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. Hi\u1ec7u t\u0103ng l\u00ean 5 \u0111\u01a1n v\u1ecb\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. Hi\u1ec7u kh\u00f4ng \u0111\u1ed5i. 6.\u00a0(1\u0111) \u0110\u00fang \u0111i\u1ec1n \u0110, sai \u0111i\u1ec1n S M\u1eb9 \u0111i l\u00e0m v\u1ec1 l\u00fac 17 gi\u1edd. An \u0111i h\u1ecdc v\u1ec1 l\u00fac 16 gi\u1edd 30 ph\u00fat. M\u1eb9 v\u1ec1 s\u1edbm h\u01a1n An v\u1ec1 s\u1edbm h\u01a1n PH\u1ea6N II. T\u1ef0 LU\u1eacN B\u00e0i 1.\u00a0\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh (2\u0111) 34 + 56 73 \u2013 36 405 + 138 853 \u2013 368 \u2026......................\u2026 \u2026......................\u2026 \u2026......................\u2026 \u2026......................\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026 ..\u2026.\u2026\u2026\u2026\u2026\u2026\u2026 \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026\u2026\u2026\u2026. \u2026.\u2026\u2026\u2026\u2026\u2026\u2026... B\u00e0i 2. T\u00ecm x: (1\u0111)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 a. x - 37 = 63 b. 7 = x + 19 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 331","B\u00e0i 3.\u00a0\u00a0Gi\u1ea3i to\u00e1n: (2\u0111) M\u1ed7i chu\u1ed3ng c\u00f3 3 con g\u00e0. H\u1ecfi 8 chu\u1ed3ng nh\u01b0 th\u1ebf c\u00f3 bao nhi\u00eau con g\u00e0? 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B\u00e0i 5.\u00a0\u00a0(1\u0111) M\u1ed9t s\u1ed1 nh\u00e2n v\u1edbi 2 r\u1ed3i c\u1ed9ng th\u00eam 17 th\u00ec \u0111\u01b0\u1ee3c 29. T\u00ecm s\u1ed1 ban \u0111\u1ea7u. 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To\u00e1n 2-1 Page 332","\u0110\u00c1P AN \u0110\u1ec0 THI GI\u1eeeA K\u00cc II \u0110\u1ec0 S\u1ed0 1 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 4 5 6 7 \u0110\u00e1p \u00e1n B A D C C C B PH\u1ea6N II. T\u1ef0 LU\u1eacN B\u00e0i 1.\u00a0\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh (2\u0111) B\u00e0i 2. T\u00ecm x: (1\u0111)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 a. x = 26 b. x = 16 B\u00e0i 3.\u00a0\u00a0 C\u00e1c b\u1ea1n nam c\u1ea7n chu\u1ea9n b\u1ecb s\u1ed1 b\u00f4ng hoa l\u00e0: 3 x 4 = 12 (b\u00f4ng) \u0110\u00e1p s\u1ed1: 12 b\u00f4ng hoa B\u00e0i 5.\u00a0\u00a0 \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng NP l\u00e0: 30 \u2013 12 = 18 (cm) \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng PQ l\u00e0: 30 \u2013 18 = 12 (cm) \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac MNPQ l\u00e0: 30 + 12 + 18 = 60 (cm) \u0110\u00e1p s\u1ed1: a. \u0110o\u1ea1n th\u1eb3ng NP: 18cm; \u0111o\u1ea1n th\u1eb3ng PQ: 12cm b. \u0110\u01b0\u1eddng g\u1ea5p kh\u00fac MNPQ: 60cm To\u00e1n 2-1 Page 333","\u0110\u1ec0 S\u1ed0 2 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 4 5 6 \u0110\u00e1p \u00e1n C A B C B C,D PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 2: T\u00ecm X (1\u0111) a. X = 6 b. X = 10 B\u00e0i 3. M\u1ed7i t\u1ed5 c\u00f3 s\u1ed1 h\u1ecdc sinh l\u00e0: 25 : 5 = 5 (h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 5 h\u1ecdc sinh B\u00e0i 4. \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n d\u00e2y \u0111\u00f3 l\u00e0: 3 x 3 = 9 (cm) \u0110\u00e1p s\u1ed1: 9cm \u0110\u1ec0 S\u1ed0 3 I. TR\u1eaeC NGHI\u1ec6M (4\u0111). Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u d\u01b0\u1edbi \u0111\u00e2y PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 5 6 \u0110\u00e1p \u00e1n C B C B A 4. (1 \u0111) N\u1ed1i \u00f4 tr\u1ed1ng v\u1edbi ph\u00e9p to\u00e1n th\u00edch h\u1ee3p 29 < < 42 II. T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 2. (1 \u0111) T\u00ecm x a.x = 16 b. x = 6 B\u00e0i 3. (2 \u0111) Gi\u1ea3i to\u00e1n \u0110\u1ed5i 1 tu\u1ea7n = 7 ng\u00e0y Sau m\u1ed9t tu\u1ea7n l\u1ec5 nh\u00e0 Mai \u0103n h\u1ebft s\u1ed1 ki-l\u00f4-gam g\u1ea1o l\u00e0: 2 x 7 = 14 (kg) \u0110\u00e1p s\u1ed1: 14kg B\u00e0i 4. N\u1ebfu g\u1ea5p s\u1ed1 th\u1ee9 hai l\u00ean 3 l\u1ea7n th\u00ec t\u00edch c\u0169ng g\u1ea5p l\u00ean 3 l\u1ea7n T\u00edch ban \u0111\u1ea7u c\u1ee7a hai s\u1ed1 l\u00e0: 24 : 3 = 8 \u0110\u00e1p s\u1ed1: 8 To\u00e1n 2-1 Page 334","\u0110\u1ec0 S\u1ed0 4 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 4 5 6 3 tam gi\u00e1c \u0110\u00e1p \u00e1n A A C D A 3 t\u1ee9 gi\u00e1c II. T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 2. (1 \u0111) T\u00ecm y a. y = 8 b. y = 34 B\u00e0i 3. (2 \u0111) Gi\u1ea3i to\u00e1n C\u1eeda h\u00e0ng c\u00f2n l\u1ea1i s\u1ed1 ki-l\u00f4-gam t\u00e1o l\u00e0: 51 \u2013 26 = 25 (kg) \u0110\u00e1p s\u1ed1: 25 kg t\u00e1o B\u00e0i 4. (1\u0111) T\u00edch hai s\u1ed1 l\u00e0 8. N\u1ebfu g\u1ea5p th\u1eeba s\u1ed1 th\u1ee9 nh\u1ea5t l\u00ean 3 l\u1ea7n th\u00ec t\u00edch m\u1edbi l\u00e0 bao nhi\u00eau? N\u1ebfu g\u1ea5p th\u1eeba s\u1ed1 th\u1ee9 nh\u1ea5t l\u00ean 3 l\u1ea7n th\u00ec t\u00edch m\u1edbi c\u0169ng t\u0103ng l\u00ean 3 l\u1ea7n. T\u00edch m\u1edbi l\u00e0: 8 x 3 = 24 \u0110\u00e1p s\u1ed1: 24 \u0110\u1ec0 S\u1ed0 5 PH\u1ea6N I: (4 \u0111i\u1ec3m) TR\u1eaeC NGHI\u1ec6M Khoanh v\u00e0o \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t cho m\u1ed7i c\u00e2u sau: C\u00e2u 1 3 4 5 6 S,\u0110 \u0110\u00e1p \u00e1n D B B B PH\u1ea6N II. T\u1ef0 LU\u1eacN B\u00e0i 2. T\u00ecm x: (1\u0111)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 a. x = 100 b. x = 12 B\u00e0i 3.\u00a0\u00a0 8 chu\u1ed3ng c\u00f3 s\u1ed1 con g\u00e0 l\u00e0: 3 x 8 = 24 (con) \u0110\u00e1p s\u1ed1: 24 con g\u00e0 B\u00e0i 5. S\u1ed1 ban \u0111\u1ea7u l\u00e0: (29 \u2013 17) : 2 = 6 \u0110\u00e1p s\u1ed1: 6 To\u00e1n 2-1 Page 335","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp.......... A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N 1. C\u00e1ch \u0111\u1ecdc, vi\u1ebft c\u00e1c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 - \u0110\u1ecdc s\u1ed1 theo th\u1ee9 t\u1ef1 c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i: H\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb ( \u0110\u1ecdc s\u1ed1 tr\u0103m + tr\u0103m + s\u1ed1 ch\u1ee5c + m\u01b0\u01a1i + s\u1ed1 \u0111\u01a1n v\u1ecb) - T\u1eeb c\u00e1ch \u0111\u1ecdc s\u1ed1, em vi\u1ebft c\u00e1c ch\u1eef s\u1ed1 t\u01b0\u01a1ng \u1ee9ng v\u1edbi c\u00e1c h\u00e0ng r\u1ed3i gh\u00e9p l\u1ea1i \u0111\u1ec3 \u0111\u01b0\u1ee3c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1. V\u00ed d\u1ee5:\u00a0\u0110\u1ecdc v\u00e0 vi\u1ebft s\u1ed1 243 * L\u01b0u \u00fd: - Em c\u1ea7n \u0111\u1ecdc m\u01b0\u01a1i sau s\u1ed1 ch\u1ee5c V\u00ed d\u1ee5: 234 \u0110\u1ecdc l\u00e0 2 tr\u0103m ba m\u01b0\u01a1i t\u01b0 ch\u1ee9 kh\u00f4ng \u0111\u1ecdc l\u00e0 hai tr\u0103m ba t\u01b0 - C\u00e1ch \u0111\u1ecdc ch\u1eef s\u1ed1 5: \u1ede c\u00e1c v\u1ecb tr\u00ed kh\u00e1c nhau, ch\u1eef s\u1ed1 5 c\u00f3 c\u00e1ch \u0111\u1ecdc kh\u00e1c nhau, sau m\u01b0\u01a1i v\u00e0 m\u01b0\u1eddi em \u0111\u1ecdc l\u00e0 l\u0103m, c\u00f2n l\u1ea1i \u0111\u1ecdc l\u00e0 n\u0103m. V\u00ed d\u1ee5: C\u00e1ch \u0111\u1ecdc \u0111\u00fang C\u00e1ch \u0111\u1ecdc sai 215: Hai tr\u0103m m\u01b0\u1eddi l\u0103m Hai tr\u0103m m\u01b0\u1eddi n\u0103m 235 Hai tr\u0103m ba m\u01b0\u01a1i l\u0103m Hai tr\u0103m ba m\u01b0\u01a1i n\u0103m 205 Hai tr\u0103m linh n\u0103m Hai tr\u0103m linh l\u0103m 250 Hai tr\u0103m n\u0103m m\u01b0\u01a1i Hai tr\u0103m l\u0103m m\u01b0\u01a1i Hai tr\u0103m m\u01b0\u1eddi l\u0103m, 2. So s\u00e1nh c\u00e1c s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 - S\u1ed1 c\u00f3 \u00edt ch\u1eef s\u1ed1 h\u01a1n th\u00ec c\u00f3 gi\u00e1 tr\u1ecb b\u00e9 h\u01a1n. - Hai s\u1ed1 \u0111\u1ec1u c\u00f3 ba ch\u1eef s\u1ed1, em so s\u00e1nh c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i. V\u00ed d\u1ee5:\u00a0\u0110i\u1ec1n d\u1ea5u th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 123....132 Gi\u1ea3i: 123 < 132 ( Hai s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1, h\u00e0ng tr\u0103m \u0111\u1ec1u l\u00e0 ch\u1eef s\u1ed1 1; h\u00e0ng ch\u1ee5c c\u00f3 2 < 3 V\u1eady d\u1ea5u c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0 d\u1ea5u <. 3. M\u00e9t M\u00e9t vi\u1ebft t\u1eaft l\u00e0 m1m = 1000mm 1m = 10dm 1m = 100cm To\u00e1n 2-1 Page 336","B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: a. C\u00e1c s\u1ed1 sau \u0111\u00e2y \u0111\u01b0\u1ee3c x\u1ebfp theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn : A. 345 ; 453 ; 534 ; 543 ; 435 ; 354 \u2026 B. 345 ; 354 ; 435 ; 453 ; 534 ; 543 \u2026 C. 345 ; 453 ; 534 ; 543 ; 354; 435 \u2026 D. 354; 345 ; 435 ; 453 ; 534 ; 543 \u2026 b. 3m=.......cm. S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0 A. 30 B. 300 C. 3 D. 13 c.T\u1eeb 100 \u0111\u1ebfn 109 c\u00f3 bao nhi\u00eau s\u1ed1 kh\u00e1c nhau : A. 8 s\u1ed1 B . 9 s\u1ed1 C . 10 s\u1ed1 D . 11 s\u1ed1 d. M\u1ed7i b\u1ed9 qu\u1ea7n \u00e1o may h\u1ebft 3m v\u1ea3i . H\u1ecfi c\u00f3 18m v\u1ea3i th\u00ec may \u0111\u01b0\u1ee3c bao nhi\u00eau b\u1ed9 qu\u1ea7n \u00e1o nh\u01b0 th\u1ebf ? A. 21 b\u1ed9 B. 15 b\u1ed9 C. 6 b\u1ed9 D. 6 m v\u1ea3i B\u00e0i 2: S\u1ed1? a) 141; 142; ......;......;......;......; 147; ......;......;......;......; b) 697; 698; ......;......;......;......;......;......;......;......;......; c) 810; 820; ......;......;......;......;......;......;......;......;......; B\u00e0i 3: \u0110\u00fang ghi \u0110 , sai ghi S : a) 2 m = 20 cm \u2026 e) 40 cm = 4 dm\u2026 b) 2 m = 20 dm \u2026 g) 40 cm = 4 m\u2026 c) 3 dm = 30 mm\u2026 h) 50 mm = 5 dm\u2026 d) 3 dm = 30 cm\u2026 i) 50 mm = 5 cm\u2026 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 a) 7 tr\u0103m 5 ch\u1ee5c 3 \u0111\u01a1n v\u1ecb ................... ................................................................. b) 2 tr\u0103m 0 ch\u1ee5c 8 \u0111\u01a1n v\u1ecb ................... ................................................................. c) 0 tr\u0103m 9 ch\u1ee5c 0 \u0111\u01a1n v\u1ecb .................... ................................................................. d) 9 tr\u0103m 9 ch\u1ee5c 9 d\u01a1n v\u1ecb ................... ................................................................. To\u00e1n 2-1 Page 337","e) 1 tr\u0103m 1 ch\u1ee5c 0 \u0111\u01a1n v\u1ecb ................... ................................................................. B\u00e0i 2: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: S\u1ed1 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb \u0110\u1ecdc s\u1ed1 315 765 374 904 255 B\u00e0i 3: Vi\u1ebft s\u1ed1 li\u1ec1n sau c\u1ee7a c\u00e1c s\u1ed1 sau: a) S\u1ed1 li\u1ec1n sau c\u1ee7a99 l\u00e0 ........ b) S\u1ed1 li\u1ec1n sau c\u1ee7a199 l\u00e0 ......... c) S\u1ed1 li\u1ec1n sau c\u1ee7a 999 l\u00e0 ......... B\u00e0i 4: \u00a0Cho c\u00e1c s\u1ed1: 106; 207; 301; 408; 602; 803; 909; 704; 605. a) S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 tr\u00ean theo tr\u1eadt t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9. ......................................................................................................................................... ... ......................................................................................................................................... ... b) S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 tr\u00ean theo tr\u1eadt t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn. ......................................................................................................................................... ......................................................................................................................................... ...... B\u00e0i 5: H\u00e3y vi\u1ebft theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn : a) C\u00e1c s\u1ed1 tr\u00f2n tr\u0103m c\u00f3 3 ch\u1eef s\u1ed1 :\u2026\u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026\u2026\u2026. b) C\u00e1c s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 gi\u1ed1ng nhau :\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 6: Vi\u1ebft cm, ho\u1eb7c dm v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p? a. Gang tay c\u1ee7a em d\u00e0i kho\u1ea3ng 12 ............................ b. Em cao kho\u1ea3ng 13 ................................... c. M\u1eb9 em cao kho\u1ea3ng 160 ............................... d. C\u00e1i b\u00e0n h\u1ecdc c\u1ee7a em d\u00e0i kho\u1ea3ng 120.............. e. Quy\u1ec3n v\u1edf \u00f4 ly c\u1ee7a em d\u00e0i kho\u1ea3ng 3................ B\u00e0i 7: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m To\u00e1n 2-1 Page 338","1 m = ............ cm 10 dm = ................... m ...............cm = 1 m 1 m = ............ dm 100 cm =.................. m ...............dm = 1 m B\u00e0i 8: T\u00ednh a) 36m + 28 m = \u2026 8 m + 67 m = \u2026 b) 42 m \u2013 24 m = \u2026 35 m \u2013 19 m = \u2026 c) 4 m \u00d7 6 = \u2026 4m\u00d74=\u2026 d) 28 m : 4 = \u2026 25 m : 5 = \u2026 B\u00e0i 9: \u0110i\u1ec1n d\u1ea5u <,>,= 49 cm + 50 cm \u2026. 2m 1 m \u2026. 35 dm + 55 dm 50 cm \u00d7 2 \u2026.. 1 m 20 cm \u00d7 4 \u2026. 1m B\u00e0i 10: T\u1ea5m v\u1ea3i xanh d\u00e0i 18 m , t\u1ea5m v\u1ea3i hoa d\u00e0i h\u01a1n t\u1ea5m v\u1ea3i xanh l\u00e0 7m . H\u1ecfi t\u1ea5m v\u1ea3i hoa d\u00e0i bao nhi\u00eau m\u00e9t ? B\u00e0i gi\u1ea3i B\u00e0i 10\u00a0:M\u1ed9t t\u1ea5m v\u1ea3i d\u00e0i 40 m . H\u1ecfi sau khi c\u1eaft \u0111i 15m th\u00ec t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i d\u00e0i bao nhi\u00eau m\u00e9t ? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 339","To\u00e1n 2-1 Page 340","\u0110\u00c1P \u00c1N Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : d B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u a b c \u0110\u00e1p \u00e1n BBCC B\u00e0i 2: S\u1ed1? a) 141; 142; 143; 144; 145; 146; 147; 148; 149; 150; 151 b) 697; 698; 699; 700; 701; 702; 703; 704; 705; 706; 707 c) 810; 820; 830; 840; 850; 860; 870; 880; 890; 900; 910 B\u00e0i 3: \u0110\u00fang ghi \u0110 , sai ghi S : a) 2 m = 20 cm S e) 40 cm = 4 dm \u0110 b) 2 m = 20 dm \u0110 g) 40 cm = 4 m S c) 3 dm = 30 mm S h) 50 mm = 5 dm S d) 3 dm = 30 cm \u0110 i) 50 mm = 5 cm \u0110 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 a) 7 tr\u0103m 5 ch\u1ee5c 3 \u0111\u01a1n v\u1ecb 753 B\u1ea3y tr\u0103m n\u0103m m\u01b0\u01a1i ba b) 2 tr\u0103m 0 ch\u1ee5c 8 \u0111\u01a1n v\u1ecb 208 Hai tr\u0103m linh t\u00e1m c) 0 tr\u0103m 9 ch\u1ee5c 0 \u0111\u01a1n v\u1ecb 90 Ch\u00edn m\u01b0\u01a1i d) 9 tr\u0103m 9 ch\u1ee5c 9 d\u01a1n v\u1ecb 999 Ch\u00edn tr\u0103m ch\u00edn m\u01b0\u01a1i ch\u00edn e) 1 tr\u0103m 1 ch\u1ee5c 0 \u0111\u01a1n v\u1ecb 110 M\u1ed9t tr\u0103m m\u01b0\u1eddi B\u00e0i 2: Ho\u00e0n th\u00e0nh b\u1ea3ng sau: S\u1ed1 Tr\u0103m Ch\u1ee5c \u0110\u01a1n v\u1ecb \u0110\u1ecdc s\u1ed1 315 3 1 5 Ba tr\u0103m m\u01b0\u1eddi l\u0103m 765 7 6 5 B\u1ea3y tr\u0103m s\u00e1u m\u01b0\u01a1i l\u0103m 374 3 7 4 Ba tr\u0103m b\u1ea3y m\u01b0\u01a1i t\u01b0 904 9 0 4 Ch\u00edn tr\u0103m linh t\u01b0 255 2 5 5 Hai tr\u0103m n\u0103m m\u01b0\u01a1i l\u0103m B\u00e0i 3: Vi\u1ebft s\u1ed1 li\u1ec1n sau c\u1ee7a c\u00e1c s\u1ed1 sau: a) S\u1ed1 li\u1ec1n sau c\u1ee7a 99 l\u00e0 100 b) S\u1ed1 li\u1ec1n sau c\u1ee7a199 l\u00e0 200 c) S\u1ed1 li\u1ec1n sau c\u1ee7a 999 l\u00e0 1000 To\u00e1n 2-1 Page 341","B\u00e0i 4: \u00a0Cho c\u00e1c s\u1ed1: 106; 207; 301; 408; 602; 803; 909; 704; 605. a) S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 tr\u00ean theo tr\u1eadt t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9: 106; 207; 301; 408; 602; 605; 704; 803; 909. b) S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 tr\u00ean theo tr\u1eadt t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn: 909, 803; 704; 605; 602; 408; 301; 207; 106. B\u00e0i 5: H\u00e3y vi\u1ebft theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn : a) C\u00e1c s\u1ed1 tr\u00f2n tr\u0103m c\u00f3 3 ch\u1eef s\u1ed1 : 100, 200, 300, 400, 500, 600, 700, 800, 900 b) C\u00e1c s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 gi\u1ed1ng nhau : 111, 222, 333, 444, 555, 666, 777, 888, 999 B\u00e0i 6: Vi\u1ebft cm, ho\u1eb7c dm v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p? a. Gang tay c\u1ee7a em d\u00e0i kho\u1ea3ng 12 cm b. Em cao kho\u1ea3ng 13 dm c. M\u1eb9 em cao kho\u1ea3ng 160 cm d. C\u00e1i b\u00e0n h\u1ecdc c\u1ee7a em d\u00e0i kho\u1ea3ng 120 cm e. Quy\u1ec3n v\u1edf \u00f4 ly c\u1ee7a em d\u00e0i kho\u1ea3ng 3 dm B\u00e0i 7: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m 1 m = 100 cm 10 dm = 1 m 100 cm = 1 m 1 m = 10 dm 100 cm = 1 m 10 dm = 1 m B\u00e0i 8: T\u00ednh a) 36m + 28 m = 64m 8 m + 67 m = 75m b) 42 m \u2013 24 m = 18m 35 m \u2013 19 m = 16m c) 4 m \u00d7 6 = 24m 4 m \u00d7 4 = 16m d) 28 m : 4 = 7m 25 m : 5 = 5m B\u00e0i 9: \u0110i\u1ec1n d\u1ea5u <,>,= 49 cm + 50 cm < 2m 1 m > 35 dm + 55 dm 50 cm \u00d7 2 = 1 m 20 cm \u00d7 4 < 1m B\u00e0i 10: B\u00e0i gi\u1ea3i T\u1ea5m v\u1ea3i hoa d\u00e0i s\u1ed1 m\u00e9t l\u00e0: 18 + 7 = 25 (m) \u0110\u00e1p s\u1ed1: 25m B\u00e0i 10\u00a0: B\u00e0i gi\u1ea3i Sau khi c\u1eaft \u0111i 15m th\u00ec t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i d\u00e0i s\u1ed1 m\u00e9t l\u00e0 : 40 - 15 = 25 (m) \u0110\u00e1p s\u1ed1: 25m To\u00e1n 2-1 Page 342","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N .1. Ki-l\u00f4-m\u00e9t Ki-l\u00f4-m\u00e9t l\u00e0 m\u1ed9t \u0111\u01a1n v\u1ecb \u0111o \u0111\u1ed9 d\u00e0i ( ch\u1eb3ng h\u1ea1n, \u0111\u1ec3 \u0111o qu\u00e3ng \u0111\u01b0\u1eddng gi\u1eefa hai t\u1ec9nh, ta d\u00f9ng \u0111\u01a1n v\u1ecb ki-l\u00f4-m\u00e9t. Ki-l\u00f4-m\u00e9t vi\u1ebft t\u1eaft l\u00e0 km 1km= 1000m 2. Mi-li-m\u00e9t Mi-li-m\u00e9t l\u00e0 m\u1ed9t \u0111\u01a1n v\u1ecb \u0111o \u0111\u1ed9 d\u00e0i. Mi-li-m\u00e9t vi\u1ebft t\u1eaft l\u00e0 mm 1cm= 10mm 1m= 1000mm 3. Vi\u1ebft s\u1ed1 th\u00e0nh t\u1ed5ng c\u00e1c tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb B\u01b0\u1edbc 1: X\u00e1c \u0111\u1ecbnh s\u1ed1 tr\u0103m, s\u1ed1 ch\u1ee5c, s\u1ed1 \u0111\u01a1n v\u1ecb c\u1ee7a s\u1ed1 \u0111\u00f3. B\u01b0\u1edbc 2: Vi\u1ebft s\u1ed1 \u0111\u00f3 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng: h\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb V\u00ed d\u1ee5:\u00a0Vi\u1ebft s\u1ed1 123 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb. Gi\u1ea3i: 123 = 100 + 20 + 3 4. Ph\u00e9p c\u1ed9ng kh\u00f4ng nh\u1edb trong ph\u1ea1m vi 1000 \u00a0- \u0110\u1eb7t t\u00ednh, c\u00e1c ch\u1eef s\u1ed1 c\u00f9ng m\u1ed9t h\u00e0ng th\u1eb3ng c\u1ed9t v\u1edbi nhau. - Th\u1ef1c hi\u1ec7n ph\u00e9p c\u1ed9ng t\u1eeb ph\u1ea3i sang tr\u00e1i. V\u00ed d\u1ee5:\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh 123 + 345 B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: 1. S\u1ed1 li\u1ec1n sau c\u1ee7a 899 l\u00e0: A. 898 B. 890 C. 900 D. 910 2. 1m 7dm = \u2026..dm . S\u1ed1 th\u00edch h\u1ee3p c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. 170 B. 17 C. 107 D. 8 3. S\u1ed1 tam gi\u00e1c trong h\u00ecnh b\u00ean l\u00e0: A. 8 B. 9 C. 10 D. 11 To\u00e1n 2-1 Page 343","4. Trong c\u00e1c s\u1ed1 569, 965, 659, 956 s\u1ed1 l\u1edbn nh\u1ea5t l\u00e0: A. 569 B. 956 C. 659 D. 965 5. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p c\u1ed9ng 112 v\u00e0 215 l\u00e0: A. 327 B. 427 C. 337 D. 437 6. Tam gi\u00e1c ABC c\u00f3 c\u00e1c c\u1ea1nh l\u1ea7n l\u1ee3t l\u00e0 : 15mm, 36mm, 17mm . Chu vi tam gi\u00e1c ABC l\u00e0: A. 58mm B. 68cm C. 68mm D. 67mm B\u00e0i 2: : S\u1ed1? 18 + 27 = 102 + 201 = +++ +++ 27 + 18 = 201 + 102 = === === += += B\u00e0i 3: N\u1ed1i ( theo m\u1eabu ) : To\u00e1n 2-1 Page 344","B\u00e0i 4: \u0110\u00fang ghi \u0110 , sai ghi S : b) 1m + 9 dm = 10 dm \u2026 402 + 497 a) 6 m = 60 cm \u2026 1m + 9 dm = 19 dm \u2026 6 m = 600 cm \u2026 1 m + 5 cm = 15 cm \u2026 700 mm = 7 m \u2026 1 m + 5 cm = 6 cm \u2026 700 mm = 7 dm \u2026 1 m + 5 cm = 105 cm \u2026 80 dm < 800 cm \u2026 80 dm > 800 cm \u2026 762 + 136 689 + 110 260 + 439 80 dm = 800 cm \u2026 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 545 + 124 207 + 372 234 + 432 B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 2 cm = \u2026 mm a) 3 m = \u2026 dm 4 cm = \u2026 mm 5m = \u2026 dm 50 mm = \u2026 cm b) 20 dm = \u2026 m \u00a090 mm = \u2026 cm \u00a060 dm = \u2026 m B\u00e0i 3: a.Vi\u1ebft s\u1ed1 th\u00e0nh t\u1ed5ng c\u00e1c tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb: 367 =.................................................... 603 =............................................ 439 =.................................................... 940 =............................................... b. Vi\u1ebft t\u1ed5ng th\u00e0nh s\u1ed1: 300 + 40 + 6 =................ 600 + 60 =............................. 900 + 90 + 9 =..................... 400 + 9 =......................... 500 + 80 + 1 =................... 500 + 7 =........................... B\u00e0i 4: : \u0110i\u1ec1n d\u1ea5u > , <, = v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026.) 367......257 498.....568 260......300 215......219 834.....834 863......817 To\u00e1n 2-1 Page 345","213mm ... 231 mm 200m + 300m ... 400m 100 cm ... 1m 30dm ... 29dm 350km ... 349km 45cm + 55cm ... 10dm 1000mm ... 1m 178m ... 201m B\u00e0i 5: \u00a0\u0110i\u1ec1n \u0111\u01a1n v\u1ecb (m, dm, cm, mm) v\u00e0o ch\u1ed7 ch\u1ea5m: 1 km = 1000......... 3m = 3000............ 5 m = 500........... 1m = 10....... 200 mm = 2........... 70..............= 7 cm \u0110i\u1ec1n \u0111\u01a1n v\u1ecb (m, dm, cm, mm) v\u00e0o ch\u1ed7 ch\u1ea5m: 1 km = 1000......... 3m = 3000............ 5 m = 500........... 1m = 10....... 200 mm = 2........... 70..............= 7 cm B\u00e0i 6: T\u00ednh: a) 36m + 28 m = \u2026\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a018 mm + 7 mm = \u2026 b) 42 m \u2013 24 m = \u2026\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a035 mm \u2013 9 mm = \u2026 c) 4 km \u00d7 6 = \u2026\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a05 km \u00d7 8 = \u2026 d) 32 km : 4 = \u2026\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a045 km : 5 = \u2026 B\u00e0i 7: M\u1ed9t ng\u00f4i nh\u00e0 g\u1ed3m 7 t\u1ea7ng cao b\u1eb1ng nhau. Bi\u1ebft r\u1eb1ng ng\u00f4i nh\u00e0 cao 21m. H\u1ecfi m\u1ed7i t\u1ea7ng cao m\u1ea5y m\u00e9t? B\u00e0i gi\u1ea3i B\u00e0i 8: Cu\u1ed1n s\u00e1ch Ti\u1ebfng Vi\u1ec7t d\u00e0y 9 mm. Cu\u1ed1n s\u00e1ch To\u00e1n d\u00e0y 6mm. H\u1ecfi cu\u1ed1n s\u00e1ch n\u00e0o m\u1ecfng h\u01a1n v\u00e0 m\u1ecfng h\u01a1n bao nhi\u00eau mm? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 346","To\u00e1n 2-1 Page 347","B\u00e0i 9: \u0110\u00e8n bi\u1ec3n c\u00e1ch b\u1edd 4km, m\u1ed9t chi\u1ebfc t\u00e0u \u0111\u00e1nh c\u00e1 c\u00e1ch b\u1edd 3km (nh\u01b0 h\u00ecnh v\u1ebd). H\u1ecfi chi\u1ebfc t\u00e0u \u0111\u00e1nh c\u00e1 \u0111\u00f3 c\u00e1ch \u0111\u00e8n bi\u1ec3n bao nhi\u00eau ki-l\u00f4-m\u00e9t? B\u00e0i gi\u1ea3i B\u00e0i 10\u00a0: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 :105 cm , 11 dm, 113 cm, 16 dm. B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 348","\u0110\u00c1P \u00c1N B. B\u00c0I T\u1eacP Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u 1 2 3 4 5 6 C \u0110\u00e1p \u00e1n C BB D A B\u00e0i 2: : S\u1ed1? 18 + 27 = 45 102 + 201 = 303 +++ ++ + 27 + 18 = 45 201 + 102 = 303 === == = 45 + 45 = 90 303 + 303 = 606 B\u00e0i 3: N\u1ed1i ( theo m\u1eabu ) : 2. N\u1ed1i ( theo m\u1eabu ) : To\u00e1n 2-1 Page 349","B\u00e0i 4: \u0110\u00fang ghi \u0110 , sai ghi S : b) 1m + 9 dm = 10 dm S 1m + 9 dm = 19 dm \u0110 a) 6 m = 60 cm S 1 m + 5 cm = 15 cm S 6 m = 600 cm \u0110 1 m + 5 cm = 6 cm S 700 mm = 7 m S 1 m + 5 cm = 105 cm \u0110 700 mm = 7 dm \u0110 80 dm < 800 cm S 80 dm > 800 cm S 80 dm = 800 cm \u0110 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 545 + 124 = 669 207 + 372 = 579 234 + 432 = 666 762 + 136 = 898 689 + 110 = 799 260 + 439 =699 402 + 497 = 899 B\u00e0i 2: S\u1ed1? Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: a) 3 m = 30 dm 5m = 50 dm b) 20 dm = 2 m \u00a060 dm = 6 m a) 2 cm = 20 mm 4 cm = 40 mm b) 50 mm = 5 cm \u00a090 mm = 9 cm B\u00e0i 3: a.Vi\u1ebft s\u1ed1 th\u00e0nh t\u1ed5ng c\u00e1c tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb: 367 = 300 + 60 + 7 603 = 600 + 3 439 = 400 + 30 + 9 940 = 900 + 40 b. Vi\u1ebft t\u1ed5ng th\u00e0nh s\u1ed1: 300 + 40 + 6 = 346 600 + 60 = 660 900 + 90 + 9 = 909 400 + 9 = 409 500 + 80 + 1 = 581 500 + 7 = 507 B\u00e0i 4: : \u0110i\u1ec1n d\u1ea5u > , <, = v\u00e0o ch\u1ed7 ch\u1ea5m (\u2026.) 367 > 257 498 < 568 260 < 300 215 < 219 834 = 834 863 > 817 213mm < 231 mm 200m + 300m > 400m 100 cm = 1m 30dm > 29dm 350km > 349km 45cm + 55cm = 10dm 1000mm = 1m 178m < 201m To\u00e1n 2-1 Page 350"]