Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

["\u0110\u1ec0 S\u1ed0 9 PH\u00c2\u0300N I: TR\u1eaeC NGHI\u1ec6M (3,5\u0111) Khoanh va\u0300o ch\u01b0\u0303 ca\u0301i \u0111\u0103\u0323t tr\u01b0\u01a1\u0301c c\u00e2u tra\u0309 l\u01a1\u0300i \u0111u\u0301ng nh\u00e2\u0301t: C\u00e2u 1. (0,5\u0111) H\u00ecnh n\u00e0o \u0111\u00e3 t\u00f4 m\u00e0u s\u1ed1 \u00f4 vu\u00f4ng: \u2026...\/ A. B. C. D. D. 1000 C\u00e2u 2. (0,5\u0111) S\u1ed1 th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: 1 m = \u2026 mm D. 8 ngh\u00ecn A. 10 B. 100 C. 1 C\u00e2u 3. (0,5\u0111) Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 8 trong s\u1ed1 584 l\u00e0: A. 8 \u0111\u01a1n v\u1ecb B. 8 tr\u0103m C. 8 ch\u1ee5c C\u00e2u 4. (1\u0111) \u0110\u1ed3ng h\u1ed3 b\u00ean ch\u1ec9 m\u1ea5y gi\u1edd : A. 9 gi\u1edd 15 ph\u00fat B. 10 gi\u1edd 30 ph\u00fat C. 10 gi\u1edd 3 ph\u00fat D. 9 gi\u1edd 3 ph\u00fat C\u00e2u 5. (1\u0111) \u0110i\u1ec1n d\u1ea5u >,<,= th\u00edch h\u1ee3p v\u00e0o ch\u1ed5 tr\u1ed1ng : 2m 20 cm 360 \u2013 10 350 PH\u1ea6N II: T\u1ef0 LU\u1eacN C\u00e2u 1. (2\u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: a) 541 + 243 b) 957 \u2013 431 c) 42 + 29 d) 100 \u2013 43 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2: (1\u0111) a, T\u00ecm x : b, T\u00ednh 81 \u2013 x = 19 5 x 8 - 20 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 3. (1,5\u0111) T\u00ednh \u0111\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac ABCDE sau : BD AC E B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 401","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 4. (2\u0111) M\u1ed9t thanh k\u1ebdm \u0111\u01b0\u1ee3c b\u1ed1 u\u1ed1n th\u00e0nh khung h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh \u0111\u1ec1u b\u1eb1ng 2dm. H\u1ecfi thanh k\u1ebdm ph\u1ea3i d\u00e0i bao nhi\u00eau \u0111\u1ec1 - xi \u2013 m\u00e9t \u0111\u1ec3 u\u1ed1n \u0111\u1ee7 th\u00e0nh khung h\u00ecnh tam gi\u00e1c? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 402","\u0110\u1ec0 S\u1ed0 10 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4 \u0111i\u1ec3m): C\u00e2u 1 (2 \u0111i\u1ec3m): H\u00e3y khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t. a) Cho 345 \u2026 300 + 54. D\u1ea5u th\u00edch h\u1ee3p \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. > B. < C. = D. + b) Cho 213 + y = 567. Gi\u00e1 tr\u1ecb c\u1ee7a y l\u00e0: A. 354 B. 880 C. 345 D. 754 c) K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh 352 + 443 l\u00e0: A. 785 B. 795 C. 885 d) H\u00ecnh v\u1ebd b\u00ean c\u00f3 ...... h\u00ecnh tam gi\u00e1c. A. 5 B. 6 C. 4. D. 7 C\u00e2u 2.\u0110\u00fang \u0111i\u1ec1n \u0110, sai \u0111i\u1ec1n S v\u00e0o cu\u1ed1i m\u1ed7i d\u00f2ng sau (1 \u0111i\u1ec3m) : Trong ph\u00e9p t\u00ednh 18 : 3 = 6, th\u00ec : a) S\u1ed1 18 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 s\u1ed1 chia. \u25a1 b) S\u1ed1 3 g\u1ecdi l\u00e0 s\u1ed1 b\u1ecb chia. \u25a1 c) \u201c18 : 3\u201d \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 th\u01b0\u01a1ng. \u25a1 d) S\u1ed1 6 g\u1ecdi l\u00e0 th\u01b0\u01a1ng \u25a1 C\u00e2u 3. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m (1 \u0111i\u1ec3m): a) S\u1ed1 209 g\u1ed3m \u2026 tr\u0103m \u2026 ch\u1ee5c \u2026 \u0111\u01a1n v\u1ecb. b) S\u1ed1 g\u1ed3m 6 tr\u0103m 5 ch\u1ee5c 7 \u0111\u01a1n v\u1ecb vi\u1ebft s\u1ed1 l\u00e0 \u2026\u2026 PH\u1ea6N II: T\u1ef0 LU\u1eacN (6 \u0111i\u1ec3m) : C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2 \u0111i\u1ec3m): 48 + 27 95 \u2013 68 516 + 238 802 \u2013 539 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2. a) T\u00ednh (1 \u0111i\u1ec3m) : 0 : 4 x 24 = 5 x 1 + 38 = b) T\u00ecm y (1 \u0111i\u1ec3m): yx5=0 67 \u2013 y = 19 Page 403 To\u00e1n 2-1","C\u00e2u 3. (1 \u0111i\u1ec3m) C\u00f3 m\u1ed9t s\u1ed1 g\u1ea1o, n\u1ebfu \u0111\u1ef1ng v\u00e0o m\u1ed7i t\u00fai 4 kg th\u00ec \u0111\u01b0\u1ee3c 9 t\u00fai. T\u00ednh s\u1ed1 l\u01b0\u1ee3ng g\u1ea1o \u0111\u00f3. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 4. (1\u0111i\u1ec3m) T\u00ecm t\u1ed5ng c\u1ee7a s\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 kh\u00e1c nhau. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 404","To\u00e1n 2-1 Page 405","\u0110\u00c1P AN \u0110\u1ec0 THI CU\u1ed0I H\u1eccC K\u00cc II \u0110\u1ec0 S\u1ed0 1 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (3,5\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: C\u00e2u 1 2 3 4 5 6 7 \u0110\u00e1p \u00e1n B C D C D C C PH\u1ea6N II: T\u1ef0 LU\u1eacN (6,5\u0111) B\u00e0i 2.\u0110i\u1ec1n d\u1ea5u th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: (1\u0111i\u1ec3m) 1km > 999m 13mm > 15mm \u2013 1cm B\u00e0i 3. T\u00ecm y(1\u0111i\u1ec3m) y=6 y = 24 B\u00e0i 4.C\u00f3 40 qu\u1ea3 t\u00e1o b\u00e0y v\u00e0o c\u00e1c \u0111\u0129a, m\u1ed7i \u0111\u0129a 5 qu\u1ea3. H\u1ecfi c\u00f3 bao nhi\u00eau \u0111\u0129a t\u00e1o?(1,5\u0111i\u1ec3m) C\u00f3 s\u1ed1 \u0111\u0129a t\u00e1o l\u00e0: 40 : 5 = 8 (c\u00e1i \u0111\u0129a) \u0110\u00e1p s\u1ed1: 8 c\u00e1i \u0111\u0129a B\u00e0i 5.T\u1ed5ng c\u1ee7a s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 kh\u00e1c nhau v\u00e0 s\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 bao nhi\u00eau?(1\u0111i\u1ec3m) S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 kh\u00e1c nhau l\u00e0 98 S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 900 T\u1ed5ng hai s\u1ed1 l\u00e0: 98 + 900 = 998 \u0110\u00e1p s\u1ed1: 998 To\u00e1n 2-1 Page 406","\u0110\u1ec0 S\u1ed0 2 PH\u1ea6N 1. TR\u1eaeC NGHI\u1ec6M (6 \u0111) C\u00e2u 1(4 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang C\u00e2u 1 2 3 4 5 6 7 \u0110\u00e1p \u00e1n B D C A A,B C D C\u00e2u 2. (1 \u0111) \u0110i\u1ec1n s\u1ed1 v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p 1km = 1000 m 1m 8dm = 18dm 24dm : 3 = 8dm C\u00e2u 3. (1 \u0111) a. Vi\u1ebft s\u1ed1 v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: 116 ; 216 ; 316 ; 416 ; 516. b. Vi\u1ebft hai s\u1ed1 l\u1edbn h\u01a1n 499 m\u00e0 m\u1ed7i s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 gi\u1ed1ng nhau: 555; 666 PH\u1ea6N 2. T\u1ef0 LU\u1eacN(4 \u0111) C\u00e2u 2. Gi\u1ea3i to\u00e1n(2 \u0111) M\u1ed9t c\u1eeda h\u00e0ng trong m\u1ed9t tu\u1ea7n b\u00e1n \u0111\u01b0\u1ee3c 645m v\u1ea3i hoa. S\u1ed1 m\u00e9t v\u1ea3i hoa \u0111\u00e3 b\u00e1n nhi\u1ec1u h\u01a1n v\u1ea3i tr\u1eafng l\u00e0 243m. H\u1ecfi c\u1eeda h\u00e0ng \u0111\u00f3 \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau m\u00e9t v\u1ea3i tr\u1eafng? C\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 v\u1ea3i tr\u1eafng l\u00e0: 645 \u2013 243 = 401 (m) \u0110\u00e1p s\u1ed1: 401 m v\u1ea3i To\u00e1n 2-1 Page 407","\u0110\u1ec0 S\u1ed0 3 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1 2 3 4 \u0110\u00e1p \u00e1n B =;> C A C\u00e2u 5. (1\u0111) Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edchh\u1ee3p: a. 211; 212; 213; 214; 215; 216; 217; 218; 219; 220 b. 510; 515;520; 525; 530; 535; 540; PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 2. T\u00ecm y (1\u0111) a. y = 32 b. y = 5 C\u00e2u 3. Gi\u1ea3i to\u00e1n: S\u1ed1 d\u1ea7u c\u1eeda h\u00e0ng b\u00e1n nhi\u1ec1u h\u01a1n s\u1ed1 x\u0103ng l\u00e0: 865 \u2013 724 = 141 (l\u00edt) \u0110\u00e1p s\u1ed1: 141 l\u00edt C\u00e2u 4. (1\u0111) To\u00e1n 2-1 Page 408","\u0110\u1ec0 S\u1ed0 4 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1 2 3 4 5 \u0110\u00e1p \u00e1n B > : > A C C PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 2. T\u00ecm y (1\u0111) a. y = 3 b. y = 16 C\u00e2u 3. a. Trong v\u01b0\u1eddn c\u00f3 s\u1ed1 c\u00e2y qu\u00fdt l\u00e0: 230 + 128 = 358 (c\u00e2y) b. Trong v\u01b0\u1eddn c\u00f3 s\u1ed1 c\u00e2y cam v\u00e0 qu\u00fdt l\u00e0: 230 + 358 = 588 (c\u00e2y) \u0110\u00e1p s\u1ed1: 588 c\u00e2y C\u00e2u 4. (0,5\u0111) H\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau \u0111o\u1ea1n th\u1eb3ng? - C\u00f3 6 \u0111o\u1ea1n th\u1eb3ng To\u00e1n 2-1 Page 409","\u0110\u1ec0 S\u1ed0 5 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: C\u00e2u 1 2 3 4 5 \u0110\u00e1p \u00e1n B C A D B PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 1. T\u00ednh(2\u0111i\u1ec3m) a. 5 x 9 + 453 = 45 + 453 b. 20 : 5 x 8 = 4 x 8 = 498 = 32 B\u00e0i 2. T\u00ecm y (1\u0111) y=7 y = 15 B\u00e0i 3.(2\u0111) \u00d4ng n\u0103m nay c\u00f3 s\u1ed1 tu\u1ed5i l\u00e0: 36 + 27 = 63 (tu\u1ed5i) \u0110\u00e1p s\u1ed1: 63 tu\u1ed5i B\u00e0i 4.(1\u0111)T\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft n\u1ebfu ta chia s\u1ed1 \u0111\u00f3 cho 2, r\u1ed3i c\u1ed9ng v\u1edbi 19 th\u00ec \u0111\u01b0\u1ee3c s\u1ed1 m\u1edbi l\u00e0 24. S\u1ed1 \u0111\u00f3 l\u00e0: (24 \u2013 19) x 2 = 10 To\u00e1n 2-1 Page 410","\u0110\u1ec0 S\u1ed0 6 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) C\u00e2u 1. (1\u0111)\u00a0Khoanh v\u00e0o ch\u1eef c\u00e1i c\u00f3 k\u1ebft qu\u1ea3 \u0111\u00fang: a. 0 : 4 = ? A. 0 \u00a0 \u00a0 \u00a0 b. 5 x 0 =? B. C\u00e2u 2:\u00a0(0,5\u0111) \u0110\u00fang ghi \u0110, sai ghi S \u0110 H\u00f4m nay l\u00e0 th\u1ee9 ba, ng\u00e0y 16 th\u00e1ng 4. Th\u1ee9 ba tu\u1ea7n sau v\u00e0o ng\u00e0y 23 th\u00e1ng 4. S T\u1eeb 7 gi\u1edd s\u00e1ng \u0111\u1ebfn 2 gi\u1edd chi\u1ec1u c\u00f9ng ng\u00e0y l\u00e0 6 gi\u1edd. C\u00e2u 3:(1\u0111) N\u1ed1i ph\u00e9p t\u00ednh v\u1edbi k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh \u0111\u00f3: C\u00e2u 4.\u00a0(1\u0111) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed5 ch\u1ea5m: a. 5 x 3 = 15 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 14 : 2 = 7 b.\u00a0M\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 12 cm, 13cm, 14cm, 15 cm. Chu vi h\u00ecnh t\u1ee9 gi\u00e1c l\u00e0:54cm C\u00e2u 5. (0,5\u0111)\u00a0 C PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 2.(1\u0111) T\u00ecm x X= 57 X= 46 To\u00e1n 2-1 Page 411","C\u00e2u 3. (2\u0111) M\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 1dm 2cm, 13cm, 14cm, 15 cm. T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3. \u0110\u1ed5i 1dm 2cm = 12cm Chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3 l\u00e0: 12 + 13 + 14 + 15 = 54cm C\u00e2u 4: S\u1ed1 k\u1eb9o c\u1ee7a Lan l\u00e0 s\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 gi\u1ed1ng nhau. Lan cho Hoa s\u1ed1 k\u1eb9o l\u00e0 s\u1ed1 ch\u1eb5n nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1. H\u1ecfi Lan c\u00f2n bao nhi\u00eau c\u00e1i k\u1eb9o? S\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 gi\u1ed1ng nhau l\u00e0 11 S\u1ed1 ch\u1eb5n nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 l\u00e0 10 Lan c\u00f2n s\u1ed1 k\u1eb9o l\u00e0: 11 \u2013 10 = 1 (c\u00e1i k\u1eb9o) \u0110\u00e1p s\u1ed1: 1 c\u00e1i k\u1eb9o To\u00e1n 2-1 Page 412","\u0110\u1ec0 S\u1ed0 7 C\u00e2u 1: (1 \u0111i\u1ec3m):Khoanh v\u00e0o tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t: c) C d) B,D C\u00e2u 2: (1 \u0111i\u1ec3m) Vi\u1ebft s\u1ed1 v\u00e0 ch\u1eef th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng (theo m\u1eabu): Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 107 M\u1ed9t tr\u0103m linh b\u1ea3y 439 B\u1ed1n tr\u0103m ba m\u01b0\u01a1i ch\u00edn 862 T\u00e1m tr\u0103m s\u00e1u m\u01b0\u01a1i hai C\u00e2u 3:(`1 \u0111i\u1ec3m)Khoanh v\u00e0o tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t: a) B b) 8 x 5 : 2 = 40 : 2 b) B = 20 C\u00e2u 4:(1 \u0111i\u1ec3m) b) \u0110i\u1ec1n d\u1ea5u >;<; =? 635 <639 827= 800 + 27 C\u00e2u 5:(1 \u0111i\u1ec3m): T\u00ednh b) 4 x 6 + 5 = 24 + 5 = 29 To\u00e1n 2-1 Page 413","C\u00e2u 6:(1 \u0111i\u1ec3m) Chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0: 3 + 4 + 6 + 8 = 21 (cm) C\u00e2u 7:(1 \u0111i\u1ec3m): \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: C\u00f3 80kg ng\u00f4 chia \u0111\u1ec1u v\u00e0o 4 bao. M\u1ed7i bao c\u00f3: A. 20 kg ng\u00f4 \u0110 B. 4 kg ng\u00f4 S C\u00e2u 8:(1 \u0111i\u1ec3m)\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: x5 :5 -5 + 50 C\u00e2u 9: (1 \u0111i\u1ec3m) = 24 \u0110\u1ed5i 1m = 100cm = 24 : 4 S\u1ee3i d\u00e2y th\u00e9p d\u00e0i l\u00e0: 100 \u2013 6 = 94 (cm) =6 \u0110\u00e1p s\u1ed1: 94cm C\u00e2u 10: (1 \u0111i\u1ec3m)T\u00ecm x, bi\u1ebft: X + X+ X + X = 24 Xx4 X X To\u00e1n 2-1 Page 414","\u0110\u1ec0 S\u1ed0 8 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (5\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1. (1\u0111) B C\u00e2u 2.(1\u0111)\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 3kg = 3000 g C\u00e2u 3. (1\u0111) A C\u00e2u4. (1\u0111) A C\u00e2u 5.(1\u0111) B PH\u1ea6N II: T\u1ef0 LU\u1eacN (5\u0111) b) x = 16 C\u00e2u 2. T\u00ecm x(2\u0111): \u00a0 a) x = 5 C\u00e2u 3. (1\u0111)\u00a0L\u1edbp 2A c\u00f3 32 h\u1ecdc sinh \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 4 h\u00e0ng \u0111\u1ec3 t\u1eadp th\u1ec3 d\u1ee5c. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 m\u1ea5y h\u1ecdc sinh? M\u1ed7i h\u00e0ng c\u00f3 s\u1ed1 h\u1ecdc sinh l\u00e0: 32 : 4 = 8 (h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 8 h\u1ecdc sinh C\u00e2u 4. (1\u0111) T\u00ecm hi\u1ec7u c\u1ee7a s\u1ed1 tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u1edbi s\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t c\u00f3 m\u1ed9t ch\u1eef s\u1ed1 . S\u1ed1 tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 l\u00e0 90 S\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t c\u00f3 m\u1ed9t ch\u1eef s\u1ed1 l\u00e0 8 Hi\u1ec7u 2 s\u1ed1 \u0111\u00f3 l\u00e0: 90 \u2013 8 = 82 To\u00e1n 2-1 Page 415","\u0110\u1ec0 S\u1ed0 9 PH\u00c2\u0300N I: TR\u1eaeC NGHI\u1ec6M(3,5\u0111) Khoanh va\u0300o ch\u01b0\u0303 ca\u0301i \u0111\u0103\u0323t tr\u01b0\u01a1\u0301c c\u00e2u tra\u0309 l\u01a1\u0300i \u0111u\u0301ng nh\u00e2\u0301t: C\u00e2u 1 2 3 4 5 \u0110\u00e1p \u00e1n B D C A > ; = PH\u1ea6N II: T\u1ef0 LU\u1eacN b, T\u00ednh C\u00e2u2: (1\u0111)a, T\u00ecm x : 5 x 8 \u2013 20 = 40 \u2013 20 = 20 X = 62 C\u00e2u 3.(1,5\u0111) \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac ABCDE l\u00e0 : 3 + 4 + 4 + 3 = 14 (cm) \u0110\u00e1p s\u1ed1: 14cm C\u00e2u 4. (2\u0111) M\u1ed9t thanh k\u1ebdm \u0111\u01b0\u1ee3c b\u1ed1 u\u1ed1n th\u00e0nh khung h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh \u0111\u1ec1u b\u1eb1ng 2dm. H\u1ecfi thanh k\u1ebdm ph\u1ea3i d\u00e0i bao nhi\u00eau \u0111\u1ec1 - xi \u2013 m\u00e9t \u0111\u1ec3 u\u1ed1n \u0111\u1ee7 th\u00e0nh khung h\u00ecnh tam gi\u00e1c? Thanh k\u1ebdm d\u00e0i l\u00e0: 2 x 3 = 6 (dm) \u0110\u00e1p s\u1ed1: 6dm To\u00e1n 2-1 Page 416","\u0110\u1ec0 S\u1ed0 10 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4 \u0111i\u1ec3m): C\u00e2u 1 (2 \u0111i\u1ec3m): H\u00e3y khoanh tr\u00f2n v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t. C\u00e2u 1 2 3 4 \u0110\u00e1p \u00e1n B A B B C\u00e2u 2.\u0110\u00fang \u0111i\u1ec1n \u0110, sai \u0111i\u1ec1n S v\u00e0o cu\u1ed1i m\u1ed7i d\u00f2ng sau (1 \u0111i\u1ec3m) : Trong ph\u00e9p t\u00ednh 18 : 3 = 6, th\u00ec : a) S\u1ed1 18 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 s\u1ed1 chia. S b) S\u1ed1 3 g\u1ecdi l\u00e0 s\u1ed1 b\u1ecb chia. S c) \u201c18 : 3\u201d \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 th\u01b0\u01a1ng. \u0110 d) S\u1ed1 6 g\u1ecdi l\u00e0 th\u01b0\u01a1ng \u0110 C\u00e2u 3. \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m (1 \u0111i\u1ec3m): a) S\u1ed1 209 g\u1ed3m 2 tr\u0103m 0 ch\u1ee5c 9 \u0111\u01a1n v\u1ecb. b) S\u1ed1 g\u1ed3m 6 tr\u0103m 5 ch\u1ee5c 7 \u0111\u01a1n v\u1ecb vi\u1ebft s\u1ed1 l\u00e0 657 PH\u1ea6N II: T\u1ef0 LU\u1eacN (6 \u0111i\u1ec3m) : y=0 C\u00e2u 2. a) T\u00ednh (1 \u0111i\u1ec3m) : 5 x 1 + 38 = 5 + 38 = 43 0 : 4 x 24 = 0 x 24 = 0 b) T\u00ecm y (1 \u0111i\u1ec3m): y = 48 C\u00e2u 3.(1 \u0111i\u1ec3m) S\u1ed1 l\u01b0\u1ee3ng g\u1ea1o \u0111\u00f3 l\u00e0: 4 x 9 = 36 (kg) \u0110\u00e1p s\u1ed1: 36 kg To\u00e1n 2-1 Page 417","C\u00e2u 4. (1\u0111i\u1ec3m) T\u00ecm t\u1ed5ng c\u1ee7a s\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 v\u00e0 s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 kh\u00e1c nhau. S\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 900 S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 kh\u00e1c nhau l\u00e0 98 T\u1ed5ng 2 s\u1ed1 l\u00e0: 900 + 98 = 998 \u0110\u00e1p s\u1ed1: 998 To\u00e1n 2-1 Page 418"]