Phiếu bài tập cuối tuần Toán 2 sách Cánh diều.doc

["B\u00e0i 5: \u00a0\u0110i\u1ec1n \u0111\u01a1n v\u1ecb (m, dm, cm, mm) v\u00e0o ch\u1ed7 ch\u1ea5m: 1 km = 1000m 3m = 3000 mm 5 m = 500cm 1m = 10 dm 200 mm = 2dm 70 dm = 7 cm \u0110i\u1ec1n \u0111\u01a1n v\u1ecb (m, dm, cm, mm) v\u00e0o ch\u1ed7 ch\u1ea5m: 1 km = 1000m 3m = 3000mm 5 m = 500cm 1m = 10dm 200 mm = 2dm 70mm= 7 cm B\u00e0i 6: T\u00ednh: a) 36m + 28 m = 44m\u00a0\u00a0\u00a0\u00a0\u00a0\u00a018 mm + 7 mm = 25mm b) 42 m \u2013 24 m = 18m\u00a0\u00a0\u00a0\u00a0\u00a035 mm \u2013 9 mm = 26mm c) 4 km \u00d7 6 = 24km\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a05 km \u00d7 8 = 40km d) 32 km : 4 = 8km\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a045 km : 5 = 9km B\u00e0i 7: M\u1ed9t ng\u00f4i nh\u00e0 g\u1ed3m 7 t\u1ea7ng cao b\u1eb1ng nhau. Bi\u1ebft r\u1eb1ng ng\u00f4i nh\u00e0 cao 21m. H\u1ecfi m\u1ed7i t\u1ea7ng cao m\u1ea5y m\u00e9t? B\u00e0i gi\u1ea3i M\u1ed7i t\u1ea7ng c\u1ee7a ng\u00f4i nh\u00e0 \u0111\u00f3 cao s\u1ed1 m\u00e9t l\u00e0: 21 : 7= 3 (m) \u0110\u00e1p s\u1ed1: 3m B\u00e0i 8: Cu\u1ed1n s\u00e1ch Ti\u1ebfng Vi\u1ec7t d\u00e0y 9 mm. Cu\u1ed1n s\u00e1ch To\u00e1n d\u00e0y 6mm. H\u1ecfi cu\u1ed1n s\u00e1ch n\u00e0o m\u1ecfng h\u01a1n v\u00e0 m\u1ecfng h\u01a1n bao nhi\u00eau mm? B\u00e0i gi\u1ea3i Cu\u1ed1n s\u00e1ch To\u00e1n m\u1ecfng h\u01a1n s\u1ed1 mi-li-m\u00e9t l\u00e0: 9 \u2013 6 = 3 (mm) \u0110\u00e1p s\u1ed1: 3mm B\u00e0i 9: \u0110\u00e8n bi\u1ec3n c\u00e1ch b\u1edd 4km, m\u1ed9t chi\u1ebfc t\u00e0u \u0111\u00e1nh c\u00e1 c\u00e1ch b\u1edd 3km (nh\u01b0 h\u00ecnh v\u1ebd). H\u1ecfi chi\u1ebfc t\u00e0u \u0111\u00e1nh c\u00e1 \u0111\u00f3 c\u00e1ch \u0111\u00e8n bi\u1ec3n bao nhi\u00eau ki-l\u00f4-m\u00e9t? B\u00e0i gi\u1ea3i Chi\u1ebfc t\u00e0u \u0111\u00e1nh c\u00e1 \u0111\u00f3 c\u00e1ch \u0111\u00e8n bi\u1ec3n s\u1ed1 ki-l\u00f4-m\u00e9t l\u00e0: 4 \u2013 3 = 1 (km) \u0110\u00e1p s\u1ed1: 1km B\u00e0i 10\u00a0: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 :105 cm , 11 dm, 113 cm, 16 dm. B\u00e0i gi\u1ea3i \u0110\u1ed5i 11dm = 110cm, 16dm = 160cm Chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3 l\u00e0 105 + 110 + 113 + 160 = 488 (cm) \u0110\u00e1p s\u1ed1\u00a0: 488cm To\u00e1n 2-1 Page 351","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N .1. Ph\u00e9p tr\u1eeb kh\u00f4ng nh\u1edb trong ph\u1ea1m vi 1000 D\u1ea1ng 1: \u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh - \u0110\u1eb7t t\u00ednh v\u1edbi c\u00e1c h\u00e0ng t\u01b0\u01a1ng \u1ee9ng \u0111\u1eb7t th\u1eb3ng c\u1ed9t v\u1edbi nhau: H\u00e0ng tr\u0103m c\u1ee7a s\u1ed1 n\u00e0y th\u1eb3ng h\u00e0ng tr\u0103m c\u1ee7a s\u1ed1 kia, t\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady v\u1edbi h\u00e0ng ch\u1ee5c v\u00e0 h\u00e0ng \u0111\u01a1n v\u1ecb. - Th\u1ef1c hi\u1ec7n ph\u00e9p tr\u1eeb t\u1eeb ph\u1ea3i sang tr\u00e1i. V\u00ed d\u1ee5:\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh 789 - 123 Gi\u1ea3i: B. B\u00c0I T\u1eacP B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 234 + 324 506 + 233 574 \u2013 204 348 - 317 B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: 262 S\u1ed1 b\u1ecb tr\u1eeb 234 420 485 To\u00e1n 2-1 Page 352","S\u1ed1 tr\u1eeb 105 110 234 132 Hi\u1ec7u \u00a0 \u00a0 \u00a037 \u00a0203 \u00a0410 345 B\u00e0i 3: x + 135 = 287 x \u2013 78 = 210 327 \u2013 x = 225 512 + x = 987 \u2013 41 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 4: Em t\u1ef1 vi\u1ebft ba s\u1ed1 \u0111\u1ec1u c\u00f3 ba ch\u1eef s\u1ed1 v\u00e0o b\u1ea3ng r\u1ed3i vi\u1ebft ti\u1ebfp theo m\u1eabu: S\u1ed1 S\u1ed1 g\u1ed3m c\u00f3 T\u1ed5ng c\u00e1c h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb 247 2 tr\u0103m 4 ch\u1ee5c 7 \u0111\u01a1n v\u1ecb 247 = 200 + 40 + 7 \u00a0\u00a0 \u00a0 \u00a0\u00a0 \u00a0 \u00a0\u00a0 \u00a0 B\u00e0i 5: \u00a0\u00a0Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: a. 211; 212; 213; \u2026\u2026..; \u2026\u2026..; 216; \u2026\u2026..; 218; 219; \u2026\u2026.. b. 510; 515;\u2026\u2026..; 525; 530; \u2026\u2026..; \u2026\u2026..; B\u00e0i 6: \u0110i\u1ec1n d\u1ea5u >, <, = v\u00e0o \u00f4 tr\u1ed1ng: a. 600 + 30 \u00a0\u00a063\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b. 30 : 5 : 3 \u00a0\u00a012 c. 100 \u00a0\u00a0 1000\u00a0 d. 400 \u00d7 2 \u00a0\u00a0 600 + 200\u00a0 B\u00e0i 7: C\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 120 kg g\u1ea1o n\u1ebfp v\u00e0 b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 g\u1ea1o t\u1ebb nhi\u1ec1u h\u01a1n s\u1ed1 g\u1ea1o n\u1ebfp l\u00e0 130 kg. H\u1ecfi c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ki-l\u00f4-gam g\u1ea1o t\u1ebb? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 353","B\u00e0i 8: M\u1ed9t nh\u00e0 m\u00e1y c\u00f3 175 c\u00f4ng nh\u00e2n nam, s\u1ed1 c\u00f4ng nh\u00e2n n\u1eef nhi\u1ec1u h\u01a1n s\u1ed1 c\u00f4ng nh\u00e2n nam l\u00e0 22 c\u00f4ng nh\u00e2n. H\u1ecfi nh\u00e0 m\u00e1y c\u00f3 bao nhi\u00eau c\u00f4ng nh\u00e2n n\u1eef? B\u00e0i gi\u1ea3i B\u00e0i 9: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 120 cm; 130 cm v\u00e0 140 cm. B\u00e0i gi\u1ea3i B\u00e0i 10\u00a0: M\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh l\u00e0 200 cm . H\u1ecfi h\u00ecnh vu\u00f4ng \u0111\u00f3 c\u00f3 chu vi l\u00e0 bao nhi\u00eau m\u00e9t? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 354","B\u00e0i 11*: T\u00ecm hi\u1ec7u c\u1ee7a s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1 kh\u00e1c nhau v\u00e0 s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 gi\u1ed1ng nhau B\u00e0i gi\u1ea3i \u0110\u00c1P \u00c1N B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 234 + 324 =558 506 + 233 = 739 574 \u2013 204 = 370 348 \u2013 317 = 31 B\u00e0i 2: S\u1ed1? S\u1ed1 b\u1ecb tr\u1eeb 234 420 485 262 644 477 S\u1ed1 tr\u1eeb 105 110 448 59 234 132 Hi\u1ec7u \u00a0129 \u00a0310 \u00a037 \u00a0203 \u00a0410 345 B\u00e0i 3: x + 135 = 287 x \u2013 78 = 210 x = 287 \u2013 135 x = 210 + 78 x = 152 x = 288 327 \u2013 x = 225 512 + x = 987 \u2013 41 To\u00e1n 2-1 Page 355","x = 327 \u2013 225 512 + x = 936 x = 102 x = 936 - 512 x = 424 B\u00e0i 4: Em t\u1ef1 vi\u1ebft ba s\u1ed1 \u0111\u1ec1u c\u00f3 ba ch\u1eef s\u1ed1 v\u00e0o b\u1ea3ng r\u1ed3i vi\u1ebft ti\u1ebfp theo m\u1eabu: S\u1ed1 S\u1ed1 g\u1ed3m c\u00f3 T\u1ed5ng c\u00e1c h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb 247 2 tr\u0103m 4 ch\u1ee5c 7 \u0111\u01a1n v\u1ecb 247 = 200 + 40 + 7 \u00a0345 \u00a03 tr\u0103m 4 ch\u1ee5c 4 \u0111\u01a1n v\u1ecb \u00a0345= 300 + 40 + 5 \u00a0674 \u00a06 tr\u0103m 7 ch\u1ee5c 4 \u0111\u01a1n v\u1ecb \u00a0674 = 600 + 70 +4 \u00a0908 \u00a09 tr\u0103m 8 \u0111\u01a1n v\u1ecb \u00a0908 = 900 + 8 B\u00e0i 5: \u00a0\u00a0Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: a. 211; 212; 213; 214; 215; 216; 217; 218; 219; 220 b. 510; 515; 520; 525; 530; 535; 540; B\u00e0i 6: \u0110i\u1ec1n d\u1ea5u >, <, = v\u00e0o \u00f4 tr\u1ed1ng: a. 600 + 30 \u00a0\u00a063\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b. 30 : 5 : 3 \u00a0\u00a012 c. 100 \u00a0\u00a0 1000\u00a0 d. 400 \u00d7 2 \u00a0\u00a0 600 + 200\u00a0 B\u00e0i 7: C\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 120 kg g\u1ea1o n\u1ebfp v\u00e0 b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 g\u1ea1o t\u1ebb nhi\u1ec1u h\u01a1n s\u1ed1 g\u1ea1o n\u1ebfp l\u00e0 130 kg. H\u1ecfi c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ki-l\u00f4-gam g\u1ea1o t\u1ebb? B\u00e0i gi\u1ea3i C\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 ki-l\u00f4-gam g\u1ea1o t\u1ebb l\u00e0: 210 + 130 = 250 (kg) \u0110\u00e1p s\u1ed1: 250 kg g\u1ea1o B\u00e0i 8: M\u1ed9t nh\u00e0 m\u00e1y c\u00f3 175 c\u00f4ng nh\u00e2n nam, s\u1ed1 c\u00f4ng nh\u00e2n n\u1eef nhi\u1ec1u h\u01a1n s\u1ed1 c\u00f4ng nh\u00e2n nam l\u00e0 22 c\u00f4ng nh\u00e2n. H\u1ecfi nh\u00e0 m\u00e1y c\u00f3 bao nhi\u00eau c\u00f4ng nh\u00e2n n\u1eef? B\u00e0i gi\u1ea3i Nh\u00e0 m\u00e1y c\u00f3 s\u1ed1 c\u00f4ng nh\u00e2n n\u1eef l\u00e0: 175 + 22 = 197 ( c\u00f4ng nh\u00e2n) \u0110\u00e1p s\u1ed1: 197 c\u00f4ng nh\u00e2n n\u1eef B\u00e0i 9: T\u00ednh chu vi h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 120 cm; 130 cm v\u00e0 140 cm. To\u00e1n 2-1 Page 356","B\u00e0i gi\u1ea3i Chu vi h\u00ecnh tam gi\u00e1c \u0111\u00f3 l\u00e0\u00a0: 120 + 130 + 140 = 390 (cm) \u0110\u00e1p s\u1ed1\u00a0: 390cm B\u00e0i 10\u00a0: M\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh l\u00e0 200 cm . H\u1ecfi h\u00ecnh vu\u00f4ng \u0111\u00f3 c\u00f3 chu vi l\u00e0 bao nhi\u00eau m\u00e9t ? B\u00e0i gi\u1ea3i \u0110\u1ed5i 200cm = 2m Chu vi h\u00ecnh vu\u00f4ng \u0111\u00f3 l\u00e0\u00a0: 2 \u00d7 4 = 8(m) \u0110\u00e1p s\u1ed1\u00a0: 8m B\u00e0i 11*: S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1 kh\u00e1c nhau l\u00e0 987 S\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 gi\u1ed1ng nhau l\u00e0: 111 Hi\u1ec7u l\u00e0 : 987 \u2013 111 =876 To\u00e1n 2-1 Page 357","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N .1. \u00d4n t\u1eadp c\u00e1c s\u1ed1 trong ph\u1ea1m vi 1000 a. C\u00e1ch \u0111\u1ecdc, vi\u1ebft c\u00e1c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 - \u0110\u1ecdc s\u1ed1 theo th\u1ee9 t\u1ef1 c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i: H\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb ( \u0110\u1ecdc s\u1ed1 tr\u0103m + tr\u0103m + s\u1ed1 ch\u1ee5c + m\u01b0\u01a1i + s\u1ed1 \u0111\u01a1n v\u1ecb) - T\u1eeb c\u00e1ch \u0111\u1ecdc s\u1ed1, em vi\u1ebft c\u00e1c ch\u1eef s\u1ed1 t\u01b0\u01a1ng \u1ee9ng v\u1edbi c\u00e1c h\u00e0ng r\u1ed3i gh\u00e9p l\u1ea1i \u0111\u1ec3 \u0111\u01b0\u1ee3c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1. b. So s\u00e1nh c\u00e1c s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 - S\u1ed1 c\u00f3 \u00edt ch\u1eef s\u1ed1 h\u01a1n th\u00ec c\u00f3 gi\u00e1 tr\u1ecb b\u00e9 h\u01a1n. - Hai s\u1ed1 \u0111\u1ec1u c\u00f3 ba ch\u1eef s\u1ed1, em so s\u00e1nh c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i. c. Vi\u1ebft s\u1ed1 th\u00e0nh t\u1ed5ng c\u00e1c tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb B\u01b0\u1edbc 1: X\u00e1c \u0111\u1ecbnh s\u1ed1 tr\u0103m, s\u1ed1 ch\u1ee5c, s\u1ed1 \u0111\u01a1n v\u1ecb c\u1ee7a s\u1ed1 \u0111\u00f3. B\u01b0\u1edbc 2: Vi\u1ebft s\u1ed1 \u0111\u00f3 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng: h\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb V\u00ed d\u1ee5:\u00a0Vi\u1ebft s\u1ed1 123 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb. Gi\u1ea3i: 123 = 100 + 20 + 3 2. \u00d4n t\u1eadp v\u1ec1 ph\u00e9p c\u1ed9ng, ph\u00e9p tr\u1eeb \u00a0- \u0110\u1eb7t t\u00ednh, c\u00e1c ch\u1eef s\u1ed1 c\u00f9ng m\u1ed9t h\u00e0ng th\u1eb3ng c\u1ed9t v\u1edbi nhau. - Th\u1ef1c hi\u1ec7n ph\u00e9p c\u1ed9ng (tr\u1eeb) t\u1eeb ph\u1ea3i sang tr\u00e1i. B. B\u00c0I T\u1eacP B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : 537 -123 658 \u2013 420 349 \u2013 28 236 \u2013 5 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 956 147 147 147 \u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026 24 24 123 B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng : 210 S\u1ed1 b\u1ecb tr\u1eeb 956 956 295 - x = 180 S\u1ed1 tr\u1eeb 210 Hi\u1ec7u 746 B\u00e0i 3: T\u00ecm 400 + x = 600 b. To\u00e1n 2-1 Page 358","B\u00e0i 4: <, >, = ? 37m d. 35m - 16m 19m a. 61m - 15m b. 84m \u00d7 1 90m - 12m e. 42kg \u00d7 0 42kg + 0kg c. 63m - 27m 24m + 19m g. 13kg : 1 13kg \u00d7 1 B\u00e0i 5: \u00a0T\u00ednh nh\u1ea9m 600m + 300m =............ 700cm + 20cm =.......... 20dm + 500dm =............. 1000km \u2013 200 km =.............. B\u00e0i 6: C\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c 350 kg g\u1ea1o t\u1ebb v\u00e0 g\u1ea1o n\u1ebfp , trong \u0111\u00f3 c\u00f3 210 kg g\u1ea1o t\u1ebb . H\u1ecfi c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau ki-l\u00f4-gam g\u1ea1o n\u1ebfp ? B\u00e0i gi\u1ea3i B\u00e0i 7: C\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 35l d\u1ea7u ; bu\u1ed5i chi\u1ec1u b\u00e1n \u00edt h\u01a1n bu\u1ed5i s\u00e1ng l\u00e0 8l d\u1ea7u . H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u ? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 359","To\u00e1n 2-1 Page 360","B\u00e0i 8: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD A 100m B 100m 420m 330m D C B\u00e0i gi\u1ea3i B\u00e0i 9: Tr\u01b0\u1eddng ti\u1ec3u h\u1ecdc H\u00f2a B\u00ecnh c\u00f3 214 h\u1ecdc sinh l\u1edbp 3 v\u00e0 4 . Bi\u1ebft s\u1ed1 h\u1ecdc sinh l\u1edbp 3 l\u00e0 119 b\u1ea1n . H\u1ecfi tr\u01b0\u1eddng ti\u1ec3u h\u1ecdc H\u00f2a B\u00ecnh c\u00f3 bao nhi\u00eau h\u1ecdc sinh l\u1edbp 4 ? B\u00e0i gi\u1ea3i B\u00e0i 10\u00a0: L\u1edbp 2A c\u00f3 32 h\u1ecdc sinh \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 4 h\u00e0ng \u0111\u1ec3 t\u1eadp th\u1ec3 d\u1ee5c. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 m\u1ea5y h\u1ecdc sinh? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 361","B\u00e0i 11*: Cho 3 ch\u1eef s\u1ed1 0; 4; 7 a. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ........................................................ b. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ........................................................ c. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ................................... d. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ................................... To\u00e1n 2-1 Page 362","\u0110\u00c1P \u00c1N B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh : 537 -123 = 414 658 \u2013 420 = 238 349 \u2013 28= 321 236 \u2013 5 = 231 B\u00e0i 2: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng : S\u1ed1 b\u1ecb tr\u1eeb 956 956 956 147 147 147 S\u1ed1 tr\u1eeb 210 210 746 24 123 24 Hi\u1ec7u 746 746 210 123 24 123 B\u00e0i 3: T\u00ecm 400 + x = 600 295 \u2013 x =180 x = 295 \u2013 180 x = 6 0 0 - 40 0 x = 115 x = 200 B\u00e0i 4: <, >, = ? 37m d. 35m - 16m 19m a. 61m - 15m e. 42kg \u00d7 0 42kg + 0kg b. 84m \u00d7 1 90m - 12m g. 13kg : 1 13kg \u00d7 1 c. 63m - 27m 24m + 19m B\u00e0i 5: \u00a0T\u00ednh nh\u1ea9m 600m + 300m = 900m 700cm + 20cm = 720cm 20dm + 500dm = 520dm 1000km \u2013 200 km = 800km B\u00e0i 6: B\u00e0i gi\u1ea3i B\u00e0i 7: C\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 ki-l\u00f4-gam g\u1ea1o n\u1ebfp l\u00e0: B\u00e0i 8: 350 \u2013 210 = 140 (kg) \u0110\u00e1p s\u1ed1: 140kg g\u1ea1o B\u00e0i gi\u1ea3i Bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 35 \u2013 8 = 27 (l) \u0110\u00e1p s\u1ed1: 27l d\u1ea7u B\u00e0i gi\u1ea3i Chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0: 100 + 100 + 330 + 420 = 950 (m) To\u00e1n 2-1 Page 363","B\u00e0i 9: \u0110\u00e1p s\u1ed1: 950m B\u00e0i 10\u00a0: B\u00e0i gi\u1ea3i Tr\u01b0\u1eddng ti\u1ec3u h\u1ecdc H\u00f2a B\u00ecnh c\u00f3 s\u1ed1 h\u1ecdc sinh l\u1edbp 4 l\u00e0: 214 \u2013 119 = 95 ( h\u1ecdc sinh) \u0110\u00e1p s\u1ed1:95 h\u1ecdc sinh l\u1edbp 4 B\u00e0i gi\u1ea3i M\u1ed7i h\u00e0ng c\u00f3 s\u1ed1 h\u1ecdc sinh l\u00e0: 32 : 4 = 8 ( h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 8 h\u1ecdc sinh B\u00e0i 11*: Cho 3 ch\u1eef s\u1ed1 0; 4; 7 a. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 740 b. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 407 c. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 74 d. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 40 To\u00e1n 2-1 Page 364","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N 1. \u00d4n t\u1eadp c\u00e1c s\u1ed1 trong ph\u1ea1m vi 1000 a. C\u00e1ch \u0111\u1ecdc, vi\u1ebft c\u00e1c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 - \u0110\u1ecdc s\u1ed1 theo th\u1ee9 t\u1ef1 c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i: H\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb ( \u0110\u1ecdc s\u1ed1 tr\u0103m + tr\u0103m + s\u1ed1 ch\u1ee5c + m\u01b0\u01a1i + s\u1ed1 \u0111\u01a1n v\u1ecb) - T\u1eeb c\u00e1ch \u0111\u1ecdc s\u1ed1, em vi\u1ebft c\u00e1c ch\u1eef s\u1ed1 t\u01b0\u01a1ng \u1ee9ng v\u1edbi c\u00e1c h\u00e0ng r\u1ed3i gh\u00e9p l\u1ea1i \u0111\u1ec3 \u0111\u01b0\u1ee3c s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1. b. So s\u00e1nh c\u00e1c s\u1ed1 c\u00f3 3 ch\u1eef s\u1ed1 - S\u1ed1 c\u00f3 \u00edt ch\u1eef s\u1ed1 h\u01a1n th\u00ec c\u00f3 gi\u00e1 tr\u1ecb b\u00e9 h\u01a1n. - Hai s\u1ed1 \u0111\u1ec1u c\u00f3 ba ch\u1eef s\u1ed1, em so s\u00e1nh c\u00e1c h\u00e0ng t\u1eeb tr\u00e1i sang ph\u1ea3i. c. Vi\u1ebft s\u1ed1 th\u00e0nh t\u1ed5ng c\u00e1c tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb B\u01b0\u1edbc 1: X\u00e1c \u0111\u1ecbnh s\u1ed1 tr\u0103m, s\u1ed1 ch\u1ee5c, s\u1ed1 \u0111\u01a1n v\u1ecb c\u1ee7a s\u1ed1 \u0111\u00f3. B\u01b0\u1edbc 2: Vi\u1ebft s\u1ed1 \u0111\u00f3 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng: h\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb V\u00ed d\u1ee5:\u00a0Vi\u1ebft s\u1ed1 123 th\u00e0nh t\u1ed5ng c\u1ee7a c\u00e1c h\u00e0ng tr\u0103m, ch\u1ee5c, \u0111\u01a1n v\u1ecb. Gi\u1ea3i: 123 = 100 + 20 + 3 2. \u00d4n t\u1eadp v\u1ec1 ph\u00e9p c\u1ed9ng, ph\u00e9p tr\u1eeb \u00a0- \u0110\u1eb7t t\u00ednh, c\u00e1c ch\u1eef s\u1ed1 c\u00f9ng m\u1ed9t h\u00e0ng th\u1eb3ng c\u1ed9t v\u1edbi nhau. - Th\u1ef1c hi\u1ec7n ph\u00e9p c\u1ed9ng (tr\u1eeb) t\u1eeb ph\u1ea3i sang tr\u00e1i. 3. \u00d4n t\u1eadp v\u1ec1 ph\u00e9p nh\u00e2n, ph\u00e9p chia B\u1ea2NG C\u1eecU CH\u01af\u01a0NG NH\u00c2N 2\u00d71=2 3\u00d71=3 4\u00d71=4 5\u00d71=5 2\u00d72=4 3\u00d72=6 4\u00d72=8 5 \u00d7 2 = 10 2\u00d73=6 3\u00d73=9 4 \u00d7 3 = 12 5 \u00d7 3 = 15 2\u00d74=8 3 \u00d7 4 = 12 4 \u00d7 4 = 16 5 \u00d7 4 = 20 2 \u00d7 5 = 10 3 \u00d7 5 = 15 4 \u00d7 5 = 20 5 \u00d7 5 = 25 2 \u00d7 6 = 12 3 \u00d7 6 = 18 4 \u00d7 6 = 24 5 \u00d7 6 = 30 2 \u00d7 7 = 14 3 \u00d7 7 = 21 4 \u00d7 7 = 28 5 \u00d7 7 = 35 2 \u00d7 8 = 16 3 \u00d7 8 = 24 4 \u00d7 8 = 32 5 \u00d7 8 = 40 2 \u00d7 9 = 18 3 \u00d7 9 = 27 4 \u00d7 9 = 36 5 \u00d7 9 = 45 2 \u00d7 10 = 20 3 \u00d7 10 = 30 4 \u00d7 10 = 40 5 \u00d7 10 = 50 To\u00e1n 2-1 B\u1ea2NG C\u1eecU CH\u01af\u01a0NG CHIA Page 365","2:2=1 3:3=1 4:4=1 5:5=1 4:2=2 6:3=2 8:4=2 10 : 5 = 2 6:2=3 9:3=3 12 : 4 = 3 15 : 5 = 3 8:2=4 12 : 3 = 4 16 : 4 = 4 20 : 5 = 4 10 : 2 = 5 15 : 3 = 5 20 : 4 = 5 25 : 5 = 5 12 : 2 = 6 18 : 3 = 6 24 : 4 = 6 30 : 5 = 6 14 : 2 = 7 21 : 3 = 7 28 : 4 = 7 35 : 5 = 7 16 : 2 = 8 24 : 3 = 8 32 : 4 = 8 40 : 5 = 8 18 : 2 = 9 27 : 3 = 9 36 : 4 = 9 45 : 5 = 9 20 : 2 = 10 30 : 3 = 10 40 : 4 = 10 50 : 5 = 10 B. B\u00c0I T\u1eacP B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 56 + 3 41 \u2013 34 527 + 162 875 \u2013 28 + 69 86 \u2013 29 47 + 18 263 B\u00e0i 2: T\u00ednh: 5 \u00d7 8 : 4 = .......................... 4 \u00d7 9 + 423 = ........................ 25 + 27 + 643 = .................... = .......................... = ......................... = .................... 18 : 2 : 3 = ....................... 4 \u00d7 7 - 28 =........................... 789 \u2013 325 \u2013 33 = .................. = .......................... = .......................... = .................. B\u00e0i 3: \u0110i\u1ec1n s\u1ed1? a) Th\u1eeba s\u1ed1 5 3 52 b) SB chia 36 18 45 Th\u1eeba s\u1ed1 5 7 6 3 S\u1ed1 chia 4 5 2 3 5 9 T\u00edch 18 25 16 24 Th\u01b0\u01a1ng 3 9 3 B\u00e0i 4: Vi\u1ebft c\u00e1c s\u1ed1 842 ; 965 ; 404 theo m\u1eabu : (0.5 \u0111i\u1ec3m) M\u1eabu : 842 = 800 + 40 + 2 ................................................... .................................................... B\u00e0i 5: \u00a0T\u00ecm x : a) x + 123 = 579 b) 20 + x = 543 To\u00e1n 2-1 Page 366","\u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. c) x \u2013 205 = 301 d) 576 \u2013 x = 53 \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. \u2026\u2026\u2026\u2026\u2026.. B\u00e0i 6: a,S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 sau theo th\u1ee9 t\u1ef1 t\u0103ng d\u1ea7n : 724 , 192 , 853 , 358 , 446 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026 b, \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m 235;237;\u2026\u2026.;\u2026\u2026..;243. 426;436;\u2026\u2026.;\u2026\u2026..;\u2026\u2026.. B\u00e0i 7: M\u1ed7i cu\u1ed9n d\u00e2y \u0111i\u1ec7n d\u00e0i 9m. H\u1ecfi 5 cu\u1ed9n d\u00e2y \u0111i\u1ec7n nh\u01b0 th\u1ebf d\u00e0i bao nhi\u00eau m\u00e9t? B\u00e0i gi\u1ea3i B\u00e0i 8: C\u00f3 40 l\u00edt d\u1ea7u, r\u00f3t \u0111\u1ec1u v\u00e0o 5 can. H\u1ecfi m\u1ed7i can ch\u1ee9a bao nhi\u00eau l\u00edt d\u1ea7u? B\u00e0i gi\u1ea3i B\u00e0i 9: \u0110\u00e0n v\u1ecbt c\u00f3 238 con, \u0111\u00e0n g\u00e0 \u00edt h\u01a1n \u0111\u00e0n v\u1ecbt 126 con. H\u1ecfi \u0111\u00e0n g\u00e0 c\u00f3 bao nhi\u00eau con? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 367","B\u00e0i 10\u00a0: T\u00ednh \u0111\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac c\u00f3 ba \u0111o\u1ea1n th\u1eb3ng v\u1edbi c\u00e1c \u0111\u1ed9 d\u00e0i l\u00e0 1m ;3 dm v\u00e0 5cm B\u00e0i gi\u1ea3i B\u00e0i 11*: T\u00ecm c\u00e1c s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 m\u00e0 t\u1ed5ng c\u00e1c ch\u1eef s\u1ed1 l\u00e0 13 , t\u00edch l\u00e0 36 B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 368","To\u00e1n 2-1 Page 369","\u0110\u00c1P \u00c1N B\u00e0i 2: T\u00ednh: 5 \u00d7 8 : 4 = 40 : 4 4 \u00d7 9 + 423 = 36 + 423 25 + 27 + 643 = 52 + 643 = 10 = 459 = 695 18 : 2 : 3 = 9 : 3 4 \u00d7 7 \u2013 28 = 28 - 28 789 \u2013 325 \u2013 33 = 464 - 33 =3 =0 =431 B\u00e0i 3: \u0110i\u1ec1n s\u1ed1? a) Th\u1eeba s\u1ed1 5 3 3 5 2 8 b) SB chia 36 15 18 27 45 27 9 Th\u1eeba s\u1ed1 5 7 6 5 8 3 S\u1ed1 chia 4 5 2 3 5 3 T\u00edch 25 21 18 25 16 24 Th\u01b0\u01a1ng 9 3 9 9 9 B\u00e0i 4: Vi\u1ebft c\u00e1c s\u1ed1 842 ; 965 ; 404 theo m\u1eabu : (0.5 \u0111i\u1ec3m) 965 = 900 + 60 + 5 404 = 400 + 4 B\u00e0i 5: \u00a0T\u00ecm x : a) x + 123 =579 b) 20 + x = 543 x = 579 \u2013 123 x = 543 -20 x = 456 x = 523 c) x \u2013 205 = 301 d) 576 \u2013 x = 53 x = 301 + 205 x = 576 \u2013 53 x = 506 x = 523 B\u00e0i 6: a,S\u1eafp x\u1ebfp c\u00e1c s\u1ed1 sau theo th\u1ee9 t\u1ef1 t\u0103ng d\u1ea7n : 192 , 358 ,446, 724 , 853 b, 235;237; 239; 241;243. 426;436; 446; 456; 466 B\u00e0i 7: 5 cu\u1ed9n d\u00e2y \u0111i\u1ec7n nh\u01b0 th\u1ebf d\u00e0i s\u1ed1 m\u00e9t l\u00e0: 9 \u00d7 5 = 45 (m) \u0110\u00e1p s\u1ed1: 45m B\u00e0i 8: M\u1ed7i can ch\u1ee9a s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 40 : 5 = 8 (l) \u0110\u00e1p s\u1ed1: 8l d\u1ea7u B\u00e0i 9: \u0110\u00e0n g\u00e0 c\u00f3 s\u1ed1 con l\u00e0: 238 - 126 = 112 (con) \u0110\u00e1p s\u1ed1: 112 con g\u00e0 B\u00e0i 10\u00a0: \u0110\u1ed5i 1m = 100cm; 3dm = 30 cm \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac \u0111\u00f3 l\u00e0: 100 + 30 + 5 = 135 (cm) \u0110\u00e1p s\u1ed1: 135cm B\u00e0i 11*: T\u00ecm c\u00e1c s\u1ed1 c\u00f3 hai ch\u1eef s\u1ed1 m\u00e0 t\u1ed5ng c\u00e1c ch\u1eef s\u1ed1 l\u00e0 13 , t\u00edch l\u00e0 36 Hai s\u1ed1 \u0111\u00f3 l\u00e0: 49 v\u00e0 94 v\u00ec 4 + 9 = 13, 4 \u00d7 9 = 36 To\u00e1n 2-1 Page 370","H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp A. T\u00d3M T\u1eaeT L\u00cd THUY\u1ebeT TRONG TU\u1ea6N 1. \u00d4n t\u1eadp v\u1ec1 \u0111\u1ea1i l\u01b0\u1ee3ng a. \u0110\u01a1n v\u1ecb \u0111o \u0111\u1ed9 d\u00e0i M\u00e9t \u0110\u1ec1-xi-m\u00e9t X\u0103ng-ti-m\u00e9t Mi-li-m\u00e9t T\u00ean Ki-l\u00f4-m\u00e9t (km) (m) (dm) (cm) (mm) M\u1ed7i quan h\u1ec7 1km = 1000m 1m = 1 dm = 10 cm 10 cm = 1 dm gi\u1eefa c\u00e1c \u0111\u01a1n 10dm 1dm = 100mm 1cm = 10mm v\u1ecb \u0111o 1m = 100cm 1m = 1000mm b. \u0110\u01a1n v\u1ecb \u0111o kh\u1ed1i l\u01b0\u1ee3ng Ki \u2013 l\u00f4 \u2013 gam l\u00e0 1 \u0111\u01a1n v\u1ecb \u0111o l\u01b0\u1eddng. N\u00f3 d\u00f9ng \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh \u0111\u1ed9 n\u1eb7ng nh\u1eb9 c\u1ee7a c\u00e1c v\u1eadt (tr\u1ecdng l\u01b0\u1ee3ng). Ki \u2013 l\u00f4 \u2013 gam vi\u1ebft t\u1eaft l\u00e0 kg. 1 ki \u2013 l\u00f4 \u2013 gam = 1 kg; 2 ki \u2013 l\u00f4 \u2013 gam = 2 kg 5 ki \u2013 l\u00f4 \u2013 gam = 5 kg; 10 ki \u2013 l\u00f4 \u2013 gam = 10 kg c. \u0110\u01a1n v\u1ecb \u0111o s\u1ee9c ch\u1ee9a c\u1ee7a m\u1ed9t v\u1eadt L\u00edt l\u00e0 1 \u0111\u01a1n v\u1ecb \u0111o l\u01b0\u1eddng. N\u00f3 d\u00f9ng \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh \u0111\u1ed9 \u0111\u1ea7y v\u01a1i c\u1ee7a c\u00e1c ch\u1ea5t l\u1ecfng trong b\u00ecnh ch\u1ee9a (th\u1ec3 t\u00edch c\u1ee7a ch\u1ea5t l\u1ecfng \u0111\u00f3.). L\u00edt vi\u1ebft t\u1eaft l\u00e0 l 1 l\u00edt = 1l 2 l\u00edt = 2l 3 l\u00edt = 3l d. \u0110\u01a1n v\u1ecb \u0111o th\u1eddi gian Ng\u00e0y, gi\u1edd, th\u00e1ng, n\u0103m M\u1ed9t ng\u00e0y c\u00f3 24 gi\u1edd. B\u1eaft \u0111\u1ea7u t\u1eeb 12 gi\u1edd \u0111\u00eam h\u00f4m tr\u01b0\u1edbc \u0111\u1ebfn 12 gi\u1edd \u0111\u00eam h\u00f4m sau. M\u1ed9t n\u0103m c\u00f3 12 th\u00e1ng. M\u1ed7i th\u00e1ng th\u01b0\u1eddng c\u00f3 30 ho\u1eb7c 31 ng\u00e0y. Ri\u00eang th\u00e1ng 2 c\u00f3 28 ho\u1eb7c 29 ng\u00e0y. Gi\u1edd, ph\u00fat 1 gi\u1edd = 60 ph\u00fat. 1 ph\u00fat = 60 gi\u00e2y 1 ng\u00e0y c\u00f3 24 gi\u1edd 2 gi\u1edd 30 ph\u00fat hay c\u00f2n g\u1ecdi l\u00e0 2 gi\u1edd r\u01b0\u1ee1i. To\u00e1n 2-1 Page 371","2. \u00d4n t\u1eadp v\u1ec1 h\u00ecnh h\u1ecdc a.\u0110\u01b0\u1eddng th\u1eb3ng Ta c\u00f3: \u0110o\u1ea1n th\u1eb3ng AB. (\u0111o\u1ea1n th\u1eb3ng b\u1ecb gi\u1edbi h\u1ea1n b\u1edfi 2 \u0111\u1ea7u m\u00fat) \u0110\u01b0\u1eddng th\u1eb3ng CD. (\u0111o\u1ea1n th\u1eb3ng \u0111\u01b0\u1ee3c k\u00e9o d\u00e0i v\u1ec1 2 ph\u00eda g\u1ecdi l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng) Ba \u0111i\u1ec3m M, N, O c\u00f9ng n\u1eb1m tr\u00ean 1 \u0111\u01b0\u1eddng th\u1eb3ng. M, N, O l\u00e0 ba \u0111i\u1ec3m th\u1eb3ng h\u00e0ng. b. \u0110\u01b0\u1eddng g\u1ea5p kh\u00fac \u2013 \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac c. H\u00ecnh ch\u1eef nh\u1eadt \u2013 H\u00ecnh t\u1ee9 gi\u00e1c H\u00ecnh t\u1ee9 gi\u00e1c l\u00e0 h\u00ecnh c\u00f3 4 c\u1ea1nh v\u00e0 4 g\u00f3c. H\u00ecnh ch\u1eef nh\u1eadt l\u00e0 h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u1eb7c bi\u1ec7t v\u00ec c\u00f3 4 g\u00f3c vu\u00f4ng b\u1eb1ng nhau, 2 c\u1ea1nh d\u00e0i b\u1eb1ng nhau, 2 c\u1ea1nh ng\u1eafn b\u1eb1ng nhau. (Ch\u00fa th\u00edch: g\u00f3c vu\u00f4ng l\u00e0 g\u00f3c m\u00e0 khi \u0111o b\u1eb1ng \u00ea ke \u0111\u01b0\u1ee3c 90 \u0111\u1ed9) d. Chu vi h\u00ecnh tam gi\u00e1c \u2013 chu vi h\u00ecnh t\u1ee9 gi\u00e1c - Chu vi h\u00ecnh tam gi\u00e1c l\u00e0 t\u1ed5ng \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh c\u1ee7a h\u00ecnh tam gi\u00e1c. Chu vi tam gi\u00e1c ABC = AB + BC + CA - Chu vi c\u1ee7a t\u1ee9 gi\u00e1c l\u00e0 t\u1ed5ng \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c. Chu vi t\u1ee9 gi\u00e1c ABCD = AB + BC + CD + DA B. B\u00c0I T\u1eacP B\u00e0i 1: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: 354 + 35 972 \u2013 430 586 \u2013 42 532 + 225 To\u00e1n 2-1 Page 372","B\u00e0i 2: T\u00ednh: (1\u0111i\u1ec3m) 45 m : 5 = \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...... 32 cm : 4 9+ 6 = =\u2026\u2026\u2026\u2026.....................\u2026\u2026\u2026........ 40 : 4 : 5 =...................................... 4 \u00d7 .......................................................... B\u00e0i 3: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 1m = .........dm 519cm = 2m 6 dm = \u2026\u2026..dm 30dm = \u2026.m 24cm = \u2026.\u2026dm......cm \u2026\u2026.m\u2026....cm 5m 6dm= \u2026\u2026. dm 1000m = \u2026.km 1m = \u2026\u2026. dm 1cm = \u2026\u2026.mm 1000mm = \u2026...m 50cm = \u2026.dm 60mm = \u2026.cm B\u00e0i 4: H\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh: \u2026\u2026\u2026 t\u1ee9 gi\u00e1c. \u2026\u2026\u2026 tam gi\u00e1c B\u00e0i 5: \u00a0Cho h\u00ecnh t\u1ee9 gi\u00e1c ABCD nh\u01b0 h\u00ecnh v\u1ebd.T\u00ednh chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD. B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 373","B\u00e0i 6: M\u1ed9t tr\u1ea1i ch\u0103n nu\u00f4i g\u00e0 c\u00f3 650 con g\u00e0 m\u00e1i v\u00e0 s\u1ed1 g\u00e0 tr\u1ed1ng \u00edt h\u01a1n s\u1ed1 g\u00e0 m\u00e1i l\u00e0 23 con . H\u1ecfi tr\u1ea1i \u0111\u00f3 nu\u00f4i bao nhi\u00eau con g\u00e0 tr\u1ed1ng ? B\u00e0i gi\u1ea3i B\u00e0i 7: M\u1ed7i chu\u1ed3ng c\u00f3 4 con th\u1ecf . H\u1ecfi 5 chu\u1ed3ng \u0111\u00f3 c\u00f3 bao nhi\u00eau con th\u1ecf ? B\u00e0i gi\u1ea3i B\u00e0i 8: L\u1edbp 2A c\u00f3 32 h\u1ecdc sinh chia \u0111\u1ec1u th\u00e0nh ph\u1ed1 4 t\u1ed5 . H\u1ecfi m\u1ed7i t\u1ed5 \u0111\u00f3 c\u00f3 bao nhi\u00eau h\u1ecdc sinh ? To\u00e1n 2-1 Page 374","B\u00e0i 9: C\u1eeda h\u00e0ng c\u00f3 m\u1ed9t s\u1ed1 tr\u1ee9ng g\u00e0 . Sau khi ng\u01b0\u1eddi ta b\u00e1n \u0111i 250 qu\u1ea3 tr\u1ee9ng g\u00e0 th\u00ec c\u00f2n l\u1ea1i 150 qu\u1ea3 tr\u1ee9ng g\u00e0 . H\u1ecfi khi ch\u01b0a b\u00e1n tr\u1ee9ng th\u00ec c\u1eeda h\u00e0ng \u0111\u00f3 c\u00f3 bao nhi\u00eau qu\u1ea3 tr\u1ee9ng g\u00e0 ? B\u00e0i 10\u00a0: Gi\u1ea3i b\u00e0i to\u00e1n theo t\u00f3m t\u1eaft sau: \u0110o\u1ea1n d\u00e2y d\u00e0i: 362 cm C\u1eaft \u0111i: : 25 cm C\u00f2n l\u1ea1i : \u2026 cm ? B\u00e0i gi\u1ea3i B\u00e0i 11*: \u0110i\u1ec1n d\u1ea5u + ho\u1eb7c \u2013 v\u00e0o \u00f4 tr\u1ed1ng : 40 30 20 10 = 80 40 30 20 10 = 60 40 30 20 10 = 40 40 30 20 10 = 20 To\u00e1n 2-1 Page 375","\u0110\u00c1P \u00c1N B\u00e0i 2: T\u00ednh: 45 m : 5 = 9m 32 cm : 4 = 8cm 40 : 4 : 5 = 10 : 5 = 2 4 \u00d7 9 + 6 = 36 + 6 = 42 B\u00e0i 3: Vi\u1ebft s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 1m = 10 dm 519cm = 5m 19cm 2m 6 dm = 26dm 30dm = 3m 24cm = 2dm 4cm 1cm = 10mm 5m 6dm= 56dm 1000m = 1km 1m = 10dm 50cm = 5dm 1000mm = 1m 60mm = 6cm B\u00e0i 4: H\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau h\u00ecnh: 2 t\u1ee9 gi\u00e1c. 4 tam gi\u00e1c B\u00e0i 5: \u00a0 Chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0: 2 + 3 + 4 + 6 = 15 (cm) \u0110\u00e1p s\u1ed1: 15cm B\u00e0i 6: Tr\u1ea1i \u0111\u00f3 nu\u00f4i s\u1ed1 con g\u00e0 tr\u1ed1ng l\u00e0: 650 \u2013 23 = 627 (con g\u00e0) \u0110\u00e1p s\u1ed1: 627 con g\u00e0 tr\u1ed1ng B\u00e0i 7: 5 chu\u1ed3ng \u0111\u00f3 c\u00f3 s\u1ed1 con th\u1ecf l\u00e0: 4 \u00d7 5 = 20 (con th\u1ecf) \u0110\u00e1p s\u1ed1: 20 con th\u1ecf B\u00e0i 8: M\u1ed7i t\u1ed5 c\u00f3 s\u1ed1 h\u1ecdc sinh l\u00e0: 32 : 4 = 8 ( h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 8 h\u1ecdc sinh B\u00e0i 9: Khi ch\u01b0a b\u00e1n tr\u1ee9ng th\u00ec c\u1eeda h\u00e0ng \u0111\u00f3 c\u00f3 s\u1ed1 qu\u1ea3 tr\u1ee9ng g\u00e0 l\u00e0: 250 + 150 = 400 ( qu\u1ea3 tr\u1ee9ng) \u0110\u00e1p s\u1ed1: 400 qu\u1ea3 tr\u1ee9ng g\u00e0 B\u00e0i 10\u00a0: B\u00e0i gi\u1ea3i \u0110o\u1ea1n d\u00e2y c\u00f2n l\u1ea1i d\u00e0i s\u1ed1 x\u0103ng-ti-m\u00e9t l\u00e0: 362 \u2013 25 = 337 (cm) \u0110\u00e1p s\u1ed1: 337cm B\u00e0i 11*: \u0110i\u1ec1n d\u1ea5u + ho\u1eb7c \u2013 v\u00e0o \u00f4 tr\u1ed1ng : 40 + 30 + 20 - 10 = 80 40 + 30 - 20 + 10 = 60 To\u00e1n 2-1 Page 376","40 - 30 + 20 + 10 = 40 40 - 30 + 20 - 10 = 20 H\u1ecd v\u00e0 t\u00ean:\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026...................L\u1edbp Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: a) Trong r\u1ed5 c\u00f3 35 qu\u1ea3 cam, s\u1ed1 cam trong r\u1ed5 l\u00e0: A. 5 qu\u1ea3 B. 7 qu\u1ea3 C. 6 qu\u1ea3 D. 8 qu\u1ea3 b) S\u1ed1 g\u1ed3m: 5 tr\u0103m, 1 ch\u1ee5c v\u00e0 0 \u0111\u01a1n v\u1ecb \u0111\u01b0\u1ee3c vi\u1ebft l\u00e0: A. 510 B. 501 C. 105 D. 150 c) K\u1ebft qu\u1ea3 c\u1ee7a d\u00e3y t\u00ednh 5 \u00d7 7 + 25 l\u00e0: A. 50 B. 40 C. 60 D. 70 d)H\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0: AB = 300 cm, BC = 200 cm, AC = 400cm. Chu vi c\u1ee7a h\u00ecnh tam gi\u00e1c l\u00e0: A. 900 cm B. 600cm C. 700cm D. 800cm e)Trong h\u00ecnh b\u00ean c\u00f3 m\u1ea5y h\u00ecnh tam gi\u00e1c? A. 2 B. 3 C. 4 D. 5 g)\u0110\u1ed3ng h\u1ed3 ch\u1ec9: A. 3 gi\u1edd 10 ph\u00fat B. 9 gi\u1edd 15 ph\u00fat C. 10 gi\u1edd 15 ph\u00fat D. 3 gi\u1edd 30 ph\u00fat h.Th\u1ee9 3 tu\u1ea7n n\u00e0y l\u00e0 ng\u00e0y 5 th\u00e1ng 4, th\u1ee9 3 tu\u1ea7n sau l\u00e0 ng\u00e0y m\u1ea5y ? A.12 B.9 C.11 To\u00e1n 2-1 Page 377","To\u00e1n 2-1 Page 378","B\u00e0i 2: N\u1ed1i ( theo m\u1eabu ) : B\u00e0i 3: \u0110\u00fang ghi (\u0110), sai ghi (S) v\u00e0o a\/ S\u1ed1 li\u1ec1n sau c\u1ee7a 891 l\u00e0 890 b\/ C\u00e1c s\u1ed1 289, 305, 350, 355 \u0111\u00e3 x\u1ebfp theo th\u1ee9 t\u1ef1 t\u0103ng d\u1ea7n. c\/ S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1 l\u00e0 999 d\/ 2km3m = 2300m B\u00e0i 4: S\u1ed1 \u00d77 \u00d7 8 :5 : 4 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : Vi\u1ebft s\u1ed1 B\u00e0i 1: \u0110\u1ecdc vi\u1ebft c\u00e1c s\u1ed1 th\u00edch h\u1ee3p \u1edf b\u1ea3ng sau: \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u0110\u1ecdc s\u1ed1 B\u1ea3y tr\u0103m hai m\u01b0\u01a1i ba 415 T\u00e1m tr\u0103m m\u01b0\u1eddi l\u0103m \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. To\u00e1n 2-1 Page 379","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. 500 B\u00e0i 2: \u0110i\u1ec1n d\u1ea5u >,<,= 428\u2026\u2026.482 596\u2026\u2026\u2026612 16kg + 9kg.......33kg - 8kg 200cm +30cm....203cm 129\u2026\u2026.129 215+25\u2026\u2026.240 B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 532 + 245 351 - 46 972 - 430 589 - 35 B\u00e0i 4: T\u00ecm y : b, y - 112 = 338-221 a, y + 256 = 123 + 336 B\u00e0i 5: Cho 4 \u0111i\u1ec3m A, B, C, D a, D\u00f9ng th\u01b0\u1edbc n\u1ed1i A v\u1edbi B; B v\u1edbi D; D v\u1edbi C. A. .B T\u00ean \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac v\u1eeba n\u1ed1i \u0111\u01b0\u1ee3c l\u00e0: ................. b, Cho AB= 5cm; BD= 6cm; DC= 7 cm T\u00ednh \u0111\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac \u0111\u00f3. .............................................................................. .............................................................................. C. . D B\u00e0i 6:aVi\u1ebft c\u00e1c s\u1ed1 : 439 ; 972 ; 394 ; 521 a,\/ Theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9 b\/ Theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026. B\u00e0i 7: C\u1eeda h\u00e0ng bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 35l d\u1ea7u ; bu\u1ed5i chi\u1ec1u b\u00e1n \u00edt h\u01a1n bu\u1ed5i s\u00e1ng l\u00e0 8l d\u1ea7u . H\u1ecfi bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt d\u1ea7u ? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 380","B\u00e0i 8: T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD 150cm B A 20dm 150cm D 40dm C B\u00e0i gi\u1ea3i B\u00e0i 9: L\u1edbp 2A c\u00f3 32 h\u1ecdc sinh x\u1ebfp th\u00e0nh 4 h\u00e0ng. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 bao nhi\u00eau h\u1ecdc sinh ? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 381","B\u00e0i 10\u00a0: \u0110\u01b0\u1eddng t\u1eeb nh\u00e0 H\u00e0 \u0111\u1ebfn c\u1ed5ng tr\u01b0\u1eddng d\u00e0i 350m, \u0111\u01b0\u1eddng t\u1eeb nh\u00e0 B\u00ecnh \u0111\u1ebfn c\u1ed5ng tr\u01b0\u1eddng d\u00e0i h\u01a1n t\u1eeb nh\u00e0 H\u00e0 \u0111\u1ebfn tr\u01b0\u1eddng 600m. H\u1ecfi \u0111\u01b0\u1eddng t\u1eeb nh\u00e0 B\u00ecnh \u0111\u1ebfn c\u1ed5ng tr\u01b0\u1eddng d\u00e0i bao nhi\u00eau m\u00e9t? B\u00e0i gi\u1ea3i B\u00e0i 11*: Cho 3 ch\u1eef s\u1ed1 8; 4; 5 a. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ........................................................ b. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ........................................................ c. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ................................... d. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: ................................... To\u00e1n 2-1 Page 382","\u0110\u00c1P \u00c1N g h C A Ph\u1ea7n 1. B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m : B\u00e0i 1: Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc \u00fd \u0111\u00fang trong m\u1ed7i c\u00e2u sau: C\u00e2u a b c d e \u0110\u00e1p \u00e1n B A C A B B\u00e0i 2: N\u1ed1i ( theo m\u1eabu ) : B\u00e0i 3: \u0110\u00fang ghi (\u0110), sai ghi (S) v\u00e0o a\/ S b\/ \u0110 c\/ \u0110 d\/ S B\u00e0i 4: S\u1ed1 \u00d77 \u00d78 :5 :4 Ph\u1ea7n 2 - T\u1ef1 Lu\u1eadn : Vi\u1ebft s\u1ed1 B\u00e0i 1: \u0110\u1ecdc vi\u1ebft c\u00e1c s\u1ed1 th\u00edch h\u1ee3p \u1edf b\u1ea3ng sau: 723 815 \u0110\u1ecdc s\u1ed1 415 B\u1ea3y tr\u0103m hai m\u01b0\u01a1i ba 500 T\u00e1m tr\u0103m m\u01b0\u1eddi l\u0103m B\u1ed1n tr\u0103m m\u01b0\u1eddi l\u0103m N\u0103m tr\u0103m To\u00e1n 2-1 Page 383","To\u00e1n 2-1 Page 384","B\u00e0i 2: \u0110i\u1ec1n d\u1ea5u >,<,= 428 < 482 596 < 612 16kg + 9kg = 33kg - 8kg 200cm +30cm > 203cm 129 = 129 215+25 = 240 972 \u2013 430 = 542 589 \u2013 B\u00e0i 3: \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 532 + 245 = 777 351 - 46 =305 35= 554 B\u00e0i 4: T\u00ecm y : a, y + 256 = 123 + 336 b, y \u2013 112 = 338-221 y + 256 = 459 y \u2013 112 = 117 y = 459 \u2013 256 y = 117 + 112 y = 203 y = 229 B\u00e0i 5: Cho 4 \u0111i\u1ec3m A, B, C, D a, D\u00f9ng th\u01b0\u1edbc n\u1ed1i A v\u1edbi B; B v\u1edbi D; D v\u1edbi C. A. .B T\u00ean \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac v\u1eeba n\u1ed1i \u0111\u01b0\u1ee3c l\u00e0: ABDC. b, Cho AB= 5cm; BD= 6cm; DC= 7 cm T\u00ednh \u0111\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac \u0111\u00f3. \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng g\u1ea5p kh\u00fac \u0111\u00f3 l\u00e0: 5 + 6 + 7 = 18(cm) \u0110\u00e1p s\u1ed1: 18cm C. . D B\u00e0i 6:aVi\u1ebft c\u00e1c s\u1ed1 : 439 ; 972 ; 394 ; 521 a,\/ Theo th\u1ee9 t\u1ef1 t\u1eeb l\u1edbn \u0111\u1ebfn b\u00e9 b\/ Theo th\u1ee9 t\u1ef1 t\u1eeb b\u00e9 \u0111\u1ebfn l\u1edbn 972 ; 521; 439 ; 394 394; 521; 439 ; 972 B\u00e0i 7: B\u00e0i gi\u1ea3i Bu\u1ed5i chi\u1ec1u c\u1eeda h\u00e0ng b\u00e1n \u0111\u01b0\u1ee3c s\u1ed1 l\u00edt d\u1ea7u l\u00e0: 35 \u2013 8 = 27 (l) \u0110\u00e1p s\u1ed1: 27l d\u1ea7u B\u00e0i 8: B\u00e0i gi\u1ea3i \u0110\u1ed5i 30 dm = 300cm, 40dm = 400cm Chu vi h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0: 150 + 150 + 200 + 400= 900 (cm) \u0110\u00e1p s\u1ed1: 900cm B\u00e0i 9: B\u00e0i gi\u1ea3i M\u1ed7i h\u00e0ng c\u00f3 s\u1ed1 h\u1ecdc sinh l\u00e0: 32 : 4 = 7 ( h\u1ecdc sinh) \u0110\u00e1p s\u1ed1: 7 h\u1ecdc sinh B\u00e0i 10\u00a0: B\u00e0i gi\u1ea3i \u0110\u01b0\u1eddng t\u1eeb nh\u00e0 B\u00ecnh \u0111\u1ebfn c\u1ed5ng tr\u01b0\u1eddng d\u00e0i s\u1ed1 m\u00e9t l\u00e0: 350 + 600 = 950 (cm) \u0110\u00e1p s\u1ed1\u00a0: 950m To\u00e1n 2-1 Page 385","B\u00e0i 11*: Cho 3 ch\u1eef s\u1ed1 8; 4; 5 a. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 854 b. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 458 c. H\u00e3y vi\u1ebft s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 85 d. H\u00e3y vi\u1ebft s\u1ed1 b\u00e9 nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 trong 3 ch\u1eef s\u1ed1 \u0111\u00e3 cho: 45 To\u00e1n 2-1 Page 386","MA TR\u1eacN \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I H\u1eccC K\u00cc 2 M\u00d4N TO\u00c1N - L\u1edaP 2 TT M\u1ea1ch ki\u1ebfn th\u1ee9c, C\u00e2u\/ M\u1ee9c 1 M\u1ee9c 2 M\u1ee9c 3 M\u1ee9c 4 T\u1ed5ng s\u1ed1 k\u0129 n\u0103ng \u0111i\u1ec3m TN TL TN TL TN TL TN TL TN TL S\u1ed1 c\u00e2u 3 1 1 11 52 1 S\u1ed1 h\u1ecdc C\u00e2u s\u1ed1 I.1,2,3II.1 I.4 II.2 I.8 I.1,2,3, 11 4 II.1,2 S\u1ed1 1,5 2 1 I.8 \u0111i\u1ec3m 3,5 3 S\u1ed1 c\u00e2u 1 1 2 Y\u1ebfu t\u1ed1 \u0111\u1ea1i l\u01b0\u1ee3ng C\u00e2u s\u1ed1 I.5 I.5 S\u1ed1 0,5 0,5 \u0111i\u1ec3m S\u1ed1 c\u00e2u 11 11 3 Gi\u1ea3i to\u00e1n c\u00f3 l\u1eddi v\u0103nC\u00e2u s\u1ed1 I.6 II.3 I.6 II.3 S\u1ed1 0,5 2 0,5 2 \u0111i\u1ec3m S\u1ed1 c\u00e2u 11 Y\u1ebfu t\u1ed1 h\u00ecnh h\u1ecdc C\u00e2u s\u1ed1 I.7 I.7 4 S\u1ed1 0,5 0,5 \u0111i\u1ec3m S\u1ed1 c\u00e2u 3 1 3 1 1 1 1 83 C\u00e2u s\u1ed1 I.1,2, II.1 I.4,5, II.3 I.7 II.2 I.8 I.1-8 II.1,2, 3 6 3 T\u1ed5ng 5 S\u1ed1 50% 5 \u0111i\u1ec3m 1,5 2 2 2 0,5 1 1 50% T\u1ec9 l\u1ec7 35% 40% 15% 10% To\u00e1n 2-1 Page 387","M\u1ed8T S\u1ed0 \u0110\u1ec0 KI\u1ec2M TRA CU\u1ed0I H\u1eccC K\u00cc II \u0110\u1ec0 S\u1ed0 1 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (3,5\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. S\u1ed1 g\u1ed3m 3 ch\u1ee5c, 2 tr\u0103m, 5 \u0111\u01a1n v\u1ecb l\u00e0: A. 325 B. 235 C. 352 D. 325 2. S\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1 kh\u00e1c nhau l\u00e0: A. 789 B. 999 C. 987 D. 978 3. K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh 4 x 7 + 145 l\u00e0: A. 28 B. 156 C. 163 D. 173 4. S\u1ed1 h\u00ecnh tam gi\u00e1c c\u00f3 trong h\u00ecnh b\u00ean l\u00e0: A. 4 B. 5 C. 6 D. 7 5. T\u00ednh chu vi h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u1ea7n l\u01b0\u1ee3t l\u00e0: 28cm, 12cm, 20mm. A. 50cm B. 60cm C. 42mm D. 42cm 6. \u0110\u1ed3ng h\u1ed3 ch\u1ec9 m\u1ea5y gi\u1edd n\u1ebfu kim ng\u1eafn \u1edf gi\u1eefa s\u1ed1 3 v\u00e0 4, kim d\u00e0i ch\u1ec9 s\u1ed1 6: A. 3 gi\u1edd 15 ph\u00fat B. 4 gi\u1edd r\u01b0\u1ee1i C. 15 gi\u1edd 30 ph\u00fat D. 15 gi\u1edd 7. s\u1ed1 ng\u00f4i sao trong h\u00ecnh v\u1ebd b\u00ean l\u00e0: A. 4 ng\u00f4i sao B. 5 ng\u00f4i sao C. 6 ng\u00f4i sao D. 7 ng\u00f4i sao PH\u1ea6N II: T\u1ef0 LU\u1eacN (6,5\u0111) B\u00e0i 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: (2\u0111i\u1ec3m) 362 + 235 53 + 436 623 \u2013 202 61 \u2013 45 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 388","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 2. \u0110i\u1ec1n d\u1ea5u th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: (1\u0111i\u1ec3m) 1km \u2026 999m 13mm \u2026 15mm \u2013 1cm B\u00e0i 3. T\u00ecm y (1\u0111i\u1ec3m) 4 x y = 24 y : 3 = 54 \u2013 46 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 4. C\u00f3 40 qu\u1ea3 t\u00e1o b\u00e0y v\u00e0o c\u00e1c \u0111\u0129a, m\u1ed7i \u0111\u0129a 5 qu\u1ea3. H\u1ecfi c\u00f3 bao nhi\u00eau \u0111\u0129a t\u00e1o? (1,5\u0111i\u1ec3m) B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 5. T\u1ed5ng c\u1ee7a s\u1ed1 l\u1edbn nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 kh\u00e1c nhau v\u00e0 s\u1ed1 tr\u00f2n tr\u0103m l\u1edbn nh\u1ea5t c\u00f3 3 ch\u1eef s\u1ed1 l\u00e0 bao nhi\u00eau? (1\u0111i\u1ec3m) B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 389","\u0110\u1ec0 S\u1ed0 2 PH\u1ea6N 1. TR\u1eaeC NGHI\u1ec6M (6 \u0111) C\u00e2u 1(4 \u0111i\u1ec3m). Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang 1. (0,5 \u0111) S\u1ed1 845 \u0111\u1ecdc l\u00e0: A. T\u00e1m tr\u0103m b\u1ed1n m\u01b0\u01a1i n\u0103m B. T\u00e1m tr\u0103m b\u1ed1n m\u01b0\u01a1i l\u0103m C. T\u00e1m b\u1ed1n l\u0103m D. T\u00e1m tr\u0103m b\u1ed1n n\u0103m 2. (0,5 \u0111) S\u1ed1 g\u1ed3m 6 tr\u0103m, 9 \u0111\u01a1n v\u1ecb vi\u1ebft l\u00e0: A. 6009 B. 69 C. 690 D. 609 3. (0,5 \u0111) An \u0111\u00e1 b\u00f3ng t\u1eeb 17 gi\u1edd \u0111\u1ebfn 6 gi\u1edd chi\u1ec1u. H\u1ecfi An \u0111\u00e1 b\u00f3ng trong m\u1ea5y gi\u1edd? A. 11 gi\u1edd B. 2 gi\u1edd C. 1 gi\u1edd D. 23 gi\u1edd 4. (0,5 \u0111) M\u1ed9t \u0111\u00e0n heo c\u00f3 16 c\u00e1i ch\u00e2n. H\u1ecfi \u0111\u00e0n heo \u0111\u00f3 c\u00f3 bao nhi\u00eau con? \u0110\u00e1p s\u1ed1 c\u1ee7a b\u00e0i to\u00e1n l\u00e0: A. 4 con B. 20 con C. 12 con D. 8 con 5. (1 \u0111) Nh\u1eefng ph\u00e9p t\u00ednh n\u00e0o sai? A. 3 : 3 + 0 = 0 B. 0 x 4 : 4 = 1 C. 3 x 3 = 9 D. 20 : 5 = 4 x 1 6. (0,5 \u0111) S\u1ed1 h\u00ecnh t\u1ee9 gi\u00e1c trong h\u00ecnh v\u1ebd d\u01b0\u1edbi l\u00e0: A. 3 h\u00ecnh B. 4 h\u00ecnh C. 5 h\u00ecnh D. 6 h\u00ecnh 7. (0,5 \u0111) T\u1ed5 M\u1ed9t x\u1ebfp \u0111\u01b0\u1ee3c 321 chi\u1ebfc thuy\u1ec1n gi\u1ea5y. T\u1ed5 Hai x\u1ebfp \u0111\u01b0\u1ee3c \u00edt h\u01a1n T\u1ed5 M\u1ed9t 21 chi\u1ebfc thuy\u1ec1n gi\u1ea5y. H\u1ecfi T\u1ed5 Hai x\u1ebfp \u0111\u01b0\u1ee3c bao nhi\u00eau chi\u1ebfc thuy\u1ec1n gi\u1ea5y? A. 341 chi\u1ebfc \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 340 chi\u1ebfc \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 302 chi\u1ebfc \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 300 chi\u1ebfc C\u00e2u 2. (1 \u0111) \u0110i\u1ec1n s\u1ed1 v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p 1km = \u2026\u2026.. m 1m \u2026dm = 18dm 24dm : 3 = \u2026\u2026.dm C\u00e2u 3. (1 \u0111) a. Vi\u1ebft s\u1ed1 v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: 116 ; 216 ; ...... ; ....... ; 516. b. Vi\u1ebft hai s\u1ed1 l\u1edbn h\u01a1n 499 m\u00e0 m\u1ed7i s\u1ed1 c\u00f3 ba ch\u1eef s\u1ed1 gi\u1ed1ng nhau. ......................................................................................................................................... ... PH\u1ea6N 2. T\u1ef0 LU\u1eacN (4 \u0111) C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2 \u0111) 305 + 289 502 \u2013 147 56 + 514 733 \u2013 110 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2. Gi\u1ea3i to\u00e1n (2 \u0111) M\u1ed9t c\u1eeda h\u00e0ng trong m\u1ed9t tu\u1ea7n b\u00e1n \u0111\u01b0\u1ee3c 645m v\u1ea3i hoa. S\u1ed1 m\u00e9t v\u1ea3i hoa \u0111\u00e3 b\u00e1n nhi\u1ec1u h\u01a1n v\u1ea3i tr\u1eafng l\u00e0 243m. H\u1ecfi c\u1eeda h\u00e0ng \u0111\u00f3 \u0111\u00e3 b\u00e1n \u0111\u01b0\u1ee3c bao nhi\u00eau m\u00e9t v\u1ea3i tr\u1eafng? To\u00e1n 2-1 Page 390","B\u00e0i gi\u1ea3i ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... To\u00e1n 2-1 Page 391","\u0110\u1ec0 S\u1ed0 3 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1. (0,5\u0111) S\u1ed1 453 \u0111\u1ecdc l\u00e0: A. B\u1ed1n n\u0103m ba B. B\u1ed1n tr\u0103m n\u0103m m\u01b0\u01a1i ba C. B\u1ed1n l\u0103m ba D. B\u1ed1n tr\u0103m l\u0103m m\u01b0\u01a1i ba C\u00e2u 2. (1\u0111) \u0110i\u1ec1n d\u1ea5u >; <; = th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: a. 4 x 3 + 20 ....... 5 x 10 \u2013 18 b. 40 : 4 + 13 ....... 2 x 8 \u2013 9 C\u00e2u 3. (0,5\u0111) C\u00f3 50kg khoai t\u00e2y chia \u0111\u1ec1u v\u00e0o 5 bao. H\u1ecfi m\u1ed7i bao c\u00f3 bao nhi\u00eau ki-l\u00f4-gam khoai t\u00e2y? A. 45kg B. 55kg C. 10kg D. 25kg C\u00e2u 4. (1\u0111) M\u1eb9 \u0111i l\u00e0m ca chi\u1ec1u b\u1eaft \u0111\u1ea7u t\u1eeb 2 gi\u1edd chi\u1ec1u \u0111\u1ebfn 22 gi\u1edd. H\u1ecfi m\u1eb9 \u0111\u00e3 l\u00e0m trong m\u1ea5y gi\u1edd? A. 8 gi\u1edd B. 24 gi\u1edd C. 20 gi\u1edd D. 12 gi\u1edd C\u00e2u 5. (1\u0111) Vi\u1ebft ti\u1ebfp v\u00e0o ch\u1ed7 ch\u1ea5m cho th\u00edch h\u1ee3p: a. 211; 212; 213; \u2026\u2026..; \u2026\u2026..; 216; \u2026\u2026..; 218; 219; \u2026\u2026.. b. 510; 515;\u2026\u2026..; 525; 530; \u2026\u2026..; \u2026\u2026..; PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111) 84 + 19 62 - 25 536 + 243 879 - 356 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2. T\u00ecm y (1\u0111) a. y : 4 = 8 b. y x 4 = 12 + 8 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... C\u00e2u 3. Gi\u1ea3i to\u00e1n: (2\u0111) M\u1ed9t c\u1eeda h\u00e0ng b\u00e1n x\u0103ng d\u1ea7u trong bu\u1ed5i s\u00e1ng b\u00e1n \u0111\u01b0\u1ee3c 865 l\u00edt d\u1ea7u v\u00e0 724 l\u00edt x\u0103ng. H\u1ecfi s\u1ed1 d\u1ea7u c\u1eeda h\u00e0ng \u0111\u00e3 b\u00e1n nhi\u1ec1u h\u01a1n s\u1ed1 x\u0103ng bao nhi\u00eau l\u00edt? B\u00e0i gi\u1ea3i ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... C\u00e2u 4. (1\u0111) K\u1ebb th\u00eam m\u1ed9t \u0111o\u1ea1n th\u1eb3ng v\u00e0o h\u00ecnh sau \u0111\u1ec3 \u0111\u01b0\u1ee3c hai h\u00ecnh t\u1ee9 gi\u00e1c v\u00e0 m\u1ed9t h\u00ecnh tam gi\u00e1c. To\u00e1n 2-1 Page 392","\u0110\u1ec0 S\u1ed0 4 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1. (0,5\u0111) Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 8 trong s\u1ed1 185 l\u00e0: A. 8 B. 80 C. 800 D. 18 C\u00e2u 2. (1\u0111) \u0110i\u1ec1n d\u1ea5u >; <; = th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: a.8dm x 3 ....... 22cm b. 80cm : 2 ....... 14dm : 4 C\u00e2u 3. (0,5\u0111) M\u1ed7i chu\u1ed3ng c\u00f3 4 con g\u00e0. H\u1ecfi 5 chu\u1ed3ng nh\u01b0 th\u1ebf c\u00f3 bao nhi\u00eau con g\u00e0? A. 20 con g\u00e0 B. 9 con g\u00e0 C. 16 con g\u00e0 D. 18 con g\u00e0 C\u00e2u 4. (1\u0111) S\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 ba ch\u1eef s\u1ed1 m\u00e0 ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c b\u1eb1ng 6 l\u00e0: A. 100 B. 666 C. 160 D. 660 C\u00e2u 5. (1\u0111) H\u00ecnh b\u00ean c\u00f3: A. 2 h\u00ecnh tam gi\u00e1c v\u00e0 2 h\u00ecnh t\u1ee9 gi\u00e1c B. 2 h\u00ecnh tam gi\u00e1c v\u00e0 3 h\u00ecnh t\u1ee9 gi\u00e1c C. 2 h\u00ecnh tam gi\u00e1c v\u00e0 4 h\u00ecnh t\u1ee9 gi\u00e1c PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (2\u0111) 26 + 54 74 - 46 205 + 118 567 - 376 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2. T\u00ecm y (1\u0111) a. y x 4 = 12 b. y : 4 = 12 - 8 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... C\u00e2u 3. Gi\u1ea3i to\u00e1n: (2,5\u0111) Trong v\u01b0\u1eddn nh\u00e0 ch\u00fa T\u01b0 c\u00f3 230 c\u00e2y cam, s\u1ed1 c\u00e2y cam \u00edt h\u01a1n s\u1ed1 c\u00e2y qu\u00fdt 128 c\u00e2y. H\u1ecfi: a. Trong v\u01b0\u1eddn c\u00f3 bao nhi\u00eau c\u00e2y qu\u00fdt? b. Trong v\u01b0\u1eddn c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau c\u00e2y cam v\u00e0 qu\u00fdt? B\u00e0i gi\u1ea3i ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... C\u00e2u 4. (0,5\u0111) H\u00ecnh b\u00ean c\u00f3 bao nhi\u00eau \u0111o\u1ea1n th\u1eb3ng? - C\u00f3 .......... \u0111o\u1ea1n th\u1eb3ng To\u00e1n 2-1 Page 393","\u0110\u1ec0 S\u1ed0 5 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang: 1. (0,5\u0111) S\u1ed1 g\u1ed3m 9 ch\u1ee5c, 4 tr\u0103m, 2 \u0111\u01a1n v\u1ecb l\u00e0: A. 942 B. 492 C. 429 D. 294 2. (1\u0111) Gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c c\u1ee7a s\u1ed1 253 l\u1edbn h\u01a1n gi\u00e1 tr\u1ecb c\u1ee7a ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb c\u1ee7a s\u1ed1 \u0111\u00f3 bao nhi\u00eau \u0111\u01a1n v\u1ecb? A. 2 B. 50 C. 47 D. 53 3. (0,5\u0111) \u0110\u1ed3ng h\u1ed3 b\u00ean ch\u1ec9: A. 11 gi\u1edd 15 ph\u00fat B. 11 gi\u1edd 3 ph\u00fat C. 12 gi\u1edd 15 ph\u00fat D. 15 gi\u1edd 4. (1\u0111) H\u00ecnh t\u1ee9 gi\u00e1c ABCD c\u00f3 AB = BC = 2dm v\u00e0 AD = CD = 35cm. V\u1eady chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD l\u00e0 bao nhi\u00eau? A. 37cm B. 74cm C. 55cm D. 110cm 5. (1\u0111) s\u1ed1 ng\u00f4i sao trong h\u00ecnh v\u1ebd b\u00ean l\u00e0: A. 4 ng\u00f4i sao B. 5 ng\u00f4i sao C. 6 ng\u00f4i sao D. 7 ng\u00f4i sao PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) B\u00e0i 1. T\u00ednh (2\u0111i\u1ec3m) a. 5 x 9 + 453 b. 20 : 5 x 8 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 2. T\u00ecm y (1\u0111) 4 x y = 28 y : 5 = 12 : 4 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 3. (2\u0111) Gi\u1ea3i to\u00e1n: N\u0103m nay b\u1ed1 36 tu\u1ed5i, \u00f4ng nhi\u1ec1u h\u01a1n b\u1ed1 27 tu\u1ed5i. H\u1ecfi \u00f4ng n\u0103m n\u00e0y bao nhi\u00eau tu\u1ed5i? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 B\u00e0i 4.(1\u0111) T\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft n\u1ebfu ta chia s\u1ed1 \u0111\u00f3 cho 2, r\u1ed3i c\u1ed9ng v\u1edbi 19 th\u00ec \u0111\u01b0\u1ee3c s\u1ed1 m\u1edbi l\u00e0 24. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 394","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 395","\u0110\u1ec0 S\u1ed0 6 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (4\u0111) C\u00e2u 1. (1\u0111)\u00a0Khoanh v\u00e0o ch\u1eef c\u00e1i c\u00f3 k\u1ebft qu\u1ea3 \u0111\u00fang: a. 0 : 4 = ? A. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 4 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 40 b. 5 x 0 =? A. 5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 50 C\u00e2u 2:\u00a0(0,5\u0111) \u0110\u00fang ghi \u0110, sai ghi S H\u00f4m nay l\u00e0 th\u1ee9 ba, ng\u00e0y 16 th\u00e1ng 4. Th\u1ee9 ba tu\u1ea7n sau v\u00e0o ng\u00e0y 23 th\u00e1ng 4. T\u1eeb 7 gi\u1edd s\u00e1ng \u0111\u1ebfn 2 gi\u1edd chi\u1ec1u c\u00f9ng ng\u00e0y l\u00e0 6 gi\u1edd. C\u00e2u 3: (1\u0111) N\u1ed1i ph\u00e9p t\u00ednh v\u1edbi k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p t\u00ednh \u0111\u00f3: C\u00e2u 4.\u00a0(1\u0111) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed5 ch\u1ea5m: a. 5 x 3 =\u2026\u2026\u2026\u2026. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 14 : 2 = ............ b.\u00a0M\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 12 cm, 13cm, 14cm, 15 cm. Chu vi h\u00ecnh t\u1ee9 gi\u00e1c l\u00e0:\u2026\u2026\u2026\u2026 C\u00e2u 5. (0,5\u0111)\u00a0 30 + 50\u00a0\u2026\u00a020 + 60. D\u1ea5u c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m l\u00e0: A. < \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. > \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. = \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. kh\u00f4ng c\u00f3 d\u1ea5u n\u00e0o PH\u1ea6N II: T\u1ef0 LU\u1eacN (6\u0111) C\u00e2u 1. (2\u0111) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh 465 + 213 857 \u2013 432 456 \u2013 15 234 + 235 .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... .......................... C\u00e2u 2. (1\u0111) T\u00ecm x x - 24 = 47 - 14 67 \u2013 x = 15 + 6 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 3. (2\u0111) M\u1ed9t h\u00ecnh t\u1ee9 gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0 1dm 2cm, 13cm, 14cm, 15 cm. T\u00ednh chu vi h\u00ecnh t\u1ee9 gi\u00e1c \u0111\u00f3. B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 4: S\u1ed1 k\u1eb9o c\u1ee7a Lan l\u00e0 s\u1ed1 nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1 gi\u1ed1ng nhau. Lan cho Hoa s\u1ed1 k\u1eb9o l\u00e0 s\u1ed1 ch\u1eb5n nh\u1ecf nh\u1ea5t c\u00f3 2 ch\u1eef s\u1ed1. H\u1ecfi Lan c\u00f2n bao nhi\u00eau c\u00e1i k\u1eb9o? B\u00e0i gi\u1ea3i To\u00e1n 2-1 Page 396","\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 397","\u0110\u1ec0 S\u1ed0 7 C\u00e2u 1: (1 \u0111i\u1ec3m): Khoanh v\u00e0o tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t: a) S\u1ed1 li\u1ec1n tr\u01b0\u1edbc s\u1ed1 546 l\u00e0: A. 547 B. 400 C. 545 D. 500 b) Gi\u00e1 tr\u1ecb c\u1ee7a s\u1ed1 4 trong s\u1ed1 546 l\u00e0: A. 4 B. 4 ch\u1ee5c C. 546 D. 40 C\u00e2u 2: (1 \u0111i\u1ec3m) Vi\u1ebft s\u1ed1 v\u00e0 ch\u1eef th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng (theo m\u1eabu): Vi\u1ebft s\u1ed1 \u0110\u1ecdc s\u1ed1 107 M\u1ed9t tr\u0103m linh b\u1ea3y 439 T\u00e1m tr\u0103m s\u00e1u m\u01b0\u01a1i hai C\u00e2u 3: (`1 \u0111i\u1ec3m) Khoanh v\u00e0o tr\u01b0\u1edbc k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t: a) \u0110\u1ed3ng h\u1ed3 ch\u1ec9: A. 3 gi\u1edd B. 7 gi\u1edd 15 ph\u00fat C. 7 gi\u1edd 30 ph\u00fat D. 19 gi\u1edd 15 ph\u00fat t\u1ed1i b) H\u00f4m nay ng\u00e0y 8 th\u00e1ng 11 l\u00e0 th\u1ee9 hai, th\u1ee9 hai tu\u1ea7n sau l\u00e0 ng\u00e0y: A. 13 B. 15 C. 20 D. 21 C\u00e2u 4: (1 \u0111i\u1ec3m) a) \u0110i\u1ec1n d\u1ea5u >;<; b) \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh: =? 25 + 47 786 - 364 635 ..... 639 827 ..... 800 + 27 ............................................................................................... ............................................................................................... ............................................................................................. C\u00e2u 5: (1 \u0111i\u1ec3m): T\u00ednh a) 4 x 6 + 5 = \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 b) 8 x 5 : 2 =\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026... C\u00e2u 6: (1 \u0111i\u1ec3m) Cho h\u00ecnh t\u1ee9 gi\u00e1c nh\u01b0 h\u00ecnh v\u1ebd A 4cm B T\u00ednh chu vi c\u1ee7a h\u00ecnh t\u1ee9 gi\u00e1c ABCD. 3cm 6cm B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 398","C\u00e2u 7: (1 \u0111i\u1ec3m): \u0110\u00fang ghi \u0110, sai ghi S v\u00e0o \u00f4 tr\u1ed1ng: C\u00f3 80kg ng\u00f4 chia \u0111\u1ec1u v\u00e0o 4 bao. M\u1ed7i bao c\u00f3: A. 20 kg ng\u00f4 B. 4 kg ng\u00f4 C\u00e2u 8: (1 \u0111i\u1ec3m) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng: x5 :5 -5 + 50 C\u00e2u 9: (1 \u0111i\u1ec3m) S\u1ee3i d\u00e2y \u0111\u1ed3ng d\u00e0i 1m. S\u1ee3i d\u00e2y th\u00e9p ng\u1eafn h\u01a1n s\u1ee3i d\u00e2y \u0111\u1ed3ng 6cm. H\u1ecfi s\u1ee3i d\u00e2y th\u00e9p d\u00e0i bao nhi\u00eau? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 10: (1 \u0111i\u1ec3m) T\u00ecm x, bi\u1ebft: X + X+ X + X = 24 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 399","\u0110\u1ec0 S\u1ed0 8 PH\u1ea6N I: TR\u1eaeC NGHI\u1ec6M (5\u0111) Khoanh v\u00e0o ch\u1eef c\u00e1i \u0111\u1eb7t tr\u01b0\u1edbc c\u00e2u tr\u1ea3 l\u1eddi \u0111\u00fang ho\u1eb7c l\u00e0m theo y\u00eau c\u1ea7u: C\u00e2u 1. (1\u0111) S\u1ed1 th\u00edch h\u1ee3p c\u1ea7n \u0111i\u1ec1n v\u00e0o ch\u1ed7 ch\u1ea5m \u0111\u1ec3 1m 3cm = ..... cm l\u00e0: A. 10 B. 103 C. 13 D. 30 C\u00e2u 2. (1\u0111) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 3kg = ..... g C\u00e2u 3. (1\u0111) \u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m: 5 x 6 : 3 =\u2026.. A. 10 B. 30 C. 2 D. 3 C\u00e2u 4. (1\u0111) H\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u00e1c c\u1ea1nh l\u00e0: AB = 300 cm, BC = 200 cm, AC = 400cm. Chu vi c\u1ee7a h\u00ecnh tam gi\u00e1c l\u00e0: A. 900 cm B. 600cm C. 700cm D. 800cm C\u00e2u 5. (1\u0111) H\u00ecnh b\u00ean c\u00f3 m\u1ea5y h\u00ecnh tam gi\u00e1c? A. 2 C. 4 B. 3 D. 5 PH\u1ea6N II: T\u1ef0 LU\u1eacN (5\u0111) C\u00e2u 1. \u0110\u1eb7t t\u00ednh r\u1ed3i t\u00ednh (1\u0111) a) 683 + 204 b) 548 - 312 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 2. T\u00ecm x (2\u0111): \u00a0 a) 5 x x = 25 b) x : 4 = 4 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 3. (1\u0111)\u00a0 L\u1edbp 2A c\u00f3 32 h\u1ecdc sinh \u0111\u01b0\u1ee3c chia \u0111\u1ec1u th\u00e0nh 4 h\u00e0ng \u0111\u1ec3 t\u1eadp th\u1ec3 d\u1ee5c. H\u1ecfi m\u1ed7i h\u00e0ng c\u00f3 m\u1ea5y h\u1ecdc sinh? B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 C\u00e2u 4. (1\u0111) T\u00ecm hi\u1ec7u c\u1ee7a s\u1ed1 tr\u00f2n ch\u1ee5c l\u1edbn nh\u1ea5t c\u00f3 hai ch\u1eef s\u1ed1 v\u1edbi s\u1ed1 ch\u1eb5n l\u1edbn nh\u1ea5t c\u00f3 m\u1ed9t ch\u1eef s\u1ed1 . B\u00e0i gi\u1ea3i \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 To\u00e1n 2-1 Page 400"]