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Home Explore Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

Published by THƯ VIỆN TIỂU HỌC TÂN QUANG, 2023-08-17 09:08:10

Description: Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

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["PHI\u1ebeU B\u00c0I T\u1eacP CU\u1ed0I TU\u1ea6N 9 A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N 1.L\u00edt L\u00edt l\u00e0 1 \u0111\u01a1n v\u1ecb \u0111o l\u01b0\u1eddng. N\u00f3 d\u00f9ng \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh \u0111\u1ed9 \u0111\u1ea7y v\u01a1i c\u1ee7a c\u00e1c ch\u1ea5t l\u1ecfng trong b\u00ecnh ch\u1ee9a (th\u1ec3 t\u00edch c\u1ee7a ch\u1ea5t l\u1ecfng \u0111\u00f3.). L\u00edt vi\u1ebft t\u1eaft l\u00e0 l 1 l\u00edt = 1l 2 l\u00edt = 2l 3 l\u00edt = 3l 2. T\u00ecm m\u1ed9t s\u1ed1 h\u1ea1ng trong m\u1ed9t t\u1ed5ng. Mu\u1ed1n t\u00ecm s\u1ed1 h\u1ea1ng ch\u01b0a bi\u1ebft, ta l\u1ea5y t\u1ed5ng tr\u1eeb \u0111i s\u1ed1 h\u1ea1ng \u0111\u00e3 bi\u1ebft. B. B\u00c0I T\u1eacP C\u01a0 B\u1ea2N Ph\u1ea7n 1 : B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1. N\u1ed1i c\u00e1c v\u1eadt d\u1ee5ng ch\u1ee9a \u0111\u1ea7y n\u01b0\u1edbc v\u1edbi can ch\u1ee9a l\u01b0\u1ee3ng n\u01b0\u1edbc b\u1eb1ng t\u1ed5ng s\u1ed1 l\u00edt n\u01b0\u1edbc trong c\u00e1c v\u1eadt d\u1ee5ng \u0111\u00f3 : B\u00e0i 2: Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. S\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a 39 l\u00e0 : A. 40 B. 38 C. 92 D. 94 To\u00e1n 2-1 Page 51","2. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p c\u1ed9ng 26 + 7 l\u00e0: A. 96 B. 23 C. 43 D. 33 3. S\u1ed1 h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 9 B. 4 C. 5 D. 6 4. Cho ph\u00e9p tr\u1eeb 59 \u2013 34 = 25, s\u1ed1 b\u1ecb tr\u1eeb l\u00e0: A. 25 B. 34 C. 59 D. 95 5. \u0110\u1ed9 d\u00e0i m\u1ed9t gang tay c\u1ee7a m\u1eb9 l\u00e0: A. 20 dm B. 2 cm C. 200 cm D. 20 cm 6. 6 < 61 Ch\u1eef s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: A. 0 B. 2 C. 3 D. 9 B\u00e0i 3: . \u0110\u00fang ghi \u0110, sai ghi S : 1. T\u00ecm x bi\u1ebft : x + 15 = 48 a) x = 63\u2026 b) x = 33 \u2026. 2. S\u1ed1 n\u00e0o th\u00eam 23 th\u00ec \u0111\u01b0\u1ee3c 57 ? a) 80\u2026. b) 34 \u2026. 3.S\u1ed1 21 th\u00eam bao nhi\u00eau \u0111\u1ec3 \u0111\u01b0\u1ee3c 46 ? a) 67\u2026. b) 25 \u2026. 4. S\u1ed1 n\u00e0o th\u00eam 38 \u0111\u1ec3 \u0111\u01b0\u1ee3c 100 ? a) 72\u2026. b) 62 \u2026. 5*. Anh c\u00f3 nhi\u1ec1u h\u01a1n H\u00e0 l\u00e0 6 nh\u00e3n v\u1edf . H\u1ecfi Anh cho H\u00e0 m\u1ea5y nh\u00e3n v\u1edf th\u00ec s\u1ed1 nh\u00e3n v\u1edf c\u1ee7a hai b\u1ea1n b\u1eb1ng nhau ? a) 6 nh\u00e3n v\u1edf\u2026. b) 3 nh\u00e3n v\u1edf \u2026. 5. C\u00f3 4 ch\u1ee5c b\u00e1t , b\u1ecb v\u1ee1 2 c\u00e1i b\u00e1t . H\u1ecfi c\u00f2n l\u1ea1i bao nhi\u00eau c\u00e1i b\u00e1t ? a) 2 c\u00e1i b\u00e1t \u2026. b) 38 c\u00e1i b\u00e1t \u2026. B\u00e0i 4: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m a) Trong h\u00ecnh b\u00ean c\u00f3 .......... h\u00ecnh t\u1ee9 gi\u00e1c b) Trong h\u00ecnh \u0111\u00f3 c\u00f3 ..............h\u00ecnh tam gi\u00e1c B\u00e0i 5: \u0110\u00e1nh d\u1ea5u X v\u00e0o tranh c\u00f3 s\u1ed1 con v\u1eadt l\u00e0 s\u1ed1 tr\u00f2n ch\u1ee5c li\u1ec1n sau s\u1ed1 10 To\u00e1n 2-1 Page 52","B\u1ee9c tranh 1: B\u1ee9c tranh 2: B\u1ee9c tranh 3 Ph\u1ea7n 2. B\u00e0i t\u1eadp t\u1ef1 lu\u1eadn B\u00e0i 1: a) \u0110\u1ecdc c\u00e1c s\u1ed1 \u0111o: 25kg:.......................................................................................................................... 30l:............................................................................................................................. b) Vi\u1ebft c\u00e1c s\u1ed1 \u0111o B\u1ed1n m\u01b0\u01a1i hai l\u00edt:........................................................................................................ N\u0103m m\u01b0\u01a1i l\u0103m ki-l\u00f4-gam:......................................................................................... B\u00e0i 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 75 + 25 35 + 47 69 + 8 76 \u2013 25 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026B\u00e0i 3: \u0110i\u1ec1n s\u1ed1? S\u1ed1 h\u1ea1ng 35 12 ....... 23 14 ....... S\u1ed1 h\u1ea1ng 16 ...... 25 19 ....... 28 To\u00e1n 2-1 Page 53","T\u1ed5ng 36 67 ....... 77 89 B\u00e0i 4: \u0110i\u1ec1n d\u1ea5u >;=;< a. 25m : 5 . . . . . . . . 32dm b. 5l \u00d7 6 . . . . . . . 2l \u00d7 2 c. 40mm : 8 . . . . . . . 2cm : 5 d. 4kg \u00d7 2 . . . . . . 8cm \u00d7 8 B\u00e0i 5: T\u00ecm x: a) x + 30 = 50 c) 7 + x = 10 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) x + 12 = 47 d) 17 + x = 39 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 6: T\u00ednh: 23 + 14 + 10 = ....... 54 \u2013 10 + 21 16 dm + 5dm \u2013 10dm = =.............. ............. 45 + 22 \u2013 13 =\u2026\u2026 79 \u2013 56 \u2013 11 24kg \u2013 13kg + 4kg =........... =................... B\u00e0i 7. Bu\u1ed5i s\u00e1ng c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 48 l d\u1ea7u ; bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n bu\u1ed5i s\u00e1ng l\u00e0 52l d\u1ea7u . H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u ? B\u00e0i 8. Th\u00f9ng th\u1ee9 nh\u1ea5t ch\u1ee9a 35l d\u1ea7u . Th\u00f9ng th\u1ee9 hai ch\u1ee9a 65l d\u1ea7u . H\u1ecfi c\u1ea3 hai th\u00f9ng ch\u1ee9a bao nhi\u00eau l\u00edt d\u1ea7u ? To\u00e1n 2-1 Page 54","B\u00e0i 9: D\u1ef1a v\u00e0o t\u00f3m t\u1eaft, l\u1eadp b\u00e0i to\u00e1n r\u1ed3i gi\u1ea3i b\u00e0i to\u00e1n sau: C. B\u00c0I T\u1eacP N\u00c2NG CAO B\u00e0i 1*: Th\u00f9ng th\u1ee9 nh\u1ea5t \u0111\u1ef1ng 39 l\u00edt d\u1ea7u, th\u00f9ng th\u1ee9 2 \u0111\u1ef1ng \u00edt h\u01a1n th\u00f9ng th\u1ee9 nh\u1ea5t 9 l\u00edt d\u1ea7u. H\u1ecfi c\u1ea3 hai th\u00f9ng \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u ? To\u00e1n 2-1 Page 55","To\u00e1n 2-1 Page 56","B\u00e0i 2*: x + 12 = 23 + 34 d) 24 + x = 35 + 64 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026........ .....\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026............. B\u00e0i 3*: Con th\u1ecf v\u00e0 con m\u00e8o c\u00e2n n\u1eb7ng b\u1eb1ng con g\u00e0 v\u00e0 con v\u1ecbt, con th\u1ecf n\u1eb7ng h\u01a1n con g\u00e0. Em h\u00e3y cho bi\u1ebft con m\u00e8o v\u00e0 con v\u1ecbt, con n\u00e0o n\u1eb7ng h\u01a1n? B\u00e0i 4*: V\u1edbi m\u1ed9t can 5l v\u00e0 m\u1ed9t can 2l , l\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 \u0111ong \u0111\u01b0\u1ee3c 3l n\u01b0\u1edbc. \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 5*:K\u1ebb th\u00eam 3 \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 4 h\u00ecnh tam gi\u00e1c. To\u00e1n 2-1 Page 57","\u0110\u00c1P \u00c1N B\u00c0I T\u1eacP C\u01a0 B\u1ea2N Ph\u1ea7n 1 : B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1. B\u00e0i 2: Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 6 C\u00e2u 1 2 3 4 5 A \u0110\u00e1p \u00e1n B D A C D B\u00e0i 3: . \u0110\u00fang ghi \u0110, sai ghi S : 1. T\u00ecm x bi\u1ebft : x + 15 = 48 a) x = 63 S b) x = 33 \u0110 2. S\u1ed1 n\u00e0o th\u00eam 23 th\u00ec \u0111\u01b0\u1ee3c 57 ? a) 80 S b) 34 \u0110 3.\u0110\u00fang ghi \u0110 , sai ghi S : S\u1ed1 21 th\u00eam bao nhi\u00eau \u0111\u1ec3 \u0111\u01b0\u1ee3c 46 ? a) 67 \u0110 b) 25 S 4. \u0110\u00fang ghi \u0110 , sai ghi S : S\u1ed1 n\u00e0o th\u00eam 38 \u0111\u1ec3 \u0111\u01b0\u1ee3c 100 ? a) 72 S b) 62 \u0110 5*. \u0110\u00fang ghi \u0110, sai ghi S : Anh c\u00f3 nhi\u1ec1u h\u01a1n H\u00e0 l\u00e0 6 nh\u00e3n v\u1edf . H\u1ecfi Anh cho H\u00e0 m\u1ea5y nh\u00e3n v\u1edf th\u00ec s\u1ed1 nh\u00e3n v\u1edf c\u1ee7a hai b\u1ea1n b\u1eb1ng nhau ? To\u00e1n 2-1 Page 58","a) 6 nh\u00e3n v\u1edf S b) 3 nh\u00e3n v\u1edf \u0110 6. \u0110\u00fang ghi \u0110, sai ghi S : C\u00f3 4 ch\u1ee5c b\u00e1t , b\u1ecb v\u1ee1 2 c\u00e1i b\u00e1t . H\u1ecfi c\u00f2n l\u1ea1i bao nhi\u00eau c\u00e1i b\u00e1t ? a) 2 c\u00e1i b\u00e1t S b) 38 c\u00e1i b\u00e1t \u0110 B\u00e0i 4: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m a) Trong h\u00ecnh b\u00ean c\u00f3 3 h\u00ecnh t\u1ee9 gi\u00e1c b) Trong h\u00ecnh \u0111\u00f3 c\u00f3 3 h\u00ecnh tam gi\u00e1c B\u00e0i 5: \u0110\u00e1nh d\u1ea5u X v\u00e0o b\u1ee9c tranh 1 Ph\u1ea7n 2. B\u00e0i t\u1eadp t\u1ef1 lu\u1eadn B\u00e0i 1: a) \u0110\u1ecdc c\u00e1c s\u1ed1 \u0111o: 25kg: Hai m\u01b0\u01a1i l\u0103m ki-l\u00f4-gam 30l: Ba m\u01b0\u01a1i l\u00edt b) Vi\u1ebft c\u00e1c s\u1ed1 \u0111o B\u1ed1n m\u01b0\u01a1i hai l\u00edt 42l N\u0103m m\u01b0\u01a1i l\u0103m ki-l\u00f4-gam: 52kg B\u00e0i 2: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 75 + 25 = 100 35 + 47 = 82 69 + 8 = 77 76 \u2013 25 = 51 B\u00e0i 3: \u0110i\u1ec1n s\u1ed1? S\u1ed1 h\u1ea1ng 35 12 42 23 14 61 19 63 28 S\u1ed1 h\u1ea1ng 16 24 25 42 77 89 T\u1ed5ng 51 36 67 B\u00e0i 4: a. 25m : 5 > 32dm b. 5cm \u00d7 6 < 2dm \u00d7 2 c. 40mm : 8 < 2cm : 5 d. 4dm \u00d7 2 > 8cm \u00d7 8 B\u00e0i 5: T\u00ecm x: To\u00e1n 2-1 Page 59","a) x + 30 = 50 c) 7 + x =10 x = 10 \u2013 7 x = 50 \u2013 30 x =3 x = 20 d) 17 + x = 39 x = 39 \u2013 17 b) x + 12 = 47 x = 22 x = 47 \u2013 12 16 dm + 5dm \u2013 10dm = 11dm 24kg \u2013 13kg + 4kg = 15kg x = 35 B\u00e0i 6: T\u00ednh: 23 + 14 + 10 = 47 54 \u2013 10 + 21 = 65 45 + 22 \u2013 13 = 54 79 \u2013 56 \u2013 11 = 12 B\u00e0i 7. B\u00e0i gi\u1ea3i Bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 48 + 52 = 100 (l) \u0110\u00e1p s\u1ed1: 100 l d\u1ea7u B\u00e0i 8. B\u00e0i gi\u1ea3i C\u1ea3 hai th\u00f9ng ch\u1ee9a \u0111\u01b0\u1ee3c s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 35 + 65 = 100 (l\u00edt) B\u00e0i 9: D\u1ef1a v\u00e0o t\u00f3m t\u1eaft, l\u1eadp b\u00e0i to\u00e1n r\u1ed3i gi\u1ea3i b\u00e0i to\u00e1n sau: B\u00e0i to\u00e1n B\u00e0i gi\u1ea3i D\u0169ng c\u00f3 28 vi\u00ean ph\u1ea5n. H\u00f9ng c\u00f3 \u00edt h\u01a1n H\u00f9ng c\u00f3 s\u1ed1 vi\u00ean ph\u1ea5n l\u00e0: D\u0169ng 7 vi\u00ean ph\u1ea5n. H\u1ecfi H\u00f9ng c\u00f3 bao 28 \u2013 7 = 21 ( vi\u00ean ph\u1ea5n) nhi\u00eau vi\u00ean ph\u1ea5n? \u0110\u00e1p s\u1ed1: 21 vi\u00ean ph\u1ea5n To\u00e1n 2-1 Page 60","\u0110\u00c1P \u00c1N B\u00c0I T\u1eacP N\u00c2NG CAO B\u00e0i 1: Th\u00f9ng th\u1ee9 nh\u1ea5t \u0111\u1ef1ng 39 l\u00edt d\u1ea7u, th\u00f9ng th\u1ee9 2 \u0111\u1ef1ng \u00edt h\u01a1n th\u00f9ng th\u1ee9 nh\u1ea5t 9 l\u00edt d\u1ea7u. H\u1ecfi c\u1ea3 hai th\u00f9ng \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u ? B\u00e0i gi\u1ea3i C\u1ea3 hai th\u00f9ng \u0111\u1ef1ng \u0111\u01b0\u1ee3c s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 39 + 39 \u2013 9 = 69 (l) \u0110\u00e1p s\u1ed1: 69l d\u1ea7u B\u00e0i 2: a) x + 12 = 23 + 34 b) 24 + x = 35 + 64 x + 12 = 57 24 + x = 99 x = 57 \u2013 12 x = 99 \u2013 24 x = 45 x = 75 B\u00e0i 3: Con th\u1ecf v\u00e0 con m\u00e8o c\u00e2n n\u1eb7ng b\u1eb1ng con g\u00e0 v\u00e0 con v\u1ecbt, con th\u1ecf n\u1eb7ng h\u01a1n con g\u00e0. Em h\u00e3y cho bi\u1ebft con m\u00e8o v\u00e0 con v\u1ecbt, con n\u00e0o n\u1eb7ng h\u01a1n? Th\u1ecf v\u00e0 M\u00e8o c\u00e2n n\u1eb7ng b\u1eb1ng G\u00e0 v\u00e0 V\u1ecbt Th\u1ecf n\u1eb7ng h\u01a1n G\u00e0 n\u00ean V\u1ecbt n\u1eb7ng h\u01a1n M\u00e8o. B\u00e0i 4: Ta \u0111\u1ed5 n\u01b0\u1edbc v\u00e0o can 5l r\u1ed3i l\u1ea5y n\u01b0\u1edbc \u1edf can 5l \u0111\u1ed5 v\u00e0o can 2l. S\u1ed1 n\u01b0\u1edbc c\u00f2n l\u1ea1i \u1edf can 5l ch\u00ednh l\u00e0 3l n\u01b0\u1edbc. B\u00e0i 5:K\u1ebb th\u00eam 3 \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh v\u1ebd c\u00f3 4 h\u00ecnh tam gi\u00e1c. To\u00e1n 2-1 Page 61","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N 1.S\u1ed1 tr\u00f2n ch\u1ee5c tr\u1eeb \u0111i m\u1ed9t s\u1ed1 2. 11 tr\u1eeb \u0111i m\u1ed9t s\u1ed1 11 \u2013 6 = 5 11 \u2013 2 = 9 11 \u2013 7 = 4 11 \u2013 3= 8 11 \u2013 8 = 3 11 \u2013 4 = 7 11 \u2013 9 = 2 11 \u2013 5 = 6 3. 31 \u2013 5, 51 -15. B. B\u00c0I T\u1eacP C\u01a0 B\u1ea2N Ph\u1ea7n 1 : B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : 1. B\u00e0i 1. \u0110\u00fang ghi \u0110; sai ghi S : a. Hi\u1ec7u c\u1ee7a tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 l\u00e0 81 \u25a1 b. M\u1ed9t ph\u00e9p c\u1ed9ng c\u00f3 t\u1ed5ng l\u00e0 71, s\u1ed1 h\u1ea1ng th\u1ee9 nh\u1ea5t l\u00e0 8. S\u1ed1 h\u1ea1ng th\u1ee9 hai l\u00e0 79 \u25a1 To\u00e1n 2-1 Page 62","c. Trong h\u00ecnh v\u1ebd b\u00ean: (1 \u0111i\u1ec3m) - C\u00f3 2 h\u00ecnh tam gi\u00e1c \u25a1 - C\u00f3 4 h\u00ecnh t\u1ee9 gi\u00e1c \u25a1 d. T\u00ecm x bi\u1ebft : x + 15 = 41 x + 15 = 41 x + 15 = 41 x = 41 + 15 x = 41 \u2013 15 x = 56 x = 26 B\u00e0i 2: Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. 32cm + 1dm = ? A. 33 dm B. 33 cm C.42 cm D.42 dm 2. M\u1ed9t ph\u00e9p c\u1ed9ng c\u00f3 t\u1ed5ng l\u00e0 31 v\u00e0 m\u1ed9t s\u1ed1 h\u1ea1ng l\u00e0 15. S\u1ed1 h\u1ea1ng c\u00f2n l\u1ea1i l\u00e0: A. 46 B. 26 C. 16 D.6 3S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o d\u00e3y s\u1ed1 : 3, 6, 9, 12,\u2026.,.18, 21 l\u00e0: A. 13. B. 14 C. 15. D. 17 4.Khi th\u00eam v\u00e0o s\u1ed1 h\u1ea1ng th\u1ee9 nh\u1ea5t v\u00e0 b\u1edbt \u0111i \u1edf s\u1ed1 h\u1ea1ng th\u1ee9 hai c\u00f9ng m\u1ed9t s\u1ed1 \u0111\u01a1n v\u1ecb nh\u01b0 nhau th\u00ec: A. T\u1ed5ng kh\u00f4ng thay \u0111\u1ed5i B. T\u1ed5ng th\u00eam 1 \u0111\u01a1n v\u1ecb C-T\u1ed5ng b\u1edbt 1 \u0111\u01a1n v\u1ecb. D. T\u1ed5ng t\u0103ng 2 \u0111\u01a1n v\u1ecb 5. C\u00e1c s\u1ed1 \u0111o vi\u1ebft theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9 l\u00e0: A. 5cm, 7 cm, 1 dm, 2 dam B. 1dm, 2 dam, 5cm, 7cm C. 7cm, 5cm, 2dam, 1 dam D. 2dam, 1dm, 7cm, 5cm 6. H\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y c\u00f3 m\u1ea5y \u0111o\u1ea1n th\u1eb3ng: A. C\u00f3 3 \u0111o\u1ea1n th\u1eb3ng B. C\u00f3 4 \u0111o\u1ea1n th\u1eb3ng C. C\u00f3 5 \u0111o\u1ea1n th\u1eb3ng D. C\u00f3 6 \u0111o\u1ea1n th\u1eb3ng B\u00e0i 3. N\u1ed1i c\u00e1c s\u1ed1 ho\u1eb7c c\u00e1c ph\u00e9p t\u00ednh th\u00edch v\u00e0o \u00f4 tr\u1ed1ng ( 1, 5 \u0111i\u1ec3m ) 17 < < 27 B\u00e0i 4. \u0110i\u1ec1n d\u1ea5u + ho\u1eb7c \u2013 v\u00e0o \u00f4 tr\u1ed1ng \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang : 21 \u2026. 15 = 36 31 \u2026. 14 = 17 61 \u2026. 18 = 79 51 \u2026. 15 = 36 41 \u2026. 17 = 58 71 \u2026. 17 = 54 To\u00e1n 2-1 Page 63","B\u00e0i 5: S\u1ed1? (2 \u0111i\u1ec3m) + 16 a) + 12 + 15 + 20 b) Ph\u1ea7n 2. B\u00e0i t\u1eadp t\u1ef1 lu\u1eadn B\u00e0i 1: T\u00ednh. 60 70 40 81 41 71 61 81 - 9 - 4 - 12 - 13 - 5 - 38 - 24 - 56 ..... ..... ..... ..... ..... ....... ..... ..... B\u00e0i 2: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m. 11 - 2 = ...... 11 - ........... = 7 7l + 8l = ........ 11 - ....... = 7 11 \u2013 9 = ...... 18kg + 4kg = ....... 11 - 6 = ...... 11- ........ = 4 5l + 3l + 8l = .......... 11 - 5 = ...... 4 + 9 - 8 = ...... 31kg - 3kg + 4kg= ....... B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. 11 \u2013 5 11 \u2013 9 51 \u2013 6 81 \u2013 8 81 \u2013 44 51 \u2013 25 B\u00e0i 4: T\u00ecm x. b) x + 35 = 81 c) 18 + x = 61 a) x + 15 = 44 B\u00e0i 5: T\u00ecm m\u1ed9t s\u1ed1 h\u1ea1ng c\u1ee7a t\u1ed5ng bi\u1ebft t\u1ed5ng v\u00e0 s\u1ed1 h\u1ea1ng c\u00f2n l\u1ea1i l\u00e0: a. 51 v\u00e0 19 b. 61 v\u00e0 27 c. 91 v\u00e0 56 B\u00e0i gi\u1ea3i a. S\u1ed1 h\u1ea1ng c\u1ea7n t\u00ecm l\u00e0: 51 - 19 = ................................. b. .................................................................................................................................... c. ..................................................................................................................................... B\u00e0i 6: \u0110i\u1ec1n d\u1ea5u >;=;< \u0110i\u1ec1n d\u1ea5u (<, >, =) 35 cm 17cm +18cm 52cm +19cm 81cm 42cm 71cm - 27cm 61cm - 39cm 15cm To\u00e1n 2-1 Page 64","B\u00e0i 7: T\u00ecm x: c) 7 + x = 10 a) x + 30 = 50 b) x + 12 = 47 d) 17 + x = 39 B\u00e0i 8: Nh\u00e0 b\u1ebfp mua v\u1ec1 51 kg rau , sau khi \u0111\u00e3 d\u00f9ng m\u1ed9t l\u01b0\u1ee3ng rau th\u00ec c\u00f2n l\u1ea1i 25 kg rau . H\u1ecfi nh\u00e0 b\u1ebfp \u0111\u00e3 d\u00f9ng bao nhi\u00eau ki-l\u00f4-gam rau ? B\u00e0i gi\u1ea3i B\u00e0i 9. \u0110\u1ed9i v\u0103n ngh\u1ec7 c\u00f3 31 b\u1ea1n , trong \u0111\u00f3 c\u00f3 15 b\u1ea1n nam . H\u1ecfi \u0111\u1ed9i v\u0103n ngh\u1ec7 c\u00f3 bao nhi\u00eau b\u1ea1n n\u1eef ? To\u00e1n 2-1 Page 65","B\u00e0i 10. C\u1eeda h\u00e0ng c\u00f3 71 kg b\u00e1nh , \u0111\u00e3 b\u00e1n 37 kg b\u00e1nh . H\u1ecfi c\u1eeda h\u00e0ng c\u00f2n l\u1ea1i bao nhi\u00eau ki-l\u00f4-gam b\u00e1nh ? B\u00e0i 11: H\u00ecnh v\u1ebd b\u00ean c\u00f3: (1 \u0111i\u1ec3m) a) \u2026 h\u00ecnh tam gi\u00e1c b) \u2026 h\u00ecnh t\u1ee9 gi\u00e1c C. B\u00c0I T\u1eacP N\u00c2NG CAO B\u00e0i 1*: Lan c\u00f3 51 que t\u00ednh. Lan c\u00f3 nhi\u1ec1u h\u01a1n H\u1ed3ng 8 que t\u00ednh. H\u1ecfi H\u1ed3ng c\u00f3 bao nhi\u00eau que t\u00ednh? B\u00e0i 2*: Em h\u00e3y v\u1ebd c\u00e1c h\u00ecnh sao cho c\u00e1i c\u00e2n th\u1ee9 ba th\u0103ng b\u1eb1ng B\u00e0i 3*: a) B\u00ecnh n\u00f3i v\u1edbi C\u01b0\u1eddng: \u201c N\u1ebfu b\u1ea1n \u0111\u01b0a t\u1edb 5 que t\u00ednh th\u00ec khi \u0111\u00f3 s\u1ed1 que t\u00ednh c\u1ee7a m\u00ecnh s\u1ebd b\u1eb1ng s\u1ed1 que t\u00ednh c\u1ee7a b\u1ea1n.\u201d H\u1ecfi C\u01b0\u1eddng c\u00f3 nhi\u1ec1u h\u01a1n B\u00ecnh bao nhi\u00eau que t\u00ednh? To\u00e1n 2-1 Page 66","b) 5 n\u0103m tr\u01b0\u1edbc, t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a An, B\u00ecnh, C\u01b0\u1eddng l\u00e0 29 tu\u1ed5i. T\u00ednh t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a 3 ng\u01b0\u1eddi hi\u1ec7n nay. B\u00e0i 4*: T\u00ecm x bi\u1ebft : a) 12 + 13 + x = 51 b) 41 \u2013 14 + x = 91 \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. \u2026\u2026\u2026\u2026\u2026. c) x + 18 = 15 + 26 d) 17 + x = 89 \u2013 18 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 B\u00e0i 5*:K\u1ebb th\u00eam 1 \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh d\u01b0\u1edbi c\u00f3 3 tam gi\u00e1c, 3 t\u1ee9 gi\u00e1c. To\u00e1n 2-1 Page 67","\u0110\u00c1P \u00c1N B\u00c0I T\u1eacP C\u01a0 B\u1ea2N Ph\u1ea7n 1 : B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : 2. B\u00e0i 1. \u0110\u00fang ghi \u0110; sai ghi S : a. Hi\u1ec7u c\u1ee7a tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 li\u1ec1n tr\u01b0\u1edbc c\u1ee7a s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 l\u00e0 81 \u0110 b. M\u1ed9t ph\u00e9p c\u1ed9ng c\u00f3 t\u1ed5ng l\u00e0 71, s\u1ed1 h\u1ea1ng th\u1ee9 nh\u1ea5t l\u00e0 8. S\u1ed1 h\u1ea1ng th\u1ee9 hai l\u00e0 79 S c. Trong h\u00ecnh v\u1ebd b\u00ean: (1 \u0111i\u1ec3m) - C\u00f3 2 h\u00ecnh tam gi\u00e1c S - C\u00f3 4 h\u00ecnh t\u1ee9 gi\u00e1c \u0110 d. T\u00ecm x bi\u1ebft : x + 15 = 41 x + 15 = 41 x + 15 = 41 x = 41 + 15 x = 41 \u2013 15 x = 56 S x = 26 \u0110 B\u00e0i 2: Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: C\u00e2u 1 2 3 4 5 6 \u0110\u00e1p \u00e1n C D A A D B 3. N\u1ed1i c\u00e1c s\u1ed1 ho\u1eb7c c\u00e1c ph\u00e9p t\u00ednh th\u00edch v\u00e0o \u00f4 tr\u1ed1ng ( 1, 5 \u0111i\u1ec3m ) 17 < < 27 4. \u0110i\u1ec1n d\u1ea5u + ho\u1eb7c \u2013 v\u00e0o \u00f4 tr\u1ed1ng \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang : 21 + 15 = 36 31 - 14 = 17 61 + 18 = 79 51 - 15 = 36 41 + 17 = 58 71 - 17 = 54 B\u00e0i 5: S\u1ed1? (2 \u0111i\u1ec3m) a) + 12 + 16 + 15 + 20 b) Ph\u1ea7n 2. B\u00e0i t\u1eadp t\u1ef1 lu\u1eadn B\u00e0i 1: T\u00ednh. 70 40 81 41 71 61 81 60 4 24 56 9 66 12 13 5 38 37 25 51 28 68 36 33 To\u00e1n 2-1 Page 68","B\u00e0i 2: \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m. 11 - 2 = 9 11 - 4 = 7 7l + 8l = 15l 11 - 4 = 7 11 \u2013 9 = 2 18kg + 4kg = 22kg 11 - 6 = 5 11- 7 = 4 5l + 3l + 8l = 16l 11 - 5 = 6 2+9-8=3 31kg - 3kg + 4kg= 32kg B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh. 11 \u2013 5 = 6 11 \u2013 9 = 2 51 \u2013 6 = 45 81 \u2013 8 = 73 81 \u2013 44 = 37 51 \u2013 25 = 26 B\u00e0i 4: T\u00ecm x. a) x + 15 = 46 b) x + 35 = 81 c) 18 + x = 61 x = 46 \u2013 15 x =81 \u2013 35 x = 61 \u2013 18 x = 31 x = 46 x = 43 B\u00e0i 5: a. S\u1ed1 h\u1ea1ng c\u1ea7n t\u00ecm l\u00e0: 51 - 19 = 32 b. S\u1ed1 h\u1ea1ng c\u1ea7n t\u00ecm l\u00e0: 61 \u2013 27 = 34 c. S\u1ed1 h\u1ea1ng c\u1ea7n t\u00ecm l\u00e0: 91- 56 = 35 B\u00e0i 6: \u0110i\u1ec1n d\u1ea5u >;=;< 35 cm = 17cm +18cm 52cm +19cm = 81cm 42cm > 71cm - 27cm 61cm - 39cm > 15cm B\u00e0i 7: B\u00e0i gi\u1ea3i Nh\u00e0 b\u1ebfp \u0111\u00e3 d\u00f9ng s\u1ed1 ki-l\u00f4-gam rau l\u00e0: 51 \u2013 25 = 26 (kg) \u0110\u00e1p s\u1ed1: 26kg rau B\u00e0i 8: B\u00e0i gi\u1ea3i \u0110\u1ed9i v\u0103n ngh\u1ec7 c\u00f3 s\u1ed1 b\u1ea1n n\u1eef l\u00e0: 31 \u2013 15 = 16 (b\u1ea1n) \u0110\u00e1p s\u1ed1: 16 b\u1ea1n n\u1eef B\u00e0i 9. B\u00e0i gi\u1ea3i C\u1eeda h\u00e0ng c\u00f2n l\u1ea1i s\u1ed1 ki-l\u00f4-gam b\u00e1nh l\u00e0: 71 \u2013 37 = 34 (kg) \u0110\u00e1p s\u1ed1: 34kg b\u00e1nh B\u00e0i 10. H\u00ecnh v\u1ebd b\u00ean c\u00f3: (1 \u0111i\u1ec3m) 4 h\u00ecnh tam gi\u00e1c 4 h\u00ecnh t\u1ee9 gi\u00e1c To\u00e1n 2-1 Page 69","\u0110\u00c1P \u00c1N B\u00c0I T\u1eacP N\u00c2NG CAO B\u00e0i 1*: Lan c\u00f3 51 que t\u00ednh. Lan c\u00f3 nhi\u1ec1u h\u01a1n H\u1ed3ng 8 que t\u00ednh. H\u1ecfi H\u1ed3ng c\u00f3 bao nhi\u00eau que t\u00ednh? B\u00e0i gi\u1ea3i H\u1ed3ng c\u00f3 s\u1ed1 que t\u00ednh l\u00e0: 51 \u2013 8 = 43 (que t\u00ednh) \u0110\u00e1p s\u1ed1\u00a0:43 que t\u00ednh B\u00e0i 2*: Em h\u00e3y v\u1ebd c\u00e1c h\u00ecnh sao cho c\u00e1i c\u00e2n th\u1ee9 ba th\u0103ng b\u1eb1ng B\u00e0i 3*: a) B\u00ecnh n\u00f3i v\u1edbi C\u01b0\u1eddng: \u201c N\u1ebfu b\u1ea1n \u0111\u01b0a t\u1edb 5 que t\u00ednh th\u00ec khi \u0111\u00f3 s\u1ed1 que t\u00ednh c\u1ee7a m\u00ecnh s\u1ebd b\u1eb1ng s\u1ed1 que t\u00ednh c\u1ee7a b\u1ea1n.\u201d H\u1ecfi C\u01b0\u1eddng c\u00f3 nhi\u1ec1u h\u01a1n B\u00ecnh bao nhi\u00eau que t\u00ednh? B\u00e0i gi\u1ea3i Ta c\u00f3 s\u01a1 \u0111\u1ed3 bi\u1ec3u th\u1ecb s\u1ed1 que t\u00ednh c\u1ee7a hai b\u1ea1n sau khi C\u01b0\u1eddng \u0111\u01b0a cho B\u00ecnh 5 que t\u00ednh S\u1ed1 que t\u00ednh c\u1ee7a B\u00ecnh: S\u1ed1 que t\u00ednh c\u1ee7a C\u01b0\u1eddng: Nh\u00ecn v\u00e0o s\u01a1 \u0111\u1ed3 ta th\u1ea5y, C\u01b0\u1eddng c\u00f3 nhi\u1ec1u h\u01a1n B\u00ecnh s\u1ed1 vi\u00ean bi l\u00e0: 5 + 5 = 10( vi\u00ean) \u0110\u00e1p s\u1ed1: 10 vi\u00ean bi b) 5 n\u0103m tr\u01b0\u1edbc, t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a An, B\u00ecnh, C\u01b0\u1eddng l\u00e0 29 tu\u1ed5i. T\u00ednh t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a 3 ng\u01b0\u1eddi hi\u1ec7n nay. Sau 5 n\u0103m, c\u1ea3 ba b\u1ea1n m\u1ed7i b\u1ea1n \u0111\u1ec1u t\u0103ng 5 tu\u1ed5i V\u1eady t\u1ed5ng s\u1ed1 tu\u1ed5i c\u1ee7a ba ng\u01b0\u1eddi hi\u1ec7n nay l\u00e0: 29 + 5 + 5 + 5 = 44 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 44 tu\u1ed5i B\u00e0i 4*: T\u00ecm x bi\u1ebft : 12 + 13 + x = 51 41 \u2013 14 + x = 91 To\u00e1n 2-1 Page 70","25 + x =51 27 + x = 91 x = 51 \u2013 25 x =91 \u2013 27 x = 26 x = 64 x + 18 = 15 + 26 17 + x = 89 \u2013 18 x + 18 = 41 17 + x = 71 x = 41 \u2013 18 x = 71 \u2013 17 x = 23 x = 54 B\u00e0i 5*:K\u1ebb th\u00eam 1 \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh d\u01b0\u1edbi c\u00f3 3 tam gi\u00e1c, 3 t\u1ee9 gi\u00e1c. To\u00e1n 2-1 Page 71","M\u1ed8T S\u1ed0 \u0110\u1ec0 THI \u00d4N T\u1eacP GI\u1eeeA H\u1eccC K\u1ef2 1 \u0110\u1ec0 1 B\u00e0i 1. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau 45 79 60 99 B\u00e0i 2. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh t\u1ed5ng, bi\u1ebft c\u00e1c s\u1ed1 h\u1ea1ng l\u00e0: 27 v\u00e0 39 16 v\u00e0 54 45 v\u00e0 27 36 v\u00e0 28 B\u00e0i 3. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: d) a) b) c) B\u00e0i 4. Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a. S\u1ed1 h\u00ecnh tam gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 2 B. 3 C. 4 a. S\u1ed1 h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 1 B. 2 C. 3 D. 4 B\u00e0i 5. T\u00ednh: a) 34l + 26l = \u2026\u2026\u2026. b) 12l + 39l = \u2026\u2026\u2026. c) 48kg + 27kg = \u2026\u2026\u2026. d) 38kg + 25kg = \u2026\u2026\u2026. B\u00e0i 6. Anh Quang n\u1eb7ng 52kg, anh Qu\u00e2n n\u1eb7ng h\u01a1n anh Quang 9kg. H\u1ecfi anh Qu\u00e2n n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam? To\u00e1n 2-1 Page 72","B\u00e0i 7. Th\u00f9ng to \u0111\u1ef1ng 55l d\u1ea7u, th\u00f9ng b\u00e9 \u0111\u1ef1ng 45l d\u1ea7u. H\u1ecfi c\u1ea3 hai th\u00f9ng \u0111\u1ef1ng \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u? To\u00e1n 2-1 Page 73","To\u00e1n 2-1 Page 74","\u0110\u1ec0 2 B\u00e0i 1. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: B\u00e0i 2. Vi\u1ebft s\u1ed1 ho\u1eb7c c\u00e1ch \u0111\u1ecdc s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 \u2026\u2026\u2026\u2026\u2026 B\u1ed1n m\u01b0\u01a1i b\u1ea3y 51 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. B\u00e0i 3. S\u1ed1? a) b) c) d) B\u00e0i 4. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 36 + 34 49 + 27 38 + 16 57 + 25 B\u00e0i 5. N\u1ed1i 5 \u0111i\u1ec3m cho tr\u01b0\u1edbc A, B, C, D, E d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 c\u00f3 m\u1ed9t h\u00ecnh ch\u1eef nh\u1eadt v\u00e0 2 h\u00ecnh tam gi\u00e1c A .B E DC B\u00e0i 6. Bu\u1ed5i s\u00e1ng b\u00e1c Ti\u1ebfn b\u00e1n \u0111\u01b0\u1ee3c 45kg g\u1ea1o, bu\u1ed5i chi\u1ec1u b\u00e1c Ti\u1ebfn b\u00e1n \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n bu\u1ed5i s\u00e1ng 9kg g\u1ea1o. H\u1ecfi bu\u1ed5i chi\u1ec1u b\u00e1c Ti\u1ebfn b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ki-l\u00f4-gam g\u1ea1o? To\u00e1n 2-1 Page 75","B\u00e0i 7. Can xanh c\u00f3 27l x\u0103ng, can tr\u1eafng c\u00f3 \u00edt h\u01a1n can xanh 12l x\u0103ng . H\u1ecfi can tr\u1eafng c\u00f3 bao nhi\u00eau l\u00edt x\u0103ng? B\u00e0i 8. \u0110i\u1ec1n c\u00e1c ch\u1eef s\u1ed1 2, 5, 7, 8 v\u00e0o \u00f4 tr\u1ed1ng \u0111\u1ec3 \u0111\u01b0\u1ee3c ph\u00e9p t\u00ednh \u0111\u00fang: To\u00e1n 2-1 Page 76","\u0110\u1ec0 3 B\u00e0i 1. \u0110i\u1ec1n d\u1ea5u (>, =, <) th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: a) 10 \uf063 11 a) 50 \uf063 49 c) 50 \uf063 57 \uf063 57 d) 90 \uf063 89 \uf063 88 B\u00e0i 2. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: S\u1ed1 li\u1ec1n tr\u01b0\u1edbc S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 39 \u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026 70 B\u00e0i 3. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: a) 9 + 8 = 16 \uf063 b) 8 + 7 = 15 \uf063 c) 49 + 46 = 85 \uf063 c) 48 + 47 = 95 \uf063 B\u00e0i 4. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 27 + 26 59 + 23 48 + 17 65 + 28 B\u00e0i 5. Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: H\u00ecnh v\u1ebd b\u00ean c\u00f3: A. 1 h\u00ecnh ch\u1eef nh\u1eadt. B. 2 h\u00ecnh ch\u1eef nh\u1eadt. C. 3 h\u00ecnh ch\u1eef nh\u1eadt. D. 4 h\u00ecnh ch\u1eef nh\u1eadt. B\u00e0i 6. Bao ng\u00f4 n\u1eb7ng 58kg, bao l\u1ea1c nh\u1eb9 h\u01a1n bao ng\u00f4 14kg. H\u1ecfi bao l\u1ea1c n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam? To\u00e1n 2-1 Page 77","B\u00e0i 7. Th\u00f9ng x\u0103ng xe \u00f4 t\u00f4 con ch\u1ee9a \u0111\u01b0\u1ee3c 47l x\u0103ng, th\u00f9ng x\u0103ng xe \u00f4 t\u00f4 t\u1ea3i ch\u1ee9a \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n th\u00f9ng x\u0103ng xe \u00f4 t\u00f4 con 35l x\u0103ng. H\u1ecfi th\u00f9ng x\u0103ng xe \u00f4 t\u00f4 t\u1ea3i ch\u1ee9a \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt x\u0103ng? B\u00e0i 8. T\u00ecm x b) 23 + x = 59 a) x \u2013 14 = 32 To\u00e1n 2-1 Page 78","To\u00e1n 2-1 Page 79","\u0110\u1ec0 4 B\u00e0i 1. Vi\u1ebft s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 75 t\u00e1m m\u01b0\u01a1i ch\u00edn 55 ch\u00edn m\u01b0\u01a1i t\u00e1m 91 B\u00e0i 2. T\u00ednh: 8 + 7 = \u2026\u2026.. 9 + 6 = \u2026\u2026.. 3 + 8 = \u2026\u2026.. 4 + 9 = \u2026\u2026.. 7 + 7 = \u2026\u2026.. 6 + 5 = \u2026\u2026.. 8 + 6 = \u2026\u2026.. 2 + 8 = \u2026\u2026.. 6 + 6 = \u2026\u2026.. d) B\u00e0i 3. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: a) b) c) B\u00e0i 4. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 28 + 15 19 + 15 47 + 19 36 + 17 38 + 7 66 + 8 77 + 8 46 + 54 B\u00e0i 5. N\u0103m nay m\u1eb9 36 tu\u1ed5i, b\u1ed1 h\u01a1n m\u1eb9 8 tu\u1ed5i. H\u1ecfi n\u0103m nay b\u1ed1 bao nhi\u00eau tu\u1ed5i? To\u00e1n 2-1 Page 80","B\u00e0i 6. Con l\u1ee3n \u0111en c\u00e2n n\u1eb7ng 57kg, con l\u1ee3n tr\u1eafng nh\u1eb9 h\u01a1n con l\u1ee3n \u0111en 6kg. H\u1ecfi con l\u1ee3n tr\u1eafng c\u00e2n n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam? B\u00e0i 7. S\u1ed1? H\u00ecnh b\u00ean c\u00f3: a. \u2026\u2026 h\u00ecnh ch\u1eef nh\u1eadt. b. \u2026\u2026. \u0111o\u1ea1n th\u1eb3ng. To\u00e1n 2-1 Page 81","\u0110\u1ec0 5 B\u00e0i 1. S\u1ed1? S\u1ed1 li\u1ec1n tr\u01b0\u1edbc S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau 55 v\u00e0 27 65 89 20 90 B\u00e0i 2. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh t\u1ed5ng, bi\u1ebft c\u00e1c s\u1ed1 h\u1ea1ng l\u00e0: 29 v\u00e0 34 46 v\u00e0 17 28 v\u00e0 33 57 v\u00e0 9 26 v\u00e0 36 23 v\u00e0 19 22 v\u00e0 78 B\u00e0i 3. 18 + 7 \uf063 24 22 + 8 \uf063 30 49 + 9 \uf063 60 34 + 9 \uf063 44 34 + 7 \uf063 40 58 + 18 \uf063 75 69 + 9 \uf063 76 66 + 34 \uf063 100 B\u00e0i 4. Gi\u1ea3i b\u00e0i to\u00e1n theo t\u00f3m t\u1eaft sau: Ng\u0103n tr\u00ean Ng\u0103n d\u01b0\u1edbi To\u00e1n 2-1 Page 82","B\u00e0i 5. Quy\u1ec3n truy\u1ec7n c\u1ee7a Qu\u00e2n d\u00e0y 56 trang, quy\u1ec3n truy\u1ec7n c\u1ee7a Quang d\u00e0y h\u01a1n quy\u1ec3n truy\u1ec7n c\u1ee7a Qu\u00e2n 16 trang. H\u1ecfi quy\u1ec3n truy\u1ec7n c\u1ee7a Quang d\u00e0y bao nhi\u00eau trang? B\u00e0i 6. S\u1ed1 ? H\u00ecnh b\u00ean c\u00f3: \u2026. h\u00ecnh tam gi\u00e1c v\u00e0 \u2026 h\u00ecnh t\u1ee9 gi\u00e1c. B\u00e0i 7. a) Vi\u1ebft s\u1ed1 tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1. b) T\u00ednh t\u1ed5ng c\u1ee7a hai s\u1ed1 \u0111\u00f3. c) T\u00ednh hi\u1ec7u c\u1ee7a hai s\u1ed1 \u0111\u00f3. To\u00e1n 2-1 Page 83","To\u00e1n 2-1 Page 84","\u0110\u1ec0 6 B\u00e0i 1. a) H\u00e3y vi\u1ebft t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 gi\u1ed1ng nhau: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) H\u00e3y \u0111\u1ecdc c\u00e1c s\u1ed1 v\u1eeba vi\u1ebft: B\u00e0i 2. S\u1ed1? B\u00e0i 3. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: d) a) b) c) B\u00e0i 4. T\u00ednh: 29l + 17l = \u2026\u2026\u2026. 47l + 26l = \u2026\u2026\u2026. 38l + 35l = \u2026\u2026\u2026. 56l + 16l = \u2026\u2026\u2026. 71kg + 29kg = \u2026\u2026\u2026. 15kg + 25kg = \u2026\u2026\u2026. 67kg + 8kg = \u2026\u2026\u2026. 27kg + 73kg = \u2026\u2026\u2026. B\u00e0i 5. Khoanh v\u00e0o ch\u1eef \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: a) S\u1ed1 h\u00ecnh tam gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 2 h\u00ecnh B. 3 h\u00ecnh To\u00e1n 2-1 Page 85","C. 4 h\u00ecnh D. 5 h\u00ecnh b) S\u1ed1 h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 5 h\u00ecnh B. 4 h\u00ecnh C. 3 h\u00ecnh D. 2 h\u00ecnh B\u00e0i 6. \u0110o\u1ea1n th\u1eb3ng AB d\u00e0i 3dm 8cm, \u0111o\u1ea1n th\u1eb3ng CD ng\u1eafn h\u01a1n \u0111o\u1ea1n th\u1eb3ng AB 4cm. H\u1ecfi \u0111o\u1ea1n th\u1eb3ng CD d\u00e0i bao nhi\u00eau x\u0103ng-ti-m\u00e9t? B\u00e0i 7. T\u1ed5ng c\u1ee7a hai s\u1ed1 l\u00e0 57. Khi th\u00eam v\u00e0o s\u1ed1 b\u00e9 9 \u0111\u01a1n v\u1ecb v\u00e0 b\u1edbt \u1edf s\u1ed1 l\u1edbn \u0111i 5 \u0111\u01a1n v\u1ecb th\u00ec t\u1ed5ng hai s\u1ed1 m\u1edbi l\u00e0 bao nhi\u00eau? To\u00e1n 2-1 Page 86","\u0110\u1ec0 7 B\u00e0i 1. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: a) S\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 l\u00e0 \u2026\u2026.. b) S\u1ed1 li\u1ec1n sau s\u1ed1 73 l\u00e0 \u2026\u2026.., s\u1ed1 li\u1ec1n tr\u01b0\u1edbc s\u1ed1 73 l\u00e0 \u2026\u2026.. c) S\u1ed1 l\u1edbn h\u01a1n 75 nh\u01b0ng nh\u1ecf h\u01a1n 77 l\u00e0 \u2026\u2026.. d) S\u1ed1 nh\u1ecf h\u01a1n 88 nh\u01b0ng l\u1edbn h\u01a1n 86 l\u00e0 \u2026\u2026.. B\u00e0i 2. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh t\u1ed5ng, bi\u1ebft c\u00e1c s\u1ed1 h\u1ea1ng l\u00e0: 15 v\u00e0 35 67 v\u00e0 26 78 v\u00e0 13 59 v\u00e0 22 44 v\u00e0 19 26 v\u00e0 28 63 v\u00e0 37 21 v\u00e0 79 B\u00e0i 3. T\u00ednh (theo m\u1eabu): M\u1eabu: 56kg + 17kg \u2013 21kg = 73kg \u2013 21kg = 52kg a) 29kg + 17kg \u2013 5kg = \u2026\u2026\u2026. b) 57kg \u2013 12kg + 9kg = \u2026\u2026\u2026. = \u2026\u2026\u2026. = \u2026\u2026\u2026. c) 48l + 17l \u2013 12l = \u2026\u2026\u2026. d) 52l + 15l \u2013 24l = \u2026\u2026\u2026. = \u2026\u2026\u2026. = \u2026\u2026\u2026. B\u00e0i 4. N\u0103m nay b\u00e1c H\u1ed3ng 48 tu\u1ed5i, c\u00f4 Hoa k\u00e9m b\u00e1c H\u1ed3ng 14 tu\u1ed5i. H\u1ecfi n\u0103m nay c\u00f4 Hoa bao nhi\u00eau tu\u1ed5i? To\u00e1n 2-1 Page 87","B\u00e0i 5. M\u1ed9t c\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 17 chi\u1ebfc qu\u1ea1t \u0111i\u1ec7n, bu\u1ed5i chi\u1ec1u b\u00e1n \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n bu\u1ed5i s\u00e1ng 8 chi\u1ebfc qu\u1ea1t \u0111i\u1ec7n. H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau chi\u1ebfc qu\u1ea1t \u0111i\u1ec7n? B\u00e0i 6. Cho h\u00ecnh v\u1ebd b\u00ean: a) C\u00f3 \u2026\u2026 h\u00ecnh ch\u1eef nh\u1eadt. b) H\u00e3y k\u1ebb th\u00eam m\u1ed9t \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh b\u00ean c\u00f3 t\u1ea5t c\u1ea3 5 h\u00ecnh ch\u1eef nh\u1eadt. B\u00e0i 7. V\u1edbi m\u1ed9t can 5 l\u00edt v\u00e0 m\u1ed9t can 2 l\u00edt, l\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 \u0111ong \u0111\u01b0\u1ee3c 3 l\u00edt d\u1ea7u? To\u00e1n 2-1 Page 88","\u0110\u1ec0 8 B\u00e0i 1. a) Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: b) Vi\u1ebft c\u00e1c s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 m\u00e0 ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb l\u00e0 5 theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026..\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. B\u00e0i 2. T\u00ednh nh\u1ea9m: 30 + 40 =\u2026\u2026 35 + 50 =\u2026\u2026 10 + 67 =\u2026\u2026 50 + 100 =\u2026\u2026 36 + 4 + 20 =\u2026\u2026 52 + 8 + 40 =\u2026\u2026 11 + 9 + 80 =\u2026\u2026 40 + 6 + 10 =\u2026\u2026 B\u00e0i 3. 77 + 7 \uf063 85 22 + 77 \uf063 100 47 + 53 \uf063 100 55 + 9 \uf063 64 4 + 59 \uf063 62 88 + 6 \uf063 95 40 + 50 \uf063 89 69 + 25 \uf063 92 B\u00e0i 4. B\u00e9 Mai cao 8dm 5cm, b\u00e9 H\u00e0 cao h\u01a1n b\u00e9 Mai 9cm. H\u1ecfi b\u00e9 H\u00e0 cao bao nhi\u00eau x\u0103ng-ti-m\u00e9t? To\u00e1n 2-1 Page 89","B\u00e0i 5. S\u1ed1? To\u00e1n 2-1 Page 90","B\u00e0i 6. M\u1ed9t th\u00f9ng ch\u1ee9a 97l d\u1ea7u, ng\u01b0\u1eddi ta r\u00f3t ra 45l d\u1ea7u. H\u1ecfi trong th\u00f9ng c\u00f2n l\u1ea1i bao nhi\u00eau l\u00edt d\u1ea7u? B\u00e0i 7. Cho h\u00ecnh v\u1ebd b\u00ean: a) C\u00f3 \u2026\u2026 h\u00ecnh ch\u1eef nh\u1eadt. b) H\u00e3y k\u1ebb th\u00eam m\u1ed9t \u0111o\u1ea1n th\u1eb3ng \u0111\u1ec3 h\u00ecnh b\u00ean c\u00f3 th\u00eam 2 h\u00ecnh ch\u1eef nh\u1eadt n\u1eefa. To\u00e1n 2-1 Page 91","To\u00e1n 2-1 Page 92","\u0110\u1ec0 9 Ph\u1ea7n 1. Tr\u1eafc nghi\u1ec7m (3 \u0111). Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. C\u00e1c s\u1ed1 tr\u00f2n ch\u1ee5c nh\u1ecf h\u01a1n 50 l\u00e0: A. 10; 20; 30; 50 B. 10 ; 20; 30; 40 C. 0; 10; 20; 30 D. 20; 10; 30; 50 2. S\u1ed1 th\u00edch h\u1ee3p vi\u1ebft v\u00e0o ch\u1ed7 ch\u1ea5m cho \u0111\u00fang th\u1ee9 t\u1ef1: 90 ; \u2026\u2026.. ; \u2026\u2026.. ; 87 l\u00e0: A. 91; 92 B. 88; 89 C. 89; 88 D. 98 ; 97 3. H\u00ecnh v\u1ebd b\u00ean c\u00f3: A. 2 h\u00ecnh t\u1ee9 gi\u00e1c B. 3 h\u00ecnh t\u1ee9 gi\u00e1c C. 4 h\u00ecnh t\u1ee9 gi\u00e1c D. 5 h\u00ecnh t\u1ee9 gi\u00e1c 4. 90 cm = \u2026.. dm . S\u1ed1 th\u00edch h\u1ee3p vi\u1ebft v\u00e0o ch\u1ed7\u2026\u2026l\u00e0: A. 10 B. 90 C. 8 D. 9 5. Trong b\u00e3i c\u00f3 58 chi\u1ebfc xe t\u1ea3i. C\u00f3 38 chi\u1ebfc r\u1eddi b\u00e3i. S\u1ed1 xe t\u1ea3i c\u00f2n l\u1ea1i trong b\u00e3i l\u00e0: A. 20 chi\u1ebfc B. 96 chi\u1ebfc C. 30 chi\u1ebfc D. 26 chi\u1ebfc 6. 40 cm \u2026\u2026 40 dm. D\u1ea5u th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. > B. < C. = Ph\u1ea7n 2. (7 \u0111) T\u1ef1 lu\u1eadn B\u00e0i 1. (2 \u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 8 + 78 99 - 57 28 + 17 49 + 26 B\u00e0i 2. (1 \u0111) T\u00ednh: 67 cm + 15 cm 90 kg - 30 kg + 26 kg B\u00e0i 3. (1 \u0111) T\u00ecm Y Y + 27 = 59 54 + Y = 79 B\u00e0i 4. (2 \u0111) Th\u00f9ng th\u1ee9 nh\u1ea5t ch\u1ee9a 35 l\u00edt d\u1ea7u. Th\u00f9ng th\u1ee9 hai ch\u1ee9a nhi\u1ec1u h\u01a1n th\u00f9ng To\u00e1n 2-1 Page 93","th\u1ee9 nh\u1ea5t 15 l\u00edt d\u1ea7u. H\u1ecfi th\u00f9ng th\u1ee9 hai ch\u1ee9a \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u? B\u00e0i 5. (1 \u0111) S\u1ed1 n\u00e0o ? To\u00e1n 2-1 Page 94","\u0110\u1ec0 10 A- Ph\u1ea7n ki\u1ec3m tra tr\u1eafc nghi\u1ec7m. C\u00e2u 1. Trong ph\u00e9p t\u00ednh 3 x 6 = 18 c\u00f3: A. 3 l\u00e0 th\u1eeba s\u1ed1, 6 l\u00e0 th\u1eeba s\u1ed1, 18 l\u00e0 t\u00edch. B. 3 l\u00e0 th\u1eeba s\u1ed1, 18 l\u00e0 th\u1eeba s\u1ed1, 6 l\u00e0 t\u00edch. C. 3 l\u00e0 s\u1ed1 h\u1ea1ng, 6 l\u00e0 s\u1ed1 h\u1ea1ng, 18 l\u00e0 t\u1ed5ng. C\u00e2u 2. T\u00edch c\u1ee7a 4 v\u00e0 9 l\u00e0: A. 32. B. 13 C. 36. D. 31 C\u00e2u 3. Hi\u1ec7u c\u1ee7a 35 v\u00e0 16 l\u00e0: A. 9. B. 19 C. 29. D. 51 C\u00e2u 4. M\u1ed9t tu\u1ea7n c\u00f3\u2026\u2026ng\u00e0y: A. 24 B. 10 C. 7 D. 30 C\u00e2u 5: C\u00e1c s\u1ed1 33, 54, 45 v\u00e0 28 \u0111\u01b0\u1ee3c x\u1ebfp theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn l\u00e0: A. 45, 54, 33, 28 . B. 28, 33, 45, 54. C. 45, 54, 28, 33. D. 33, 28, 45, 54 C\u00e2u 6: S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o d\u00e3y s\u1ed1 : 3, 6, 9, 12,\u2026.,.18, 21 l\u00e0: A. 13. B. 14 C. 15. D. 17 C\u00e2u 7. Y x 4 = 12 A.Y = 8 B. Y = 4 C. Y = 3 D. Y= 16 C\u00e2u 8. Xem t\u1edd l\u1ecbch sau: Th\u1ee9 hai Th\u1ee9 ba Th\u1ee9 t\u01b0 Th\u1ee9 Th\u1ee9 s\u00e1u Th\u1ee9 b\u1ea9y Ch\u1ee7 n\u0103m nh\u1eadt 1 2 34 5 6 7 8 9 10 11 5 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 - Ng\u00e0y 19 th\u00e1ng 5 l\u00e0 th\u1ee9 m\u1ea5y A. Th\u1ee9 hai B. Th\u1ee9 ba C. Th\u1ee9 s\u00e1u D. Th\u1ee9 b\u1ea9y C\u00e2u 9. Hi\u1ec7u c\u1ee7a s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 1 ch\u1eef s\u1ed1 l\u00e0: A. 99. B. 10 C. 9. D. 90 C\u00e2u 10. Chu vi c\u1ee7a m\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh: 1 cm; 2 cm; 3 cm; 4 cm l\u00e0: A. 9 cm B. 8 cm C. 10 cm D. 7 cm C\u00e2u11. Chu vi c\u1ee7a m\u1ed9t h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh: 4 cm; 2 cm; 3 cm l\u00e0: A. 8 cm B. 9 cm C. 10 cm To\u00e1n 2-1 Page 95","C\u00e2u 12. C\u00f3 30 chi\u1ebfc gh\u1ebf chia \u0111\u1ec1u th\u00e0nh 5 h\u00e0ng. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 m\u1ea5y chi\u1ebfc gh\u1ebf ? A. 5 chi\u1ebfc B. 6 chi\u1ebfc C. 7 chi\u1ebfc D. 4 chi\u1ebfc C\u00e2u 13. H\u00ecnh n\u00e0o sau \u0111\u00e2y s\u1ed1 \u00f4 vu\u00f4ng \u0111\u01b0\u1ee3c t\u00f4 m\u00e0u: AB C D B -Ph\u1ea7n ki\u1ec3m tra t\u1ef1 lu\u1eadn C\u00e2u 1. T\u00ednh nh\u1ea9m : 3 x 4 =........... 5 x 4 =.............. 5 x 7 =........... 4 x 5 =.............. 5 x 3 =............ 28 : 4 =........... 5 : 1 =.............. 4 x 9 =............ 24 : 3 =........... 0 : 5 =............... 15 : 3 =............ 45 : 5 = ........... b) 6 : 3 x 5 = C\u00e2u 2. T\u00ednh a) 5 x 6 : 3 = C\u00e2u 3. T\u00ecm X b) 3 + X = 15 a) X x 2 = 6 C\u00e2u 4. M\u1ed7i h\u1ecdc sinh \u0111\u01b0\u1ee3c m\u01b0\u1ee3n 5 quy\u1ec3n truy\u1ec7n. H\u1ecfi 8 h\u1ecdc sinh \u0111\u01b0\u1ee3c m\u01b0\u1ee3n bao nhi\u00eau quy\u1ec3n truy\u1ec7n. To\u00e1n 2-1 Page 96","To\u00e1n 2-1 Page 97","C\u00e2u 5. Con l\u1ee3n th\u1ee9 nh\u1ea5t n\u1eb7ng 78 kg. Nh\u01b0 v\u1eady k\u00e9m con l\u1ee3n th\u1ee9 hai l\u00e0 15 kg. H\u1ecfi con l\u1ee3n th\u1ee9 hai n\u1eb7ng bao nhi\u00eau ki-l\u00f4-gam ? To\u00e1n 2-1 Page 98","\u0110\u1ec0 11 C\u00e2u 1. Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: a\/ 46 ; 48 ; 50 ; \u2026\u2026..; \u2026\u2026\u2026; \u2026\u2026\u2026.; \u2026\u2026\u2026.; 60. b\/ 39 ; 40 ; 41 ; \u2026\u2026..; \u2026\u2026\u2026; \u2026\u2026\u2026.; \u2026\u2026\u2026.; 45. C\u00e2u 2. Vi\u1ebft s\u1ed1 li\u1ec1n tr\u01b0\u1edbc, li\u1ec1n sau v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: S\u1ed1 \u0111\u00e3 cho S\u1ed1 li\u1ec1n sau S\u1ed1 li\u1ec1n tr\u01b0\u1edbc \u2026\u2026\u2026\u2026\u2026\u2026\u2026. 35 \u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026\u2026\u2026 90 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 S\u1ed1 b\u1ecb tr\u1eeb 29 79 S\u1ed1 tr\u1eeb 7 70 Hi\u1ec7u ? a\/ C\u00e2u 3. C\u00e2u 4. \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: (1 \u0111i\u1ec3m) a\/ 8 + 6 = 15 b\/ 8 + 8 = 16 c\/ 8 + 2 + 9 = 19 d\/ 35 + 3 > 58 C\u00e2u 5. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2 \u0111i\u1ec3m) 47 + 24 56 + 31 78 \u2013 56 58 \u2013 17 C\u00e2u 6. Gi\u1ea3i to\u00e1n: (2 \u0111i\u1ec3m) a\/ M\u1eb9 h\u00e1i \u0111\u01b0\u1ee3c 37 qu\u1ea3 b\u01b0\u1edfi, ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c 18 qu\u1ea3 b\u01b0\u1edfi. H\u1ecfi m\u1eb9 v\u00e0 ch\u1ecb h\u00e1i \u0111\u01b0\u1ee3c t\u1ea5t c\u1ea3 bao nhi\u00eau qu\u1ea3 b\u01b0\u1edfi? B\u00e0i l\u00e0m ................................................................ ................................................................ ................................................................ ................................................................ b\/ M\u1ed9t l\u1edbp h\u1ecdc c\u00f3 33 h\u1ecdc sinh, trong \u0111\u00f3 c\u00f3 20 h\u1ecdc sinh nam. H\u1ecfi l\u1edbp h\u1ecdc \u0111\u00f3 c\u00f3 bao nhi\u00eau h\u1ecdc sinh n\u1eef? ................................................................ ................................................................","................................................................ ................................................................ To\u00e1n 2-1 Page 100"]


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